<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">APM</journal-id><journal-title-group><journal-title>Advances in Pure Mathematics</journal-title></journal-title-group><issn pub-type="epub">2160-0368</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/apm.2015.511061</article-id><article-id pub-id-type="publisher-id">APM-59419</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  Multistage Numerical Picard Iteration Methods for Nonlinear Volterra Integral Equations of the Second Kind
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>ian</surname><given-names>Chen</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Junsheng</surname><given-names>Duan</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib></contrib-group><aff id="aff1"><addr-line>School of Sciences, Shanghai Institute of Technology, Shanghai, China</addr-line></aff><author-notes><corresp id="cor1">* E-mail:<email>duanjs@sit.edu.cn(JD)</email>;</corresp></author-notes><pub-date pub-type="epub"><day>07</day><month>09</month><year>2015</year></pub-date><volume>05</volume><issue>11</issue><fpage>672</fpage><lpage>682</lpage><history><date date-type="received"><day>5</day>	<month>July</month>	<year>2015</year></date><date date-type="rev-recd"><day>accepted</day>	<month>4</month>	<year>September</year>	</date><date date-type="accepted"><day>7</day>	<month>September</month>	<year>2015</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  Using the Picard iteration method and treating the involved integration by numerical quadrature formulas, we propose a numerical scheme for the second kind nonlinear Volterra integral equations. For enlarging the convergence region of the Picard iteration method, multistage algorithm is devised. We also introduce an algorithm for problems with some singularities at the limits of integration including fractional integral equations. Numerical tests verify the validity of the proposed schemes.
 
</p></abstract><kwd-group><kwd>Volterra Integral Equation</kwd><kwd> Picard Iteration Method</kwd><kwd> Numerical Integration</kwd><kwd> Multistage Scheme</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>The Volterra integral equations arise in many scientific and engineering fields such as the population dynamics, spread of epidemics, semi-conductor devices, vehicular traffic, the theory of optimal control, the kinetic theory of gases and economics [<xref ref-type="bibr" rid="scirp.59419-ref1">1</xref>] - [<xref ref-type="bibr" rid="scirp.59419-ref7">7</xref>] . The initial or boundary value problems for ordinary differential equations and some fractional differential equations can be equivalently expressed by the second-kind Volterra integral equation [<xref ref-type="bibr" rid="scirp.59419-ref6">6</xref>] - [<xref ref-type="bibr" rid="scirp.59419-ref9">9</xref>] .</p><p>In this work, we consider the general nonlinear Volterra integral equation of the second kind</p><disp-formula id="scirp.59419-formula364"><label>(1)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x6.png"  xlink:type="simple"/></disp-formula><p>where it permits weak singularity at the limits of integration.</p><p>The specific conditions under which a solution exists for the nonlinear Volterra integral equation are considered in [<xref ref-type="bibr" rid="scirp.59419-ref1">1</xref>] - [<xref ref-type="bibr" rid="scirp.59419-ref4">4</xref>] [<xref ref-type="bibr" rid="scirp.59419-ref7">7</xref>] . Many analytical and numerical methods have been proposed for solving this type of equations, such as the linearization and collocation method [<xref ref-type="bibr" rid="scirp.59419-ref10">10</xref>] - [<xref ref-type="bibr" rid="scirp.59419-ref14">14</xref>] , the trapezoidal numerical integration and implicit scheme method [<xref ref-type="bibr" rid="scirp.59419-ref15">15</xref>] , the implicit multistep collocation methods [<xref ref-type="bibr" rid="scirp.59419-ref16">16</xref>] , the reproducing kernel method [<xref ref-type="bibr" rid="scirp.59419-ref17">17</xref>] , the wavelet method [<xref ref-type="bibr" rid="scirp.59419-ref18">18</xref>] [<xref ref-type="bibr" rid="scirp.59419-ref19">19</xref>] , the Adomian decomposition method [<xref ref-type="bibr" rid="scirp.59419-ref6">6</xref>] [<xref ref-type="bibr" rid="scirp.59419-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.59419-ref20">20</xref>] and the methods by using function approximation [<xref ref-type="bibr" rid="scirp.59419-ref21">21</xref>] - [<xref ref-type="bibr" rid="scirp.59419-ref23">23</xref>] .</p><p>The Picard iteration method, or the successive approximations method, is a direct and convenient technique for the resolution of differential equations. This method solves any problem by finding successive approximations to the solution by starting with the zeroth approximation. The symbolic computation applied to the Picard iteration is considered in [<xref ref-type="bibr" rid="scirp.59419-ref24">24</xref>] [<xref ref-type="bibr" rid="scirp.59419-ref25">25</xref>] , and the Picard iteration can be used to generate the Taylor series solution for an ordinary differential equation [<xref ref-type="bibr" rid="scirp.59419-ref25">25</xref>] .</p><p>In this work, we concern on the numerical Picard iteration methods for nonlinear Volterra integral Equation (1). By using the proposed methods, we treat the involved integrals numerically and enlarge the effective region of convergence of the Picard iteration. The rest of the paper is organized as follows. In Section 2, the scheme in a single interval is considered, and the validity of the method is verified by some numerical tests. Basing on the scheme proposed in Section 2, we devise a multistage algorithm in Section 3 for enlarging the convergence region. In Section 4, an algorithm is introduced for problems with some singularity. To show the effectiveness of the proposed algorithms, we perform some numerical results.</p></sec><sec id="s2"><title>2. Numerical Picard Iteration Method for Integral Equations</title><p>The Picard iteration scheme for the considered Equation (1) reads [<xref ref-type="bibr" rid="scirp.59419-ref7">7</xref>] [<xref ref-type="bibr" rid="scirp.59419-ref26">26</xref>]</p><disp-formula id="scirp.59419-formula365"><label>(2)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x7.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.59419-formula366"><label>(3)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x8.png"  xlink:type="simple"/></disp-formula><p>The Picard iteration scheme has been applied in almost each textbook on differential equations to mainly prove the existence and uniqueness of solutions. It is direct and easily learned for numerical calculation.</p><p>Assume the recursion scheme is convergent for<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x9.png" xlink:type="simple"/></inline-formula>. Denote</p><disp-formula id="scirp.59419-formula367"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x10.png"  xlink:type="simple"/></disp-formula><p>At<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x11.png" xlink:type="simple"/></inline-formula>, (3) becomes</p><disp-formula id="scirp.59419-formula368"><label>(4)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x12.png"  xlink:type="simple"/></disp-formula><p>Treating the integral involved in (4) by numerical quadrature formulas, we have the numerical Picard iteration scheme for (1) over <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x13.png" xlink:type="simple"/></inline-formula></p><disp-formula id="scirp.59419-formula369"><label>(5)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x14.png"  xlink:type="simple"/></disp-formula><disp-formula id="scirp.59419-formula370"><label>(6)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x15.png"  xlink:type="simple"/></disp-formula><p>where <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x16.png" xlink:type="simple"/></inline-formula> and <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x17.png" xlink:type="simple"/></inline-formula> are the corresponding weights. Considering the compound trapezoidal formula in (6), the weights are</p><disp-formula id="scirp.59419-formula371"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x18.png"  xlink:type="simple"/></disp-formula><p>Numerical results are given to validate the proposed scheme. Let us start with an example in which the inte- grand <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x19.png" xlink:type="simple"/></inline-formula> is independent with t.</p><p>Example 1 Consider the initial value problem (IVP) for the nonlinear differential equation</p><disp-formula id="scirp.59419-formula372"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x20.png"  xlink:type="simple"/></disp-formula><p>This IVP has the exact solution</p><disp-formula id="scirp.59419-formula373"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x21.png"  xlink:type="simple"/></disp-formula><p>The equivalent integral equation of the IVP is</p><disp-formula id="scirp.59419-formula374"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x22.png"  xlink:type="simple"/></disp-formula><p>Denote <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x23.png" xlink:type="simple"/></inline-formula> the result after <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x23.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x24.png" xlink:type="simple"/></inline-formula> iterations when discretization parameter N is taken. Take T = 10, N = 20. <xref ref-type="fig" rid="fig1">Figure 1</xref>(a) and <xref ref-type="fig" rid="fig1">Figure 1</xref>(b) show the results of the first 5 iterations and the errors at T for each iteration respectively. It’s shown in the figure that, the iterative solution converges exponentially respect to iteration num- ber n.</p><p>The relative errors <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x25.png" xlink:type="simple"/></inline-formula>are larger than <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x25.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x26.png" xlink:type="simple"/></inline-formula> when N = 20. For higher accuracy, more nodes in</p><p>numerical integration are needed. For each fixed N, iterations stop when<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x27.png" xlink:type="simple"/></inline-formula>. Errors for <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x27.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x28.png" xlink:type="simple"/></inline-formula> are plotted in <xref ref-type="fig" rid="fig2">Figure 2</xref>(a). Especially at T, we report the dependence of the error on n and N in <xref ref-type="fig" rid="fig2">Figure 2</xref>(b) and <xref ref-type="fig" rid="fig2">Figure 2</xref>(c), respectively. The figures show that the errors increase respect to t and decrease respect to n exponentially, and decrease respect to N at an order about</p><p><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x29.png" xlink:type="simple"/></inline-formula>.</p><p>Next we give an example with t-dependent integrand.</p><p>Example 2 Consider the pendulum equation</p><disp-formula id="scirp.59419-formula375"><label>(7)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x30.png"  xlink:type="simple"/></disp-formula><p>The exact solution can be expressed in terms of the Jacobi elliptic function</p><disp-formula id="scirp.59419-formula376"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x31.png"  xlink:type="simple"/></disp-formula><p>Integrating the differential equation in (7) yields</p><disp-formula id="scirp.59419-formula377"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x32.png"  xlink:type="simple"/></disp-formula><p>Take<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x33.png" xlink:type="simple"/></inline-formula>,<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x33.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x34.png" xlink:type="simple"/></inline-formula>. Similar behavior of errors as in <xref ref-type="fig" rid="fig1">Figure 1</xref> can be observed from <xref ref-type="fig" rid="fig3">Figure 3</xref> which shows</p><fig-group id="fig1"><label><xref ref-type="fig" rid="fig1">Figure 1</xref></label><caption><title> Example 1 is simulated by numerical scheme (5), (6) with discretization parameter N = 20. (a) The numerical solution <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x37.png" xlink:type="simple"/></inline-formula> of the first 5 iterations for integration time<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x37.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x38.png" xlink:type="simple"/></inline-formula>; (b) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x37.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x38.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x39.png" xlink:type="simple"/></inline-formula> on iteration number n.</title></caption><fig id ="fig1_1"><label> (b)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x35.png"/></fig><fig id ="fig1_2"><label></label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x36.png"/></fig></fig-group><fig-group id="fig2"><label><xref ref-type="fig" rid="fig2">Figure 2</xref></label><caption><title> Example 1 is simulated by (5), (6) with various discretization parameter N. (a) Dependence of the error<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x43.png" xlink:type="simple"/></inline-formula> on integration time t; (b) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x43.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x44.png" xlink:type="simple"/></inline-formula> on iteration number n; (c) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x43.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x44.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x45.png" xlink:type="simple"/></inline-formula> on discretization parameter N.</title></caption><fig id ="fig2_1"><label>(b)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x40.png"/></fig><fig id ="fig2_2"><label> (c)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x41.png"/></fig><fig id ="fig2_3"><label></label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x42.png"/></fig></fig-group><fig-group id="fig3"><label><xref ref-type="fig" rid="fig3">Figure 3</xref></label><caption><title> Example 2 is simulated by numerical scheme (5), (6) with N = 20. (a) The numerical solution <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x48.png" xlink:type="simple"/></inline-formula> of the first 5 iterations for integration time<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x48.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x49.png" xlink:type="simple"/></inline-formula>; (b) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x48.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x49.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x50.png" xlink:type="simple"/></inline-formula> on iteration number n.</title></caption><fig id ="fig3_1"><label> (b)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x46.png"/></fig><fig id ="fig3_2"><label></label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x47.png"/></fig></fig-group><p>the results of the first 5 iterations and the errors at T for each iteration. It confirms the validity of the scheme (5), (6) for equations with general integrand f.</p><p>What’s different from Example 1 is that, at T, the results of the second and the third iterations are even worse than the first one. However, it can be noticed that, in the interval closer to t = 0, for example<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x51.png" xlink:type="simple"/></inline-formula>, the errors decrease as n increases all the same. So the underlying numerical iteration method can be viewed as a point-by- point correction process.</p></sec><sec id="s3"><title>3. Multistage Scheme</title><p>It’s well-known that the convergence of the Picard iteration is constrained in some interval. Then how can we get the numerical solution to the integral Equation (1) when t is outside the interval of convergence? We will take advantage of the multistage method and design a scheme by which the considered problem can be solved interval by interval. For example, the Equation (1) is considered on<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x52.png" xlink:type="simple"/></inline-formula>, however, assume that the single- stage-scheme designed in the previous section is convergent only on<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x52.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x53.png" xlink:type="simple"/></inline-formula>, where t<sub>1</sub> &lt; T. For achieving the numerical result at T, we can regard the problem on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x52.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x53.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x54.png" xlink:type="simple"/></inline-formula> as a new one, in which we take the numerical result at <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x52.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x53.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x54.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x55.png" xlink:type="simple"/></inline-formula> as the initial value. Now we begin to design the multistage scheme in detail.</p><p>Denote the time interval considered for (1) by<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x56.png" xlink:type="simple"/></inline-formula>. For a given positive integer K, we break I into K disjoint subintervals such that<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x56.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x57.png" xlink:type="simple"/></inline-formula>,</p><disp-formula id="scirp.59419-formula378"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x58.png"  xlink:type="simple"/></disp-formula><p>where<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x59.png" xlink:type="simple"/></inline-formula>. For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x59.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x60.png" xlink:type="simple"/></inline-formula>, take <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x59.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x60.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x61.png" xlink:type="simple"/></inline-formula> uniformly distributed nodes <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x59.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x60.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x61.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x62.png" xlink:type="simple"/></inline-formula> on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x59.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x60.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x61.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x62.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x63.png" xlink:type="simple"/></inline-formula> satisfy- ing</p><disp-formula id="scirp.59419-formula379"><label>(8)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x64.png"  xlink:type="simple"/></disp-formula><p>Suppose the equation has been solved on<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula>, namely, the first <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x66.png" xlink:type="simple"/></inline-formula> subintervals. For <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x66.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x67.png" xlink:type="simple"/></inline-formula> (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x66.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x67.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x68.png" xlink:type="simple"/></inline-formula>), denote the times of iteration by <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x66.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x67.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x68.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x69.png" xlink:type="simple"/></inline-formula> and the iterative solutions by<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x66.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x67.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x68.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x69.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x70.png" xlink:type="simple"/></inline-formula>, where<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x65.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x66.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x67.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x68.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x69.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x70.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x71.png" xlink:type="simple"/></inline-formula>.</p><p>Now we consider the solution on<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x72.png" xlink:type="simple"/></inline-formula>. Taking <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x72.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x73.png" xlink:type="simple"/></inline-formula> in (1),</p><disp-formula id="scirp.59419-formula380"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x74.png"  xlink:type="simple"/></disp-formula><p>we have for<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x75.png" xlink:type="simple"/></inline-formula>,</p><disp-formula id="scirp.59419-formula381"><label>(9)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x76.png"  xlink:type="simple"/></disp-formula><p>the right hand side of which will be analyzed below.</p><p>・ An approximation <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x77.png" xlink:type="simple"/></inline-formula> of the first term <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x77.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x78.png" xlink:type="simple"/></inline-formula> has been gotten in previous resolution.</p><p>・ The second part, with the approximations of <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x79.png" xlink:type="simple"/></inline-formula> on nodes in <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x79.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x80.png" xlink:type="simple"/></inline-formula> having been gained, can also be ap- proximated</p><disp-formula id="scirp.59419-formula382"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x81.png"  xlink:type="simple"/></disp-formula><p>where the corresponding weights for numerical integration on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x82.png" xlink:type="simple"/></inline-formula> are</p><disp-formula id="scirp.59419-formula383"><label>(10)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x83.png"  xlink:type="simple"/></disp-formula><p>・ <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x84.png" xlink:type="simple"/></inline-formula>can be calculated directly.</p><p>Denoting</p><disp-formula id="scirp.59419-formula384"><label>(11)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x85.png"  xlink:type="simple"/></disp-formula><p>(9) leads to a new equation, which is similar to the considered problem (1),</p><disp-formula id="scirp.59419-formula385"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x86.png"  xlink:type="simple"/></disp-formula><p>namely,</p><disp-formula id="scirp.59419-formula386"><label>(12)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x87.png"  xlink:type="simple"/></disp-formula><p>Using (5), (6) over<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x88.png" xlink:type="simple"/></inline-formula>, numerical solution to (12) can be obtained.</p><p>We conclude the previous analysis as an algorithm.</p><p>Algorithm 1 Choose the algorithm’s parameters: number of subintervals<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x89.png" xlink:type="simple"/></inline-formula>, set of nodes <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x89.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x90.png" xlink:type="simple"/></inline-formula> and discretization parameters<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x89.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x90.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x91.png" xlink:type="simple"/></inline-formula>.</p><p>Step 1. For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x92.png" xlink:type="simple"/></inline-formula>, generate</p><p>- the uniformly distributed nodes and corresponding weights <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x93.png" xlink:type="simple"/></inline-formula> on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x93.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x94.png" xlink:type="simple"/></inline-formula> according to (8) and (10)</p><p>- the weights <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x95.png" xlink:type="simple"/></inline-formula> for numerical integration on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x95.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x96.png" xlink:type="simple"/></inline-formula> <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x95.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x96.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x97.png" xlink:type="simple"/></inline-formula>,</p><disp-formula id="scirp.59419-formula387"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x98.png"  xlink:type="simple"/></disp-formula><p>Step 2. For k = 1, solve (12). Note that the first term of<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x99.png" xlink:type="simple"/></inline-formula>. So solving (12) for k = 1 is equivalent to solving the original Equation (1) for<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x99.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x100.png" xlink:type="simple"/></inline-formula>. Use (5), (6) with <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x99.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x100.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x101.png" xlink:type="simple"/></inline-formula> instead of<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x99.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x100.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x101.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x102.png" xlink:type="simple"/></inline-formula>.</p><p>Step 3. Recursively solve (12) for <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x103.png" xlink:type="simple"/></inline-formula> using a similar scheme to (2) as follows:</p><p>- Calculate <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x104.png" xlink:type="simple"/></inline-formula> <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x104.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x105.png" xlink:type="simple"/></inline-formula> by (11).</p><p>- The initial value of iteration:</p><disp-formula id="scirp.59419-formula388"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x106.png"  xlink:type="simple"/></disp-formula><p>- For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x107.png" xlink:type="simple"/></inline-formula>, <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x107.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x108.png" xlink:type="simple"/></inline-formula>and</p><disp-formula id="scirp.59419-formula389"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x109.png"  xlink:type="simple"/></disp-formula><p>Here, we perform a numerical test to examine the effectiveness of Algorithm 1 and compare it with the scheme in single interval (2).</p><p>Example 3 Consider the Lane-Emden equation</p><disp-formula id="scirp.59419-formula390"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x110.png"  xlink:type="simple"/></disp-formula><p>The exact solution is</p><disp-formula id="scirp.59419-formula391"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x111.png"  xlink:type="simple"/></disp-formula><p>The equivalent integral form of the Lane?Emden equation is [<xref ref-type="bibr" rid="scirp.59419-ref20">20</xref>]</p><disp-formula id="scirp.59419-formula392"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x112.png"  xlink:type="simple"/></disp-formula><p>First, taking T = 4, <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x113.png" xlink:type="simple"/></inline-formula>, we solve the current problem by (5), (6). The numerical solutions of the first 5 iterations and the errors at T are shown in <xref ref-type="fig" rid="fig4">Figure 4</xref> from which the convergence can be observed. Unfortunately, the scheme is not convergent for T = 6.</p><p>Consider the underlying problem for larger T by Algorithm 1. The time interval <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x114.png" xlink:type="simple"/></inline-formula> is uniformly divided into K subintervals, in which the same discretization parameter, denoted by N, is taken. Take <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x114.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x115.png" xlink:type="simple"/></inline-formula> and<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x114.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x115.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x116.png" xlink:type="simple"/></inline-formula>. For each N, iterations on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x114.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x115.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x116.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x117.png" xlink:type="simple"/></inline-formula> (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x114.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x115.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x116.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x117.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x118.png" xlink:type="simple"/></inline-formula>) stop when</p><disp-formula id="scirp.59419-formula393"><label>(13)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x119.png"  xlink:type="simple"/></disp-formula><p>where <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x120.png" xlink:type="simple"/></inline-formula> denotes the result after n iterations when discretization parameters N and K are taken. Errors and convergence rates respect to N at t = 12 are reported in <xref ref-type="table" rid="table1">Table 1</xref>, from which one can see that the underlying scheme is of order<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x120.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x121.png" xlink:type="simple"/></inline-formula>.</p><fig-group id="fig4"><label><xref ref-type="fig" rid="fig4">Figure 4</xref></label><caption><title> Example 3 is simulated by numerical scheme (5), (6) with N = 20. (a) The numerical solution φ of the first 5 iterations for integration time<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x124.png" xlink:type="simple"/></inline-formula>; (b) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x124.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x125.png" xlink:type="simple"/></inline-formula> on iteration number n.</title></caption><fig id ="fig4_1"><label> (b)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x122.png"/></fig><fig id ="fig4_2"><label></label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x123.png"/></fig></fig-group><table-wrap id="table1" ><label><xref ref-type="table" rid="table1">Table 1</xref></label><caption><title> The error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x126.png" xlink:type="simple"/></inline-formula> and convergence rate at t = 12 (Example 3 is simulated by Algorithm 1 with various discretization parameter N and number of subintervals K)</title></caption><table><tbody><thead><tr><th align="center" valign="middle"  rowspan="2"  >N</th><th align="center" valign="middle"  colspan="2"  >K = 3</th><th align="center" valign="middle"  colspan="2"  >K = 4</th><th align="center" valign="middle"  colspan="2"  >K = 6</th><th align="center" valign="middle"  colspan="2"  >K = 12</th></tr></thead><tr><td align="center" valign="middle" >Error</td><td align="center" valign="middle" >Order</td><td align="center" valign="middle" >Error</td><td align="center" valign="middle" >Order</td><td align="center" valign="middle" >Error</td><td align="center" valign="middle" >Order</td><td align="center" valign="middle" >Error</td><td align="center" valign="middle" >Order</td></tr><tr><td align="center" valign="middle" >10</td><td align="center" valign="middle" >1.814e−3</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >9.131e−4</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >3.771e−4</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >9.040e−5</td><td align="center" valign="middle" ></td></tr><tr><td align="center" valign="middle" >20</td><td align="center" valign="middle" >3.771e−4</td><td align="center" valign="middle" >−2.27</td><td align="center" valign="middle" >2.070e−4</td><td align="center" valign="middle" >−2.14</td><td align="center" valign="middle" >9.040e−5</td><td align="center" valign="middle" >−2.06</td><td align="center" valign="middle" >2.237e−5</td><td align="center" valign="middle" >−2.01</td></tr><tr><td align="center" valign="middle" >30</td><td align="center" valign="middle" >1.625e−4</td><td align="center" valign="middle" >−2.08</td><td align="center" valign="middle" >9.040e−5</td><td align="center" valign="middle" >−2.04</td><td align="center" valign="middle" >3.987e−5</td><td align="center" valign="middle" >−2.02</td><td align="center" valign="middle" >9.922e−6</td><td align="center" valign="middle" >−2.01</td></tr><tr><td align="center" valign="middle" >40</td><td align="center" valign="middle" >9.040e−5</td><td align="center" valign="middle" >−2.04</td><td align="center" valign="middle" >5.054e−5</td><td align="center" valign="middle" >−2.02</td><td align="center" valign="middle" >2.237e−5</td><td align="center" valign="middle" >−2.01</td><td align="center" valign="middle" >5.578e−6</td><td align="center" valign="middle" >−2.00</td></tr></tbody></table></table-wrap><p>In fact, from the errors reported in the table, the convergence order <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x127.png" xlink:type="simple"/></inline-formula> can also be obtained. So the scheme is of order<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x127.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x128.png" xlink:type="simple"/></inline-formula>. Errors for K = 3 and N = 10, 20, 30, 40 are plotted in <xref ref-type="fig" rid="fig5">Figure 5</xref>(a). The validity of Algorithm 1 is numerically confirmed.</p><p>It’s an interesting phenomenon observed from <xref ref-type="table" rid="table1">Table 1</xref> that almost the same results are obtained for same NK. For example, when NK = 120, the errors are all<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x129.png" xlink:type="simple"/></inline-formula>. This may be because “enough” iteration numbers are taken for all subintervals in the sense of (13). Setting the maximal iteration number allowed for each sub- interval to 3 and taking NK = 120, we recalculate the current example up to T = 12 for K = 3, 4, 5, 6, 8, 10, 12, 15. The errors at T are presented in <xref ref-type="fig" rid="fig5">Figure 5</xref>(b) which shows the decrement of the errors respect to K.</p></sec><sec id="s4"><title>4. Problem with Singular Integrand</title><p>In recent years, the fractional differential or integral equations are much involved. In fact, fractional integral is a class of integration with weak singular kernel. So many fractional differential and integral equations can be equivalently expressed by the singular Volterra integral equation of the second kind. Let us consider such an integral equation with some singularity.</p><p>Example 4 Consider the singular Volterra integral equation [<xref ref-type="bibr" rid="scirp.59419-ref14">14</xref>]</p><disp-formula id="scirp.59419-formula394"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x130.png"  xlink:type="simple"/></disp-formula><p>The exact solution is<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x131.png" xlink:type="simple"/></inline-formula>. Note that in the integrand there has<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x131.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x132.png" xlink:type="simple"/></inline-formula>, which is infinity at<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x131.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x132.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x133.png" xlink:type="simple"/></inline-formula>. Insuch case, the numerical scheme (5), (6) and corresponding multistage scheme (Algorithm 1) are not valid any more.</p><p>A simple idea is to avoid the value of the integrand at s = t in the numerical integration, so an alternative is to</p><fig-group id="fig5"><label><xref ref-type="fig" rid="fig5">Figure 5</xref></label><caption><title> Example 3 is simulated by Algorithm 1. (a) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x136.png" xlink:type="simple"/></inline-formula> on integration time t with the number of subintervals K = 3; (b) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x136.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x137.png" xlink:type="simple"/></inline-formula> on the number of subintervals K with NK = 120 and<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x136.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x137.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x138.png" xlink:type="simple"/></inline-formula>.</title></caption><fig id ="fig5_1"><label> (b)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x134.png"/></fig><fig id ="fig5_2"><label></label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x135.png"/></fig></fig-group><p>integrate with compound rectangular formula. The only things we need to do are changing the nodes of numerical integration and generating approximations for the values of <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x139.png" xlink:type="simple"/></inline-formula> on these points since only the values on the</p><p>nodes <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x140.png" xlink:type="simple"/></inline-formula> have been gained.</p><p>For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x141.png" xlink:type="simple"/></inline-formula>, denote the midpoint of <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x141.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x142.png" xlink:type="simple"/></inline-formula> (<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x141.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x142.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x143.png" xlink:type="simple"/></inline-formula>) and the corresponding weight by</p><disp-formula id="scirp.59419-formula395"><label>(14)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x144.png"  xlink:type="simple"/></disp-formula><p>Denote</p><disp-formula id="scirp.59419-formula396"><label>(15)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x145.png"  xlink:type="simple"/></disp-formula><p>in which</p><disp-formula id="scirp.59419-formula397"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x146.png"  xlink:type="simple"/></disp-formula><p>Thus, (12) becomes</p><disp-formula id="scirp.59419-formula398"><label>(16)</label><graphic position="anchor" xlink:href="http://html.scirp.org/file/3-5300933x147.png"  xlink:type="simple"/></disp-formula><p>We present the following algorithm.</p><p>Algorithm 2 Choose the algorithm’s parameters: number of subintervals<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x148.png" xlink:type="simple"/></inline-formula>, set of nodes <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x148.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x149.png" xlink:type="simple"/></inline-formula> and discretization parameters<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x148.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x149.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x150.png" xlink:type="simple"/></inline-formula>.</p><p>Step 1. For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x151.png" xlink:type="simple"/></inline-formula>, generate</p><p>- the nodes <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x152.png" xlink:type="simple"/></inline-formula> on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x152.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x153.png" xlink:type="simple"/></inline-formula> according to (8).</p><p>- the integral nodes and weights <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x154.png" xlink:type="simple"/></inline-formula> on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x154.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x155.png" xlink:type="simple"/></inline-formula> according to (14).</p><p>- the weights <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x156.png" xlink:type="simple"/></inline-formula> for numerical integration on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x156.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x157.png" xlink:type="simple"/></inline-formula> <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x156.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x157.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x158.png" xlink:type="simple"/></inline-formula>,</p><disp-formula id="scirp.59419-formula399"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x159.png"  xlink:type="simple"/></disp-formula><p>Step 2. Solve (16) for k = 1. As in Algorithm 1, since<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x160.png" xlink:type="simple"/></inline-formula>, it is equivalent to solving (1) for<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x160.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x161.png" xlink:type="simple"/></inline-formula>. Detail algorithm reads:</p><p>- For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x162.png" xlink:type="simple"/></inline-formula>, calculate <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x162.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x163.png" xlink:type="simple"/></inline-formula> and get the initial value of iteration:<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x162.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x163.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x164.png" xlink:type="simple"/></inline-formula>.</p><p>- For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x165.png" xlink:type="simple"/></inline-formula>, <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x165.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x166.png" xlink:type="simple"/></inline-formula>and</p><disp-formula id="scirp.59419-formula400"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x167.png"  xlink:type="simple"/></disp-formula><p>where<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x168.png" xlink:type="simple"/></inline-formula>.</p><p>Step 3. Recursively solve (16) for <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x169.png" xlink:type="simple"/></inline-formula> as follows:</p><p>- For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x170.png" xlink:type="simple"/></inline-formula>, calculate <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x170.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x171.png" xlink:type="simple"/></inline-formula> by (15) and get the initial value of iteration:</p><disp-formula id="scirp.59419-formula401"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x172.png"  xlink:type="simple"/></disp-formula><p>- For<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x173.png" xlink:type="simple"/></inline-formula>, <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x173.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x174.png" xlink:type="simple"/></inline-formula>and</p><disp-formula id="scirp.59419-formula402"><graphic  xlink:href="http://html.scirp.org/file/3-5300933x175.png"  xlink:type="simple"/></disp-formula><p>where<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x176.png" xlink:type="simple"/></inline-formula>.</p><p>Now, we come back to Example 4. Taking <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x177.png" xlink:type="simple"/></inline-formula> to subdivide the time interval <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x177.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x178.png" xlink:type="simple"/></inline-formula> and N = 5, 10, 20, 40. <xref ref-type="fig" rid="fig6">Figure 6</xref> presents the dependence of the error on <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x177.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x178.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x179.png" xlink:type="simple"/></inline-formula> for each N and that on N at t = 1. The results verify the validity of Algorithm 2 in solving problems with some singularity at the limits of integration. However, the method is of order about only <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x177.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x178.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x179.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x180.png" xlink:type="simple"/></inline-formula> for this example.</p><p>Remark 1. Algorithm 2 is devised not especially for singular problems. It’s also valid for regular problems. For instance, we recalculate Example 1 with K = 2 and N = 5, 10, 20, 40, 80, 160. Errors and convergence rates respect to N are reported in <xref ref-type="table" rid="table2">Table 2</xref>, from which we can find the order is<inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x181.png" xlink:type="simple"/></inline-formula>.</p></sec><sec id="s5"><title>5. Conclusions</title><p>In this work, Picard iteration methods with numerical integration are devised for the second kind nonlinear Volterra integral equations. The Picard iteration method solves the considered nonlinear equation explicitly, while the multistage scheme solves it interval by interval and enlarges the convergence region of the Picard iteration method. Numerical results validate the proposed schemes and algorithms and reveal that the schemes are of order <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x182.png" xlink:type="simple"/></inline-formula> for regular problems.</p><fig-group id="fig6"><label><xref ref-type="fig" rid="fig6">Figure 6</xref></label><caption><title> Example 4 is simulated by Algorithm 2. (a) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x185.png" xlink:type="simple"/></inline-formula> on integration time t; (b) Dependence of the error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x185.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x186.png" xlink:type="simple"/></inline-formula> on discretization parameter N.</title></caption><fig id ="fig6_1"><label> (b)</label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x183.png"/></fig><fig id ="fig6_2"><label></label><graphic mimetype="image"   position="float"  xlink:type="simple"  xlink:href="http://html.scirp.org/file/3-5300933x184.png"/></fig></fig-group><table-wrap id="table2" ><label><xref ref-type="table" rid="table2">Table 2</xref></label><caption><title> The error <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x187.png" xlink:type="simple"/></inline-formula> and convergence rate at t = 10 (Example 1 is simulated by Algorithm 2 with number of subintervals K = 2 and various discretization parameter N)</title></caption><table><tbody><thead><tr><th align="center" valign="middle" >N</th><th align="center" valign="middle" >5</th><th align="center" valign="middle" >10</th><th align="center" valign="middle" >20</th><th align="center" valign="middle" >40</th><th align="center" valign="middle" >80</th><th align="center" valign="middle" >160</th></tr></thead><tr><td align="center" valign="middle" >Error</td><td align="center" valign="middle" >5.807e−0</td><td align="center" valign="middle" >1.376e−0</td><td align="center" valign="middle" >3.394e−1</td><td align="center" valign="middle" >8.459e−2</td><td align="center" valign="middle" >2.113e−2</td><td align="center" valign="middle" >5.281e−3</td></tr><tr><td align="center" valign="middle" >Order</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >−2.08</td><td align="center" valign="middle" >−2.02</td><td align="center" valign="middle" >−2.00</td><td align="center" valign="middle" >−2.00</td><td align="center" valign="middle" >−2.00</td></tr></tbody></table></table-wrap><p>What should be noticed is that the errors reported in the numerical results decrease exponentially respect to times of iteration n (for example, through simple calculation, we can observe from <xref ref-type="fig" rid="fig3">Figure 3</xref>(b) and <xref ref-type="fig" rid="fig4">Figure 4</xref>(b) that the convergence rates are about <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x188.png" xlink:type="simple"/></inline-formula> for Examples 2 and 3) and are of order <inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x188.png" xlink:type="simple"/></inline-formula><inline-formula><inline-graphic xlink:href="http://html.scirp.org/file/3-5300933x189.png" xlink:type="simple"/></inline-formula> respect to discretization parameter NK. Future work may concern on enhancing the rate of convergence respect to NK.</p></sec><sec id="s6"><title>Acknowledgements</title><p>This work was supported by the Natural Science Foundation of Shanghai (No. 14ZR1440800) and the Innovation Program of the Shanghai Municipal Education Commission (No. 14ZZ161).</p></sec><sec id="s7"><title>Cite this paper</title><p>Lian Chen,Junsheng Duan, (2015) Multistage Numerical Picard Iteration Methods for Nonlinear Volterra Integral Equations of the Second Kind. Advances in Pure Mathematics,05,672-682. doi: 10.4236/apm.2015.511061</p></sec><sec id="s8"><title>NOTES</title></sec></body><back><ref-list><title>References</title><ref id="scirp.59419-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Davis, H.T. (1962) Introduction to Nonlinear Differential and Integral Equations. 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