<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    ojpc
   </journal-id>
   <journal-title-group>
    <journal-title>
     Open Journal of Physical Chemistry
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2162-1969
   </issn>
   <issn publication-format="print">
    2162-1977
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/ojpc.2025.151001
   </article-id>
   <article-id pub-id-type="publisher-id">
    ojpc-140494
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Chemistry 
     </subject>
     <subject>
       Materials Science
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Bose-Einstein Condensation Yb
    <sub>2</sub>Si
    <sub>2</sub>O
    <sub>7</sub> Retaining Si Applied in UV-Etching 1 nm Quantum Wires
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Hung Te Henry
      </surname>
      <given-names>
       Su
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Po-Han
      </surname>
      <given-names>
       Lee
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff2"> 
      <sup>2</sup>
     </xref> 
     <xref ref-type="aff" rid="aff3"> 
      <sup>3</sup>
     </xref>
    </contrib>
   </contrib-group> 
   <aff id="aff1">
    <addr-line>
     aDepartment of Physics, National Chung Cheng University, Chiayi
    </addr-line> 
   </aff> 
   <aff id="aff2">
    <addr-line>
     aDepartment of Electro-Optical Engineering, National Taipei University of Technology, Taipei City
    </addr-line> 
   </aff> 
   <aff id="aff3">
    <addr-line>
     aThe Affiliated Senior High School, National Taiwan Normal University, Taipei City
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     11
    </day> 
    <month>
     02
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    15
   </volume> 
   <issue>
    01
   </issue>
   <fpage>
    1
   </fpage>
   <lpage>
    19
   </lpage>
   <history>
    <date date-type="received">
     <day>
      29,
     </day>
     <month>
      December
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      8,
     </day>
     <month>
      December
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      8,
     </day>
     <month>
      February
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    A Bose-Einstein condensate (BEC) is a topic of significant interest within the scientific community. It is well understood that Rb-87 and Yb
    <sub>2</sub>Si
    <sub>2</sub>O
    <sub>7</sub> have been utilized in experiments to explore this phenomenon. These studies have demonstrated that these materials can achieve the BEC phase, a state that has been experimentally validated. In this paper, we further establish, from the perspective of theoretical physics, that silicon is also capable of exhibiting BEC properties. Our approach differs from prior studies in that it uses innovatively certain boundary conditions. Specifically, we employed Yb-70 as a gamma-ray radiation source and a 1 nm linewidth (as the half-width of a 2 nm line). Additionally, we utilized the concept of half-value thickness from nuclear physics absorption models to optimize the semiconductor process. This method effectively removes ytterbium (Yb) during the process, leaving only silicon, silicon-based materials, or silicon topological superconductors on the wafer. This technical procedure results in the creation of “BEC silicon” at absolute zero temperature (0 K), introducing a novel material for BEC realization.
   </abstract>
   <kwd-group> 
    <kwd>
     Rb-87
    </kwd> 
    <kwd>
      BEC Phase
    </kwd> 
    <kwd>
      Yb-70
    </kwd> 
    <kwd>
      BEC Silicon
    </kwd> 
    <kwd>
      Absolute Zero Temperature
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>In Ref. <xref ref-type="bibr" rid="scirp.140494-1">
     [1]
    </xref>, it is well established that the first complete realization of Bose-Einstein Condensation (BEC) in the history of science occurred on June 5, 1995, at MIT and the University of Colorado Boulder in the United States. In Ref. <xref ref-type="bibr" rid="scirp.140494-2">
     [2]
    </xref>, scientists discovered that silicon alloys Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub> can successfully achieve the BEC phase. This finding represents a significant milestone in materials physics, highlighting the profound potential of silicon-based materials. It suggests that silicon, silicon alloys, and silicon topological superconductors possess either latent potential or demonstrated capability to achieve the BEC phase. The findings discussed in Refs. <xref ref-type="bibr" rid="scirp.140494-3">
     [3]
    </xref>-<xref ref-type="bibr" rid="scirp.140494-25">
     [25]
    </xref> demonstrate that the technology of Electromagnetically Induced Transparency (EIT) for light storage (quantum storage or mode locking) relies on laser light sources provided externally rather than generated internally by Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub>. By effectively applying the concept of half-value thickness from nuclear physics absorption models, it can be concluded that the ytterbium (Yb) atoms in a Bose-Einstein Condensate (BEC) may be considered absent. This also implies that single-crystal silicon ingots could be excluded at the initial stages of manufacturing. In other words, doping substrates with Yb atoms is unnecessary (as supported in Appendix A), and Yb can be eliminated entirely from the process.</p>
   <p>This paper addresses a long-standing issue in the semiconductor industry: the challenges posed by 1-nanometer circuit nodes (quantum wires). Our work derives and verifies a solution to this critical problem. We have conducted extensive pioneering studies in this area and are now presenting them here. The focus of this paper is to explore whether silicon can achieve BEC and to conduct verification work related to this hypothesis.</p>
   <p>Additionally, we have demonstrated that electron transport through 0.5-nanometer channels is fundamentally prohibited due to quantum mechanical scattering states. Specifically, electrons are scattered by the potential barriers within the channels. Detailed discussions and supporting evidence can be found in Appendices B and C.</p>
   <p>We aim to ensure that these discussions align with experimental procedures and engineering realities. We confirm that this work is the same as the current BEC experiments. This is based on the properties of solid silicon crystals, which naturally play the role of a MOT, and the process of BEC laser cooling silicon is also the same as that of the current laser cooling Rb-87.</p>
  </sec><sec id="s2">
   <title>2. Method</title>
   <sec id="s2_1">
    <title>2.1. Discourses on the Existence of Silicon in BEC Phases</title>
    <p>Based on two fundamental assumptions outlined in Sect. 2.3, the energy gap of diamond-structured silicon at room temperature is denoted as:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mtext>
           Si 
         </mtext> 
         <mo>
           , 
         </mo> 
         <mn>
           300 
         </mn> 
         <mtext>
             
         </mtext> 
         <mtext>
           K 
         </mtext> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               κ 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <msub> 
          <mi>
            m 
          </mi> 
          <mi>
            e 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (1)</p>
    <p>As is widely known, this is an experimental value where the wave vector 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        κ 
      </mi> 
     </math> is used instead of k, since electrons are assumed to exist within the periodic potentials of the lattice structure in single-crystal silicon ingots. When employing Bose-Einstein Condensation (BEC) technology to form Fermi condensation, and in accordance with the principle of energy conservation, it follows that:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mtext>
           Si 
         </mtext> 
         <mo>
           , 
         </mo> 
         <mn>
           0 
         </mn> 
         <mtext>
             
         </mtext> 
         <mtext>
           K 
         </mtext> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         1.12 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         eV 
       </mtext> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          F 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.12 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         eV 
       </mtext> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               k 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <msub> 
          <mi>
            m 
          </mi> 
          <mi>
            e 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (2)</p>
    <p>where 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         C 
       </mi> 
       <mo>
         ≡ 
       </mo> 
       <mn>
         1.12 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         eV 
       </mtext> 
      </mrow> 
     </math>. Therefore,</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
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        </mi> 
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           Si 
         </mtext> 
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         = 
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         C 
       </mi> 
       <mo>
         − 
       </mo> 
       <munder> 
        <mrow> 
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           lim 
         </mi> 
        </mrow> 
        <mtable columnalign="left"> 
         <mtr> 
          <mtd> 
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             </mi> 
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              → 
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              0 
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              + 
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           </mrow> 
          </mtd> 
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             </mi> 
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              → 
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            ) 
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         C 
       </mi> 
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           lim 
         </mi> 
        </mrow> 
        <mtable columnalign="left"> 
         <mtr> 
          <mtd> 
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              → 
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            <mn>
              0 
            </mn> 
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              + 
            </mo> 
           </mrow> 
          </mtd> 
         </mtr> 
         <mtr> 
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           <mrow> 
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             </mi> 
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             </mi> 
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              → 
            </mo> 
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             <mi>
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             </mi> 
             <mi>
               c 
             </mi> 
            </msub> 
           </mrow> 
          </mtd> 
         </mtr> 
        </mtable> 
       </munder> 
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        <mrow> 
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            </mo> 
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              ) 
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         </mn> 
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          </mi> 
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        </mo> 
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               d 
             </mtext> 
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                T 
              </mi> 
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                γ 
              </mi> 
             </msub> 
            </mrow> 
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             </mtext> 
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                T 
              </mi> 
              <mi>
                γ 
              </mi> 
             </msub> 
            </mrow> 
           </mfrac> 
          </mrow> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <mtext>
               d 
             </mtext> 
             <msub> 
              <mi>
                T 
              </mi> 
              <mi>
                c 
              </mi> 
             </msub> 
            </mrow> 
            <mrow> 
             <mtext>
               d 
             </mtext> 
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                T 
              </mi> 
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                γ 
              </mi> 
             </msub> 
            </mrow> 
           </mfrac> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (3)</p>
    <p>(Here two fundamental assumptions would be provided in later sections.)</p>
    <p>Hence</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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         </mtext> 
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           K 
         </mtext> 
        </mrow> 
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          ) 
        </mo> 
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       <mo>
         = 
       </mo> 
       <mi>
         C 
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         − 
       </mo> 
       <munder> 
        <mrow> 
         <mi>
           lim 
         </mi> 
        </mrow> 
        <mtable columnalign="left"> 
         <mtr> 
          <mtd> 
           <mrow> 
            <msub> 
             <mi>
               T 
             </mi> 
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               c 
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            <mo>
              → 
            </mo> 
            <mn>
              0 
            </mn> 
            <mo>
              + 
            </mo> 
           </mrow> 
          </mtd> 
         </mtr> 
         <mtr> 
          <mtd> 
           <mrow> 
            <msub> 
             <mi>
               T 
             </mi> 
             <mi>
               γ 
             </mi> 
            </msub> 
            <mo>
              → 
            </mo> 
            <msub> 
             <mi>
               T 
             </mi> 
             <mi>
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             </mi> 
            </msub> 
           </mrow> 
          </mtd> 
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             </mi> 
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          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
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           2 
         </mn> 
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            m 
          </mi> 
          <mi>
            e 
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       </mfrac> 
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             </mtext> 
             <msub> 
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              </mi> 
              <mi>
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              </mi> 
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             </mtext> 
             <msub> 
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              </mi> 
             </msub> 
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           − 
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       </msup> 
      </mrow> 
     </math> (4)</p>
    <p>When the single-crystal silicon ingot is cooled using a laser, and based on the equation we derived theoretically (partially inspired by the seminal experiment (<sup>87</sup>Rb, 170 nK) conducted in 1995), namely,</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
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        </mi> 
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         = 
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           + 
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            1 
          </mn> 
          <mrow> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mi>
              γ 
            </mi> 
           </msup> 
          </mrow> 
         </mfrac> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
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        </mi> 
       </msub> 
       <mo>
         , 
       </mo> 
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         γ 
       </mi> 
       <mo>
         ≥ 
       </mo> 
       <mn>
         3 
       </mn> 
      </mrow> 
     </math> (5)</p>
    <p>The minimum 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         γ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         3 
       </mn> 
      </mrow> 
     </math> is specifically chosen. The “quantum temperature” (as we refer to it here) of the photons possess<sup>1</sup>—derived as a general result of black-body radiation—is given by</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          γ 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <mn>
             1000 
           </mn> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math> (6)</p>
    <p>Thus we have:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          γ 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           + 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <mn>
             1000 
           </mn> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mtext>
         d 
       </mtext> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
      </mrow> 
     </math> (7)</p>
    <p>By substituting the above equation back into Equation (4), we obtain:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mtext>
             Si 
           </mtext> 
           <mo>
             , 
           </mo> 
           <mn>
             0 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             K 
           </mtext> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mi>
           C 
         </mi> 
         <mo>
           − 
         </mo> 
         <munder> 
          <mrow> 
           <mi>
             lim 
           </mi> 
          </mrow> 
          <mtable columnalign="left"> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 T 
               </mi> 
               <mi>
                 c 
               </mi> 
              </msub> 
              <mo>
                → 
              </mo> 
              <mn>
                0 
              </mn> 
              <mo>
                + 
              </mo> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 T 
               </mi> 
               <mi>
                 γ 
               </mi> 
              </msub> 
              <mo>
                → 
              </mo> 
              <msub> 
               <mi>
                 T 
               </mi> 
               <mi>
                 c 
               </mi> 
              </msub> 
             </mrow> 
            </mtd> 
           </mtr> 
          </mtable> 
         </munder> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ℏ 
               </mi> 
               <mi>
                 k 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <msup> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <mtext>
                d 
              </mtext> 
              <msub> 
               <mi>
                 T 
               </mi> 
               <mi>
                 c 
               </mi> 
              </msub> 
             </mrow> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mn>
                  1 
                </mn> 
                <mo>
                  + 
                </mo> 
                <mrow> 
                 <mn>
                   1 
                 </mn> 
                 <mo>
                   / 
                 </mo> 
                 <mrow> 
                  <mn>
                    1000 
                  </mn> 
                 </mrow> 
                </mrow> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
              <mtext>
                d 
              </mtext> 
              <msub> 
               <mi>
                 T 
               </mi> 
               <mi>
                 c 
               </mi> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msup> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <mo>
           = 
         </mo> 
         <mi>
           C 
         </mi> 
         <mo>
           − 
         </mo> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ℏ 
               </mi> 
               <mi>
                 k 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             1 
           </mn> 
           <mo>
             + 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              / 
            </mo> 
            <mrow> 
             <mn>
               1000 
             </mn> 
            </mrow> 
           </mrow> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math> (8)</p>
    <p>With 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         C 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               κ 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <msub> 
          <mi>
            m 
          </mi> 
          <mi>
            e 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> substituted back into Equation (8), hence</p>
    <p>Similarly, with 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         C 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msup> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               κ 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <msub> 
          <mi>
            m 
          </mi> 
          <mi>
            e 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> substituted back into Equation (8), we derive:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mtext>
             Si 
           </mtext> 
           <mo>
             , 
           </mo> 
           <mn>
             0 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             K 
           </mtext> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ℏ 
               </mi> 
               <mi>
                 k 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mo>
           − 
         </mo> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ℏ 
               </mi> 
               <mi>
                 k 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             1 
           </mn> 
           <mo>
             + 
           </mo> 
           <mfrac> 
            <mn>
              1 
            </mn> 
            <mrow> 
             <mn>
               1000 
             </mn> 
            </mrow> 
           </mfrac> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ℏ 
               </mi> 
               <mi>
                 k 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mn>
             1 
           </mn> 
           <mo>
             − 
           </mo> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               1 
             </mn> 
             <mo>
               + 
             </mo> 
             <mfrac> 
              <mn>
                1 
              </mn> 
              <mrow> 
               <mn>
                 1000 
               </mn> 
              </mrow> 
             </mfrac> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <mo>
           = 
         </mo> 
         <mo>
           − 
         </mo> 
         <mfrac> 
          <mn>
            1 
          </mn> 
          <mrow> 
           <mn>
             1000 
           </mn> 
          </mrow> 
         </mfrac> 
         <mo>
           ⋅ 
         </mo> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ℏ 
               </mi> 
               <mi>
                 k 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math> (9)</p>
    <p>Since</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         k 
       </mi> 
       <mover> 
        <mo>
          → 
        </mo> 
        <mover accent="true"> 
         <mi>
           T 
         </mi> 
         <mo>
           ^ 
         </mo> 
        </mover> 
       </mover> 
       <mi>
         κ 
       </mi> 
      </mrow> 
     </math> (10)</p>
    <p>Therefore,</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mtext>
           Si 
         </mtext> 
         <mo>
           , 
         </mo> 
         <mn>
           0 
         </mn> 
         <mtext>
             
         </mtext> 
         <mtext>
           K 
         </mtext> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <mn>
           1000 
         </mn> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <munder> 
        <munder> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msup> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mi>
                  ℏ 
                </mi> 
                <mi>
                  κ 
                </mi> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <msub> 
             <mi>
               m 
             </mi> 
             <mi>
               e 
             </mi> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo stretchy="true">
           ︸ 
         </mo> 
        </munder> 
        <mrow> 
         <mo>
           = 
         </mo> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mtext>
             Si 
           </mtext> 
           <mo>
             , 
           </mo> 
           <mn>
             300 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             K 
           </mtext> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </munder> 
       <mo>
         &lt; 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> (11)</p>
    <p>It is evident that as the temperature of the single-crystal silicon ingot approaches absolute 0 K, the energy gap of the ingot enters a bound state. This indicates that the electron becomes completely confined within the material.</p>
    <p>When considering only the first Brillouin zone, any arbitrary wave vector in the reciprocal lattice space, based on the wave vector 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        k 
      </mi> 
     </math>, can be analyzed using Bloch’s theorem. After the application of the translation operator 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mover accent="true"> 
       <mi>
         T 
       </mi> 
       <mo>
         ^ 
       </mo> 
      </mover> 
     </math>, the resulting state becomes 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         k 
       </mi> 
       <mover> 
        <mo>
          → 
        </mo> 
        <mover accent="true"> 
         <mi>
           T 
         </mi> 
         <mo>
           ^ 
         </mo> 
        </mover> 
       </mover> 
       <mi>
         κ 
       </mi> 
      </mrow> 
     </math>, as described above. In the next section, we introduce and discuss the concepts of coherent states.</p>
    <p>The above discussion strongly supports the argument that 1 nm wire manufacturing necessitates the use of BEC-silicon, achieved through laser cooling. In practice, Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub> can serve as a suitable BEC material, as supported by known experimental data. Furthermore, due to the influence of channel sizes (as detailed in Equations (21) - (25) below), silicon retains its prominence as a widely used material for 1 nm wires.</p>
   </sec>
   <sec id="s2_2">
    <title>2.2. Examination: Consistency (I)</title>
    <p>It is widely known that silicon atoms possess four covalent electrons in their outer shells. When silicon atoms bond with one another, they form shared electron pairs. These electron pairs exhibit physical behavior analogous to “Cooper pairs” as described in BCS theory, particularly at temperatures approaching absolute zero (0 K). For simplicity, we express the relevant quantum mechanical (QM) equations as follows:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          E 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              ψ 
            </mi> 
            <mi>
              n 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            〉 
          </mo> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          n 
        </mi> 
       </msub> 
      </mrow> 
     </math> (12)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          E 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <msup> 
           <mi>
             n 
           </mi> 
           <mo>
             ′ 
           </mo> 
          </msup> 
          <mo>
            = 
          </mo> 
          <mn>
            0 
          </mn> 
         </mrow> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              ψ 
            </mi> 
            <msup> 
             <mi>
               n 
             </mi> 
             <mo>
               ′ 
             </mo> 
            </msup> 
           </msub> 
          </mrow> 
          <mo>
            〉 
          </mo> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          E 
        </mi> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </msub> 
      </mrow> 
     </math> (13)</p>
    <p>Here, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mo>
          { 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            n 
          </mi> 
         </msub> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            E 
          </mi> 
          <msup> 
           <mi>
             n 
           </mi> 
           <mo>
             ′ 
           </mo> 
          </msup> 
         </msub> 
        </mrow> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math> represents a mathematical “ensemble of energy eigenvalues” for quantum particles in physics. Photons produced through laser cooling are effectively described by Equation (12) (photon ensembles), while the pair-electrons in silicon atoms are accurately modeled by Equation (13) (electron ensembles).</p>
    <p>When coherent states emerge in silicon systems, it indicates that 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mi>
          n 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         n 
       </mi> 
       <mo>
         ≠ 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> Equation (12) specifically applies to laser photons. In this context, we attempt to compute the inner product of the states described by the above two equations. In other words,</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mstyle displaystyle="true"> 
          <munderover> 
           <mo>
             ∑ 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               n 
             </mi> 
             <mo>
               ′ 
             </mo> 
            </msup> 
            <mo>
              = 
            </mo> 
            <mn>
              0 
            </mn> 
           </mrow> 
           <mi>
             ∞ 
           </mi> 
          </munderover> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msup> 
              <mrow> 
               <mrow> 
                <mo>
                  〈 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <msup> 
                   <mi>
                     n 
                   </mi> 
                   <mo>
                     ′ 
                   </mo> 
                  </msup> 
                 </msub> 
                </mrow> 
                <mo>
                  | 
                </mo> 
               </mrow> 
              </mrow> 
              <mtext>
                * 
              </mtext> 
             </msup> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ⋅ 
           </mo> 
           <mrow> 
            <mo>
              | 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ψ 
              </mi> 
              <mi>
                n 
              </mi> 
             </msub> 
            </mrow> 
            <mo>
              〉 
            </mo> 
           </mrow> 
          </mrow> 
         </mstyle> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math> (14)</p>
    <p>Next, we apply the energy operator twice to Equation (14), yielding:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mover accent="true"> 
         <mi>
           E 
         </mi> 
         <mo>
           ^ 
         </mo> 
        </mover> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mstyle displaystyle="true"> 
          <munderover> 
           <mo>
             ∑ 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               n 
             </mi> 
             <mo>
               ′ 
             </mo> 
            </msup> 
            <mo>
              = 
            </mo> 
            <mn>
              0 
            </mn> 
           </mrow> 
           <mi>
             ∞ 
           </mi> 
          </munderover> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msup> 
              <mrow> 
               <mrow> 
                <mo>
                  〈 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <msup> 
                   <mi>
                     n 
                   </mi> 
                   <mo>
                     ′ 
                   </mo> 
                  </msup> 
                 </msub> 
                </mrow> 
                <mo>
                  | 
                </mo> 
               </mrow> 
              </mrow> 
              <mtext>
                * 
              </mtext> 
             </msup> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ⋅ 
           </mo> 
           <mrow> 
            <mo>
              | 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ψ 
              </mi> 
              <mi>
                n 
              </mi> 
             </msub> 
            </mrow> 
            <mo>
              〉 
            </mo> 
           </mrow> 
          </mrow> 
         </mstyle> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math> (15)</p>
    <p>Furthermore, leveraging the linearity of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mover accent="true"> 
       <mi>
         E 
       </mi> 
       <mo>
         ^ 
       </mo> 
      </mover> 
     </math>, we derive:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          E 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mover accent="true"> 
            <mi>
              E 
            </mi> 
            <mo>
              ^ 
            </mo> 
           </mover> 
           <mstyle displaystyle="true"> 
            <munderover> 
             <mo>
               ∑ 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 n 
               </mi> 
               <mo>
                 ′ 
               </mo> 
              </msup> 
              <mo>
                = 
              </mo> 
              <mn>
                0 
              </mn> 
             </mrow> 
             <mi>
               ∞ 
             </mi> 
            </munderover> 
            <mrow> 
             <msup> 
              <mrow> 
               <mrow> 
                <mo>
                  〈 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <msup> 
                   <mi>
                     n 
                   </mi> 
                   <mo>
                     ′ 
                   </mo> 
                  </msup> 
                 </msub> 
                </mrow> 
                <mo>
                  | 
                </mo> 
               </mrow> 
              </mrow> 
              <mtext>
                * 
              </mtext> 
             </msup> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              ψ 
            </mi> 
            <mi>
              n 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            〉 
          </mo> 
         </mrow> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math> (16)</p>
    <p>By applying Equation (12) and Equation (13), and considering the photon ensembles from the laser source (as demonstrated in the calculation of the equation’s right-hand side below), we obtain<sup>2</sup>:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          E 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mover accent="true"> 
            <mi>
              E 
            </mi> 
            <mo>
              ^ 
            </mo> 
           </mover> 
           <mstyle displaystyle="true"> 
            <munderover> 
             <mo>
               ∑ 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 n 
               </mi> 
               <mo>
                 ′ 
               </mo> 
              </msup> 
              <mo>
                = 
              </mo> 
              <mn>
                0 
              </mn> 
             </mrow> 
             <mi>
               ∞ 
             </mi> 
            </munderover> 
            <mrow> 
             <msup> 
              <mrow> 
               <mrow> 
                <mo>
                  〈 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <msup> 
                   <mi>
                     n 
                   </mi> 
                   <mo>
                     ′ 
                   </mo> 
                  </msup> 
                 </msub> 
                </mrow> 
                <mo>
                  | 
                </mo> 
               </mrow> 
              </mrow> 
              <mtext>
                * 
              </mtext> 
             </msup> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              ψ 
            </mi> 
            <mi>
              n 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            〉 
          </mo> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <msubsup> 
        <mi>
          E 
        </mi> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
        <mo>
          * 
        </mo> 
       </msubsup> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          n 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          | 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            E 
          </mi> 
          <msup> 
           <mi>
             n 
           </mi> 
           <mo>
             ′ 
           </mo> 
          </msup> 
         </msub> 
        </mrow> 
        <mo>
          | 
        </mo> 
       </mrow> 
       <mrow> 
        <mo>
          | 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            n 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          | 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              E 
            </mi> 
            <mi>
              n 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            | 
          </mo> 
         </mrow> 
        </mrow> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         = 
       </mo> 
       <msubsup> 
        <mi>
          E 
        </mi> 
        <mi>
          n 
        </mi> 
        <mn>
          2 
        </mn> 
       </msubsup> 
      </mrow> 
     </math> (17)</p>
    <p>Finally, taking the square root of both sides of Equation (17),</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          E 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <mstyle displaystyle="true"> 
            <munderover> 
             <mo>
               ∑ 
             </mo> 
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              <msup> 
               <mi>
                 n 
               </mi> 
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                 ′ 
               </mo> 
              </msup> 
              <mo>
                = 
              </mo> 
              <mn>
                0 
              </mn> 
             </mrow> 
             <mi>
               ∞ 
             </mi> 
            </munderover> 
            <mrow> 
             <mstyle displaystyle="true"> 
              <munderover> 
               <mo>
                 ∑ 
               </mo> 
               <mrow> 
                <mi>
                  n 
                </mi> 
                <mo>
                  = 
                </mo> 
                <mn>
                  1 
                </mn> 
               </mrow> 
               <mi>
                 ∞ 
               </mi> 
              </munderover> 
              <mrow> 
               <mrow> 
                <mo>
                  〈 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <msup> 
                   <mi>
                     n 
                   </mi> 
                   <mo>
                     ′ 
                   </mo> 
                  </msup> 
                 </msub> 
                </mrow> 
                <mo>
                  | 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <mi>
                    n 
                  </mi> 
                 </msub> 
                </mrow> 
                <mo>
                  〉 
                </mo> 
               </mrow> 
              </mrow> 
             </mstyle> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            | 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          | 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            n 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          | 
        </mo> 
       </mrow> 
       <mo>
         &gt; 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         , 
       </mo> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mi>
          n 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mrow> 
     </math> (18)</p>
    <p>And,</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mover accent="true"> 
        <mi>
          E 
        </mi> 
        <mo>
          ^ 
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       </mover> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <mstyle displaystyle="true"> 
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             <mo>
               ∑ 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 n 
               </mi> 
               <mo>
                 ′ 
               </mo> 
              </msup> 
              <mo>
                = 
              </mo> 
              <mn>
                0 
              </mn> 
             </mrow> 
             <mi>
               ∞ 
             </mi> 
            </munderover> 
            <mrow> 
             <mstyle displaystyle="true"> 
              <munderover> 
               <mo>
                 ∑ 
               </mo> 
               <mrow> 
                <mi>
                  n 
                </mi> 
                <mo>
                  = 
                </mo> 
                <mn>
                  1 
                </mn> 
               </mrow> 
               <mi>
                 ∞ 
               </mi> 
              </munderover> 
              <mrow> 
               <mrow> 
                <mo>
                  〈 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <msup> 
                   <mi>
                     n 
                   </mi> 
                   <mo>
                     ′ 
                   </mo> 
                  </msup> 
                 </msub> 
                </mrow> 
                <mo>
                  | 
                </mo> 
                <mrow> 
                 <msub> 
                  <mi>
                    ψ 
                  </mi> 
                  <mi>
                    n 
                  </mi> 
                 </msub> 
                </mrow> 
                <mo>
                  〉 
                </mo> 
               </mrow> 
              </mrow> 
             </mstyle> 
            </mrow> 
           </mstyle> 
          </mrow> 
          <mo>
            | 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         , 
       </mo> 
       <mi>
         n 
       </mi> 
       <mo>
         ≠ 
       </mo> 
       <msup> 
        <mi>
          n 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mrow> 
     </math> (19)</p>
    <p>Finally, taking the square root of both sides of Equation (17), Equation (18) reveals that coherent states emerge as 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mi>
          n 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mrow> 
     </math>. Consequently, we obtain the eigenvalues of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          n 
        </mi> 
       </msub> 
       <mo>
         &gt; 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mi>
          n 
        </mi> 
       </msub> 
       <mo>
         &lt; 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math>, respectively, with the latter corresponding exactly to Equation (11).</p>
    <p>It is important to note that the energy gap is one of the eigenvalue solutions of the Schrödinger equation in the context of solid-state physics. Through quantum mechanics (QM), we have provided strong evidence to support this paper, particularly the precise arguments presented in this section.</p>
   </sec>
   <sec id="s2_3">
    <title>2.3. Examination of Consistency (II)</title>
    <p>According to Equation (11) in Sect. 2.1, it is evident that</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
       <mtr> 
        <mtd> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              E 
            </mi> 
            <mi>
              g 
            </mi> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mtext>
               Si 
             </mtext> 
             <mo>
               , 
             </mo> 
             <mn>
               0 
             </mn> 
             <mtext>
                 
             </mtext> 
             <mtext>
               K 
             </mtext> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            | 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mn>
            1 
          </mn> 
          <mrow> 
           <mn>
             1000 
           </mn> 
          </mrow> 
         </mfrac> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            E 
          </mi> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mtext>
             Si 
           </mtext> 
           <mo>
             , 
           </mo> 
           <mn>
             300 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             K 
           </mtext> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mn>
            1 
          </mn> 
          <mrow> 
           <mn>
             1000 
           </mn> 
          </mrow> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             1.12 
           </mn> 
           <mtext>
               
           </mtext> 
           <mtext>
             eV 
           </mtext> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <mo>
           = 
         </mo> 
         <mtext>
           0 
         </mtext> 
         <mtext>
           .00112 
         </mtext> 
         <mtext>
             
         </mtext> 
         <mtext>
           eV 
         </mtext> 
         <mo>
           ≈ 
         </mo> 
         <msup> 
          <mn>
            10 
          </mn> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             3 
           </mn> 
          </mrow> 
         </msup> 
         <mtext>
             
         </mtext> 
         <mtext>
           eV 
         </mtext> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math> (20)</p>
    <p>Based on the fundamental conditions of a Fermi condensate and the formation of “Cooper pairs,” the system’s energy for electron pairs (e.g., the energy gap) must be reduced below ~10<sup>−</sup><sup>3</sup> eV. This inference aligns well with widely recognized facts, reinforcing the consistency of our findings.</p>
    <p><sup>2</sup>Here, we focus on Equation (2) and Equation (3) and subsequently provide two fundamental assumptions for them, as outlined below.</p>
    <p>Fundamental Assumption I</p>
    <p>One of a silicon atom’s covalent bonds shares two outer electrons, whose physical behavior during Fermi condensation at extremely low temperatures resembles <sup>87</sup>Rb - <sup>87</sup>Rb in solid-state systems at absolute zero.</p>
    <p>Fundamental Assumption II</p>
    <p>Considering the Fermi-Dirac distribution, the probability of 1/2 corresponds to the energy level at which an electron occupies the Fermi energy level. This resultsin 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         0 
       </mn> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           ε 
         </mi> 
         <mo>
           − 
         </mo> 
         <mi>
           μ 
         </mi> 
        </mrow> 
        <mrow> 
         <mi>
           k 
         </mi> 
         <mi>
           T 
         </mi> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math>, which is directly associated with the discussion above. Hence, we can sufficiently assume 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         k 
       </mi> 
       <mi>
         ε 
       </mi> 
       <mo>
         = 
       </mo> 
       <mi>
         k 
       </mi> 
       <mi>
         μ 
       </mi> 
      </mrow> 
     </math>, and it is evident that 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1 
       </mn> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           k 
         </mi> 
         <mi>
           μ 
         </mi> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mi>
           k 
         </mi> 
         <mi>
           ε 
         </mi> 
        </mrow> 
       </mrow> 
       <mo>
         ≡ 
       </mo> 
       <mrow> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            γ 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            C 
          </mi> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math> at absolute 0 K. Notably, electrons are nearly fully populated at the Fermi energy 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        ε 
      </mi> 
     </math> during Bose-Einstein Condensation (BEC). As the system’s temperature is further reduced toward absolute zero, the Fermi energy of the electron aligns precisely with the Fermi energy level. Consequently, the electron possesses 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1 
       </mn> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            γ 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            C 
          </mi> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math>, as described in the assumption above. Furthermore, this relationship forms an “implicit equation,” which can be mathematically expressed as 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          γ 
        </mi> 
       </msub> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          C 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math>, using principles from calculus.</p>
   </sec>
  </sec><sec id="s3">
   <title>3. Results And Discussion</title>
   <sec id="s3_1">
    <title>3.1. Results Analysis</title>
    <p>Let us directly apply the technique of topological mapping in advanced physical mathematics (i.e., conformal mapping) to the manufactured line widths of the material Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub>, such that</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         2 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
       <mo>
         ↦ 
       </mo> 
       <mn>
         1 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math> (21)</p>
    <p>This is because 1 nm is precisely half the width of 2 nm, and a quantum barrier occurred at solid angle of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Ω 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         4 
       </mn> 
       <mi>
         π 
       </mi> 
      </mrow> 
     </math> (refer to Appendix B). It is widely known that the half-value thickness in an absorption model of nuclear physics refers to the thickness of a barrier material required to reduce the intensity of an incident ray to half its original value. Consequently, the value of the semi-absorbing thickness is</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           ln 
         </mi> 
         <mn>
           2 
         </mn> 
        </mrow> 
        <mi>
          γ 
        </mi> 
       </mfrac> 
       <mo>
         ≈ 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           0.693 
         </mn> 
        </mrow> 
        <mi>
          γ 
        </mi> 
       </mfrac> 
       <mo>
         ≠ 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> (22)</p>
    <p>Here, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        γ 
      </mi> 
     </math> denotes the absorption coefficient of the barrier material for incident rays. It is well known that when the circuit’s short width is 2 nm, no significant quantum effects occur (as commonly understood). Consequently, there is no need to consider whether it could represent a Bose-Einstein Condensate (BEC) phase.</p>
    <p>However, when the circuit component is exactly reduced to 1 nm, the situation changes significantly. According to the Fresnel diffraction formula and the Huygens-Fresnel principle in near-field optics, a pronounced quantum tunneling effect is observed. Notably, the probability of the electron’s tunneling effect in a 2 nm circuit is precisely 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          / 
        </mo> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </mrow> 
     </math> times that of a 1 nm circuit. Considering the physical significance of “skin depth” and referencing Equation (21), we have strictly derived<sup>3</sup>:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         0.5 
       </mn> 
       <msub> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           ln 
         </mi> 
         <mn>
           1 
         </mn> 
        </mrow> 
        <msup> 
         <mi>
           γ 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> (23)</p>
    <p>Here, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          γ 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mo>
         ≡ 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         γ 
       </mi> 
      </mrow> 
     </math>. This result arises from considering the inverse scenario of using Yb as a “gamma-ray source” at the 1 nm circuit component line width’s node. Using this perspective, we have identified the following mathematical techniques to calculate the “half-value thickness of absorption” for gamma-rays in the circuit component line width (specifically, the numerator of ln2 in Equation (22)):</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mtable columnalign="left"> 
         <mtr> 
          <mtd> 
           <mfrac> 
            <mrow> 
             <mtext>
               d 
             </mtext> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 − 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mo>
               ! 
             </mo> 
            </mrow> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 − 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mo>
               ! 
             </mo> 
            </mrow> 
           </mfrac> 
           <mo>
             = 
           </mo> 
           <mtext>
             d 
           </mtext> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ln 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 − 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mo>
               ! 
             </mo> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             ≈ 
           </mo> 
           <mtext>
             d 
           </mtext> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 − 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mi>
               ln 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 − 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mo>
               − 
             </mo> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 − 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             , 
           </mo> 
           <mi>
             x 
           </mi> 
           <mo>
             ≠ 
           </mo> 
           <mn>
             1 
           </mn> 
          </mtd> 
         </mtr> 
         <mtr> 
          <mtd> 
           <mfrac> 
            <mrow> 
             <mtext>
               d 
             </mtext> 
             <mi>
               x 
             </mi> 
            </mrow> 
            <mi>
              x 
            </mi> 
           </mfrac> 
           <mo>
             = 
           </mo> 
           <mtext>
             d 
           </mtext> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ln 
             </mi> 
             <mi>
               x 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             , 
           </mo> 
           <mstyle displaystyle="true"> 
            <mrow> 
             <munderover> 
              <mo>
                ∫ 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 = 
               </mo> 
               <mn>
                 1 
               </mn> 
               <mtext>
                   
               </mtext> 
               <mtext>
                 nm 
               </mtext> 
              </mrow> 
              <mrow> 
               <mn>
                 2 
               </mn> 
               <mtext>
                   
               </mtext> 
               <mtext>
                 nm 
               </mtext> 
              </mrow> 
             </munderover> 
             <mrow> 
              <mtext>
                d 
              </mtext> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mi>
                  ln 
                </mi> 
                <mi>
                  x 
                </mi> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mrow> 
           </mstyle> 
           <mover> 
            <mo>
              = 
            </mo> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 B 
               </mi> 
               <mo>
                 . 
               </mo> 
               <mi>
                 C 
               </mi> 
               <mo>
                 . 
               </mo> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </mover> 
           <msubsup> 
            <mrow> 
             <mrow> 
              <mi>
                ln 
              </mi> 
              <mi>
                x 
              </mi> 
             </mrow> 
             <mo>
               | 
             </mo> 
            </mrow> 
            <mrow> 
             <mi>
               x 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               1 
             </mn> 
             <mtext>
                 
             </mtext> 
             <mtext>
               nm 
             </mtext> 
            </mrow> 
            <mrow> 
             <mn>
               2 
             </mn> 
             <mtext>
                 
             </mtext> 
             <mtext>
               nm 
             </mtext> 
            </mrow> 
           </msubsup> 
           <mo>
             = 
           </mo> 
           <mi>
             ln 
           </mi> 
           <mn>
             2 
           </mn> 
           <mo>
             ≈ 
           </mo> 
           <mn>
             0.693 
           </mn> 
          </mtd> 
         </mtr> 
        </mtable> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (24)</p>
    <p>It is not difficult to find that the above is in agreement with what is revealed by the half-value thickness of an absorption model in nuclear physics.</p>
    <p>Furthermore, by considering the continuous variations in the component line width during the manufacturing process (i.e., a homeomorphism mapping, where all manufacturing processes can theoretically be represented along the time-axis, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         2 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
       <mo>
         ↦ 
       </mo> 
       <mn>
         1 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
       <mo>
         ↦ 
       </mo> 
       <msup> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
       </msup> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math>), thus we obtain:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mtable columnalign="left"> 
         <mtr> 
          <mtd> 
           <msub> 
            <mrow> 
             <mrow> 
              <mfrac> 
               <mrow> 
                <mtext>
                  d 
                </mtext> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    x 
                  </mi> 
                  <mo>
                    − 
                  </mo> 
                  <mn>
                    1 
                  </mn> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <mo>
                  ! 
                </mo> 
               </mrow> 
               <mrow> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    x 
                  </mi> 
                  <mo>
                    − 
                  </mo> 
                  <mn>
                    1 
                  </mn> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <mo>
                  ! 
                </mo> 
               </mrow> 
              </mfrac> 
             </mrow> 
             <mo>
               | 
             </mo> 
            </mrow> 
            <mrow> 
             <mi>
               x 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </msub> 
           <mo>
             ≈ 
           </mo> 
           <msub> 
            <mrow> 
             <mrow> 
              <mtext>
                d 
              </mtext> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    x 
                  </mi> 
                  <mo>
                    − 
                  </mo> 
                  <mn>
                    1 
                  </mn> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <mi>
                  ln 
                </mi> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    x 
                  </mi> 
                  <mo>
                    − 
                  </mo> 
                  <mn>
                    1 
                  </mn> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <mo>
                  − 
                </mo> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    x 
                  </mi> 
                  <mo>
                    − 
                  </mo> 
                  <mn>
                    1 
                  </mn> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
             <mo>
               | 
             </mo> 
            </mrow> 
            <mrow> 
             <mi>
               x 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <msub> 
            <mrow> 
             <mrow> 
              <mi>
                ln 
              </mi> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mi>
                  x 
                </mi> 
                <mo>
                  − 
                </mo> 
                <mn>
                  1 
                </mn> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
              <mtext>
                d 
              </mtext> 
              <mi>
                x 
              </mi> 
             </mrow> 
             <mo>
               | 
             </mo> 
            </mrow> 
            <mrow> 
             <mi>
               x 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             0 
           </mn> 
          </mtd> 
         </mtr> 
         <mtr> 
          <mtd> 
           <mfrac> 
            <mrow> 
             <mtext>
               d 
             </mtext> 
             <mi>
               x 
             </mi> 
            </mrow> 
            <mi>
              x 
            </mi> 
           </mfrac> 
           <mo>
             = 
           </mo> 
           <mtext>
             d 
           </mtext> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ln 
             </mi> 
             <mi>
               x 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             , 
           </mo> 
           <mstyle displaystyle="true"> 
            <mrow> 
             <munderover> 
              <mo>
                ∫ 
              </mo> 
              <mrow> 
               <mi>
                 x 
               </mi> 
               <mo>
                 = 
               </mo> 
               <msup> 
                <mn>
                  1 
                </mn> 
                <mo>
                  − 
                </mo> 
               </msup> 
               <mtext>
                 nm 
               </mtext> 
              </mrow> 
              <mrow> 
               <mn>
                 1 
               </mn> 
               <mtext>
                   
               </mtext> 
               <mtext>
                 nm 
               </mtext> 
              </mrow> 
             </munderover> 
             <mrow> 
              <mtext>
                d 
              </mtext> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mi>
                  ln 
                </mi> 
                <mi>
                  x 
                </mi> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mrow> 
           </mstyle> 
           <mover> 
            <mo>
              = 
            </mo> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 B 
               </mi> 
               <mo>
                 . 
               </mo> 
               <mi>
                 C 
               </mi> 
               <mo>
                 . 
               </mo> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </mover> 
           <msup> 
            <mn>
              0 
            </mn> 
            <mo>
              + 
            </mo> 
           </msup> 
          </mtd> 
         </mtr> 
        </mtable> 
        <mo>
          } 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (25)</p>
    <p>Evidently, the result of the formula in Equation (25) is physically equivalent to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         ln 
       </mi> 
       <mn>
         1 
       </mn> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
      </mrow> 
     </math> (i.e., the extremely small error can be completely ignored in physics). Thus, it is identical to the numerator of Equation (23).</p>
    <p>It is important to note that after topological mapping, the left and right boundary conditions (B.C.) of the 1 nm component line width become significantly narrower than those described in Equation (24), as indicated by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           − 
         </mo> 
         <msup> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
         </msup> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mtext>
         nm 
       </mtext> 
       <mo>
         ≪ 
       </mo> 
       <mn>
         1 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math>.</p>
   </sec>
   <sec id="s3_2">
    <title>3.2. Theoretical Analysis</title>
    <p>According to Equation (23), the gamma-ray’s penetrating ability is revealed to be zero, which physically signifies “no penetration.” This paradox can be resolved in one of two ways:</p>
    <p>(A) the absence of gamma-ray photons, or (B) the component has automatically undergone light storage (or quantum storage).</p>
    <p>It is clear that case (B) must be discarded. This is because light storage relies on photons <xref ref-type="bibr" rid="scirp.140494-3">
      [3]
     </xref>-<xref ref-type="bibr" rid="scirp.140494-25">
      [25]
     </xref> supplied by an external EIT light source rather than being generated internally by Yb atoms. Therefore, the correct solution is case (A): the source of gamma-rays does not exist or is not necessary initially. Consequently, it becomes evident that doping Yb is redundant and unnecessary in the semiconductor manufacturing process for a 1 nm line width. It is worth noting that the above represents a simple and elegant application of phenomenological techniques in theoretical physics.</p>
    <p>It is important to note that the 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         U 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          1 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> gauge symmetry breaking discussed in Ref. <xref ref-type="bibr" rid="scirp.140494-2">
      [2]
     </xref> actually refers to the 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         S 
       </mi> 
       <mi>
         U 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          3 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         × 
       </mo> 
       <mi>
         U 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          1 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> gauge symmetry group. Specifically, this indicates that the physical size of the electron remains constant at the turning point 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            r 
          </mi> 
          <mtext>
            0 
          </mtext> 
         </msub> 
         <mo>
           ≈ 
         </mo> 
         <mtext>
           1 
         </mtext> 
         <mtext>
           .954 fm 
         </mtext> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> of the Yukawa potential <xref ref-type="bibr" rid="scirp.140494-26">
      [26]
     </xref>. (The detailed discussion of this topic is lengthy and highly complex; we will provide full proof in a forthcoming paper.)</p>
    <p>In this context, electrons and photons involved in the EIT effect remain quantum entangled to sustain Bose-Einstein Condensation (BEC) at extremely low temperatures approaching absolute zero. This quantum entanglement manifests in the behavior of photoelectrons, wherein these two elementary particles 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           γ 
         </mi> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            e 
          </mi> 
          <mo>
            − 
          </mo> 
         </msup> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> exchange their wave functions during the process <xref ref-type="bibr" rid="scirp.140494-3">
      [3]
     </xref>-<xref ref-type="bibr" rid="scirp.140494-25">
      [25]
     </xref>. Evidently, silicon is entirely suitable as a material for achieving BEC, reinforcing its critical role in the semiconductor industry. The reasons for this have already been successfully deduced using principles of solid-state physics, as discussed earlier.</p>
    <p>Particular we indicated it that in Equation (C.2), since that in current semiconductor industrial, where one overcomes the problem of electron tunneling effects (i.e., so-called “punch through”) is by using solutions: the method named “high-κ dielectric”. As far, we can see later on (Equation (C.2) in Appendix C), the terms of voltage: V (inversely proportional to above 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msqrt> 
        <mi>
          κ 
        </mi> 
       </msqrt> 
      </mrow> 
     </math> dielectric ( 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          / 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
       <mo>
         ∝ 
       </mo> 
       <mi>
         κ 
       </mi> 
      </mrow> 
     </math>)) such reflects to the shorter thickness 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        t 
      </mi> 
     </math> of the tunnels (notice that the structure is around 3 nm). This complete agrees with the deductions and physical pictures by Equations. (21) - (25). Since that at constant wavelengths, the higher 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        κ 
      </mi> 
     </math> dielectric as smaller thickness of the tunnels, but the difference is that we adopt the BEC laser and the EIT artificial, in contrast, instead of adopting the solution by “high-κ dielectric”<sup>4</sup>. This grant reduces its multiple-steps in semiconductor manufacturing, and simultaneously obtained the same results of extending Moore’s law.</p>
   </sec>
  </sec><sec id="s4">
   <title>4. Conclusion</title>
   <p>Based on the discussions in sections 2 and 3 previously, we have deduced that silicon can serve as one of the standard materials for a Fermi condensate. With appropriate transformations or technical manipulations—typically within the framework of BCS theory (e.g., effective applications of Cooper pairs)—a Fermi condensate can be sufficiently transformed into a Bose-Einstein condensate. In the manufacturing process, the intrinsic properties of silicon are preserved. Using quantum processing technologies, such as the so-called “light storage of EIT,” silicon can be advanced into a novel material known as a “silicon topological superconductor.” However, the fabrication of 0.5 nm channels is not feasible (it is explicitly prohibited). For further details on this specific case, refer to Appendices B and C.</p>
  </sec><sec id="s5">
   <title>Acknowledgements</title>
   <p>After the completion of this paper, we would like to extend our gratitude to the exchange student from Switzerland, studying in the Department of Computer Engineering at National Yang Ming Chiao Tung University, Taiwan region, for providing valuable advice that contributed to this work.</p>
  </sec><sec id="s6">
   <title>Appendix A: Numbers of Atoms Allowed</title>
   <p>Fundamentally, Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub> contains 11 atoms but does not allow its 11th atom to be accommodated within 1-nanometer wires, assuming an average atomic size of 0.1 nm, i.e.,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        11 
      </mn> 
      <mo>
        ⋅ 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0.1 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        1.1 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
      <mo>
        ≥ 
      </mo> 
      <mn>
        1 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (A.1)</p>
   <p>Clearly, a matter of 0.1 nm cannot fit, indicating that one atom would be cut, leading to boundary effects. Such effects are not permissible in a 1-nanometer channel.</p>
   <p>For silicon, with a lattice constant of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        a 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0.543 
      </mn> 
      <mtext>
          
      </mtext> 
      <mi>
        Å 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
       <mrow> 
        <mtext>
          18 
        </mtext> 
        <mtext>
          .4162 
        </mtext> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> and a face-centered cubic (F.C.C.) structure, silicon atoms can be fully accommodated without cutting. This configuration allows for a maximum of 10 silicon atoms to be arranged within 1-nanometer wires.</p>
   <p>Restriction of Boundary Effect: Nanowires cannot permit non-integer numbers of atoms to be accommodated within a channel. As the size of the nanowire decreases, the ratio of surface atoms to the total number of atoms increases, making the “boundary effect” more pronounced <xref ref-type="bibr" rid="scirp.140494-27">
     [27]
    </xref>. At this scale, if an atom is cut, it leads to a violation of the boundary effect, which also contradicts the quantization effect. As noted in Ref. <xref ref-type="bibr" rid="scirp.140494-27">
     [27]
    </xref>, quantum size effects, quantum interference effects, and general quantization effects strongly support the arguments presented in this paper.</p>
   <p><u>Remark</u><u>.</u></p>
   <p>Considering the atomic radius of silicon (111 pm), we next examine the constraints of a 1 nm channel. Specifically, this requires the exclusion of two silicon atoms to avoid boundary effects. Based on this, we initially obtain</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <mfrac> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            nm 
          </mtext> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mo>
            × 
          </mo> 
          <mn>
            111 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            pm 
          </mtext> 
          <mo>
            + 
          </mo> 
          <mi>
            a 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msup> 
           <mrow> 
            <mn>
              10 
            </mn> 
           </mrow> 
           <mrow> 
            <mo>
              − 
            </mo> 
            <mn>
              9 
            </mn> 
           </mrow> 
          </msup> 
          <mtext>
              
          </mtext> 
          <mtext>
            m 
          </mtext> 
         </mrow> 
         <mrow> 
          <mn>
            222 
          </mn> 
          <mo>
            × 
          </mo> 
          <msup> 
           <mrow> 
            <mn>
              10 
            </mn> 
           </mrow> 
           <mrow> 
            <mo>
              − 
            </mo> 
            <mn>
              13 
            </mn> 
           </mrow> 
          </msup> 
          <mtext>
              
          </mtext> 
          <mtext>
            m 
          </mtext> 
          <mo>
            + 
          </mo> 
          <mn>
            0.543 
          </mn> 
          <mtext>
              
          </mtext> 
          <mi>
            Å 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <mo>
          ≈ 
        </mo> 
        <mn>
          13.072 
        </mn> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <mo>
          = 
        </mo> 
        <mn>
          11.072 
        </mn> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mrow> 
         <mo>
           [ 
         </mo> 
         <mrow> 
          <mn>
            11.072 
          </mn> 
         </mrow> 
         <mo>
           ] 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mn>
          11 
        </mn> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (A.2)</p>
   <p>Returning to Equation (A.1), it becomes evident that one additional silicon atom must also be excluded artificially. Consequently, the final result is:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mo>
          × 
        </mo> 
        <mn>
          111 
        </mn> 
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        </mtext> 
        <mtext>
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        </mtext> 
        <mo>
          + 
        </mo> 
        <mi>
          a 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        − 
      </mo> 
      <mn>
        3 
      </mn> 
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        = 
      </mo> 
      <mn>
        10.072 
      </mn> 
      <mo>
        , 
      </mo> 
      <mrow> 
       <mo>
         [ 
       </mo> 
       <mrow> 
        <mn>
          10.072 
        </mn> 
       </mrow> 
       <mo>
         ] 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        10 
      </mn> 
     </mrow> 
    </math> (A.3)</p>
   <p>This implies that only 10 silicon atoms can be accommodated within 1 nanowire. Such a reversal solution for Equation (A.1) indicates that Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub> cannot be applied to 1 nanowire unless Yb atoms are not doped, leaving Si<sub>2</sub>O<sub>7</sub>.</p>
   <p>However, even in this scenario, Yb<sub>2</sub>Si<sub>2</sub>O<sub>7</sub> still provides valuable insights (or contributes ideas) that can promote experimental advancements. These advancements may help transform silicon (Si) or Si<sub>2</sub>O<sub>7</sub> into novel materials when subjected to BEC laser cooling, respectively.</p>
  </sec><sec id="s7">
   <title>Appendix B: 0.5 nm Channel as a Barrier Is Forbidden in Physics</title>
   <p>Consider a special case: wave-numbers of electrons in 1D quantum wells of 0.5 nm-channels, namely 0.5 nm channel as a barrier is forbidden in physics. Consider a special case involving the wave numbers of electrons in one-dimensional (1D) quantum wells within 0.5 nm channels. Specifically:</p>
   <p>
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      <mi>
        κ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          π 
        </mi> 
       </mrow> 
       <mi>
         λ 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (B.1)</p>
   <p>If the channel is contracted from 1 nm to 0.5 nm, the boundary conditions (B.C.) of the infinite potential wells change from 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mo>
        ± 
      </mo> 
      <mrow> 
       <mi>
         L 
       </mi> 
       <mo>
         / 
       </mo> 
       <mn>
         2 
       </mn> 
      </mrow> 
     </mrow> 
    </math> (for the 1 nm channel, used as the reference level) to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mo>
        ± 
      </mo> 
      <mrow> 
       <mi>
         L 
       </mi> 
       <mo>
         / 
       </mo> 
       <mn>
         4 
       </mn> 
      </mrow> 
     </mrow> 
    </math> (for the 0.5 nm channel).With 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        κ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mi>
         π 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         λ 
       </mi> 
      </mrow> 
     </mrow> 
    </math> applied, this contraction produces the eigenvalues of potential energy as follows<sup>5</sup>:</p>
   <p>
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      </mi> 
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        = 
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        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msup> 
         <mi>
           κ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          m 
        </mi> 
        <msup> 
         <mi>
           L 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          m 
        </mi> 
       </mrow> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mrow> 
             <mi>
               π 
             </mi> 
             <mo>
               / 
             </mo> 
             <mi>
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             </mi> 
            </mrow> 
           </mrow> 
           <mrow> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               4 
             </mn> 
            </mrow> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mn>
        16 
      </mn> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              π 
            </mi> 
            <mi>
              ℏ 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          m 
        </mi> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              λ 
            </mi> 
            <mi>
              L 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> in channels (1D-wells) (B.2)</p>
   <p>Moreover,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        E 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          m 
        </mi> 
       </mrow> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mn>
              4 
            </mn> 
            <mi>
              π 
            </mi> 
           </mrow> 
           <mi>
             L 
           </mi> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (B.3)</p>
   <p>Derive the above equation by varying 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       λ 
     </mi> 
    </math> when an electron is input into the 0.5 nm channel from the tuning voltage source of integrated circuits</p>
   <p>
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      <mfrac> 
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        </mi> 
       </mrow> 
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        </mo> 
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        </mi> 
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      </mo> 
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      </mo> 
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       </mrow> 
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       </mi> 
      </mfrac> 
      <msup> 
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        <mrow> 
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           ( 
         </mo> 
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              4 
            </mn> 
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              π 
            </mi> 
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           <mi>
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           </mi> 
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         </mrow> 
         <mo>
           ) 
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       </mrow> 
       <mn>
         2 
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       </mn> 
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         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        &lt; 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> with fixed 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (B.4)</p>
   <p>And it is in the bound state due to the negative sign mentioned above. However, when taking the second derivative of the above equation by varying 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       λ 
     </mi> 
    </math> as an electron is “quasi-standing” in the 0.5 nm channel space (regarding this part, it shall be seen in new sections (Appendix C)), so that</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mo>
           ∂ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          E 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          3 
        </mn> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         m 
       </mi> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mn>
              4 
            </mn> 
            <mi>
              π 
            </mi> 
           </mrow> 
           <mi>
             L 
           </mi> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ∝ 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mi>
        Ω 
      </mi> 
      <mo>
        ≡ 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math> (B.5)</p>
   <p>With a constant 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> retained and solid angles 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Ω 
      </mi> 
      <mo>
        ≡ 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math> considered in a spherical coordinate system (Refer to Ref. <xref ref-type="bibr" rid="scirp.140494-28">
     [28]
    </xref>), the actual result implies Rayleigh scattering in the case of a Fermi gas particle as the subject of interaction—provided we disregard the effects of the Pauli exclusion principle and spin (i.e., treating it as a classical particle for faster solutions). Note that the barrier, acting as the scattering center, is exactly half the width of the 1 nm channels (i.e., 0.5 nm channels). Since scattering states occur in 0.5 nm channels, we propose that it is unnecessary to produce these in physical engineering based on this section's deduction, thereby avoiding unnecessary waste. Notably, other solutions, such as destructive interference in quantum mechanics, can be explored to address this issue. Therefore with eigenfunctions:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           ψ 
         </mi> 
         <mi>
           n 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msqrt> 
         <mrow> 
          <mfrac> 
           <mn>
             2 
           </mn> 
           <mrow> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
          </mfrac> 
         </mrow> 
        </msqrt> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mi>
              n 
            </mi> 
            <mi>
              π 
            </mi> 
            <mi>
              x 
            </mi> 
           </mrow> 
           <mrow> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          , 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ≠ 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <msub> 
         <msup> 
          <mi>
            ψ 
          </mi> 
          <mo>
            ″ 
          </mo> 
         </msup> 
         <mi>
           n 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <msqrt> 
         <mrow> 
          <mfrac> 
           <mn>
             2 
           </mn> 
           <mrow> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
          </mfrac> 
         </mrow> 
        </msqrt> 
        <msup> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <mi>
               n 
             </mi> 
             <mi>
               π 
             </mi> 
            </mrow> 
            <mrow> 
             <mrow> 
              <mi>
                L 
              </mi> 
              <mo>
                / 
              </mo> 
              <mn>
                2 
              </mn> 
             </mrow> 
            </mrow> 
           </mfrac> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mi>
              n 
            </mi> 
            <mi>
              π 
            </mi> 
            <mi>
              x 
            </mi> 
           </mrow> 
           <mrow> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          , 
        </mo> 
        <mi>
          x 
        </mi> 
        <mo>
          ≠ 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mi>
          n 
        </mi> 
        <mo>
          = 
        </mo> 
        <mn>
          1 
        </mn> 
        <mo>
          , 
        </mo> 
        <mn>
          2 
        </mn> 
        <mo>
          , 
        </mo> 
        <mn>
          3 
        </mn> 
        <mo>
          , 
        </mo> 
        <mo>
          ⋯ 
        </mo> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (B.6)</p>
   <p>The above equation implies that electrons disappear at the scattering center 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          x 
        </mi> 
        <mo>
          = 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. In other words, in the case of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0.05 
      </mn> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math>,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           ψ 
         </mi> 
         <mi>
           n 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mrow> 
          <mrow> 
           <msqrt> 
            <mrow> 
             <mfrac> 
              <mn>
                2 
              </mn> 
              <mrow> 
               <mrow> 
                <mi>
                  L 
                </mi> 
                <mo>
                  / 
                </mo> 
                <mn>
                  2 
                </mn> 
               </mrow> 
              </mrow> 
             </mfrac> 
            </mrow> 
           </msqrt> 
           <mi>
             sin 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mfrac> 
              <mrow> 
               <mi>
                 n 
               </mi> 
               <mi>
                 π 
               </mi> 
               <mi>
                 x 
               </mi> 
              </mrow> 
              <mrow> 
               <mrow> 
                <mi>
                  L 
                </mi> 
                <mo>
                  / 
                </mo> 
                <mn>
                  2 
                </mn> 
               </mrow> 
              </mrow> 
             </mfrac> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            | 
          </mo> 
         </mrow> 
         <mrow> 
          <mrow> 
           <mrow> 
            <mi>
              x 
            </mi> 
            <mo>
              = 
            </mo> 
            <mi>
              L 
            </mi> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
          <mo>
            = 
          </mo> 
          <mn>
            0.5 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            nm 
          </mtext> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mi>
          n 
        </mi> 
        <mo>
          = 
        </mo> 
        <mn>
          1 
        </mn> 
        <mo>
          , 
        </mo> 
        <mn>
          2 
        </mn> 
        <mo>
          , 
        </mo> 
        <mn>
          3 
        </mn> 
        <mo>
          , 
        </mo> 
        <mo>
          ⋯ 
        </mo> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (B.7)</p>
   <p>Thus, electrons are completely absent within the 0.5 nm channels 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          x 
        </mi> 
        <mo>
          ≤ 
        </mo> 
        <mn>
          0.5 
        </mn> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> when affected by circuit nodes. In this case, the complete quantum mechanical solution with significant allowed values is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mtable columnalign="left"> 
        <mtr> 
         <mtd> 
          <msub> 
           <mi>
             ψ 
           </mi> 
           <mi>
             n 
           </mi> 
          </msub> 
          <mo>
            = 
          </mo> 
          <msqrt> 
           <mrow> 
            <mfrac> 
             <mn>
               2 
             </mn> 
             <mrow> 
              <mrow> 
               <mi>
                 L 
               </mi> 
               <mo>
                 / 
               </mo> 
               <mn>
                 2 
               </mn> 
              </mrow> 
             </mrow> 
            </mfrac> 
           </mrow> 
          </msqrt> 
          <mi>
            sin 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <mi>
                n 
              </mi> 
              <mi>
                π 
              </mi> 
              <mi>
                x 
              </mi> 
             </mrow> 
             <mrow> 
              <mrow> 
               <mi>
                 L 
               </mi> 
               <mo>
                 / 
               </mo> 
               <mn>
                 2 
               </mn> 
              </mrow> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            , 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            &gt; 
          </mo> 
          <mn>
            0.5 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            nm 
          </mtext> 
         </mtd> 
        </mtr> 
        <mtr> 
         <mtd> 
          <msub> 
           <msup> 
            <mi>
              ψ 
            </mi> 
            <mo>
              ″ 
            </mo> 
           </msup> 
           <mi>
             n 
           </mi> 
          </msub> 
          <mo>
            = 
          </mo> 
          <mo>
            − 
          </mo> 
          <msqrt> 
           <mrow> 
            <mfrac> 
             <mn>
               2 
             </mn> 
             <mrow> 
              <mrow> 
               <mi>
                 L 
               </mi> 
               <mo>
                 / 
               </mo> 
               <mn>
                 2 
               </mn> 
              </mrow> 
             </mrow> 
            </mfrac> 
           </mrow> 
          </msqrt> 
          <msup> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mfrac> 
              <mrow> 
               <mi>
                 n 
               </mi> 
               <mi>
                 π 
               </mi> 
              </mrow> 
              <mrow> 
               <mrow> 
                <mi>
                  L 
                </mi> 
                <mo>
                  / 
                </mo> 
                <mn>
                  2 
                </mn> 
               </mrow> 
              </mrow> 
             </mfrac> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mi>
            sin 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <mi>
                n 
              </mi> 
              <mi>
                π 
              </mi> 
              <mi>
                x 
              </mi> 
             </mrow> 
             <mrow> 
              <mrow> 
               <mi>
                 L 
               </mi> 
               <mo>
                 / 
               </mo> 
               <mn>
                 2 
               </mn> 
              </mrow> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            , 
          </mo> 
          <mi>
            x 
          </mi> 
          <mo>
            &gt; 
          </mo> 
          <mn>
            0.5 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            nm 
          </mtext> 
         </mtd> 
        </mtr> 
        <mtr> 
         <mtd> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
          <mo>
            , 
          </mo> 
          <mn>
            2 
          </mn> 
          <mo>
            , 
          </mo> 
          <mn>
            3 
          </mn> 
          <mo>
            , 
          </mo> 
          <mo>
            ⋯ 
          </mo> 
         </mtd> 
        </mtr> 
       </mtable> 
       <mo>
         } 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (B.8)</p>
   <p>For all space, whereas in industrial settings, the space in laboratories or fabrication facilities is considered complete.</p>
   <p><u>Remark</u><u>.</u></p>
   <p>Note that if the scattering angle 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        θ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math> 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        θ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math> (with cylindrical coordinates chosen) possibly occurs in the 0.5 nm channel, this choice retains valid, since that</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Ω 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mn>
              1 
            </mn> 
            <mo>
              − 
            </mo> 
            <mi>
              cos 
            </mi> 
            <mi>
              θ 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           | 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mi>
          θ 
        </mi> 
        <mo>
          = 
        </mo> 
        <mi>
          π 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> (B.9)</p>
  </sec><sec id="s8">
   <title>Appendix C: Mie’s &amp; Rayleigh’s Scatterings</title>
   <p>By applying the Heisenberg uncertainty principle, we obtain the lifetime of the quasi-standing state represented in terms of</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <msub> 
       <mi>
         τ 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℏ 
       </mi> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          Δ 
        </mi> 
        <mi>
          E 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          ℏ 
        </mi> 
        <mi>
          m 
        </mi> 
       </mrow> 
       <mrow> 
        <mn>
          16 
        </mn> 
       </mrow> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mi>
              λ 
            </mi> 
            <mi>
              L 
            </mi> 
           </mrow> 
           <mrow> 
            <mi>
              π 
            </mi> 
            <mi>
              ℏ 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        ≈ 
      </mo> 
      <mtext>
        3 
      </mtext> 
      <mtext>
        .4340 
      </mtext> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mtext>
          10 
        </mtext> 
       </mrow> 
       <mrow> 
        <mtext>
          -36 
        </mtext> 
       </mrow> 
      </msup> 
      <mi>
        sec 
      </mi> 
      <mo>
        ≪ 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          9 
        </mn> 
       </mrow> 
      </msup> 
      <mi>
        sec 
      </mi> 
     </mrow> 
    </math> (C.1)</p>
   <p>Under the given conditions 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mi>
        λ 
      </mi> 
     </mrow> 
    </math>, the photon-electronic sensitive time (10<sup>−</sup><sup>9</sup> sec) cannot immediately match the lifetime of the system. Therefore, it can be considered that the electron is initially well-scattered, resulting in outcomes similar to those observed in other solutions. We have primarily derived energy 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       λ 
     </mi> 
    </math> as a “twice,” caused by electron quantum tunneling. This tunneling process occurs at the boundaries of 0.5 nm channels (quantum wells), which serve as scattering centers at 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>.</p>
   <p>It is important to note that the parameter L must approach the wavelengths of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       λ 
     </mi> 
    </math>, making it necessary to achieve a Mie scattering pattern 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          L 
        </mi> 
        <mo>
          ≈ 
        </mo> 
        <mi>
          λ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. Next, we examine f 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       κ 
     </mi> 
    </math> for the matter-wave properties of the electron within the 0.5 nm channel. Here, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         V 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> is determined by the applied voltages in the integrated circuits, which can be manually adjusted to fine-tune the required wavelengths.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <mi>
          κ 
        </mi> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
         </mrow> 
         <mi>
           λ 
         </mi> 
        </mfrac> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mi>
          λ 
        </mi> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
         </mrow> 
         <mi>
           κ 
         </mi> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mi>
           h 
         </mi> 
         <mi>
           p 
         </mi> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mi>
           h 
         </mi> 
         <mrow> 
          <msqrt> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <msub> 
             <mi>
               m 
             </mi> 
             <mi>
               e 
             </mi> 
            </msub> 
            <msub> 
             <mi>
               V 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msqrt> 
         </mrow> 
        </mfrac> 
        <mo>
          ≡ 
        </mo> 
        <mfrac> 
         <mi>
           C 
         </mi> 
         <mrow> 
          <msqrt> 
           <mrow> 
            <msub> 
             <mi>
               V 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </msqrt> 
         </mrow> 
        </mfrac> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (C.2)</p>
   <p>When the standing wave patterns formed by electron subjects are established within the 0.5 nm channel, and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        λ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          π 
        </mi> 
       </mrow> 
       <mi>
         κ 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> is tuned (i.e., fixed at specific points a and b):</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mtable columnalign="left"> 
        <mtr> 
         <mtd> 
          <mrow> 
           <mo>
             | 
           </mo> 
           <mrow> 
            <msub> 
             <mi>
               x 
             </mi> 
             <mrow> 
              <mi>
                a 
              </mi> 
              <mi>
                b 
              </mi> 
             </mrow> 
            </msub> 
           </mrow> 
           <mo>
             | 
           </mo> 
          </mrow> 
          <mo>
            = 
          </mo> 
          <mrow> 
           <mo>
             | 
           </mo> 
           <mrow> 
            <msub> 
             <mi>
               x 
             </mi> 
             <mi>
               b 
             </mi> 
            </msub> 
            <mo>
              − 
            </mo> 
            <msub> 
             <mi>
               x 
             </mi> 
             <mi>
               a 
             </mi> 
            </msub> 
           </mrow> 
           <mo>
             | 
           </mo> 
          </mrow> 
          <mo>
            = 
          </mo> 
          <mn>
            0.5 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            nm 
          </mtext> 
          <mo>
            ≡ 
          </mo> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mtd> 
        </mtr> 
        <mtr> 
         <mtd> 
          <mi>
            L 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            nm 
          </mtext> 
         </mtd> 
        </mtr> 
       </mtable> 
       <mo>
         } 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (C.3)</p>
   <p>When the wavelength is confined within the 0.5 nm channel, consider the relationship between the wavelengths and the particle size under Mie scattering conditions. Here, the scattering center (corresponding to the particle size, 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math>) and the wavelengths of electron matter-waves (analogous to light wavelengths) are key factors. Associated with 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        λ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math>, the relationship is expressed as:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mi>
        λ 
      </mi> 
     </mrow> 
    </math> (C.4)</p>
   <p>This clearly corresponds to the Mie scattering conditions outlined in Equation (C.1). Furthermore, by manually decreasing the value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         V 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> (tuned to smaller values), a greater 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       λ 
     </mi> 
    </math> would be applied. As a result, Mie scattering transitions into Rayleigh scattering, while maintaining a fixed 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       L 
     </mi> 
    </math> (i.e., 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        ≫ 
      </mo> 
      <mi>
        λ 
      </mi> 
     </mrow> 
    </math>) to remain consistent with the prior discussions.</p>
  </sec><sec id="s9">
   <title>Appendix D: Examinations Through Mathematical Physics</title>
   <p>Associated with Equations (B.4) - (B.8) (excluding Equation (B.7)), it is evident that the results align with the sinc function. Based on Equation (B.4) and Equation (B.5), observation leads to the corresponding wavelengths of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        2 
      </mn> 
      <mi>
        λ 
      </mi> 
     </mrow> 
    </math> versus the phase angle 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math>, represented in figures of sinc functions. This observation is also consistent with Equation (B.1).</p>
   <p>Rewriting Equation (B.4) such yields:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          E 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          λ 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         m 
       </mi> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mn>
              4 
            </mn> 
            <mi>
              π 
            </mi> 
           </mrow> 
           <mrow> 
            <mi>
              λ 
            </mi> 
            <mi>
              L 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mi>
         λ 
       </mi> 
      </mfrac> 
      <mo>
        &lt; 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> with fixed 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (D.1)</p>
   <p>Make the same procedure, so</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mo>
           ∂ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          E 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          3 
        </mn> 
        <msup> 
         <mi>
           ℏ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mi>
         m 
       </mi> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mn>
              4 
            </mn> 
            <mi>
              π 
            </mi> 
           </mrow> 
           <mrow> 
            <mi>
              λ 
            </mi> 
            <mi>
              L 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ∝ 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           λ 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mi>
        Ω 
      </mi> 
      <mo>
        ≡ 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math> (D.2)</p>
   <p>Referring to the second formulations of Equation (B.6) and Equation (B.8), we derive:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msub> 
         <msup> 
          <mi>
            ψ 
          </mi> 
          <mo>
            ″ 
          </mo> 
         </msup> 
         <mi>
           n 
         </mi> 
        </msub> 
       </mrow> 
       <mi>
         C 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mn>
           2 
         </mn> 
         <mrow> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <msup> 
       <mi>
         C 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mfrac> 
       <mrow> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           C 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         C 
       </mi> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mi>
        x 
      </mi> 
      <mo>
        ≠ 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (D.3)</p>
   <p>And</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msub> 
         <msup> 
          <mi>
            ψ 
          </mi> 
          <mo>
            ″ 
          </mo> 
         </msup> 
         <mi>
           n 
         </mi> 
        </msub> 
       </mrow> 
       <mi>
         C 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mn>
           2 
         </mn> 
         <mrow> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <msup> 
       <mi>
         C 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mfrac> 
       <mrow> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           C 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         C 
       </mi> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mi>
        x 
      </mi> 
      <mo>
        &gt; 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (D.4)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        C 
      </mi> 
      <mo>
        ≡ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          n 
        </mi> 
        <mi>
          π 
        </mi> 
        <mi>
          x 
        </mi> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mi>
           L 
         </mi> 
         <mo>
           / 
         </mo> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> is defined here.</p>
   <p>It is evident that both Equation (D.3) and Equation (D.4) can be represented as sinc functions<sup>6</sup>.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msub> 
         <msup> 
          <mi>
            ψ 
          </mi> 
          <mo>
            ″ 
          </mo> 
         </msup> 
         <mi>
           n 
         </mi> 
        </msub> 
       </mrow> 
       <mi>
         C 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mn>
           2 
         </mn> 
         <mrow> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <msup> 
       <mi>
         C 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mi>
        sin 
      </mi> 
      <mi>
        c 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         C 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mi>
        x 
      </mi> 
      <mo>
        ≠ 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (D.5)</p>
   <p>And</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msub> 
         <msup> 
          <mi>
            ψ 
          </mi> 
          <mo>
            ″ 
          </mo> 
         </msup> 
         <mi>
           n 
         </mi> 
        </msub> 
       </mrow> 
       <mi>
         C 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mn>
           2 
         </mn> 
         <mrow> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
      <msup> 
       <mi>
         C 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mi>
        sin 
      </mi> 
      <mi>
        c 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         C 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mi>
        x 
      </mi> 
      <mo>
        &gt; 
      </mo> 
      <mn>
        0.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (D.6)</p>
   <p>This implies that they serve as strong evidence precisely supporting the previous discussions (i.e., Equation (D.1) and Equation (D.2)). Specifically, through a step-by-step approach using mathematical physics, these results directly correspond to “Mie scattering.”</p>
  </sec><sec id="s10">
   <title>Appendix E: Approximation of Scattering States</title>
   <p>In this section, we briefly demonstrate how the general interference patterns of an incident wave degenerate into particle scattering patterns.</p>
   <p>In case of a 0.5 nm channel, when electron matter-waves encounter a slit with a width of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       a 
     </mi> 
    </math>, the diffraction patterns observed on the screen degenerate into an optical spot governed by the properties of sinc functions. This occurs due to the limiting condition with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        C 
      </mi> 
      <mo>
        → 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> in Equation. (D.5) and Equation (D.6) (i.e., 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        a 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mi>
        λ 
      </mi> 
     </mrow> 
    </math>). In other words, when the wavelength 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        λ 
      </mi> 
      <mo>
        ≅ 
      </mo> 
      <mtext>
        0 
      </mtext> 
      <mtext>
        .5 
      </mtext> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> of the incident wave approaches or equals the slit width 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       a 
     </mi> 
    </math>, the wave-like behavior transitions into a particle-like spot. However, in earlier sections of this paper, nano-silicon particles were arranged within a 0.5 nm channel (as described in Equation (A.1), where up to five silicon atoms can be partially accommodated within this space). Thus, the slit width can be approximately equated to the lattice spacing, estimated between 0.1 nm and 0.5 nm. These values align in terms of magnitude, allowing us to conceptually replace the slits (i.e., lattice spacing) with the particles themselves. Through this reasoning, we conclude that wave-like behaviors degenerate into particle-like behaviors within the framework of quantum mechanics. This strongly supports the idea of specific scattering states, consistent with the results of the previous sections. These scattering states are well-established for a 0.5 nm channel. In summary, the work presented in this paper addresses related issues in a self-consistent and complete manner.</p>
  </sec><sec id="s11">
   <title>Appendix F: Mode Locking for Protection Tunneling of Electrons</title>
   <p>Using Equation (C.1), within a 1 nm channel, if one aims to confine electron gas within the wires while imposing infinite pressure (or momentum), the tunneling probability becomes zero. Thus, we derive condition</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <msub> 
       <mi>
         θ 
       </mi> 
       <mrow> 
        <mi>
          min 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <munder> 
       <mrow> 
        <mi>
          lim 
        </mi> 
       </mrow> 
       <mrow> 
        <mi>
          Δ 
        </mi> 
        <mi>
          P 
        </mi> 
        <mo>
          → 
        </mo> 
        <mi>
          ∞ 
        </mi> 
       </mrow> 
      </munder> 
      <msub> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mfrac> 
           <mi>
             ℏ 
           </mi> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mi>
              Δ 
            </mi> 
            <mi>
              P 
            </mi> 
            <mi>
              Δ 
            </mi> 
            <mi>
              x 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           | 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mi>
          Δ 
        </mi> 
        <mi>
          x 
        </mi> 
        <mo>
          = 
        </mo> 
        <mn>
          1 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> with mode locking (F.1)</p>
   <p>This implies that the phase retains synchronized for all electrons in silicon atoms. The technological approach undoubtedly relies on Bose-Einstein Condensate (BEC) laser cooling and Electromagnetically Induced Transparency (EIT) to achieve mode locking. To ensure Moore’s Law remains valid, the following must hold:</p>
   <p>BEC silicon = BEC laser cooling Si + EIT (F.2)</p>
  </sec><sec id="s12">
   <title>Appendix G: Calculation By Kramers-Kronig Relations</title>
   <p>In Kramers-Kronig relations, the dielectric constant can be written as</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        χ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        + 
      </mo> 
      <mi>
        i 
      </mi> 
      <msub> 
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         χ 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (G.1)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> is the real part, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> is the imaginary part (and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         ω 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        ∈ 
      </mo> 
      <mi>
        Im 
      </mi> 
     </mrow> 
    </math>).</p>
   <p>Moreover,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mn>
         2 
       </mn> 
       <mi>
         π 
       </mi> 
      </mfrac> 
      <mi>
        ℑ 
      </mi> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <munderover> 
         <mo>
           ∫ 
         </mo> 
         <mn>
           0 
         </mn> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <mi>
             ω 
           </mi> 
           <msub> 
            <mi>
              χ 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <msup> 
             <mi>
               ω 
             </mi> 
             <mo>
               ′ 
             </mo> 
            </msup> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <msup> 
            <msup> 
             <mi>
               ω 
             </mi> 
             <mo>
               ′ 
             </mo> 
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            <mn>
              2 
            </mn> 
           </msup> 
           <mo>
             − 
           </mo> 
           <msup> 
            <mi>
              ω 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <msup> 
          <mi>
            ω 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math> (G.2)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℑ 
     </mi> 
    </math> means: taking imaginary parts. (The above integral must be convergence to a finite value.) In a BEC phase, obviously resonant 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ω 
     </mi> 
    </math> keeps the same frequency, thus set 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ω 
      </mi> 
      <mo>
        ≡ 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> [1/sec] fixed as a singular point in polar coordinates.</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
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       </mi> 
       <mn>
         2 
       </mn> 
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      <mrow> 
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         ( 
       </mo> 
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       </mi> 
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      <mi>
        ℑ 
      </mi> 
      <mstyle displaystyle="true"> 
       <mrow> 
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         <mo>
           ∫ 
         </mo> 
         <mn>
           0 
         </mn> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msub> 
            <mi>
              χ 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <msup> 
             <mi>
               ω 
             </mi> 
             <mo>
               ′ 
             </mo> 
            </msup> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <mn>
             1 
           </mn> 
           <mo>
             − 
           </mo> 
           <msup> 
            <msup> 
             <mi>
               ω 
             </mi> 
             <mo>
               ′ 
             </mo> 
            </msup> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <msup> 
          <mi>
            ω 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math> (G.3)</p>
   <p>Since that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         ω 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        ∈ 
      </mo> 
      <mi>
        Im 
      </mi> 
     </mrow> 
    </math>, so that</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           χ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           2 
         </mn> 
         <mi>
           π 
         </mi> 
        </mfrac> 
        <mi>
          ℑ 
        </mi> 
        <mstyle displaystyle="true"> 
         <mrow> 
          <munderover> 
           <mo>
             ∫ 
           </mo> 
           <mn>
             0 
           </mn> 
           <mi>
             ∞ 
           </mi> 
          </munderover> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <msub> 
              <mi>
                χ 
              </mi> 
              <mn>
                1 
              </mn> 
             </msub> 
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              </mo> 
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               </mi> 
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                ) 
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               1 
             </mn> 
             <mo>
               − 
             </mo> 
             <msup> 
              <mrow> 
               <mrow> 
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                  ( 
                </mo> 
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                 <mi>
                   i 
                 </mi> 
                 <mi>
                   ω 
                 </mi> 
                </mrow> 
                <mo>
                  ) 
                </mo> 
               </mrow> 
              </mrow> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
           </mfrac> 
           <mtext>
             d 
           </mtext> 
           <msup> 
            <mi>
              ω 
            </mi> 
            <mo>
              ′ 
            </mo> 
           </msup> 
          </mrow> 
         </mrow> 
        </mstyle> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           χ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           2 
         </mn> 
         <mi>
           π 
         </mi> 
        </mfrac> 
        <mi>
          ℑ 
        </mi> 
        <mstyle displaystyle="true"> 
         <mrow> 
          <munderover> 
           <mo>
             ∫ 
           </mo> 
           <mn>
             0 
           </mn> 
           <mi>
             ∞ 
           </mi> 
          </munderover> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <msub> 
              <mi>
                χ 
              </mi> 
              <mn>
                1 
              </mn> 
             </msub> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 i 
               </mi> 
               <mi>
                 ω 
               </mi> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
            <mrow> 
             <msup> 
              <mi>
                ω 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
             <mo>
               + 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </mfrac> 
           <mtext>
             d 
           </mtext> 
           <msup> 
            <mi>
              ω 
            </mi> 
            <mo>
              ′ 
            </mo> 
           </msup> 
          </mrow> 
         </mrow> 
        </mstyle> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (G.4)</p>
   <p>Using the residue-method:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             χ 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              i 
            </mi> 
            <mi>
              ω 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
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         <mrow> 
          <msup> 
           <mi>
             ω 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            + 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             χ 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              i 
            </mi> 
            <mi>
              ω 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            i 
          </mi> 
         </mrow> 
        </mfrac> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mrow> 
            <mi>
              ω 
            </mi> 
            <mo>
              − 
            </mo> 
            <mi>
              i 
            </mi> 
           </mrow> 
          </mfrac> 
          <mo>
            − 
          </mo> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mrow> 
            <mi>
              ω 
            </mi> 
            <mo>
              + 
            </mo> 
            <mi>
              i 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mi>
          R 
        </mi> 
        <mi>
          e 
        </mi> 
        <msub> 
         <mi>
           s 
         </mi> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mo>
            = 
          </mo> 
          <mi>
            i 
          </mi> 
         </mrow> 
        </msub> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             χ 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              i 
            </mi> 
            <mi>
              ω 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            i 
          </mi> 
         </mrow> 
        </mfrac> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (G.5)</p>
   <p>Then due to the theorem of residues we have:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℑ 
      </mi> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <munderover> 
         <mo>
           ∫ 
         </mo> 
         <mn>
           0 
         </mn> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msub> 
            <mi>
              χ 
            </mi> 
            <mn>
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            </mn> 
           </msub> 
           <mrow> 
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              ( 
            </mo> 
            <mrow> 
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               i 
             </mi> 
             <mi>
               ω 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <msup> 
            <mi>
              ω 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
           <mo>
             + 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <msup> 
          <mi>
            ω 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </mrow> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mi>
        ℑ 
      </mi> 
      <mrow> 
       <mo>
         { 
       </mo> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          π 
        </mi> 
        <mi>
          i 
        </mi> 
        <mtext>
            
        </mtext> 
        <mi>
          R 
        </mi> 
        <mi>
          e 
        </mi> 
        <msub> 
         <mi>
           s 
         </mi> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mo>
            = 
          </mo> 
          <mi>
            i 
          </mi> 
         </mrow> 
        </msub> 
        <mi>
          f 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         } 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        ℑ 
      </mi> 
      <mrow> 
       <mo>
         { 
       </mo> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          π 
        </mi> 
        <mi>
          i 
        </mi> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             χ 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              i 
            </mi> 
            <mi>
              ω 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            i 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         } 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        π 
      </mi> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (G.6)</p>
   <p>Such that yields in Equation (G.4),</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         2 
       </mn> 
       <mi>
         π 
       </mi> 
      </mfrac> 
      <mi>
        ℑ 
      </mi> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <munderover> 
         <mo>
           ∫ 
         </mo> 
         <mn>
           0 
         </mn> 
         <mi>
           ∞ 
         </mi> 
        </munderover> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msub> 
            <mi>
              χ 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               i 
             </mi> 
             <mi>
               ω 
             </mi> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <msup> 
            <mi>
              ω 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
           <mo>
             + 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <msup> 
          <mi>
            ω 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </mrow> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (G.7)</p>
   <p>As far, therefore:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <mi>
          χ 
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           ( 
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           ) 
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        </mrow> 
        <mo>
          = 
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        <msub> 
         <mi>
           χ 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
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         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <mi>
          i 
        </mi> 
        <msub> 
         <mi>
           χ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mi>
          ℑ 
        </mi> 
        <mi>
          χ 
        </mi> 
        <mrow> 
         <mo>
           ( 
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           ) 
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        </mrow> 
        <mo>
          = 
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        <msub> 
         <mi>
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         <mn>
           2 
         </mn> 
        </msub> 
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         <mo>
           ( 
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           ω 
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           ) 
         </mo> 
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          = 
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          2 
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           1 
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           ) 
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        </mrow> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mi>
          ℜ 
        </mi> 
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           ) 
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        </mrow> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mstyle displaystyle="true"> 
         <munderover> 
          <mo>
            ∑ 
          </mo> 
          <mrow> 
           <mi>
             i 
           </mi> 
           <mo>
             = 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </munderover> 
         <mrow> 
          <msub> 
           <mi>
             ε 
           </mi> 
           <mrow> 
            <mi>
              i 
            </mi> 
            <mo>
              , 
            </mo> 
            <mi>
              r 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             ω 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mstyle> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           ε 
         </mi> 
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           1 
         </mn> 
        </msub> 
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           ( 
         </mo> 
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           ω 
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           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <mn>
          2 
        </mn> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mn>
          3 
        </mn> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ≡ 
        </mo> 
        <mn>
          3 
        </mn> 
        <mi>
          ε 
        </mi> 
        <msup> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            ω 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math> (G.8)</p>
   <p>Equation (G.8) complete fits the current solution way by using “high-κ dielectric” but the BEC laser plus EIT artificial promoted by this paper is much more advanced and affordable than it.</p>
   <p>Notice that in Equation (G.6), the result of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        π 
      </mi> 
      <msub> 
       <mi>
         χ 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ω 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> actually provides one that the Zak phase: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         φ 
       </mi> 
       <mrow> 
        <mi>
          Z 
        </mi> 
        <mi>
          k 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math>. Associated with this quantity and its potential optical resonance, both ensure the symmetry-protected topological (SPT) order for Equation (F.2), namely this paper’s highly-technology. In another respect, the axion-graphene system (Dr. ‘t Hooft condition 2D-graphenes with QFT-axions) reveals that the Berry curvature is zero (i.e., a plane) as shown in Equations (36)-(37) of Ref. <xref ref-type="bibr" rid="scirp.140494-29">
     [29]
    </xref>, i.e., the electrons running in 1 nm wires which represent as the nature of topological invariance (i.e., 3D topological insulators) undoubted. Moreover, the above deductions completely adhere Chern-Simon theory, since that due to Ref. <xref ref-type="bibr" rid="scirp.140494-29">
     [29]
    </xref> the Chern-numbers are 1,3,5 (gives Fractional Quantum Hall effect (FQHE) 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mfrac> 
       <mn>
         3 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mfrac> 
       <mn>
         5 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> ) where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mn>
         5 
       </mn> 
       <mo>
         / 
       </mo> 
       <mn>
         2 
       </mn> 
      </mrow> 
     </mrow> 
    </math> denotes Dirac matters presented for Equation (F.2), and the technology provided by Equation (F.2) is a production better cheap than current graphene materials. —The big breakthrough.</p>
   <p>Claims</p>
   <p>Point 1: If a 0.5 nm channel is positioned at the center of scattering, it renders any manufacturing process impossible to directly implement. However, alternative approaches remain feasible. We emphasize that this paper does not endorse or support any commercial manufacturing without explicit authorization through proper purchasing agreements. Any commercial production of 1 nm chips based on the ideas presented in this paper must utilize materials developed through “silicon tomography” as outlined herein.</p>
   <p>Point 2: While AI calculations may independently derive results similar to those presented in this paper, the intellectual priority belongs to this work. This precedence is established by our earlier efforts and contributions in advancing these findings.</p>
   <p>Point 3: A possible issue and/or argument might be occurred at that the research done by this successful work whether if the first author’s mother-school attended it or not? The first author claims that the all work done by himself independently (of course the second author has attended) and confirms that this work without any request(ing) from National Chung Cheng University (in Taiwan region) nor obtaining any help (e.g. its equipment or instruments) from it, although the first author had ever learned there. And this point of claims is only limited in this paper.</p>
  </sec><sec id="s13">
   <title>NOTES</title>
   <p>
    <xref ref-type="bibr" rid="scirp.140494-"></xref><sup>1</sup>In thermal equilibrium, the energy that the photon gas has, which reflects to the energy of the absorption material of silicon is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        E 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        n 
      </mi> 
      <mi>
        h 
      </mi> 
      <mi>
        v 
      </mi> 
      <mo>
        = 
      </mo> 
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       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
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         ( 
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        <mi>
          γ 
        </mi> 
        <mi>
          k 
        </mi> 
        <mi>
          T 
        </mi> 
        <mo>
          + 
        </mo> 
        <mi>
          h 
        </mi> 
        <mi>
          v 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        n 
      </mi> 
      <mo>
        &gt; 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        γ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        3 
      </mn> 
     </mrow> 
    </math>. Via an approximation by large number we confirm that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         γ 
       </mi> 
      </msub> 
      <mo>
        ≡ 
      </mo> 
      <mrow> 
       <mo>
         ( 
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       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
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          ε 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ε 
      </mi> 
      <mo>
        ≡ 
      </mo> 
      <mrow> 
       <mn>
         1 
       </mn> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msup> 
         <mrow> 
          <mn>
            10 
          </mn> 
         </mrow> 
         <mi>
           γ 
         </mi> 
        </msup> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>.</p>
   <p><sup>2</sup>To simplify the discussion, we have adopted the use of absolute value notation to exclude complex numbers when analyzing the projection of one quantum state onto another.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.140494-"></xref><sup>3</sup>In the Fresnel approximation, supposed that a nano tunnel in 2nm, the widely-known expression as practical material of silicon, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ρ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mo>
        ± 
      </mo> 
      <msqrt> 
       <mrow> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
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            <msub> 
             <mi>
               x 
             </mi> 
             <mn>
               1 
             </mn> 
            </msub> 
            <mo>
              − 
            </mo> 
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             <msup> 
              <mi>
                x 
              </mi> 
              <mo>
                ′ 
              </mo> 
             </msup> 
             <mn>
               2 
             </mn> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          + 
        </mo> 
        <msup> 
         <mrow> 
          <mrow> 
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             ( 
           </mo> 
           <mrow> 
            <msub> 
             <mi>
               x 
             </mi> 
             <mn>
               2 
             </mn> 
            </msub> 
            <mo>
              − 
            </mo> 
            <msub> 
             <msup> 
              <mi>
                x 
              </mi> 
              <mo>
                ′ 
              </mo> 
             </msup> 
             <mn>
               2 
             </mn> 
            </msub> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        = 
      </mo> 
      <mstyle displaystyle="true"> 
       <munderover> 
        <mo>
          ∑ 
        </mo> 
        <mrow> 
         <mi>
           i 
         </mi> 
         <mo>
           = 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
        <mn>
          3 
        </mn> 
       </munderover> 
       <mrow> 
        <msub> 
         <mi>
           x 
         </mi> 
         <mi>
           i 
         </mi> 
        </msub> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math> for the wavelengths of gamma-rays: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         λ 
       </mi> 
       <mi>
         γ 
       </mi> 
      </msub> 
      <mo>
        ≪ 
      </mo> 
      <mi>
        ρ 
      </mi> 
      <mo>
        ≪ 
      </mo> 
      <msub> 
       <mi>
         x 
       </mi> 
       <mn>
         3 
       </mn> 
      </msub> 
     </mrow> 
    </math> and then 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <msub> 
       <mi>
         x 
       </mi> 
       <mn>
         3 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ρ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <msub> 
         <mi>
           x 
         </mi> 
         <mn>
           3 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Ω 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        π 
      </mi> 
     </mrow> 
    </math> such that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        ≈ 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ρ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         r 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        ≈ 
      </mo> 
      <mn>
        2 
      </mn> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ρ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mn>
         4 
       </mn> 
      </mfrac> 
     </mrow> 
    </math>. Therefore 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <msup> 
        <mi>
          r 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        + 
      </mo> 
      <mn>
        4 
      </mn> 
      <mo>
        × 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ρ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mn>
         8 
       </mn> 
      </mfrac> 
     </mrow> 
    </math> with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ψ 
       </mi> 
       <mi>
         n 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>, this leads to corresponding: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ln 
      </mi> 
      <mn>
        2 
      </mn> 
      <mo>
        → 
      </mo> 
      <mi>
        ln 
      </mi> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.140494-"></xref><sup>4</sup>In other words, it is not essential that the structures required such as Gate-SiO<sub>2</sub>-Si Substrate to be manufactured in a semiconductor manufactures by this paper. (BEC Si plus EIT can be feasible.) Here given reasons: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mi>
          ε 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math> and due to Equation (11), Equation (17), and Equation (18) 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ω 
     </mi> 
    </math> in BEC is obviously coherent. Therefore, BEC resonant 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ω 
     </mi> 
    </math> is regarded as contributing to imaginary parts of dielectric constants: 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          3 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          nm 
        </mtext> 
       </mrow> 
      </mfrac> 
      <mi>
        ε 
      </mi> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mn>
        3 
      </mn> 
      <mo>
        × 
      </mo> 
      <munder> 
       <munder> 
        <mrow> 
         <mn>
           3.9 
         </mn> 
        </mrow> 
        <mo stretchy="true">
          ︸ 
        </mo> 
       </munder> 
       <mrow> 
        <msub> 
         <mrow> 
          <mtext>
            SiO 
          </mtext> 
         </mrow> 
         <mtext>
           2 
         </mtext> 
        </msub> 
       </mrow> 
      </munder> 
      <mo>
        ≈ 
      </mo> 
      <munder> 
       <munder> 
        <mrow> 
         <mn>
           11.68 
         </mn> 
        </mrow> 
        <mo stretchy="true">
          ︸ 
        </mo> 
       </munder> 
       <mrow> 
        <mtext>
          Si 
        </mtext> 
       </mrow> 
      </munder> 
     </mrow> 
    </math> which is compared with 3 nm (Gate-SiO<sub>2</sub>-Si substrate) and 1nm tunnels. It also can be computed by Kramers–Kronig relations that we confirm in Appendix G.</p>
   <p><sup>5</sup>The electron Hamiltonian is given as 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        H 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        E 
      </mi> 
      <mo>
        + 
      </mo> 
      <mi>
        V 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         x 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, since it behaves as a free particle when affected, so that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        H 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        E 
      </mi> 
     </mrow> 
    </math>.</p>
   <p><sup>6</sup> 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <msup> 
       <mi>
         c 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         c 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, exhibits extremely small differences in area relative to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <mi>
        c 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         c 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, making it an effective approximation. Note that, evidently the sinc functions effectively represent quantum barriers.</p>
  </sec>
 </body><back>
  <ref-list>
   <title>References</title>
   <ref id="scirp.140494-ref1">
    <label>1</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Klaers, J., Schmitt, J., Vewinger, F. and Weitz, M. (2010) Bose-Einstein Condensation of Photons in an Optical Microcavity. Nature, 468, 545-548. &gt;https://doi.org/10.1038/nature09567
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref2">
    <label>2</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Hester, G., Nair, H.S., Reeder, T., Yahne, D.R., DeLazzer, T.N., Berges, L., et al. (2019) Novel Strongly Spin-Orbit Coupled Quantum Dimer Magnet: Yb
     <sub>2</sub>Si
     <sub>2</sub>O
     <sub>7</sub>. Physical Review Letters, 123, Article ID: 027201. &gt;https://doi.org/10.1103/physrevlett.123.027201
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref3">
    <label>3</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Fleischhauer, M., Imamoglu, A. and Marangos, J.P. (2005) Electromagnetically Induced Transparency: Optics in Coherent Media. Reviews of Modern Physics, 77, 633-673. &gt;https://doi.org/10.1103/revmodphys.77.633
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref4">
    <label>4</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Hau, L.V., Harris, S.E., Dutton, Z. and Behroozi, C.H. (1999) Light Speed Reduction to 17 Metres per Second in an Ultracold Atomic Gas. Nature, 397, 594-598. &gt;https://doi.org/10.1038/17561
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref5">
    <label>5</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Kash, M.M., Sautenkov, V.A., Zibrov, A.S., Hollberg, L., Welch, G.R., Lukin, M.D., et al. (1999) Ultraslow Group Velocity and Enhanced Nonlinear Optical Effects in a Coherently Driven Hot Atomic Gas. Physical Review Letters, 82, 5229-5232. &gt;https://doi.org/10.1103/physrevlett.82.5229
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref6">
    <label>6</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Harris, S.E. and Hau, L.V. (1999) Nonlinear Optics at Low Light Levels. Physical Review Letters, 82, 4611-4614. &gt;https://doi.org/10.1103/physrevlett.82.4611
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref7">
    <label>7</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Kang, H., Hernandez, G. and Zhu, Y. (2004) Slow-Light Six-Wave Mixing at Low Light Intensities. Physical Review Letters, 93, Article ID: 073601. &gt;https://doi.org/10.1103/physrevlett.93.073601
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref8">
    <label>8</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Braje, D.A., Balić, V., Goda, S., Yin, G.Y. and Harris, S.E. (2004) Frequency Mixing Using Electromagnetically Induced Transparency in Cold Atoms. Physical Review Letters, 93, Article ID: 183601. &gt;https://doi.org/10.1103/physrevlett.93.183601
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref9">
    <label>9</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Harris, S.E. and Yamamoto, Y. (1998) Photon Switching by Quantum Interference. Physical Review Letters, 81, 3611-3614. &gt;https://doi.org/10.1103/physrevlett.81.3611
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref10">
    <label>10</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Yan, M., Rickey, E.G. and Zhu, Y. (2001) Observation of Absorptive Photon Switching by Quantum Interference. Physical Review A, 64, Article ID: 041801. &gt;https://doi.org/10.1103/physreva.64.041801
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref11">
    <label>11</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Braje, D.A., Balić, V., Yin, G.Y. and Harris, S.E. (2003) Low-Light-Level Nonlinear Optics with Slow Light. Physical Review A, 68, Article ID: 041801. &gt;https://doi.org/10.1103/physreva.68.041801
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref12">
    <label>12</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Chen, Y., Tsai, Z., Liu, Y. and Yu, I.A. (2005) Low-Light-Level Photon Switching by Quantum Interference. Optics Letters, 30, 3207-3209. &gt;https://doi.org/10.1364/ol.30.003207
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref13">
    <label>13</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Wang, C., Chen, Y., Lin, S., Lin, W., Kuan, P. and Yu, I.A. (2006) Low-Light-Level All-Optical Switching. Optics Letters, 31, 2350-2352. &gt;https://doi.org/10.1364/ol.31.002350
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref14">
    <label>14</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Lin, W.H., Liao, W.T., Wang, C.Y., Lee, Y.F. and Yu, I.A. (2008) Low-Light-Level All-Optical Switching Based on Stored Light Pulses. Physical Review A, 78, Article ID: 033807.
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref15">
    <label>15</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Schmidt, H. and Imamoglu, A. (1996) Giant Kerr Nonlinearities Obtained by Electromagnetically Induced Transparency. Optics Letters, 21, 1936-1938. &gt;https://doi.org/10.1364/ol.21.001936
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref16">
    <label>16</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Lukin, M.D. and Imamoğlu, A. (2000) Nonlinear Optics and Quantum Entanglement of Ultraslow Single Photons. Physical Review Letters, 84, 1419-1422. &gt;https://doi.org/10.1103/physrevlett.84.1419
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref17">
    <label>17</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Kang, H. and Zhu, Y. (2003) Observation of Large Kerr Nonlinearity at Low Light Intensities. Physical Review Letters, 91, Article ID: 093601. &gt;https://doi.org/10.1103/physrevlett.91.093601
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref18">
    <label>18</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Chen, Y., Wang, C., Wang, S. and Yu, I.A. (2006) Low-Light-Level Cross-Phase-Modulation Based on Stored Light Pulses. Physical Review Letters, 96, Article ID: 043603. &gt;https://doi.org/10.1103/physrevlett.96.043603
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref19">
    <label>19</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Fleischhauer, M. and Lukin, M.D. (2000) Dark-State Polaritons in Electromagnetically Induced Transparency. Physical Review Letters, 84, 5094-5097. &gt;https://doi.org/10.1103/physrevlett.84.5094
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref20">
    <label>20</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Liu, C., Dutton, Z., Behroozi, C.H. and Hau, L.V. (2001) Observation of Coherent Optical Information Storage in an Atomic Medium Using Halted Light Pulses. Nature, 409, 490-493. &gt;https://doi.org/10.1038/35054017
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref21">
    <label>21</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Phillips, D.F., Fleischhauer, A., Mair, A., Walsworth, R.L. and Lukin, M.D. (2001) Storage of Light in Atomic Vapor. Physical Review Letters, 86, 783-786. &gt;https://doi.org/10.1103/physrevlett.86.783
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref22">
    <label>22</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Longdell, J.J., Fraval, E., Sellars, M.J. and Manson, N.B. (2005) Stopped Light with Storage Times Greater than One Second Using Electromagnetically Induced Transparency in a Solid. Physical Review Letters, 95, Article ID: 063601. &gt;https://doi.org/10.1103/physrevlett.95.063601
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref23">
    <label>23</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Chen, Y., Liu, Y., Tsai, Z., Wang, S. and Yu, I.A. (2005) Beat-note Interferometer for Direct Phase Measurement of Photonic Information. Physical Review A, 72, Article ID: 033812. &gt;https://doi.org/10.1103/physreva.72.033812
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref24">
    <label>24</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Chanelière, T., Matsukevich, D.N., Jenkins, S.D., Lan, S., Kennedy, T.A.B. and Kuzmich, A. (2005) Storage and Retrieval of Single Photons Transmitted between Remote Quantum Memories. Nature, 438, 833-836. &gt;https://doi.org/10.1038/nature04315
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref25">
    <label>25</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Eisaman, M.D., André, A., Massou, F., Fleischhauer, M., Zibrov, A.S. and Lukin, M.D. (2005) Electromagnetically Induced Transparency with Tunable Single-Photon Pulses. Nature, 438, 837-841. &gt;https://doi.org/10.1038/nature04327
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref26">
    <label>26</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Barnea, N., Friedman, E. and Gal, A. (2021) On the Width of the K
     <sup>−</sup>D Atom Ground State. Nuclear Physics A, 1006, Article ID: 122112. &gt;https://doi.org/10.1016/j.nuclphysa.2020.122112
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref27">
    <label>27</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Tilke, A.T., Simmel, F.C., Lorenz, H., Blick, R.H. and Kotthaus, J.P. (2003) Quantum Interference in a One-Dimensional Silicon Nanowire. Physical Review B, 68, Article ID: 075311. &gt;https://doi.org/10.1103/physrevb.68.075311
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref28">
    <label>28</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Su, H.D. (2011) Research for Optical Properties, Various Shapes and Sizes of Nano-metallic Particles. Department of Physics, National Chung Cheng University, 106. 
    </mixed-citation>
   </ref>
   <ref id="scirp.140494-ref29">
    <label>29</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Su, H. and Lee, P. (2025) Sub-Atom Particles and Magnetic Monopoles Spin Ice Condensed in Higgs-Field Portals. Journal of Applied Mathematics and Physics, 13, 348-364. &gt;https://doi.org/10.4236/jamp.2025.131016
    </mixed-citation>
   </ref>
  </ref-list>
 </back>
</article>