<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">WJM</journal-id><journal-title-group><journal-title>World Journal of Mechanics</journal-title></journal-title-group><issn pub-type="epub">2160-049X</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/wjm.2016.68020</article-id><article-id pub-id-type="publisher-id">WJM-70144</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Engineering</subject><subject> Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  Determination of Shear Center of Arbitrary Cross-Section
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Hiroaki</surname><given-names>Katori</given-names></name><xref ref-type="aff" rid="aff1"><sub>1</sub></xref></contrib></contrib-group><aff id="aff1"><label>1</label><addr-line>Department of Vehicle System Engineering, Faculty of Science and Technology, Meijo University, Nagoya, Japan</addr-line></aff><author-notes><corresp id="cor1">* E-mail:</corresp></author-notes><pub-date pub-type="epub"><day>04</day><month>08</month><year>2016</year></pub-date><volume>06</volume><issue>08</issue><fpage>249</fpage><lpage>256</lpage><history><date date-type="received"><day>23</day>	<month>July</month>	<year>2016</year></date><date date-type="rev-recd"><day>accepted</day>	<month>26</month>	<year>August</year>	</date><date date-type="accepted"><day>29</day>	<month>August</month>	<year>2016</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  In structural analysis, it is often necessary to determine the geometrical properties of cross section. The location of the shear center is greater importance for an arbitrary cross section. In this study, the problems of coupled shearing and torsional were analyzed by using the finite element method. Namely, the simultaneous equations with respect to the warping, shear deflection, angle of torsion and Lagrange’s multipliers are derived by finite element approximation. Solving them numerically, the matrix of the shearing rigidity and torsional rigidity is obtained. This matrix indicates the coupled shearing and torsional deflection. The shear center can be obtained determining the coordinate axes so as to eliminate the non-diagonal terms. Several numerical examples are performed and show that the present method gives excellent results for an arbitrary cross section.
 
</p></abstract><kwd-group><kwd>Shear Center</kwd><kwd> Finite Element Method</kwd><kwd> Structural Analysis</kwd><kwd> Beam Theory</kwd><kwd> Shear-Torsion Coupling Problem</kwd><kwd> Shear Deformation</kwd><kwd> Elasticity</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>Beam theory is often used in the analysis of many structures in the initial design stage, including machinery, ships, and vehicles. Because beams are three-dimensional (3D) elastic bodies, their behavior must be calculated on the basis of 3D elasticity theory if it is to be calculated precisely. However, there are several difficulties involved in calculating an exact solution. Thus, current beam theory is systematized under the assumption that beams are long, thin structures, with cross-sectional dimensions that are very small with respect to their lengths [<xref ref-type="bibr" rid="scirp.70144-ref1">1</xref>] . This theory for the beam was derived from the assumption of the cross-section invariant. Several geometric constants are very important when performing analysis based on the beam theory: these constants are cross- section-specific and are determined by the crosssection’s shape and dimensions.</p><p>One of these constants is the shear center, defined as the point at which a beam’s flexural deformation can be separated from its torsional deformation. The shear center is significant for the mechanical behavior of beams, and so it must be determined correctly in advance of analysis. Various definitions of the shear center discussed in Fung [<xref ref-type="bibr" rid="scirp.70144-ref2">2</xref>] . Namely</p><p>1) Setting the shear center as the point of action of the resultant of the shearing stresses in the section;</p><p>2) Setting the shear center as the point of the torsion-free bending on the basis of the strain energy considerations [<xref ref-type="bibr" rid="scirp.70144-ref3">3</xref>] ; and</p><p>3) Setting the shear center as the point where, in the flexural-torsional problem, the axial force of the torsion arise [<xref ref-type="bibr" rid="scirp.70144-ref4">4</xref>] .</p><p>However, it is difficult to accurately determine the location of the shear center in beams of arbitrary cross- sectional shapes; the cross-sectional shapes for which it can be determined are quite limited. Thus, a practical calculation method is sought that can determine the shear center and other cross-sectional constants for beams of arbitrary cross-sectional shape. Analysis using the finite element method (FEM) is practical and useful, and extremely beneficial in the initial design of beam structures based on beam theory. IN [<xref ref-type="bibr" rid="scirp.70144-ref5">5</xref>] , Katori has proposed a method to determine the shear center of the thin-walled cross-section by FEM.</p><p>Therefore, starting with the assumption of the cross-section invariant, we show here a practical, FEM-based calculation method for determining the shear center of a beam of arbitrary cross-sectional shape. The first, we discuss the shear-torsion coupling problem for beams of arbitrary cross-sectional shape based on Saint-Venant’s theorem [<xref ref-type="bibr" rid="scirp.70144-ref6">6</xref>] . In order to determine the relationship between shear deflection and shear force in this coupling problem, we treat it as a stationary value problem with subsidiary conditions, and derive simultaneous equations for warping, shear deflection, torsion angle, and undetermined Lagrange multipliers by means of a finite element approximation. We then solve this to derive a 3 &#215; 3 matrix of flexural rigidity versus torsional rigidity represent- ing the coupling of shear deflection and torsion. We determine the shear center by defining the coordinate axis such that the elements representing the coupling of shear and torsion in this matrix, (1, 3) and (2, 3), become zero.</p></sec><sec id="s2"><title>2. Theory</title><sec id="s2_1"><title>2.1. Finite Element Analysis of the Shear-Torsion Coupling Problem in Beams</title><p>In a straight beam of uniform cross section of the type shown in <xref ref-type="fig" rid="fig1">Figure 1</xref> is considered. The x-axis is the longitudinal centroidal axis, while they- and z-axes are set according to the right-handed system. In bending of beam, the cross section remains plane as is assumed in the elementary theory. Vlasov is the assumption of the cross section invariant is the starting point. Here, we formulate our equations based on his assumption of the cross section invariant. This assumption can be made from two standpoints: 1) the assumption of rigid cross sections and 2) the assumption of planar stress-free cross sections. Here, the taking assumption of rigid cross sections. therefore, we make the following reasonable assumption: the strain components<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x6.png" xlink:type="simple"/></inline-formula>, and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x7.png" xlink:type="simple"/></inline-formula> at all points in the beam. Based on this assumption, deriving the directional displacements v and w in the y- and z-axes at an arbitrary point on the beam gives us the following:</p><disp-formula id="scirp.70144-formula1227"><label>(1)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x8.png"  xlink:type="simple"/></disp-formula><p>where <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x9.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x10.png" xlink:type="simple"/></inline-formula> are the displacement components of the centroid in the y and z directions, and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x11.png" xlink:type="simple"/></inline-formula> is the angle of rotation of the cross section about the x-axis.</p><p>Next, an x-axis displacement of the beam should accompany the cross-sectional displacement given by Equation (1). This x-axis displacement is approximated over each element e by</p><disp-formula id="scirp.70144-formula1228"><label>(2)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x12.png"  xlink:type="simple"/></disp-formula><p>where u is the vector of nodal values u<sub>i</sub> of u for the element and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x13.png" xlink:type="simple"/></inline-formula> is a vector of the shape functions N<sub>i</sub>.</p><p>In the following equation, the shear strains generated in the crosssection of the beam <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x14.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x15.png" xlink:type="simple"/></inline-formula> are expressed in terms of the displacement components u, v, and w:</p><disp-formula id="scirp.70144-formula1229"><label>(3)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x16.png"  xlink:type="simple"/></disp-formula><fig id="fig1"  position="float"><label><xref ref-type="fig" rid="fig1">Figure 1</xref></label><caption><title> Coordinate system of an elastic beam</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-4900424x17.png"/></fig><p>By substituting Equations (1)-(2) into Equation (3), the shear strains <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x18.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x19.png" xlink:type="simple"/></inline-formula> can be expressed as follows:</p><disp-formula id="scirp.70144-formula1230"><label>(4)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x20.png"  xlink:type="simple"/></disp-formula><p>where a prime denotes derivation with respect to x, that is <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x21.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x21.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x22.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x21.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x22.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x23.png" xlink:type="simple"/></inline-formula> represent the derivation with respect to y and z of the shape function, respectively.</p><p>The strain energy U of per unit length along the x-axis is found by evaluating the following integral:</p><disp-formula id="scirp.70144-formula1231"><label>(5)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x24.png"  xlink:type="simple"/></disp-formula><p>The potential energy L for the external forces meanwhile is given as follows</p><disp-formula id="scirp.70144-formula1232"><label>(6)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x25.png"  xlink:type="simple"/></disp-formula><p>where Q<sub>y</sub> and Q<sub>z</sub> are the shear forces in they and z directions, respectively, and M<sub>x</sub> is the torsional moment.</p><p>Let us now consider how to minimize the total potential energy <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x26.png" xlink:type="simple"/></inline-formula> under the following conditions.</p><p>The axial stress can be expressed as follows when the beam is subjected to axial forces P and moments (M<sub>y</sub>, M<sub>z</sub>)</p><disp-formula id="scirp.70144-formula1233"><label>(7)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x27.png"  xlink:type="simple"/></disp-formula><p>The warping u by shear and torsion is independent of the u due to axial force and bending</p><disp-formula id="scirp.70144-formula1234"><label>(8)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x28.png"  xlink:type="simple"/></disp-formula><p>Substitute of Equation (7) into Equation (8) and the integrals of Equation (8), in terms of the warping u, become</p><disp-formula id="scirp.70144-formula1235"><label>(9)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x29.png"  xlink:type="simple"/></disp-formula><p>At this time we make use of the method of the Lagrange multiplier. That is, we multiply Equation (9) by an undetermined constant <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x30.png" xlink:type="simple"/></inline-formula> (the Lagrange multiplier) and add Equation (5), (6) and (9) to get:</p><disp-formula id="scirp.70144-formula1236"><label>(10)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x31.png"  xlink:type="simple"/></disp-formula><p>The stationary condition for <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x32.png" xlink:type="simple"/></inline-formula> in Π<sub>1</sub> in the above equation becomes the following:</p><disp-formula id="scirp.70144-formula1237"><label>(11)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x33.png"  xlink:type="simple"/></disp-formula><p>Thus,</p><disp-formula id="scirp.70144-formula1238"><label>(12)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x34.png"  xlink:type="simple"/></disp-formula><p>in which</p><disp-formula id="scirp.70144-formula1239"><label>(13)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x35.png"  xlink:type="simple"/></disp-formula><p>Writing an inverse matrix of the left-hand-side matrix of Equation (12) as</p><disp-formula id="scirp.70144-formula1240"><label>(14)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x36.png"  xlink:type="simple"/></disp-formula><p>Thus, according to Equation (12)</p><disp-formula id="scirp.70144-formula1241"><label>(15)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x37.png"  xlink:type="simple"/></disp-formula><p>From Equation (15), the following relationship can be derived easily</p><disp-formula id="scirp.70144-formula1242"><label>(16)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x38.png"  xlink:type="simple"/></disp-formula><p>In addition, the warping u in the x-axis generated by shear force and torsional moment can be obtained via Equation (15)</p><disp-formula id="scirp.70144-formula1243"><label>(17)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x39.png"  xlink:type="simple"/></disp-formula></sec><sec id="s2_2"><title>2.2. Shear Center</title><p>Converting the above displacement of and force acting on the centroid to an arbitrary point (y<sub>s</sub>, z<sub>s</sub>) in the cross- sectional plane (e.g., <xref ref-type="fig" rid="fig2">Figure 2</xref>) yields</p><fig id="fig2"  position="float"><label><xref ref-type="fig" rid="fig2">Figure 2</xref></label><caption><title> Centroid O and shear center S</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-4900424x40.png"/></fig><disp-formula id="scirp.70144-formula1244"><label>(18)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x41.png"  xlink:type="simple"/></disp-formula><p>Now replacing the relationship between shear force and shear deflection on the centroid in Equation (16) Using Equation (18), we arrive at the result:</p><disp-formula id="scirp.70144-formula1245"><label>(19)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x42.png"  xlink:type="simple"/></disp-formula><p>where</p><disp-formula id="scirp.70144-formula1246"><label>(20)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x43.png"  xlink:type="simple"/></disp-formula><p>The shear center is obtained by equating to zero the elements (1, 3) and (2, 3) of matrix D<sub>s</sub>, i.e.</p><disp-formula id="scirp.70144-formula1247"><label>(21)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x44.png"  xlink:type="simple"/></disp-formula><p>Where D<sub>ij</sub> is the (i, j)<sup>th</sup> element of<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x45.png" xlink:type="simple"/></inline-formula>, as defined in Equation (16).</p></sec></sec><sec id="s3"><title>3. Numerical Example</title><p>The procedures of the previous sections have been applied to two example problems. Calculations were performed using triangular linear elements, which are widely utilized in typical finite element analysis.</p><p>Example 1. Initially selecting the semicircular cross section of radius R as shown in <xref ref-type="fig" rid="fig3">Figure 3</xref>. We determined its shear center and compared it with other calculation results. In this analysis, calculations were performed after dividing the semicircular cross section into triangular elements, for a model with 108 nodes and 180 elements (Model I) and for a model with 186 nodes and 322 elements (Model II). <xref ref-type="table" rid="table1">Table 1</xref> presents a comparison positions of shear center in a semicircular cross section. Assuming that in-plane stress is zero, Timoshenko determined the shear center for a corrected semicircular cross section with reference to the shear stress distribution when a concentrated load was applied to the end of a cantilever beam with a circular cross section [<xref ref-type="bibr" rid="scirp.70144-ref7">7</xref>] . In addition, Kawai et al. [<xref ref-type="bibr" rid="scirp.70144-ref8">8</xref>] determined the shear center from simple calculations based on the assumption of cross-section invariant without the need for corrections such as Timoshenko’s. Furthermore, the basic equation and boundary conditions in the shear-torsion coupling problem shown by the authors in Reference [<xref ref-type="bibr" rid="scirp.70144-ref6">6</xref>] are as follows:</p><disp-formula id="scirp.70144-formula1248"><label>(22)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x46.png"  xlink:type="simple"/></disp-formula><p>The shear center (y<sub>s</sub>, z<sub>s</sub>) is thus derived as</p><disp-formula id="scirp.70144-formula1249"><graphic  xlink:href="http://html.scirp.org/file/3-4900424x47.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.70144-formula1250"><label>(23)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x48.png"  xlink:type="simple"/></disp-formula><p>The function <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x49.png" xlink:type="simple"/></inline-formula> satisfies Equation (22) in the case of a semicircular cross section</p><disp-formula id="scirp.70144-formula1251"><label>(24)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x50.png"  xlink:type="simple"/></disp-formula><p>where <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-4900424x51.png" xlink:type="simple"/></inline-formula> is the position of the centroid. The position of the shear center can be determined as follows</p><disp-formula id="scirp.70144-formula1252"><label>(25)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-4900424x52.png"  xlink:type="simple"/></disp-formula><p>These results differ from the results of our FEM-based analysis by less than 1%, suggesting our solution has sufficient accuracy in practice.</p><p>Example 2. Determine the shear center of a circular cross section with a circular notch shown in <xref ref-type="fig" rid="fig4">Figure 4</xref>. <xref ref-type="fig" rid="fig5">Figure 5</xref> shows the coordinates y/r for the shear center y<sub>s</sub> and centroid y<sub>c</sub>, for various ratios a/r of the radius r of the circular cross section versus the radius a of the circular notch. The figure also shows the results of the analsysis of Strongeand Zhang [<xref ref-type="bibr" rid="scirp.70144-ref9">9</xref>] . The resent analysis results are almost entirely consistent with theirs, supporting the validity of the present analysis method. <xref ref-type="fig" rid="fig6">Figure 6</xref> shows the distribution of warping u for ratios a/r of 0.2, 0.6, and 1.0 when the torsional moment M<sub>x</sub> has acted. Contour has become finer in the notch tip. This tendency is remarkable enough to a/r is smaller.</p></sec><sec id="s4"><title>4. Conclusion</title><p>This paper discussed a practical calculation method to address shear-torsion coupling. Based on the FEM, we proposed a method to analyze the shear-torsion coupling problem when analyzing beams with cross sections of arbitrary shape as a stationary value problem with subsidiary condition. Specifically, we constructed simultaneous equations for strain deflection, torsion angle, warping, and undetermined Lagrange multipliers,</p><fig id="fig3"  position="float"><label><xref ref-type="fig" rid="fig3">Figure 3</xref></label><caption><title> Semicircular cross section</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-4900424x53.png"/></fig><fig id="fig4"  position="float"><label><xref ref-type="fig" rid="fig4">Figure 4</xref></label><caption><title> Circular cross section with circular notch</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-4900424x54.png"/></fig><table-wrap id="table1" ><label><xref ref-type="table" rid="table1">Table 1</xref></label><caption><title> Shear center for semicircular cross section</title></caption><table><tbody><thead><tr><th align="center" valign="middle"  rowspan="2"  >Timoshenko</th><th align="center" valign="middle"  rowspan="2"  >Kawai et al. [<xref ref-type="bibr" rid="scirp.70144-ref8">8</xref>]</th><th align="center" valign="middle"  rowspan="2"  >Exact Equation (25)</th><th align="center" valign="middle"  colspan="2"  >Present</th></tr></thead><tr><td align="center" valign="middle" >Model I</td><td align="center" valign="middle" >Model II</td></tr><tr><td align="center" valign="middle" >0.511R</td><td align="center" valign="middle" >0.509R</td><td align="center" valign="middle" >0.509R</td><td align="center" valign="middle" >0.508R</td><td align="center" valign="middle" >0.509R</td></tr></tbody></table></table-wrap><fig id="fig5"  position="float"><label><xref ref-type="fig" rid="fig5">Figure 5</xref></label><caption><title> Coordinates of shear center and centroid of circular cross section with circular notch</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-4900424x55.png"/></fig><fig id="fig6"  position="float"><label><xref ref-type="fig" rid="fig6">Figure 6</xref></label><caption><title> Warping of twisted shaft with notched circular cross section. (a) a/r = 0.2; (b) a/r = 0.6; (c) a/r = 1.0</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-4900424x56.png"/></fig><p>using finite element approximations. We then solved this to derive a matrix of strain rigidity versus torsional rigidity. This matrix represents the coupling of shear deflection and torsion: we successfully determined the shear center by defining a coordinate axis such that non-diagonal terms in it disappeared. We analyzed a simple example using a calculation program created based on this analysis, and confirmed the usefulness of this technique.</p></sec><sec id="s5"><title>Acknowledgements</title><p>The author thanks the editor and the referee for their comments.</p></sec><sec id="s6"><title>Cite this paper</title><p>Hiroaki Katori, (2016) Determination of Shear Center of Arbitrary Cross-Section. 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