Evidence for a Second Neutral Pion

Abstract

Evidence suggests the existence of a second neutral pion based on: (1) the anomalous branching ratios in the reactions p ¯ pππ and p ¯ dππN , and (2) the 1960s findings of Tsai-Chü et al. regarding antinucleon annihilation stars in emulsions. The anomaly in (1) disappears if the two neutral pions in the reactions p ¯ p π 0 π 0 and p ¯ d π 0 π 0 n are not identical. Tsai-Chü et al. observed a second neutral pion that “decays more rapidly into electron pairs with larger opening angles and more frequently into double pairs.” One antineutron annihilation event produced three neutral particles, each with a mass of 135 ± 14 MeV, decaying into four electrons with significantly wider opening angles than those of the internal conversion electrons observed in π 0 decays. The larger opening angles and higher frequency of double pair production could be caused by neutral pions with such a short lifetime that they decay into photon pairs before they can leave the annihilation nucleus (e.g., Ag) of the emulsion. We discuss several methods for searching for a second neutral pion.

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Perkins, W.A. (2025) Evidence for a Second Neutral Pion. Journal of High Energy Physics, Gravitation and Cosmology, 11, 1224-1238. doi: 10.4236/jhepgc.2025.114076.

1. Introduction

Significant experimental evidence indicates that capture and annihilation reactions occur predominately from the atomic S states in liquid hydrogen. The anomalously large fraction of antiproton annihilations proceeding from the P states in two sets of reactions ( p ¯ pππ and p ¯ dππN ) was not measured directly, but was inferred using the theoretical argument that p ¯ p π 0 π 0 cannot occur from a p ¯ p atomic S state. However, if the two π 0 ’s are not identical, p ¯ p π L 0 π S 0 and p ¯ d π L 0 π S 0 n can occur from an atomic S states, and there is no anomaly. Here, we denote the usual π 0 that decays in ∼10−16 s as π L 0 and a second neutral pion that decays with a much shorter lifetime as π S 0 .

The rules governing the p ¯ pππ reactions are discussed in Section 2, and the experimental evidence of the anomaly is presented in Section 3. In Section 4, we present a slightly different interpretation of the results of Tsai-Chü et al. Their main point is that a second neutral pion with a very short lifetime exists is unchanged. Although they assumed that the observed electrons came directly from the decay of this second neutral pion, π S 0 , we suggest that the observed electrons came from pair production inside the annihilation nucleus. Our interpretation has the advantage of explaining why such electron pairs and double pairs are not observed in p ¯ annihilation in hydrogen and deuterium. (These electron pairs are not Dalitz pairs as discussed in Section 4).

Experimental tests that could demonstrate the existence of two distinct π 0 are discussed in Section 5, along with another test (based on the results of Tsai-Chü et al.) that can prove the existence and determine the lifetime of this second neutral pion.

2. Allowed Antiproton-Proton Reactions

The conservation of angular momentum, parity, and charge parity dictates the allowed reactions in which protonium is annihilated into two pions. The eigenvalues of parity and charge parity of a fermion-antifermion pair are given by [1],

ω Parity = ( 1 ) X+1 , ω Charge parity = ( 1 ) X+s , (1)

where X is the relative orbital angular momentum of the two particles and s is the spin of the fermion-antifermion system. The eigenvalues of parity and charge parity of a two-pion system are given by [1],

ω Parity = ( 1 ) Y , ω Charge parity = ( 1 ) Y , (2)

where Y denotes the relative orbital angular momentum of the two pions.

Further contraints exist for the π 0 π 0 system. Because of Bose statistics, the states of two identical pions must be symmetric under interchange. Thus Y must be even and both parity and charge parity must be +1 for the π 0 π 0 system. From these considerations, we obtain Tables 1-3 for the initial and final states, respectively.

Using the conservation of parity, charge parity, and total angular momentum to match the initial and final states, we determine the allowed reactions:

p ¯ p( 3 S 1 ) π + π ( P 1 ), p ¯ p( 3 P 0 ) π 0 π 0 ( S 0 ), p ¯ p( 3 P 0 ) π + π ( S 0 ), p ¯ p( 3 P 2 ) π 0 π 0 ( D 2 ), p ¯ p( 3 P 2 ) π + π ( D 2 ). (3)

Thus, we see that the p ¯ p π 0 π 0 reaction cannot occur from an atomic S

Table 1. Initial state of p ¯ p Atom.

State

J

Parity

Charge parity

  1 S 0

0

−1

+1

  3 S 1

1

−1

−1

  3 P 0

0

+1

+1

  1 P 1

1

+1

−1

  3 P 1

1

+1

+1

  3 P 2

2

+1

+1

Table 2. Final state of π 0 π 0 system.

State

J

Parity

Charge parity

Comment

S 0

0

+1

+1

Y = 0

D 2

2

+1

+1

Y = 2

Table 3. Final state of π + π system.

State

J

Parity

Charge parity

Comment

S 0

0

+1

+1

Y = 0

P 1

1

−1

−1

Y = 1

D 2

2

+1

+1

Y = 2

state of the p ¯ p system if the two π 0 ’s are identical. To match the initial   3 S 1 state of p ¯ p , the π 0 π 0 system requires a P 1 state with parity = −1 and charge parity = −1 as shown in the second line of Table 3 for the π + π system. The significant difference in eigenvalues between the π + π system and the π 0 π 0 system arises because the two π 0 ’s are identical whereas the π + and π are not.

If the π 0 ’s are different, there is no requirement that the state of the two π 0 ’s must be symmetric under interchange. Therefore, Y can be odd for some π L 0 π S 0 states similar to the π + π system, leading to a P 1 state with parity of −1. Charge parity also depends upon the relative angular momentum of the two particles. Thus, the charge parity becomes the same as in the π + π case, as given by Equation (2), and the reaction,

p ¯ p( 3 S 1 ) π L 0 π S 0 ( P 1 ) (4)

is allowed.

3. Need for Two Neutral Pions to Explain Anomalous Branching Ratios

When an antiproton or some other negatively charged particle slows down in liquid H2 it is typically captured into a Bohr orbit by a proton at a principle quantum number n30 and with high orbital angular momentum, X . The process is depicted in Figure 1. Collisional deexcitations and radiative transitions transform the atom to lower n and lower X values, allowing the electrically neutral atom to penetrate neighboring atoms and experience the electric field of the protons. This causes Stark effect transitions between the degenerate orbital angular momentum states. The rates for radiative transition and nuclear absorption (or annihilation) from P states are small in comparison with the rate at which the Stark effect populates the S state. Because S-state absorption (or annihilation) can occur from high n values, the atom is unlikely to deexcite to low n values for which P state nuclear absorption (or annihilation) is more important.

Figure 1. Levels of atomic orbital states for a negatively charged particle and a proton with principle quantum number n and orbital angular momentum X . It shows the effect of Stark transitions on different X states, radiative deexcitations, and levels from which nuclear absorption or annihilation are likely.

Thus, according to theory [2] [3] absorption occurs predominantly from S states for π and K . In 1960, Desai [4] concluded, “Rough calculations indicate that for protonium also the capture will take place predominantly from S states.”

There is also strong experimental evidence that S-state capture dominates in liquid H2. The π p [5] [6], K p [7] [8], and Σ p [9] reactions have been studied. Since these negatively-charged particles decay, the nuclear absorption time can be determined by observing the fraction that decay. The cascade times are approximately two orders of magnitude shorter than those required for radiative deexcitation. Because the antiproton does not decay, such a measurement is not possible. Since the short cascade times for π , K , and Σ cannot be explained without recourse to the Stark effect, the Stark effect must also play a role in the p ¯ p case.

There is some direct evidence of S-state dominance in p ¯ p reactions. It has been determined [10] that p ¯ pKK<6% from P states with a 95% confidence level. From the ρ decay angular distribution, it has been determined [11] [12] that p ¯ p π + π π 0 <5% from P states. Thus, the experimental evidence strongly supports S-state domination for p ¯ p reactions.

We first examined the experimental results for p ¯ pππ . In liquid hydrogen the branching ratio for p ¯ p π + π is (32 ± 1) × 10−4 [13] [14], and measurements of the branching ratio for p ¯ p π 0 π 0 are given in Table 4.

The experimental results obtained using the Crystal Barrel detector are likely to be the most accurate. As they noted in their paper [20], “Owning to our large detection efficiency and small background our result is least likely influenced by undetected systematic errors. The reliability of the result is strengthened by the internal consistency of a large set of two-body branching ratios measured with the Crystal Barrel detector and their agreement with previous determinations, especially with bubble chamber data.”

Assuming that the two π 0 ’s in the reaction p ¯ p π 0 π 0 are identical, one can calculate the fraction of annihilations proceeding from P states, P LH ( ππ ) , for p ¯ pππ as follows,

P LH ( ππ )= BR ( p ¯ p π + π ) P +BR ( p ¯ p π 0 π 0 ) P BR ( p ¯ p π + π ) S&P +BR ( p ¯ p π 0 π 0 ) P . (5)

Assuming charge independence,

BR ( p ¯ p π + π ) P =2×BR ( p ¯ p π 0 π 0 ) P , (6)

We obtain the % proceeding from P states which is given in Column 2 of Table 4. The result of 48% proceeding from P states, shown in Table 4 (Crystal Barrel collaboration), is anomalously high.

Table 4. Branching ratio for p ¯ p π 0 π 0 .

Measured value

% from P states

Year

Reference

(4.8 ± 1.0) × 10−4

39%

1971

Devons et al. [15]

(1.4 ± 0.3) × 10−4

13%

1979

Bassompierre et al. [16]

(6 ± 4) × 10−4

47%

1983

Backenstoss et al. [17]

(2.06 ± 0.14) × 10−4

18%

1987

Adiels et al. [18]

(2.5 ± 0.3) × 10−4

22%

1988

Chiba et al. [19]

(6.93 ± 0.43) × 10−4

53%

1992

Crystal Barrel [20]

(2.8 ± 0.4) × 10−4

24%

1998

Obelix [21]

(6.14 ± 0.40) × 10−4

48%

2001

Crystal Barrel [14]

We now consider antiproton annihilation in deuterium. By studying the reactions p ¯ d π π + n and p ¯ d π π 0 p in a liquid deuterium bubble chamber, Gray et al. [22] reported that (75 ± 8)% of the annihilations originate from P states. The quantity measured is,

r= BR( p ¯ d π π 0 p ) BR( p ¯ d π + π n ) . (7)

The percentage proceeding from P states was then calculated using charge independence,

BR( p ¯ d π + π n )= 1 2 BR( p ¯ d π π 0 p )+2×BR( p ¯ d π 0 π 0 n ), (8)

and

P LD ( ππ )= 3BR( p ¯ d π 0 π 0 n ) BR( p ¯ d π + π n )+BR( p ¯ d π 0 π 0 n ) , (9)

resulting in,

P LD ( ππ )= 3( 2r ) 6r . (10)

Equation (9) is based on the theoretical argument that p ¯ d π 0 π 0 n cannot occur from an atomic S state. This argument is identical to that presented in Sec. 2 for the reaction p ¯ p π 0 π 0 .

The results of Gray et al. [22] and two other groups are listed in Table 5. The experimental results of Bridges et al. [23] using a magnetic spectrometer are in close agreement with those of Gray et al. [22]; however, the high statistics experiment of Angelopoulos et al. [24] using a magnetic spectrometer is consistent with a P-state fraction of 0%. Reifenröther and Klempt [25] noted that this low value [24] could have been caused by the tight cut on the colinearity of the π + π pair used. A cut that is too tight can result in π + π pairs being lost. Gray et al. [22] used a cut angle of 16 degrees, Bridges et al. [23] used 10 degrees, and Angelopoulos et al. [24] used 5 degrees.

We performed a Monte Carlo calculation of the expected deviation from the colinearity of the π + π pairs for the reaction p ¯ d π + π n . We used the

Table 5. Ratio BR( p ¯ d π π 0 p )/ BR( p ¯ d π + π n ) .

Measured value

Method

% from P states

Year

Reference

(0.68 ± 0.07)

deuterium

75%

1973

Gray et al. [22]

bubble

chamber

(0.70 ± 0.05)

magnetic

74%

1986

Bridges et al. [23]

(0.55 ± 0.05)

spectrometer

80%

1986

Bridges et al. [23]

(2.07 ± 0.05)

magnetic

0%

1988

Angelopoulos et al. [24]

spectrometer

neutron momentum distribution shown in Figure 2(a), which was derived from the results obtained by Gray et al. [22]. (See Fig. 1c of Ref. [22] and Fig. 5 of Ref. [23].) The calculated angular deviation from colinearity, plotted in Figure 2(b), shows that a significant fraction of the pairs extending beyond 5 degrees. Our correction factor for pairs beyond 5 degrees is 1.58, whereas that used in Ref. [24] was 1.13. Using this new correction factor results in r=1.48 and P LD ( ππ )=34% , which is in good agreement with the first two experiments.

Figure 2. (a) Neutron momentum distribution in reaction p ¯ d π + π n at rest, derived from result of Gray et al. [22]. (b) Monte Carlo calculation of number of π + π pairs versus their angular deviation from colinearity in reaction p ¯ d π + π n . Vertical line is at 5 degree cutoff.

Reifenröther and Klempt [25] have suggested a modification which includes the measured ratio (1.33) of p ¯ p to p ¯ n in D 2 . This reduces the 75% from P states to 55%. With considerations similar to those of Equations (11)-(13) shown below, they obtain an f P of 45%.

Efforts were made to resolve the discrepancies in p ¯ pππ by lowering the P-state fraction inferred from the measured branching ratios. Doser et al. [26] suggested that the total P-state fraction might be lower than that given by Equation (5), and it was just that the branching ratio into two pions (rather than into other particles) was greater from P states than that from S states. In support of this idea, Doser et al. [26] measured the branching ratio for p ¯ p π + π from a pure P state (by detection of the reaction in coincidence with transition X-rays) to be (4.81 ± 0.49) × 10−3.

The P-state annihilation fraction, f P , can be calculated as follows [25] [27],

BR( p ¯ p π + π )=( 1 f P ) B 0 + f P B 1 , (11)

BR( p ¯ p π 0 π 0 )= 1 2 f P B 1 , (12)

BR ( p ¯ p π + π ) X = B 1 . (13)

where B 0 and B 1 are the branching-ratio coefficients (independent of density) from S and P states, respectively.

Using the Crystal Barrel collaboration result [14] and Doser et al. [26] for BR ( p ¯ p π + π ) X , one obtains B 1 =4.81× 10 3 from Equation (13) and f P =26% from Equation (12).

Batty [27] discovered an interesting mechanism for further reducing this percentage. He introduced the enhancement of annihilations from fine-structure states over that expected from a statistical population. He modified the earlier calculations of Reifenröther and Klempt [25] using the Borie and Leon model [28] to incorporate enhancement factors. With these enhancement factors, Equations (11)-(13) become,

BR( p ¯ p π + π )=( 1 f P ) 3 4 E( 3 S 1 )B( 3 S 1 ) + f P [ 1 12 E( 3 P 0 )B( 3 P 0 )+ 5 12 E( 3 P 2 )B( 3 P 2 ) ], (14)

BR( p ¯ p π 0 π 0 )= 1 2 f P [ 1 12 E( 3 P 0 )B( 3 P 0 )+ 5 12 E( 3 P 2 )B( 3 P 2 ) ], (15)

BR ( p ¯ p π + π ) X = 1 12 B( 3 P 0 )+ 5 12 B( 3 P 2 ). (16)

The enhancement factors E( 3 S 1 ) and E( 3 P 2 )1.0 for all densities while the enhancement factor for the   3 P 0 state, E( 3 P 0 )1.0 at low density and increases to 2.076 to 2.556 (depending upon the model used in the calculation) at liquid H2 density. To reduce f P , Batty assumed B( 3 P 0 )B( 3 P 2 ) , but his result, f P =10 to 12%, is still at least a factor of two too high. This reduction depends strongly on the choice of parameters. For example, if we take B( 3 P 0 )=B( 3 P 2 ) , f p would only be reduced to 20%. Thus, Batty’s mechanism is not sufficiently large to remove the discrepancy in the p ¯ pππ case. In addition, the enhancement factors are not effective in reducing the discrepancy in the p ¯ dππN case [29] as the predicted enhancement factors are approximately 1.

In summary, if we assume that the two π 0 ’s are identical, the branching ratios for the reactions p ¯ pππ and p ¯ dππN indicate a fraction proceeding from P states that is 4 to 8 greater than that occurring in other reactions. However, if the two π 0 ’s are not identical, reactions can occur from S states and the anomaly is eliminated.

4. New Interpretation of Tsai-Chü et al. Results

In the 1960s Tsai-Chü et al. [30] [31] found evidence of a second neutral pion with some surprising properties. They placed stacks of K-5 emulsions in the antiproton beam of the Berkeley Bevatron and looked for multi-prong stars. They were surprised to see many electrons coming from some of the annihilation vertices.

Through charge exchange some of the antiprotons were converted to antineutrons. Notably, one star caused by antineutron annihilation produced 12 electrons [30]. The analysis showed that electrons (four each) came from three neutral particles, with masses of 136 ± 14, 135 ± 14, and 136 ± 13 MeV. The likelihood of three ordinary neutral pions decaying with double Dalitz pairs is exceedingly rare, at less than 10−13.

From an analysis of 15 antinucleon annihilation stars, Tsai-Chü et al. [31] reported the following properties for this second neutral pion: 1) It has a mass of the same order as the usual π 0 , 2) it is emitted with the same energy as that of a charged pion, 3) it decays more frequently into electron pairs and into double pairs, 4) the electron pairs from this second π 0 have larger opening angles than those of Dalitz pairs, and 5) it has a very short lifetime (much shorter than the usual π 0 ) because the electrons are emitted directly from the origin of the stars.

More recent experiments using improved low-energy antiproton beams annihilating in liquid hydrogen and deuterium have not shown the emission of electron pairs with these characteristics. This raises the question: What was happening in those experiments of Tsai-Chü et al.? A plausible explanation is that this second neutral pion has a lifetime that is so short that it occasionally decays before it can leave the annihilation nucleus of the emulsion, for example, Ag nucleus. This is illustrated in Figure 3.

The primary decay mode of this second neutral pion must be π S 0 2γ because this is the detection method for π 0 [14] in p ¯ p π L 0   π S 0 experiments. The probability of creation of electron pairs by π 0 photons is very high inside the nucleus. This explains the appearance of electrons in heavy-nuclei annihilations but not in hydrogen and deuterium annihilations. The opening angles for pairs produced by high-energy photons on nuclei [32] are wider than those from Dalitz pairs and the distribution of angles is in reasonable agreement with the result given in Table III of Tsai-Chü et al. [31].

Analysis of Tsai-Chü et al.’s results suggests that the annihilations that produce these electrons occur in 1% to 10% of annihilation stars. Assuming one π S 0 per

Figure 3. Illustration of proposed method by which second neutral pion appears to decay into four electrons. The π S 0 decays inside the annihilation nucleus and its photons produce the observed electrons by pair production. Since π S 0 must decay inside the nucleus, this process requires a lifetime ∼10−21 s or less.

star, the estimated lifetime ranges from 10−21 s to 10−22 s. According to the uncertainty principle, this corresponds to a width is between 0.7 MeV and 7 MeV. The lifetime of π S 0 cannot be significantly shorter than 10−22 s, as it would have been evident in the missing mass spectra for reactions such as p ¯ p π + π π S 0 . A broad resonance at m π 0 would appear significantly different from the detected, narrow π 0 peak.

5. Experimental Tests

Although seven different groups measured the branching ratio for p ¯ p π 0 π 0 , showing the importance of this unexpectedly large branching ratio, no direct test has been performed to determine whether the reaction could be occurring from an atomic S state. Such a test could be conducted by establishing an initial p ¯ p atomic S state and observing the π 0 π 0 final state. The method is illustrated in Figure 4. As discussed earlier, in liquid H 2 the Stark effect causes transitions to S states at high n-values, where annihilation occurs more readily than deexcitation. One can decrease the effect of Stark transitions by using H2 gas at STP, and thereby observe the deexcitation radiation.

The coincidence of the L and K X-rays from protonium shows that the atom is in the 1S state. The energy of the K X-rays is between 9.4 KeV ( K α ) and 12.5 KeV ( K ), while energy of the L X-rays is between 1.7 KeV and 3.1 KeV. The energy of M X-rays is between 0.5 KeV and 1.3 KeV. Thus, X-rays from different transitions tend to be distinguishable.

The Asterix Collaboration detected K α X-rays coinciding with L X-rays [33]. Our proposed experiment mirrors their setup but adds the complexity of requiring

Figure 4. Test for p ¯ p π L 0 π S 0 from S state. It shows radiative cascades to the 1S state which involve L and K X-rays followed by annihilation.

the triple coincidence of L and K X-rays from protonium and the π 0 π 0 annihilation mode. The detection of such events proves that the annihilation reaction occurs from an atomic S state.

It should be noted that some vector mesons can decay into π L 0 π S 0 if the   3 S 1 state of protonium can, because certain vector mesons also have J=1 , parity = −1, and charge parity = −1. We considered the π L 0 π S 0 decay mode of the ρ (770) 0 , ω( 782 ) , ϕ( 1020 ) , and J/ψ ( 1S ) . This decay mode of the ω( 782 ) , ϕ( 1020 ) , and J/ψ ( 1S ) is forbidden by G-parity conservation, but it can proceed electromagnetically. In estimating the branching ratios, we assumed that the π L 0 π S 0 mode would occur at approximately the same rate as the π + π mode, but reduced by a factor of two.

The ρ ( 770 ) 0 has I=1 , so the reaction ρ ( 770 ) 0 π + π is allowed by isospin conservation because the π + π system can have I=0,1 or 2. The reaction ρ ( 770 ) 0 π 0 π 0 is forbidden for the usual π 0 because the π 0 π 0 system can only have I=0 or 2. Occurring electromagnetically, the branching ratio is reduced by a factor α 2 . Assuming that π S 0 has isospin 1, reaction ρ ( 770 ) 0 π L 0 π S 0 is similarly suppressed. This assumption is crucial for otherwise the reaction would have occurred readily.

Our estimated branching ratios are,

BR( ρ ( 770 ) 0 π L 0 π S 0 )=5× 10 5 , BR( ω( 782 ) π L 0 π S 0 )=1× 10 2 , BR( ϕ( 1020 ) π L 0 π S 0 )=4× 10 5 , BR( J/ψ ( 1S ) π L 0 π S 0 )=7× 10 5 . (17)

The only measured upper limit [34], BR( ϕ( 1020 ) π 0 π 0 )<4× 10 5 , was in the expected range. The search for the decay mode, ω( 782 ) π L 0 π S 0 with an expected branching ratio of 1 × 10−2 is particularly compelling. It is already known that ω( 782 ) decays into undetermined neutrals with branching ratio between 1.8 × 10−3 and 1.4 × 10−2.

The results of Tsai-Chü et al. [30] [31] suggest another test that could allow a determination of the lifetime of this second π 0 . By varying the mass number, A, of the target material in low-energy antiproton annihilation, one should be able to observe the increase in electron-positron pairs (as A increases) from the decay of π S 0 ’s inside the annihilation nucleus.

6. Conclusions

This has been a phenomenon driver investigation. The anomalous results for the reactions p ¯ pππ and p ¯ dππN strongly indicate the existence of two distinct π 0 ’s. The results of Tsai-Chü et al. provide direct evidence of a different kind of π 0 . With our reinterpretation of their results, it is not surprising that this second π 0 has not been noticed in other reactions, because the major difference between it and the other π 0 is its much shorter lifetime.

The quark structure of the two neutral pions, π L 0 and π S 0 , should be related to each other as that of the K L 0 and K S 0 which is,

K S 0 = ( d s ¯ s d ¯ ) 2 , K L 0 = ( d s ¯ +s d ¯ ) 2 . (18)

Thus, we have,

π S 0 = ( u u ¯ d d ¯ ) 2 , π L 0 = ( u u ¯ +d d ¯ ) 2 . (19)

In addition, antinucleon-annihilation reactions suggest the concurrent production of π L 0 and π S 0 , mirroring the production patterns observed for K L 0 and K S 0 .

Because the main difference between the two neutral pions is that one has a lifetime ∼10−16 s while the other has a lifetime from 10−21 s to 10−22 s, one might think that this short-lived π 0 would have been detected in the π 0 lifetime measurements [35]. However, because the usual π 0 has such a short lifetime, it is difficult to separate it from one with a shorter lifetime. In addition, because the experimenters were not looking for a prompt decaying π S 0 , they often eliminated prompt signals as unwanted background.

For example, the experiment of Atherton et al. [36] was designed such that the measurement of the mean decay length would not be affected by prompt decays such as ηγγ . In their ratio R = [Y(250) − Y(45)]/[Y(250) − Y(0)] the positrons from prompt decays, which are not dependent on foil separation, are cancelled. Shwe et al. [37] ignored prompt decays to eliminate confusing backgrounds. As they noted, “Among the events missed or unmeasured were... Events with very small gaps which lie within the ‘circle of confusion’ around the star center.” Stamer et al. [38] worked with the K + π + π 0 decay at rest, and their histogram of number of decays versus the gap shows a very large peak in the 0 to 0.5 micron bin that could contain half prompt decays by a short-lived π S 0 .

One of the most accurate methods of measuring the π 0 lifetime is based on the Primakoff effect, which involves coherent photoproduction of π 0 ’s in the Coulomb field of nuclei. Unlike other techniques, this method is heavy on theory. Although the results do not indicate a short-lived π 0 , this method may not be appropriate for a second π 0 that decays by a mechanism in the 10−21 s to 10−22 s range.

Finding this elusive, short-lived second neutral pion is paramount. We have suggested some tests in Sec. 5 which can prove the existence of two distinct π 0 ’s and some tests to confirm the existence of a π S 0 with a very short lifetime.

Acknowledgements

I gratefully acknowledge the helpful discussions with Prof. J. E. Kiskis.

Conflicts of Interest

The author declares no conflicts of interest regarding the publication of this paper.

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