<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">MSCE</journal-id><journal-title-group><journal-title>Journal of Materials Science and Chemical Engineering</journal-title></journal-title-group><issn pub-type="epub">2327-6045</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/msce.2016.44003</article-id><article-id pub-id-type="publisher-id">MSCE-66118</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Chemistry&amp;Materials Science</subject></subj-group></article-categories><title-group><article-title>
 
 
  Application of Finite Fourier Transform and Similarity Approach in a Binary System of the Diffusion of Water in a Polymer
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>isham</surname><given-names>A. Maddah</given-names></name><xref ref-type="aff" rid="aff1"><sub>1</sub></xref></contrib></contrib-group><aff id="aff1"><label>1</label><addr-line>Department of Chemical Engineering, King Abdulaziz University, Rabigh, Saudi Arabia</addr-line></aff><author-notes><corresp id="cor1">* E-mail:</corresp></author-notes><pub-date pub-type="epub"><day>25</day><month>04</month><year>2016</year></pub-date><volume>04</volume><issue>04</issue><fpage>20</fpage><lpage>30</lpage><history><date date-type="received"><day>4</day>	<month>April</month>	<year>2016</year></date><date date-type="rev-recd"><day>accepted</day>	<month>25</month>	<year>April</year>	</date><date date-type="accepted"><day>28</day>	<month>April</month>	<year>2016</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  This paper describes the method of two important mathematical techniques used in chemical engineering applications. Solving a mass transfer problem, weather in finite or semi-infinite domain, may seem difficult without the practice of Finite Fourier Transform (FFT) and Similarity Transformation. Finite systems refer to any closed system that has a specific boundary that can be determined. For example, polymer sheets, membranes, storage tanks, oil reservoirs and a human stomach are determined to be finite systems where FFT is applicable to derive expressions for concentration profiles of the materials in the system. However, Similarity Transformation method is used to identify the concentration profile in semi-infinite systems that have no limits. It has been approved that we may also use the similarity procedure for finite systems since our results are almost the same. Methodologies of both techniques have been discussed thoroughly in order to apply them to a water-polymer diffusion system for the determination of the concentration of water in a polymer sheet of PET. Discussion and comparison between FFT and similarity is included to illustrate the power of each mathematical procedure in predicting and modeling mass concentrations.
 
</p></abstract><kwd-group><kwd>Similarity</kwd><kwd> Fininte Fourier Transfrom</kwd><kwd> Modeling</kwd><kwd> Mass Transfer</kwd><kwd> Concentration Profile</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>Recent advancements in applied mathematics allow engineers to encounter mass transfer problems easier than before. Emerging mathematics with engineering is necessary to solve problems in chemical engineering such as the determination of a concentration profile of material A in a binary A-B system. Difficulty of the problem depends on how many terms are; we going to deal with after applying our assumptions to the continuity equation [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] .</p><p>For instance, steady state diffusion equations are usually easy to solve compared to unsteady state or convention related problems. Additionally, considering a reaction rate will make it even harder to carry out final solution. Thus, previous established techniques including Finite Fourier Transform (FFT) and Similarity Transformation show a promising way in solving mass transfer problems and predict an approximation to the concentration profile in mass transfer systems [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref2">2</xref>] . FFT is applied to finite systems while similarity is used to solve problems in a semi-infinite domain. However, similarity method is much easier than FFT and may be applied to a finite system under specific conditions [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref3">3</xref>] .</p><p>Finite Fourier transform (FFT) method is one of various analytical or numerical techniques in which exact or approximate solutions to partial differential equations are found by expanding the solution in terms of a set of known functions called basis functions, and then determining the unknown coefficients in the expansion [<xref ref-type="bibr" rid="scirp.66118-ref4">4</xref>] .</p><p>The FFT method is fundamentally comparable to the method of separation of variables discussed in many traditional books on mathematical methods in physics and engineering; for example, see Arpaci (1966), Butkov (1968), Carslaw and Jaeger (1959), Churchill (1963), and Morse and Feshbach (1953). However, the FFT method is more flexible and easy to apply with a more direct attack on many problems. The reader who is familiar with separation of variables will easily notice the differences and the improvements suggested by the FFT method, but prior experience to separation of variables is not necessary for what is presented here [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref4">4</xref>] .</p><p>The FFT is an alternative technique for solving nonhomogeneous initial boundary value problems in which time-dependent and time-independent problems are treated in exactly the same way. Also, the FFT practice can smoothly encounter and solve problems in higher dimensions. Strictly speaking, application of FFT to initial boundary value problems always follows the same pattern whether the problem is homogeneous or nonhomogeneous. The general FFT solution is always in the form of an infinite series. However, the generalized Fourier series of a simple function can show up as a part or all of the FFT solution. Thus, the FFT transform method shows its true flexibility in problems with nonhomogeneous PDEs and/or boundary conditions [<xref ref-type="bibr" rid="scirp.66118-ref2">2</xref>] .</p><p>The method of similarity (combination of variables) is useful for semi-infinite systems, such that the initial condition and the boundary condition at infinity may be combined into a single new boundary condition [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] . The similarity technique reduces a partial differential equation in two independent variables to an ordinary differential equation involving a single composite variable. Similarity analysis is applicable to certain problems in which the characteristic lengths are determined by rate processes, rather than by the geometric dimensions. In particular, the technique is applied to problems that generally involve regions which are regarded as being semi-infinite. The method may be used with linear and nonlinear problems [<xref ref-type="bibr" rid="scirp.66118-ref4">4</xref>] .</p><p>In this work, we would like to show the methodology of each technique and solve one common problem to identify the differences between both methods. A discussion section is included to confirm our results, understand the physical meaning of the equations and compare between both results for further purposes.</p></sec><sec id="s2"><title>2. Finite Fourier Transform</title><sec id="s2_1"><title>2.1. Methodology</title><p>1) Write the governing equation, initial and boundary conditions after applying the given assumptions.</p><p>2) Make the governing equation in a dimensionless form.</p><p>3) Write the initial and boundary conditions in dimensionless forms.</p><p>4) Define a new eigenvalue problem (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x6.png" xlink:type="simple"/></inline-formula>) from the dimensionless governing equation in Step (2) to get the transient solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x7.png" xlink:type="simple"/></inline-formula>); then solve for (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x8.png" xlink:type="simple"/></inline-formula>) by using FFT in <xref ref-type="table" rid="table1">Table 1</xref> depending on the boundary conditions.</p><p>5) Continue solving for the transient solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x9.png" xlink:type="simple"/></inline-formula>) by multiplying the dimensionless governing equation in</p><p>Step (2) by the solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x10.png" xlink:type="simple"/></inline-formula>) we get in Step (4) and take the integration <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x11.png" xlink:type="simple"/></inline-formula> for all terms. Note that we</p><p>take the integration with respect to the variable that we solved for in the eigenvalue problem (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x12.png" xlink:type="simple"/></inline-formula>) and here we have (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x13.png" xlink:type="simple"/></inline-formula>) because we solved for <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x14.png" xlink:type="simple"/></inline-formula> in our example.</p><p>6) Solve each integration independently; then, put everything back into the dimensionless governing equation in Step (2) and solve it analytically if possible.</p><table-wrap id="table1" ><label><xref ref-type="table" rid="table1">Table 1</xref></label><caption><title> Basis fuctions for certain eigenvalue problems in Cartesian coordiantes [<xref ref-type="bibr" rid="scirp.66118-ref4">4</xref>] </title></caption><table><tbody><thead><tr><th align="center" valign="middle" >Case</th><th align="center" valign="middle" >Boundary conditions</th><th align="center" valign="middle" >Basis functions<sup>*</sup></th></tr></thead><tr><td align="center" valign="middle" ></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x15.png" xlink:type="simple"/></inline-formula></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x16.png" xlink:type="simple"/></inline-formula></td></tr><tr><td align="center" valign="middle" ></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x17.png" xlink:type="simple"/></inline-formula></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x18.png" xlink:type="simple"/></inline-formula></td></tr><tr><td align="center" valign="middle" ></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x19.png" xlink:type="simple"/></inline-formula></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x20.png" xlink:type="simple"/></inline-formula></td></tr><tr><td align="center" valign="middle" ></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x21.png" xlink:type="simple"/></inline-formula></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x22.png" xlink:type="simple"/></inline-formula></td></tr></tbody></table></table-wrap><p><sup>*</sup>δ = Length or thickness, z = coordinate axis.</p><p>7) Write down the final transient solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x23.png" xlink:type="simple"/></inline-formula>).</p><p>8) Now, solve for the steady state solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x24.png" xlink:type="simple"/></inline-formula>); where<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x25.png" xlink:type="simple"/></inline-formula>; change in time is zero since<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x26.png" xlink:type="simple"/></inline-formula>.</p><p>9) Apply the formula <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x27.png" xlink:type="simple"/></inline-formula> to find the overall unsteady state solution.</p><p>10) Apply the dimensionless initial condition from Step (3) and the orthogonality property into Step (9) overall unsteady state solution and solve for the constant<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x28.png" xlink:type="simple"/></inline-formula>. You can solve for the constant <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x28.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x29.png" xlink:type="simple"/></inline-formula> by multiplying</p><p>all terms by the same function that remained in the summation and, then, take the integration <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x30.png" xlink:type="simple"/></inline-formula> for all terms and apply orthogonality.</p><p>11) Substitute the constant <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x31.png" xlink:type="simple"/></inline-formula> back into Step (9) and rewrite the overall specific solution of the unsteady state problem.</p></sec><sec id="s2_2"><title>2.2. An Example in Diffusion of Water in a Polymer</title><p>Assume that we have a polyethylene terephthalate (PET) tile that is stored for a time before extruding. PET will absorb moist (water) from the air and may plug the extruder when being processed. Therefore, we are interested in studying the concentration of water <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x32.png" xlink:type="simple"/></inline-formula> in the PET sheet. Solution to this problem is important because we need to determine how much water is diffused into the PET with respect to time and space [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref5">5</xref>] . Obviously, our system is finite and we can solve the problem by applying FFT method. We have a binary system of A and B in which we are studying the mass transfer of component A (water) into component B (PET). <xref ref-type="fig" rid="fig1">Figure 1</xref> shows a schematic to the problem with PET boundaries and assuming that there is diffusion from the topside only since the tile is very thin.</p><p>Step (1):</p><p>Let us start the solution by using the continuity equation in Cartesian coordinates <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x33.png" xlink:type="simple"/></inline-formula> since the PET tile is a plane system [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref6">6</xref>] .</p><disp-formula id="scirp.66118-formula2048"><label>(1)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x34.png"  xlink:type="simple"/></disp-formula><p>where; <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x35.png" xlink:type="simple"/></inline-formula>is the concentration of water in the PET tile, <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x35.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x36.png" xlink:type="simple"/></inline-formula>is diffusivity of A (water) into B (PET), <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x35.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x36.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x37.png" xlink:type="simple"/></inline-formula>is the reaction rate of A, <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x35.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x36.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x37.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x38.png" xlink:type="simple"/></inline-formula>is the velocity of component A in the x coordinate, t is the time and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x35.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x36.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x37.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x38.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x39.png" xlink:type="simple"/></inline-formula> are the Cartesian coordinates of the system.</p><p>Assumptions:</p><p>a) Mass transfer occurs by diffusion only (no convention).</p><p>b) Mass transfer is only in the z-direction.</p><p>c) No reaction.</p><p>Thus, Equation (1) becomes:</p><disp-formula id="scirp.66118-formula2049"><label>(2)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x40.png"  xlink:type="simple"/></disp-formula><p>Initial condition (I.C.):</p><fig id="fig1"  position="float"><label><xref ref-type="fig" rid="fig1">Figure 1</xref></label><caption><title> Schematic of the problem showing the system boundaries and that diffusion is only in z-direction</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-1740327x41.png"/></fig><disp-formula id="scirp.66118-formula2050"><label>(3)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x42.png"  xlink:type="simple"/></disp-formula><p>Boundary conditions (B.C.’s):</p><disp-formula id="scirp.66118-formula2051"><label>(4)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x43.png"  xlink:type="simple"/></disp-formula><p>Step (2):</p><p>Let <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x44.png" xlink:type="simple"/></inline-formula> to be the dimensional concentration of component A (water) [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref6">6</xref>] :</p><disp-formula id="scirp.66118-formula2052"><label>(5)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x45.png"  xlink:type="simple"/></disp-formula><p><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x46.png" xlink:type="simple"/></inline-formula>is the initial concentration of the water in the PET at<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x46.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x47.png" xlink:type="simple"/></inline-formula>. Make everything dimensionless and convert space and time into a dimensional form as follows [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref6">6</xref>] :</p><disp-formula id="scirp.66118-formula2053"><label>(6)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x48.png"  xlink:type="simple"/></disp-formula><p>where; <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x49.png" xlink:type="simple"/></inline-formula>refers to the PET tile thickness. The governing equation in Equation (2) becomes:</p><disp-formula id="scirp.66118-formula2054"><label>(7)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x50.png"  xlink:type="simple"/></disp-formula><p>Step (3):</p><p>Dimensionless I.C.:</p><disp-formula id="scirp.66118-formula2055"><label>(8)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x51.png"  xlink:type="simple"/></disp-formula><p>Dimensionless B.C’s.:</p><disp-formula id="scirp.66118-formula2056"><label>(9)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x52.png"  xlink:type="simple"/></disp-formula><p>We can write the dimensionless B.C.’s as follows:</p><disp-formula id="scirp.66118-formula2057"><label>(10)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x53.png"  xlink:type="simple"/></disp-formula><p>Step (4):</p><p>Define a new eigenvalue problem by selecting the term with the higher derivative order in Equation (7).</p><disp-formula id="scirp.66118-formula2058"><label>(11)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x54.png"  xlink:type="simple"/></disp-formula><p>where; <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x55.png" xlink:type="simple"/></inline-formula>is a constant and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x55.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x56.png" xlink:type="simple"/></inline-formula> is the defined eigenvalue function. Solving for <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x55.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x56.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x57.png" xlink:type="simple"/></inline-formula> gives:</p><disp-formula id="scirp.66118-formula2059"><label>(12)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x58.png"  xlink:type="simple"/></disp-formula><p>Applying dimensionless B.C.’s from Equation (9), Equation (10) or by using <xref ref-type="table" rid="table1">Table 1</xref> at<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x59.png" xlink:type="simple"/></inline-formula>, we get:</p><disp-formula id="scirp.66118-formula2060"><label>(13)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x60.png"  xlink:type="simple"/></disp-formula><p>where; n refers to the summation number and in the range<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x61.png" xlink:type="simple"/></inline-formula>; <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x61.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x62.png" xlink:type="simple"/></inline-formula>is defined from FFT as follows:</p><disp-formula id="scirp.66118-formula2061"><label>(14)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x63.png"  xlink:type="simple"/></disp-formula><p>Step (5):</p><p>Solving for the transient solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x64.png" xlink:type="simple"/></inline-formula>); multiply the dimensionless governing equation in Equation (7) by</p><p><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x65.png" xlink:type="simple"/></inline-formula>and integrate<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x66.png" xlink:type="simple"/></inline-formula>, this yield to:</p><disp-formula id="scirp.66118-formula2062"><label>(15)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x67.png"  xlink:type="simple"/></disp-formula><p>Step (6):</p><p>Solve the integration of each part in Equation (15) independently.</p><disp-formula id="scirp.66118-formula2063"><label>(16)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x68.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2064"><label>(17)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x69.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2065"><label>(18)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x70.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2066"><label>(19)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x71.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2067"><label>(20)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x72.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2068"><label>(21)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x73.png"  xlink:type="simple"/></disp-formula><p>Also, from <xref ref-type="table" rid="table1">Table 1</xref> and since we used the B.C.’s at <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x74.png" xlink:type="simple"/></inline-formula> from Equation (10) to determine the solution; we must have<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x74.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x75.png" xlink:type="simple"/></inline-formula>, (Case II), therefore:</p><disp-formula id="scirp.66118-formula2069"><label>(22)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x76.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2070"><label>(23)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x77.png"  xlink:type="simple"/></disp-formula><p>Plug Equations (21), (22) and (23) into Equation (17), then plug Equations (16) and (17) into Equation (15).</p><disp-formula id="scirp.66118-formula2071"><label>(24)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x78.png"  xlink:type="simple"/></disp-formula><p>Equation (24) is a separable differential equation which can be solved easily to get [<xref ref-type="bibr" rid="scirp.66118-ref7">7</xref>] - [<xref ref-type="bibr" rid="scirp.66118-ref9">9</xref>] :</p><disp-formula id="scirp.66118-formula2072"><label>(25)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x79.png"  xlink:type="simple"/></disp-formula><p>Apply I.C. from Equation (8) to get<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x80.png" xlink:type="simple"/></inline-formula>, hence:</p><disp-formula id="scirp.66118-formula2073"><label>(26)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x81.png"  xlink:type="simple"/></disp-formula><p>Step (7):</p><p>The final transient solution is</p><disp-formula id="scirp.66118-formula2074"><label>(27)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x82.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2075"><label>(28)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x83.png"  xlink:type="simple"/></disp-formula><p>Step (8):</p><p>Solve for the steady state solution <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x84.png" xlink:type="simple"/></inline-formula></p><disp-formula id="scirp.66118-formula2076"><label>(29)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x85.png"  xlink:type="simple"/></disp-formula><p>Thus, Equation (7) becomes:</p><disp-formula id="scirp.66118-formula2077"><label>(30)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x86.png"  xlink:type="simple"/></disp-formula><p>Apply B.C. from Equation (9),</p><disp-formula id="scirp.66118-formula2078"><label>(31)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x87.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2079"><label>(32)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x88.png"  xlink:type="simple"/></disp-formula><p>Step (9):</p><p>The overall solution is</p><disp-formula id="scirp.66118-formula2080"><label>(33)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x89.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2081"><label>(34)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x90.png"  xlink:type="simple"/></disp-formula><p>Step (10):</p><p>Applying I.C. from Equation (8) and orthogonality to get the constant <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x91.png" xlink:type="simple"/></inline-formula> [<xref ref-type="bibr" rid="scirp.66118-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref8">8</xref>] .</p><disp-formula id="scirp.66118-formula2082"><label>(35)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x92.png"  xlink:type="simple"/></disp-formula><p>Multiply both sides by <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x93.png" xlink:type="simple"/></inline-formula> and integrate <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x93.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x94.png" xlink:type="simple"/></inline-formula></p><disp-formula id="scirp.66118-formula2083"><label>(36)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x95.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2084"><label>(37)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x96.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2085"><label>(38)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x97.png"  xlink:type="simple"/></disp-formula><p>Step (11):</p><p>Plug Equation (38) and Equation (14) into Equation (34), the overall specific solution is as follows:</p><disp-formula id="scirp.66118-formula2086"><label>(39)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x98.png"  xlink:type="simple"/></disp-formula><p>Let us assume our dimensional space to be in this notation (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x99.png" xlink:type="simple"/></inline-formula>) to compare with the similarity example.</p><disp-formula id="scirp.66118-formula2087"><label>(40)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x100.png"  xlink:type="simple"/></disp-formula><p>where;</p><disp-formula id="scirp.66118-formula2088"><label>(41)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x101.png"  xlink:type="simple"/></disp-formula><p>At steady state: (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x102.png" xlink:type="simple"/></inline-formula>)</p><disp-formula id="scirp.66118-formula2089"><label>(42)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x103.png"  xlink:type="simple"/></disp-formula></sec></sec><sec id="s3"><title>3. Similarity Transformation</title><sec id="s3_1"><title>3.1. Methodology</title><p>1) Write the governing equation, initial and boundary conditions after applying the given assumptions.</p><p>2) Make the governing equation in a dimensionless form.</p><p>3) Write the initial and boundary conditions in dimensionless forms.</p><p>4) Propose a dimensionless combinations solution that will satisfy our problem. However, the proposed solution is usually in form of<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x104.png" xlink:type="simple"/></inline-formula>.</p><p>5) Apply the chain rule to each derivative term in the dimensionless governing equation in Step (2). Use our proposed solution (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x105.png" xlink:type="simple"/></inline-formula>) in step 4 to carry out the chain rule derivatives.</p><p>6) Substitute the new relations that you get back into the dimensionless governing equation in Step (2).</p><p>7) Solve the dimensionless governing equation and get the general solution.</p><p>8) Apply the dimensionless boundary conditions from Step (3) to find constants, hereafter the specific solution.</p></sec><sec id="s3_2"><title>3.2. An Example in Diffusion of Water in a Polymer</title><p>Here, we need to solve the same previous problem (FFT) with the Similarity transformation procedure. The only parameter that will change is the boundary conditions since we are dealing with semi-infinite domain in this method. In other words, the PET polymer sheet is considered as a semi-infinite system that has no boundaries from one side which makes<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x106.png" xlink:type="simple"/></inline-formula>. <xref ref-type="fig" rid="fig2">Figure 2</xref> shows a schematic to the problem with the PET boundaries in Similarity method.</p><p>Step (1):</p><p>We can start our solution from Equation (2) since we have the same assumptions.</p><disp-formula id="scirp.66118-formula2090"><label>(43)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x107.png"  xlink:type="simple"/></disp-formula><p>I.C.:</p><disp-formula id="scirp.66118-formula2091"><label>(44)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x108.png"  xlink:type="simple"/></disp-formula><p>B.C.’s: assume <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x109.png" xlink:type="simple"/></inline-formula></p><disp-formula id="scirp.66118-formula2092"><label>(45)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x110.png"  xlink:type="simple"/></disp-formula><fig id="fig2"  position="float"><label><xref ref-type="fig" rid="fig2">Figure 2</xref></label><caption><title> Schematic of the problem showing the system boundaries where<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x112.png" xlink:type="simple"/></inline-formula></title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-1740327x111.png"/></fig><p>Step (2):</p><p>Dimensionless concentration, time and space [<xref ref-type="bibr" rid="scirp.66118-ref1">1</xref>] [<xref ref-type="bibr" rid="scirp.66118-ref6">6</xref>] :</p><disp-formula id="scirp.66118-formula2093"><label>(46)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x113.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2094"><label>(47)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x114.png"  xlink:type="simple"/></disp-formula><p>Plug Equations (46) and (47) into Equation (43) to get the dimensionless governing equation:</p><disp-formula id="scirp.66118-formula2095"><label>(48)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x115.png"  xlink:type="simple"/></disp-formula><p>Step (3):</p><p>Dimensionless I.C.:</p><disp-formula id="scirp.66118-formula2096"><label>(49)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x116.png"  xlink:type="simple"/></disp-formula><p>Dimensionless B.C.’s:</p><disp-formula id="scirp.66118-formula2097"><label>(50)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x117.png"  xlink:type="simple"/></disp-formula><p>Step (4):</p><p>where;</p><disp-formula id="scirp.66118-formula2098"><label>(51)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x118.png"  xlink:type="simple"/></disp-formula><p>Step (5):</p><p>Use Equation (51) to apply the chain rule to Equation (48) with respect to <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x119.png" xlink:type="simple"/></inline-formula></p><disp-formula id="scirp.66118-formula2099"><label>(52)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x120.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2100"><label>(53)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x121.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2101"><label>(54)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x122.png"  xlink:type="simple"/></disp-formula><p>Step (6):</p><p>Plug Equation (52) and (54) into Equation (48) to get:</p><disp-formula id="scirp.66118-formula2102"><label>(55)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x123.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2103"><label>(56)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x124.png"  xlink:type="simple"/></disp-formula><p>Step (7):</p><p>Solution to Equation (56) gives:</p><disp-formula id="scirp.66118-formula2104"><label>(57)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x125.png"  xlink:type="simple"/></disp-formula><p>Step (8):</p><p>Apply dimensionless B.C.’s from Equation (50) to determine the constants</p><disp-formula id="scirp.66118-formula2105"><label>(58)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x126.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2106"><label>(59)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x127.png"  xlink:type="simple"/></disp-formula><p>Thus, final specific unsteady state solution becomes:</p><disp-formula id="scirp.66118-formula2107"><label>(60)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x128.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2108"><label>(61)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x129.png"  xlink:type="simple"/></disp-formula><p>At steady state: <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x130.png" xlink:type="simple"/></inline-formula></p><disp-formula id="scirp.66118-formula2109"><label>(62)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x131.png"  xlink:type="simple"/></disp-formula></sec></sec><sec id="s4"><title>4. Results and Discussions</title><p>Comparing both results obtained from FFT strategy and Similarity transformation will allow us to analyze the credibility of each method. We wish to study the differences in both steady state and unsteady state systems. By comparing the steady state solution from Equation (42) and Equation (62), we realize that FFT and Similarity transformation gave the same result. However, we want to see weather changing the domain of a problem from its finite domain to a semi-infinite system in the unsteady state situation will have an impact on our results or not. Equalizing similar terms in both solutions would allow us to find an estimation for the diffusivity. We have confirmed our solutions in different ways to ensure that we have correct answers in both methods.</p><p>Combining Equation (40) and Equation (61) gives:</p><disp-formula id="scirp.66118-formula2110"><label>(63)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x132.png"  xlink:type="simple"/></disp-formula><p>Take the derivative with respect to (z) for both sides in Equation (63); and consider only the first term in the summation at<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x133.png" xlink:type="simple"/></inline-formula>; neglect other terms since they will have smaller values.</p><disp-formula id="scirp.66118-formula2111"><label>(64)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x134.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2112"><label>(65)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x135.png"  xlink:type="simple"/></disp-formula><p>Thus, if diffusivity value is not constant, we can estimate the diffusivity at any time and space within the system from Equation (65). We know that the general solution for the unsteady state diffusion equation is [<xref ref-type="bibr" rid="scirp.66118-ref10">10</xref>] :</p><disp-formula id="scirp.66118-formula2113"><label>(66)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x136.png"  xlink:type="simple"/></disp-formula><p>where; b is a constant and must be <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x137.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x137.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x138.png" xlink:type="simple"/></inline-formula> is an imaginary unit. Equation (66) is the general complex solution to the diffusion Equation (7); and their real and imaginary parts are both solutions [<xref ref-type="bibr" rid="scirp.66118-ref10">10</xref>] .</p><disp-formula id="scirp.66118-formula2114"><label>(67)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x139.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.66118-formula2115"><label>(68)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x140.png"  xlink:type="simple"/></disp-formula><p>Our FFT solution in Equation (40) is identical to the general diffusion solution formula in Equation (68). Therefore, FFT complex solution must be correct. Comparison of both Equations gives:</p><disp-formula id="scirp.66118-formula2116"><label>(69)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-1740327x141.png"  xlink:type="simple"/></disp-formula><p>Now, we need to confirm the Similarity transformation solution from the concentration profile plot. Data is assumed as shown in <xref ref-type="table" rid="table2">Table 2</xref>, and then applied in Equation (61).</p><p><xref ref-type="fig" rid="fig3">Figure 3</xref> showed that Similarity solution to our problem is logical. Dimensionless concentration is at the maximum at the PET surface <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x142.png" xlink:type="simple"/></inline-formula> where the water concentration at this place is at its peak value since it is at the interface between moist air and PET tile [<xref ref-type="bibr" rid="scirp.66118-ref5">5</xref>] . On the other hand, dimensionless concentration is close to zero and at its minimum value at the end of the tile thickness<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x142.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x143.png" xlink:type="simple"/></inline-formula>. Concentration is decreasing linearly as thickness becomes larger since the water diffusion becomes weaker at the inside areas. Moreover, the higher the exposure diffusion time we have the more water concentration we notice in the PET. <xref ref-type="fig" rid="fig4">Figure 4</xref> shows that higher exposure times such as one day or two will result in having a minimum concentration at the PET thickness <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x142.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x143.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x144.png" xlink:type="simple"/></inline-formula> that is more than one half of the initial concentration that is at the membrane surface<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x142.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x143.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x144.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x145.png" xlink:type="simple"/></inline-formula>. Similarity solution explained the concentration profile perfectly which making Similarity transformation technique is a viable option in finite systems as well as the semi-infinite domains.</p></sec><sec id="s5"><title>5. Conclusion</title><p>Solutions to the given example show identical results in both steady and unsteady state systems for finite and</p><table-wrap id="table2" ><label><xref ref-type="table" rid="table2">Table 2</xref></label><caption><title> Data used in the calcuations of water concentrat on profile</title></caption><table><tbody><thead><tr><th align="center" valign="middle" >Thickness (z)</th><th align="center" valign="middle" >Time (t)</th><th align="center" valign="middle" >Diffusivity <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x146.png" xlink:type="simple"/></inline-formula><sup>*</sup></th></tr></thead><tr><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x147.png" xlink:type="simple"/></inline-formula></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x148.png" xlink:type="simple"/></inline-formula></td><td align="center" valign="middle" ><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x149.png" xlink:type="simple"/></inline-formula></td></tr></tbody></table></table-wrap><p><sup>*</sup>Diffusivity is calculated at 32˚C from:<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-1740327x150.png" xlink:type="simple"/></inline-formula>; [<xref ref-type="bibr" rid="scirp.66118-ref11">11</xref>] .</p><fig id="fig3"  position="float"><label><xref ref-type="fig" rid="fig3">Figure 3</xref></label><caption><title> Dimensionless water concentration profile in the PET at different exposure times</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-1740327x151.png"/></fig><fig id="fig4"  position="float"><label><xref ref-type="fig" rid="fig4">Figure 4</xref></label><caption><title> Dimensionless water concentration profile in the PET at high exposure times</title></caption><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-1740327x152.png"/></fig><p>semi-infinite domains. Although similarity is mostly used in semi-infinite systems, it may also be used to determine approximated results for finite systems such as diffusion of water into a polymer; specifically the diffusion of moist air into the PET tile. Confirmation to our solutions is initiated by different mathematical manipulations. FFT solution is approved by comparing the final solution with the general solution formula for the diffusion equation. However, confirmation of similarity procedure is achieved by substituting assumed data and plotting the results which predict that we have a logical answer.</p></sec><sec id="s6"><title>Acknowledgements</title><p>The author would like to acknowledge the Saudi Arabian Cultural Mission (SACM) for their continuous support, fund and encouragement to accomplish this work.</p></sec><sec id="s7"><title>Cite this paper</title><p>Hisham A. Maddah,1 1, (2016) Application of Finite Fourier Transform and Similarity Approach in a Binary System of the Diffusion of Water in a Polymer. Journal of Materials Science and Chemical Engineering,04,20-30. doi: 10.4236/msce.2016.44003</p></sec></body><back><ref-list><title>References</title><ref id="scirp.66118-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Bird, R.B., Stewart, W.E. and Lightfoot, E.N. (2002) Transport Phenomena. 2nd Edition, John Wiley &amp; Sons Ltd., New York. http://dx.doi.org/10.1115/1.1424298</mixed-citation></ref><ref id="scirp.66118-ref2"><label>2</label><mixed-citation publication-type="other" xlink:type="simple">Trim, D.W. (1990) Applied Partial Differential Equations. 1st Edition, Pws Pub Co., Boston.</mixed-citation></ref><ref id="scirp.66118-ref3"><label>3</label><mixed-citation publication-type="other" xlink:type="simple">Welty, J., Wicks, C.E., Wilson, R.E. and Rorrer, G.L. 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