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  <front>
    <journal-meta>
      <journal-id journal-id-type="publisher-id">ojapps</journal-id>
      <journal-title-group>
        <journal-title>Open Journal of Applied Sciences</journal-title>
      </journal-title-group>
      <issn pub-type="epub">2165-3925</issn>
      <issn pub-type="ppub">2165-3917</issn>
      <publisher>
        <publisher-name>Scientific Research Publishing</publisher-name>
      </publisher>
    </journal-meta>
    <article-meta>
      <article-id pub-id-type="doi">10.4236/ojapps.2026.164079</article-id>
      <article-id pub-id-type="publisher-id">ojapps-151114</article-id>
      <article-categories>
        <subj-group>
          <subject>Article</subject>
        </subj-group>
        <subj-group>
          <subject>Biomedical</subject>
          <subject>Life Sciences</subject>
          <subject>Chemistry</subject>
          <subject>Materials Science</subject>
          <subject>Computer Science</subject>
          <subject>Communications</subject>
          <subject>Engineering</subject>
          <subject>Physics</subject>
          <subject>Mathematics</subject>
        </subj-group>
      </article-categories>
      <title-group>
        <article-title>Analysis and Modeling of Energy Losses in an Electrical Power System Using Maxwell’s Equations</article-title>
      </title-group>
      <contrib-group>
        <contrib contrib-type="author" corresp="yes">
          <contrib-id contrib-id-type="orcid">0009-0004-0883-9393</contrib-id>
          <name name-style="western">
            <surname>Nzao</surname>
            <given-names>Anthony Bassesuka Sandoka</given-names>
          </name>
          <xref ref-type="aff" rid="aff1">1</xref>
        </contrib>
        <contrib contrib-type="author">
          <name name-style="western">
            <surname>Christian</surname>
            <given-names>Vunda Ngulumingi</given-names>
          </name>
          <xref ref-type="aff" rid="aff1">1</xref>
        </contrib>
        <contrib contrib-type="author">
          <contrib-id contrib-id-type="orcid">0009-0000-9330-8079</contrib-id>
          <name name-style="western">
            <surname>Garcia</surname>
            <given-names>Tuka Biaba Samuel</given-names>
          </name>
          <xref ref-type="aff" rid="aff2">2</xref>
        </contrib>
      </contrib-group>
      <aff id="aff1"><label>1</label> Department of Electrical Engineering, ISTA Kinshasa, Kinshasa, Democratic Republic of the Congo </aff>
      <aff id="aff2"><label>2</label> Doctoral School of ISTA Kinshasa, Complementary Master in Science and Technology/Electrical Engineering, Electrotechnical Option, Kinshasa, Democratic Republic of Congo </aff>
      <author-notes>
        <fn fn-type="conflict" id="fn-conflict">
          <p>The authors declare no conflicts of interest regarding the publication of this paper.</p>
        </fn>
      </author-notes>
      <pub-date pub-type="epub">
        <day>02</day>
        <month>04</month>
        <year>2026</year>
      </pub-date>
      <pub-date pub-type="collection">
        <month>04</month>
        <year>2026</year>
      </pub-date>
      <volume>16</volume>
      <issue>04</issue>
      <fpage>1360</fpage>
      <lpage>1385</lpage>
      <history>
        <date date-type="received">
          <day>02</day>
          <month>03</month>
          <year>2026</year>
        </date>
        <date date-type="accepted">
          <day>27</day>
          <month>04</month>
          <year>2026</year>
        </date>
        <date date-type="published">
          <day>30</day>
          <month>04</month>
          <year>2026</year>
        </date>
      </history>
      <permissions>
        <copyright-statement>© 2026 by the authors and Scientific Research Publishing Inc.</copyright-statement>
        <copyright-year>2026</copyright-year>
        <license license-type="open-access">
          <license-p> This article is an open access article distributed under the terms and conditions of the Creative Commons Attribution (CC BY) license ( <ext-link ext-link-type="uri" xlink:href="https://creativecommons.org/licenses/by/4.0/">https://creativecommons.org/licenses/by/4.0/</ext-link> ). </license-p>
        </license>
      </permissions>
      <self-uri content-type="doi" xlink:href="https://doi.org/10.4236/ojapps.2026.164079">https://doi.org/10.4236/ojapps.2026.164079</self-uri>
      <abstract>
        <p>The consequences of energy losses in a three-phase electrical system include increased heat loss in conductors, causing overheating of cables and equipment, which can lead to fires or voltage drops. This reduces motor efficiency, increases operating costs, and can degrade power quality, causing failures in other equipment connected to the grid. In the long term, this shortens equipment lifespan and can cause cascading grid degradation. These energy losses in three-phase electrical systems, such as power grids, are categorised into two types: technical losses and non-technical losses. Non-technical losses represent energy consumed but not recorded. Technical losses refer to the losses in the grid resulting from Joule heating, corona discharge, and iron losses in transformers. Evaluating energy losses in a high-voltage (HV) three-phase electrical system allows for optimizing grid performance, increasing transmission efficiency, and reducing operating costs. It helps to reduce voltage drops, increase available power, and minimize energy waste, thus limiting the risks of failure and accidents. This article aims to apply a method based on Maxwell’s equations for the analysis and modeling of energy losses in a power system, specifically in the case of high-voltage AC transmission lines. The Simulink model, developed in MATLAB using experimental data from the 262 km long 220 kV Inga-Kinshasa high-voltage AC line in the Democratic Republic of Congo, was compared to the results of a proposed model for the analysis and modeling of energy losses in high-voltage AC transmission lines. The results of the various 2D simulations obtained show that the analytical approaches and the computer tools used are satisfactory.</p>
      </abstract>
      <kwd-group kwd-group-type="author-generated" xml:lang="en">
        <kwd>Power Electrical System</kwd>
        <kwd>HV-AC Power Transmission Lines</kwd>
        <kwd>Energy Losses</kwd>
        <kwd>Technical Losses</kwd>
        <kwd>Non-Technical Losses</kwd>
        <kwd>Voltage Drop</kwd>
        <kwd>Joule Effect</kwd>
        <kwd>Analysis</kwd>
        <kwd>Modeling</kwd>
        <kwd>Maxwell’s Equations</kwd>
        <kwd>2D Simulations</kwd>
        <kwd>Matlab/Simulink</kwd>
      </kwd-group>
    </article-meta>
  </front>
  <body>
    <sec id="sec1">
      <title>1. Introduction</title>
      <p>The transmission of electrical energy through various elements of an electrical network results in energy losses. These losses in electrical networks are divided into two categories: technical losses and non-technical losses. Non-technical losses represent energy consumed but not recorded [<xref ref-type="bibr" rid="B1">1</xref>]-[<xref ref-type="bibr" rid="B3">3</xref>]. Technical losses correspond to losses in the networks due to Joule heating (heating of cables), corona discharge (electrical discharge caused by ionization of the medium surrounding a conductor), and iron losses from transformers [<xref ref-type="bibr" rid="B3">3</xref>]-[<xref ref-type="bibr" rid="B4">4</xref>].</p>
      <p>Technical losses in the electrical network are losses of energy dissipated as heat during transmission and distribution. These losses are a concern for stakeholders in the sector because they need to be compensated [<xref ref-type="bibr" rid="B3">3</xref>]-[<xref ref-type="bibr" rid="B5">5</xref>]. The cost of these losses is either passed on to consumers or borne by network operators, who must anticipate the volume and purchase the corresponding electricity to meet demand [<xref ref-type="bibr" rid="B3">3</xref>]-[<xref ref-type="bibr" rid="B8">8</xref>].</p>
      <p>According to existing literature [<xref ref-type="bibr" rid="B9">9</xref>][<xref ref-type="bibr" rid="B10">10</xref>], technical losses in electrical grids lead to increased operating costs and higher energy consumption [<xref ref-type="bibr" rid="B11">11</xref>], resulting in reduced profitability for distributors and potentially higher prices for consumers [<xref ref-type="bibr" rid="B12">12</xref>][<xref ref-type="bibr" rid="B13">13</xref>]. These losses, caused by the Joule effect (cable heating), the corona effect, and transformer losses, reduce the overall efficiency of the grid [<xref ref-type="bibr" rid="B14">14</xref>][<xref ref-type="bibr" rid="B15">15</xref>]. Furthermore, they can cause grid stability problems and, in extreme cases, lead to widespread outages [<xref ref-type="bibr" rid="B16">16</xref>][<xref ref-type="bibr" rid="B17">17</xref>]. These losses result, among other things, in voltage drops.</p>
      <p>Assessing energy losses is crucial for the financial and technical performance of electrical grids. It allows for measuring grid efficiency, identifying the causes of losses (such as the Joule effect or load imbalances), and reducing costs by preventing overproduction. Furthermore, a sound assessment helps to control the supply-demand balance, optimize investments, and better distinguish technical losses from non-technical losses (fraud, metering errors) [<xref ref-type="bibr" rid="B18">18</xref>].</p>
      <p>According to [<xref ref-type="bibr" rid="B9">9</xref>][<xref ref-type="bibr" rid="B10">10</xref>], the energy loss rate, the ratio of energy lost to total energy injected, is an internationally recognised indicator relevant for assessing the performance of electricity grids and the companies responsible for their operation [<xref ref-type="bibr" rid="B11">11</xref>]-[<xref ref-type="bibr" rid="B14">14</xref>].</p>
      <p>Methods for analyzing and modeling energy losses in a high-voltage electrical network include deterministic and statistical approaches. Deterministic methods (energy balance by voltage level and evaluation of technical energy losses inherent in the physical operation of networks [<xref ref-type="bibr" rid="B15">15</xref>][<xref ref-type="bibr" rid="B16">16</xref>]) use calculations based on physics (Joule effect, corona effect, transformer losses), while statistical methods rely on historical data to estimate losses and are often used for medium- and long-term forecasts. These two approaches can be combined, for example, by calibrating statistical forecasts with physical measurements or energy balances. The energy balance will determine the total energy lost and the technical losses; by subtracting the total energy lost from the technical losses, non-technical losses will be assessed [<xref ref-type="bibr" rid="B16">16</xref>][<xref ref-type="bibr" rid="B17">17</xref>].</p>
      <p>Deterministic methods have the advantage of offering high accuracy if the data are precise, but they can be rigid and fail to handle uncertainties [<xref ref-type="bibr" rid="B18">18</xref>][<xref ref-type="bibr" rid="B19">19</xref>], as fraudulently siphoned electrical energy, considered non-technical losses, is not taken into account. Statistical methods are more flexible and allow for the management of variations, but they can be less precise and struggle to estimate exact energy volumes, sometimes reproducing atypical past events [<xref ref-type="bibr" rid="B20">20</xref>].</p>
      <p>This manuscript proposes a method for analyzing and modeling energy losses in an electrical system, based on Maxwell’s equations, which provide a theoretical framework for understanding these losses. In the absence of non-technical losses, the voltage drop is correlated with technical losses. Maxwell’s equations allow for the estimation of energy losses in high-voltage lines using an analytical model based on two measurements: the voltage drop at a given time (t) and the power factor under normal network conditions. This method requires simultaneous voltage readings at the starting and ending nodes. Calculating averages over fixed time horizons necessitates a computer network due to the distances between the nodes. The advantage of this approach compared to existing ones in the literature lies in its ease of implementation and its implicit consideration of fraudulently consumed electrical energy, considered as non-technical losses, since it is included in the losses calculated from the known voltage drop at a given instant (t).</p>
      <p>The results obtained show a direct correlation between the proposed models and the Simulink models developed in MATLAB.</p>
    </sec>
    <sec id="sec2">
      <title>2. Method</title>
      <p>The analysis and modeling of energy losses in a three-phase electrical system using Maxwell’s equations are based on the study of electromagnetic fields and their interactions to deduce the losses [<xref ref-type="bibr" rid="B21">21</xref>]-[<xref ref-type="bibr" rid="B23">23</xref>]. Maxwell’s equations (Expressions 1 - 7), in their differential form, describe the sources (charges and currents) and the evolution of the electric (<inline-formula><mml:math display="inline"><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> E </mml:mi></mml:mstyle></mml:math></inline-formula> ) and magnetic (<inline-formula><mml:math display="inline"><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> B </mml:mi></mml:mstyle></mml:math></inline-formula> ) fields [<xref ref-type="bibr" rid="B24">24</xref>][<xref ref-type="bibr" rid="B25">25</xref>]. The losses manifest themselves as heat due to the Joule effect in the conductors <inline-formula><mml:math display="inline"><mml:mrow><mml:mrow><mml:mo> ( </mml:mo><mml:mrow><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> j </mml:mi></mml:mstyle><mml:mo> , </mml:mo><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> E </mml:mi></mml:mstyle></mml:mrow><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> , eddy currents in the ferromagnetic cores (related to the variation of the magnetic field), and magnetic losses in the ferromagnetic materials, modelled via relationships derived from these equations [<xref ref-type="bibr" rid="B26">26</xref>][<xref ref-type="bibr" rid="B27">27</xref>]. The scope of this article concerns technical losses due to the Joule effect in the conductors of high-voltage AC lines. </p>
      <sec id="sec2dot1">
        <title>2.1. Assumptions and Applicability</title>
        <p>The main simplifications used in this article are:</p>
        <p>Balanced currents.Constant power factor.Negligible transverse parameters.Invariant line parameters.</p>
        <p>The model is susceptible to failures (e.g., compensation devices, tap changes, unbalanced load).</p>
      </sec>
      <sec id="sec2dot2">
        <title>2.2. Modeling of High-Voltage Power Lines</title>
        <p>Modelling power lines allows us to represent their expected electrical behaviour. The main modelling method is based on a system of two partial differential equations that describe the evolution of voltage and current on a power line as a function of distance and time. Two methods, with completely distinct foundations, are used:</p>
        <p>Field theory, developed from Maxwell’s equations [<xref ref-type="bibr" rid="B23">23</xref>], is rigorous but not always easy to apply and allows us to establish the second theory (circuit theory).Circuit theory: modelling propagation along the line by constructing an equivalent circuit (inductors, capacitors, resistors), the analysis of which is simple.</p>
        <p>In this article, we will limit ourselves to field theory. Indeed, field theory, developed from Maxwell’s equations [<xref ref-type="bibr" rid="B27">27</xref>], is rigorous but not always easy to apply and allows us to establish the second theory (circuit theory). At any point in space, which is not located on a surface separating two media, that is, in a linear, homogeneous, and isotropic (LHI) medium, Maxwell’s general equations specify that [<xref ref-type="bibr" rid="B28">28</xref>]:</p>
        <disp-formula id="FD1">
          <label>(1)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>×</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>E</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mo>−</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mstyle mathvariant="bold" mathsize="normal">
                    <mml:mi>B</mml:mi>
                  </mml:mstyle>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mi>t</mml:mi>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD2">
          <label>(2)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>×</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>H</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>J</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>+</mml:mo>
              <mml:msub>
                <mml:mi>ε</mml:mi>
                <mml:mn>0</mml:mn>
              </mml:msub>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mstyle mathvariant="bold" mathsize="normal">
                    <mml:mi>E</mml:mi>
                  </mml:mstyle>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mi>t</mml:mi>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD3">
          <label>(3)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>⋅</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>D</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mi>ρ</mml:mi>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD4">
          <label>(4)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>⋅</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>B</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>The basic variables of these equations are:</p>
        <p><inline-formula><mml:math><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> B </mml:mi></mml:mstyle></mml:math></inline-formula> : Magnetic induction (Tesla, T).</p>
        <p><inline-formula><mml:math><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> H </mml:mi></mml:mstyle></mml:math></inline-formula> : Magnetic field strength (Ampere/meter<sup>2</sup>, Am<sup>−</sup><sup>2</sup>).</p>
        <p><inline-formula><mml:math><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> D </mml:mi></mml:mstyle></mml:math></inline-formula> : Electric flux density (coulomb/meter<sup>2</sup>, Cm<sup>−2</sup>).</p>
        <p><inline-formula><mml:math display="inline"><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> E </mml:mi></mml:mstyle></mml:math></inline-formula> : Electric field density (volt/meter, Vm<sup>−</sup><sup>1</sup>).</p>
        <p><inline-formula><mml:math display="inline"><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> J </mml:mi></mml:mstyle></mml:math></inline-formula> : Electric current density (Ampere/meter<sup>2</sup>, Am<sup>−2</sup>).</p>
        <p><italic>ρ</italic>: Electric charge density (coulomb/meter<sup>3</sup>, Cm<sup>−</sup><sup>3</sup>).</p>
        <p>With:</p>
        <disp-formula id="FD5">
          <label>(5)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>B</mml:mi>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mi>μ</mml:mi>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>H</mml:mi>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD6">
          <label>(6)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>D</mml:mi>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mi>ε</mml:mi>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>E</mml:mi>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD7">
          <label>(7)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>J</mml:mi>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mi>σ</mml:mi>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>E</mml:mi>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>And:</p>
        <p><italic>µ</italic>: Magnetic permeability in Tm<sup>2</sup>/A</p>
        <p><italic>ε</italic>: Electrical permeability in Cm<sup>−</sup><sup>3</sup>/V</p>
        <p><italic>σ</italic>: Electrical conductivity</p>
        <p>In this form, called local or differential, Maxwell’s equations express relationships between spatial variations of certain fields and temporal variations of other fields [<xref ref-type="bibr" rid="B26">26</xref>][<xref ref-type="bibr" rid="B27">27</xref>].</p>
        <p>In a vacuum:</p>
        <disp-formula id="FD8">
          <label>(8)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>B</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>μ</mml:mi>
                <mml:mn>0</mml:mn>
              </mml:msub>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>H</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD9">
          <label>(9)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>D</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>ε</mml:mi>
                <mml:mn>0</mml:mn>
              </mml:msub>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>E</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Then Maxwell’s equations become [<xref ref-type="bibr" rid="B26">26</xref>][<xref ref-type="bibr" rid="B27">27</xref>]:</p>
        <disp-formula id="FD10">
          <label>(10)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>×</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>H</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>ε</mml:mi>
                <mml:mn>0</mml:mn>
              </mml:msub>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mstyle mathvariant="bold" mathsize="normal">
                    <mml:mi>E</mml:mi>
                  </mml:mstyle>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mi>t</mml:mi>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD11">
          <label>(11)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>⋅</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>H</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD12">
          <label>(12)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>⋅</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>B</mml:mi>
              </mml:mstyle>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>t</mml:mi>
                  <mml:mo>,</mml:mo>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>The differential operator <inline-formula><mml:math display="inline"><mml:mrow><mml:mo> ∇ </mml:mo><mml:mo> ⋅ </mml:mo></mml:mrow></mml:math></inline-formula> is used to express the curl operation <inline-formula><mml:math display="inline"><mml:mrow><mml:mo> ∇ </mml:mo><mml:mo> × </mml:mo></mml:mrow></mml:math></inline-formula> = rot and the divergence operation <inline-formula><mml:math display="inline"><mml:mrow><mml:mo> ∇ </mml:mo><mml:mo> ⋅ </mml:mo><mml:mo> = </mml:mo><mml:mtext> div </mml:mtext></mml:mrow></mml:math></inline-formula> . Maxwell’s equations can also be expressed in “global form” as follows [<xref ref-type="bibr" rid="B26">26</xref>][<xref ref-type="bibr" rid="B27">27</xref>]: </p>
        <disp-formula id="FD13">
          <label>(13)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∮</mml:mo>
                    <mml:mi>c</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>E</mml:mi>
                    </mml:mstyle>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mi>t</mml:mi>
                        <mml:mo>,</mml:mo>
                        <mml:mi>r</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                    <mml:mtext>d</mml:mtext>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>l</mml:mi>
                    </mml:mstyle>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mo>−</mml:mo>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∫</mml:mo>
                    <mml:mi>s</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>n</mml:mi>
                    </mml:mstyle>
                    <mml:mfrac>
                      <mml:mrow>
                        <mml:mo>∂</mml:mo>
                        <mml:mstyle mathvariant="bold" mathsize="normal">
                          <mml:mi>B</mml:mi>
                        </mml:mstyle>
                        <mml:mrow>
                          <mml:mo>(</mml:mo>
                          <mml:mrow>
                            <mml:mi>t</mml:mi>
                            <mml:mo>,</mml:mo>
                            <mml:mi>r</mml:mi>
                          </mml:mrow>
                          <mml:mo>)</mml:mo>
                        </mml:mrow>
                      </mml:mrow>
                      <mml:mrow>
                        <mml:mo>∂</mml:mo>
                        <mml:mi>t</mml:mi>
                      </mml:mrow>
                    </mml:mfrac>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>A</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD14">
          <label>(14)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∮</mml:mo>
                    <mml:mi>c</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>H</mml:mi>
                    </mml:mstyle>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mi>t</mml:mi>
                        <mml:mo>,</mml:mo>
                        <mml:mi>r</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                    <mml:mtext>d</mml:mtext>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>l</mml:mi>
                    </mml:mstyle>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mo>−</mml:mo>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∫</mml:mo>
                    <mml:mi>s</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>n</mml:mi>
                    </mml:mstyle>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mfrac>
                          <mml:mrow>
                            <mml:mo>∂</mml:mo>
                            <mml:mstyle mathvariant="bold" mathsize="normal">
                              <mml:mi>D</mml:mi>
                            </mml:mstyle>
                            <mml:mrow>
                              <mml:mo>(</mml:mo>
                              <mml:mrow>
                                <mml:mi>t</mml:mi>
                                <mml:mo>,</mml:mo>
                                <mml:mi>r</mml:mi>
                              </mml:mrow>
                              <mml:mo>)</mml:mo>
                            </mml:mrow>
                          </mml:mrow>
                          <mml:mrow>
                            <mml:mo>∂</mml:mo>
                            <mml:mi>t</mml:mi>
                          </mml:mrow>
                        </mml:mfrac>
                        <mml:mo>+</mml:mo>
                        <mml:mstyle mathvariant="bold" mathsize="normal">
                          <mml:mi>J</mml:mi>
                        </mml:mstyle>
                        <mml:mrow>
                          <mml:mo>(</mml:mo>
                          <mml:mrow>
                            <mml:mi>t</mml:mi>
                            <mml:mo>,</mml:mo>
                            <mml:mi>r</mml:mi>
                          </mml:mrow>
                          <mml:mo>)</mml:mo>
                        </mml:mrow>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>A</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>After integrating Equations (13) and (14), using the divergence theorem, the two Equations (4) and (6) then become [<xref ref-type="bibr" rid="B26">26</xref>][<xref ref-type="bibr" rid="B27">27</xref>]:</p>
        <disp-formula id="FD15">
          <label>(15)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∮</mml:mo>
                    <mml:mi>c</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>n</mml:mi>
                      <mml:mi>D</mml:mi>
                    </mml:mstyle>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mi>t</mml:mi>
                        <mml:mo>,</mml:mo>
                        <mml:mi>r</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>A</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∫</mml:mo>
                    <mml:mi>v</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mi>ρ</mml:mi>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mi>t</mml:mi>
                        <mml:mo>,</mml:mo>
                        <mml:mi>r</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>A</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD16">
          <label>(16)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∫</mml:mo>
                    <mml:mi>s</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>n</mml:mi>
                      <mml:mi>B</mml:mi>
                    </mml:mstyle>
                    <mml:mrow>
                      <mml:mo>(</mml:mo>
                      <mml:mrow>
                        <mml:mi>t</mml:mi>
                        <mml:mo>,</mml:mo>
                        <mml:mi>r</mml:mi>
                      </mml:mrow>
                      <mml:mo>)</mml:mo>
                    </mml:mrow>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>A</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>The boundary conditions for fields [<xref ref-type="bibr" rid="B26">26</xref>][<xref ref-type="bibr" rid="B27">27</xref>] are:</p>
        <disp-formula id="FD17">
          <label>(17)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>n</mml:mi>
              </mml:mstyle>
              <mml:mo>×</mml:mo>
              <mml:mrow>
                <mml:mo>[</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>E</mml:mi>
                    </mml:mstyle>
                    <mml:mn>1</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                  <mml:mo>−</mml:mo>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>E</mml:mi>
                    </mml:mstyle>
                    <mml:mn>2</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mo>]</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD18">
          <label>(18)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>n</mml:mi>
              </mml:mstyle>
              <mml:mo>×</mml:mo>
              <mml:mrow>
                <mml:mo>[</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>H</mml:mi>
                    </mml:mstyle>
                    <mml:mn>1</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                  <mml:mo>−</mml:mo>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>H</mml:mi>
                    </mml:mstyle>
                    <mml:mn>2</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mo>]</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mstyle mathvariant="bold" mathsize="normal">
                  <mml:mi>j</mml:mi>
                </mml:mstyle>
                <mml:mi>s</mml:mi>
              </mml:msub>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD19">
          <label>(19)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>n</mml:mi>
              </mml:mstyle>
              <mml:mo>×</mml:mo>
              <mml:mrow>
                <mml:mo>[</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>D</mml:mi>
                    </mml:mstyle>
                    <mml:mn>1</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                  <mml:mo>−</mml:mo>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>D</mml:mi>
                    </mml:mstyle>
                    <mml:mn>2</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mo>]</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>ρ</mml:mi>
                <mml:mi>s</mml:mi>
              </mml:msub>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD20">
          <label>(20)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>n</mml:mi>
              </mml:mstyle>
              <mml:mo>×</mml:mo>
              <mml:mrow>
                <mml:mo>[</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>B</mml:mi>
                    </mml:mstyle>
                    <mml:mn>1</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                  <mml:mo>−</mml:mo>
                  <mml:msub>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>B</mml:mi>
                    </mml:mstyle>
                    <mml:mn>2</mml:mn>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mi>t</mml:mi>
                      <mml:mo>,</mml:mo>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
                <mml:mo>]</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With:</p>
        <p><inline-formula><mml:math><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> n </mml:mi></mml:mstyle></mml:math></inline-formula> : is the normal to the separation surface, going from medium 2 to medium 1;</p>
        <p><inline-formula><mml:math><mml:mrow><mml:msub><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> J </mml:mi></mml:mstyle><mml:mi> s </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> : is the surface current density;</p>
        <p><inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> ρ </mml:mi><mml:mi> s </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> : is the surface charge density.</p>
      </sec>
      <sec id="sec2dot3">
        <title>2.3. Pi Modeling of High Voltage AC Power Lines</title>
        <p>Pi modelling of power lines (see <xref ref-type="fig" rid="fig1">Figure 1</xref> below) allows us to represent their expected electrical behaviour. It is based on the telegraphers’ equations [<xref ref-type="bibr" rid="B28">28</xref>]-[<xref ref-type="bibr" rid="B30">30</xref>].</p>
        <fig id="fig1">
          <label>Figure 1</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId88.jpeg?20260430040519" />
        </fig>
        <p><bold>Figure 1.</bold> Simplified model of a high-voltage power line [<xref ref-type="bibr" rid="B28">28</xref>]-[<xref ref-type="bibr" rid="B30">30</xref>].</p>
        <p>A portion of a power line can be represented by the four-terminal network in <xref ref-type="fig" rid="fig2">Figure 2</xref> below, where [<xref ref-type="bibr" rid="B31">31</xref>]-[<xref ref-type="bibr" rid="B35">35</xref>]:</p>
        <p>The linear resistance (per unit length) <italic>R</italic> of the conductor is represented by a series resistance (expressed in ohms per unit length).The linear inductance <italic>L</italic> is represented by an inductance (Henry per unit length).The linear capacitance <italic>C</italic> between the two conductors is represented by a shunt capacitor <italic>C</italic> (Farad per unit length).The linear conductance <italic>G</italic> of the dielectric medium separating the two conductors is represented by a shunt resistance (Siemens per unit length). The resistance in this model has a value of 1/<italic>G</italic> Ohms.</p>
        <p>In this model, we define the voltage at any point a distance <italic>x</italic> from the beginning of the line and at any time <italic>t</italic>, the voltage <inline-formula><mml:math display="inline"><mml:mrow><mml:mi> U </mml:mi><mml:mrow><mml:mo> ( </mml:mo><mml:mrow><mml:mi> x </mml:mi><mml:mo> , </mml:mo><mml:mi> t </mml:mi></mml:mrow><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> and the current <inline-formula><mml:math display="inline"><mml:mrow><mml:mi> I </mml:mi><mml:mrow><mml:mo> ( </mml:mo><mml:mrow><mml:mi> x </mml:mi><mml:mo> , </mml:mo><mml:mi> t </mml:mi></mml:mrow><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> . The equations are written [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>]:</p>
        <disp-formula id="FD21">
          <label>(21)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mrow>
                <mml:mo>{</mml:mo>
                <mml:mtable columnalign="left">
                  <mml:mtr>
                    <mml:mtd>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>U</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>x</mml:mi>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>=</mml:mo>
                      <mml:mo>−</mml:mo>
                      <mml:mi>L</mml:mi>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>I</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>−</mml:mo>
                      <mml:mi>R</mml:mi>
                      <mml:mi>I</mml:mi>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                    </mml:mtd>
                  </mml:mtr>
                  <mml:mtr>
                    <mml:mtd>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>I</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>x</mml:mi>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>=</mml:mo>
                      <mml:mo>−</mml:mo>
                      <mml:mi>C</mml:mi>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>U</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>−</mml:mo>
                      <mml:mi>G</mml:mi>
                      <mml:mi>U</mml:mi>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                    </mml:mtd>
                  </mml:mtr>
                </mml:mtable>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <fig id="fig2">
          <label>Figure 2</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId95.jpeg?20260430040519" />
        </fig>
        <p><bold>Figure 2.</bold> Two-port network model of a high-voltage power line [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>].</p>
        <p>From the formulation above, we can derive two partial differential equations, each involving only one variable [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>]:</p>
        <disp-formula id="FD22">
          <label>(22)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mrow>
                <mml:mo>{</mml:mo>
                <mml:mtable columnalign="left">
                  <mml:mtr>
                    <mml:mtd>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:msup>
                            <mml:mo>∂</mml:mo>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                          <mml:mi>U</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:msup>
                            <mml:mi>x</mml:mi>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>=</mml:mo>
                      <mml:mi>L</mml:mi>
                      <mml:mi>C</mml:mi>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:msup>
                            <mml:mo>∂</mml:mo>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                          <mml:mi>U</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:msup>
                            <mml:mi>t</mml:mi>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>+</mml:mo>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>R</mml:mi>
                          <mml:mi>C</mml:mi>
                          <mml:mo>+</mml:mo>
                          <mml:mi>G</mml:mi>
                          <mml:mi>L</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>U</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>+</mml:mo>
                      <mml:mi>G</mml:mi>
                      <mml:mi>R</mml:mi>
                      <mml:mi>U</mml:mi>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                    </mml:mtd>
                  </mml:mtr>
                  <mml:mtr>
                    <mml:mtd>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:msup>
                            <mml:mo>∂</mml:mo>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                          <mml:mi>I</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:msup>
                            <mml:mi>x</mml:mi>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>=</mml:mo>
                      <mml:mi>L</mml:mi>
                      <mml:mi>C</mml:mi>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:msup>
                            <mml:mo>∂</mml:mo>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                          <mml:mi>I</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:msup>
                            <mml:mi>t</mml:mi>
                            <mml:mn>2</mml:mn>
                          </mml:msup>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>+</mml:mo>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>R</mml:mi>
                          <mml:mi>C</mml:mi>
                          <mml:mo>+</mml:mo>
                          <mml:mi>G</mml:mi>
                          <mml:mi>L</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>I</mml:mi>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:mo>∂</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                      <mml:mo>+</mml:mo>
                      <mml:mi>G</mml:mi>
                      <mml:mi>R</mml:mi>
                      <mml:mi>I</mml:mi>
                      <mml:mrow>
                        <mml:mo>(</mml:mo>
                        <mml:mrow>
                          <mml:mi>x</mml:mi>
                          <mml:mo>,</mml:mo>
                          <mml:mi>t</mml:mi>
                        </mml:mrow>
                        <mml:mo>)</mml:mo>
                      </mml:mrow>
                    </mml:mtd>
                  </mml:mtr>
                </mml:mtable>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
      </sec>
      <sec id="sec2dot4">
        <title>2.4. High-Voltage Line Parameter Models</title>
        <p>The calculation of the electrical parameters used for the modelling is based on Maxwell’s equations. The model with a single Pi section is only valid for low frequencies and short power lines; otherwise, several Pi sections must be connected in series [<xref ref-type="bibr" rid="B34">34</xref>]-[<xref ref-type="bibr" rid="B37">37</xref>].</p>
        <p>2.4.1. Resistance Model</p>
        <p>Starting from the local Ohm’s law in local form [<xref ref-type="bibr" rid="B40">40</xref>]:</p>
        <disp-formula id="FD23">
          <label>(23)</label>
          <mml:math>
            <mml:mrow>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>j</mml:mi>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mi>δ</mml:mi>
              <mml:mo>⋅</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>E</mml:mi>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Or:</p>
        <p><inline-formula><mml:math><mml:mstyle mathvariant="bold" mathsize="normal"><mml:mi> J </mml:mi></mml:mstyle></mml:math></inline-formula> : Current density (A/m<sup>2</sup>)</p>
        <p><inline-formula><mml:math><mml:mi> δ </mml:mi></mml:math></inline-formula> : Electrical conductivity (Ω<sup>−</sup><sup>1</sup>)</p>
        <disp-formula id="FD24">
          <label>(V/m)</label>
          <mml:math>
            <mml:mstyle mathvariant="bold" mathsize="normal">
              <mml:mi>E</mml:mi>
            </mml:mstyle>
          </mml:math>
        </disp-formula>
        <p>The resistance of conductors depends on temperature and frequency; it is defined by [<xref ref-type="bibr" rid="B39">39</xref>][<xref ref-type="bibr" rid="B40">40</xref>]: </p>
        <disp-formula id="FD25">
          <label>(24)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>R</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mi>l</mml:mi>
                <mml:mrow>
                  <mml:mi>G</mml:mi>
                  <mml:mi>S</mml:mi>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mi>ρ</mml:mi>
                  <mml:mi>l</mml:mi>
                </mml:mrow>
                <mml:mi>s</mml:mi>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mi>Ω</mml:mi>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>The resistivity of a material increases with temperature according to this law.</p>
        <disp-formula id="FD26">
          <label>(25)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mi>ρ</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>ρ</mml:mi>
                <mml:mi>o</mml:mi>
              </mml:msub>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>+</mml:mo>
                  <mml:mi>α</mml:mi>
                  <mml:mi>Δ</mml:mi>
                  <mml:mi>t</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Or:</p>
        <p><inline-formula><mml:math display="inline"><mml:mi> α </mml:mi></mml:math></inline-formula> : The coefficient of dilation</p>
        <p><inline-formula><mml:math><mml:mrow><mml:mi> Δ </mml:mi><mml:mi> t </mml:mi><mml:mo></mml:mo></mml:mrow></mml:math></inline-formula> : Temperature variation ˚C</p>
        <disp-formula id="FD27">
          <label>(Ωm)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>ρ</mml:mi>
                <mml:mi>o</mml:mi>
              </mml:msub>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD28">
          <label>(26)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>R</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>ρ</mml:mi>
                    <mml:mi>o</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mn>1</mml:mn>
                      <mml:mo>+</mml:mo>
                      <mml:mi>α</mml:mi>
                      <mml:mi>Δ</mml:mi>
                      <mml:mi>t</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                  <mml:mi>l</mml:mi>
                </mml:mrow>
                <mml:mi>s</mml:mi>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mi>Ω</mml:mi>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>2.4.2. Inductance Model</p>
        <p>A conductor carrying a varying current “<italic>I</italic>” generates a magnetic flux “<italic>φ</italic>”. The variation of this flux is the cause of the appearance of the induced voltage. To account for these effects, the linear inductance of a conductor alone is defined as follows [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>]:</p>
        <disp-formula id="FD29">
          <label>(27)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>L</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mi>φ</mml:mi>
                <mml:mi>I</mml:mi>
              </mml:mfrac>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>μ</mml:mi>
                    <mml:mn>0</mml:mn>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:mn>2</mml:mn>
                  <mml:mi>π</mml:mi>
                </mml:mrow>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>ln</mml:mi>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:mn>2</mml:mn>
                      <mml:mi>h</mml:mi>
                    </mml:mrow>
                    <mml:mi>D</mml:mi>
                  </mml:mfrac>
                  <mml:mo>+</mml:mo>
                  <mml:mfrac>
                    <mml:mn>1</mml:mn>
                    <mml:mrow>
                      <mml:mn>4</mml:mn>
                      <mml:mi>n</mml:mi>
                    </mml:mrow>
                  </mml:mfrac>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With: <italic>h</italic> (m): height of the line relative to the ground. <italic>D</italic> (mm): diameter of the conductor. <italic>n</italic>: Number of conductors in the bundle [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>].</p>
        <p>2.4.3. Capacity Model</p>
        <p>The electric field established between the line and ground is the cause of the appearance of capacitive current (leakage current). To account for these effects, capacitance is defined as follows [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>]:</p>
        <disp-formula id="FD30">
          <label>(28)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>C</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mi>Q</mml:mi>
                <mml:mi>v</mml:mi>
              </mml:mfrac>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mn>2</mml:mn>
                  <mml:mi>π</mml:mi>
                  <mml:msub>
                    <mml:mi>ε</mml:mi>
                    <mml:mn>0</mml:mn>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:mi>ln</mml:mi>
                  <mml:mfrac>
                    <mml:mi>D</mml:mi>
                    <mml:mi>h</mml:mi>
                  </mml:mfrac>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
      </sec>
      <sec id="sec2dot5">
        <title>2.5. Modeling of Energy Losses in High-Voltage Lines</title>
        <p>For the calculations of losses in the lines, we assume that the current intensities are balanced in the lines; that is, we start from the assumption of equipartition of the loads in the lines. Energy <italic>losses</italic>in HV lines are intrinsically linked to Maxwell’s equations, in particular via Poynting’s theorem, which describes the electromagnetic energy balance. The term for dissipation due to the Joule effect appears in the local energy conservation equation.</p>
        <p>The starting point is Poynting’s theorem in its local form, derived from Maxwell’s equations (notably Maxwell-Faraday and Maxwell-Ampère) [<xref ref-type="bibr" rid="B36">36</xref>]-[<xref ref-type="bibr" rid="B40">40</xref>]:</p>
        <disp-formula id="FD31">
          <label>(29)</label>
          <mml:math>
            <mml:mrow>
              <mml:mo>∇</mml:mo>
              <mml:mo>⋅</mml:mo>
              <mml:mi>Π</mml:mi>
              <mml:mo>+</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:msub>
                    <mml:mi>ϖ</mml:mi>
                    <mml:mrow>
                      <mml:mi>e</mml:mi>
                      <mml:mi>m</mml:mi>
                    </mml:mrow>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:mo>∂</mml:mo>
                  <mml:mi>t</mml:mi>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>+</mml:mo>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>j</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD32">
          <label>(30)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>Π</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mn>1</mml:mn>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>μ</mml:mi>
                    <mml:mn>0</mml:mn>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mstyle mathvariant="bold" mathsize="normal">
                    <mml:mi>E</mml:mi>
                  </mml:mstyle>
                  <mml:mo>∧</mml:mo>
                  <mml:mstyle mathvariant="bold" mathsize="normal">
                    <mml:mi>B</mml:mi>
                  </mml:mstyle>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD33">
          <label>(31)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>ϖ</mml:mi>
                <mml:mrow>
                  <mml:mi>e</mml:mi>
                  <mml:mi>m</mml:mi>
                </mml:mrow>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mn>1</mml:mn>
                <mml:mn>2</mml:mn>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>ε</mml:mi>
                    <mml:mn>0</mml:mn>
                  </mml:msub>
                  <mml:mstyle mathvariant="bold" mathsize="normal">
                    <mml:mi>E</mml:mi>
                  </mml:mstyle>
                  <mml:mo>+</mml:mo>
                  <mml:mfrac>
                    <mml:mn>1</mml:mn>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>μ</mml:mi>
                        <mml:mn>0</mml:mn>
                      </mml:msub>
                    </mml:mrow>
                  </mml:mfrac>
                  <mml:msup>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>B</mml:mi>
                    </mml:mstyle>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With: <inline-formula><mml:math display="inline"><mml:mi> Π </mml:mi></mml:math></inline-formula> is the Poynting vector (surface density of electromagnetic power). <inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> ϖ </mml:mi><mml:mrow><mml:mi> e </mml:mi><mml:mi> m </mml:mi></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> is the volumetric density of stored electromagnetic energy. <inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> P </mml:mi><mml:mi> j </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> is the volumetric density of power dissipated by Joule effect.</p>
        <p>By combining Maxwell’s equations, we can isolate the dissipation term. For a conducting medium obeying local Ohm’s law (<italic>J</italic>= <italic>ρE</italic>), where <italic>ρ</italic> is the electrical conductivity, the volumetric power density dissipated by Joule heating is given by:</p>
        <disp-formula id="FD34">
          <label>(32)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>j</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>E</mml:mi>
              </mml:mstyle>
              <mml:mo>⋅</mml:mo>
              <mml:mstyle mathvariant="bold" mathsize="normal">
                <mml:mi>j</mml:mi>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Using Ohm’s law, it can be expressed as a function of the electric field or current density:</p>
        <disp-formula id="FD35">
          <label>(33)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>j</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mi>σ</mml:mi>
              <mml:msup>
                <mml:mi>E</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msup>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mn>1</mml:mn>
                <mml:mi>σ</mml:mi>
              </mml:mfrac>
              <mml:msup>
                <mml:mi>J</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msup>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>To obtain the total power dissipated by Joule heating in a given volume <italic>V</italic> (for example, a conductor of resistance <italic>R</italic>), the volumetric power density must be integrated over this volume:</p>
        <disp-formula id="FD36">
          <label>(34)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>p</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∭</mml:mo>
                    <mml:mi>v</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:msub>
                      <mml:mi>P</mml:mi>
                      <mml:mi>j</mml:mi>
                    </mml:msub>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>v</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
              <mml:mo>=</mml:mo>
              <mml:mstyle displaystyle="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mo>∭</mml:mo>
                    <mml:mi>v</mml:mi>
                  </mml:msub>
                  <mml:mrow>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>E</mml:mi>
                    </mml:mstyle>
                    <mml:mo>⋅</mml:mo>
                    <mml:mstyle mathvariant="bold" mathsize="normal">
                      <mml:mi>j</mml:mi>
                    </mml:mstyle>
                    <mml:mtext>d</mml:mtext>
                    <mml:mi>v</mml:mi>
                  </mml:mrow>
                </mml:mrow>
              </mml:mstyle>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>This integration leads, in the simple case of an Ohmic circuit, to the well-known macroscopic law:</p>
        <disp-formula id="FD37">
          <label>(35)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>p</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mi>R</mml:mi>
              <mml:msup>
                <mml:mi>I</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msup>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>For a high-voltage line of <italic>L</italic><italic><sub>c</sub></italic> = conductor length, containing <italic>n</italic> conductors of the line and <italic>R</italic><italic><sub>c</sub></italic> = linear resistance, carrying the maximum current Imax, the Joule effect losses in this line are calculated using the following equation:</p>
        <disp-formula id="FD38">
          <label>(36)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>j</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mi>n</mml:mi>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>c</mml:mi>
                  </mml:msub>
                  <mml:msubsup>
                    <mml:mi>I</mml:mi>
                    <mml:mrow>
                      <mml:mi>max</mml:mi>
                    </mml:mrow>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                  <mml:msub>
                    <mml:mi>L</mml:mi>
                    <mml:mi>c</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mrow>
                <mml:mo>[</mml:mo>
                <mml:mtext>W</mml:mtext>
                <mml:mo>]</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With:</p>
        <p><italic>P</italic><italic><sub>j</sub></italic> = Joule effect losses in lines</p>
        <p><italic>n</italic> = Number of conductors on the line</p>
        <p><italic>R</italic><italic><sub>c</sub></italic> = Linear resistance [Ω/km]</p>
        <p><italic>I</italic><sub>max</sub> = Maximum current of a conductor [A]</p>
        <p><italic>L</italic><italic><sub>c</sub></italic> = Length of conductor [m]</p>
        <p>These losses are obtained primarily based on the physical characteristics of the line. Given the line voltage and the current it can carry, the active power that the line will supply can perhaps be modelled as follows [<xref ref-type="bibr" rid="B41">41</xref>]: </p>
        <disp-formula id="FD39">
          <label>(37)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>P</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:msqrt>
                <mml:mn>3</mml:mn>
              </mml:msqrt>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msub>
                <mml:mi>I</mml:mi>
                <mml:mrow>
                  <mml:mi>max</mml:mi>
                </mml:mrow>
              </mml:msub>
              <mml:mi>cos</mml:mi>
              <mml:mi>φ</mml:mi>
              <mml:mrow>
                <mml:mo>[</mml:mo>
                <mml:mrow>
                  <mml:mtext>kW</mml:mtext>
                </mml:mrow>
                <mml:mo>]</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With: </p>
        <p><italic>P</italic> = Active power supplied by the line;<italic>U</italic><italic><sub>L</sub></italic> = Line voltage [kV];<italic>I</italic><sub>max</sub> = intensity of a conductor [A];<inline-formula><mml:math><mml:mrow><mml:mi> cos </mml:mi><mml:mi> φ </mml:mi><mml:mo> = </mml:mo><mml:mn> 0.9 </mml:mn></mml:mrow></mml:math></inline-formula></p>
        <p>We know that in a conductor, the power lost due to Joule heating is “<inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> c </mml:mi></mml:msub><mml:msubsup><mml:mi> I </mml:mi><mml:mi> c </mml:mi><mml:mn> 2 </mml:mn></mml:msubsup></mml:mrow></mml:math></inline-formula> ”, with “<inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> I </mml:mi><mml:mi> c </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> ”, the current flowing in the conductor. Considering the balanced, three-phase line, the apparent power it carries will be written as follows [<xref ref-type="bibr" rid="B42">42</xref>]:</p>
        <disp-formula id="FD40">
          <label>(38)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>S</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:msqrt>
                <mml:mn>3</mml:mn>
              </mml:msqrt>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msub>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:msqrt>
                <mml:mrow>
                  <mml:msup>
                    <mml:mi>P</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                  <mml:mo>+</mml:mo>
                  <mml:msup>
                    <mml:mi>Q</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                </mml:mrow>
              </mml:msqrt>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With:</p>
        <p><italic>U</italic><italic><sub>L</sub></italic> = Line voltage (kV)</p>
        <p><italic>I</italic><italic><sub>L</sub></italic> = Line intensity (A)</p>
        <p><italic>P</italic> = Active power carried by the line (W)</p>
        <p><italic>Q</italic> = reactive power carried by the line (VAr)</p>
        <p>Consider the following equality:</p>
        <disp-formula id="FD41">
          <label>(39)</label>
          <mml:math>
            <mml:mrow>
              <mml:mn>3</mml:mn>
              <mml:msubsup>
                <mml:mi>U</mml:mi>
                <mml:mi>L</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msubsup>
              <mml:msubsup>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msubsup>
              <mml:mo>=</mml:mo>
              <mml:msup>
                <mml:mi>P</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msup>
              <mml:mo>+</mml:mo>
              <mml:msup>
                <mml:mi>Q</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msup>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Thus we can draw the line current <italic>I</italic><italic><sub>L</sub></italic>:</p>
        <disp-formula id="FD42">
          <label>(40)</label>
          <mml:math>
            <mml:mrow>
              <mml:msubsup>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msubsup>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msup>
                    <mml:mi>P</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                  <mml:mo>+</mml:mo>
                  <mml:msup>
                    <mml:mi>Q</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                </mml:mrow>
                <mml:mrow>
                  <mml:mn>3</mml:mn>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>The power loss “<italic>P</italic><italic><sub>P</sub></italic>” in the line can thus be noted as:</p>
        <disp-formula id="FD43">
          <label>(41)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>P</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mn>3</mml:mn>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msubsup>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msubsup>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Substituting expression (40) into relation (41) gives us:</p>
        <disp-formula id="FD44">
          <label>(42)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>P</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mn>3</mml:mn>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msubsup>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
                <mml:mn>2</mml:mn>
              </mml:msubsup>
              <mml:mo>=</mml:mo>
              <mml:mn>3</mml:mn>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:msup>
                        <mml:mi>P</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msup>
                      <mml:mo>+</mml:mo>
                      <mml:msup>
                        <mml:mi>Q</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msup>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:mn>3</mml:mn>
                      <mml:msubsup>
                        <mml:mi>U</mml:mi>
                        <mml:mi>L</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msubsup>
                    </mml:mrow>
                  </mml:mfrac>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD45">
          <label>(43)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mi>P</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:msup>
                        <mml:mi>P</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msup>
                      <mml:mo>+</mml:mo>
                      <mml:msup>
                        <mml:mi>Q</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msup>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:msubsup>
                        <mml:mi>U</mml:mi>
                        <mml:mi>L</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msubsup>
                    </mml:mrow>
                  </mml:mfrac>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msup>
                    <mml:mi>P</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>+</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msup>
                    <mml:mi>Q</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With: <italic>R</italic><italic><sub>L</sub></italic>, <italic>I</italic><italic><sub>L</sub></italic> and <italic>U</italic><italic><sub>L</sub></italic>, respectively the line resistance, the maximum line current and the line voltage.</p>
        <p>The relative losses in the line are thus given by the following expression:</p>
        <disp-formula id="FD46">
          <label>(44)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mrow>
                  <mml:mi>p</mml:mi>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mn>3</mml:mn>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msubsup>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
                <mml:mrow>
                  <mml:msqrt>
                    <mml:mn>3</mml:mn>
                  </mml:msqrt>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>cos</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>With:</p>
        <p><inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> P </mml:mi><mml:mrow><mml:mi> p </mml:mi><mml:mi> r </mml:mi></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> : Relative power losses in %;<inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> I </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> : Line intensity in A;<inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> : Conductor resistance in Ω;<inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> U </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> : Voltage composed of a V-shaped line.</p>
      </sec>
      <sec id="sec2dot6">
        <title>2.6. Modeling of the Relative Voltage Drop in the HV Line</title>
        <p>The assumptions for calculating the voltage drop in AC for a high-voltage AC line are that the overvoltage is primarily caused by the longitudinal parameters, resistance and reactance in series (<italic>R</italic><italic><sub>L</sub></italic>, <italic>X</italic><italic><sub>L</sub></italic>), and that the contribution of the transverse parameters is negligible. The transmission line model adopted is therefore the equivalent circuit shown in <xref ref-type="fig" rid="fig3">Figure 3</xref> below [<xref ref-type="bibr" rid="B43">43</xref>][<xref ref-type="bibr" rid="B44">44</xref>]:</p>
        <fig id="fig3">
          <label>Figure 3</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId174.jpeg?20260430040522" />
        </fig>
        <p><bold>Figure 3.</bold>Equivalent circuit of the HV line [<xref ref-type="bibr" rid="B43">43</xref>]-[<xref ref-type="bibr" rid="B47">47</xref>].</p>
        <p>Legend</p>
        <p><inline-formula><mml:math><mml:mrow><mml:mover accent="true"><mml:mrow><mml:msub><mml:mi> U </mml:mi><mml:mi> O </mml:mi></mml:msub></mml:mrow><mml:mo stretchy="true"> ¯ </mml:mo></mml:mover></mml:mrow></mml:math></inline-formula> =Voltage from the origin relative to neutral in kV</p>
        <p><inline-formula><mml:math><mml:mrow><mml:mover accent="true"><mml:mrow><mml:msub><mml:mi> I </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow><mml:mo stretchy="true"> ¯ </mml:mo></mml:mover></mml:mrow></mml:math></inline-formula> =Maximum line intensity at A</p>
        <p><inline-formula><mml:math><mml:mrow><mml:mover accent="true"><mml:mrow><mml:msub><mml:mi> U </mml:mi><mml:mi> F </mml:mi></mml:msub></mml:mrow><mml:mo stretchy="true"> ¯ </mml:mo></mml:mover></mml:mrow></mml:math></inline-formula> =Voltage at the end relative to neutral in kV</p>
        <p><inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> X </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> = Reactance inductance of the line in Ω</p>
        <p><inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> =Line resistance in Ω</p>
        <p>Applying Kirchhoff’s law to <xref ref-type="fig" rid="fig3">Figure 3</xref> above, we find the following equations:</p>
        <disp-formula id="FD47">
          <label>(45)</label>
          <mml:math>
            <mml:mrow>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>O</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
              <mml:mo>=</mml:mo>
              <mml:msub>
                <mml:mi>X</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
              <mml:mo>+</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
              <mml:mo>+</mml:mo>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>F</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD48">
          <label>(46)</label>
          <mml:math>
            <mml:mrow>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>O</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
              <mml:mo>−</mml:mo>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>F</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
              <mml:mo>=</mml:mo>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mo>+</mml:mo>
                  <mml:msub>
                    <mml:mi>X</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
              <mml:mover accent="true">
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mo stretchy="true">¯</mml:mo>
              </mml:mover>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD49">
          <label>(47)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>Δ</mml:mi>
                <mml:mi>U</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mrow>
                <mml:mo>|</mml:mo>
                <mml:mrow>
                  <mml:mover accent="true">
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>U</mml:mi>
                        <mml:mi>O</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                    <mml:mo stretchy="true">¯</mml:mo>
                  </mml:mover>
                </mml:mrow>
                <mml:mo>|</mml:mo>
              </mml:mrow>
              <mml:mo>−</mml:mo>
              <mml:mrow>
                <mml:mo>|</mml:mo>
                <mml:mrow>
                  <mml:mover accent="true">
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>U</mml:mi>
                        <mml:mi>F</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                    <mml:mo stretchy="true">¯</mml:mo>
                  </mml:mover>
                </mml:mrow>
                <mml:mo>|</mml:mo>
              </mml:mrow>
              <mml:mo>≈</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msub>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mi>cos</mml:mi>
              <mml:mi>φ</mml:mi>
              <mml:mo>+</mml:mo>
              <mml:msub>
                <mml:mi>X</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msub>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mi>sin</mml:mi>
              <mml:mi>φ</mml:mi>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Thus, the relative phase-to-neutral voltage drop can be denoted by the following equation:</p>
        <disp-formula id="FD50">
          <label>(48)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mi>Δ</mml:mi>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>r</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>Δ</mml:mi>
                    <mml:mi>U</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Integrating Equation (47) into expression (48), we find the following equations:</p>
        <disp-formula id="FD51">
          <label>(49)</label>
          <mml:math>
            <mml:mrow>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>Δ</mml:mi>
                    <mml:mi>U</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>cos</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>+</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>X</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>sin</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD52">
          <label>(50)</label>
          <mml:math>
            <mml:mrow>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>Δ</mml:mi>
                    <mml:mi>U</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>cos</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>+</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>X</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>sin</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Multiplying the right-hand side of Equation (50) by <inline-formula><mml:math><mml:mrow><mml:msqrt><mml:mn> 3 </mml:mn></mml:msqrt></mml:mrow></mml:math></inline-formula> , the voltage drop relative to the line voltage gives:</p>
        <disp-formula id="FD53">
          <label>(51)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>Δ</mml:mi>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>r</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msqrt>
                    <mml:mn>3</mml:mn>
                  </mml:msqrt>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>cos</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>+</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>X</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msqrt>
                    <mml:mn>3</mml:mn>
                  </mml:msqrt>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>sin</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>We know that in three-phase:</p>
        <disp-formula id="FD54">
          <label>(52)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>P</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:msqrt>
                <mml:mn>3</mml:mn>
              </mml:msqrt>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msub>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mi>cos</mml:mi>
              <mml:mi>φ</mml:mi>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD55">
          <label>(53)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>Q</mml:mi>
              <mml:mo>=</mml:mo>
              <mml:msqrt>
                <mml:mn>3</mml:mn>
              </mml:msqrt>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:msub>
                <mml:mi>I</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mi>sin</mml:mi>
              <mml:mi>φ</mml:mi>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Thus, expressions (52) and (53) in relation (51) give us:</p>
        <disp-formula id="FD56">
          <label>(54)</label>
          <mml:math display="inline">
            <mml:mrow>
              <mml:mi>Δ</mml:mi>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>r</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>P</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>+</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>X</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>Q</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Let’s highlight <italic>R</italic><italic><sub>L</sub></italic> in Equation (54), so we find:</p>
        <disp-formula id="FD57">
          <label>(55)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>Δ</mml:mi>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>r</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mi>P</mml:mi>
                  <mml:mo>+</mml:mo>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>X</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>R</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                  </mml:mfrac>
                  <mml:mi>Q</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Therefore, <inline-formula><mml:math><mml:mrow><mml:mfrac><mml:mi> Q </mml:mi><mml:mi> P </mml:mi></mml:mfrac><mml:mo> = </mml:mo><mml:mtext> tg </mml:mtext><mml:mi> φ </mml:mi></mml:mrow></mml:math></inline-formula> in expression (55), we find:</p>
        <disp-formula id="FD58">
          <label>(56)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>Δ</mml:mi>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>r</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mi>P</mml:mi>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>+</mml:mo>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>X</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>R</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                  </mml:mfrac>
                  <mml:mtext>tg</mml:mtext>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD59">
          <label>(57)</label>
          <mml:math>
            <mml:mrow>
              <mml:mi>Δ</mml:mi>
              <mml:msub>
                <mml:mi>U</mml:mi>
                <mml:mi>r</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msqrt>
                    <mml:mn>3</mml:mn>
                  </mml:msqrt>
                  <mml:msub>
                    <mml:mi>R</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:msub>
                    <mml:mi>I</mml:mi>
                    <mml:mi>L</mml:mi>
                  </mml:msub>
                  <mml:mi>cos</mml:mi>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mrow>
                  <mml:msubsup>
                    <mml:mi>U</mml:mi>
                    <mml:mi>L</mml:mi>
                    <mml:mn>2</mml:mn>
                  </mml:msubsup>
                </mml:mrow>
              </mml:mfrac>
              <mml:mrow>
                <mml:mo>(</mml:mo>
                <mml:mrow>
                  <mml:mn>1</mml:mn>
                  <mml:mo>+</mml:mo>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>X</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:msub>
                        <mml:mi>R</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                    </mml:mrow>
                  </mml:mfrac>
                  <mml:mtext>tg</mml:mtext>
                  <mml:mi>φ</mml:mi>
                </mml:mrow>
                <mml:mo>)</mml:mo>
              </mml:mrow>
            </mml:mrow>
          </mml:math>
        </disp-formula>
      </sec>
      <sec id="sec2dot7">
        <title>2.7. Modeling of Energy Losses in High-Voltage Lines Depending on the Relative Voltage Drop</title>
        <p>Since losses result, among other things, in voltage drop, we can determine the models that highlight the losses related to the active power transmitted by the line and the voltage drop related to the line voltage, based on expressions (44) and (57). The ratio between <inline-formula><mml:math><mml:mrow><mml:msub><mml:mi> P </mml:mi><mml:mrow><mml:mi> p </mml:mi><mml:mi> r </mml:mi></mml:mrow></mml:msub></mml:mrow></mml:math></inline-formula> these two values <inline-formula><mml:math display="inline"><mml:mrow><mml:mi> Δ </mml:mi><mml:msub><mml:mi> U </mml:mi><mml:mi> r </mml:mi></mml:msub></mml:mrow></mml:math></inline-formula> gives:</p>
        <disp-formula id="FD60">
          <label>(58)</label>
          <mml:math>
            <mml:mrow>
              <mml:mfrac>
                <mml:mrow>
                  <mml:msub>
                    <mml:mi>P</mml:mi>
                    <mml:mrow>
                      <mml:mi>p</mml:mi>
                      <mml:mi>r</mml:mi>
                    </mml:mrow>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:mi>Δ</mml:mi>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>r</mml:mi>
                  </mml:msub>
                </mml:mrow>
              </mml:mfrac>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:mn>3</mml:mn>
                      <mml:msub>
                        <mml:mi>R</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                      <mml:msubsup>
                        <mml:mi>I</mml:mi>
                        <mml:mi>L</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msubsup>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:msqrt>
                        <mml:mn>3</mml:mn>
                      </mml:msqrt>
                      <mml:msub>
                        <mml:mi>U</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                      <mml:msub>
                        <mml:mi>I</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                      <mml:mi>cos</mml:mi>
                      <mml:mi>φ</mml:mi>
                    </mml:mrow>
                  </mml:mfrac>
                </mml:mrow>
                <mml:mrow>
                  <mml:mfrac>
                    <mml:mrow>
                      <mml:msqrt>
                        <mml:mn>3</mml:mn>
                      </mml:msqrt>
                      <mml:msub>
                        <mml:mi>R</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                      <mml:msub>
                        <mml:mi>U</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                      <mml:msub>
                        <mml:mi>I</mml:mi>
                        <mml:mi>L</mml:mi>
                      </mml:msub>
                      <mml:mi>cos</mml:mi>
                      <mml:mi>φ</mml:mi>
                    </mml:mrow>
                    <mml:mrow>
                      <mml:msubsup>
                        <mml:mi>U</mml:mi>
                        <mml:mi>L</mml:mi>
                        <mml:mn>2</mml:mn>
                      </mml:msubsup>
                    </mml:mrow>
                  </mml:mfrac>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mn>1</mml:mn>
                      <mml:mo>+</mml:mo>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:msub>
                            <mml:mi>X</mml:mi>
                            <mml:mi>L</mml:mi>
                          </mml:msub>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:msub>
                            <mml:mi>R</mml:mi>
                            <mml:mi>L</mml:mi>
                          </mml:msub>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mtext>tg</mml:mtext>
                      <mml:mi>φ</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>Hence:</p>
        <disp-formula id="FD61">
          <label>(59)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mrow>
                  <mml:mi>p</mml:mi>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mi>Δ</mml:mi>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>r</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msup>
                    <mml:mrow>
                      <mml:mi>cos</mml:mi>
                    </mml:mrow>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                  <mml:mi>φ</mml:mi>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mn>1</mml:mn>
                      <mml:mo>+</mml:mo>
                      <mml:mfrac>
                        <mml:mrow>
                          <mml:msub>
                            <mml:mi>X</mml:mi>
                            <mml:mi>L</mml:mi>
                          </mml:msub>
                        </mml:mrow>
                        <mml:mrow>
                          <mml:msub>
                            <mml:mi>R</mml:mi>
                            <mml:mi>L</mml:mi>
                          </mml:msub>
                        </mml:mrow>
                      </mml:mfrac>
                      <mml:mtext>tg</mml:mtext>
                      <mml:mi>φ</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>From this relation (59), we can draw the following conclusions:</p>
        <disp-formula id="FD62">
          <label>(60)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>X</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mn>0</mml:mn>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD63">
          <label>(61)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>X</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mo>≅</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <disp-formula id="FD64">
          <label>(62)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>X</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
              <mml:mo>≠</mml:mo>
              <mml:msub>
                <mml:mi>R</mml:mi>
                <mml:mi>L</mml:mi>
              </mml:msub>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p><inline-formula><mml:math><mml:mrow><mml:mfrac><mml:mrow><mml:msub><mml:mi> X </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:mfrac><mml:mo> = </mml:mo><mml:mtext> tg </mml:mtext><mml:mi> δ </mml:mi></mml:mrow></mml:math></inline-formula> The quality factor of a high-voltage (HV) line is typically between 2 and 10 for a 220 kV HV line. <inline-formula><mml:math><mml:mrow><mml:mtext> tg </mml:mtext><mml:mi> δ </mml:mi></mml:mrow></mml:math></inline-formula> It is calculated based on the linear inductance (<italic>L</italic>) and resistance (<italic>R</italic>), which are low over long distances. The quality factor of an HV power line is not a standard value, but rather the result of calculations based on its physical properties (inductance, resistance, capacitance) and the line frequency.</p>
        <disp-formula id="FD65">
          <label>(63)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mrow>
                  <mml:mi>p</mml:mi>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mi>Δ</mml:mi>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>r</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msup>
                    <mml:mrow>
                      <mml:mi>cos</mml:mi>
                    </mml:mrow>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                  <mml:mi>φ</mml:mi>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mn>1</mml:mn>
                      <mml:mo>+</mml:mo>
                      <mml:mtext>tg</mml:mtext>
                      <mml:mi>δ</mml:mi>
                      <mml:mo>⋅</mml:mo>
                      <mml:mtext>tg</mml:mtext>
                      <mml:mi>φ</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
        <p>The <inline-formula><mml:math><mml:mrow><mml:mtext> tg </mml:mtext><mml:mi> δ </mml:mi><mml:mo> = </mml:mo><mml:mn> 2 </mml:mn></mml:mrow></mml:math></inline-formula> , losses related to the active power transmitted by the HV line as a function of the voltage drop relative to the line voltage are quantified from expression (64) below:</p>
        <disp-formula id="FD66">
          <label>(64)</label>
          <mml:math>
            <mml:mrow>
              <mml:msub>
                <mml:mi>P</mml:mi>
                <mml:mrow>
                  <mml:mi>p</mml:mi>
                  <mml:mi>r</mml:mi>
                </mml:mrow>
              </mml:msub>
              <mml:mo>=</mml:mo>
              <mml:mfrac>
                <mml:mrow>
                  <mml:mi>Δ</mml:mi>
                  <mml:msub>
                    <mml:mi>U</mml:mi>
                    <mml:mi>r</mml:mi>
                  </mml:msub>
                </mml:mrow>
                <mml:mrow>
                  <mml:msup>
                    <mml:mrow>
                      <mml:mi>cos</mml:mi>
                    </mml:mrow>
                    <mml:mn>2</mml:mn>
                  </mml:msup>
                  <mml:mi>φ</mml:mi>
                  <mml:mrow>
                    <mml:mo>(</mml:mo>
                    <mml:mrow>
                      <mml:mn>1</mml:mn>
                      <mml:mo>+</mml:mo>
                      <mml:mn>2</mml:mn>
                      <mml:mo>⋅</mml:mo>
                      <mml:mtext>tg</mml:mtext>
                      <mml:mi>φ</mml:mi>
                    </mml:mrow>
                    <mml:mo>)</mml:mo>
                  </mml:mrow>
                </mml:mrow>
              </mml:mfrac>
            </mml:mrow>
          </mml:math>
        </disp-formula>
      </sec>
      <sec id="sec2dot8">
        <title>2.8. Accurate and Reproducible Description of the Use of High Voltage (HV) Line Data</title>
        <p>To provide an accurate and reproducible description of the use of data from the SNEL Inga-Kinshasa HV line in a calculation or simulation model, the following are the standard parameters generally applied in engineering studies of the Congolese grid:</p>
        <p>2.8.1. Dataset Description</p>
        <p><bold>Source</bold>: SNEL (National Electricity Company) SCADA System.<bold>Measurement Points</bold>:Transmitting End: Inga substations (Inga 1 or Inga 2).Receiving End: Kimwenza substations (depending on the specific line of the corridor).Parameters Collected: Line Voltage (<italic>U</italic>), Phase Current (<italic>I</italic>), Active Power (<italic>P</italic>), Reactive Power (<italic>Q</italic>), and Frequency (<italic>f</italic>).</p>
        <p>2.8.2. Processing Protocol (Model)</p>
        <p>Sampling Interval: Typically 10 seconds for SCADA historical archiving, although phase measurement units (PMUs), if present, can reach 50 - 60 samples per second.Averaging Window: Raw data is often integrated over a 10 - 15 minute window for load planning studies, or stored at the second level for transient stability analyses.Operating Conditions: Steady State for power flows. Data generally excludes periods of major maintenance unless the study focuses on reliability.Preprocessing:Filtering of outliers due to telecommunication errors.Normalization (per unit conversion) based on nominal voltages (220 kV depending on the segment).</p>
        <p>2.8.3. Assumptions of Uncertainty and Accuracy</p>
        <p>In the absence of specific calibration certificates, the models use the following industry standards for high-voltage sensors:</p>
        <p><bold>a) Voltage Measurements (TP):</bold></p>
        <p>Accuracy class: 0.5% to 1%.Allowable uncertainty: ±1% (including transmission line errors).</p>
        <p><bold>b) Current Measurements (TI):</bold></p>
        <p>Accuracy class: 0.5% (measurement) or 5P20 (protection).Allowable uncertainty: ±1.5% at full scale.</p>
        <p><bold>c) Power (P and Q):</bold></p>
        <p>The combined uncertainty is generally estimated at ±2% to ±3%.</p>
        <p>2.8.4. Use in the Model</p>
        <p><bold>The data is primarily used for:</bold></p>
        <p>Validation: Adjusting the line parameters (impedance, admittance) so that the software results (Matlab) correspond to the actual measurements.State Estimation: Verify the consistency of redundant measurements between Inga and Kinshasa to identify actual line losses.</p>
      </sec>
    </sec>
    <sec id="sec3">
      <title>3. Simulation</title>
      <sec id="sec3dot1">
        <title>3.1. Declaration of High-Voltage Line Parameters</title>
        <p>The numerical values of the HV line parameters, such as <italic>R</italic><italic><sub>L</sub></italic> = 0.07 Ω/km, <italic>X</italic><italic><sub>L</sub></italic> = 0.15 Ω/km, line length 262 km, power factor cos<italic>φ</italic> = 0.9, tg<italic>φ</italic> = 0.484, and respective active and reactive power (<italic>P</italic> = 350 MW and <italic>Q</italic> = 169.4 MVAr the line input) and (<italic>P</italic> = 279 MW and <italic>Q</italic> = 84.1 MVAr the line output), are taken from SNEL/DRC. </p>
      </sec>
      <sec id="sec3dot2">
        <title>3.2. Simulation Results</title>
        <p>Energy losses are a major concern for all producers, transmission, and distribution of electrical energy. To simulate these losses in high-voltage lines, we assumed that the current intensities were balanced. Considering the proposed models (see Equations (57) and (64)), the computer tools used, the characteristic data of the 220 kV line, and the power transmission readings provided by SNEL/DG/PKB, the simulation results are presented in <xref ref-type="fig" rid="fig4">Figures 4-20</xref> below:</p>
        <fig id="fig4">
          <label>Figure 4</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId244.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 4.</bold> Simulink model of power transmission on the 220 kV Inga-Kimwenza high-voltage line.</p>
        <fig id="fig5">
          <label>Figure 5</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId245.jpeg?20260430040528" />
        </fig>
        <p><bold>Figure 5</bold><bold>.</bold> Voltage of point A the Inga dispersal substation (220 kV HV line input) in Volts.</p>
        <fig id="fig6">
          <label>Figure 6</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId246.jpeg?20260430040528" />
        </fig>
        <p><bold>Figure 6</bold><bold>.</bold> Current of point A the Inga dispersal substation (220 kV HV line input) in Amperes.</p>
        <fig id="fig7">
          <label>Figure 7</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId247.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 7.</bold> (a) Active power in Watts and (b) Reactive power at point A the Inga dispersal station (HV line inlet).</p>
        <fig id="fig8">
          <label>Figure 8</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId248.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 8.</bold>Voltage at point B the Kimwenza substation (220 kV HV line output) in Volts.</p>
        <fig id="fig9">
          <label>Figure 9</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId249.jpeg?20260430040528" />
        </fig>
        <p><bold>Figure 9.</bold> Current at point B at the Kimwenza substation (220 kV HV line output) in Amperes.</p>
        <fig id="fig10">
          <label>Figure 10</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId250.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 10.</bold> (a) Active power in Watts and (b) Reactive power of point B the Kimwenza substation (high-voltage line output).</p>
        <fig id="fig11">
          <label>Figure 11</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId251.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 11.</bold> Simulink model of the voltage drop on the 220 kV Inga-Kimwenza high-voltage line.</p>
        <fig id="fig12">
          <label>Figure 12</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId252.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 12.</bold> Voltage drop in % the end of the 220 kV Inga-Kimwenza high-voltage line.</p>
        <fig id="fig13">
          <label>Figure 13</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId253.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 13.</bold>Voltage drop in kV the end of the 220 kV Inga-Kimwenza high-voltage line.</p>
        <fig id="fig14">
          <label>Figure 14</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId254.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 14.</bold>Simulink model of active power losses (in % and in Watts) in the 220 kV Inga-Kimwenza high-voltage line.</p>
        <fig id="fig15">
          <label>Figure 15</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId255.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 15</bold><bold>.</bold> Results (a) active power losses in % and (b) active power losses in Watts in the 220 kV HV line obtained from the Simulink model.</p>
        <fig id="fig16">
          <label>Figure 16</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId256.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 16</bold><bold>.</bold> Model of the equation <inline-formula><mml:math><mml:mrow><mml:mi> Δ </mml:mi><mml:msub><mml:mi> U </mml:mi><mml:mi> r </mml:mi></mml:msub><mml:mo> = </mml:mo><mml:mfrac><mml:mrow><mml:msqrt><mml:mn> 3 </mml:mn></mml:msqrt><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:msub><mml:mi> U </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:msub><mml:mi> I </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:mi> cos </mml:mi><mml:mi> φ </mml:mi></mml:mrow><mml:mrow><mml:msubsup><mml:mi> U </mml:mi><mml:mi> L </mml:mi><mml:mn> 2 </mml:mn></mml:msubsup></mml:mrow></mml:mfrac><mml:mrow><mml:mo> ( </mml:mo><mml:mrow><mml:mn> 1 </mml:mn><mml:mo> + </mml:mo><mml:mfrac><mml:mrow><mml:msub><mml:mi> X </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:mfrac><mml:mtext> tg </mml:mtext><mml:mi> φ </mml:mi></mml:mrow><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> (57) proposed for calculating the voltage drop on the HV line.</p>
        <fig id="fig17">
          <label>Figure 17</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId259.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 17.</bold>Results of the equation model <inline-formula><mml:math><mml:mrow><mml:mi> Δ </mml:mi><mml:msub><mml:mi> U </mml:mi><mml:mi> r </mml:mi></mml:msub><mml:mo> = </mml:mo><mml:mfrac><mml:mrow><mml:msqrt><mml:mn> 3 </mml:mn></mml:msqrt><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:msub><mml:mi> U </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:msub><mml:mi> I </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:mi> cos </mml:mi><mml:mi> φ </mml:mi></mml:mrow><mml:mrow><mml:msubsup><mml:mi> U </mml:mi><mml:mi> L </mml:mi><mml:mn> 2 </mml:mn></mml:msubsup></mml:mrow></mml:mfrac><mml:mrow><mml:mo> ( </mml:mo><mml:mrow><mml:mn> 1 </mml:mn><mml:mo> + </mml:mo><mml:mfrac><mml:mrow><mml:msub><mml:mi> X </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:mfrac><mml:mtext> tg </mml:mtext><mml:mi> φ </mml:mi></mml:mrow><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> (57) proposed for calculating the voltage drop in % on the HV line.</p>
        <fig id="fig18">
          <label>Figure 18</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId262.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 18.</bold> Results of the equation model <inline-formula><mml:math><mml:mrow><mml:mi> Δ </mml:mi><mml:msub><mml:mi> U </mml:mi><mml:mi> r </mml:mi></mml:msub><mml:mo> = </mml:mo><mml:mfrac><mml:mrow><mml:msqrt><mml:mn> 3 </mml:mn></mml:msqrt><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:msub><mml:mi> U </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:msub><mml:mi> I </mml:mi><mml:mi> L </mml:mi></mml:msub><mml:mi> cos </mml:mi><mml:mi> φ </mml:mi></mml:mrow><mml:mrow><mml:msubsup><mml:mi> U </mml:mi><mml:mi> L </mml:mi><mml:mn> 2 </mml:mn></mml:msubsup></mml:mrow></mml:mfrac><mml:mrow><mml:mo> ( </mml:mo><mml:mrow><mml:mn> 1 </mml:mn><mml:mo> + </mml:mo><mml:mfrac><mml:mrow><mml:msub><mml:mi> X </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow><mml:mrow><mml:msub><mml:mi> R </mml:mi><mml:mi> L </mml:mi></mml:msub></mml:mrow></mml:mfrac><mml:mtext> tg </mml:mtext><mml:mi> φ </mml:mi></mml:mrow><mml:mo> ) </mml:mo></mml:mrow></mml:mrow></mml:math></inline-formula> (57) proposed for calculating the voltage drop in Volts on the HV line.</p>
        <fig id="fig19">
          <label>Figure 19</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId265.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 19.</bold>Proposed model (Equation (64)) for evaluating active power losses (in % and in Watts) in the HV line. Implemented in Matlab.</p>
        <fig id="fig20">
          <label>Figure 20</label>
          <graphic xlink:href="https://html.scirp.org/file/2313713-rId266.jpeg?20260430040529" />
        </fig>
        <p><bold>Figure 20.</bold>Results of equation 64 (a) active power losses in % and (b) active power losses in Watts in the HV line.</p>
      </sec>
    </sec>
    <sec id="sec4">
      <title>4. Summary of Results</title>
      <p><bold>Table 1.</bold>Power transmission results on the 220 kV HV line.</p>
      <table-wrap id="tbl1">
        <label>Table 1</label>
        <table>
          <tbody>
            <tr>
              <td>Settings</td>
              <td>Simulink model</td>
              <td>High-voltage line readings</td>
              <td>Gap</td>
              <td>%</td>
            </tr>
            <tr>
              <td>High voltage input setpoint in kV</td>
              <td>254 kV</td>
              <td>250</td>
              <td>4 kV</td>
              <td>1.57%</td>
            </tr>
            <tr>
              <td>Line current in A</td>
              <td>894.1 A</td>
              <td>890.1</td>
              <td>4 A</td>
              <td>0.45%</td>
            </tr>
            <tr>
              <td>Operating voltage at the HV line output in kV</td>
              <td>205.5kV</td>
              <td>205 kV</td>
              <td>0.5 kV</td>
              <td>0.24%</td>
            </tr>
            <tr>
              <td>Active power input in MW</td>
              <td>320 MW</td>
              <td>350 MW</td>
              <td>30 MW</td>
              <td>9.3%</td>
            </tr>
            <tr>
              <td>Active power output line in MW</td>
              <td>279 MW</td>
              <td>275.4 MW</td>
              <td>4.4 MW</td>
              <td>1.5%</td>
            </tr>
            <tr>
              <td>Reactive power input in MVAr</td>
              <td>165.3 MVAr</td>
              <td>169.4 MVAr</td>
              <td>4.1 MVAr</td>
              <td>2.5%</td>
            </tr>
            <tr>
              <td>Reactive power output line in MVAr</td>
              <td>79.67 MVAr</td>
              <td>84.1 MVAr</td>
              <td>4.43 MVAr</td>
              <td>5.5%</td>
            </tr>
            <tr>
              <td>Average deviation in %</td>
              <td>-</td>
              <td>-</td>
              <td>-</td>
              <td>3%</td>
            </tr>
          </tbody>
        </table>
      </table-wrap>
      <p><bold>Table 2.</bold>Results of active power losses and voltage drop in the 220 kV HV line.</p>
      <table-wrap id="tbl2">
        <label>Table 2</label>
        <table>
          <tbody>
            <tr>
              <td>Settings</td>
              <td>Simulink model</td>
              <td>Proposed Models</td>
              <td>Gap</td>
              <td>%</td>
            </tr>
            <tr>
              <td>Voltage Drop in %</td>
              <td>19.3%</td>
              <td>18.9%</td>
              <td>0.4%</td>
              <td>2%</td>
            </tr>
            <tr>
              <td>Voltage Drop in kV</td>
              <td>49.4 kV</td>
              <td>47.85 kV</td>
              <td>1.15 kV</td>
              <td>2.3%</td>
            </tr>
            <tr>
              <td>Active power losses in %</td>
              <td>12.4%</td>
              <td>11.22%</td>
              <td>1.18%</td>
              <td>9%</td>
            </tr>
            <tr>
              <td>Active power losses in MW</td>
              <td>40 MW</td>
              <td>37 MW</td>
              <td>3 MW</td>
              <td>7%</td>
            </tr>
            <tr>
              <td>Average deviation in %</td>
              <td>
              </td>
              <td>
              </td>
              <td>
              </td>
              <td>5%</td>
            </tr>
          </tbody>
        </table>
      </table-wrap>
    </sec>
    <sec id="sec5">
      <title>5. Discussions</title>
      <p>Energy losses are of increasing concern to producers, transmission system operators, and distributors of electrical energy. Evaluating these energy losses in a high-voltage AC power system allows for the optimization of network performance, increased transmission efficiency, and reduced operating costs. Several equations exist for modeling these losses based on the characteristics of the equipment used in the installation. To obtain the results of various simulations, energy loss models based on voltage drop, derived from Maxwell’s equations, were developed and used for the analytical and numerical modeling of the problem addressed in this article.</p>
      <p>To this end, the following results were obtained:</p>
      <p><xref ref-type="fig" rid="fig4">Figure 4</xref>represents the Simulink model of power transmission on the HV line that is the subject of our study. This figure, developed in Matlab, not only allows us to quantify the energy state of the HV line as a function of its characteristics, but also gives rise to <xref ref-type="fig" rid="fig5">Figures 5-10</xref>.</p>
      <p><xref ref-type="fig" rid="fig5">Figure 5</xref> shows the voltage at the input of the high-voltage line; as we can see, this voltage is approximately 254 kV. <xref ref-type="fig" rid="fig6">Figure 6</xref> shows the current drawn by the load at the end of the high-voltage line, which is 894.1 A. <xref ref-type="fig" rid="fig7">Figure 7(a)</xref> visualizes the profile of the active power injected at the input of the high-voltage line, which is 320 MW, and <xref ref-type="fig" rid="fig7">Figure 7(b)</xref> shows the reactive power at the input of the high-voltage line, quantified at 165.3 MVAr. However, <xref ref-type="fig" rid="fig8">Figure 8</xref> visualizes the voltage at the output of the high-voltage line; as we can see, this voltage is estimated at 205.5 kV. <xref ref-type="fig" rid="fig9">Figure 9</xref> shows the current across the load at the end of the high-voltage line, which is 894.1 A. <xref ref-type="fig" rid="fig10">Figure 10(a)</xref> gives the active power profile at the output of the HV line which is 279 MW and <xref ref-type="fig" rid="fig10">Figure 10(b)</xref> gives the reactive power at the output of the HV line estimated at 79.67 MVAr.</p>
      <p>We can confirm that the results in <xref ref-type="fig" rid="fig5">Figures 5-10</xref> corroborate the power transmission readings provided by SNEL/DG/PKB, as shown in <bold>Table 1</bold> above. This table indicates the discrepancies recorded between the power transmission readings provided by SNEL/DG/PKB and the Simulink model of power transmission on the HV line under study. We observe an average discrepancy of approximately 0.03, or 3%. This low root mean square error (RMSE) allows us to confirm that our results are valid.</p>
      <p><xref ref-type="fig" rid="fig11">Figure 11</xref>, developed using Matlab, presents the Simulink model of the voltage drop on the high-voltage line, which has two ends (A, the line input, and B, the output). This model yields the results shown in <xref ref-type="fig" rid="fig12">Figures 12-13</xref>. These figures show the voltage drops of 19.3% and 49.4 kV at the end of the line, respectively. <xref ref-type="fig" rid="fig15">Figure 15</xref>, also developed using Matlab, presents the Simulink model of the active power losses, expressed as a percentage and in MW, dissipated along the high-voltage line. The simulation of this model produces the results shown in <xref ref-type="fig" rid="fig15">Figures 15(a)-(b)</xref>. These figures show that the active power losses along the line are 12.4% (see <xref ref-type="fig" rid="fig14">Figure 14(a)</xref>). This represents 40 MW (see <xref ref-type="fig" rid="fig15">Figure 15(b)</xref>). This loss rate exceeds the standard value of 5% recommended by IEC standards.</p>
      <p>Thus, we can confirm that the results of <xref ref-type="fig" rid="fig12">Figures 12-13</xref> and <xref ref-type="fig" rid="fig15">Figure 15</xref> are close to those of <xref ref-type="fig" rid="fig16">Figures 16-20</xref> obtained based on models 57 and 64, as can be seen in the comparison shown in <bold>Table 2</bold> above. This table indicates the differences recorded between the results of <xref ref-type="fig" rid="fig12">Figures 12-13</xref>, <xref ref-type="fig" rid="fig15">Figure 15</xref> and those of <xref ref-type="fig" rid="fig17">Figures 17-18</xref>, <xref ref-type="fig" rid="fig20">Figure 20</xref>. We observe an average difference of approximately 0.05, or 5%, which is within the normal range (RMSE). We can therefore confirm that our models are validated.</p>
    </sec>
    <sec id="sec6">
      <title>6. Conclusions</title>
      <p>The electrical energy from large generating stations travels through the transmission network and then the distribution network before reaching consumers. This process results in energy losses, classified as transmission and distribution losses. This is the subject of our study. In any electrical system, energy losses are unavoidable, representing a necessary cost for transporting electricity from the point of production to the point of consumption.</p>
      <p>To assess these energy losses, several classic methods make it possible to carry out an analysis of the energy losses produced in the electrical network; however, these classic methods do not take into account non-technical losses, have time requirements, and are cumbersome and complex in terms of the laborious calculations of numerous parameters.</p>
      <p>Therefore, this article aimed to propose a rapid and reliable method for evaluating energy losses in high-voltage AC (HVAC) power lines, taking into account non-technical losses. The case study focused on the 220 kV Inga-Kinshasa HVAC line in the Democratic Republic of Congo, which faces numerous operational challenges. Implementing this method requires measuring the voltage drop at both ends of the HV line, which is easier and less expensive, and calculating the power factor.</p>
      <p>The results presented in this article highlight the direct corroboration between the power transit readings provided by SNEL/DG/PKB [<xref ref-type="bibr" rid="B45">45</xref>] and the Simulink model of power transit on the HTAC line which is the subject of our study, with an average difference of around 0.03 or 3%, a low mean squared error according to the standard (RMSE).</p>
      <p>Thus, we can confirm that the simulation results of voltage drop and energy losses in the HV line obtained via the Matlab environment bring the models proposed via equations 57 and 64 closer together, with an average difference of around 0.05 or 5%, which is within the margin of the standard (RMSE).</p>
      <p>These results can be used for practical applications in the engineering and design of high-voltage transmission networks. They can also guide policymakers.</p>
      <p>Analysis of the results of the applications processed shows that the proposed method is very useful and constitutes an adequate model for evaluating these energy losses in HTAC power lines.</p>
      <p>The prospects arising from this study of energy loss analysis and modelling are vast, ranging from the optimization of transformers and motors to the design of absorbent materials, including improving the efficiency of electrical networks and analyzing electromagnetic compatibility, to reduce energy waste in numerous technological and industrial sectors. In addition, the study assesses the robustness of the proposed models<italic>.</italic></p>
      <p>A compact validation step at several operating points (e.g., different load levels or time windows) and a consistent definition of the error measurement (e.g., RMSE/MAE with units and normalization) so that agreement is not demonstrated on a single representative case, sensitivity control for parameters that most affect losses (especially conductor resistance as a function of temperature and assumed power factor) and estimation of losses change in case of plausible parameter variation to support robustness claims, will be the subject of future studies.</p>
    </sec>
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