<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jmp
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of Modern Physics
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2153-1196
   </issn>
   <issn publication-format="print">
    2153-120X
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jmp.2025.169063
   </article-id>
   <article-id pub-id-type="publisher-id">
    jmp-145511
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    General Relativity Explains Why Ball Lightning Does Not Fall
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Charles H. McGruder
      </surname>
      <given-names>
       III
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aDepartment of Physics and Astronomy, Western Kentucky University, Bowling Green, KY, USA
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     10
    </day> 
    <month>
     09
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    16
   </volume> 
   <issue>
    09
   </issue>
   <fpage>
    1222
   </fpage>
   <lpage>
    1231
   </lpage>
   <history>
    <date date-type="received">
     <day>
      1,
     </day>
     <month>
      August
     </month>
     <year>
      2025
     </year>
    </date>
    <date date-type="published">
     <day>
      8,
     </day>
     <month>
      August
     </month>
     <year>
      2025
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      8,
     </day>
     <month>
      September
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    We suggest ball lightning does not fall because of the gravitational force experienced by ball lightning. We show that this force is predominantly determined by the electrons in ball lightning that came chiefly from the lightning strike that caused the phenomenon. General Relativity predicts that these electrons cause ball lightning to experience gravitational repulsion.
   </abstract>
   <kwd-group> 
    <kwd>
     Ball Lightning
    </kwd> 
    <kwd>
      General Relativity
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>Ball lightning is spherical in shape and ranges in size from a centimeter to 10 meters. It is luminous and exhibits various colors such as white, yellow, red, or blue. It is associated with lightning strikes. It is a transient phenomenon that usually exists for several seconds. However, it can occasionally persist up to 10 minutes. Finally, we note it is an extremely rare phenomenon <xref ref-type="bibr" rid="scirp.145511-1">
     [1]
    </xref>-<xref ref-type="bibr" rid="scirp.145511-3">
     [3]
    </xref>. <xref ref-type="bibr" rid="scirp.145511-4">
     [4]
    </xref> cites only 5 - 15 reliable reports of ball lightning events per year.</p>
   <p>Although ball lightning has been known for many centuries, it is one of the most mysterious atmospheric phenomena. There are many theories of ball lightning (50 - 100), but there is no consensus on which of these theories is correct if any of them is correct.</p>
   <p>Theoretical understanding of ball lightning employing well known physics is so poor that particles have been invoked to explain ball lightning that have never been observed in laboratories such as magnetic monopoles <xref ref-type="bibr" rid="scirp.145511-5">
     [5]
    </xref> <xref ref-type="bibr" rid="scirp.145511-6">
     [6]
    </xref>, black holes <xref ref-type="bibr" rid="scirp.145511-7">
     [7]
    </xref> <xref ref-type="bibr" rid="scirp.145511-8">
     [8]
    </xref>, axions <xref ref-type="bibr" rid="scirp.145511-9">
     [9]
    </xref> and dark matter <xref ref-type="bibr" rid="scirp.145511-10">
     [10]
    </xref>. In addition, exotic proposals such as nuclear reactions <xref ref-type="bibr" rid="scirp.145511-11">
     [11]
    </xref> and antimatter <xref ref-type="bibr" rid="scirp.145511-12">
     [12]
    </xref> have been made. Here we do not present a model of the structure or formation of ball lightning; instead, we discuss only why it does not fall as normal physical bodies do.</p>
  </sec><sec id="s2">
   <title>
    <xref ref-type="bibr" rid="scirp.145511-"></xref>2. Theory</title>
   <p>The motion of ball lightning is highly enigmatic because it appears to defy gravity, that is, it does not fall, rather its motion is horizontal. <xref ref-type="bibr" rid="scirp.145511-13">
     [13]
    </xref> suggests this lack of vertical motion is caused by the earth’s electric field, <xref ref-type="bibr" rid="scirp.145511-14">
     [14]
    </xref> by an electric discharge that continuously varies on a microsecond time scale, <xref ref-type="bibr" rid="scirp.145511-15">
     [15]
    </xref> through trapped electromagnetic waves inside the plasma that create outward radiation pressure sufficient to counteract gravity, <xref ref-type="bibr" rid="scirp.145511-16">
     [16]
    </xref> <xref ref-type="bibr" rid="scirp.145511-17">
     [17]
    </xref> maintain a plasma contained within a force-free magnetic field, <xref ref-type="bibr" rid="scirp.145511-18">
     [18]
    </xref> electrostatic attraction between similarly charged clusters that supports ball lightning preventing it from falling, <xref ref-type="bibr" rid="scirp.145511-19">
     [19]
    </xref> a plasma-microwave structure that prevents falling, <xref ref-type="bibr" rid="scirp.145511-20">
     [20]
    </xref> a microwave-trapped plasma cavity, <xref ref-type="bibr" rid="scirp.145511-21">
     [21]
    </xref> a self-contained spherical current/radiation circuit, where energy is stored outside the ionized core that creates electromagnetic-balancing forces that allow the structure to float and <xref ref-type="bibr" rid="scirp.145511-22">
     [22]
    </xref> a phase-locked electromagnetic wave packets within plasma, which lead to stable motion without falling.</p>
   <p>In contrast to all the above theories, we employ General Relativity, which is Einstein’s theory of gravitation <xref ref-type="bibr" rid="scirp.145511-23">
     [23]
    </xref>, to explain ball lightning’s lack of falling motion. This theory predicts that not only mass but also energy gravitates. Specifically, we employ the circumstance that the electrostatic field energy associated with charged particles gravitates repulsively <xref ref-type="bibr" rid="scirp.145511-24">
     [24]
    </xref> to explain the observational fact that ball lightning does not fall.</p>
   <p>We base our theory on just two fundamental assumptions:</p>
   <p>1) Ball lightning is charged as <xref ref-type="bibr" rid="scirp.145511-13">
     [13]
    </xref> <xref ref-type="bibr" rid="scirp.145511-14">
     [14]
    </xref> <xref ref-type="bibr" rid="scirp.145511-18">
     [18]
    </xref> <xref ref-type="bibr" rid="scirp.145511-25">
     [25]
    </xref>-<xref ref-type="bibr" rid="scirp.145511-27">
     [27]
    </xref> assume.</p>
   <p>2) Ball lightning is a physical body, meaning that it obeys the laws of physics. Therefore, it is not a hallucination or caused by sensual perception as some maintain <xref ref-type="bibr" rid="scirp.145511-28">
     [28]
    </xref> <xref ref-type="bibr" rid="scirp.145511-29">
     [29]
    </xref>. Observations show that ball lightning moves as a whole and we therefore assume that it responds to gravitational forces as a whole. Consequently, if only Newtonian gravity were present and no other forces, ball lightning would fall.</p>
   <p>Instead of Newton’s theory of gravitation we employ Einstein’s theory of gravitation, which is more commonly referred to as General Relativity, to explain why ball lightning does not fall as normal physical bodies do. According to Einstein, energy gravitates, therefore, the electrostatic field energy associated with charged particles must gravitate. It gravitates repulsively <xref ref-type="bibr" rid="scirp.145511-24">
     [24]
    </xref>.</p>
   <p>The basic equation we employ in our analysis of the motion of ball lightning is <xref ref-type="bibr" rid="scirp.145511-30">
     [30]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         m 
       </mi> 
      </mfrac> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         e 
       </mi> 
      </msub> 
     </mrow> 
    </math>(1)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the contribution of the electrostatic field energy to the gravitational acceleration of ball lightning. m is the mass of the matter in ball lightning in units of electron mass. n is the number of electrons in the ball lightning that predominantly originated in the lightning strike that caused the phenomenon. Technically, n should include charged particles in the atoms or ions that may be a part of ball lightning, but we have shown <xref ref-type="bibr" rid="scirp.145511-30">
     [30]
    </xref> that their effect is extremely small, because their masses are so much higher than those of electrons. So we do not include them in n.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         e 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the contribution of the electrostatic field energy of a single electron to the gravitational acceleration of ball lightning. The effect of electrostatic field energy of an electron of mass, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         m 
       </mi> 
       <mi>
         e 
       </mi> 
      </msub> 
     </mrow> 
    </math>, on the surface of the earth, on the gravitational acceleration is <xref ref-type="bibr" rid="scirp.145511-24">
     [24]
    </xref></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         e 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           e 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           m 
         </mi> 
         <mi>
           e 
         </mi> 
        </msub> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          r 
        </mi> 
       </mrow> 
      </mfrac> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         N 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        4.4 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          22 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         N 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           g 
         </mi> 
         <mi>
           N 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           n 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(2)</p>
   <p>which is the classical electron radius divided by the radius of the earth, r, multiplied by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         N 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          G 
        </mi> 
        <mi>
          M 
        </mi> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>, the Newtonian acceleration of gravity. c is the speed of light and e the charge of an electron. For convenience we introduce: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <mn>
          4.4 
        </mn> 
        <mo>
          × 
        </mo> 
        <msup> 
         <mrow> 
          <mn>
            10 
          </mn> 
         </mrow> 
         <mrow> 
          <mo>
            − 
          </mo> 
          <mn>
            22 
          </mn> 
         </mrow> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>. Below we will give a physical interpretation of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>Combining Equations (1) and (2) leads to:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mi>
          m 
        </mi> 
        <msub> 
         <mi>
           n 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         N 
       </mi> 
      </msub> 
     </mrow> 
    </math>(3)</p>
   <p>It is most important to understand the following. Because 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         N 
       </mi> 
      </msub> 
      <mo>
        &lt; 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>, that is, physical bodies fall downward, according to the above equation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math>, the gravitational acceleration of the electrostatic field energy, is upward. Thus, the energy of the electrostatic field gravitates repulsively <xref ref-type="bibr" rid="scirp.145511-24">
     [24]
    </xref>.</p>
   <p>In general, n and m of ball lightning on the right side of Equation (1) are not known. However, we do know the value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math> on the left side of Equation (1). Since ball lightning does not fall it means that:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mi>
         N 
       </mi> 
      </msub> 
     </mrow> 
    </math>(4)</p>
   <p>This equation means that the upward gravitational acceleration caused by the electrostatic field energy of the electrons, which came chiefly from the lightning bolt that created the ball lightning, balances the normal Newtonian gravitational acceleration.</p>
   <p>Combining these last two equations yields:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         m 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2.3 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          21 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>(5)</p>
   <p>So, even though we generally do not know the values of n and m, we do know the ratio of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         m 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>. We now turn to employing the above equation to explore the relationship between the values of n and m under various circumstances.</p>
   <sec id="s2_1">
    <title>
     <xref ref-type="bibr" rid="scirp.145511-"></xref>2.1. Electron Body</title>
    <p>A number of theories propose that electrons play a major role in the formation and structure of ball lightning: <xref ref-type="bibr" rid="scirp.145511-18">
      [18]
     </xref> <xref ref-type="bibr" rid="scirp.145511-31">
      [31]
     </xref>-<xref ref-type="bibr" rid="scirp.145511-37">
      [37]
     </xref>.</p>
    <p>In this section we consider the extreme case that ball lightning contains only electrons. m in the above equation is expressed in units of electron mass. It follows that for an electron body 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         m 
       </mi> 
       <mo>
         = 
       </mo> 
       <mi>
         n 
       </mi> 
      </mrow> 
     </math>. We refer to the value of n in this case of an electron body as 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          n 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>. The above equation yields 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          n 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2.3 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> electrons in an electron body that exactly balances gravity. If n is greater than 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          n 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>, then the electron body will accelerate upward. If n is less than 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          n 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>, then it will accelerate downward.</p>
    <p>Lightning bolts are generally in the range of 5 to 350 coulombs, which corresponds to 3 × 10<sup>19</sup> to 2 × 10<sup>21</sup> electrons. Thus, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          n 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> is approximately in the highest part of the range of normal lightning strikes. Consequently, if ball lightning is a pure electron body, it would mean that its occurrence is rare, which is indeed the case.</p>
    <p>According to General Relativity the gravitational acceleration, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
      </mrow> 
     </math>, that ball lightning experiences is the sum of Newtonian acceleration plus the contribution to the acceleration due to the electrostatic field energy of its charges.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          N 
        </mi> 
       </msub> 
       <mo>
         + 
       </mo> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          E 
        </mi> 
       </msub> 
      </mrow> 
     </math>(6)</p>
    <p>Assuming that ball lightning consists only of n electrons, <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref> shows the gravitational acceleration of ball lightning in units of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mo>
          | 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mi>
            N 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          | 
        </mo> 
       </mrow> 
      </mrow> 
     </math> as a function of Log10(n). 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> means that the ball lightning is neither rising nor falling, which corresponds to observations. 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
       <mo>
         &gt; 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> means it is rising and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mi>
          B 
        </mi> 
       </msub> 
       <mo>
         &lt; 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> falling as normal bodies do.</p>
    <fig id="fig1" position="float">
     <label>Figure 1</label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.145511-"></xref>Figure 1. Acceleration vs. number of electrons.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505784-rId67.jpeg?20250911112516" />
    </fig>
   </sec>
   <sec id="s2_2">
    <title>
     <xref ref-type="bibr" rid="scirp.145511-"></xref>2.2. Electrons with Uncharged Matter</title>
    <p>In this section, we assume that ball lightning contains electrons, chiefly from the lightning strike that created it, and also uncharged matter. The uncharged matter could be from the atmosphere and/or from soil as <xref ref-type="bibr" rid="scirp.145511-38">
      [38]
     </xref>-<xref ref-type="bibr" rid="scirp.145511-45">
      [45]
     </xref> maintain.</p>
    <p>We now investigate the relationship between the number of electrons and the total mass of uncharged matter contained in ball lightning. These two quantities must satisfy Equation (5) because observations show that ball lightning does not fall. m is the total mass of ball lightning, so it must include the mass of uncharged matter, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math>, as well as the mass of n electrons. Equation (5) becomes:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            n 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           μ 
         </mi> 
         <mo>
           + 
         </mo> 
         <mi>
           n 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          n 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>(7)</p>
    <p>n in the numerator is the number of electrons, and n in the denominator like 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math> is in units of electron mass.</p>
    <p>To obtain the number of electrons as a function of the mass of the uncharged component, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math>, we must solve the above equation for n. We choose to express 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math> in grams so we must divide it by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          m 
        </mi> 
        <mi>
          e 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         9.1 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           28 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math>, the mass of the electron.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            n 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           + 
         </mo> 
         <msqrt> 
          <mrow> 
           <msubsup> 
            <mi>
              n 
            </mi> 
            <mn>
              0 
            </mn> 
            <mn>
              2 
            </mn> 
           </msubsup> 
           <mo>
             + 
           </mo> 
           <mfrac> 
            <mrow> 
             <mn>
               4 
             </mn> 
             <msub> 
              <mi>
                n 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mi>
               μ 
             </mi> 
            </mrow> 
            <mrow> 
             <msub> 
              <mi>
                m 
              </mi> 
              <mi>
                e 
              </mi> 
             </msub> 
            </mrow> 
           </mfrac> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mn>
          2 
        </mn> 
       </mfrac> 
      </mrow> 
     </math>(8)</p>
    <p>
     <xref ref-type="fig" rid="fig2">
      Figure 2
     </xref> shows the relationship between 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        n 
      </mi> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math>. Both quantities are expressed as the logarithm to the base 10. In grams the range of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math> in the figure is: 10<sup>−</sup><sup>9</sup> to 10<sup>2</sup>. For a given mass, n is the number of electrons ball lightning must have in order for it not to fall or rise, as observations show. If the actual number of electrons is greater than n, then the ball lightning will rise, if less than n, it will fall.</p>
    <fig id="fig2" position="float">
     <label>Figure 2</label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.145511-"></xref>Figure 2. Number of electrons vs. mass.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505784-rId88.jpeg?20250911112516" />
    </fig>
   </sec>
  </sec><sec id="s3">
   <title>
    <xref ref-type="bibr" rid="scirp.145511-"></xref>3. Discussion</title>
   <p>Equation (8) leads to the conclusion that the minimum number of electrons required to achieve the equality of downward Newtonian gravitational force and upward gravitational force of the electrostatic field energy is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2.3 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          21 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>. 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> is the value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       n 
     </mi> 
    </math>, when 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        μ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>. That is it corresponds to a pure electron body. But, out of all the models proposed so far that suggest ball lightning is charged, the model with the highest estimate of the value of the charge is <xref ref-type="bibr" rid="scirp.145511-18">
     [18]
    </xref> with 0.1 C that is 6.24 × 10<sup>17</sup> electrons. 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> is orders of magnitude larger than this value, which suggests that none of these models is correct in their current form.</p>
   <p>Does 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> fit estimates of the energy in ball lightning? A lightning bolt containing 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> electrons has an estimated energy of 3.68 × 10<sup>10</sup> joules. This energy fits well with the estimated energy density, 10<sup>10</sup> J/m<sup>3</sup> of ball lightning <xref ref-type="bibr" rid="scirp.145511-46">
     [46]
    </xref>.</p>
   <p>How frequent are lightning strikes with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        n 
      </mi> 
      <mo>
        ≥ 
      </mo> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>? <xref ref-type="bibr" rid="scirp.145511-47">
     [47]
    </xref> estimate that 0.1% of lightning strikes transport a charge &gt; 350 C. 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> corresponds to 368.5 C so they are roughly 0.1% of the total number of lightning strikes. They are therefore rare, about 1 in 1000 strikes. Nevertheless the total number of such strikes is appreciable. There are worldwide about 100 lightning strikes/s that is 3.15 billion/year. So every 10 s or about 3 × 10<sup>6</sup> per year is an estimate of the frequency of superbolts with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        n 
      </mi> 
      <mo>
        ≥ 
      </mo> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>However, only a small faction of these strikes, which may lead to ball lightning, are reported. This is because of geographical constraints: 1) Only a small fraction of the earth’s surface at any instance is visible to humans. 2) reporting is more likely to take place in developed countries. <xref ref-type="bibr" rid="scirp.145511-4">
     [4]
    </xref> cites 5 - 15 reliable reports of ball lightning events per year. Considering these constraints we suggest this number is explained by the frequency of superbolts with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        n 
      </mi> 
      <mo>
        ≥ 
      </mo> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>Experiments have been performed to create ball lightning. <xref ref-type="bibr" rid="scirp.145511-38">
     [38]
    </xref> simulated a lightning strike in the lab by applying a 10 - 20 kV direct current (DC) discharge to a 3-mm layer of soil, transferring up to 3.4 coulombs of charge. <xref ref-type="bibr" rid="scirp.145511-48">
     [48]
    </xref> reproduced ball-lightning-like “plasma fireballs” using a combination of air-gap electrical discharge and microwave radiation. <xref ref-type="bibr" rid="scirp.145511-49">
     [49]
    </xref>-<xref ref-type="bibr" rid="scirp.145511-51">
     [51]
    </xref> produced glowing plasma formations generated by discharges with polymer and metal materials. <xref ref-type="bibr" rid="scirp.145511-52">
     [52]
    </xref> created microwave-sustained plasma fireballs under atmospheric conditions, which exhibited some features of natural ball lightning. None of these experiments created ball lightning. However, they all possessed some features of ball lightning.</p>
  </sec><sec id="s4">
   <title>
    <xref ref-type="bibr" rid="scirp.145511-"></xref>4. Conclusions</title>
   <p>Observations show that ball lightning does not fall. It therefore appears to defy gravity. We invoke Einstein’s theory of gravitation instead of Newton’s theory of gravitation to explain these observations. Our theory rests on the circumstance of Einstein’s theory that the electrostatic field energy associated with charged particles (in our case electrons) gravitates repulsively.</p>
   <p>We suggest electrons chiefly from the lightning strike that caused the formation of the ball lightning remain in the ball lightning. If the number of electrons is greater than 2.3 × 10<sup>21</sup> then it is possible for the upward gravitational acceleration of the electrons to equal the downward gravitational force of Newtonian gravitational theory. The exact number of electrons required to achieve this equality depends upon the mass of uncharged matter in the ball lightning as <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref> shows.</p>
   <p>In addition to explaining why ball lightning does not fall, our theory also explains why the reporting of ball lightning sightings is so rare. This circumstance is due to the rarity of superbolts coupled with geographical and reporting constraints. We have therefore explained two major aspects of the phenomenon of ball lightning.</p>
   <p>We conclude that ball lightning does not defy gravity. It indeed obeys the laws of gravitation, however, not Newton’s law of gravitation rather Einstein’s theory of gravitation.</p>
  </sec><sec id="s5">
   <title>Acknowledgements</title>
   <p>Many thanks to Dr. and Mrs. William McCormick, whose generous support has provided the prerequisite financial basis and most importantly the necessary time to complete this project.</p>
  </sec>
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