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  <front>
    <journal-meta>
      <journal-id journal-id-type="publisher-id">am</journal-id>
      <journal-title-group>
        <journal-title>Applied Mathematics</journal-title>
      </journal-title-group>
      <issn pub-type="epub">2152-7393</issn>
      <issn pub-type="ppub">2152-7385</issn>
      <publisher>
        <publisher-name>Scientific Research Publishing</publisher-name>
      </publisher>
    </journal-meta>
    <article-meta>
      <article-id pub-id-type="doi">10.4236/am.2026.176023</article-id>
      <article-id pub-id-type="publisher-id">am-152051</article-id>
      <article-categories>
        <subj-group>
          <subject>Article</subject>
        </subj-group>
        <subj-group>
          <subject>Physics</subject>
          <subject>Mathematics</subject>
        </subj-group>
      </article-categories>
      <title-group>
        <article-title>Very Large Dissipative Term in Rayleigh Oscillator</article-title>
      </title-group>
      <contrib-group>
        <contrib contrib-type="author">
          <contrib-id contrib-id-type="orcid">0000-0001-8830-9667</contrib-id>
          <name name-style="western">
            <surname>Zarmi</surname>
            <given-names>Yair</given-names>
          </name>
          <xref ref-type="aff" rid="aff1">1</xref>
        </contrib>
      </contrib-group>
      <aff id="aff1"><label>1</label> Jacob Blaustein Institutes for Desert Research, Be Gurion University of the Negev, Midreshet Ben Gurion, Israel </aff>
      <author-notes>
        <fn fn-type="conflict" id="fn-conflict">
          <p>The authors declare no conflicts of interest regarding the publication of this paper.</p>
        </fn>
      </author-notes>
      <pub-date pub-type="epub">
        <day>16</day>
        <month>06</month>
        <year>2026</year>
      </pub-date>
      <pub-date pub-type="collection">
        <month>06</month>
        <year>2026</year>
      </pub-date>
      <volume>17</volume>
      <issue>06</issue>
      <fpage>370</fpage>
      <lpage>379</lpage>
      <history>
        <date date-type="received">
          <day>23</day>
          <month>05</month>
          <year>2026</year>
        </date>
        <date date-type="accepted">
          <day>21</day>
          <month>06</month>
          <year>2026</year>
        </date>
        <date date-type="published">
          <day>24</day>
          <month>06</month>
          <year>2026</year>
        </date>
      </history>
      <permissions>
        <copyright-statement>© 2026 by the authors and Scientific Research Publishing Inc.</copyright-statement>
        <copyright-year>2026</copyright-year>
        <license license-type="open-access">
          <license-p> This article is an open access article distributed under the terms and conditions of the Creative Commons Attribution (CC BY) license ( <ext-link ext-link-type="uri" xlink:href="https://creativecommons.org/licenses/by/4.0/">https://creativecommons.org/licenses/by/4.0/</ext-link> ). </license-p>
        </license>
      </permissions>
      <self-uri content-type="doi" xlink:href="https://doi.org/10.4236/am.2026.176023">https://doi.org/10.4236/am.2026.176023</self-uri>
      <abstract>
        <p>The dissipative term in the Rayleigh oscillator contains a nonlinear (cubic) contribution. Usually, the coefficient, <italic>ε</italic>, of the dissipative term is assigned a small value. The solution evolves into a limit cycle with <italic>O</italic>(1) maximal amplitude, maximal velocity and period. In this paper, the case, in which this coefficient is extremely large (<italic>ε</italic>  1), is studied. As expected, for long times, the solution tends to a limit cycle. The characteristics of the solution are different from those encountered in energy conserving oscillatory systems in which the magnitude of the nonlinear term is increased indefinitely. Based on numerical solutions of the equation, it is found that the amplitude and period grow linearly with <italic>ε</italic>, whereas the maximal velocity remains <italic>O</italic>(1). The consequences of the linear growth with <italic>ε</italic> of amplitude and period are studied through the definition a scaled solution and a scaled time variable, an angle <italic>θ</italic>, in which the scaled form of the limit cycle is periodic.</p>
      </abstract>
      <kwd-group kwd-group-type="author-generated" xml:lang="en">
        <kwd>Rayleigh Oscillator</kwd>
        <kwd>Large Dissipative Term</kwd>
      </kwd-group>
    </article-meta>
  </front>
  <body>
    <sec id="sec1">
      <title>1. Introduction</title>
      <p>The equation for Rayleigh oscillator,</p>
      <disp-formula id="FD1">
        <label>(1)</label>
        <mml:math>
          <mml:mrow>
            <mml:mover accent="true">
              <mml:mi>x</mml:mi>
              <mml:mo>¨</mml:mo>
            </mml:mover>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>+</mml:mo>
            <mml:mi>x</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mi>ε</mml:mi>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mover accent="true">
              <mml:mi>x</mml:mi>
              <mml:mo>˙</mml:mo>
            </mml:mover>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mn>1</mml:mn>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mo>−</mml:mo>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mover accent="true">
                  <mml:mi>x</mml:mi>
                  <mml:mo>˙</mml:mo>
                </mml:mover>
                <mml:msup>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mi>t</mml:mi>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mn>2</mml:mn>
                </mml:msup>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>was proposed by Rayleigh as the dynamical description of stable sound oscillations in musical instruments [<xref ref-type="bibr" rid="B1">1</xref>]. Traditionally, the coefficient, <italic>ε</italic>, is assigned small values (<italic>ε</italic>  1). Approximations to the limit-cycle solution are obtained by perturbation methods, such as the Method of Multiple Time Scales (see, e.g., [<xref ref-type="bibr" rid="B2">2</xref>]-[<xref ref-type="bibr" rid="B4">4</xref>] or the Method of Normal Forms (see. e.g., [<xref ref-type="bibr" rid="B5">5</xref>]-[<xref ref-type="bibr" rid="B8">8</xref>]]. Some works study the limit cycle solution (or of the equivalent Van der Pol oscillator) for <italic>ε</italic> = <italic>O</italic> (1) (see. e.g., [<xref ref-type="bibr" rid="B9">9</xref>][<xref ref-type="bibr" rid="B10">10</xref>]. However, the effect on the solution in the limit (<italic>ε</italic>  1) has not been studied. It is analyzed in this paper.</p>
      <p>As <italic>ε</italic> is increased, the amplitude, <italic>x</italic><sub>max</sub>, and the period of oscillations, <italic>T</italic>, grow linearly with <italic>ε</italic>, whereas the maximal velocity <italic>v</italic><sub>max</sub>, remains <italic>O</italic> (1). The variation of the amplitude near the turning point is very fast and the velocity varies very rapidly between its positive and negative extreme values (both <italic>O</italic> (1)).</p>
      <p>The motivation for studying the <italic>ε</italic>  1 limit for Equation (1) is that this limit is the parallel of “nonlinear violence” in conservative oscillatory systems. In the latter case, the nonlinear term is increased indefinitely. The effect on the solutions in the two cases is qualitatively different. The case of conservative oscillatory systems has been studied in [<xref ref-type="bibr" rid="B11">11</xref>]. For the sake of showing the qualitative difference of the effect of nonlinear violence on conservative oscillatory systems and on the Rayleigh oscillator, the Duffing Equation:</p>
      <disp-formula id="FD2">
        <label>(2)</label>
        <mml:math>
          <mml:mrow>
            <mml:mi>x</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mo>+</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mover accent="true">
              <mml:mi>x</mml:mi>
              <mml:mo>¨</mml:mo>
            </mml:mover>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
            </mml:mtext>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mo>+</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mi>ε</mml:mi>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mi>x</mml:mi>
            <mml:msup>
              <mml:mrow>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mi>t</mml:mi>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
              </mml:mrow>
              <mml:mn>3</mml:mn>
            </mml:msup>
            <mml:mo>=</mml:mo>
            <mml:mn>0</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>is discussed in Appendix I.</p>
    </sec>
    <sec id="sec2">
      <title>2. Numerical Analysis</title>
      <p>All numerical solutions of Equation (1) are obtained through Wolfram Mathematica NDSolve, which uses the Explicit Runge-Kutta method. The boundary conditions are <italic>x</italic> (0) = 1 and <italic>v</italic> (0) = 0. The program is run up to long times, where the limit-cycle pattern emerges and prevails.</p>
      <p>The numerical solutions of Equation (1) have been obtained for 0 ≤ <italic>ε</italic> ≤ 2000. <xref ref-type="fig" rid="fig1">Figure 1</xref> and <xref ref-type="fig" rid="fig2">Figure 2</xref>present, respectively, the long-time dependence of <italic>x</italic> (<italic>t</italic>) and d<italic>x</italic>/d<italic>t</italic> (<italic>t</italic>) for <italic>ε</italic> = 2000.</p>
      <p>The numerical solutions for a range of values <italic>ε</italic> provide the <italic>ε</italic> - dependence of the period of oscillations, <italic>T</italic> (<xref ref-type="fig" rid="fig3">Figure 3</xref>), maximal oscillation amplitude, <italic>x</italic><sub>max</sub>, (<xref ref-type="fig" rid="fig4">Figure 4</xref>) and the maximal velocity, <italic>v</italic><sub>max</sub> (<xref ref-type="fig" rid="fig5">Figure 5</xref>). Both are obtained through </p>
      <fig id="fig1">
        <label>Figure 1</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId19.jpeg?20260624024506" />
      </fig>
      <p><bold>Figure 1</bold><bold>.</bold> Long time dependence of <italic>x</italic> (<italic>t</italic>), solution of Equation (1); <italic>ε</italic> = 2000. Dashed lines: ±<italic>x</italic><sub>max</sub>.</p>
      <fig id="fig2">
        <label>Figure 2</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId20.jpeg?20260624024505" />
      </fig>
      <p><bold>Figure 2</bold><bold>.</bold> Long time dependence of d<italic>x</italic>/d<italic>t</italic> for solution of Equation (1); <italic>ε</italic> = 2000. Dashed lines: extreme velocity, ±<italic>v</italic><sub>max</sub>; dotted lines – velocity (±1) at <italic>x</italic> (<italic>t</italic>) = 0.</p>
      <fig id="fig3">
        <label>Figure 3</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId21.jpeg?20260624024505" />
      </fig>
      <p><bold>Figure 3</bold><bold>.</bold><italic>ε</italic> - dependence of period of oscillations, <italic>T</italic>.</p>
      <fig id="fig4">
        <label>Figure 4</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId22.jpeg?20260624024505" />
      </fig>
      <p><bold>Figure 4</bold><bold>.</bold><italic>ε</italic> - dependence of maximal oscillation amplitude, <italic>x</italic><sub>max</sub>.</p>
      <fig id="fig5">
        <label>Figure 5</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId23.jpeg?20260624024505" />
      </fig>
      <p><bold>Figure 5</bold><bold>.</bold><italic>ε</italic> - dependence of maximal velocity, <italic>v</italic><sub>max</sub>.</p>
      <p>Wolfram Mathematica instructions: <italic>T</italic> by finding the zeroes of the solution for <italic>x</italic> (<italic>t</italic>); <italic>x</italic><sub>max</sub> - by numerically finding maxima of the solution for <italic>x</italic> (<italic>t</italic>); <italic>v</italic><sub>max</sub> - by numerically finding maxima of the solution for d<italic>x</italic>/d<italic>t</italic>.</p>
      <p>A study of numerical fits for the dependence of <italic>v</italic><sub>max</sub> and <italic>T</italic> on <italic>ε</italic> yields that, except for small values of <italic>ε</italic>, both <italic>T</italic> and <italic>x</italic><sub>max</sub> grow linearly with <italic>ε</italic>. Writing</p>
      <disp-formula id="FD3">
        <label>(3)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>T</mml:mi>
            <mml:mo>=</mml:mo>
            <mml:msub>
              <mml:mi>T</mml:mi>
              <mml:mn>0</mml:mn>
            </mml:msub>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mi>ε</mml:mi>
            <mml:mo>,</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msub>
              <mml:mi>x</mml:mi>
              <mml:mrow>
                <mml:mi>max</mml:mi>
              </mml:mrow>
            </mml:msub>
            <mml:mo>=</mml:mo>
            <mml:msub>
              <mml:mi>X</mml:mi>
              <mml:mn>0</mml:mn>
            </mml:msub>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mi>ε</mml:mi>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>For 10 ≤ <italic>ε</italic> ≤ 1000, the results of the numerical solutions presented in <xref ref-type="fig" rid="fig3">Figures 3-5</xref> yield that</p>
      <disp-formula id="FD4">
        <label>(4)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:msub>
              <mml:mi>T</mml:mi>
              <mml:mn>0</mml:mn>
            </mml:msub>
            <mml:mo>=</mml:mo>
            <mml:mn>1.61492</mml:mn>
            <mml:mo>,</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msub>
              <mml:mi>X</mml:mi>
              <mml:mn>0</mml:mn>
            </mml:msub>
            <mml:mo>=</mml:mo>
            <mml:mn>0.38513</mml:mn>
            <mml:mo>,</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msub>
              <mml:mi>v</mml:mi>
              <mml:mrow>
                <mml:mi>max</mml:mi>
              </mml:mrow>
            </mml:msub>
            <mml:mo>=</mml:mo>
            <mml:mn>1.15532.</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>The standard deviations the linear fit <italic>T</italic> from the numerical data vary from 0.0006 at <italic>ε</italic> =10, to 0.00002 at <italic>ε</italic> =1000. The standard deviations the linear fit from <italic>X</italic><italic><sub>0</sub></italic> from the numerical data vary data vary respectively, from.0001 to 0.00005. The deviations of the fit for a constant <italic>v</italic><sub>max</sub> are always of the order of than 0.05.</p>
    </sec>
    <sec id="sec3">
      <title>3. Scaled Variables</title>
      <p>It pays to use scaled variables as follows:</p>
      <disp-formula id="FD5">
        <label>(5)</label>
        <mml:math>
          <mml:mrow>
            <mml:mi>x</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:msub>
              <mml:mi>x</mml:mi>
              <mml:mrow>
                <mml:mi>max</mml:mi>
              </mml:mrow>
            </mml:msub>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>,</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mi>θ</mml:mi>
            <mml:mo>=</mml:mo>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>2</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mi>π</mml:mi>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mi>t</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mi>T</mml:mi>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>⇒</mml:mo>
            <mml:mover accent="true">
              <mml:mi>x</mml:mi>
              <mml:mo>˙</mml:mo>
            </mml:mover>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>t</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>2</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mi>π</mml:mi>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msub>
                          <mml:mi>x</mml:mi>
                          <mml:mrow>
                            <mml:mi>max</mml:mi>
                          </mml:mrow>
                        </mml:msub>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mi>T</mml:mi>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>′</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>In addition, as <italic>ε</italic> is large, it pays to define a small parameter:</p>
      <disp-formula id="FD6">
        <label>(6)</label>
        <mml:math>
          <mml:mrow>
            <mml:mi>μ</mml:mi>
            <mml:mo>=</mml:mo>
            <mml:mrow>
              <mml:mrow>
                <mml:mn>2</mml:mn>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mi>π</mml:mi>
              </mml:mrow>
              <mml:mo>/</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mrow>
                    <mml:msub>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                    </mml:msub>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:mi>ε</mml:mi>
                  </mml:mrow>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
              </mml:mrow>
            </mml:mrow>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>Using Equations (5) and (6), Equation (1) leads to</p>
      <disp-formula id="FD7">
        <label>(7)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>−</mml:mo>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>2</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mi>π</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:msub>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                    </mml:msub>
                  </mml:mrow>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>′</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>+</mml:mo>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>8</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msup>
                          <mml:mi>π</mml:mi>
                          <mml:mn>3</mml:mn>
                        </mml:msup>
                        <mml:msubsup>
                          <mml:mi>X</mml:mi>
                          <mml:mn>0</mml:mn>
                          <mml:mn>2</mml:mn>
                        </mml:msubsup>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:msubsup>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                      <mml:mn>3</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>′</mml:mo>
            </mml:msup>
            <mml:msup>
              <mml:mrow>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mi>θ</mml:mi>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
              </mml:mrow>
              <mml:mn>3</mml:mn>
            </mml:msup>
            <mml:mo>+</mml:mo>
            <mml:msup>
              <mml:mi>μ</mml:mi>
              <mml:mn>2</mml:mn>
            </mml:msup>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>″</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mn>0</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>For <italic>t</italic>  1, <italic>x</italic> (<italic>t</italic>) tends to a limit cycle; <italic>ξ</italic> becomes periodic in <italic>θ</italic> with period 2π. Solutions of Equation (1) for different values of <italic>ε</italic> differ. <xref ref-type="fig" rid="fig6">Figure 6</xref> shows phase-space plots of solutions with <italic>ε</italic> = 2000 (full line) and 850 (dashed line).</p>
      <p>Once the transformation, Equation (5), is employed, the phase-space plots of the two scaled solutions fall on top on another, as shown in <xref ref-type="fig" rid="fig7">Figure 7</xref>.</p>
      <p>The plots in <xref ref-type="fig" rid="fig6">Figure 6</xref> are for very long times, where the limit cycle has been reached.</p>
      <fig id="fig6">
        <label>Figure 6</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId34.jpeg?20260624024506" />
      </fig>
      <p><bold>Figure 6</bold><bold>.</bold> Phase-space plots of solutions of Equation (1); <italic>ε</italic> = 2000 (full line) and 850 (dashed line).</p>
      <fig id="fig7">
        <label>Figure 7</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId35.jpeg?20260624024506" />
      </fig>
      <p><bold>Figure 7</bold><bold>.</bold> Asymptotic phase-space plot of scaled solution (Equations (5) and (6)).</p>
      <p>Plots of <italic>ξ</italic> and d<italic>ξ</italic>/d<italic>θ</italic> are shown in <xref ref-type="fig" rid="fig8">Figure 8</xref> and <xref ref-type="fig" rid="fig9">Figure 9</xref>, respectively.</p>
      <fig id="fig8">
        <label>Figure 8</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId36.jpeg?20260624024506" />
      </fig>
      <p><bold>Figure 8</bold><bold>.</bold> Plot of <italic>ξ</italic>. Full line- solution of Equation (1) scaled by Equations (3), (5) and (6); Dashed line- approximate solution (Equation (12)) discussed in Section 4.A.</p>
      <fig id="fig9">
        <label>Figure 9</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId37.jpeg?20260624024506" />
      </fig>
      <p><bold>Figure 9</bold><bold>.</bold> Plot of d<italic>ξ</italic>/d<italic>θ</italic> vs. <italic>θ</italic>: solution of Equation (1) scaled by Equations (3), (5) and (6).</p>
      <p>While <italic>ξ</italic> is periodic and vanishes at <italic>θ</italic> = 0, π and 2π, the extreme values (±1) occur at points that are slightly shifted from π/2 and 3π/2 (see <xref ref-type="fig" rid="fig9">Figure 9</xref>). As the shifts from π/2 and 3π/2 are the same, let us focus on one of the points, <italic>θ</italic><sub>0</sub> in <xref ref-type="fig" rid="fig8">Figure 8</xref>. The numerical solution for <italic>ε</italic> = 2000 yields</p>
      <disp-formula id="FD8">
        <label>(8)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:msub>
              <mml:mi>θ</mml:mi>
              <mml:mn>0</mml:mn>
            </mml:msub>
            <mml:mo>=</mml:mo>
            <mml:mtext>1</mml:mtext>
            <mml:mtext>.75685</mml:mtext>
            <mml:mo>⋯</mml:mo>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>The dashed line in <xref ref-type="fig" rid="fig9">Figure 9</xref> is a plot of an approximate solution for <italic>ξ</italic> (<italic>θ</italic>) discussed in Section 4.A (Equation (12)).</p>
    </sec>
    <sec id="sec4">
      <title>4. Matching Approximate Solutions</title>
      <p><bold>A.</bold><bold>Approximation starts around</bold><italic><bold>θ</bold></italic><bold>= 0</bold></p>
      <p>Consider the solution of Equation (7) near <italic>θ</italic> = 0, with <italic>ξ</italic> (0) =0. As <inline-formula><mml:math><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ″ </mml:mo></mml:msup></mml:math></inline-formula> is bounded there (it is extremely large only for <italic>θ</italic> near <italic>θ</italic><sub>0</sub>), in the limit <italic>μ</italic> → 0, the <italic>O</italic> (<italic>μ</italic><sup>2</sup>) term in Equation (7) can be neglected as long as (<italic>θ</italic><sub>0</sub> − <italic>θ</italic>) exceeds <italic>O</italic> (<italic>μ</italic>) (see Section 4.B), yielding</p>
      <disp-formula id="FD9">
        <label>(9)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mo>−</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>2</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mi>π</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:msub>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                    </mml:msub>
                  </mml:mrow>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>′</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mo>+</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>8</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msup>
                          <mml:mi>π</mml:mi>
                          <mml:mn>3</mml:mn>
                        </mml:msup>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msubsup>
                          <mml:mi>X</mml:mi>
                          <mml:mn>0</mml:mn>
                          <mml:mn>2</mml:mn>
                        </mml:msubsup>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:msubsup>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                      <mml:mn>3</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>′</mml:mo>
            </mml:msup>
            <mml:msup>
              <mml:mrow>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mi>θ</mml:mi>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
              </mml:mrow>
              <mml:mn>3</mml:mn>
            </mml:msup>
            <mml:mo>=</mml:mo>
            <mml:mn>0</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>We look for an approximate solution for Equation (9) in powers of <italic>θ</italic>:</p>
      <disp-formula id="FD10">
        <label>(10)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>≈</mml:mo>
            <mml:mstyle displaystyle="true">
              <mml:munderover>
                <mml:mo>∑</mml:mo>
                <mml:mrow>
                  <mml:mi>k</mml:mi>
                  <mml:mo>=</mml:mo>
                  <mml:mn>1</mml:mn>
                </mml:mrow>
                <mml:mi>n</mml:mi>
              </mml:munderover>
              <mml:mrow>
                <mml:msub>
                  <mml:mi>c</mml:mi>
                  <mml:mi>k</mml:mi>
                </mml:msub>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:msup>
                  <mml:mi>θ</mml:mi>
                  <mml:mi>k</mml:mi>
                </mml:msup>
              </mml:mrow>
            </mml:mstyle>
            <mml:mo>≡</mml:mo>
            <mml:msub>
              <mml:mi>θ</mml:mi>
              <mml:mi>n</mml:mi>
            </mml:msub>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>Substituting Equation (10) in Equation (9), one solves for <italic>c</italic><italic><sub>k</sub></italic> power by power in <italic>θ</italic>. Up to <italic>n</italic> = 5, one finds:</p>
      <disp-formula id="FD11">
        <label>(11)</label>
        <mml:math display="inline">
          <mml:mtable columnalign="left">
            <mml:mtr>
              <mml:mtd>
                <mml:msub>
                  <mml:mi>c</mml:mi>
                  <mml:mn>1</mml:mn>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:mrow>
                  <mml:mrow>
                    <mml:msub>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                    </mml:msub>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:mo stretchy="false">(</mml:mo>
                    <mml:mn>2</mml:mn>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:mi>π</mml:mi>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:msub>
                      <mml:mi>X</mml:mi>
                      <mml:mn>0</mml:mn>
                    </mml:msub>
                    <mml:mo stretchy="false">)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:msub>
                  <mml:mi>c</mml:mi>
                  <mml:mn>2</mml:mn>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:mo>−</mml:mo>
                <mml:mrow>
                  <mml:mrow>
                    <mml:msubsup>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                      <mml:mn>2</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>16</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msup>
                          <mml:mi>π</mml:mi>
                          <mml:mn>2</mml:mn>
                        </mml:msup>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msub>
                          <mml:mi>X</mml:mi>
                          <mml:mn>0</mml:mn>
                        </mml:msub>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                </mml:mrow>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:msub>
                  <mml:mi>c</mml:mi>
                  <mml:mn>3</mml:mn>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:mo>−</mml:mo>
                <mml:mrow>
                  <mml:mrow>
                    <mml:msubsup>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                      <mml:mn>3</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>96</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msup>
                          <mml:mi>π</mml:mi>
                          <mml:mn>3</mml:mn>
                        </mml:msup>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msub>
                          <mml:mi>X</mml:mi>
                          <mml:mn>0</mml:mn>
                        </mml:msub>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                </mml:mrow>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:msub>
                  <mml:mi>c</mml:mi>
                  <mml:mn>4</mml:mn>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:mo>−</mml:mo>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mn>13</mml:mn>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:msubsup>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                      <mml:mn>4</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>3072</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msup>
                          <mml:mi>π</mml:mi>
                          <mml:mn>4</mml:mn>
                        </mml:msup>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msub>
                          <mml:mi>X</mml:mi>
                          <mml:mn>0</mml:mn>
                        </mml:msub>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                </mml:mrow>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:msub>
                  <mml:mi>c</mml:mi>
                  <mml:mn>5</mml:mn>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:mo>−</mml:mo>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mn>143</mml:mn>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:msubsup>
                      <mml:mi>T</mml:mi>
                      <mml:mn>0</mml:mn>
                      <mml:mn>5</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mn>61440</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msup>
                          <mml:mi>π</mml:mi>
                          <mml:mn>5</mml:mn>
                        </mml:msup>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msub>
                          <mml:mi>X</mml:mi>
                          <mml:mn>0</mml:mn>
                        </mml:msub>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                </mml:mrow>
              </mml:mtd>
            </mml:mtr>
          </mml:mtable>
        </mml:math>
      </disp-formula>
      <p>Using the values of <italic>T</italic><sub>0</sub> and, <italic>X</italic><sub>0</sub> given in Equation (4), through <italic>n</italic> = 5, Equation (10) becomes:</p>
      <disp-formula id="FD12">
        <label>(12)</label>
        <mml:math>
          <mml:mtable>
            <mml:mtr>
              <mml:mtd>
                <mml:mi>ξ</mml:mi>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mi>θ</mml:mi>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
                <mml:mo>=</mml:mo>
                <mml:mn>0.667221</mml:mn>
                <mml:mi>θ</mml:mi>
                <mml:mo>−</mml:mo>
                <mml:mn>0.0428289</mml:mn>
                <mml:msup>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>2</mml:mn>
                </mml:msup>
                <mml:mo>−</mml:mo>
                <mml:mn>0.00366558</mml:mn>
                <mml:msup>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>3</mml:mn>
                </mml:msup>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mo>−</mml:mo>
                <mml:mn>0.000764703</mml:mn>
                <mml:msup>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>4</mml:mn>
                </mml:msup>
                <mml:mo>−</mml:mo>
                <mml:mn>0.000215979</mml:mn>
                <mml:msup>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>5</mml:mn>
                </mml:msup>
                <mml:mo>.</mml:mo>
              </mml:mtd>
            </mml:mtr>
          </mml:mtable>
        </mml:math>
      </disp-formula>
      <p>The matching procedure is based on finding an approximation for <italic>θ</italic><sub>0</sub> by requiring that, for a polynomial with a given <italic>n</italic> in Equation (10),</p>
      <disp-formula id="FD13">
        <label>(13)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:msub>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>0</mml:mn>
                </mml:msub>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mn>1</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>The value of <italic>θ</italic><sub>0</sub>, computed from the numerical solution of Equation (1), for <italic>ε</italic> = 2000 (<italic>μ</italic> = 0.001947), is 1.75685 (see Equation (8)). The values computed from Equation (12) depend on the highest power, <italic>n</italic>. The deviation from 1.75685 is about 15% for polynomials ending with <italic>n</italic> =1 and 2. It becomes smaller as the number of terms in <italic>ξ</italic> (<italic>θ</italic>) (Equation (9)) is increased and is reduced to about 1% for <italic>n</italic> = 5. A plot of the <italic>n</italic> = 5 polynomial (Equation (12)) is included in <xref ref-type="fig" rid="fig9">Figure 9</xref> (dashed line).</p>
      <p><bold>B.</bold><bold>Approximation around</bold><italic><bold>θ</bold></italic><bold>=</bold><italic><bold>θ</bold></italic><bold><sub>0</sub></bold></p>
      <p>In <xref ref-type="fig" rid="fig8">Figure 8</xref>, the approximate solution developed around <italic>θ</italic> = 0 (Equation (12), dashed line) agrees very well with the full numerical solution (full line). They grossly disagree beyond <italic>θ</italic> = <italic>θ</italic><sub>0</sub> because <inline-formula><mml:math><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ″ </mml:mo></mml:msup></mml:math></inline-formula> for the polynomial approximation misses completely the violent behavior of <inline-formula><mml:math><mml:mrow><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ″ </mml:mo></mml:msup><mml:mrow><mml:mo> ( </mml:mo><mml:mi> θ </mml:mi><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> for the full numerical solution. This can be understood by taking into account that <inline-formula><mml:math><mml:mrow><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ′ </mml:mo></mml:msup><mml:mrow><mml:mo> ( </mml:mo><mml:mi> θ </mml:mi><mml:mo> ) </mml:mo></mml:mrow><mml:mo> ≈ </mml:mo><mml:mn> 0 </mml:mn></mml:mrow></mml:math></inline-formula> in the vicinity of <italic>θ</italic> = <italic>θ</italic><sub>0</sub><inline-formula><mml:math><mml:mrow><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ′ </mml:mo></mml:msup><mml:mrow><mml:mo> ( </mml:mo><mml:mi> θ </mml:mi><mml:mo> ) </mml:mo></mml:mrow><mml:mo> ≈ </mml:mo><mml:mn> 0 </mml:mn></mml:mrow></mml:math></inline-formula> . Neglecting <inline-formula><mml:math><mml:mrow><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ′ </mml:mo></mml:msup><mml:mrow><mml:mo> ( </mml:mo><mml:mi> θ </mml:mi><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> in Equation (7), the latter is reduced to</p>
      <disp-formula id="FD14">
        <label>(14)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mo>+</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>μ</mml:mi>
              <mml:mn>2</mml:mn>
            </mml:msup>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>″</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mn>0</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>For</p>
      <disp-formula id="FD15">
        <label>(15)</label>
        <mml:math>
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:msub>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>0</mml:mn>
                </mml:msub>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mn>1</mml:mn>
            <mml:mtext>
               
            </mml:mtext>
            <mml:mo>,</mml:mo>
            <mml:mtext>
               
            </mml:mtext>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>′</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:msub>
                  <mml:mi>θ</mml:mi>
                  <mml:mn>0</mml:mn>
                </mml:msub>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mn>0</mml:mn>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>Equation (13) is solved by</p>
      <disp-formula id="FD16">
        <label>(16)</label>
        <mml:math display="inline">
          <mml:mrow>
            <mml:mi>ξ</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mi>cos</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:msub>
                          <mml:mi>θ</mml:mi>
                          <mml:mn>0</mml:mn>
                        </mml:msub>
                        <mml:mo>−</mml:mo>
                        <mml:mi>θ</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mi>μ</mml:mi>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>⇒</mml:mo>
            <mml:msup>
              <mml:mi>ξ</mml:mi>
              <mml:mo>″</mml:mo>
            </mml:msup>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mi>θ</mml:mi>
              <mml:mo>)</mml:mo>
            </mml:mrow>
            <mml:mo>=</mml:mo>
            <mml:mo>−</mml:mo>
            <mml:mfrac>
              <mml:mn>1</mml:mn>
              <mml:mrow>
                <mml:msup>
                  <mml:mi>μ</mml:mi>
                  <mml:mn>2</mml:mn>
                </mml:msup>
              </mml:mrow>
            </mml:mfrac>
            <mml:mi>cos</mml:mi>
            <mml:mrow>
              <mml:mo>(</mml:mo>
              <mml:mrow>
                <mml:mrow>
                  <mml:mrow>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:msub>
                          <mml:mi>θ</mml:mi>
                          <mml:mn>0</mml:mn>
                        </mml:msub>
                        <mml:mo>−</mml:mo>
                        <mml:mi>θ</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                  </mml:mrow>
                  <mml:mo>/</mml:mo>
                  <mml:mi>μ</mml:mi>
                </mml:mrow>
              </mml:mrow>
              <mml:mo>)</mml:mo>
            </mml:mrow>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p><inline-formula><mml:math display="inline"><mml:mrow><mml:msup><mml:mi> ξ </mml:mi><mml:mo> ″ </mml:mo></mml:msup><mml:mrow><mml:mo> ( </mml:mo><mml:mi> θ </mml:mi><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> is extremely large, of <italic>O</italic> (1/<italic>μ</italic><sup>2</sup>) for (<italic>θ</italic><sub>0</sub> − <italic>θ</italic>) = <italic>O</italic> (<italic>μ</italic>). It goes down rapidly once (<italic>θ</italic><sub>0</sub> − <italic>θ</italic>) exceeds <italic>O</italic> (<italic>μ</italic>). The polynomial approximation of Equation (10) cannot reproduce this violent behavior. This is demonstrated in <xref ref-type="fig" rid="fig10">Figure 10</xref>, where the solution of Equation (1), scaled by Equations (3)-(5), the approximate solution developed around <italic>θ</italic> = 0 (Section 4.A, Equation (12)), and the approximate solution around <italic>θ</italic> = <italic>θ</italic><sub>0</sub> (Equation (16)), are plotted in the vicinity of <italic>θ</italic> = <italic>θ</italic><sub>0</sub>.</p>
      <fig id="fig10">
        <label>Figure 10</label>
        <graphic xlink:href="https://html.scirp.org/file/7405608-rId70.jpeg?20260624024506" />
      </fig>
      <p><bold>Figure 10</bold><bold>.</bold> Comparison of solution of Equation (1), scaled by Equations (3)-(5) (full line) and approximate solutions generated in vicinity of <italic>θ</italic> = 0 (Equation (12), dotted line)) and in vicinity of <italic>θ</italic> = <italic>θ</italic><sub>0</sub> (Equation (16), dashed line).</p>
      <p>Whereas the solution generated in the vicinity of <italic>θ</italic> = 0 (Equation (12)) is almost constant over the narrow range of <italic>θ</italic> around <italic>θ</italic><sub>0</sub>, the solution generated in vicinity of <italic>θ</italic> = <italic>θ</italic><sub>0</sub> (Equation (16) varies dramatically in this narrow range of <italic>θ</italic>.</p>
    </sec>
    <sec id="sec5">
      <title>Appendix I Nonlinear Violence in Duffing Equation</title>
      <p>Nonlinear Violence occurs when the nonlinear term in the equation of motion is much greater than the linear part of the driving force (<italic>x</italic> (<italic>t</italic>)) [<xref ref-type="bibr" rid="B12">12</xref>]. In the case of the Duffing Equation (Equation (2)), this may occur by increasing either <italic>ε</italic> or <italic>x</italic><sub>max</sub>. It can be analyzed through studying, <italic>E</italic>, the total oscillation energy:</p>
      <disp-formula id="FD17">
        <label>(17)</label>
        <mml:math>
          <mml:mtable columnalign="left">
            <mml:mtr>
              <mml:mtd>
                <mml:mi>E</mml:mi>
                <mml:mo>=</mml:mo>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>/</mml:mo>
                  <mml:mn>2</mml:mn>
                </mml:mrow>
                <mml:msup>
                  <mml:mi>x</mml:mi>
                  <mml:mn>2</mml:mn>
                </mml:msup>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mo>+</mml:mo>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>/</mml:mo>
                  <mml:mn>2</mml:mn>
                </mml:mrow>
                <mml:msup>
                  <mml:mover accent="true">
                    <mml:mi>x</mml:mi>
                    <mml:mo>˙</mml:mo>
                  </mml:mover>
                  <mml:mn>2</mml:mn>
                </mml:msup>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mo>+</mml:mo>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>/</mml:mo>
                  <mml:mn>4</mml:mn>
                </mml:mrow>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mi>ε</mml:mi>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:msup>
                  <mml:mi>x</mml:mi>
                  <mml:mn>4</mml:mn>
                </mml:msup>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mo>=</mml:mo>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>/</mml:mo>
                  <mml:mn>2</mml:mn>
                </mml:mrow>
                <mml:msubsup>
                  <mml:mi>x</mml:mi>
                  <mml:mrow>
                    <mml:mi>max</mml:mi>
                  </mml:mrow>
                  <mml:mn>2</mml:mn>
                </mml:msubsup>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mo>+</mml:mo>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>/</mml:mo>
                  <mml:mn>4</mml:mn>
                </mml:mrow>
                <mml:mi>ε</mml:mi>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:msubsup>
                  <mml:mi>x</mml:mi>
                  <mml:mrow>
                    <mml:mi>max</mml:mi>
                  </mml:mrow>
                  <mml:mn>4</mml:mn>
                </mml:msubsup>
                <mml:mo>=</mml:mo>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>/</mml:mo>
                  <mml:mn>2</mml:mn>
                </mml:mrow>
                <mml:msup>
                  <mml:mover accent="true">
                    <mml:mi>x</mml:mi>
                    <mml:mo>˙</mml:mo>
                  </mml:mover>
                  <mml:mn>2</mml:mn>
                </mml:msup>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:mo>⇒</mml:mo>
                <mml:msub>
                  <mml:mi>x</mml:mi>
                  <mml:mrow>
                    <mml:mi>max</mml:mi>
                  </mml:mrow>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:msqrt>
                  <mml:mrow>
                    <mml:mfrac>
                      <mml:mrow>
                        <mml:msqrt>
                          <mml:mrow>
                            <mml:mn>1</mml:mn>
                            <mml:mtext>
                               
                            </mml:mtext>
                            <mml:mo>+</mml:mo>
                            <mml:mtext>
                               
                            </mml:mtext>
                            <mml:mn>4</mml:mn>
                            <mml:mtext>
                               
                            </mml:mtext>
                            <mml:mi>E</mml:mi>
                            <mml:mtext>
                               
                            </mml:mtext>
                            <mml:mi>ε</mml:mi>
                          </mml:mrow>
                        </mml:msqrt>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mo>−</mml:mo>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mn>1</mml:mn>
                      </mml:mrow>
                      <mml:mi>ε</mml:mi>
                    </mml:mfrac>
                  </mml:mrow>
                </mml:msqrt>
              </mml:mtd>
            </mml:mtr>
            <mml:mtr>
              <mml:mtd>
                <mml:msub>
                  <mml:mi>v</mml:mi>
                  <mml:mrow>
                    <mml:mi>max</mml:mi>
                  </mml:mrow>
                </mml:msub>
                <mml:mo>=</mml:mo>
                <mml:mi>max</mml:mi>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mover accent="true">
                    <mml:mi>x</mml:mi>
                    <mml:mo>˙</mml:mo>
                  </mml:mover>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
                <mml:mo>=</mml:mo>
                <mml:msqrt>
                  <mml:mrow>
                    <mml:mn>2</mml:mn>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:mi>E</mml:mi>
                  </mml:mrow>
                </mml:msqrt>
              </mml:mtd>
            </mml:mtr>
          </mml:mtable>
        </mml:math>
      </disp-formula>
      <p>As the total energy may be chosen to have any value, increasing the total energy goes hand in hand with increasing the amplitudes of oscillation and velocity. The increase in velocity leads to a reduction in the period of oscillations. This pattern consequence is independent of the magnitude of <italic>ε</italic>.</p>
      <p>For fixed <italic>E</italic>, as <italic>ε</italic> → ∞, <italic>x</italic><sub>max</sub> → 0. For fixed, <italic>ε</italic> and <italic>x</italic><sub>max</sub> → ∞, <italic>E</italic> → ∞. When <italic>E</italic> → ∞, <italic>v</italic><sub>max</sub> → ∞.</p>
      <p>A direct calculation yields for the period:</p>
      <disp-formula id="FD18">
        <label>(18)</label>
        <mml:math>
          <mml:mrow>
            <mml:mi>T</mml:mi>
            <mml:mo>=</mml:mo>
            <mml:mfrac>
              <mml:mrow>
                <mml:mn>8</mml:mn>
                <mml:mtext>
                   
                </mml:mtext>
                <mml:mi>K</mml:mi>
                <mml:mrow>
                  <mml:mo>(</mml:mo>
                  <mml:mrow>
                    <mml:mo>−</mml:mo>
                    <mml:mfrac>
                      <mml:mrow>
                        <mml:mi>ε</mml:mi>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msubsup>
                          <mml:mi>x</mml:mi>
                          <mml:mrow>
                            <mml:mi>max</mml:mi>
                          </mml:mrow>
                          <mml:mn>2</mml:mn>
                        </mml:msubsup>
                      </mml:mrow>
                      <mml:mrow>
                        <mml:mn>2</mml:mn>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mo>+</mml:mo>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:mi>ε</mml:mi>
                        <mml:mtext>
                           
                        </mml:mtext>
                        <mml:msubsup>
                          <mml:mi>x</mml:mi>
                          <mml:mrow>
                            <mml:mi>max</mml:mi>
                          </mml:mrow>
                          <mml:mn>2</mml:mn>
                        </mml:msubsup>
                      </mml:mrow>
                    </mml:mfrac>
                  </mml:mrow>
                  <mml:mo>)</mml:mo>
                </mml:mrow>
              </mml:mrow>
              <mml:mrow>
                <mml:msqrt>
                  <mml:mrow>
                    <mml:mn>4</mml:mn>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:mo>+</mml:mo>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:mn>2</mml:mn>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:mi>ε</mml:mi>
                    <mml:mtext>
                       
                    </mml:mtext>
                    <mml:msubsup>
                      <mml:mi>x</mml:mi>
                      <mml:mrow>
                        <mml:mi>max</mml:mi>
                      </mml:mrow>
                      <mml:mn>2</mml:mn>
                    </mml:msubsup>
                  </mml:mrow>
                </mml:msqrt>
              </mml:mrow>
            </mml:mfrac>
          </mml:mrow>
        </mml:math>
      </disp-formula>
      <p>where <italic>K</italic> (<italic>x</italic>) is the complete elliptic integral of the first kind.</p>
      <p><italic>T</italic> is reduced as <italic>x</italic><sub>max</sub> or <italic>ε</italic> are increased and tends to zero as either <italic>x</italic><sub>max</sub> or <italic>ε</italic> → ∞.</p>
      <p>In summary, the effect of nonlinear violence in conservative oscillatory systems is qualitatively quite different from the effect on the Rayleigh oscillator.</p>
    </sec>
    <sec id="sec6">
      <title>Author Responsibility</title>
      <p>1) The author made all contributions to the conception or design of the work. No data acquisition was required. No new software was created;</p>
      <p>2) The author drafted the work or revised it critically for important intellectual content;</p>
      <p>3) The author approved the version to be published;</p>
      <p>4) The author agrees to be accountable for all aspects of the work in ensuring that questions related to the accuracy or integrity of any part of the work are appropriately investigated and resolved.</p>
      <p>Data availability statement: data sharing is not applicable to this article, as no datasets were generated or analyzed during the current study.</p>
      <p>No data associated with this study have been deposited in a publicly available repository.</p>
      <p>No data were used for the research described in the article.</p>
    </sec>
  </body>
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