<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jamp
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of Applied Mathematics and Physics
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2327-4352
   </issn>
   <issn publication-format="print">
    2327-4379
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jamp.2025.134065
   </article-id>
   <article-id pub-id-type="publisher-id">
    jamp-141941
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Optimization of Tubular Gas Heaters on Pellets with Recirculation of Gas-Air Mixture Using a Quasi-Two-Dimensional Model
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Kostiantyn
      </surname>
      <given-names>
       Dudkin
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Vladislav
      </surname>
      <given-names>
       Danishevskyy
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff2"> 
      <sup>2</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Vyacheslav
      </surname>
      <given-names>
       Irodov
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff3"> 
      <sup>3</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Halyna
      </surname>
      <given-names>
       Prokofieva
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff4"> 
      <sup>4</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Leontina
      </surname>
      <given-names>
       Solod
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff4"> 
      <sup>4</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Valeria
      </surname>
      <given-names>
       Tkachova
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff4"> 
      <sup>4</sup>
     </xref>
    </contrib>
   </contrib-group> 
   <aff id="aff1">
    <addr-line>
     aCollective Research and Production Enterprise “Energocomplex”, Dnipro, Ukraine
    </addr-line> 
   </aff> 
   <aff id="aff2">
    <addr-line>
     aDepartment of Structural and Theoretical Mechanics and Strength of Materials, Prydniprovska State Academy of Civil Engineering and Architecture, Dnipro, Ukraine
    </addr-line> 
   </aff> 
   <aff id="aff3">
    <addr-line>
     aDepartment of Information Technologies of the Dnipro Technological University “Step”, Dnipro, Ukraine
    </addr-line> 
   </aff> 
   <aff id="aff4">
    <addr-line>
     aDepartment of Heating, Ventilation, Air Conditioning, Heat and Gas Supply, Prydniprovska State Academy of Civil Engineering and Architecture, Dnipro, Ukraine
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     03
    </day> 
    <month>
     04
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    13
   </volume> 
   <issue>
    04
   </issue>
   <fpage>
    1232
   </fpage>
   <lpage>
    1241
   </lpage>
   <history>
    <date date-type="received">
     <day>
      8,
     </day>
     <month>
      March
     </month>
     <year>
      2025
     </year>
    </date>
    <date date-type="published">
     <day>
      12,
     </day>
     <month>
      March
     </month>
     <year>
      2025
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      12,
     </day>
     <month>
      April
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    The article is devoted to decision-making in the control and design of autonomous heat supply systems with tubular gas heaters. The results of mathematical modelling and optimization of tubular gas heaters (TGN) are known. Tubular gas heaters are an extension of the term “infrared tubular gas heaters”. The main elements are: a gas burner, a tubular heater inside which gas combustion products with air move, and a mechanical fan (supply or exhaust), which ensures the movement of the coolant inside the tubular part and its removal outside. There are a number of new technical solutions that expand the scope of tubular gas heaters, for example, tubular gas heaters on pellets. Mathematical models of tubular heaters on pellets and solutions to the problems of optimal design of tubular heaters of linear structure are known. Another possible structure of tubular gas heaters is heaters with recirculation of the heating gas-air medium. Optimisation of such pellet heaters has not been performed before, which determined the subject of this paper. The article is devoted to the presentation of the method of optimization of the design solution for tubular heaters taking into account recirculation under the existing constraints. The novelty of the optimization lies in the use of a quasi-two-dimensional mathematical model for the hydraulic circuit of the heater. An evolutionary search algorithm with binary choice functions is used for numerical search of solutions, for which convergence with probability 1 to the optimal solution is shown. The algorithm contains two consecutive functions: the function of solution generation and the function of solution selection. The function of solution generation is built largely independently of the content of the problem to be solved, while the function of selection is built in such a way that the resulting binary selection relation is completely determined by the requirement of finding the necessary solution. The resulting binary selection relation includes both the selection components of the available constraints and the basic optimiztion requirement.
   </abstract>
   <kwd-group> 
    <kwd>
     Mathematical Model
    </kwd> 
    <kwd>
      Evolutionary Search
    </kwd> 
    <kwd>
      Binary Choice Relations
    </kwd> 
    <kwd>
      Tubular Gas Heaters on Pellets
    </kwd> 
    <kwd>
      Recirculation of Gas-Air Mixture
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>Infrared tube gas heaters (ITGOs) are used for autonomous heating and heating, which consist of a gas burner, a tube heater—a pipe inside which the combustion products of gas and air move, reflectors of the radiant flow and a fan (supply or exhaust), thanks to which the coolant moves inside the pipe and is removed outside after its cooling. There is a lot of experience in the application of ITGOs <xref ref-type="bibr" rid="scirp.141941-1">
     [1]
    </xref>-<xref ref-type="bibr" rid="scirp.141941-3">
     [3]
    </xref>. The use of tubular gas heaters has been developed, for example <xref ref-type="bibr" rid="scirp.141941-4">
     [4]
    </xref> the use of tubular gas heaters as an industrial product, including partial recirculation of the gas-air mixture <xref ref-type="bibr" rid="scirp.141941-5">
     [5]
    </xref>. The term “tubular gas heaters” (TGH) is an extension of the concept of ITGOs, which consist formally of similar elements, but are used not only for infrared heating of surfaces, but also for heating air, water, obtaining water vapour <xref ref-type="bibr" rid="scirp.141941-6">
     [6]
    </xref>. As a rule, TGHs are used as a result of individual design of the heating and gas supply system, which requires appropriate methodological support and calculations for decision-making. Relatively recently in tubular gas heaters began to use instead of combustible gas—wood pellets <xref ref-type="bibr" rid="scirp.141941-7">
     [7]
    </xref>, as a result of combustion processes of which a gas-air mixture is formed, which is a coolant of TGH. Mathematical models of tubular gas heaters with pellets and solution of the problem of optimal design of tubular gas heaters are known, for example <xref ref-type="bibr" rid="scirp.141941-8">
     [8]
    </xref>. Various technical solutions are known, including those for TGH with recirculation of the coolant. For such a technical solution, the calculation of parameters was performed on the basis of a one-dimensional mathematical model of the hydraulic circuit. Earlier, a quasi-dimensional mathematical model of a tubular gas heater was also proposed, which allows describing the change of external temperature on the heater surface, which is desirable for solving a number of problems. However, the solution of the optimisation problem in the design of tubular gas heaters with recirculation of the coolant and taking into account the quasi-dimensional model has not been previously carried out, which determined the purpose of this work. The decision-making problem is formulated using binary choice relations. For numerical solution of the problem, the original algorithm of evolutionary search with several branches of the process running in parallel was used. Due to such construction of the algorithm it is possible to control the search parameters, which provides convergence of the evolutionary search to the optimal solution with probability 1.</p>
   <p>Today, one of the urgent problems is the decision-making to pellet tube heaters with recirculation of gas-air mixture (<xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>).</p>
   <fig id="fig1" position="float">
    <label>Figure 1</label>
    <caption>
     <title>1) pellet burner; 2), 3) air and pellet supply nozzles; 4) the main section of the tubular heater; 5) fan; 6) ejector; 7) nozzle of the ejector for the active medium; 8) fan outlet; 9) nozzle of the ejector for the passive medium; 10) outlet nozzle of the ejector; 11) a pipe for the exit of flue gases.Figure 1. Tubular gas pellet heater with heat carrier recirculation.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1724098-rId14.jpeg?20250506025715" />
   </fig>
   <p>The purpose of the study</p>
   <p>The purpose of the research: to obtain algorithmic support for making optimal decisions in the processes of construction and design of autonomous heat supply systems for pellet tubular gas heaters with heat carrier recirculation.</p>
   <p>The goal of the work: to develop an algorithm of evolutionary search with a binary relation of choosing the most attractive (optimal) solutions for tubular gas heaters with heat carrier recirculation.</p>
  </sec><sec id="s2">
   <title>2. Mathemanical Model of Pellet Tubular Gas Heaters</title>
   <p>One-dimensional steady-state motion of the gas-air mixture inside the heater tube part is considered, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       l 
     </mi> 
    </math> is a linear coordinate.</p>
   <p>The equations of motion along the length of the tube heater are as follows</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        p 
      </mi> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mi>
        Λ 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mrow> 
       <mrow> 
        <mtext>
          d 
        </mtext> 
        <mi>
          x 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         D 
       </mi> 
      </mrow> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        ρ 
      </mi> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           w 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mtext>
        d 
      </mtext> 
      <mi>
        h 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           ρ 
         </mi> 
         <mi>
           a 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        g 
      </mi> 
     </mrow> 
    </math> (1)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        ρ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <mi>
            ρ 
          </mi> 
          <mo>
            − 
          </mo> 
          <mi>
            ρ 
          </mi> 
          <mi>
            R 
          </mi> 
          <mtext>
            d 
          </mtext> 
          <mi>
            T 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mi>
          R 
        </mi> 
        <mi>
          T 
        </mi> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math> (2)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        w 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mo>
            − 
          </mo> 
          <mi>
            ρ 
          </mi> 
          <mi>
            w 
          </mi> 
          <mtext>
            d 
          </mtext> 
          <mi>
            F 
          </mi> 
          <mo>
            − 
          </mo> 
          <mi>
            w 
          </mi> 
          <mi>
            F 
          </mi> 
          <mtext>
            d 
          </mtext> 
          <mi>
            ρ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mi>
          ρ 
        </mi> 
        <mi>
          F 
        </mi> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math> (3)</p>
   <p>where: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ρ 
     </mi> 
    </math>—density of the gas-air mixture; 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       w 
     </mi> 
    </math>—average linear velocity of the gas-air mixture moving along the radiating tube; 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       F 
     </mi> 
    </math>—cross-sectional area of the tube; 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        P 
      </mi> 
      <mo>
        , 
      </mo> 
      <mi>
        T 
      </mi> 
     </mrow> 
    </math>—absolute pressure and temperature of the gas-air mixture in the given cross-section of the radiating tube; 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       R 
     </mi> 
    </math>—gas constant depending on the composition of the gas-air mixture after complete combustion of combustible gas; 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        p 
      </mi> 
     </mrow> 
    </math>—pressure drop of the gas-air mixture on the section of length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        l 
      </mi> 
     </mrow> 
    </math>; 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       Λ 
     </mi> 
    </math>—friction coefficient.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        D 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         l 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mi>
        h 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         l 
       </mi> 
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         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mi>
        T 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          p 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mi>
        F 
      </mi> 
      <mrow> 
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         ( 
       </mo> 
       <mi>
         l 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>—known functions. There is an integral condition for the entire heater, which must be satisfied based on physical laws of the form. There is an integral condition for the entire heater, which must be satisfied based on physical laws of the form</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <munder> 
         <mo>
           ∫ 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             l 
           </mi> 
           <mi>
             i 
           </mi> 
          </msub> 
         </mrow> 
        </munder> 
        <mrow> 
         <mtext>
           d 
         </mtext> 
         <mi>
           p 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              l 
            </mi> 
            <mi>
              i 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        p 
      </mi> 
      <mo>
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      </mo> 
      <mi>
        c 
      </mi> 
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      </mi> 
      <mi>
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      </mi> 
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      </mi> 
     </mrow> 
    </math> (4)</p>
   <p>To make decisions, two criteria were used— 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
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         ( 
       </mo> 
       <mi>
         x 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> the criterion of the efficiency of the tubular heater, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mrow> 
        <mn>
          21 
        </mn> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         x 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>—the criterion of fulfilling physical laws (4), 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mrow> 
        <mn>
          22 
        </mn> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         x 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>—the criterion of fulfilling the technical conditions for the operation of the heater along the entire length.</p>
   <sec id="s2_1">
    <title>Heat Transfer Equations</title>
    <p>
     <xref ref-type="bibr" rid="scirp.141941-"></xref> 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mi>
           c 
         </mi> 
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         </mi> 
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         </mi> 
        </mrow> 
       </msub> 
       <mo>
         + 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mi>
           r 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           d 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
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        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
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           c 
         </mi> 
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         </mi> 
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         </mi> 
        </mrow> 
       </msub> 
       <mo>
         + 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
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         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           d 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> (5)</p>
    <p>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
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       </msub> 
       <mo>
         , 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mi>
           r 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           d 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>—Convective and radiant heat flows on the inner surface of the pipe, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
      </mrow> 
     </math>—heat flux by heat conduction through the pipe wall, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           c 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           n 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         , 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           r 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           d 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>—Convective and radiant heat fluxes on the outer surface of the pipe, where</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           π 
         </mi> 
         <mi>
           D 
         </mi> 
         <mtext>
           d 
         </mtext> 
         <mi>
           l 
         </mi> 
         <mi>
           λ 
         </mi> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mi>
          δ 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             i 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi>
         π 
       </mi> 
       <mi>
         D 
       </mi> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
       <msub> 
        <mi>
          c 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <msub> 
        <mi>
          ε 
        </mi> 
        <mi>
          w 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
          <mn>
            4 
          </mn> 
         </msubsup> 
         <mo>
           − 
         </mo> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mi>
            o 
          </mi> 
          <mn>
            4 
          </mn> 
         </msubsup> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           8 
         </mn> 
        </mrow> 
       </msup> 
       <mo>
         + 
       </mo> 
       <mi>
         π 
       </mi> 
       <mi>
         D 
       </mi> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
       <msub> 
        <mi>
          α 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (6)</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         π 
       </mi> 
       <mi>
         D 
       </mi> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
       <msub> 
        <mi>
          α 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           T 
         </mi> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             i 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         + 
       </mo> 
       <mi>
         π 
       </mi> 
       <mi>
         D 
       </mi> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
       <msub> 
        <mi>
          c 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mi>
         ε 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msup> 
          <mi>
            T 
          </mi> 
          <mn>
            4 
          </mn> 
         </msup> 
         <mo>
           − 
         </mo> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             i 
           </mi> 
          </mrow> 
          <mn>
            4 
          </mn> 
         </msubsup> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           8 
         </mn> 
        </mrow> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           π 
         </mi> 
         <mi>
           D 
         </mi> 
         <mtext>
           d 
         </mtext> 
         <mi>
           l 
         </mi> 
         <mi>
           λ 
         </mi> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mi>
          δ 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             i 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (7)</p>
    <p>To obtain a quasi-dimensional mathematical model of the thermal and hydraulic modes of the TGN, it is proposed to consider the temperature dependence of the heater surface as a function of linear and angular coordinates:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           l 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           ϕ 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math></p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           о 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           о 
         </mi> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           l 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           ϕ 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (8)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          о 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         c 
       </mi> 
       <mi>
         o 
       </mi> 
       <mi>
         n 
       </mi> 
       <mi>
         s 
       </mi> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math>,</p>
    <p>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        ϕ 
      </mi> 
     </math>—angular coordinate of the heater surface; 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
      </mrow> 
     </math>—absolute ambient temperature.</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           c 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           n 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          D 
        </mi> 
        <mn>
          2 
        </mn> 
       </mfrac> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <munderover> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             π 
           </mi> 
          </mrow> 
         </munderover> 
         <mrow> 
          <msub> 
           <mi>
             α 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             l 
           </mi> 
           <mo>
             , 
           </mo> 
           <mi>
             ϕ 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         ϕ 
       </mi> 
       <mtext>
           
       </mtext> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
      </mrow> 
     </math> (9)</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           r 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           d 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          D 
        </mi> 
        <mn>
          2 
        </mn> 
       </mfrac> 
       <msub> 
        <mi>
          с 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <munderover> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             π 
           </mi> 
          </mrow> 
         </munderover> 
         <mrow> 
          <msub> 
           <mi>
             ε 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
          <mn>
            4 
          </mn> 
         </msubsup> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             l 
           </mi> 
           <mo>
             , 
           </mo> 
           <mi>
             ϕ 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           − 
         </mo> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mi>
            o 
          </mi> 
          <mn>
            4 
          </mn> 
         </msubsup> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         ϕ 
       </mi> 
       <mtext>
           
       </mtext> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
       <mtext>
           
       </mtext> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           8 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (10)</p>
    <p>A set of parameters affecting the temperature distribution around the heater perimeter due to convective motion can be identified and represented as follows 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          θ 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         ψ 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            θ 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           , 
         </mo> 
         <mi>
           P 
         </mi> 
         <mi>
           r 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           R 
         </mi> 
         <mi>
           e 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           G 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          θ 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           o 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>—average surface temperature of the heater, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         P 
       </mi> 
       <mi>
         r 
       </mi> 
       <mo>
         , 
       </mo> 
       <mi>
         R 
       </mi> 
       <mi>
         e 
       </mi> 
       <mo>
         , 
       </mo> 
       <mi>
         G 
       </mi> 
       <mi>
         r 
       </mi> 
      </mrow> 
     </math>—Prandtl, Reynolds and Grasshoff numbers. On the basis of the experimental results, the regression dependence was obtained in the form of</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          θ 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             i 
           </mi> 
          </mrow> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            ϕ 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          k 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <mo>
         + 
       </mo> 
       <msub> 
        <mi>
          k 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             P 
           </mi> 
           <mi>
             r 
           </mi> 
           <mo>
             ⋅ 
           </mo> 
           <mi>
             G 
           </mi> 
           <mi>
             r 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            k 
          </mi> 
          <mn>
            3 
          </mn> 
         </msub> 
        </mrow> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         R 
       </mi> 
       <msup> 
        <mi>
          e 
        </mi> 
        <mrow> 
         <msub> 
          <mi>
            k 
          </mi> 
          <mn>
            4 
          </mn> 
         </msub> 
        </mrow> 
       </msup> 
       <mi>
         cos 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          ϕ 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (11)</p>
    <p>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          ϕ 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> is the temperature on the surface of the heater cross-section with angular coordinate 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        ϕ 
      </mi> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           w 
         </mi> 
         <mi>
           o 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> is the average temperature across the heater cross-section, and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          k 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          k 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          k 
        </mi> 
        <mn>
          3 
        </mn> 
       </msub> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          k 
        </mi> 
        <mn>
          4 
        </mn> 
       </msub> 
      </mrow> 
     </math> are the regression constants. The regression dependence (11) is obtained as a result of minimizing the deviation of the calculated values of the surface temperature of the tubular heater from the experimental values presented in <xref ref-type="bibr" rid="scirp.141941-9">
      [9]
     </xref>. The error of this dependence on the experimental values is 0.07, i.e., the dependence corresponds to the process of complex heat transfer for a tubular heater and can be used for its mathematical modelling.</p>
   </sec>
  </sec><sec id="s3">
   <title>3. Methodology</title>
   <sec id="s3_1">
    <title>Presentation of the Main Research Material</title>
    <p>Following <xref ref-type="bibr" rid="scirp.141941-10">
      [10]
     </xref>, optimisation is not just a tool in the arsenal of machine learning and artificial intelligence, it is the foundation upon which the efficiency and effectiveness of these fields results. Optimisation algorithms, discussed in the study <xref ref-type="bibr" rid="scirp.141941-11">
      [11]
     </xref>, are key tools in machine learning and artificial intelligence. Each algorithm uses a different strategy to navigate the complex and treacherous terrain of the Rosenbrock function, a function known for its complex optimisation landscape characterised by narrow valleys and steep ridges. Gradient descent (GD) is one of the most fundamental and widely used optimisation algorithms, but the algorithm may overshoot the minimum, leading to divergence. Conversely, the algorithm can converge very slowly, requiring an impractical number of iterations to reach the minimum <xref ref-type="bibr" rid="scirp.141941-12">
      [12]
     </xref>. Stochastic Gradient Descent (SGD) is based on the principles of standard gradient descent, but introduces an element of randomness by updating the model parameters not on the entire dataset, but on a randomly selected subset of the data, called a minipartition. By using only a subset of the data, SGD significantly reduces the computational cost per iteration, which makes it particularly suitable for large-scale problems <xref ref-type="bibr" rid="scirp.141941-13">
      [13]
     </xref>.</p>
    <p>To solve the problem of calculating the thermal and hydraulic modes of operation of a tubular heater with heat carrier recirculation, the evolutionary search algorithm for the most attractive solutions was used. The basis of the algorithmic approach is the construction of algorithms for evolutionary search of solutions by binary choice relations. This approach is most fully described in <xref ref-type="bibr" rid="scirp.141941-14">
      [14]
     </xref>.</p>
    <p>It is consider a set Ω of elements (decisions) 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         x 
       </mi> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          { 
        </mo> 
        <mrow> 
         <msup> 
          <mi>
            x 
          </mi> 
          <mn>
            1 
          </mn> 
         </msup> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            x 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           , 
         </mo> 
         <mo>
           ⋯ 
         </mo> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            x 
          </mi> 
          <mi>
            n 
          </mi> 
         </msup> 
        </mrow> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          x 
        </mi> 
        <mi>
          i 
        </mi> 
       </msup> 
      </mrow> 
     </math>—a scalar parameter (continuous or discrete). It is determined the binary choice relation 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          S 
        </mi> 
       </msub> 
      </mrow> 
     </math> for elements of the set Ω.</p>
    <p>It is meant that there is a rule (algorithm) according to one decision is “better” than another. It is determined that choice relation 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          S 
        </mi> 
       </msub> 
      </mrow> 
     </math> is a no strictly order relation.</p>
    <p>For subset 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        X 
      </mi> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         X 
       </mi> 
       <mo>
         ⊂ 
       </mo> 
       <mi>
         Ω 
       </mi> 
      </mrow> 
     </math> we denote the function of choice in the form</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          X 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          { 
        </mo> 
        <mrow> 
         <mi>
           x 
         </mi> 
         <mo>
           ∈ 
         </mo> 
         <mi>
           X 
         </mi> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <mo>
             ∀ 
           </mo> 
           <mi>
             y 
           </mi> 
           <mo>
             ∈ 
           </mo> 
           <mrow> 
            <mo>
              [ 
            </mo> 
            <mrow> 
             <mi>
               X 
             </mi> 
             <mo>
               \ 
             </mo> 
             <mi>
               S 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mi>
                X 
              </mi> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mo>
              ] 
            </mo> 
           </mrow> 
           <mo>
             , 
           </mo> 
           <mi>
             x 
           </mi> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mi>
              S 
            </mi> 
           </msub> 
           <mi>
             y 
           </mi> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (12)</p>
    <p>We shall assume that set 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          X 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> contains the concrete number of elements—N<sub>op</sub>.</p>
    <p>We shall that for the set Ω it was determined relation 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
      </mrow> 
     </math> with attachment function 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          μ 
        </mi> 
        <mrow> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mi>
            G 
          </mi> 
         </msub> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           x 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           y 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>: 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Ω 
       </mi> 
       <mo>
         × 
       </mo> 
       <mi>
         Ω 
       </mi> 
       <mo>
         → 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mn>
           0 
         </mn> 
         <mo>
           , 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math>. Relation 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          G 
        </mi> 
       </msub> 
      </mrow> 
     </math> will be termed generation relation.</p>
    <p>For subset 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        X 
      </mi> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         X 
       </mi> 
       <mo>
         ⊂ 
       </mo> 
       <mi>
         Ω 
       </mi> 
      </mrow> 
     </math> we denote the function of generation in the form</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         G 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          X 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi>
         X 
       </mi> 
       <mo>
         ∪ 
       </mo> 
       <msub> 
        <mi>
          G 
        </mi> 
        <mi>
          H 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          X 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>,</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          G 
        </mi> 
        <mi>
          H 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          X 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          { 
        </mo> 
        <mrow> 
         <mi>
           y 
         </mi> 
         <mo>
           ∈ 
         </mo> 
         <mi>
           Ω 
         </mi> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <mo>
             ∃ 
           </mo> 
           <mi>
             x 
           </mi> 
           <mo>
             ∈ 
           </mo> 
           <mi>
             X 
           </mi> 
           <mo>
             , 
           </mo> 
           <mi>
             y 
           </mi> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mi>
              G 
            </mi> 
           </msub> 
           <mi>
             x 
           </mi> 
           <mo>
             , 
           </mo> 
           <msub> 
            <mi>
              μ 
            </mi> 
            <mrow> 
             <msub> 
              <mi>
                R 
              </mi> 
              <mi>
                G 
              </mi> 
             </msub> 
            </mrow> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               x 
             </mi> 
             <mo>
               , 
             </mo> 
             <mi>
               y 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             &gt; 
           </mo> 
           <mn>
             0 
           </mn> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (13)</p>
    <p>We shall assume that set G(X) contains the concrete number of elements—N<sub>E</sub>.</p>
    <p>The algorithm to search R<sub>S</sub>—optimal solution can be represented as</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              X 
            </mi> 
            <mrow> 
             <mi>
               k 
             </mi> 
             <mo>
               − 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         k 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         1 
       </mn> 
       <mo>
         , 
       </mo> 
       <mn>
         2 
       </mn> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
      </mrow> 
     </math> (14)</p>
    <p>where X<sub>k</sub>—the set of preferred solutions according to the binary choice relation R<sub>S</sub> at the iterate step k, X<sub>k</sub> <sub>–</sub> <sub>1</sub>—this is the same at the iterate step k − 1. G(X)—the function of generation with relation of generation R<sub>G</sub>. S(X)—the function of choice with the binary choice relation R<sub>S</sub>.</p>
    <p>The iterate algorithm (14)—is the general form of evolutionary search.</p>
    <p>We will consider the decomposition</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mi>
          k 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∪ 
         </mo> 
         <mrow> 
          <mi>
            j 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             N 
           </mi> 
           <mi>
             b 
           </mi> 
          </msub> 
         </mrow> 
        </munderover> 
        <mrow> 
         <msub> 
          <mi>
            X 
          </mi> 
          <mrow> 
           <mi>
             j 
           </mi> 
           <mi>
             k 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mrow> 
         <mi>
           i 
         </mi> 
         <mi>
           k 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         ∩ 
       </mo> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mrow> 
         <mi>
           j 
         </mi> 
         <mi>
           k 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mo>
         ∅ 
       </mo> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         i 
       </mi> 
       <mo>
         ≠ 
       </mo> 
       <mi>
         j 
       </mi> 
      </mrow> 
     </math> (15)</p>
    <p>where X<sub>jk</sub>—the set of preferred solutions according to the binary choice relation R<sub>S </sub>at the iterate step k for the branch j of evolutionary search, N<sub>b</sub>—the number of branches.</p>
    <p>The algorithm (14) takes the form</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mrow> 
         <mi>
           j 
         </mi> 
         <mi>
           k 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           G 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              X 
            </mi> 
            <mrow> 
             <mi>
               j 
             </mi> 
             <mi>
               k 
             </mi> 
             <mo>
               − 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         j 
       </mi> 
       <mo>
         = 
       </mo> 
       <mover accent="true"> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            N 
          </mi> 
          <mi>
            G 
          </mi> 
         </msub> 
        </mrow> 
        <mo stretchy="true">
          ¯ 
        </mo> 
       </mover> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         k 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         1 
       </mn> 
       <mo>
         , 
       </mo> 
       <mn>
         2 
       </mn> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
      </mrow> 
     </math> (16)</p>
    <p>These iterate algorithms (14), (16)—are the general form of evolutionary search.</p>
    <p>For the task of finding the most attractive solution for a tubular gas heater with recirculation, the binary selection relation can be represented as follows.</p>
    <p>The dimensionless efficiency function in the form</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi>
         η 
       </mi> 
      </mrow> 
     </math> (17)</p>
    <p>The general penalty function in the form of</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mn>
          2 
        </mn> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mrow> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         + 
       </mo> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mrow> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (18)</p>
    <p>where</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mrow> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>—dimensionless pressure loss throughout the closed heater circuit</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mrow> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mi>
         a 
       </mi> 
       <mi>
         b 
       </mi> 
       <mi>
         s 
       </mi> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mrow> 
          <mrow> 
           <mstyle displaystyle="true"> 
            <mrow> 
             <msub> 
              <mo>
                ∮ 
              </mo> 
              <mrow> 
               <mi>
                 h 
               </mi> 
               <mi>
                 e 
               </mi> 
               <mi>
                 a 
               </mi> 
               <mi>
                 t 
               </mi> 
               <mi>
                 e 
               </mi> 
               <mi>
                 r 
               </mi> 
              </mrow> 
             </msub> 
             <mrow> 
              <mtext>
                d 
              </mtext> 
              <msub> 
               <mi>
                 p 
               </mi> 
               <mi>
                 i 
               </mi> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 x 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <mi>
             a 
           </mi> 
           <mi>
             b 
           </mi> 
           <mi>
             s 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                p 
              </mi> 
              <mrow> 
               <mi>
                 max 
               </mi> 
              </mrow> 
             </msub> 
             <mo>
               − 
             </mo> 
             <msub> 
              <mi>
                p 
              </mi> 
              <mrow> 
               <mi>
                 i 
               </mi> 
               <mi>
                 n 
               </mi> 
               <mi>
                 l 
               </mi> 
               <mi>
                 e 
               </mi> 
               <mi>
                 t 
               </mi> 
              </mrow> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (19)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mrow> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>—dimensionless exceeding the maximum permissible heat flux through the outer surface of the heater.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          F 
        </mi> 
        <mrow> 
         <mn>
           22 
         </mn> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           a 
         </mi> 
         <mi>
           b 
         </mi> 
         <mi>
           s 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             Δ 
           </mi> 
           <msub> 
            <mi>
              Q 
            </mi> 
            <mrow> 
             <mn>
               3 
             </mn> 
             <mi>
               c 
             </mi> 
             <mi>
               o 
             </mi> 
             <mi>
               n 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             + 
           </mo> 
           <mi>
             Δ 
           </mi> 
           <msub> 
            <mi>
              Q 
            </mi> 
            <mrow> 
             <mn>
               3 
             </mn> 
             <mi>
               r 
             </mi> 
             <mi>
               a 
             </mi> 
             <mi>
               d 
             </mi> 
            </mrow> 
           </msub> 
           <mo>
             − 
           </mo> 
           <mi>
             Δ 
           </mi> 
           <msub> 
            <mi>
              Q 
            </mi> 
            <mrow> 
             <mi>
               l 
             </mi> 
             <mi>
               i 
             </mi> 
             <mi>
               m 
             </mi> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mi>
           Δ 
         </mi> 
         <msub> 
          <mi>
            Q 
          </mi> 
          <mrow> 
           <mi>
             l 
           </mi> 
           <mi>
             i 
           </mi> 
           <mi>
             m 
           </mi> 
          </mrow> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> (20)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mi>
           l 
         </mi> 
         <mi>
           i 
         </mi> 
         <mi>
           m 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>—maximum permissible heat flux through the outer surface of the heater.</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           c 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           n 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          D 
        </mi> 
        <mn>
          2 
        </mn> 
       </mfrac> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <munderover> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             π 
           </mi> 
          </mrow> 
         </munderover> 
         <mrow> 
          <msub> 
           <mi>
             α 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             l 
           </mi> 
           <mo>
             , 
           </mo> 
           <mi>
             ϕ 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         ϕ 
       </mi> 
       <mtext>
           
       </mtext> 
       <mtext>
         d 
       </mtext> 
       <mi>
         l 
       </mi> 
      </mrow> 
     </math> (21)</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           r 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           d 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          D 
        </mi> 
        <mn>
          2 
        </mn> 
       </mfrac> 
       <msub> 
        <mi>
          с 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <munderover> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             π 
           </mi> 
          </mrow> 
         </munderover> 
         <mrow> 
          <msub> 
           <mi>
             ε 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mrow> 
           <mi>
             w 
           </mi> 
           <mi>
             o 
           </mi> 
          </mrow> 
          <mn>
            4 
          </mn> 
         </msubsup> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             l 
           </mi> 
           <mo>
             , 
           </mo> 
           <mi>
             ϕ 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           − 
         </mo> 
         <msubsup> 
          <mi>
            T 
          </mi> 
          <mi>
            o 
          </mi> 
          <mn>
            4 
          </mn> 
         </msubsup> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         ϕ 
       </mi> 
       <mtext>
           
       </mtext> 
       <mi>
         Δ 
       </mi> 
       <mi>
         l 
       </mi> 
       <mtext>
           
       </mtext> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           8 
         </mn> 
        </mrow> 
       </msup> 
      </mrow> 
     </math> (22)</p>
    <p>The general relation 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mrow> 
         <mi>
           S 
         </mi> 
         <mi>
           S 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> for choosing between two possible solutions x and y is as follows:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
       <mtr> 
        <mtd> 
         <mi>
           x 
         </mi> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mrow> 
           <mi>
             S 
           </mi> 
           <mi>
             S 
           </mi> 
          </mrow> 
         </msub> 
         <mi>
           y 
         </mi> 
         <mo>
           = 
         </mo> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              x 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ≤ 
           </mo> 
           <mn>
             0 
           </mn> 
           <mo>
             ∧ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              y 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             &gt; 
           </mo> 
           <mn>
             0 
           </mn> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <mtext>
             
         </mtext> 
         <mtext>
             
         </mtext> 
         <mo>
           ∨ 
         </mo> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              x 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             &gt; 
           </mo> 
           <mn>
             0 
           </mn> 
           <mo>
             ∧ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              y 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             &gt; 
           </mo> 
           <mn>
             0 
           </mn> 
           <mo>
             ∧ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              x 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ≤ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              y 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <mtext>
             
         </mtext> 
         <mtext>
             
         </mtext> 
         <mo>
           ∨ 
         </mo> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              x 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ≤ 
           </mo> 
           <mn>
             0 
           </mn> 
           <mo>
             ∧ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              y 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ≤ 
           </mo> 
           <mn>
             0 
           </mn> 
           <mo>
             ∧ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              x 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ≥ 
           </mo> 
           <msub> 
            <mi>
              F 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              y 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math> (23)</p>
   </sec>
  </sec><sec id="s4">
   <title>4. Numerical Results</title>
   <p>The algorithm for evolutionary search for the most attractive solutions to the problem of optimising the parameters of a tubular gas heater with recirculation is presented in form (16).</p>
   <p>The sought solution has the form 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         { 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mn>
           1 
         </mn> 
        </msup> 
        <mo>
          , 
        </mo> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          , 
        </mo> 
        <mo>
          ⋯ 
        </mo> 
        <mo>
          , 
        </mo> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mn>
           6 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         } 
       </mo> 
      </mrow> 
     </mrow> 
    </math> where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         1 
       </mn> 
      </msup> 
     </mrow> 
    </math>—power of pellet burner, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math>—total flow rate of fresh air supplied to the heater, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         3 
       </mn> 
      </msup> 
     </mrow> 
    </math>—diameter of the tubular part of the heater, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         4 
       </mn> 
      </msup> 
     </mrow> 
    </math>—diameter of the screen of the heater, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         5 
       </mn> 
      </msup> 
     </mrow> 
    </math>—total length of the tubular heater, including the recirculation part, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         6 
       </mn> 
      </msup> 
     </mrow> 
    </math>—length of the heater of the initial part with the screen.</p>
   <p>The initial search parameters adopted are as follows</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         p 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        200 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        Pa 
      </mtext> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mrow> 
        <mi>
          w 
        </mi> 
        <mi>
          o 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        450 
      </mn> 
      <mo>
        ˚ 
      </mo> 
      <mtext>
        C 
      </mtext> 
     </mrow> 
    </math></p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        σ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         1 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        0.1 
      </mn> 
      <mo>
        , 
      </mo> 
      <mi>
        σ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         2 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        10 
      </mn> 
      <mo>
        , 
      </mo> 
      <mi>
        σ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         3 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        0.01 
      </mn> 
      <mo>
        , 
      </mo> 
      <mi>
        σ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         4 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        0.01 
      </mn> 
      <mo>
        , 
      </mo> 
      <mi>
        σ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         5 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        , 
      </mo> 
      <mi>
        σ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         6 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         N 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mi>
         N 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mi>
         N 
       </mi> 
       <mi>
         B 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        3 
      </mn> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mi>
         N 
       </mi> 
       <mi>
         P 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        5 
      </mn> 
     </mrow> 
    </math></p>
   <p>The permissible limits of variation of the parameters are as follows</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
       <mn>
         1 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        20 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        120 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
       <mn>
         3 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        0.1 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
       <mn>
         4 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        0.25 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
       <mn>
         5 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        60 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
       <mn>
         6 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        3 
      </mn> 
     </mrow> 
    </math></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
       <mn>
         1 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        70 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        200 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
       <mn>
         3 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        0.18 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
       <mn>
         4 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        0.35 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
       <mn>
         5 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        70 
      </mn> 
      <mo>
        , 
      </mo> 
      <msubsup> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mi>
          max 
        </mi> 
       </mrow> 
       <mn>
         6 
       </mn> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        6 
      </mn> 
     </mrow> 
    </math></p>
   <p>The results of the evolutionary search for the solution of the problem of optimal design of a tubular heater with heat carrier recirculation are given in <xref ref-type="table" rid="table1">
     Table 1
    </xref>.</p>
   <table-wrap id="table1">
    <label>
     <xref ref-type="table" rid="table1">
      Table 1
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.141941-"></xref>Table 1. Results of the evolutionary search for tubular heater with recirculation and 2 criteria.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td rowspan="2" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Number of iterations</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="60.52%" colspan="7"><p style="text-align:center">Argument values (parameters)</p></td> 
      <td class="custom-top-td acenter" width="21.88%" colspan="3"><p style="text-align:center">Functions (criteria)</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.07%"><p style="text-align:center">x<sup>1</sup></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.07%"><p style="text-align:center">x<sup>2</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">x<sup>3</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">x<sup>4</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">x<sup>5</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">x<sup>6</sup></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msub> 
           <mi>
             F 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
        </math></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.95%"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msub> 
           <mi>
             F 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </math></p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 1</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">38.05292</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">178</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.121347</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.2899812</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">70</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">3</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.934281</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0.846456</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">39.47193</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">184.8262</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.123994</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.3498935</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">70</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">4.332048</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.940479</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0.872469</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">42.0129</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">172.3327</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.161610</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.2674288</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">68.91031</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">3</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.959257</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">1.42065</p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 2</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">31.84523</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">183.6643</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">69.60403</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">3.412462</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.913917</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0.005766</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">36.34251</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">200</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.105756</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">70</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">3</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.912229</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0.142706</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">44.32399</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">178.2993</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.149475</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">68.71887</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">4.826355</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.958499</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">1.254207</p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 3</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">31.84523</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">183.6643</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">69.60403</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">3.412462</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.909421</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">33.03416</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">200</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">69.92034</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">3</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.896563</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">29.27168</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">185.4664</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.137231</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">68.99318</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">5.626478</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.933428</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">0.759581</p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 5</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">29.73758</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">180.4266</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">69.74614</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">4.088115</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.914873</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">28.81708</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">193.8471</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">69.84319</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">3</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.899616</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">25.31072</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">183.625</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">69.30032</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">4.100157</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.905787</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 12</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">29.34677</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">175.7512</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">68.98177</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">5.048008</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.918704</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">29.6055</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">175.7642</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">68.51453</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">4.260027</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.919052</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">29.54401</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">175.8815</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.1</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">68.45444</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">3.897392</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.918973</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>From the computational results, we can see that the evolutionary search converges quite quickly to a single solution, viz:</p>
   <p>Heater power 30 kW, air flow rate 175 m<sup>3</sup>/hour, heater diameter 0.1 m, screen diameter 0.35 m, total heater length 69 m, initial section length with screen—4 m.</p>
   <p>The overall efficiency of the heater with recirculation reaches 91.9% while fully satisfying all constraints ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         F 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>).</p>
  </sec><sec id="s5">
   <title>5. Discussion</title>
   <p>It is of interest to compare the solution found for the recirculating tube heater on the one hand and the linear type gas tube heater on the other. The results of optimal calculation of the heater without recirculation are presented in <xref ref-type="table" rid="table2">
     Table 2
    </xref>.</p>
   <table-wrap id="table2">
    <label>
     <xref ref-type="table" rid="table2">
      Table 2
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.141941-"></xref>Table 2. Results of the evolutionary search for tubular heater without recirculation and 2 criteria.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td rowspan="2" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Number of iterations</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="60.52%" colspan="7"><p style="text-align:center">Argument values (parameters)</p></td> 
      <td class="custom-top-td acenter" width="21.88%" colspan="3"><p style="text-align:center">Functions (criteria)</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.07%"><p style="text-align:center">x<sup>1</sup></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.07%"><p style="text-align:center">x<sup>2</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">x<sup>3</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">x<sup>4</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">x<sup>5</sup></p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">x<sup>6</sup></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msub> 
           <mi>
             F 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
        </math></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="10.95%"><p style="text-align:center"> 
        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
          <msub> 
           <mi>
             F 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </math></p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 8</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">20.2981</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">246.1759</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.1063</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.30688</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">65.51886</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">4.958077</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.8061</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0.003290</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">20</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">240.6709</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.1025</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">66.24492</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">5.20974</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.81849</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">20</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">241.532</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.10673</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.337269</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">60.48888</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">5.06925</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.820997</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">0.007048</p></td> 
     </tr> 
     <tr> 
      <td rowspan="3" class="custom-top-td acenter" width="17.60%"><p style="text-align:center">Step 20</p><p style="text-align:center">Branches 1, 2, 3</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">2.017055</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">238.123</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">0.10185</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">0.346723</p></td> 
      <td class="custom-top-td acenter" width="10.07%"><p style="text-align:center">60.6891</p></td> 
      <td class="custom-top-td acenter" width="10.08%"><p style="text-align:center">3</p></td> 
      <td class="custom-top-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.82000</p></td> 
      <td class="custom-top-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="10.07%"><p style="text-align:center">2.00014</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">229.6907</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">0.10076</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">0.35</p></td> 
      <td class="acenter" width="10.07%"><p style="text-align:center">60.3744</p></td> 
      <td class="acenter" width="10.08%"><p style="text-align:center">4.505256</p></td> 
      <td class="acenter" width="10.93%" colspan="2"><p style="text-align:center">0.82884</p></td> 
      <td class="acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">20</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">231.226</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">0.10120</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">0.347317</p></td> 
      <td class="custom-bottom-td acenter" width="10.07%"><p style="text-align:center">61.3520</p></td> 
      <td class="custom-bottom-td acenter" width="10.08%"><p style="text-align:center">45.67978</p></td> 
      <td class="custom-bottom-td acenter" width="10.93%" colspan="2"><p style="text-align:center">0.82655</p></td> 
      <td class="custom-bottom-td acenter" width="10.95%"><p style="text-align:center">0</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>As can be seen from the comparison of the two optimisation results—<xref ref-type="table" rid="table1">
     Table 1
    </xref> and <xref ref-type="table" rid="table2">
     Table 2
    </xref>, there are differences in these results. First of all, at optimisation of the tube heater without recirculation the total power of the heater decreased, with recirculation +29.5 kW, without recirculation −20 kW. The fresh air flow rate increased slightly, instead of 175 m<sup>3</sup>/hour, it is necessary to supply 230 m<sup>3</sup>/hour. And the most important difference in achieving the overall efficiency of the tube heater: for the heater with recirculation—91.8%, and for the heater without recirculation—82%. These figures correspond to the efficiency of low-intensity infrared heaters <xref ref-type="bibr" rid="scirp.141941-7">
     [7]
    </xref>, which are mass-produced, with a power of 15 - 50 kW, have a length of the heating part of the heater—6 - 15 metres, and the temperature of the heating pipe can reach 1000 ˚F (540˚C).</p>
  </sec><sec id="s6">
   <title>6. Concluding Remarks</title>
   <p>Thus, it is convincingly demonstrated that the technical solution for the tubular heater provides improved heater efficiency compared to the linear configuration, as well as the simplicity and efficiency of using the algorithm for finding the most favoured solutions for selection by binary choice functions. The range of parameter variation can be specified based on the experimental study of gas emissions of pellet burner of tubular gas heater <xref ref-type="bibr" rid="scirp.141941-7">
     [7]
    </xref>, namely:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
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        55 
      </mn> 
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      </mtext> 
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        kW 
      </mtext> 
      <mo>
        , 
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      </mtext> 
      <msup> 
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      </mtext> 
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        mm 
      </mtext> 
     </mrow> 
    </math>.</p>
   <p>The validity of the obtained results is based on the reliability of the mathematical modelling of the pellet gas burner—this follows from <xref ref-type="bibr" rid="scirp.141941-7">
     [7]
    </xref>, and the modelling and calculation of the linear part of the pellet heater is outlined in <xref ref-type="bibr" rid="scirp.141941-15">
     [15]
    </xref>, which shows good agreement of the calculated temperature values with the experimental values for the tubular pellet heater located in the existing greenhouse.</p>
  </sec>
 </body><back>
  <ref-list>
   <title>References</title>
   <ref id="scirp.141941-ref1">
    <label>1</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Roberts-Gordon LLC (2012) Gas-Fired Infrared Heating for Poultry House. 35. &gt;https://www.robertsgordon.com 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref2">
    <label>2</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Morton, J.D., Lawrie, L.K., Nemeth, R.J., Reed, J. and Rives, B.L. (1992) Issues in the Design of Infrared Radiant Heating Systems, US Army Corp of Engineers Construction. Engineering Research Laboratory, AD-A261 610 USACERL Technical Report FE-93/06, 165. &gt;https://www.researchgate.net/publication/235028332_Issues_in_the_Design_of_Infrared_Radiant_Heating_Systems 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref3">
    <label>3</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Buckley, N.A. (1989) Application of Radiant Heating Saves Energy. ASHRAE Journal, 31, 17-26. &gt;https://www.osti.gov/biblio/5428356 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref4">
    <label>4</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Bolotskikh, N.N. (2012) Multi-Burner System NOR-RAY-VAC for Infrared Gas Heating of Large Premises. Energy Saving. Power Engineering. Energoaudit, 4, 56-62. &gt;http://nbuv.gov.ua/UJRN/ecee_2012_4_9 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref5">
    <label>5</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Bolotskikh, N.N. (2013) Ribbon Infrared Gas Heaters Schulte for Heating of High Premises with a Large Heat Load. Energosberezhenie. Power Engineering. Energoau-dit, 9, 38-45. &gt;http://nbuv.gov.ua/UJRN/ecee_2013_9_6 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref6">
    <label>6</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Irodov, V.F., Khatskevych, Y.V. and Chornomorets, H.Y. (2017) Rozvytok tekhnichnykh rishen teplopostachannia z trubchastymy hazovymy nahrivachamy [Development of Technical Solutions for Heat Supply with Tubular Gas Heaters]. Visnyk Prydniprovskoi derzhavnoi akademii budivnytstva ta arkhitektury, 5, 29-35. (In Ukrainian) &gt;http://srd.pgasa.dp.ua:8080/bitstream/123456789/223/1/Irodov.pdf 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref7">
    <label>7</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Irodov, V.F., Barsuk, R.V., Chornomorets, G.Y. and Chernoyvan, A.A. (2021) Experimental Simulation and Multiobjective Optimization of the Work of a Pellet Burner for a Tubular Gas Heater. Journal of Engineering Physics and Thermophysics, 94, 219-225. &gt;https://doi.org/10.1007/s10891-021-02290-0
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref8">
    <label>8</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Irodov, V., Shaptala, M., Dudkin, K., Shaptala, D. and Prokofieva, H. (2021) Development of Evolutionary Search Algorithms with Binary Choice Relations When Making Decisions for Pellet Tubular Heaters. Eastern-European Journal of Enterprise Technologies, 3, 50-59. &gt;https://doi.org/10.15587/1729-4061.2021.235837
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref9">
    <label>9</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Irodov, V.F. and Solod, L.V. (2001) Experimental Studies of Low-Temperature Air-beam Heating Systems on Natural Gas. Bulletin of the Prydniprovska State Academy of Civil Engineering and Architecture, No. 6, 20-24. &gt;http://www.irbis-nbuv.gov.ua/publ/REF-0000029462 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref10">
    <label>10</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Smith, L. and Topin, N. (2024) Beyond SGD: An Empirical Study of Modern Optimization Techniques in Deep Learning. Journal of Machine Learning Research, 25, 1-20.
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref11">
    <label>11</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Ngartera, L. and Diallo, C. (2024) A Comparative Study of Optimization Techniques on the Rosenbrock Function. Open Journal of Optimization, 13, 51-63. &gt;https://doi.org/10.4236/ojop.2024.133004
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref12">
    <label>12</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Rawhoudine, S.C. and Bacar, A.H. (2024) A New Multiobjective Particle Swarm Optimization Using Local Displacement and Local Guides. Open Journal of Optimization, 13, 31-49. &gt;https://doi.org/10.4236/ojop.2024.132003
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref13">
    <label>13</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Liu, B. (2019) A Smoothing Penalty Function Method for the Constrained Optimization Problem. Open Journal of Optimization, 8, 113-126. &gt;https://doi.org/10.4236/ojop.2019.84010
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref14">
    <label>14</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Irodov, V., Dubrovskyi, S., Dudkin, K. and Chirin, D. (2024) Evolutionary Search for Some Generalized Mathematical Programming Problems with Binary Choice Rela-tions. Elsevier, 12. &gt;https://doi.org/10.2139/ssrn.4750911 
    </mixed-citation>
   </ref>
   <ref id="scirp.141941-ref15">
    <label>15</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Dudkin, K.V., Tkachova, A.A. and Chernoivan, A.A. (2013) Tubular Gas Heaters for Heat Supply on Pellets. Construction. Materialovedenie. Mechanical Engineering, 68, 142-146. &gt;http://nbuv.gov.ua/UJRN/smmcvtek_2013_68_25
    </mixed-citation>
   </ref>
  </ref-list>
 </back>
</article>