Now come the traditional hyperbolic equations [2] [3] :

1).

2).

3).

4).

Instead of these I found new equations, and we shall derive them. First come the new equations, and then their derivations.

5).

6).

The aim is that in the Equations ((1) and (2)) appear in hyperbolic equations to express the trigonometric equations.

The triangle:

7) See Figure 1, triangle OAD:.

8) See Figure 1, {radian}.

9) See Figure 1, triangle OAD, and Equation (7)):

.

The hyperbolic function was introduced into the mathematics on the analogy of Figure 1.

The hyperbola simplest form is:

See Figure 2:

10).

11).

12).

13) Grey area (). See Equation (3) and [3] :.

(Note: Figure 1 and Figure 2 can be found in [4] ).

14) Course Equation (10), is identical with Equation (7). See Equations ((7) and (10)):

Figure 3 = Figure 1 + Figure 2.

Figure 3: The point is that if we change the value of “v” the D and the H points position changes too. From D point situation depends the H point situation. That is to say, each point on the circle is assigned to a point of hyperbole. The value of the “j” and “x” variables defines the v variable size. The value of c is constant.

We shall express the () and () variables in the Equations ((1) and (2)) with new equations.

First we prove that:. After that we prove that. Then we substitute these in the Equations ((1) and (2)).

The allows to find connection between () and (). In fact, the connection is sought between the OAD triangle Figure 3 and OEG triangle Figure 3 and OFH triangle Figure 3.

Now follow the derivation of equation.

15) We substitute the Equation (14): into the Equation (9):

It is totally in accordance with the [5] and with the [6] :

{See Equation (14)}: }.

16) See Equation (15):

17) See Equation (16):

We got the first new equation. We can see that the variable and the variable depend of each other.

The variable determines the moving point position on the circle, while the variable determines the moving point position on the hyperbola. And as we mentioned, the variable and the variable depend only of the speed of v.

We shall later substitute the Equation (17) into the Equations ((1) and (2)). But before it, we shall derive the new equation of () variable which exist in the Equations ((1) and (2)).

In the Equation (14): allows to find connection between () and ().

18) Now comes equation cotan:

19) We substitute in the Equation (18), Equation (14): and

Equation (16):

20) See Equation (19): {radian}.

So we got our second new equation as well. That means that the and variables which appear in the Equations (1) and (2), are expressible by the trigonometric functions of the Equations (17) and (20).

21) We substitute the Equation (17) and Equation (20) into the Equation (2):

Note: Equation (8):

Equation (13):

It is one of most important equation of this work. It is distinct that the both sides of equation give the same result. So the hyperbolic Equation (2), we can substitute by a trigonometric equation.

It is very important to prove that the Equations ((17) and (20)) are correct. Further we will prove the correctness of Equations ((17) and (20)) in several different ways.

Now we check the correctness of the Equation (21). So by using the new equations we derive the know equation of Lorentz transformation. So follows the known equation of x':

22) Equation (21):

See Equation (9): and see Equation (7):

23) So:

Form the Equation (21) we got exactly the known equation of Lorentz transformation. So that means that the Equation (21) is correct. Here it is clearly visible that the point of the Equation (21) is the simplicity.

For the determination of ct' the same procedure is used.

24) Now come the Equation (1):

25) We substitute the Equation (17) and Equation (20) into the Equation (1):

Now we check the correctness of the Equation (25). By the usage the new Equation (25) it is derived the Lorentz transformation other know equation t'.

Here we use the same procedure as above by the equation x'.

26) See Equation (25):

27) See Equation (7):

See Equation (9):

28) So:

From the Equation (25) we got exactly the known equation of Lorentz transformation. So that means that the Equation (25) is correct. Here it is clearly visible that the point of the Equation (25) is the simplicity.

Equation (21):

Equation (25):

Minkowsi’s equation:

So that means that the Equation (21) and Equation (25) are correct. It is visible that we got simply the well- known Minkowsi’s equation.

The aim of this derivation is to check the correctness of the Equations ((21) and (25)).

On the Figure 4 the Figure 1 OAD triangle is simple drawn again. From this triangle are again derived the Equations ((21) and (25)), but here are used the equations of Lorentz transformation as well. The ct' equation won’t be derived again only the x' equation.

29) This derivation needs the visible equations from the “Appendix I” of the book [1] :

.

30) See Figure 4 and Equation (29):

Equations (17): (). It is totally in accordance with the [5] and with the [6] :

31) See Figure 4, and Equation (7):

32) See Figure 4 and Equation (29):

Equations (20): (). It is totally in accordance with the [5] and with the [6] :

().

33) We substitute the Equation (30) (), and Equation (32) (), and Equation (31) () into the Equation (29):.

It is visible that we got the same result with the equation () by Lorentz transformation, as above with the Equation (22).

So that means that the Equation (21), is correct.

In the references at the end of the work in the “Appendix I” of the book marked by number [1] the Lorentz transformation starts from the fact that it measures in the standing and movable coordinate system the same two oncoming light rays. In the mentioned book, there is given the other derivational way too, when from the standing coordinate system are measured the features of the movable coordinate system. It is written in [1] The behaviour of measuring-rods and clocks in motion chapter of the mentioned book.

In the following derivation we measure the same light-ray from the standing and moving coordinate system. Exclusively in this case can be used that we substitute in the Equation (28) the x = ct equality. The x = ct equality substitution in the Equation (28) is given in [1] Lorentz transformation chapter.

So the travelled distance of the light-ray in the standing coordinate system is x = ct. Naturally in the movable coordinate system the travelled distance of the light-ray is x' = ct'.

From now on we shall study the travel distance of the light-ray in the standing and movable coordinate system. This gives the opportunity to derive Minkowski’s equation. From the view of the special relativity theorem it is very important to derive the Minkowski’s equation from the Lorentz transformation

So we take the Equation (28) and pick out the (t) variable. (Note: (x = ct); (x/c) = t)

34) See Equation (28):

35) Equation (t'/t):

36) The equation can be found in every high school-level mathematic book.

For example, [4] :

37) We substitute Equation (7): () and Equation (9) into the Equation (36):

38) Course, the first member the Equation (37), is identical with Equation (35):

The Equation (38) can be found in [5] .

The third member the Equation (37) can be found in [7] .

In the introductory part we already mentioned, that it is very important that the equation is in accordance with Minkowski’s equation. Further on, we are going to deal with proving of it.

In further derivation we shall use the following equations from the Appendix I of the book [1] :

39) The equations:

40) From the last equations we express the and variables:

First of all, we calculate again the “a” and “b” variables of the Lorentz transformation from

formula.

Then by our “a” and “b” equations we derive the and variables. We will prove that and then by usage of Equation (40) we shall easily get Minkowski’s equation.

Now we continue the Equation (38).

Now we transform the Equation (38) so that we can determine the Lorentz transformation “a” and “b” variables.

41) We shall transform the Equation (38) and take the Equation (39) into account:

42) Taking in account the Equations ((41), and (30), (32)):

Equation (30):

Equation (32):

Note:

Equation (8):

Equation (13):

By this we proved that the and the hyperbolic equations are connected with each other.

We mustn’t forget that we started from the fact that we measure from the standing and movable coordinate system the two oncoming light-rays. In the standing coordinate system, the travelled distance of the light-ray is x = ct. From here we started, we substituted it in the Equation (28) and could not get other result. If we look closer the Equation (25) and substitute the equation x = ct, it gives the same result.

At the Equation (41) we wrote the equation. Now we write the mathematical equation too. And here we take into account the equations of (39). The equation got in this way, we shall later use for derivation of variables “” and “” in Lorentz transformation.

The second member of the Equation (37):

43) So:

.

The following derivation aim is to prove that: ()

Equation (39):

We express the and variables:

44) Variable:

45) Variable:

46) See Equations ((44) and (45)):

Equation (41):

47) See Equation ((46) and (41)):

48) We substitute Equation (46) () variable, in the Equation (44):.

Equation (43):

49) From the Equations ((47) and (48)), ():

So we calculated “” and “”.

The equations of “” and “” can be found at the Equation (40):

See equations of (49) and equations of (40):

With this we derived Minkowsi’s equation. We proved that Minkowsi’s equation is the integral part of the Lorentz transformation. With that, we proved the legitimacy of equation.

If Minkowski’s equation is expanded by coordinates “y” and “z”, then we get the four dimensional word logical equation [1] :

The reason why the equation can be expanded by “y” and “z” coordinates comes from the fact that the derivation of the Lorentz transformation starts from that simplification that all actions happen on the “x” axe.