<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jhepgc
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of High Energy Physics, Gravitation and Cosmology
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2380-4327
   </issn>
   <issn publication-format="print">
    2380-4335
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jhepgc.2025.113073
   </article-id>
   <article-id pub-id-type="publisher-id">
    jhepgc-144431
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Equivalence between Direct Mass and NFW-Total Mass Formula in MW and M31 Galaxies
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Manuel
      </surname>
      <given-names>
       Abarca
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aIndependent Researcher, Granada, Spain
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     20
    </day> 
    <month>
     05
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    11
   </volume> 
   <issue>
    03
   </issue>
   <fpage>
    1152
   </fpage>
   <lpage>
    1179
   </lpage>
   <history>
    <date date-type="received">
     <day>
      28,
     </day>
     <month>
      March
     </month>
     <year>
      2025
     </year>
    </date>
    <date date-type="published">
     <day>
      27,
     </day>
     <month>
      March
     </month>
     <year>
      2025
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      27,
     </day>
     <month>
      July
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    In the framework of Dark Matter by Quantum Gravitation (DMbQG) theory hereafter, the Direct mass gives the total mass into the halo region, growing with the square root of radius. This formula has only one specific parameter for each galaxy. The NFW profile is a universal method that gives the DM mass function depending on radius at the bulge, the disk and the galactic halo. This function is defined by two parameters. The DMbQG theory claims that DM is generated by the own gravitational field and consequently the DM halo is unbounded. In the paper [1] (Abarca, M. 2024) was proved that it is the Dark energy the mechanism able to counterbalance the DM but at cluster scale. As the direct mass is linked to the total mass (baryonic plus DM), in the paper has been developed a method to integrate the baryonic matter into the NFW DM function in order to be able to compare both functions connected to the total mass. Thanks this method has been possible to define the R
    <sub>200-TOTAL</sub> and the M
    <sub>200-TOTAL</sub> both referred to a sphere whose total mass has a mean density equal to 200 times the critic density of the Universe. The main achievement of this paper is to demonstrate that the Direct mass function and the NFW-total mass function are equivalents into the halo region of MW and the M31. The equivalence of the two formulas for masses is based on four tests, all of them tested successfully for the both galaxies. Test I. Comparison the R
    <sub>200-</sub>
    <sub>TOTAL</sub> and the M
    <sub>200-TOTAL</sub> calculated by the two different formulas, for MW and M31. Both the Direct mass and the NFW mass formula gives similar values to R
    <sub>200-TOTAL</sub> and the M
    <sub>200-TOTAL</sub>, compatibles with the equality if it is considered the error measures. Test II. Using the M
    <sub>200-TOTAL</sub>, given by the NFW method, is calculated the parameter 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
        a
       </mi> 
       <mn>
        2
       </mn> 
      </msup> 
     </mrow> 
    </math> which is compared with the one got in the framework of DMbQG theory. This process is made in MW and M31 and the comparison is compatible with the equality if it is considered the error measures. Test III. Is similar to test II but using the R
    <sub>200-TOTAL</sub> and the M
    <sub>200-</sub>
    <sub>TOTAL</sub> and the result is successful as well. Test IV. The direct mass function and the NFW-total mass function are compared into the halo region up to R
    <sub>200-TOTAL</sub>. It is proved that its relative differences are below 10% into a wide region of the galactic halo up to R
    <sub>200-TOTAL</sub> and beyond. Although the thesis of this paper is for any galaxies, the calculus has been made with MW and M31, because they are the best well studied galaxies and his data have the maximum of accuracy. The prove reach in this paper is valuable because the NFW is a trustable profile for DM, tested in thousands of galaxies, and although the DMbQG theory claims that DM has an unbounded halo region, it gives similar results in the halo region common for both theories i.e. up to the virial radius. 
   </abstract>
   <kwd-group> 
    <kwd>
     Dark Matter
    </kwd> 
    <kwd>
      Dark Matter by Quantum Gravitation
    </kwd> 
    <kwd>
      NFW DM Density Profile
    </kwd> 
    <kwd>
      Milky Way
    </kwd> 
    <kwd>
      M31 Galaxy
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>Since 2014 up to 2024, I have published several papers studying DM in galactic halos, especially in M31 and Milky Way although also I have published some papers studying other galaxies and clusters.</p>
   <p>This paper is focused on the equivalence of NFW mass formula and the Direct mass formula, which is the formula for the total mass in the halo region developed in the framework of DMbQG. So the reader has to have at least a general knowledge about this original theory to read this paper. The paper <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca), is the best work about it, so the reader may consult such paper in order to understand the DMbQG theory.</p>
   <p>The Chapter 3 is dedicated to introduced the Direct mass and some derived formulas, and the Chapter 4 is dedicated to introduced the NFW method and his extension to the total mass (baryonic plus DM). As the reader knows, the NFW is a density profile for DM only, so in this work has been necessary to integrate the baryonic matter into the NFW profile because the Direct mass function gives the total mass into the halo region.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.144431-"></xref>As reader knows, M31 is the twin galaxy of Milky Way in the Local Group of galaxies. According to <xref ref-type="bibr" rid="scirp.144431-2">
     [2]
    </xref> (Sofue, Y. 2015), its baryonic masses are 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mtext>
          M 
        </mtext> 
        <mn>
          31 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1.6 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          11 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mtext>
          MILKY WAY 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1.4 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          11 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>The DM by Quantum Gravitation, DMbQG hereafter, theory was introduced in <xref ref-type="bibr" rid="scirp.144431-3">
     [3]
    </xref> (Abarca, M. 2014). Dark matter model by quantum vacuum). It considers that DM is generated by the own gravitational field according to an unknown quantum gravitational phenomenon.</p>
   <p>In order to study purely the phenomenon it is needed to consider a radius dominion where it is supposed that baryonic matter is negligible. i.e. radius bigger than 30 kpc for MW and 40 kpc for M31, according to some calculus made about it.</p>
   <p>This hypothesis has two main consequences: the first one is that the law of dark matter generation, in the halo region, has to be the same for all the galaxies. In the paper <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca, M. 2024) is developed the theory using the rotation curve of M31 published by <xref ref-type="bibr" rid="scirp.144431-2">
     [2]
    </xref> (Sofue, Y. 2015) and the rotation curve of MW by <xref ref-type="bibr" rid="scirp.144431-4">
     [4]
    </xref> (Sofue, Y. 2020).</p>
   <p>The second consequence is that the haloes are unlimited so the total dark matter goes up without limit. In the paper <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca, M. 2024) is solved the divergence of the total mass, thanks to the Dark energy.</p>
   <p>As I have mentioned before, this theory has been developed assuming the hypothesis that DM is a quantum gravitational effect. However, it is possible to remain into the Newtonian framework to develop the theory. In my opinion there are two factors to manage the DM conundrum with a quite simple theory.</p>
   <p>The first one, that it is developed into the halo region, where baryonic matter is negligible. The second one, that the mechanics movements of celestial bodies are very slow regarding velocity of light, which is supposed to be the speed of gravitational bosons.</p>
   <p>It is known that community of physics is researching a quantum gravitation theory since many years ago, but it does not exist yet, however I think that my works in this area support strongly that DM is a quantum gravitation phenomenon.</p>
   <p>Use a simpler theory instead the general theory is a typical procedure in physics. For example the Kirchhoff’s laws are the consequence of Maxwell theory for direct current and remain valid for alternating current, introducing complex impedances, on condition that signals must have low frequencies.</p>
   <p>So these reasons support the possibility to study a complex phenomenon as it is the DM with a theory mathematically simple in the framework of Newtonian mechanics.</p>
   <p>In the paper <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca, M. 2024) in the framework of DMbQG theory it is calculated by the Direct mass with unbounded dominion for radius the dynamical mass of the Local Group, that according to <xref ref-type="bibr" rid="scirp.144431-5">
     [5]
    </xref> (Azadeh Fattahi, Julio F. Navarro). 2020 is estimated to be 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        5 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          12 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math>. The result given by the direct mass considering the four main galaxies of the L. G. match perfectly with such estimation, whereas using the virial masses associated to MW, M31, M33 and LMC calculated by NFW the total amount of masses is scarcely 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        3 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          12 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math>. This calculus has been made without considering the dark energy because according some calculus made, into the L. G. the D. E. is important for radius bigger than 1 Mpc, so for the system MW and M31 the DE may be neglected.</p>
   <p>The DMbQG theory has been developed successfully in cluster of galaxies in the paper <xref ref-type="bibr" rid="scirp.144431-6">
     [6]
    </xref> (Abarca, M. 2024), and there have been found a set of remarkable theoretical results tested in the L. G. and the Virgo cluster, that is the nearest big cluster and consequently the cluster where measures reach the maximum of accuracy. Namely some theoretical findings match perfectly with the results published by <xref ref-type="bibr" rid="scirp.144431-7">
     [7]
    </xref> (Kashibadze, Karachentsev, 2020) and by <xref ref-type="bibr" rid="scirp.144431-8">
     [8]
    </xref> (Karachentsev, I. D., Tully, R. B 2014).</p>
   <p>Despite the fact that the DMbQG theory has been tested successfully in galaxies and clusters, the prove reach in this paper is valuable because the NFW is a trustable profile for DM, tested in thousands of galaxies, and although the DMbQG theory claims that DM has an unbounded halo region, it gives similar results in the halo region common for both theories i.e. up to the virial radius.</p>
  </sec><sec id="s2">
   <title>2. Virial Mass and Virial Radius in Galaxies and Clusters</title>
   <p>In galaxies and clusters, it is a good estimation about virial radius and virial mass to consider R<sub>vir</sub> = R<sub>200</sub> and M<sub>vir</sub> = M<sub>200</sub>. Where R<sub>200</sub> is the radius of a sphere whose mean density is 200 times bigger than the critic density of Universe</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mi>
         C 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          3 
        </mn> 
        <msup> 
         <mi>
           H 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          8 
        </mn> 
        <mi>
          π 
        </mi> 
        <mi>
          G 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        9.2055 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          27 
        </mn> 
       </mrow> 
      </msup> 
      <mtext>
          
      </mtext> 
      <mtext>
        kg 
      </mtext> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mtext>
         m 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          3 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> (2.1)</p>
   <p>(In this work it will be considered H = 70 km/s/Mpc)</p>
   <p>and M<sub>200</sub> is the total mass enclosed by the radius R<sub>200</sub>.</p>
   <p>Considering the spherical volume formula, it is right to get the following relation between both concepts.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         R 
       </mi> 
       <mrow> 
        <mn>
          200 
        </mn> 
       </mrow> 
       <mn>
         3 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          G 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mi>
           M 
         </mi> 
         <mrow> 
          <mn>
            200 
          </mn> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          100 
        </mn> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mi>
           H 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (2.2)</p>
   <p>or</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mn>
          200 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          100 
        </mn> 
        <msup> 
         <mi>
           H 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msubsup> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <mn>
            200 
          </mn> 
         </mrow> 
         <mn>
           3 
         </mn> 
        </msubsup> 
       </mrow> 
       <mi>
         G 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (2.3)</p>
   <p>or</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           M 
         </mi> 
         <mrow> 
          <mn>
            200 
          </mn> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <msubsup> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <mn>
            200 
          </mn> 
         </mrow> 
         <mn>
           3 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          100 
        </mn> 
        <msup> 
         <mi>
           H 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         G 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (2.4)</p>
   <p>These parameters are common in cluster of galaxies as well. In the Chapter 2 of paper <xref ref-type="bibr" rid="scirp.144431-6">
     [6]
    </xref> (Abarca, M. 2024) is checked the above relation between R<sub>200</sub> and M<sub>200</sub> on a set of clusters.</p>
   <p>In the Chapter 4 will be introduced the NFW density profile and the NFW mass function, both linked to DM, so in the framework of NFW the R<sub>200</sub> and the M<sub>200</sub> are connected with DM exclusively.</p>
   <p>As the Direct mass is linked to the total mass (baryonic mass plus DM), in the Chapter 4 will be developed a procedure to integrate the baryonic mass in the NFW function mass, and this is the reason why R<sub>200</sub> and the M<sub>200</sub> are written with the subscript R<sub>200-TOTAL</sub> and the M<sub>200-TOTAL</sub> when they are linked to the total mass.</p>
  </sec><sec id="s3">
   <title>3. Virial Theorem as a Method to Get the Direct Mass Formula in Galaxies or Galaxy Clusters</title>
   <p>In Chapter 8, of paper <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca, M. 2024) was demonstrated that the direct mass formula</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mtext>
          TOTAL 
        </mtext> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mo>
          &lt; 
        </mo> 
        <mi>
          r 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           a 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          ⋅ 
        </mo> 
        <msqrt> 
         <mi>
           r 
         </mi> 
        </msqrt> 
       </mrow> 
       <mi>
         G 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (3.1)</p>
   <p>is the most suitable formula to calculate the total mass (baryonic and DM) enclosed by a sphere with a specific radius that ranges into the galactic halo.</p>
   <p>The halo is the region where the density of baryonic matter is negligible versus the D. M. density. e.g. the halo for Milky Way may have a radius bigger than 30 kpc, or the halo for M31 may have a radius bigger than 40 kpc. See <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca, M. 2024).</p>
   <sec id="s3_1">
    <title>3.1. Parameter a<sup>2</sup> Formula Depending on Virial Radius and Virial Mass</title>
    <p>Due to the fact that the Direct mass formula has one parameter only, is enough to know the mass associated to a specific radius to be able to calculate parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math>.</p>
    <p>According to DMbQG theory is possible to do an equation between M<sub>200</sub> (&lt;R<sub>200</sub>) = M<sub>DIRECT</sub> (&lt;R<sub>200</sub>) i.e.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>And clearing up</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (3.2)</p>
    <p>This formula is called parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> (M<sub>2</sub><sub>00</sub>, R<sub>200</sub>) because depend on both measures.</p>
   </sec>
   <sec id="s3_2">
    <title>3.2. Parameter a<sup>2</sup> Formula Depending on Virial Mass Only</title>
    <p>In Chapter 2 was got this formula 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
        </mrow> 
        <mn>
          3 
        </mn> 
       </msubsup> 
       <mtext> 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mtext> 
       </mtext> 
       <mfrac> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (2.2) as a good approximation between the virial mass and the virial radius. So using that formula and by substitution of the virial radius in 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mtext>
             VIRIAL 
           </mtext> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mrow> 
             <mtext>
               VIRIAL 
             </mtext> 
            </mrow> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> it is right to get the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> depending on M<sub>200</sub> only</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             G 
           </mi> 
           <mo>
             ⋅ 
           </mo> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            5 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            6 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             10 
           </mn> 
           <mo>
             ⋅ 
           </mo> 
           <mi>
             H 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            3 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (3.3)</p>
    <p>This formula will be called parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> (M<sub>200</sub>) as depend on M<sub>200</sub> only. Conversely it is possible to clear up the virial mass from the previous formulas.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mo>
           − 
         </mo> 
         <mi>
           T 
         </mi> 
         <mi>
           O 
         </mi> 
         <mi>
           T 
         </mi> 
         <mi>
           A 
         </mi> 
         <mi>
           L 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mrow> 
           <mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mn>
              5 
            </mn> 
           </mrow> 
          </mrow> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               10 
             </mn> 
             <mo>
               ⋅ 
             </mo> 
             <mi>
               H 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              5 
            </mn> 
           </mrow> 
          </mrow> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (3.4)</p>
    <p>or using the Formula (2.3) and clearing up the virial radius then</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mo>
           − 
         </mo> 
         <mi>
           T 
         </mi> 
         <mi>
           O 
         </mi> 
         <mi>
           T 
         </mi> 
         <mi>
           A 
         </mi> 
         <mi>
           L 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <msup> 
              <mi>
                a 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
            <mrow> 
             <mn>
               100 
             </mn> 
             <mo>
               ⋅ 
             </mo> 
             <msup> 
              <mi>
                H 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
           </mfrac> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            5 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (3.5)</p>
    <p>It is important to insist that the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> is linked to the total mass and this is the reason why the radius and mass are written with the subscript 200-TOTAL.</p>
    <p>In <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> (Abarca, 2024) using the rotation curve of M31 published by <xref ref-type="bibr" rid="scirp.144431-2">
      [2]
     </xref> (Sofue, 2015) was got the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        a 
      </mi> 
     </math> = 4.727513 × 10<sup>10</sup> m<sup>5/4</sup>/s or 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 2.235 × 10<sup>21</sup> m<sup>5/2</sup>/s<sup>2</sup> and using the rotation curve of <xref ref-type="bibr" rid="scirp.144431-4">
      [4]
     </xref> (Sofue, 2020) was got the same parameter for MW:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.527 × 10<sup>21</sup> m<sup>5/2</sup>/s<sup>2</sup>, so using the previous formulas are got the following values. See <xref ref-type="table" rid="table1">
      Table 1
     </xref>.</p>
    <table-wrap id="table1">
     <label>
      <xref ref-type="table" rid="table1">
       Table 1
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 1. M<sub>200-TOTAL</sub> and R<sub>200-TOTAL</sub> using the parameter 

       <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math>.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">Parameter 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">M<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="14.39%"><p style="text-align:center">m<sup>5/2</sup>/s<sup>2</sup></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="14.39%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="14.39%"><p style="text-align:center">kpc</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">M31 2.235 × 10<sup>21</sup></p></td> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">1.42 × 10<sup>12</sup></p></td> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">232.15</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.39%"><p style="text-align:center">MW 1.527 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center">9.02 × 10<sup>11</sup></p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center">199.33</p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
  </sec><sec id="s4">
   <title>4. The NFW Profile for Dark Matter Mass Density</title>
   <p>The NFW profile for DM density in galaxies is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ρ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           ρ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mi>
          x 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              + 
            </mo> 
            <mi>
              x 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (4.1)</p>
   <p>being 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> a characteristic density, x = r/R<sub>0</sub> a dimensionless magnitude related with radius by R<sub>0</sub>, which is called scale radius.</p>
   <p>By integration it is right to get the Dark matter enclosed by a sphere with radius r.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mtext>
          DM 
        </mtext> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mo>
          &lt; 
        </mo> 
        <mi>
          r 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         K 
       </mi> 
       <mrow> 
        <mtext>
          NFW 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        f 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         x 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (4.2)</p>
   <p>being</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         K 
       </mi> 
       <mrow> 
        <mtext>
          NFW 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msubsup> 
       <mi>
         R 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         3 
       </mn> 
      </msubsup> 
     </mrow> 
    </math> (4.3)</p>
   <p>and</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        f 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         x 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        ln 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <mi>
          x 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mi>
         x 
       </mi> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <mi>
            x 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math> (4.4)</p>
   <p>where x = r/R<sub>0</sub>, being ln the natural logarithm.</p>
   <p>Two important concepts for NFW profiles are M<sub>200</sub> and R<sub>200</sub> both referred to DM only i.e. the DM enclosed into a sphere with R<sub>200</sub> as radius whose mean</p>
   <p>density is 200 times the critic density 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mi>
         C 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          3 
        </mn> 
        <msup> 
         <mi>
           H 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          8 
        </mn> 
        <mi>
          π 
        </mi> 
        <mi>
          G 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        9.2055 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          27 
        </mn> 
       </mrow> 
      </msup> 
      <mtext>
          
      </mtext> 
      <mtext>
        kg 
      </mtext> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mtext>
         m 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          3 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>.</p>
   <p>So</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mn>
          200 
        </mn> 
        <mtext>
          -DM 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mtext>
          DM 
        </mtext> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mo>
          &lt; 
        </mo> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <mn>
            200 
          </mn> 
         </mrow> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         K 
       </mi> 
       <mrow> 
        <mtext>
          NFW 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        f 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         c 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (4.5)</p>
   <p>where</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        c 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mrow> 
          <mn>
            200 
          </mn> 
         </mrow> 
        </msub> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           R 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math> (4.6)</p>
   <p>is called the concentration parameter and R<sub>200</sub> = R<sub>0</sub> × c.</p>
   <sec id="s4_1">
    <title>4.1. Calculus of Concentration Parameter</title>
    <p>As 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
          <mn>
            3 
          </mn> 
         </msubsup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> then 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            3 
          </mn> 
         </msubsup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           π 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            3 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            3 
          </mn> 
         </msubsup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> so</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (4.7)</p>
    <p>This equation is quite easy to solve numerically, and it is clear that c depends on the characteristic density only.</p>
    <p>With this parameter c, it is rightly calculated M<sub>200-DM</sub> and R<sub>200</sub>.</p>
    <p>In <xref ref-type="table" rid="table2">
      Table 2
     </xref> are shown the NFW parameters published by <xref ref-type="bibr" rid="scirp.144431-4">
      [4]
     </xref> (Sofue, 2020) for MW.</p>
    <table-wrap id="table2">
     <label>
      <xref ref-type="table" rid="table2">
       Table 2
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 2. The NFW parameters for M. W. according to Sofue (2020).</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="65.78%"><p style="text-align:center">Characteristic density 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </math> </p></td> 
       <td class="custom-bottom-td acenter" width="34.22%"><p style="text-align:center">Scale radius 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="65.78%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             0.787 
           </mn> 
           <mo>
             ± 
           </mo> 
           <mn>
             0.037 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             GeV 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mrow> 
             <mtext>
               cm 
             </mtext> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
           <mo>
             = 
           </mo> 
           <mn>
             1.403 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               21 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math> </p></td> 
       <td class="custom-top-td acenter" width="34.22%"><p style="text-align:center">10.94 ± 1.05 kpc</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Using the characteristic density it is right to get the equation c<sup>3</sup>/f(c) = 2286.125 that gives the value c = 16.348, and f(c) = 1.91.</p>
    <p>So R<sub>200</sub> = R<sub>0</sub>·c = 178.85 kpc.</p>
    <p>Using (4.3) 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         3.4 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> then using (4.5) 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         6.498 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>In <xref ref-type="table" rid="table3">
      Table 3
     </xref> is checked the density of the sphere with the radius R<sub>200</sub>.</p>
    <table-wrap id="table3">
     <label>
      <xref ref-type="table" rid="table3">
       Table 3
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 3. Density of R<sub>200</sub> sphere versus 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <mn>
          
   200
  
         </mn>
  
         <msub> 
   
          <mi>
           
    ρ
   
          </mi> 
   
          <mi>
           
    C
   
          </mi> 
  
         </msub> 
 
        </mrow>

       </math>.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="14.39%"><p style="text-align:center">Mean density M<sub>200-DM</sub> versus R<sub>200</sub></p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.39%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             1.837 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               24 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math> </p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             1.841 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               24 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.39%" colspan="2"><p style="text-align:center">Ratio Density of R<sub>200</sub> sphere versus 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> = 0.997827</p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
   <sec id="s4_2">
    <title>4.2. Determining the NFW Profile by R<sub>200</sub> and the Concentration Parameter c</title>
    <p>Conversely, some authors give the NFW profile using three parameters M<sub>200-DM</sub>, R<sub>200</sub> and c.</p>
    <p>Using (4.7) and knowing the parameter c is possible to clear up the characteristic density</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           ⋅ 
         </mo> 
         <mn>
           4 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           π 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           G 
         </mi> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (4.8)</p>
    <p>in addition R<sub>0</sub> = R<sub>200</sub>/c. This way, knowing 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>, it is defined the NFW profile.</p>
    <p>Although M<sub>200-DM</sub> is derived from the previous ones, as it is very important all the authors publish its value. Namely its value may be calculated by (2.3) or by (4.5).</p>
    <p>For example, in <xref ref-type="table" rid="table4">
      Table 4
     </xref>, are shown the NFW parameters published by <xref ref-type="bibr" rid="scirp.144431-9">
      [9]
     </xref> (E. Karukes, 2020).</p>
    <p>The value M<sub>TOTAL-R200</sub> represents the total mass enclosed by the sphere R<sub>200</sub> so by subtraction of M<sub>TOTAL-R200</sub> minus M<sub>200-DM</sub> may be calculated the baryonic mass of MW i.e. 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           BA-MW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         6 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> according to this author.</p>
    <table-wrap id="table4">
     <label>
      <xref ref-type="table" rid="table4">
       Table 4
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 4. The NFW parameters for M. W. according to Karukes (2020).</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="25.00%"><p style="text-align:center">M<sub>200-DM</sub></p></td> 
       <td class="custom-bottom-td acenter" width="25.00%"><p style="text-align:center">M<sub>TOTAL-R200</sub></p></td> 
       <td class="custom-bottom-td acenter" width="20.47%"><p style="text-align:center">R<sub>200</sub></p></td> 
       <td class="custom-bottom-td acenter" width="29.53%"><p style="text-align:center">Concentration factor</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="25.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="25.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="20.47%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-top-td acenter" width="29.53%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="25.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               8.3 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               0.8 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               1.2 
             </mn> 
            </mrow> 
           </msubsup> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="25.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               8.9 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               0.8 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </msubsup> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="20.47%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               193 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               6 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               9 
             </mn> 
            </mrow> 
           </msubsup> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="29.53%"><p style="text-align:center">c = 19</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Obviously using the M<sub>TOTAL-R200</sub> into the sphere R<sub>200</sub> does not verify that the mean density is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math> as it is shown in <xref ref-type="table" rid="table5">
      Table 5
     </xref>.</p>
    <table-wrap id="table5">
     <label>
      <xref ref-type="table" rid="table5">
       Table 5
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 5. Comparing two different density mean with 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <mn>
          
   200
  
         </mn>
  
         <msub> 
   
          <mi>
           
    ρ
   
          </mi> 
   
          <mi>
           
    C
   
          </mi> 
  
         </msub> 
 
        </mrow>

       </math>.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="35.55%"><p style="text-align:center">Density<sub>MEAN</sub></p><p style="text-align:center">M<sub>200-DM</sub> into R<sub>200</sub></p></td> 
       <td class="custom-bottom-td acenter" width="37.26%"><p style="text-align:center">Density<sub>MEAN</sub></p><p style="text-align:center">M<sub>TOTAL-R200</sub> into R<sub>200</sub></p></td> 
       <td class="custom-bottom-td acenter" width="27.19%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="35.55%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             1.867 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               24 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="37.26%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             2 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               24 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="27.19%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             1.841 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               24 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="35.55%"><p style="text-align:center">Match well with 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
       <td class="acenter" width="37.26%"><p style="text-align:center">Does not match with 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
       <td class="acenter" width="27.19%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Using the data of <xref ref-type="table" rid="table4">
      Table 4
     </xref> is got the two typical parameters of NFW density profile.</p>
    <p>As R<sub>0</sub> = R<sub>200</sub>/c then R<sub>0</sub> = 10.1578 kpc.</p>
    <p>As c = 19 then f(c) = 2.04573.</p>
    <p>As 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> then 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         4.057 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>As 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         4 
       </mn> 
       <mi>
         π 
       </mi> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
        <mn>
          3 
        </mn> 
       </msubsup> 
      </mrow> 
     </math> then 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2.086 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msup> 
       <mtext>
           
       </mtext> 
       <mtext>
         kg 
       </mtext> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mtext>
          m 
        </mtext> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           3 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math>.</p>
    <p>According to <xref ref-type="bibr" rid="scirp.144431-9">
      [9]
     </xref> (E. Karukes, 2020), the data of <xref ref-type="table" rid="table4">
      Table 4
     </xref> about masses means that the baryonic mass enclosed by R<sub>200</sub> is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         6 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>. However for <xref ref-type="bibr" rid="scirp.144431-2">
      [2]
     </xref> (Sofue, 2015) the baryonic mass for the MW is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1.3 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and others authors give different values. It is known that the measures for the baryonic mass of MW has a high imprecision. Similarly the relative differences about the virial masses and radius are not negligible, although both authors give results compatibles if it is considered the range of errors.</p>
    <p>In <xref ref-type="table" rid="table6">
      Table 6
     </xref> are summarized the virial data of Sofue and Karukes.</p>
    <table-wrap id="table6">
     <label>
      <xref ref-type="table" rid="table6">
       Table 6
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 6. DM virial data Sofue vs Karukes.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td rowspan="2" class="acenter" width="33.33%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="33.33%"><p style="text-align:center">M<sub>200-DM</sub></p></td> 
       <td class="custom-bottom-td acenter" width="33.33%"><p style="text-align:center">R<sub>200-DM</sub></p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="33.33%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="33.33%"><p style="text-align:center">kpc</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="33.33%"><p style="text-align:center">
         <xref ref-type="bibr" rid="scirp.144431-4">
          [4]
         </xref> Sofue 2020 data</p></td> 
       <td class="custom-top-td acenter" width="33.33%"><p style="text-align:center">6.498 × 10<sup>11</sup></p></td> 
       <td class="custom-top-td acenter" width="33.33%"><p style="text-align:center">178.85</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="33.33%"><p style="text-align:center">
         <xref ref-type="bibr" rid="scirp.144431-9">
          [9]
         </xref> Karukes 2020 data</p></td> 
       <td class="acenter" width="33.33%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               8.3 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               0.8 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               1.2 
             </mn> 
            </mrow> 
           </msubsup> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="33.33%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               193 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               6 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               9 
             </mn> 
            </mrow> 
           </msubsup> 
          </mrow> 
         </math></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="33.33%"><p style="text-align:center">Relative difference %</p></td> 
       <td class="acenter" width="33.33%"><p style="text-align:center">21%</p></td> 
       <td class="acenter" width="33.33%"><p style="text-align:center">7.8%</p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
   <sec id="s4_3">
    <title>4.3. Calculus of Concentration Parameter t for the Total Mass</title>
    <p>As in this paper it will be compared the R<sub>200</sub> for the total masses, in this epigraph it will be developed a method to calculate the R<sub>200-TOTAL</sub> in the framework of the NFW profile density for DM. i.e. the radius of the sphere where the total mass has a mean density of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math>, this total mass will be denoted by M<sub>200-TOTAL</sub>. In the epigraph 4.2 was defined M<sub>TOTAL-R200</sub> and it was shown that its mean density into the R<sub>200</sub> sphere was bigger than 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math> as it was expected. In <xref ref-type="table" rid="table9">
      Table 9
     </xref> it will be shown that the mean density of M<sub>200-TOTAL</sub> into R<sub>200-TOTAL</sub> is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math>, as R<sub>200-TOTAL</sub> is bigger than R<sub>200</sub>. Below is developed a procedure to calculate the new R<sub>200-TOTAL</sub>.</p>
    <p>The total mass is the addition of baryonic plus the DM, as the baryonic mass is mainly concentrated into the bulge and disk of a galaxy, this amount of mass is a constant quantity into the halo dominion i.e.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         + 
       </mo> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         + 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math></p>
    <p>If it is defined</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            K 
          </mi> 
          <mrow> 
           <mtext>
             NFW 
           </mtext> 
          </mrow> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (4.9)</p>
    <p>then</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> (4.10)</p>
    <p>As the sphere whose mean density is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math> verify</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
           <mtext>
             -TOTAL 
           </mtext> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
           <mtext>
             -TOTAL 
           </mtext> 
          </mrow> 
          <mn>
            3 
          </mn> 
         </msubsup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> Formula (2.4)</p>
    <p>And defining a new parameter t</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
           <mtext>
             -TOTAL 
           </mtext> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (4.11)</p>
    <p>It is got 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              f 
            </mi> 
            <mrow> 
             <mi>
               B 
             </mi> 
             <mi>
               A 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             + 
           </mo> 
           <mi>
             f 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              t 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
         <mo>
           ⋅ 
         </mo> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            3 
          </mn> 
         </msubsup> 
        </mrow> 
        <mrow> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            3 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> that leads to the expression 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> that by (4.7) leads to</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (4.12)</p>
    <p>This equation allows calculating the concentration parameter t for the total mass.</p>
    <p>The parameter t depends on the parameter c and the fraction f<sub>BA</sub>.</p>
    <p>In the following two epigraphs will be used this method with two different data set provided by two authors about the NFW profile in MW.</p>
    <p>In <xref ref-type="table" rid="table7">
      Table 7
     </xref> are the <xref ref-type="bibr" rid="scirp.144431-4">
      [4]
     </xref> Sofue (2020) data to calculate the parameter t.</p>
    <table-wrap id="table7">
     <label>
      <xref ref-type="table" rid="table7">
       Table 7
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 7. NFW parameters according Sofue to calculate the parameter t.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="100.00%" colspan="2"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             10.94 
           </mn> 
           <mo>
             ± 
           </mo> 
           <mn>
             1.05 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             kpc 
           </mtext> 
          </mrow> 
         </math> and 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             1.403 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               21 
             </mn> 
            </mrow> 
           </msup> 
           <mtext>
               
           </mtext> 
           <mtext>
             kg 
           </mtext> 
           <mo>
             ⋅ 
           </mo> 
           <msup> 
            <mtext>
              m 
            </mtext> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               3 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="100.00%" colspan="2"><p style="text-align:center">See epigraph 4.1 for calculus of: c, R<sub>200</sub>, M<sub>200-DM</sub>, K<sub>NFW</sub></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="54.50%"><p style="text-align:center">c = 16.348</p></td> 
       <td class="acenter" width="45.50%"><p style="text-align:center">R<sub>200</sub> = 178.85 kpc</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="54.50%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              K 
            </mi> 
            <mrow> 
             <mtext>
               NFW 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             3.4 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="45.50%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
             <mtext>
               -DM 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             6.498 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="54.50%"><p style="text-align:center">
         <xref ref-type="bibr" rid="scirp.144431-2">
          [2]
         </xref> Sofue (2015) 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mi>
               B 
             </mi> 
             <mi>
               A 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             1.3 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
       <td class="acenter" width="45.50%"><p style="text-align:center">f<sub>BA</sub> = M<sub>BA</sub>/K<sub>NFW</sub> = 0.382</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>So 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> leads to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           0.382 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4369.12 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           1.911 
         </mn> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         2286.156 
       </mn> 
      </mrow> 
     </math> whose solution is 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         17.527 
       </mn> 
      </mrow> 
     </math>.</p>
    <p>So 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         191.745 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         kpc 
       </mtext> 
      </mrow> 
     </math> and as 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         1.9732 
       </mn> 
      </mrow> 
     </math> the 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mn>
           0.382 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         8.0077 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>In <xref ref-type="table" rid="table8">
      Table 8
     </xref> are the <xref ref-type="bibr" rid="scirp.144431-9">
      [9]
     </xref> (Karukes, 2020) data to calculate the parameter t.</p>
    <table-wrap id="table8">
     <label>
      <xref ref-type="table" rid="table8">
       Table 8
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 8. NFW parameters according to Karukes to calculate the parameter t.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="39.60%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
             <mtext>
               -DM 
             </mtext> 
            </mrow> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td acenter" width="27.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td acenter" width="32.73%"><p style="text-align:center">Concentration factor c</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="39.60%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               8.3 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               0.8 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               1.2 
             </mn> 
            </mrow> 
           </msubsup> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
       <td class="acenter" width="27.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msubsup> 
            <mrow> 
             <mn>
               193 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               6 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               9 
             </mn> 
            </mrow> 
           </msubsup> 
          </mrow> 
         </math> kpc</p></td> 
       <td class="acenter" width="32.73%"><p style="text-align:center">c = 19</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="39.60%"><p style="text-align:center"></p></td> 
       <td class="acenter" width="27.68%"><p style="text-align:center">R<sub>0</sub> = 193/19 = 10.158</p></td> 
       <td class="acenter" width="32.73%"><p style="text-align:center">f(c) = 2.045732274</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="39.60%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              K 
            </mi> 
            <mrow> 
             <mtext>
               NFW 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             4.0572269 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mi>
               B 
             </mi> 
             <mi>
               A 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             6 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="32.73%"><p style="text-align:center">f<sub>BA</sub> = M<sub>BA</sub>/K<sub>NFW</sub> = 0.147884</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>So 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> leads to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            t 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           0.1479 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         3352.886 
       </mn> 
      </mrow> 
     </math> whose solution is 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         19.5191 
       </mn> 
      </mrow> 
     </math>.</p>
    <p>So 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         198.273 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         kpc 
       </mtext> 
      </mrow> 
     </math>.</p>
    <p>and as 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          t 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         2.07 
       </mn> 
      </mrow> 
     </math> the 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mn>
           0.1479 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            t 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         8.998 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>In <xref ref-type="table" rid="table9">
      Table 9
     </xref> are summarized the total mass and the total radius data, according Sofue and Karukes data. Although the relative differences are not negligible both match if it is considered the range of error measures.</p>
    <table-wrap id="table9">
     <label>
      <xref ref-type="table" rid="table9">
       Table 9
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 9. Virial total mass and virial radius data. Sofue versus Karukes.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td rowspan="2" class="acenter" width="31.08%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="20.01%"><p style="text-align:center">M<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="16.82%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="32.09%"><p style="text-align:center">Mean density vs 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="20.01%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="16.82%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="32.09%"><p style="text-align:center">Dimensionless</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="31.08%"><p style="text-align:center">Using Sofue data</p></td> 
       <td class="custom-top-td acenter" width="20.01%"><p style="text-align:center">8.0 × 10<sup>11</sup></p></td> 
       <td class="custom-top-td acenter" width="16.82%"><p style="text-align:center">191.7</p></td> 
       <td class="custom-top-td acenter" width="32.09%"><p style="text-align:center">0.99735</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="31.08%"><p style="text-align:center">Using Karukes data</p></td> 
       <td class="acenter" width="20.01%"><p style="text-align:center">9.0 × 10<sup>11</sup></p></td> 
       <td class="acenter" width="16.82%"><p style="text-align:center">198.3</p></td> 
       <td class="acenter" width="32.09%"><p style="text-align:center">1.01368</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="31.08%"><p style="text-align:center">Relative Diff. %</p></td> 
       <td class="acenter" width="20.01%"><p style="text-align:center">11%</p></td> 
       <td class="acenter" width="16.82%"><p style="text-align:center">3.3%</p></td> 
       <td class="acenter" width="32.09%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
  </sec><sec id="s5">
   <title>5. Testing the Equivalence between Direct Mass and NFW Total Mass in MW Halo</title>
   <p>As the direct mass is referred to the total mass into the halo region, it is needed to extend the NFW for DM formula to the total mass, following the procedure developed in the Epigraph 4.3, in order to be able to compare both formulas.</p>
   <p>In this chapter will be introduced a set of four tests to check the equivalence between the two formulas into the halo region up to the R<sub>200-TOTAL</sub> radius.</p>
   <p>Although the set of tests developed in this chapter is general, are used the MW data because our galaxy is the best well known with the most accuracy data.</p>
   <sec id="s5_1">
    <title>5.1. Comparison between R<sub>200-TOTAL</sub> and M<sub>200-TOTAL</sub> Values Got by Direct Mass and NFW Total Mass. Test I</title>
    <p>In <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> (Abarca, M. 2024) was got the direct mass (3.1) formula, that in the framework of DMbQG theory is the formula for the total mass depending on the radius into the halo and as a consequence of (3.1) were got the formulas</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mrow> 
           <mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mn>
              5 
            </mn> 
           </mrow> 
          </mrow> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               10 
             </mn> 
             <mo>
               ⋅ 
             </mo> 
             <mi>
               H 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              5 
            </mn> 
           </mrow> 
          </mrow> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (3.4) and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <msup> 
              <mi>
                a 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
            <mrow> 
             <mn>
               100 
             </mn> 
             <mo>
               ⋅ 
             </mo> 
             <msup> 
              <mi>
                H 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
           </mfrac> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            5 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (3.5) which depend on the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> solely. See <xref ref-type="table" rid="table1">
      Table 1
     </xref>.</p>
    <p>By other side, as in the epigraph 4.3 has been got the R<sub>200-TOTAL</sub> and the M<sub>200-TOTAL</sub> in the framework of NFW, now it is possible to compare both parameters got with the two different methods.</p>
    <p>In <xref ref-type="table" rid="table10">
      Table 10
     </xref> is shown the three different values for R<sub>200-TOTAL</sub> and M<sub>200-TOTAL</sub>, they match perfectly if it is considered the range of errors. Also it is checked the ratio mean density versus 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math>, which differs from unity in thousands for the three values.</p>
    <table-wrap id="table10">
     <label>
      <xref ref-type="table" rid="table10">
       Table 10
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 10. Comparison of virial total mass and virial radius for MW. Test I.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td rowspan="2" class="acenter" width="28.10%"><p style="text-align:center">MW Galaxy</p></td> 
       <td class="custom-bottom-td acenter" width="20.01%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="22.57%"><p style="text-align:center">M<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="29.32%"><p style="text-align:center">Density<sub>MEAN</sub>/ 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             200 
           </mn> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mi>
              C 
            </mi> 
           </msub> 
          </mrow> 
         </math> </p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="20.01%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="22.57%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="29.32%"><p style="text-align:center">Dimensionless</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="28.10%"><p style="text-align:center">By parameter 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> </p></td> 
       <td class="custom-top-td acenter" width="20.01%"><p style="text-align:center">199.33</p></td> 
       <td class="custom-top-td acenter" width="22.57%"><p style="text-align:center">9.02 × 10<sup>11</sup></p></td> 
       <td class="custom-top-td acenter" width="29.32%"><p style="text-align:center">1.00026</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="28.10%"><p style="text-align:center">Sofue NFW-total</p></td> 
       <td class="acenter" width="20.01%"><p style="text-align:center">191.745</p></td> 
       <td class="acenter" width="22.57%"><p style="text-align:center">8.0077 × 10<sup>11</sup></p></td> 
       <td class="acenter" width="29.32%"><p style="text-align:center">0.9976</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="28.10%"><p style="text-align:center">Karukes NFW-total</p></td> 
       <td class="acenter" width="20.01%"><p style="text-align:center">198.273</p></td> 
       <td class="acenter" width="22.57%"><p style="text-align:center">8.998 × 10<sup>11</sup></p></td> 
       <td class="acenter" width="29.32%"><p style="text-align:center">1.0139</p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
   <sec id="s5_2">
    <title>5.2. Calculus of Parameter a<sup>2</sup> Using M<sub>200-TOTAL</sub> Got by NFW. Test II</title>
    <p>As in the Epigraph 4 was calculated M<sub>200-TOTAL</sub> using the NFW method, then it is possible to use such result to calculate the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> by the formula:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             G 
           </mi> 
           <mo>
             ⋅ 
           </mo> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            5 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            6 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             10 
           </mn> 
           <mo>
             ⋅ 
           </mo> 
           <mi>
             H 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            3 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> Formula (3.3)</p>
    <p>Then this result may be compared with the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> got in <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> (Abarca, M. 2024) in the framework of DMbQG theory that for MW is 1.527 × 10<sup>21</sup> m<sup>5/2</sup>∙s<sup>−2</sup> that is the reference value. See <xref ref-type="table" rid="table11">
      Table 11
     </xref>.</p>
    <table-wrap id="table11">
     <label>
      <xref ref-type="table" rid="table11">
       Table 11
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 11. Comparing the parameter 

       <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math>. Test II.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td rowspan="2" class="acenter" width="24.99%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="26.94%"><p style="text-align:center">M<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="25.54%"><p style="text-align:center">Parameter 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td acenter" width="22.51%"><p style="text-align:center">Relative diff.</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="26.94%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="25.54%"><p style="text-align:center">m<sup>5/2</sup>∙s<sup>−2</sup></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="22.51%"><p style="text-align:center">%</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="24.99%"><p style="text-align:center">Sofue NFW</p></td> 
       <td class="custom-top-td acenter" width="26.94%"><p style="text-align:center">8.0077 × 10<sup>11</sup></p></td> 
       <td class="custom-top-td acenter" width="25.54%"><p style="text-align:center">1.383 × 10<sup>21</sup></p></td> 
       <td class="custom-top-td acenter" width="22.51%"><p style="text-align:center">9.4 (good)</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="24.99%"><p style="text-align:center">Karukes NFW</p></td> 
       <td class="acenter" width="26.94%"><p style="text-align:center">8.998 × 10<sup>11</sup></p></td> 
       <td class="acenter" width="25.54%"><p style="text-align:center">1.524 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="22.51%"><p style="text-align:center">0.2 (excellent)</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="51.95%" colspan="2"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> as reference. See <xref ref-type="table" rid="table1">
          Table 1
         </xref></p></td> 
       <td class="acenter" width="25.54%"><p style="text-align:center">1.527 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="22.51%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>The comparison between the reference parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> and the one got by Sofue NFW data is good (9.4%), but the comparison with the one got by Karukes data is excellent (0.2%).</p>
   </sec>
   <sec id="s5_3">
    <title>5.3. Calculus of Parameter a<sup>2</sup> Using M<sub>200-TOTAL</sub> and R<sub>200-TOTAL</sub> Got by NFW. Test III</title>
    <p>In this test the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> is got by the formula 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> Equation (3.2),</p>
    <p>using M<sub>200-TOTAL</sub> and R<sub>200-TOTAL</sub> got by NFW method. See <xref ref-type="table" rid="table12">
      Table 12
     </xref>, in the second and third columns are summarized the data got in the epigraph 4.3. The fourth column shows the three different values of parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math>.</p>
    <table-wrap id="table12">
     <label>
      <xref ref-type="table" rid="table12">
       Table 12
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 12. Comparing the parameter 

       <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math>. Test III.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td rowspan="2" class="acenter" width="20.01%"><p style="text-align:center">MW</p></td> 
       <td class="custom-bottom-td acenter" width="20.00%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="20.00%"><p style="text-align:center">M<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="22.60%"><p style="text-align:center">Parameter 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> </p></td> 
       <td class="custom-bottom-td acenter" width="17.40%"><p style="text-align:center">Relative diff.</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td custom-top-td acenter" width="20.00%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="20.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="22.60%"><p style="text-align:center">m<sup>5/2</sup>s<sup>−2</sup></p></td> 
       <td class="custom-bottom-td custom-top-td acenter" width="17.40%"><p style="text-align:center">%</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="20.01%"><p style="text-align:center">Sofue NFW</p></td> 
       <td class="custom-top-td acenter" width="20.00%"><p style="text-align:center">191.745</p></td> 
       <td class="custom-top-td acenter" width="20.00%"><p style="text-align:center">8.0077 × 10<sup>11</sup></p></td> 
       <td class="custom-top-td acenter" width="22.60%"><p style="text-align:center">1.3824 × 10<sup>21</sup></p></td> 
       <td class="custom-top-td acenter" width="17.40%"><p style="text-align:center">9.4</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="20.01%"><p style="text-align:center">Karukes NFW</p></td> 
       <td class="acenter" width="20.00%"><p style="text-align:center">198.273</p></td> 
       <td class="acenter" width="20.00%"><p style="text-align:center">8.998 × 10<sup>11</sup></p></td> 
       <td class="acenter" width="22.60%"><p style="text-align:center">1.5276 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="17.40%"><p style="text-align:center">0.03</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="60.01%" colspan="3"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> as reference. See <xref ref-type="table" rid="table1">
          Table 1
         </xref></p></td> 
       <td class="acenter" width="22.60%"><p style="text-align:center">1.527 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="17.40%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>The result of this test is very similar to the test II because in the framework of DMbQG the Formulas (3.3) and (3.2) are mathematically equivalents.</p>
   </sec>
   <sec id="s5_4">
    <title>5.4. Comparison of Direct Mass Formula with the NFW-Total Mass Formula into the Halo Region up to R<sub>200-TOTAL</sub>. Test IV</title>
    <p>The NFW mass formula extended to the total mass was developed in the Chapter 4, being 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> (4.10), being K<sub>NFW</sub> the constant defined by (4.3), and f<sub>BA</sub> as the fraction of baryonic matter, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            K 
          </mi> 
          <mrow> 
           <mtext>
             NFW 
           </mtext> 
          </mrow> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (4.9).</p>
    <p>In addition 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi>
         ln 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           x 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         − 
       </mo> 
       <mrow> 
        <mi>
          x 
        </mi> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             1 
           </mn> 
           <mo>
             + 
           </mo> 
           <mi>
             x 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (4.4) where x = r/R<sub>0</sub> is the dimensionless variable associated to the variable radius.</p>
    <p>The direct mass formula for the total mass in the framework of DMbQG theory is</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mi>
            r 
          </mi> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> Formula (3.1)</p>
    <p>In order to compare both formulas it is needed to use the same dimensionless variable x. So the Equation (3.1) will be changed in this way:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mi>
            r 
          </mi> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
      </mrow> 
     </math></p>
    <p>where x = r/R<sub>0</sub> being R<sub>0</sub> the NFW scale radius.</p>
    <p>Defining</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> (5.1)</p>
    <p>then the direct mass is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
      </mrow> 
     </math> (5.2)</p>
    <p>For example, for the MW galaxy using R<sub>0</sub> = 10.94 kpc, see <xref ref-type="table" rid="table2">
      Table 2
     </xref>, and parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.527 × 10<sup>21</sup> m<sup>5/2</sup>∙s<sup>−2</sup> then 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2.11 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>In order to compare the direct mass (5.2) with the NFW total mass (4.10) it is defined f<sub>T</sub> = K<sub>T</sub>/K<sub>NFW</sub> and so</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           DIRECT 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
      </mrow> 
     </math> (5.3)</p>
    <p>This way this function may be compared with</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> Formula (4.10)</p>
    <p>and If it is cancelled the common factor K<sub>NFW</sub>, with mass dimension, both functions become as dimensionless functions factors, written as FM:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           DIRECT 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
      </mrow> 
     </math> (5.4)</p>
    <p>and</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (5.5)</p>
    <p>For example using the MW Sofue data, see <xref ref-type="table" rid="table7">
      Table 7
     </xref>, may be defined (5.4) and (5.5). The parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> comes from <xref ref-type="table" rid="table1">
      Table 1
     </xref>. In <xref ref-type="table" rid="table13">
      Table 13
     </xref> are summarized all the parameters for the both functions.</p>
    <table-wrap id="table13">
     <label>
      <xref ref-type="table" rid="table13">
       Table 13
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 13. Parameters for the both function factor FM.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">f<sub>BA</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">f<sub>T</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">R<sub>0</sub> kpc</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.39%"><p style="text-align:center">MW</p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center">0.382</p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center">0.62</p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center">192 kpc</p></td> 
       <td class="acenter" width="14.39%"><p style="text-align:center">10.94</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>As the dominion for radius is the halo region from 30 kpc up to 200 kpc, the dominion for the variable x is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         x 
       </mi> 
       <mo>
         ∈ 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mo>
           , 
         </mo> 
         <mn>
           18 
         </mn> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> being x dimensionless.</p>
    <p>In <xref ref-type="table" rid="table14">
      Table 14
     </xref> are tabulated both dimensionless function factor mass and it is shown its relative difference.</p>
    <table-wrap id="table14">
     <label>
      <xref ref-type="table" rid="table14">
       Table 14
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 14. Direct mass factor function versus NFW-total mass factor function.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="17.24%"><p style="text-align:center">Radius kpc</p></td> 
       <td class="custom-bottom-td acenter" width="14.05%"><p style="text-align:center">Variable</p><p style="text-align:center">X</p></td> 
       <td class="custom-bottom-td acenter" width="25.97%"><p style="text-align:center">Dimensionless</p><p style="text-align:center">Factor Direct mass</p></td> 
       <td class="custom-bottom-td acenter" width="29.15%"><p style="text-align:center">Dimensionless factor NFW-total mass</p></td> 
       <td class="custom-bottom-td acenter" width="13.58%"><p style="text-align:center">Relative</p><p style="text-align:center">Diff. %</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="17.24%"><p style="text-align:center">32.82</p></td> 
       <td class="custom-top-td acenter" width="14.05%"><p style="text-align:center">3</p></td> 
       <td class="custom-top-td acenter" width="25.97%"><p style="text-align:center">1.07387</p></td> 
       <td class="custom-top-td acenter" width="29.15%"><p style="text-align:center">1.01829</p></td> 
       <td class="custom-top-td acenter" width="13.58%"><p style="text-align:center">5.18</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">43.76</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">4</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.24000</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.19144</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">3.92</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">54.7</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">5</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.38636</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.34043</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">3.31</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">65.64</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">6</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.51868</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.47077</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">3.16</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">76.58</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">7</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.64037</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.58644</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">3.29</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">87.52</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">8</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.75362</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.69034</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">3.61</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">98.46</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">9</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.86000</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.78459</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">4.05</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">109.4</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">10</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">1.96061</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.87080</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">4.58</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">120.34</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">11</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.05631</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">1.95024</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">5.16</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">131.28</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">12</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.14774</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.02387</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">5.77</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">142.22</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">13</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.23544</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.09249</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">6.39</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">153.16</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">14</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.31983</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.15672</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">7.03</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">164.1</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">15</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.40125</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.21709</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">7.67</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">175.04</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">16</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.48000</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.27404</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">8.30</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">185.98</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">17</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.55633</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.32793</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">8.93</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center">196.92</p></td> 
       <td class="acenter" width="14.05%"><p style="text-align:center">18</p></td> 
       <td class="acenter" width="25.97%"><p style="text-align:center">2.63044</p></td> 
       <td class="acenter" width="29.15%"><p style="text-align:center">2.37907</p></td> 
       <td class="acenter" width="13.58%"><p style="text-align:center">9.56</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Although the relative difference increases continuously, remains below 10% in the whole dominion. See <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref>.</p>
    <fig id="fig1" position="float">
     <label>Figure 1</label>
     <caption>
      <title>Figure 1. Function factor of direct mass vs function factor of NFW-total mass. Sofue data.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181303-rId313.jpeg?20250730102936" />
    </fig>
    <p>This relative difference is acceptable because the f<sub>BA</sub> is a value with a very high imprecision. In the following epigraph will be used f<sub>BA</sub> 0.1479 given by <xref ref-type="bibr" rid="scirp.144431-9">
      [9]
     </xref> (E. Karukes).</p>
    <p>In order to compare both formulas are needed the new parameters provided by this author, see <xref ref-type="table" rid="table8">
      Table 8
     </xref>, R<sub>0</sub> = 10.158 kpc, f<sub>BA</sub> = 0.147884 and K<sub>NFW</sub> = 4.0572269 × 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>In addition it is needed the factor f<sub>T</sub> = K<sub>T</sub>/K<sub>NFW</sub> where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math>.</p>
    <p>As the parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> is got by the rotation curve into the halo region and this author did not publish such curve, it is need to use the parameter calculated with <xref ref-type="bibr" rid="scirp.144431-4">
      [4]
     </xref> Sofue data, see <xref ref-type="table" rid="table1">
      Table 1
     </xref> parameter 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.527 × 10<sup>21</sup> so 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2.03584 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and f<sub>T</sub> = 0.50178.</p>
    <p>As the dominion for radius is the halo region from 30 kpc up to 198 kpc, the dominion for the variable x is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         x 
       </mi> 
       <mo>
         ∈ 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mo>
           , 
         </mo> 
         <mn>
           20 
         </mn> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math>.</p>
    <p>Comparing <xref ref-type="table" rid="table13">
      Table 13
     </xref> and <xref ref-type="table" rid="table15">
      Table 15
     </xref> it is clear that parameters f<sub>T</sub> are lightly different but parameters f<sub>BA</sub> are very different because according Karukes the baryonic mass of MW is lower than a half the value considered by Sofue.</p>
    <table-wrap id="table15">
     <label>
      <xref ref-type="table" rid="table15">
       Table 15
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 15. Parameters for the both function factor FM using Karukes data.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">f<sub>BA</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">f<sub>T</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">R<sub>0</sub></p></td> 
       <td class="custom-bottom-td acenter" width="14.39%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">MW</p></td> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">0.147884</p></td> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">0.50178</p></td> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">10.158 kpc</p></td> 
       <td class="custom-top-td acenter" width="14.39%"><p style="text-align:center">198 kpc</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           DIRECT 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
      </mrow> 
     </math> Formula (5.4)</p>
    <p>And</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> Formula (5.5)</p>
    <p>In <xref ref-type="table" rid="table16">
      Table 16
     </xref> are tabulated both dimensionless mass function factors and its relative difference. Excepting the value for radius 30.5 kpc the other one’s values have a relative difference below 5%, however with the Sofue data a half of data have its relative difference under 5% and the other half data range between 5% and 10%.</p>
    <table-wrap id="table16">
     <label>
      <xref ref-type="table" rid="table16">
       Table 16
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 16. Direct mass factor function vs NFW-total mass factor function. Karukes.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="14.48%"><p style="text-align:center">Radius</p><p style="text-align:center">kpc</p></td> 
       <td class="custom-bottom-td acenter" width="12.77%"><p style="text-align:center">Variable</p><p style="text-align:center">X</p></td> 
       <td class="custom-bottom-td acenter" width="26.40%"><p style="text-align:center">Dimensionless</p><p style="text-align:center">Factor Direct mass</p></td> 
       <td class="custom-bottom-td acenter" width="30.02%"><p style="text-align:center">Dimensionless Factor</p><p style="text-align:center">NFW-total mass</p></td> 
       <td class="custom-bottom-td acenter" width="16.33%"><p style="text-align:center">Relative</p><p style="text-align:center">Diff. %</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="14.48%"><p style="text-align:center">30.474</p></td> 
       <td class="custom-top-td acenter" width="12.77%"><p style="text-align:center">3</p></td> 
       <td class="custom-top-td acenter" width="26.40%"><p style="text-align:center">0.8657</p></td> 
       <td class="custom-top-td acenter" width="30.02%"><p style="text-align:center">0.7842</p></td> 
       <td class="custom-top-td acenter" width="16.33%"><p style="text-align:center">9.413</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">40.632</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">4</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">0.9996</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">0.9573</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">4.228</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">50.79</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">5</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.1176</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.1063</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">1.008</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">60.948</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">6</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.2243</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.2367</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−1.014</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">71.106</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">7</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.3223</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.3523</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−2.268</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">81.264</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">8</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.4136</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.4562</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−3.013</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">91.422</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">9</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.4994</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.5505</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−3.407</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">101.58</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">10</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.5805</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.6367</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−3.556</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">111.738</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">11</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.6576</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.7161</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−3.529</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">121.896</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">12</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.7314</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.7898</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−3.374</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">132.054</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">13</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.8021</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.8584</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−3.126</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">142.212</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">14</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.8701</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.9226</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−2.809</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">152.37</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">15</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.9357</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">1.9830</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−2.442</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">162.528</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">16</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">1.9992</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">2.0399</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−2.038</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">172.686</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">17</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">2.0607</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">2.0938</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−1.606</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">182.844</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">18</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">2.1205</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">2.1450</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−1.155</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">193.002</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">19</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">2.1786</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">2.1936</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−0.691</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.48%"><p style="text-align:center">203.16</p></td> 
       <td class="acenter" width="12.77%"><p style="text-align:center">20</p></td> 
       <td class="acenter" width="26.40%"><p style="text-align:center">2.2352</p></td> 
       <td class="acenter" width="30.02%"><p style="text-align:center">2.2400</p></td> 
       <td class="acenter" width="16.33%"><p style="text-align:center">−0.218</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>The cause about this discrepancy is that the baryonic mater in MW has a high level of imprecision. E.g. for Karukes 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         6 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and for Sofue M<sub>BA</sub> = 1.3 × 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>However, in my opinion both examples demonstrate the main thesis of this paper:</p>
    <p>The direct mass formula is equivalent to NFW formula extended to the total mass, into the halo region of MW from 30 kpc up to 200 kpc.</p>
    <p>In <xref ref-type="fig" rid="fig2">
      Figure 2
     </xref> is shown how close both functions are.</p>
    <fig id="fig2" position="float">
     <label>Figure 2</label>
     <caption>
      <title>Figure 2. Function factor of direct mass vs function factor of NFW-total mass. Karukes.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181303-rId332.jpeg?20250730102936" />
    </fig>
   </sec>
  </sec><sec id="s6">
   <title>6. Testing the Equivalence between Direct Mass and NFW Total Mass in M31 Halo</title>
   <p>In this chapter it will made the same four tests made to MW in the previous chapters but to M31 galaxy. It will be used the NFW DM density profile published by <xref ref-type="bibr" rid="scirp.144431-3">
     [3]
    </xref> (Sofue, Y. 2015) and the direct mass formula published in <xref ref-type="bibr" rid="scirp.144431-1">
     [1]
    </xref> (Abarca, M. 2024).</p>
   <p>In <xref ref-type="table" rid="table17">
     Table 17
    </xref> are shown the <xref ref-type="bibr" rid="scirp.144431-2">
     [2]
    </xref> (Sofue, 2015) data for the M31 NFW DM profile.</p>
   <table-wrap id="table17">
    <label>
     <xref ref-type="table" rid="table17">
      Table 17
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 17. NFW parameters and baryonic mass for M31. Sofue data.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="30.02%"><p style="text-align:center">NFW parameters</p></td> 
      <td class="custom-bottom-td acenter" width="28.32%"><p style="text-align:center">R<sub>0</sub> Radius scale</p></td> 
      <td class="custom-bottom-td acenter" width="41.67%"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msub> 
           <mi>
             ρ 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
        </math> Characteristic density</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="30.02%"><p style="text-align:center">Measures of parameters</p></td> 
      <td class="custom-top-td acenter" width="28.32%"><p style="text-align:center">34.6 ± 2.1 kpc</p></td> 
      <td class="custom-top-td acenter" width="41.67%"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <mn>
            1.51 
          </mn> 
          <mo>
            ± 
          </mo> 
          <mn>
            0.16 
          </mn> 
          <mo>
            × 
          </mo> 
          <msup> 
           <mrow> 
            <mn>
              10 
            </mn> 
           </mrow> 
           <mrow> 
            <mo>
              − 
            </mo> 
            <mn>
              22 
            </mn> 
           </mrow> 
          </msup> 
         </mrow> 
        </math> kg∙m<sup>−3</sup></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="30.02%"><p style="text-align:center">M31 Baryonic mass</p></td> 
      <td class="acenter" width="28.32%"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <mn>
            1.6 
          </mn> 
          <mo>
            × 
          </mo> 
          <msup> 
           <mrow> 
            <mn>
              10 
            </mn> 
           </mrow> 
           <mrow> 
            <mn>
              11 
            </mn> 
           </mrow> 
          </msup> 
          <msub> 
           <mi>
             M 
           </mi> 
           <mi>
             Θ 
           </mi> 
          </msub> 
         </mrow> 
        </math></p></td> 
      <td class="acenter" width="41.67%"><p style="text-align:center"></p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>Using the method developed in the epigraph 4.3 now it will be calculated R<sub>200-</sub><sub>TOTAL</sub> and M<sub>200-TOTAL</sub> for M31.</p>
   <p>So from (4.3) formula 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         K 
       </mi> 
       <mrow> 
        <mtext>
          NFW 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1.16 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          12 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mi>
          B 
        </mi> 
        <mi>
          A 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <msub> 
         <mi>
           M 
         </mi> 
         <mrow> 
          <mi>
            B 
          </mi> 
          <mi>
            A 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           K 
         </mi> 
         <mrow> 
          <mtext>
            NFW 
          </mtext> 
         </mrow> 
        </msub> 
       </mrow> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        0.14 
      </mn> 
     </mrow> 
    </math>.</p>
   <p>From Formula (4.7) it is right to get 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           c 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        246.048 
      </mn> 
     </mrow> 
    </math> the equation to calculate</p>
   <p>numerically the concentration parameter c whose solution is c = 6.579 and f(c) = 1.15734 so R<sub>200-DM</sub> = R<sub>0</sub>·c = 227.66 Kpc and from the Formula (4.5) it is got M<sub>200-DM</sub> = 1.34 × 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          12 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>The Equation (4.12) allows to calculate the concentration parameter t for the total mass, so 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msub> 
         <mtext>
           f 
         </mtext> 
         <mrow> 
          <mtext>
            BA 
          </mtext> 
         </mrow> 
        </msub> 
        <mo>
          + 
        </mo> 
        <mtext>
          f 
        </mtext> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mtext>
           t 
         </mtext> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           c 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> becomes 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          0.14 
        </mn> 
        <mo>
          + 
        </mo> 
        <mtext>
          f 
        </mtext> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mtext>
           t 
         </mtext> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        246.048 
      </mn> 
     </mrow> 
    </math> whose numerical solution is t = 6.89639.</p>
   <p>And so R<sub>200-TOTAL</sub> = t × R<sub>0</sub> = 238.6 kpc, in addition 0.14 + f(t) = 1.333.</p>
   <p>Finally by (4.10) 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mrow> 
        <mn>
          200 
        </mn> 
        <mtext>
          -TOTAL 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         [ 
       </mo> 
       <mrow> 
        <mn>
          0.14 
        </mn> 
        <mo>
          + 
        </mo> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ] 
       </mo> 
      </mrow> 
      <msub> 
       <mi>
         K 
       </mi> 
       <mrow> 
        <mtext>
          NFW 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1.546 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          12 
        </mn> 
       </mrow> 
      </msup> 
      <msub> 
       <mi>
         M 
       </mi> 
       <mi>
         Θ 
       </mi> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>These two parameters R<sub>200-TOTAL</sub> and M<sub>200-TOTAL</sub> are the adequate parameters because are linked to the total mass and they verify that the mean density in the R<sub>200-</sub><sub>TOTAL</sub> radius sphere is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        200 
      </mn> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mi>
         C 
       </mi> 
      </msub> 
     </mrow> 
    </math>. In <xref ref-type="table" rid="table18">
     Table 18
    </xref> is checked this property almost with mathematical accuracy.</p>
   <table-wrap id="table18">
    <label>
     <xref ref-type="table" rid="table18">
      Table 18
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 18. Comparison of virial total mass and virial radius for M31. Test I.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="25.33%"><p style="text-align:center"></p></td> 
      <td class="custom-bottom-td acenter" width="19.37%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
      <td class="custom-bottom-td acenter" width="26.61%"><p style="text-align:center">M<sub>200-TOTAL</sub> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msub> 
           <mi>
             M 
           </mi> 
           <mi>
             Θ 
           </mi> 
          </msub> 
         </mrow> 
        </math></p></td> 
      <td class="custom-bottom-td acenter" width="28.68%"><p style="text-align:center">Mean dens/ 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <mn>
            200 
          </mn> 
          <msub> 
           <mi>
             ρ 
           </mi> 
           <mi>
             C 
           </mi> 
          </msub> 
         </mrow> 
        </math></p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="25.33%"><p style="text-align:center">NFW-total</p></td> 
      <td class="custom-top-td acenter" width="19.37%"><p style="text-align:center">238.6 kpc</p></td> 
      <td class="custom-top-td acenter" width="26.61%"><p style="text-align:center">1.546 × 10<sup>12</sup></p></td> 
      <td class="custom-top-td acenter" width="28.68%"><p style="text-align:center">0.999595</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="25.33%"><p style="text-align:center">By parameter 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msup> 
           <mi>
             a 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </math> </p></td> 
      <td class="acenter" width="19.37%"><p style="text-align:center">232.15</p></td> 
      <td class="acenter" width="26.61%"><p style="text-align:center">1.4245 × 10<sup>12</sup></p></td> 
      <td class="acenter" width="28.68%"><p style="text-align:center">0.999959</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="25.33%"><p style="text-align:center">Relative diff. %</p></td> 
      <td class="acenter" width="19.37%"><p style="text-align:center">2.7%</p></td> 
      <td class="acenter" width="26.61%"><p style="text-align:center">7.8%</p></td> 
      <td class="acenter" width="28.68%"><p style="text-align:center"></p></td> 
     </tr> 
    </table>
   </table-wrap>
   <sec id="s6_1">
    <title>6.1. Comparison between R<sub>200-TOTAL</sub> and M<sub>200-TOTAL</sub> Values Got by Direct Mass and NFW Total Mass. Test I</title>
    <p>In the framework of DMbQG theory was got the formulas</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mrow> 
           <mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mn>
              5 
            </mn> 
           </mrow> 
          </mrow> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               10 
             </mn> 
             <mo>
               ⋅ 
             </mo> 
             <mi>
               H 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              5 
            </mn> 
           </mrow> 
          </mrow> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (3.4) and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <msup> 
              <mi>
                a 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
            <mrow> 
             <mn>
               100 
             </mn> 
             <mo>
               ⋅ 
             </mo> 
             <msup> 
              <mi>
                H 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
           </mfrac> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            5 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (3.5) so using</p>
    <p>the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> for M31 = 2.235 × 10<sup>21</sup> m<sup>5/2</sup>∙s<sup>−2</sup>, see <xref ref-type="table" rid="table1">
      Table 1
     </xref>, it is possible to calculate rightly both values. In <xref ref-type="table" rid="table18">
      Table 18
     </xref> are summarized the value of R<sub>200-TOTAL</sub> and M<sub>200-TOTAL</sub> got by the two different methods and also it is shown its relative differences, which are very low.</p>
    <p>In <xref ref-type="table" rid="table18">
      Table 18
     </xref> are checked the mean density of the R<sub>200-TOTAL</sub> radius sphere got by the two different methods, and the matching versus 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math> is almost perfect for both.</p>
   </sec>
   <sec id="s6_2">
    <title>6.2. Calculus of Parameter a<sup>2</sup> Using M<sub>200-TOTAL</sub> Got by NFW. Test II</title>
    <p>Now using the value calculated for M<sub>200-TOTAL</sub> using the NFW-total procedure, it is possible to use such result to calculate the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> by the formula:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             G 
           </mi> 
           <mo>
             ⋅ 
           </mo> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            5 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            6 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             10 
           </mn> 
           <mo>
             ⋅ 
           </mo> 
           <mi>
             H 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            3 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> Formula (3.3)</p>
    <p>Then this result may be compared with the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> got in <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> (Abarca, M. 2024) in the framework of DMbQG theory.</p>
    <p>In <xref ref-type="table" rid="table19">
      Table 19
     </xref> are compared both results of parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> with an excellent result.</p>
    <table-wrap id="table19">
     <label>
      <xref ref-type="table" rid="table19">
       Table 19
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 19. Comparing the parameter 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math> for M31. Test II.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="43.43%"><p style="text-align:center">M<sub>200-TOTAL</sub> by NFW total</p></td> 
       <td class="custom-bottom-td acenter" width="27.89%"><p style="text-align:center">Parameter 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math></p></td> 
       <td class="custom-bottom-td acenter" width="28.68%"><p style="text-align:center">Relative difference</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="43.43%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="27.89%"><p style="text-align:center">m<sup>5/2</sup>s<sup>−2</sup></p></td> 
       <td class="custom-top-td acenter" width="28.68%"><p style="text-align:center">%</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="43.43%"><p style="text-align:center">1.546 × 10<sup>12</sup></p></td> 
       <td class="acenter" width="27.89%"><p style="text-align:center">2.393 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="28.68%"><p style="text-align:center">6.6</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="43.43%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> as reference. See <xref ref-type="table" rid="table1">
          Table 1
         </xref></p></td> 
       <td class="acenter" width="27.89%"><p style="text-align:center">2.235 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="28.68%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
   <sec id="s6_3">
    <title>6.3. Calculus of Parameter a<sup>2</sup> Using M<sub>200-TOTAL</sub> and R<sub>200-TOTAL</sub> Got by NFW. Test III</title>
    <p>In this test the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> is got by the formula 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            M 
          </mi> 
          <mrow> 
           <mn>
             200 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mrow> 
             <mn>
               200 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (3.2) using M<sub>200-TOTAL</sub> and R<sub>200-TOTAL</sub> got by the NFW-total method.</p>
    <p>The result of parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> in this test is the same that in the test II because the Formula (3.3) is mathematically equivalent to (3.2) in the framework of DMbQG theory. See <xref ref-type="table" rid="table20">
      Table 20
     </xref>.</p>
    <table-wrap id="table20">
     <label>
      <xref ref-type="table" rid="table20">
       Table 20
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 20. Comparing the parameter 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math> for M31. Test III.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="17.24%"><p style="text-align:center">NFW-total</p></td> 
       <td class="custom-bottom-td acenter" width="18.52%"><p style="text-align:center">R<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="21.72%"><p style="text-align:center">M<sub>200-TOTAL</sub></p></td> 
       <td class="custom-bottom-td acenter" width="25.55%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> Formula (3.2)</p></td> 
       <td class="custom-bottom-td acenter" width="16.97%"><p style="text-align:center">Relative diff.</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="17.24%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="18.52%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-top-td acenter" width="21.72%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="25.55%"><p style="text-align:center">m<sup>5/2</sup>s<sup>−2</sup></p></td> 
       <td class="custom-top-td acenter" width="16.97%"><p style="text-align:center">%</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="17.24%"><p style="text-align:center"></p></td> 
       <td class="acenter" width="18.52%"><p style="text-align:center">238.6 kpc</p></td> 
       <td class="acenter" width="21.72%"><p style="text-align:center">1.546 × 10<sup>12</sup></p></td> 
       <td class="acenter" width="25.55%"><p style="text-align:center">2.393 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">6.6</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="57.48%" colspan="3"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> as reference. See <xref ref-type="table" rid="table1">
          Table 1
         </xref></p></td> 
       <td class="acenter" width="25.55%"><p style="text-align:center">2.235 × 10<sup>21</sup></p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
   <sec id="s6_4">
    <title>6.4. Comparison of Direct Mass Formula with the NFW-Total Mass Formula into the Halo Region up to R<sub>200-TOTAL</sub>. Test IV</title>
    <p>As it was shown in the Epigraph 5.4 to compare both formulas of the masses is enough to compare the called dimensionless function factor of masses.</p>
    <p>
     <xref ref-type="table" rid="table21">
      Table 21
     </xref> is right to define the NFW function mass and his dimensionless function factor mass associated whose formula is:</p>
    <table-wrap id="table21">
     <label>
      <xref ref-type="table" rid="table21">
       Table 21
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 21. NFW parameters for the dimensionless function factor mass.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="25.55%"><p style="text-align:center">Using NFW-Sofue data</p></td> 
       <td class="custom-bottom-td acenter" width="18.95%"><p style="text-align:center">R<sub>0</sub></p><p style="text-align:center">Radius scale</p></td> 
       <td class="custom-bottom-td acenter" width="17.03%"><p style="text-align:center">R<sub>200-TOTAL</sub></p><p style="text-align:center">NFW-total</p></td> 
       <td class="custom-bottom-td acenter" width="17.45%"><p style="text-align:center">K<sub>NFW</sub></p></td> 
       <td class="custom-bottom-td acenter" width="21.02%"><p style="text-align:center">f<sub>BA</sub> = M<sub>BA</sub>/K<sub>NFW</sub></p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="25.55%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="18.95%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-top-td acenter" width="17.03%"><p style="text-align:center">kpc</p></td> 
       <td class="custom-top-td acenter" width="17.45%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="21.02%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="25.55%"><p style="text-align:center"></p></td> 
       <td class="acenter" width="18.95%"><p style="text-align:center">34.6</p></td> 
       <td class="acenter" width="17.03%"><p style="text-align:center">238.6</p></td> 
       <td class="acenter" width="17.45%"><p style="text-align:center">1.16 × 10<sup>12</sup></p></td> 
       <td class="acenter" width="21.02%"><p style="text-align:center">0.14</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> Being 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         x 
       </mi> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mi>
          r 
        </mi> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> Formula (5.5)</p>
    <p>The data of this table were calculated at the beginning of Chapter 6.</p>
    <p>By other side, the dimensionless function factor direct mass formula is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <msubsup> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mtext>
           TOTAL 
         </mtext> 
        </mrow> 
        <mrow> 
         <mtext>
           DIRECT 
         </mtext> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mo>
           &lt; 
         </mo> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
      </mrow> 
     </math> Formula (5.4)</p>
    <p>Being x = r/R<sub>0</sub> being f<sub>T</sub> = K<sub>T</sub>/K<sub>NFW</sub> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
      </mrow> 
     </math>.</p>
    <p>Being 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 2.235 × 10<sup>21</sup> and R<sub>0</sub> = 34.6 kpc then 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         5.5 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and f<sub>T</sub> = 0.474.</p>
    <p>With these parameters the dimensionless function factor of direct mass is defined.</p>
    <p>As the radius dominion is from 40 kpc up to 240 kpc the variable x ranges from 1.2 up to 6.9.</p>
    <p>In <xref ref-type="table" rid="table22">
      Table 22
     </xref> are tabulated both functions into its dominion and its relative difference, that for x bigger than 2 its relative difference is under 15%.</p>
    <table-wrap id="table22">
     <label>
      <xref ref-type="table" rid="table22">
       Table 22
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 22. Direct mass factor function versus NFW-total mass factor function. M31.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="14.90%"><p style="text-align:center">Radius</p><p style="text-align:center">kpc</p></td> 
       <td class="custom-bottom-td acenter" width="12.99%"><p style="text-align:center">Variable</p><p style="text-align:center">X</p></td> 
       <td class="custom-bottom-td acenter" width="28.32%"><p style="text-align:center">Dimensionless Factor Direct mass</p></td> 
       <td class="custom-bottom-td acenter" width="26.82%"><p style="text-align:center">Dimensionless factor NFW-total mass</p></td> 
       <td class="custom-bottom-td acenter" width="16.97%"><p style="text-align:center">Relative diff.</p><p style="text-align:center">%</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="14.90%"><p style="text-align:center">41.52</p></td> 
       <td class="custom-top-td acenter" width="12.99%"><p style="text-align:center">1.2</p></td> 
       <td class="custom-top-td acenter" width="28.32%"><p style="text-align:center">0.51924</p></td> 
       <td class="custom-top-td acenter" width="26.82%"><p style="text-align:center">0.38300</p></td> 
       <td class="custom-top-td acenter" width="16.97%"><p style="text-align:center">26.238</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">48.44</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">1.4</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">0.56084</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">0.43214</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">22.949</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">55.36</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">1.6</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">0.59957</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">0.48013</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">19.921</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">62.28</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">1.8</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">0.63594</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">0.52676</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">17.168</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">69.2</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">2</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">0.67034</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">0.57195</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">14.678</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">103.8</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">3</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">0.82099</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">0.77629</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">5.444</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">138.4</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">4</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">0.94800</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">0.94944</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">−0.152</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">173</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">5</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">1.05990</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">1.09843</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">−3.635</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">207.6</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">6</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">1.16106</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">1.22877</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">−5.832</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.90%"><p style="text-align:center">242.2</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">7</p></td> 
       <td class="acenter" width="28.32%"><p style="text-align:center">1.25409</p></td> 
       <td class="acenter" width="26.82%"><p style="text-align:center">1.34444</p></td> 
       <td class="acenter" width="16.97%"><p style="text-align:center">−7.205</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>In <xref ref-type="fig" rid="fig3">
      Figure 3
     </xref> it is shown how close both functions are into its dominion.</p>
    <fig id="fig3" position="float">
     <label>Figure 3</label>
     <caption>
      <title>Figure 3. Function factor of direct mass vs function factor of NFW-total mass for M31.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181303-rId408.jpeg?20250730102938" />
    </fig>
    <p>In <xref ref-type="table" rid="table23">
      Table 23
     </xref> both functions are tabulated from 40 kpc up to 1380 kpc to show how in this dominion so wide, the relative difference remain negligible.</p>
    <table-wrap id="table23">
     <label>
      <xref ref-type="table" rid="table23">
       Table 23
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 23. Direct mass factor function versus NFW-total mass factor function. M31.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="14.91%"><p style="text-align:center">Radius</p><p style="text-align:center">kpc</p></td> 
       <td class="custom-bottom-td acenter" width="12.99%"><p style="text-align:center">Variable</p><p style="text-align:center">X</p></td> 
       <td class="custom-bottom-td acenter" width="28.75%"><p style="text-align:center">Dimensionless Factor Direct mass</p></td> 
       <td class="custom-bottom-td acenter" width="27.47%"><p style="text-align:center">Dimensionless factor NFW-total mass</p></td> 
       <td class="custom-bottom-td acenter" width="15.90%"><p style="text-align:center">Relat. Diff</p><p style="text-align:center">%</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="14.91%"><p style="text-align:center">41.52</p></td> 
       <td class="custom-top-td acenter" width="12.99%"><p style="text-align:center">1.2</p></td> 
       <td class="custom-top-td acenter" width="28.75%"><p style="text-align:center">0.5192</p></td> 
       <td class="custom-top-td acenter" width="27.47%"><p style="text-align:center">0.3830</p></td> 
       <td class="custom-top-td acenter" width="15.90%"><p style="text-align:center">26.24</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">51.9</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">1.5</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">0.5805</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">0.4563</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">21.40</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">69.2</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">2</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">0.6703</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">0.5719</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">14.68</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">86.5</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">2.5</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">0.7495</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">0.6785</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">9.47</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">138.4</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">4</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">0.9480</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">0.9494</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−0.15</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">207.6</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">6</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">1.1611</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">1.2288</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−5.83</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">276.8</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">8</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">1.3407</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">1.4483</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−8.03</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">415.2</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">12</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">1.6420</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">1.7819</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−8.52</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">588.2</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">17</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">1.9544</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">2.0859</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−6.73</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">761.2</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">22</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">2.2233</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">2.3190</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−4.31</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">899.6</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">26</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">2.4169</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">2.4729</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−2.31</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">1038</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">30</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">2.5962</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">2.6062</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">−0.39</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">1211</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">35</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">2.8042</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">2.7513</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">1.89</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="14.91%"><p style="text-align:center">1384</p></td> 
       <td class="acenter" width="12.99%"><p style="text-align:center">40</p></td> 
       <td class="acenter" width="28.75%"><p style="text-align:center">2.9978</p></td> 
       <td class="acenter" width="27.47%"><p style="text-align:center">2.8780</p></td> 
       <td class="acenter" width="15.90%"><p style="text-align:center">4.00</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>In <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref> is plotted <xref ref-type="table" rid="table23">
      Table 23
     </xref> and it is shown how close both functions are into a dominion so wide.</p>
    <p>According the DMbQG theory the DM grows with the square root of radius without limit. In <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> (Abarca, M. 2024), was demonstrated that the halo of the L. G. is about 2 Mpc, so it is right to study these functions in this wide dominion.</p>
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>Figure 4. Function factor of direct mass vs function factor of NFW-total mass for M31.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181303-rId409.jpeg?20250730102938" />
    </fig>
   </sec>
  </sec><sec id="s7">
   <title>7. Relation between NFW Mass Formula Parameters and the Direct Mass Parameter a<sup>2</sup></title>
   <p>In this epigraph will be developed a procedure to calculate the parameter 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         a 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math> associated to direct mass using the parameters associated to NFW total mass formula and reciprocally another procedure to calculate the parameters associated to NFW DM mass formula using the parameter 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         a 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math>. This study will be made in the MW and M31 galaxies.</p>
   <sec id="s7_1">
    <title>7.1. Milky Way Case</title>
    <p>In <xref ref-type="table" rid="table4">
      Table 4
     </xref> are shown the NFW parameters published by <xref ref-type="bibr" rid="scirp.144431-9">
      [9]
     </xref> Karukes and in the Epigraph 4.2 were calculated some parameters associated: K<sub>NFW</sub>, f<sub>BA</sub> the baryonic fraction, R<sub>0</sub> the scale radius and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> the characteristic density.</p>
    <p>By other side in <xref ref-type="table" rid="table1">
      Table 1
     </xref> is shown the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> associated to the direct mass for MW, published in <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> Abarca. In the epigraph 5.4.2 is calculated the parameter K<sub>T</sub> and f<sub>T</sub> both used to link the direct mass with the NFW total mass.</p>
    <p>In <xref ref-type="table" rid="table24">
      Table 24
     </xref> are collected all the parameters used in this epigraph.</p>
    <table-wrap id="table24">
     <label>
      <xref ref-type="table" rid="table24">
       Table 24
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 24. Parameters of MW linked to NFW total mass and Direct mass formulas.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="9.64%"><p style="text-align:center">NFW</p></td> 
       <td class="acenter" width="27.32%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              K 
            </mi> 
            <mrow> 
             <mi>
               N 
             </mi> 
             <mi>
               F 
             </mi> 
             <mi>
               W 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             4.0572269 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="16.36%"><p style="text-align:center">f<sub>BA</sub> = 0.147884</p></td> 
       <td class="acenter" width="26.68%"><p style="text-align:center">R<sub>0</sub> = 10.158 kpc</p></td> 
       <td class="acenter" width="20.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             2.0864 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               21 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p><p style="text-align:center">kg/m<sup>3</sup> units.</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="9.64%"><p style="text-align:center">Direct</p></td> 
       <td class="acenter" width="27.32%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> = 1.527 × 10<sup>21</sup> m<sup>5/2</sup>s<sup>−2</sup></p></td> 
       <td class="acenter" width="16.36%"><p style="text-align:center">f<sub>T</sub> = 0.50178</p></td> 
       <td class="acenter" width="26.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              K 
            </mi> 
            <mi>
              T 
            </mi> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             2.0358395 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="20.00%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>With the previous parameters is possible to do an equation of the dimensionless function factor linked to the direct mass and the NFW total mass. By equation the Formulas (5.4) and (5.5) are got the x values where both functions match mathematically, see Formula (7.1).</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         + 
       </mo> 
       <mi>
         ln 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           x 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mi>
          x 
        </mi> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           x 
         </mi> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (7.1)</p>
    <p>This equation is quite easy to solve numerically and its solutions are:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.09126639 
       </mn> 
      </mrow> 
     </math>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         5.6428337 
       </mn> 
      </mrow> 
     </math> and 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mn>
          3 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         19.6232587 
       </mn> 
      </mrow> 
     </math></p>
    <p>It is clear that the direct mass and the NFW total mass are functions very similar throughout its dominion, as it was shown in <xref ref-type="fig" rid="fig2">
      Figure 2
     </xref>.</p>
    <p>The value X<sub>2</sub> is used to search a relation between parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> and the parameters 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> and R<sub>0</sub>.</p>
    <p>The value X<sub>1</sub> has been rejected because does not belong to the halo. In addition the value X<sub>2</sub> is placed in the intermediate region of NFW total mass function dominion. As R<sub>0</sub> = 10.16 kpc then X<sub>2</sub> is equivalent to 57 kpc.</p>
    <p>Firstly will be equated the direct mass Formula (5.2) and NFW total mass Formula (4.10) at the point x = x<sub>2</sub> getting the Equation (7.2) in order to calculate the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math>.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mrow> 
         <msub> 
          <mi>
            x 
          </mi> 
          <mn>
            2 
          </mn> 
         </msub> 
        </mrow> 
       </msqrt> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              x 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <mn>
         4 
       </mn> 
       <mi>
         π 
       </mi> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
        <mn>
          3 
        </mn> 
       </msubsup> 
      </mrow> 
     </math> (7.2)</p>
    <p>And clearing up the parameter</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mn>
         1.1919608 
       </mn> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mrow> 
            <mn>
              5 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </mrow> 
         </msubsup> 
        </mrow> 
        <mrow> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              x 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
       </mfrac> 
       <mo>
         ≈ 
       </mo> 
       <mn>
         2.007 
       </mn> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         π 
       </mtext> 
       <mi>
         G 
       </mi> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
        <mrow> 
         <mrow> 
          <mn>
            5 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msubsup> 
      </mrow> 
     </math> (7.3)</p>
    <p>As x<sub>2</sub> = 5.64283367, f<sub>BA</sub> + f(x<sub>2</sub>) = 1.1919608 and using the other values of parameters of <xref ref-type="table" rid="table24">
      Table 24
     </xref> is got 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.527 × 10<sup>21</sup> that match mathematically with the value of parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> of MW, see <xref ref-type="table" rid="table1">
      Table 1
     </xref>.</p>
    <p>This way, using the parameters of NFW total mass formula may be got the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> associated to the direct mass formula.</p>
    <p>The next challenge is the reciprocal problem which is not so easy because the NFW DM mass formula has two parameters whereas the direct mass has only one.</p>
    <p>From Equation (7.2) is cleared up the characteristic density, see Formula (7.4)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              x 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mrow> 
            <mn>
              5 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </mrow> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              f 
            </mi> 
            <mrow> 
             <mi>
               B 
             </mi> 
             <mi>
               A 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             + 
           </mo> 
           <mi>
             f 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                x 
              </mi> 
              <mn>
                2 
              </mn> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (7.4)</p>
    <p>The problem is that the scale radius R<sub>0</sub> is a parameter belonging to NFW DM formula. Namely its value in <xref ref-type="table" rid="table24">
      Table 24
     </xref> is R<sub>0</sub> = 10.16 kpc. In the framework of DMbQG, now it will be considered R<sub>0</sub> = 30 kpc because in <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> Abarca was estimated that such radius may be the halo border where the baryonic mass density versus DM density is negligible.</p>
    <p>In this epigraph will be calculated the virial mass M<sub>200</sub> and R<sub>200</sub> using such radius and will be shown that the relative difference versus Karukes data, see <xref ref-type="table" rid="table8">
      Table 8
     </xref>, is negligible despite the fact that the value considered now for R<sub>0</sub> is three times bigger i.e. 300% bigger.</p>
    <p>In the Formula (7.4) is used the values 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.527 × 10<sup>21</sup>, f<sub>BA</sub> + f(x<sub>2</sub>) = 1.1919608, x<sub>2</sub> = 5.6428337 and the novelty is to consider R<sub>0</sub> = 30 kpc and then it is got 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.3918977 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> kg/m<sup>3</sup>. With that density and R<sub>0</sub> = 30 kpc it is got rightly 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         6.9725 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>It is clear that the values, density and K<sub>NFW</sub> are very different to the same parameters shown in <xref ref-type="table" rid="table24">
      Table 24
     </xref>. However when it is calculated the new parameter c then the virial mass and the radius will be very similar to the same concepts calculated by Karukes, and showed in <xref ref-type="table" rid="table8">
      Table 8
     </xref> because the new parameter c now will be about three times lower.</p>
    <p>The Formula (4.7) 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         226.80343 
       </mn> 
      </mrow> 
     </math> allows to calculate the new</p>
    <p>parameter c knowing the new density. This equation is right to solve numerically and its solution is c = 6.35435 and f(c) = 1.1312659.</p>
    <p>By (4.6) R<sub>200</sub> = R<sub>0</sub>·c so R<sub>200</sub> = 30·c = 190.63 kpc and</p>
    <p>By (4.5) 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         7.8878 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>In <xref ref-type="table" rid="table25">
      Table 25
     </xref> are compared the new virial mass and radius with the Karukes ones.</p>
    <table-wrap id="table25">
     <label>
      <xref ref-type="table" rid="table25">
       Table 25
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 25. Karukes virial mass and radius versus the new ones by parameter 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math>.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="19.37%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="34.49%"><p style="text-align:center">Karukes data. See <xref ref-type="table" rid="table8">
          Table 8
         </xref></p></td> 
       <td class="custom-bottom-td acenter" width="28.74%"><p style="text-align:center">New Virial values</p></td> 
       <td class="custom-bottom-td acenter" width="17.40%"><p style="text-align:center">Relative diff.</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="19.37%"><p style="text-align:center">R<sub>200</sub></p></td> 
       <td class="custom-top-td acenter" width="34.49%"><p style="text-align:center">193 kpc</p></td> 
       <td class="custom-top-td acenter" width="28.74%"><p style="text-align:center">190.63 kpc</p></td> 
       <td class="custom-top-td acenter" width="17.40%"><p style="text-align:center">1.2%</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.37%"><p style="text-align:center">M<sub>200</sub></p></td> 
       <td class="acenter" width="34.49%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             8.3 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="28.74%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             7.8878 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="17.40%"><p style="text-align:center">5 %</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="19.37%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML" display="inline"> <mrow> 
           <mrow> 
            <mrow> 
             <mover accent="true"> 
              <mrow> 
               <mtext>
                 Den 
               </mtext> 
              </mrow> 
              <mo stretchy="true">
                ¯ 
              </mo> 
             </mover> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mrow> 
             <mn>
               200 
             </mn> 
             <msub> 
              <mi>
                ρ 
              </mi> 
              <mi>
                C 
              </mi> 
             </msub> 
            </mrow> 
           </mrow> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="34.49%"><p style="text-align:center">1.01398</p></td> 
       <td class="acenter" width="28.74%"><p style="text-align:center">1.000015</p></td> 
       <td class="acenter" width="17.40%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>In the last row are shown the ratios: the mean density of the sphere R<sub>200</sub> versus 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>To illustrate how stable the virial mass and radius are regarding the parameter R<sub>0</sub>, now will be remake the virial data using R<sub>0</sub> = 20 kpc.</p>
    <p>Using Formula (7.4) now 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         3.835619 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> and K<sub>NFW</sub> = 5.69303 × 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>Now the Formula (4.7) 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         624.9968 
       </mn> 
      </mrow> 
     </math> whose solution is c = 9.709302 and f(c) = 1.4644895 and finally:</p>
    <p>By (4.6) R<sub>200</sub> = R<sub>0</sub>·c so R<sub>200</sub> = 20·c = 194.186 kpc.</p>
    <p>By (4.5) 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mo>
           − 
         </mo> 
         <mi>
           D 
         </mi> 
         <mi>
           M 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mi>
           N 
         </mi> 
         <mi>
           F 
         </mi> 
         <mi>
           W 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         8.3374 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and the ratio 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mrow> 
         <mover accent="true"> 
          <mrow> 
           <mtext>
             Den 
           </mtext> 
          </mrow> 
          <mo stretchy="true">
            ¯ 
          </mo> 
         </mover> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mi>
            C 
          </mi> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> = 1.0000006.</p>
    <p>These results show that the election of parameter R<sub>0</sub> is quite flexible in the procedure used in this section.</p>
   </sec>
   <sec id="s7_2">
    <title>7.2. M31 Case</title>
    <p>In <xref ref-type="table" rid="table17">
      Table 17
     </xref> are shown the NFW parameters published by <xref ref-type="bibr" rid="scirp.144431-2">
      [2]
     </xref> Sofue and in the Chapter 6 were calculated some parameters associated: K<sub>NFW</sub> and f<sub>BA</sub>, the baryonic fraction.</p>
    <p>By other side in <xref ref-type="table" rid="table1">
      Table 1
     </xref> is shown the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> associated to the direct mass for M31, published in <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> Abarca. In the Epigraph 6.4 is calculated the parameter K<sub>T</sub> and f<sub>T</sub> both used to link the direct mass with the NFW total mass.</p>
    <p>In <xref ref-type="table" rid="table26">
      Table 26
     </xref> are collected all the parameters used in this epigraph.</p>
    <table-wrap id="table26">
     <label>
      <xref ref-type="table" rid="table26">
       Table 26
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 26. Parameters of M31 linked to NFW total mass and Direct mass formulas.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="10.64%"><p style="text-align:center">NFW</p></td> 
       <td class="acenter" width="29.36%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              K 
            </mi> 
            <mrow> 
             <mtext>
               NFW 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             1.16 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="15.56%"><p style="text-align:center">f<sub>BA</sub> = 0.14</p></td> 
       <td class="acenter" width="24.44%"><p style="text-align:center">R<sub>0</sub> = 34.6 kpc</p></td> 
       <td class="acenter" width="20.00%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             1.51 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               22 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p><p style="text-align:center">kg/m<sup>3</sup> units.</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="10.64%"><p style="text-align:center">Direct</p></td> 
       <td class="acenter" width="29.36%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msup> 
            <mi>
              a 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </math> = 2.235 × 10<sup>21</sup> m<sup>5/2</sup>s<sup>−2</sup></p></td> 
       <td class="acenter" width="15.56%"><p style="text-align:center">f<sub>T</sub> = 0.474</p></td> 
       <td class="acenter" width="24.44%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              K 
            </mi> 
            <mi>
              T 
            </mi> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             5.5 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="20.00%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>With the previous parameters is possible to do an equation of the dimensionless function factor linked to the direct mass and the NFW total mass. By equation the Formulas (5.4) and (5.5) are got the x values where both functions match mathematically, see Formula (7.5).</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mi>
          x 
        </mi> 
       </msqrt> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mi>
           B 
         </mi> 
         <mi>
           A 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         + 
       </mo> 
       <mi>
         ln 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           x 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mi>
          x 
        </mi> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mi>
           x 
         </mi> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (7.5)</p>
    <p>This equation is quite easy to solve numerically and its solutions are:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0.091984 
       </mn> 
      </mrow> 
     </math>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         3.96548 
       </mn> 
      </mrow> 
     </math> and 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mn>
          3 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         30.826 
       </mn> 
      </mrow> 
     </math></p>
    <p>It is clear that the direct mass and the NFW total mass are functions very similar throughout its dominion, as it was shown in <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref>.</p>
    <p>The value X<sub>2</sub> is used to search a relation between parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> and parameters 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> and R<sub>0</sub>.</p>
    <p>The value X<sub>1</sub> has been rejected because does not belong to the halo. In addition the value X<sub>2</sub> is placed in the intermediate region of NFW total mass function dominion. As R<sub>0</sub> = 34.6 kpc then X<sub>2</sub> is equivalent to 137 kpc.</p>
    <p>Firstly will be equated the direct mass Formula (5.2) and the NFW total mass Formula (4.10) at the point x = x<sub>2</sub> getting the Equation (7.6) in order to calculate 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math>.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mi>
          G 
        </mi> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <msqrt> 
        <mrow> 
         <msub> 
          <mi>
            x 
          </mi> 
          <mn>
            2 
          </mn> 
         </msub> 
        </mrow> 
       </msqrt> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            f 
          </mi> 
          <mrow> 
           <mi>
             B 
           </mi> 
           <mi>
             A 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              x 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <mn>
         4 
       </mn> 
       <mi>
         π 
       </mi> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
        <mn>
          3 
        </mn> 
       </msubsup> 
      </mrow> 
     </math> (7.6)</p>
    <p>And clearing up the parameter</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mn>
         0.9439 
       </mn> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mrow> 
            <mn>
              5 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </mrow> 
         </msubsup> 
        </mrow> 
        <mrow> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              x 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
       </mfrac> 
       <mo>
         ≈ 
       </mo> 
       <mn>
         1.896 
       </mn> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         π 
       </mi> 
       <mi>
         G 
       </mi> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
        <mrow> 
         <mrow> 
          <mn>
            5 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msubsup> 
      </mrow> 
     </math> (7.7)</p>
    <p>As x<sub>2</sub> = 3.96548, f<sub>BA</sub> + f(x<sub>2</sub>) = 0.9439 and using the other values of parameters of <xref ref-type="table" rid="table26">
      Table 26
     </xref> is got 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 2.235 × 10<sup>21</sup> that matches with the value of parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> of M31, see <xref ref-type="table" rid="table1">
      Table 1
     </xref>.</p>
    <p>This way, using the parameters of NFW total mass formula may be got the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> associated to direct mass formula.</p>
    <p>The next challenge is the reciprocal problem which is not so easy because the NFW DM mass formula has two parameters whereas the direct mass has only one.</p>
    <p>From Equation (7.6) is cleared up the characteristic density, see Formula (7.8)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            a 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <msqrt> 
          <mrow> 
           <msub> 
            <mi>
              x 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
          </mrow> 
         </msqrt> 
        </mrow> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msubsup> 
          <mi>
            R 
          </mi> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mrow> 
            <mn>
              5 
            </mn> 
            <mo>
              / 
            </mo> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </mrow> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              f 
            </mi> 
            <mrow> 
             <mi>
               B 
             </mi> 
             <mi>
               A 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             + 
           </mo> 
           <mi>
             f 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                x 
              </mi> 
              <mn>
                2 
              </mn> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (7.8)</p>
    <p>The problem is that the scale radius R<sub>0</sub> is a parameter belonging to NFW DM formula. Namely its value in <xref ref-type="table" rid="table26">
      Table 26
     </xref> is R<sub>0</sub> = 34.6 kpc. However, in the framework of DMbQG will be considered R<sub>0</sub> = 40 kpc because in <xref ref-type="bibr" rid="scirp.144431-1">
      [1]
     </xref> Abarca was estimated that such radius may be the halo border where the baryonic mass density versus DM density is negligible.</p>
    <p>In this epigraph will be calculated the virial mass M<sub>200</sub> and R<sub>200</sub> using such radius and it will be shown that the relative difference versus the Sofue data, see the Chapter 6, is negligible.</p>
    <p>In the Formula (7.8) are used the values 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 2.235 × 10<sup>21</sup>, f<sub>BA</sub> + f(x<sub>2</sub>) = 0.9439, x<sub>2</sub> = 3.96548 and the novelty is to consider R<sub>0</sub> = 40 kpc and then it is got 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mtext> 
       </mtext> 
       <mo>
         = 
       </mo> 
      </mrow> 
     </math> 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1.0506 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> kg/m<sup>3</sup> Using this value got for density and R<sub>0</sub> = 40 kpc it is got rightly 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.2475 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           12 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>It is clear that the values, density and K<sub>NFW</sub> are lightly different to the same parameters shown in <xref ref-type="table" rid="table26">
      Table 26
     </xref>. However when it is calculated the new parameter c then the virial mass and the radius will be very similar to the same concepts calculated at the beginning of Chapter 6 because the new parameter c now is lightly lower.</p>
    <p>The Formula (4.7) 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         171.19 
       </mn> 
      </mrow> 
     </math> allows to calculate the new parameter c knowing the new density, this equation is right to solve numerically and its solution is c = 5.63 and f(c) = 1.0424.</p>
    <p>By (4.6) R<sub>200</sub> = R<sub>0</sub>·c so R<sub>200</sub> = 40·c = 225.2 kpc and</p>
    <p>By (4.5) 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         1.3 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           12 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>In <xref ref-type="table" rid="table27">
      Table 27
     </xref> are compared the new virial mass and radius with the Sofue ones.</p>
    <table-wrap id="table27">
     <label>
      <xref ref-type="table" rid="table27">
       Table 27
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 27. Sofue Virial mass and Radius versus the new ones by parameter 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <msup> 
   
          <mi>
           
    a
   
          </mi> 
   
          <mn>
           
    2
   
          </mn> 
  
         </msup> 
 
        </mrow>

       </math>.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="20.23%"><p style="text-align:center"></p></td> 
       <td class="custom-bottom-td acenter" width="27.46%"><p style="text-align:center">Sofue. See Chapter 6</p></td> 
       <td class="custom-bottom-td acenter" width="27.31%"><p style="text-align:center">New Virial values</p></td> 
       <td class="custom-bottom-td acenter" width="25.00%"><p style="text-align:center">Relative difference</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="20.23%"><p style="text-align:center">R<sub>200</sub></p></td> 
       <td class="custom-top-td acenter" width="27.46%"><p style="text-align:center">227.66 kpc</p></td> 
       <td class="custom-top-td acenter" width="27.31%"><p style="text-align:center">225.2 kpc</p></td> 
       <td class="custom-top-td acenter" width="25.00%"><p style="text-align:center">1%</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="20.23%"><p style="text-align:center">M<sub>200</sub></p></td> 
       <td class="acenter" width="27.46%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             1.34 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.31%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mn>
             1.3 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="25.00%"><p style="text-align:center">3%</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="20.23%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML" display="inline"> <mrow> 
           <mrow> 
            <mrow> 
             <mover accent="true"> 
              <mrow> 
               <mtext>
                 Den 
               </mtext> 
              </mrow> 
              <mo stretchy="true">
                ¯ 
              </mo> 
             </mover> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mrow> 
             <mn>
               200 
             </mn> 
             <msub> 
              <mi>
                ρ 
              </mi> 
              <mi>
                C 
              </mi> 
             </msub> 
            </mrow> 
           </mrow> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.46%"><p style="text-align:center">0.997399</p></td> 
       <td class="acenter" width="27.31%"><p style="text-align:center">0.999684</p></td> 
       <td class="acenter" width="25.00%"><p style="text-align:center"></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>In the last row are shown the ratios between the mean density of the sphere R<sub>200</sub> versus 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math>. Notice how the new virial values give an excellent approximation to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         200 
       </mn> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math>.</p>
    <p>To illustrate how stable the virial mass and radius are regarding the parameter R<sub>0</sub>, now will be remake the virial data using R<sub>0</sub> = 30 kpc instead of 40 kpc.</p>
    <p>Using the Formula (7.8) now with R<sub>0</sub> = 30 kpc it is right to get 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mtext> 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mtext> 
       </mtext> 
       <mn>
         2.1566568 
       </mn> 
      </mrow> 
     </math> 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> kg/m<sup>3</sup> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.08035 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           12 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>The Formula (4.7) becomes 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           G 
         </mi> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mn>
           100 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            H 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         351.4175 
       </mn> 
      </mrow> 
     </math> and the new solution for the parameter c is c = 7.647964 and f(c) = 1.272958.</p>
    <p>By (4.6) R<sub>200</sub> = R<sub>0</sub>·c so R<sub>200</sub> = 30·c = 229.439 kpc and</p>
    <p>By (4.5) 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -DM 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          K 
        </mi> 
        <mrow> 
         <mtext>
           NFW 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         f 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         1.375 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           12 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>The ratio 
     <math xmlns="http://www.w3.org/1998/Math/MathML" display="inline"> <mrow> 
       <mrow> 
        <mrow> 
         <mover accent="true"> 
          <mrow> 
           <mtext>
             Den 
           </mtext> 
          </mrow> 
          <mo stretchy="true">
            ¯ 
          </mo> 
         </mover> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <msub> 
          <mi>
            ρ 
          </mi> 
          <mi>
            C 
          </mi> 
         </msub> 
        </mrow> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         1.0000027 
       </mn> 
      </mrow> 
     </math> which is an excellent result.</p>
    <p>As it was expected the new virial data are very similar to the ones shown in <xref ref-type="table" rid="table27">
      Table 27
     </xref>, so it has been demonstrated that the virial data are very stable regarding the R<sub>0</sub> considered in the procedure followed to calculate the virial mass and radius using the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> as initial data.</p>
    <p>In the previous study made for MW the results were even more spectacular because that time the value for R<sub>0</sub> was 300% bigger and the new virial mass and radius have a relative difference of 1% and 4.5% respectively. See <xref ref-type="table" rid="table25">
      Table 25
     </xref>.</p>
   </sec>
   <sec id="s7_3">
    <title>7.3. An Approximate Formula for the Parameter a<sup>2</sup></title>
    <p>The Formulas (7.3) for MW galaxy and (7.7) for M31 galaxy may be approximated with accuracy by the formula</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         ≈ 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         π 
       </mi> 
       <mi>
         G 
       </mi> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msubsup> 
        <mi>
          R 
        </mi> 
        <mn>
          0 
        </mn> 
        <mrow> 
         <mrow> 
          <mn>
            5 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msubsup> 
      </mrow> 
     </math> (7.9)</p>
    <p>This is a simple formula to link the direct mass parameter with the NFW parameters.</p>
    <p>In order to check such formula will be used the data from three different authors.</p>
    <p>The first one is <xref ref-type="bibr" rid="scirp.144431-10">
      [10]
     </xref> Ou, Necib et al. In this paper is published the MW virial data and the gNFW parameters for the rotation curve (<xref ref-type="table" rid="table28">
      Table 28
     </xref>).</p>
    <table-wrap id="table28">
     <label>
      <xref ref-type="table" rid="table28">
       Table 28
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 28. MW data—Xiaowei Ou et al. (2025) page 15.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="29.38%"><p style="text-align:center">Virial data</p></td> 
       <td class="acenter" width="43.43%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mtext>
               VIR 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               7.32 
             </mn> 
             <mo>
               ± 
             </mo> 
             <mn>
               1.5 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.19%"><p style="text-align:center">R<sub>VIR</sub> = 190 ± 15 kpc </p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="29.38%"><p style="text-align:center">NFW</p></td> 
       <td class="acenter" width="43.43%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             3.73 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.19%"><p style="text-align:center">R<sub>0</sub> = 10.42 kpc.</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Through the normalization mass M<sub>0</sub> may be got the characteristic density 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.78 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msup> 
       <mrow> 
        <mrow> 
         <mtext>
           kg 
         </mtext> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msup> 
          <mtext>
            m 
          </mtext> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math>.</p>
    <p>Knowing the scale radius R<sub>0</sub> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>, using the Formula (7.9) it is possible to calculate rightly the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.38 × 10<sup>21</sup> m<sup>5/2</sup>/s<sup>2</sup> and using such value into the Formulas (3.4) and (3.5) it is got rightly the 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         8 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and R<sub>200-</sub><sub>TOTAL</sub> = 191.6 kpc. Both values match fully with the values published in <xref ref-type="bibr" rid="scirp.144431-10">
      [10]
     </xref> if it is considered the range of errors.</p>
    <p>These virial data results show that (7.9) is a good approximation for the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math>.</p>
    <p>A second test may be done with the MW data published by <xref ref-type="bibr" rid="scirp.144431-11">
      [11]
     </xref> (Labini 2024) (<xref ref-type="table" rid="table29">
      Table 29
     </xref>).</p>
    <table-wrap id="table29">
     <label>
      <xref ref-type="table" rid="table29">
       Table 29
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 29. MW data—Labini, F. S. (2024) page 13 and 14.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="29.17%"><p style="text-align:center">Virial data</p></td> 
       <td class="acenter" width="43.43%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mtext>
               VIR 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               6.5 
             </mn> 
             <mo>
               ± 
             </mo> 
             <mn>
               0.5 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               11 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.40%"><p style="text-align:center">R<sub>VIR</sub>—Not published</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="29.17%"><p style="text-align:center">NFW</p></td> 
       <td class="acenter" width="43.43%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ρ 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             9.4 
           </mn> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               22 
             </mn> 
            </mrow> 
           </msup> 
           <mrow> 
            <mrow> 
             <mtext>
               kg 
             </mtext> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mrow> 
             <msup> 
              <mtext>
                m 
              </mtext> 
              <mn>
                3 
              </mn> 
             </msup> 
            </mrow> 
           </mrow> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="27.40%"><p style="text-align:center">R<sub>0</sub> = 12.5 kpc.</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>By the Formula (7.9) it is calculated the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 1.15 × 10<sup>21</sup> m<sup>5/2</sup>/s<sup>2</sup> and by the Formulas (3.4) and (3.5) it is got rightly the 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         6.4 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           11 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and R<sub>200-TOTAL</sub> = 178 kpc. The matching with the virial mass is almost perfect, which is a good test for the Formula (7.9).</p>
    <p>A third test will be made with the M31 data published by <xref ref-type="bibr" rid="scirp.144431-12">
      [12]
     </xref> (Zhan 2024) (<xref ref-type="table" rid="table30">
      Table 30
     </xref>).</p>
    <table-wrap id="table30">
     <label>
      <xref ref-type="table" rid="table30">
       Table 30
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.144431-"></xref>Table 30. M31 galaxy data—Zhan, X (2024) page 11.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="28.95%"><p style="text-align:center">Virial data</p></td> 
       <td class="acenter" width="44.34%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mrow> 
             <mtext>
               VIR 
             </mtext> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <msubsup> 
            <mrow> 
             <mn>
               1.14 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               0.35 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               0.5 
             </mn> 
            </mrow> 
           </msubsup> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               12 
             </mn> 
            </mrow> 
           </msup> 
           <msub> 
            <mi>
              M 
            </mi> 
            <mi>
              Θ 
            </mi> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="26.70%"><p style="text-align:center">R<sub>VIR</sub> = 220 ± 25 kpc</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="28.95%"><p style="text-align:center">NFW parameter c</p></td> 
       <td class="acenter" width="44.34%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mi>
             log 
           </mi> 
           <mi>
             c 
           </mi> 
           <mo>
             = 
           </mo> 
           <msubsup> 
            <mrow> 
             <mn>
               0.94 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               0.35 
             </mn> 
            </mrow> 
            <mrow> 
             <mo>
               + 
             </mo> 
             <mn>
               025 
             </mn> 
            </mrow> 
           </msubsup> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="26.70%"><p style="text-align:center">c = 8.7</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Using R<sub>VIR</sub>, by (4.6) it is got the scale radius R<sub>0</sub> = 25.26 kpc, by (4.8) and the parameter c it is got the characteristic density</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ρ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2.939 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msup> 
       <mrow> 
        <mrow> 
         <mtext>
           kg 
         </mtext> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msup> 
          <mtext>
            m 
          </mtext> 
          <mn>
            3 
          </mn> 
         </msup> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math></p>
    <p>Now by (7.9) it is estimated the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math> = 2.09 × 10<sup>21</sup> m<sup>5/2</sup>/s<sup>2</sup>.</p>
    <p>Finally by (3.4) and (3.5) it is got 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mrow> 
         <mn>
           200 
         </mn> 
         <mtext>
           -TOTAL 
         </mtext> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.3 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mn>
           12 
         </mn> 
        </mrow> 
       </msup> 
       <msub> 
        <mi>
          M 
        </mi> 
        <mi>
          Θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> and R<sub>200-TOTAL</sub> = 226 kpc.</p>
    <p>Both values match fully with the virial data given by the author if it is considered the range of errors.</p>
    <p>Therefore one more time it is tested the Formula (7.9) as a very good approximation for the parameter 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          a 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math>.</p>
   </sec>
  </sec><sec id="s8">
   <title>8. Concluding Remarks</title>
   <p>The main goal of this paper is to demonstrate that the Direct mass and the NFW-total mass functions are equivalents into the halo up to the galactic virial radius.</p>
   <p>As it was pointed at the introduction, in the Chapter 4 it was developed a method to integrate the baryonic mass into the NFW mass formula because the Direct mass is a function for the total mass, and as the reader knows the NFW is a DM density profile only. The new NFW-total mass function developed in the Chapter 4 has been used to be compared with the Direct mass through four test. These tests have been tested successfully for the MW in the Chapter 5 and for the M31 in the Chapter 6.</p>
   <p>All the calculus and the results of the four tests are shown conveniently and it is clear that the relative differences of the calculus made by the two different functions of masses are below the error measures published by the authors.</p>
   <p>Namely the relative differences in the test IV using the <xref ref-type="bibr" rid="scirp.144431-4">
     [4]
    </xref> Sofue data for MW are below 10% into the whole halo dominion and the same test IV using the <xref ref-type="bibr" rid="scirp.144431-9">
     [9]
    </xref> Karukes data for MW are below 4% into the radius interval from 40 kpc up to 200 kpc.</p>
   <p>The same test IV made to M31 gives a successful result as well because the relative differences between both formula of masses is below 15% from 65 kpc up to 240 kpc where its relative difference is 7% only.</p>
   <p>Additionally, the good matching between the two function mass formulas for M31 is shown in <xref ref-type="fig" rid="fig4">
     Figure 4
    </xref> into a radius dominion that ranges from 40 kpc up to 1380 kpc, and at this last value, almost twice the distance MW-M31, the relative difference is 4% only.</p>
   <p>Finally, in the Chapter 7 has been got a simple formula to approximate with accuracy the parameter 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         a 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math> using the NFW parameters and such formula has been tested successfully with three different recent works about virial data of M31 and MW.</p>
   <p>The prove reach in this paper is valuable because the NFW is a trustable profile for DM, tested in thousands of galaxies, and although the DMbQG theory claims that DM has an unbounded halo region, it gives similar results in the halo region common for both theories i.e. up to the virial radius.</p>
  </sec>
 </body><back>
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