<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    ijcns
   </journal-id>
   <journal-title-group>
    <journal-title>
     International Journal of Communications, Network and System Sciences
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    1913-3715
   </issn>
   <issn publication-format="print">
    1913-3723
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/ijcns.2025.181001
   </article-id>
   <article-id pub-id-type="publisher-id">
    ijcns-138890
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Computer Science 
     </subject>
     <subject>
       Communications
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    LEO Satellite Performance Comparison under Two Different Elevations
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Shkelzen
      </surname>
      <given-names>
       Cakaj
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aCanadian Institute of Technology (CIT), Tirana, Albania
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     14
    </day> 
    <month>
     01
    </month>
    <year>
     2025
    </year>
   </pub-date> 
   <volume>
    18
   </volume> 
   <issue>
    01
   </issue>
   <fpage>
    1
   </fpage>
   <lpage>
    13
   </lpage>
   <history>
    <date date-type="received">
     <day>
      13,
     </day>
     <month>
      December
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      11,
     </day>
     <month>
      December
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      11,
     </day>
     <month>
      January
     </month>
     <year>
      2025
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    Satellites in LEO (Low Earth Orbits) are closest to the Earth’s surface, having the smallest coverage area compared to other orbits, depending on altitude and elevation angle, and providing relatively too short visibility and communication duration, in range of (2 - 15) minutes. Communication duration represents the key performance indicator for LEO satellite communication systems. For longer communication sessions, more satellites must be involved, and the signals must be handed over from one satellite to the next to provide uninterrupted real-time services to the appropriate user or ground station. This leads to the concept and structure of the satellites organized in the constellation. Communication window (visibility window) depends on the designed horizon plane width determined by licensed elevation angle. For the appropriate calculations, a satellite from the Starlink constellation at altitude of 550 km is considered, observed under licensed designed elevations of 40˚ and 25˚. Calculations under two designed elevation levels confirmed the wider horizon and consequently longer communication under the lower elevation. 
   </abstract>
   <kwd-group> 
    <kwd>
     Elevation
    </kwd> 
    <kwd>
      LEO
    </kwd> 
    <kwd>
      Horizon Plane
    </kwd> 
    <kwd>
      Satellite
    </kwd> 
    <kwd>
      Radar Map
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>Compared to terrestrial telecommunication infrastructure, among the advantages of the satellite systems is the coverage of rural and undeveloped areas where the terrestrial infrastructure is too difficult to be implemented because of natural barriers or too high implementation cost.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.138890-"></xref>The State and the Future of LEO Satellite Internet Connectivity in Africa, report of 2022, declares that around 47% of the world’s population was still offline in relation to Internet services by the end of 2021 <xref ref-type="bibr" rid="scirp.138890-1">
     [1]
    </xref>. From this perspective, international organizations, industry, operators and service providers were seriously engaged to develop the network for ubiquitous broadband Internet services deployment based on satellite network infrastructure. The most convenient infrastructure for such a coverage actually is considered the LEO satellites organized in constellations <xref ref-type="bibr" rid="scirp.138890-2">
     [2]
    </xref>.</p>
   <p>The low Earth orbits use the altitudes of 300 km up to around 1400 km above the Earth’s surface, and the satellites consolidated to these orbits are known as the LEO satellites, having important advantage over satellites in other orbits since they provide the lowest latency <xref ref-type="bibr" rid="scirp.138890-3">
     [3]
    </xref>.</p>
   <p>The actual worldwide social real-time broadband long-distance intercommunications stem from the two emphasized achievements from the last century: 1) the satellite communication systems and 2) the broadband Internet services. Unfortunately, there is still no ubiquitous worldwide coverage with broadband Internet services. Thus, communications-integrated satellite-terrestrial networks are recently seen as the most convenient structure for such global broadband coverage, based on the Low Earth Orbit (LEO) satellites configured and structured as a constellation <xref ref-type="bibr" rid="scirp.138890-3">
     [3]
    </xref>.</p>
   <p>The idea and technological efforts towards the integrated satellite-terrestrial network have been enhanced by the appearance of LEO microsatellites at the end of the last century and then also nanosatellites early this century, because it is easier to launch them into space due to their small dimension and light weight <xref ref-type="bibr" rid="scirp.138890-3">
     [3]
    </xref>. The constellations of micro-nanosatellites currently represent the best model for achieving ubiquitous global Internet broadband coverage.</p>
   <p>Iridium constellation with 66 satellites represents the first serious space technological structure, aiming at the time of the implementation to provide worldwide automatic voice communication services <xref ref-type="bibr" rid="scirp.138890-4">
     [4]
    </xref>. Efforts were then enhanced by OneWeb constellation with 648 satellites <xref ref-type="bibr" rid="scirp.138890-5">
     [5]
    </xref>, and further by Telesat with initiative of 117 satellites organized in constellation <xref ref-type="bibr" rid="scirp.138890-6">
     [6]
    </xref>. Lastly, the impressive technological and operational activities are taken by SpaceX company, respectively with its constellation defined (named) as Starlink <xref ref-type="bibr" rid="scirp.138890-7">
     [7]
    </xref>. The Starlink constellation is foreseen to be organized in three spatial shells, each of them carrying on several hundred LEO microsatellites, specially designed to provide broadband services, through their intercommunication <xref ref-type="bibr" rid="scirp.138890-8">
     [8]
    </xref> <xref ref-type="bibr" rid="scirp.138890-9">
     [9]
    </xref>.</p>
   <p>Thus, in the near future, it should be expected that the worldwide broadband services provided by integrated satellite-terrestrial communication networks will be seriously deployed, increasing the demands for such services, so the operators/providers should apply the appropriate sophisticated end-user devices for the maximized downlink data throughput related to the broadband requirements without significantly affecting the mission cost <xref ref-type="bibr" rid="scirp.138890-10">
     [10]
    </xref>. Therefore, to provide the largest capacity at the lowest cost, in addition to a need for advanced technology in on-ground receive devices, future satellite payloads and platforms must also become more agile and more adaptable related to customer premises equipment.</p>
   <p>LEO passes are characterized by short periods and consequently too short communication windows, which brings the need for optimizing methods to be applied related to the communication between the ground and space segments <xref ref-type="bibr" rid="scirp.138890-11">
     [11]
    </xref>. In case of a constellation of satellites, the case becomes more complex, so, it is required a sophisticated timely synchronization (orchestration) procedure <xref ref-type="bibr" rid="scirp.138890-12">
     [12]
    </xref>. These facts confirm too high importance of a visibility-communication window, listing it among key performance indicators in LEO satellites communication process. The visibility-communication window between the LEO satellite and ground station, is directly depended on designed horizon plane width, which is strictly determined by the licensed elevation. Thus, this paper aims to quantify the appropriate difference between two cases, as further elaborated.</p>
   <p>Here, we begin with the geometry of satellite and on-ground access point (user or ground station) in space and step by step brought in plane, known as radar map mode of the satellite path. Through the radar map, the concepts of horizon are elaborated towards the designed horizon plane width calculations. For the appropriate analysis, a Starlink satellite of the constellation at altitude of 550 km is used, observed under two licensed designed elevation of 40˚ and 25˚.</p>
  </sec><sec id="s2">
   <title>2. From Space View to the Radar Map Mode</title>
   <p>The goal of the satellite systems is to lock the satellite and on-ground Access Point (AP), usually known and used here as the Ground Station (GS), to establish the communication link in between the satellite and the appropriate ground station. Seen from the on-ground access point (ground station), the position of the LEO satellite within its orbit is defined by azimuth and elevation angles at the ground station’s horizon plane. The GS horizon plane is assumed as tangent plane (perpendicular) to vector ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          R 
        </mi> 
       </mstyle> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math>), which links the ground station location with the Earth’s center, as given in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, where the horizon plane is indicated as gray. The angle between vector ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          R 
        </mi> 
       </mstyle> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math>) and ground station’s horizon plane is denoted with 90˚ in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, indicating this perpendicularity. The elevation ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) is the angle between a satellite and the ground station (user) horizon plane. The elevation ranges from 0˚ to 90˚. The Azimuth (Az) is the angle of the direction of the satellite, measured in the horizon plane from geographical north in clockwise direction. The azimuth ranges from 0˚ to 360˚ <xref ref-type="bibr" rid="scirp.138890-13">
     [13]
    </xref>. These two parameters are the most important for the LEO satellite’s tracking process seen from the ground station. In <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, the triangle with vertices as Earth’s center, Ground Station (GS (AP)), and the Satellite (SAT) is bolded. The elevation angle ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) (is measured above the horizon up to the satellite’s position), ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         β 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) is known as central angle and ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         α 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) is nadir angle. The sides of this triangle are Earth’s radius ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        6871 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        km 
      </mtext> 
     </mrow> 
    </math>), orbital radius ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       r 
     </mi> 
    </math>) ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mi>
        H 
      </mi> 
     </mrow> 
    </math>, where H is orbital altitude), and ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       d 
     </mi> 
    </math>) is the slant range representing the distance between the satellite and ground station seen at time of ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) elevation. The slant range varies depending on elevation (see <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>) and represents the main parameter to be estimated, since the other two: satellite radius vector ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        r 
      </mi> 
     </mstyle> 
    </math>) and the ground station radius vector ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          R 
        </mi> 
       </mstyle> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math>) at any position of</p>
   <fig id="fig1" position="float">
    <label>Figure 1</label>
    <caption>
     <title>Figure 1. Ground station and LEO satellite geometry.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9702611-rId40.jpeg?20250114033219" />
   </fig>
   <p>
    <xref ref-type="bibr" rid="scirp.138890-"></xref>the satellite and the appropriate ground station, are always known <xref ref-type="bibr" rid="scirp.138890-13">
     [13]
    </xref>. Slant range is an important factor within a link budget estimation since it does not determine only free space loss but also represents the path where the signal is faced with atmospheric impact <xref ref-type="bibr" rid="scirp.138890-13">
     [13]
    </xref> <xref ref-type="bibr" rid="scirp.138890-14">
     [14]
    </xref>. The communication under too low elevation angles can be hindered by natural barriers and interfered by terrestrial communication systems, thus moving above with elevation ensures safer communication between satellite and appropriate ground station <xref ref-type="bibr" rid="scirp.138890-15">
     [15]
    </xref>.</p>
   <p>(The methodology of the slant range calculation is presented in different papers, including a few of mine <xref ref-type="bibr" rid="scirp.138890-16">
     [16]
    </xref>, etc., so, it will not be repeated here, but the final formula is given as follows, since it is valuable for further elaboration).</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        d 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         [ 
       </mo> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mfrac> 
               <mrow> 
                <mi>
                  H 
                </mi> 
                <mo>
                  + 
                </mo> 
                <msub> 
                 <mi>
                   R 
                 </mi> 
                 <mi>
                   E 
                 </mi> 
                </msub> 
               </mrow> 
               <mrow> 
                <msub> 
                 <mi>
                   R 
                 </mi> 
                 <mi>
                   E 
                 </mi> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mrow> 
            <mi>
              cos 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <msub> 
           <mi>
             ε 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
        </msqrt> 
        <mo>
          − 
        </mo> 
        <mi>
          sin 
        </mi> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mo>
         ] 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (1)</p>
   <p>Equation (1) tells us that the distance between the ground station and the satellite depends on the satellite’s altitude (H) and elevation angle ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) under which the satellite is seen.</p>
   <p>Each point on the Earth’s surface (each ground station) has its own horizon plane, perpendicular to the Earth’s radius vector ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          R 
        </mi> 
       </mstyle> 
       <mi>
         E 
       </mi> 
      </msub> 
     </mrow> 
    </math>). The satellite path orbiting over the ground station projected on the ground station’s horizon plane is known as a radar map presentation. <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref> shows a given satellite orbit and the appropriate projected path on the ground station’s horizon plane (dashed lines in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>). For the ground station and the satellite to be locked, it is mandatory to “acquire” a satellite by the ground station at the horizon plane, and then to keep it under the view as long as possible above the horizon plane. Then, when the satellite is lost from the ground station’s view at the horizon plane, the communication between the satellite and the ground station is unlocked. The link is disabled.</p>
   <p>Practically, the horizon plane determines the visibility of the satellite from the ground station. The largest possible visibility from the ground station is achieved if the satellite is acquired at elevation of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math> at the horizon plane and lost also at 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>, known as ideal horizon plane.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.138890-"></xref>Two events in space, AOS (acquisition of the satellite) and LOS (loss of the satellite), under elevation of 0˚, geographically determine the ideal horizon plane, are identified in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>. AOS indicates the case when the satellite appears just at the horizon plane to be locked and to initiate communication with the on-ground station (user); LOS (Loss of the Satellite) indicates the case when the satellite just disappears from the horizon plane, being unlocked so that there is no more communication with the ground station. Both of them are characterized with appropriate azimuth, as 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>—acquisition of the satellite (azimuth); 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>—loss of the satellite (azimuth); and respective events time as 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mtext>
          time 
        </mtext> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>—acquisition of the satellite (time), 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mtext>
          time 
        </mtext> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>—loss of the satellite (time) <xref ref-type="bibr" rid="scirp.138890-16">
     [16]
    </xref>.</p>
   <p>Next event that affects satellite paths is the maximal elevation under which one the satellite is seen above the ground station horizon plane. It is denoted Max.El., in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>. Max.El. is a characteristic parameter related to each different satellite path. The time taken, from lock, further to Max.El., and then to unlock, determines the visibility and so communication duration between the ground station and the satellite-known as visibility (communication) window. The higher the maximal elevation (Max.El.), the longer is the satellite path above the ground station, so the longer visibility, and definitely the longer communication duration.</p>
   <p>The longest possible communication duration, known as ideal communication duration between the ground station and the appropriate satellite in its orbital path is theoretically determined as the difference in time between the satellite’s appearance on the GS horizon plane (under 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>) and the time when the satellite is lost from the GS horizon plane ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>), expressed as <xref ref-type="bibr" rid="scirp.138890-13">
     [13]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        D 
      </mi> 
      <mi>
        u 
      </mi> 
      <mi>
        r 
      </mi> 
      <mi>
        a 
      </mi> 
      <mi>
        t 
      </mi> 
      <mi>
        i 
      </mi> 
      <mi>
        o 
      </mi> 
      <msub> 
       <mi>
         n 
       </mi> 
       <mrow> 
        <mtext>
          Ideal 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        A 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mtext>
          time 
        </mtext> 
       </mrow> 
      </msub> 
      <mo>
        − 
      </mo> 
      <mi>
        L 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mtext>
          time 
        </mtext> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> (2)</p>
   <p>Let us further clarify the satellite’s flight over the ground station, based on <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>. The range between the ground station and the satellite depends on the altitude (H) of the LEO satellite and the elevation angle ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) under which one the satellite is seen above the ground station’s horizon plane. Ideally, the satellite appears at elevation of 0˚ at point AOS<sub>Az</sub> seen from the ground station and being at the longest distance from the ground station. Since the longest distance refers to the elevation of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>, it is denoted as ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>), and applying 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math> at Equation (1) yields out:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mi>
          H 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            H 
          </mi> 
          <mo>
            + 
          </mo> 
          <mn>
            2 
          </mn> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mi>
             E 
           </mi> 
          </msub> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math> (3)</p>
   <p>Ideally, the lock should be established at this point. As the satellite flies over the ground station, the elevation increases up to the point of maximal elevation (Max.El.) where the range between the ground station and the satellite is the closest. For the elevation of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        M 
      </mi> 
      <mi>
        a 
      </mi> 
      <mi>
        x 
      </mi> 
      <mo>
        . 
      </mo> 
      <mi>
        E 
      </mi> 
      <mi>
        l 
      </mi> 
      <mo>
        . 
      </mo> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>, the distance between the ground station and the satellite is denoted as ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mi>
         M 
       </mi> 
      </msub> 
     </mrow> 
    </math>), and based on Equation (1), it is <xref ref-type="bibr" rid="scirp.138890-16">
     [16]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mi>
         M 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mi>
          M 
        </mi> 
        <mi>
          a 
        </mi> 
        <mi>
          x 
        </mi> 
        <mi>
          E 
        </mi> 
        <mi>
          l 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mi>
         E 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         [ 
       </mo> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mfrac> 
               <mrow> 
                <mi>
                  H 
                </mi> 
                <mo>
                  + 
                </mo> 
                <msub> 
                 <mi>
                   R 
                 </mi> 
                 <mi>
                   E 
                 </mi> 
                </msub> 
               </mrow> 
               <mrow> 
                <msub> 
                 <mi>
                   R 
                 </mi> 
                 <mi>
                   E 
                 </mi> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mrow> 
            <mi>
              cos 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              M 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              x 
            </mi> 
            <mi>
              E 
            </mi> 
            <mi>
              l 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msqrt> 
        <mo>
          − 
        </mo> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            M 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            x 
          </mi> 
          <mi>
            E 
          </mi> 
          <mi>
            l 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ] 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (4)</p>
   <p>Further from the point of Max.El. (<xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>), the satellite goes symmetrically down, through decreased elevation to point LOS (Loss of Satellite, <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>) under coordinates of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>, having again the same distance ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>). At this point the satellite disappears from the ground station’s view, there is no more communication. This leads to conclusion that the ideal horizon plane is in fact the large flat circle laid under zero elevation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math> for all azimuths (0 - 360˚), with the center at ground station position, and the radius of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           ε 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, as it is given in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>. (For practical purposes, only the right side is highlighted, in gray). The above-described process is seen from the ground station; it is automatically followed by the tracking software. For analytical purposes, the space view should be brought on plane. As the satellite moves in its orbit, that movement in space may be projected onto the ground stations’ horizon plane <xref ref-type="bibr" rid="scirp.138890-13">
     [13]
    </xref> <xref ref-type="bibr" rid="scirp.138890-16">
     [16]
    </xref>. This mode of presentation is known as a “radar map” display.</p>
   <p>The radar map mode displays the horizon plane with an accurate position of the ground station at the center. The perimeter of the circle is the horizon plane, with the north on the top ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         Z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>), then at the east ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         Z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        90 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>), south ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         Z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        180 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>), and west ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         Z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        270 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math>). Three circles represent elevations 0˚, 30˚, and 60˚. At the center, the elevation is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ε 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        90 
      </mn> 
      <mo>
        ˚ 
      </mo> 
     </mrow> 
    </math> <xref ref-type="bibr" rid="scirp.138890-13">
     [13]
    </xref>.</p>
   <p>Let us try, for the case given as in-space view in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, to bring it into the radar map view. In <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, the point 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        L 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>measured clockwise from the north (N) direction it is roughly around 10˚ on the left of NS (north-south) direction, and the point 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        O 
      </mi> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mrow> 
        <mi>
          A 
        </mi> 
        <mi>
          z 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> it is roughly around 145˚ on the left of NS (north-south) direction. In <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, the point of Max.EL., it is roughly at around 45˚ above the ground station’s horizon plane.</p>
   <p>Thus, the satellite path seen from the ground station in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, transformed on the radar map mode looks as it is given in <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref>, where the appropriate angles are denoted, also. In <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref>, ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>) is slant range under 0˚ and ( 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         d 
       </mi> 
       <mrow> 
        <mi>
          M 
        </mi> 
        <mo> 
        </mo> 
       </mrow> 
      </msub> 
     </mrow> 
    </math>) is the slant range under Max.EL.</p>
   <p>Finally, the flight of the satellite in <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref> will have a different curve on the radar map in <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref> for each different satellite path, it is seen differently from the same ground station because of the movement of the ground station with the Earth’s rotation around its N-S (North-South) axis.</p>
   <p>Communication under 0˚ elevation sounds idealistic (ideal horizon plane), and it is almost impossible in an urban environment to ensure communication at zero level of the horizon. The communication under low elevation angles can be</p>
   <fig id="fig2" position="float">
    <label>Figure 2</label>
    <caption>
     <title>Figure 2. Radar map presentation.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9702611-rId113.jpeg?20250114033218" />
   </fig>
   <p>
    <xref ref-type="bibr" rid="scirp.138890-"></xref>hindered by environmental natural/artificial barriers. Thus, the detection of the satellite above natural/artificial barriers makes the necessity to determine the designed horizon plane, to ensure safe and reliable communication <xref ref-type="bibr" rid="scirp.138890-16">
     [16]
    </xref>. To avoid the problem of such natural/artificial obstacles, since it is needed to be predetermined in advance the lowest designed elevation of the horizon plane that allows safe lock/unlock, consequently reliable communication. The designed horizon plane is defined by the minimal elevation considered for the acquisition and the loss of the satellite. The plane with appropriate designed elevation (X˚) is considered as the designed horizon plane. The desigend elevation is licensed by the appropriate regulatory body. For different purposes of the satellite systems, the minimal elevation value for the designed horizon plane ranges on 5˚ to 55˚, thus considering the discussed case, the findings from this paper are aligned and applicable for other practices in satellite communication systems.</p>
  </sec><sec id="s3">
   <title>3. Horizon Plane Width</title>
   <p>For the further discussion a satellite of the Starlink constellation is considered. Starlink constellation is planned to be deployed in three spatial shells, each with several hundred micro satellites, in altitudes of 550 km, 1110 km and 340 km. Nearly 12,000 satellites are planned to be deployed in three shells <xref ref-type="bibr" rid="scirp.138890-17">
     [17]
    </xref>.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.138890-"></xref>The first shell will be occupied by 1440 satellites organized into 72 orbital planes of 20 satellites each, aiming to be completed by the end of 2024 and to serve for real-time Internet broadband services <xref ref-type="bibr" rid="scirp.138890-17">
     [17]
    </xref>. Initially the first shell (550 km) operated under designed elevation of 40˚ <xref ref-type="bibr" rid="scirp.138890-18">
     [18]
    </xref>, and later on by FCC (Federal Communications Commission) the designed elevation for users is approved on 25˚ <xref ref-type="bibr" rid="scirp.138890-19">
     [19]
    </xref>. Thus, further analysis will provide results under orbit altitude of 550 km for designed elevation of 40˚ and 25˚, aiming to compare the width of the designed horizon under these two licensed elevations. The methodotology applied is fully applicable not only for other Starlink shells, but also for other constellation based on other altitudes.</p>
   <sec id="s3_1">
    <title>3.1. Satellite Motion Parameters</title>
    <p>The satellites’ behavior is mainly dependent on orbital radius (circular orbits), expressed as:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         r 
       </mi> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          E 
        </mi> 
       </msub> 
       <mo>
         + 
       </mo> 
       <mi>
         H 
       </mi> 
      </mrow> 
     </math> (5)</p>
    <p>where H is the orbital altitude and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          E 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         6371 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         km 
       </mtext> 
      </mrow> 
     </math> is Earth’s radius. Further satellite velocity (v), orbital period (T), and number of daily passes (paths) (n) for circular orbit are given as follows:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         v 
       </mi> 
       <mo>
         = 
       </mo> 
       <msqrt> 
        <mrow> 
         <mfrac> 
          <mi>
            μ 
          </mi> 
          <mi>
            r 
          </mi> 
         </mfrac> 
        </mrow> 
       </msqrt> 
      </mrow> 
     </math> (6)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         T 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         π 
       </mi> 
       <msqrt> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mi>
              r 
            </mi> 
            <mn>
              3 
            </mn> 
           </msup> 
          </mrow> 
          <mi>
            μ 
          </mi> 
         </mfrac> 
        </mrow> 
       </msqrt> 
      </mrow> 
     </math> (7)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            S 
          </mi> 
         </msub> 
        </mrow> 
        <mi>
          T 
        </mi> 
       </mfrac> 
      </mrow> 
     </math> (8)</p>
    <p>where (r) is the orbital radius and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         μ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mi>
         M 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         G 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         3.986 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mn>
          5 
        </mn> 
       </msup> 
      </mrow> 
     </math> km<sup>3</sup>/s<sup>2</sup> is constant, as a product of Earth’s mass and gravititional Earth’s constant, and the number of the daily passes (n) is the ratio of sideral day ( 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mrow> 
         <mi>
           S 
         </mi> 
         <mi>
           i 
         </mi> 
         <mi>
           d 
         </mi> 
         <mi>
           e 
         </mi> 
         <mi>
           r 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           l 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> = 23 h 56 min 4.1 s) over the orbital period <xref ref-type="bibr" rid="scirp.138890-3">
      [3]
     </xref> <xref ref-type="bibr" rid="scirp.138890-13">
      [13]
     </xref>. For altitude of 550 km, these motion parameters are given in <xref ref-type="table" rid="table1">
      Table 1
     </xref>.</p>
    <table-wrap id="table1">
     <label>
      <xref ref-type="table" rid="table1">
       Table 1
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.138890-"></xref>Table 1. Satellite motion parameters at altitude of 550 [km].</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="56.10%"><p style="text-align:center">Motion parameters</p></td> 
       <td class="custom-bottom-td acenter" width="43.90%"><p style="text-align:center">Orbit-SAT</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="56.10%"><p style="text-align:center">Altitude (H) [km]</p></td> 
       <td class="custom-top-td acenter" width="43.90%"><p style="text-align:center">550</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="56.10%"><p style="text-align:center">Radius (r) [km]</p></td> 
       <td class="acenter" width="43.90%"><p style="text-align:center">6921</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="56.10%"><p style="text-align:center">Velocity (v) [km/s]</p></td> 
       <td class="acenter" width="43.90%"><p style="text-align:center">7.58</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="56.10%"><p style="text-align:center">Period (T) [s]</p></td> 
       <td class="acenter" width="43.90%"><p style="text-align:center">5730.1</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="56.10%"><p style="text-align:center">Period (T) [min]</p></td> 
       <td class="acenter" width="43.90%"><p style="text-align:center">95.5</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="56.10%"><p style="text-align:center">Number of daily passes (n)</p></td> 
       <td class="acenter" width="43.90%"><p style="text-align:center">15.03</p></td> 
      </tr> 
     </table>
    </table-wrap>
   </sec>
   <sec id="s3_2">
    <title>3.2. Radar Map Satellite Path Parameters</title>
    <p>The radar map mode of a random orbit and random LEO satellite path (pass), with designed horizon at elevation of 40˚ and 25˚ ( 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ε 
        </mi> 
        <mrow> 
         <mn>
           0 
         </mn> 
         <mi>
           D 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         40 
       </mn> 
       <mo>
         ˚ 
       </mo> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ε 
        </mi> 
        <mrow> 
         <mn>
           0 
         </mn> 
         <mi>
           D 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         25 
       </mn> 
       <mo>
         ˚ 
       </mo> 
      </mrow> 
     </math>) is given in <xref ref-type="fig" rid="fig3">
      Figure 3
     </xref>. D indicates designed elevation. Bolded circles are two designed horizon elevation levels. Since the elevation of 40˚ is firstly licensed, firstly will be considered. In <xref ref-type="fig" rid="fig3">
      Figure 3
     </xref>, events as acquisition of the satellite, loss of satellite, are respectively indexed with values 40˚ and 25˚.</p>
    <p>Slant ranges are also similarly indexed. Exception is the event of maximal elevation, which is the same for the both cases, since the same path is considered under different designed elevation for comparison purposes.</p>
    <p>
     <xref ref-type="bibr" rid="scirp.138890-"></xref>For the case of designed elevation of 40˚, seen from the ground station the satellite is acquired at point A<sub>40</sub> at azimuth of 225˚ and elevation of 40˚, locked with the ground station, established communication, flying further above the ground station up to maximal elevation of 60˚, and then moving down and unlocked at azimuth of 0˚ and elevation of 40˚, when the satellite is lost from the GS view</p>
    <fig id="fig3" position="float">
     <label>Figure 3</label>
     <caption>
      <title>Figure 3. The radar map mode of the random satellite path for designed horizon of 40˚ and 25˚.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9702611-rId132.jpeg?20250114033220" />
    </fig>
    <p>at point B<sub>40</sub>, and there is no more communication between the SAT and GS. Communication between the ground station and the satellites starts at point A<sub>40</sub> and ends at B<sub>40</sub>, passing the route S<sub>40</sub> above the appropriate horizon plane.</p>
    <p>For the next case, under 25˚, seen from the ground station the satellite is acquired at point A<sub>25</sub> at azimuth of 210˚ and elevation of 25˚, locked with the ground station, established communication, flying further above the ground station up to maximal elevation of 60˚, and then moving down and unlocked at azimuth of 15˚ and elevation of 25˚, when the satellite is lost from the GS view at point B<sub>25</sub>, and there is no more communication between the SAT and GS. Communication between the ground station and the satellites starts at point A<sub>25</sub> and ends at B25. passing the route S<sub>25</sub> above the appropriate horizon plane. Azimuth and loss angles, azimuth separation angle, maximal elevation, slant range under appropriate degree of elevation, determine the satellite path parameters reflected on radar map, further known as radar map path parameters, given in <xref ref-type="table" rid="table2">
      Table 2
     </xref> and <xref ref-type="table" rid="table3">
      Table 3
     </xref>. For the Starlink satellite of altitude at 550km, these parameters are calculated based on Equations (1) and (4) and as tabulated are given in <xref ref-type="table" rid="table2">
      Table 2
     </xref> and <xref ref-type="table" rid="table3">
      Table 3
     </xref>,</p>
    <table-wrap id="table2">
     <label>
      <xref ref-type="table" rid="table2">
       Table 2
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.138890-"></xref>Table 2. Satellite radar map parameters for designed elevation of 40˚.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="67.62%"><p style="text-align:center">Radar map path parameters</p></td> 
       <td class="custom-bottom-td acenter" width="32.38%"><p style="text-align:center">Orbit-SAT</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="67.62%"><p style="text-align:center">Altitude (H) [km]</p></td> 
       <td class="custom-top-td acenter" width="32.38%"><p style="text-align:center">550</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">AOS (Az; El) [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">225; 40</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">Max.EL. [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">60</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">LOS (Az, El) [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">0; 40</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">Azimuth angular separation (∆Az) [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">135</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              d 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ε 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mo>
               = 
             </mo> 
             <mn>
               0 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math> [km]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">2703.1</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              d 
            </mi> 
            <mrow> 
             <mn>
               40 
             </mn> 
            </mrow> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ε 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mo>
               = 
             </mo> 
             <mn>
               40 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math> [km]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">813.6</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              d 
            </mi> 
            <mi>
              M 
            </mi> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ε 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mo>
               = 
             </mo> 
             <mi>
               M 
             </mi> 
             <mi>
               a 
             </mi> 
             <mi>
               x 
             </mi> 
             <mo>
               . 
             </mo> 
             <mi>
               E 
             </mi> 
             <mi>
               l 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               60 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math> [km]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">626.7</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <table-wrap id="table3">
     <label>
      <xref ref-type="table" rid="table3">
       Table 3
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.138890-"></xref>Table 3. Satellite radar map parameters for designed elevation of 25˚.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="67.62%"><p style="text-align:center">Radar map path parameters</p></td> 
       <td class="custom-bottom-td acenter" width="32.38%"><p style="text-align:center">Orbit-SAT</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="67.62%"><p style="text-align:center">Altitude (H) [km]</p></td> 
       <td class="custom-top-td acenter" width="32.38%"><p style="text-align:center">550</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">AOS (Az; El) [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">210; 25</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">Max.EL. [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">60</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">LOS (Az, El) [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">15; 25</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center">Azimuth angular separation (∆Az) [˚]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">165</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              d 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ε 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mo>
               = 
             </mo> 
             <mn>
               0 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math> [km]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">2703.1</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              d 
            </mi> 
            <mrow> 
             <mn>
               25 
             </mn> 
            </mrow> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ε 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mo>
               = 
             </mo> 
             <mn>
               25 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math> [km]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">1123.3</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="67.62%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              d 
            </mi> 
            <mi>
              M 
            </mi> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                ε 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
             <mo>
               = 
             </mo> 
             <mi>
               M 
             </mi> 
             <mi>
               a 
             </mi> 
             <mi>
               x 
             </mi> 
             <mo>
               . 
             </mo> 
             <mi>
               E 
             </mi> 
             <mi>
               l 
             </mi> 
             <mo>
               . 
             </mo> 
             <mo>
               = 
             </mo> 
             <mn>
               60 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math> [km]</p></td> 
       <td class="acenter" width="32.38%"><p style="text-align:center">626.7</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>respectively for 40˚ and 25˚.</p>
   </sec>
   <sec id="s3_3">
    <title>3.3. Designed Horizon Plane Width</title>
    <p>The ideal horizon plane represents the visibility region under 0˚ of elevation angle, as the flat circle with its ideal horizon plane width (IHPW). The plane with appropriate designed elevation (X˚) is considered as the designed horizon plane, with its designed horizon plane width (DHPW) as given in <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref>. Looking from the ground station (user), the designed horizon plane width (DHPW) is the base of virtual up napped cone with the apex exactly at the ground station (user). The ground station projected on the designed horizon is denoted as point (C). The designed horizon plane width (DHPW) is in fact the diameter of the base of the appropriate virtual cone <xref ref-type="bibr" rid="scirp.138890-3">
      [3]
     </xref>. Further it is assumed that the designed horizon plane is defined by the lowest elevation 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          ε 
        </mi> 
        <mrow> 
         <mn>
           0 
         </mn> 
         <mi>
           D 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         X 
       </mi> 
       <mo>
         ˚ 
       </mo> 
      </mrow> 
     </math> as is in <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref>. Solving the triangle: ground station (user)—AOS (X˚)—center of DHPW (C) in <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref> <xref ref-type="bibr" rid="scirp.138890-17">
      [17]
     </xref>, yields out as:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         D 
       </mi> 
       <mi>
         H 
       </mi> 
       <mi>
         P 
       </mi> 
       <mi>
         W 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <msub> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <mi>
           A 
         </mi> 
         <mi>
           O 
         </mi> 
         <mi>
           S 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            X 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         d 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            ε 
          </mi> 
          <mrow> 
           <mn>
             0 
           </mn> 
           <mi>
             D 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           = 
         </mo> 
         <mi>
           X 
         </mi> 
         <mo>
           ˚ 
         </mo> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mi>
         sin 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           90 
         </mn> 
         <mo>
           − 
         </mo> 
         <mi>
           X 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         d 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            ε 
          </mi> 
          <mrow> 
           <mn>
             0 
           </mn> 
           <mi>
             D 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           = 
         </mo> 
         <mi>
           X 
         </mi> 
         <mo>
           ˚ 
         </mo> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mi>
         cos 
       </mi> 
       <mi>
         X 
       </mi> 
      </mrow> 
     </math> (9)</p>
    <p>Starlink for the first shell (layer at the altitude of 550 km) applied elevation angle for the designed horizon plane at 40˚ for users, and latter on is licensed for the elevation of 25˚ for users.</p>
    <p>Applying data from <xref ref-type="table" rid="table2">
      Table 2
     </xref> and <xref ref-type="table" rid="table3">
      Table 3
     </xref> and Equation (9), yields out as:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         D 
       </mi> 
       <mi>
         H 
       </mi> 
       <mi>
         P 
       </mi> 
       <msub> 
        <mi>
          W 
        </mi> 
        <mrow> 
         <mn>
           40 
         </mn> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <msub> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <mn>
           40 
         </mn> 
        </mrow> 
       </msub> 
       <mi>
         cos 
       </mi> 
       <mn>
         40 
       </mn> 
      </mrow> 
     </math> (10)</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         D 
       </mi> 
       <mi>
         H 
       </mi> 
       <mi>
         P 
       </mi> 
       <msub> 
        <mi>
          W 
        </mi> 
        <mrow> 
         <mn>
           25 
         </mn> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <msub> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <mn>
           25 
         </mn> 
        </mrow> 
       </msub> 
       <mi>
         cos 
       </mi> 
       <mn>
         25 
       </mn> 
      </mrow> 
     </math> (11)</p>
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>Figure 4. Designed Horizon Plane Width (DHPW).</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9702611-rId153.jpeg?20250114033221" />
    </fig>
    <p>
     <xref ref-type="bibr" rid="scirp.138890-"></xref>Applying respective slant range and appropriate elevation it is calculated the designed horizon plane width for both cases, and given as tabulated in <xref ref-type="table" rid="table4">
      Table 4
     </xref>.</p>
    <table-wrap id="table4">
     <label>
      <xref ref-type="table" rid="table4">
       Table 4
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.138890-"></xref>Table 4. Designed horizon plane width under elevation of 25˚ and 40˚ for altitude of 550 [km].</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="custom-bottom-td acenter" width="42.85%"><p style="text-align:center">Licensed elevation [˚]</p></td> 
       <td class="custom-bottom-td acenter" width="57.15%"><p style="text-align:center">Designed horizon plane width (DHPW) [km]</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="42.85%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ε 
            </mi> 
            <mrow> 
             <mn>
               0 
             </mn> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mn>
                 40 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             40 
           </mn> 
          </mrow> 
         </math></p></td> 
       <td class="custom-top-td acenter" width="57.15%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mi>
             D 
           </mi> 
           <mi>
             H 
           </mi> 
           <mi>
             P 
           </mi> 
           <msub> 
            <mi>
              W 
            </mi> 
            <mrow> 
             <mn>
               40 
             </mn> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             1246.5 
           </mn> 
          </mrow> 
         </math></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="42.85%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              ε 
            </mi> 
            <mrow> 
             <mn>
               0 
             </mn> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mn>
                 25 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             25 
           </mn> 
          </mrow> 
         </math></p></td> 
       <td class="acenter" width="57.15%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mi>
             D 
           </mi> 
           <mi>
             H 
           </mi> 
           <mi>
             P 
           </mi> 
           <msub> 
            <mi>
              W 
            </mi> 
            <mrow> 
             <mn>
               25 
             </mn> 
            </mrow> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mn>
             2036.1 
           </mn> 
          </mrow> 
         </math></p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>The benefit of applying designed elevation of 25˚ instead of 40˚ is obvious, since the first one provides larger designed horizon planes width and consequently longer communication.</p>
   </sec>
  </sec><sec id="s4">
   <title>4. Conclusions</title>
   <p>The communications integrated satellite-terrestrial networks have recently been proven as the most convenient structure for the global broadband coverage, including on-ground access points and Low Earth Orbit (LEO) satellites organized in a constellation.</p>
   <p>It is proved that the lower elevation provides wider horizon plane, consequently longer communication duration and longer download/upload Internet sessions provided by the appropriate satellite.</p>
   <p>The methodology applied is aligned and applicable to other LEO satellite altitudes.</p>
  </sec>
 </body><back>
  <ref-list>
   <title>References</title>
   <ref id="scirp.138890-ref1">
    <label>1</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     (2022) The State and the Future of LEO Satellite Internet Connectivity in Africa.&gt;http://interactive.satellitetoday.com/via/january-february-2022/the-state-and-future-of-leo-satellite-internet-connectivity-in-africa/ 
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref2">
    <label>2</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Internet Society (2022) Perspectives on LEO Satellites: Using Low Earth Orbit Satellites for Internet Access. &gt;https://www.internetsociety.org/wp-content/uploads/2022/11/Perspectives-on-LEO-Satellites.pdf 
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref3">
    <label>3</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cakaj, S. (2022) Ground Station Design and Analysis for LEO Satellites. Wiley. &gt;https://doi.org/10.1002/9781119899280
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref4">
    <label>4</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Lin, X., Cioni, S., Charbit, G., Chuberre, N., Hellsten, S. and Boutillon, J. (2021) On the Path to 6G: Embracing the Next Wave of Low Earth Orbit Satellite Access. IEEE Communications Magazine, 59, 36-42. &gt;https://doi.org/10.1109/mcom.001.2100298
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref5">
    <label>5</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cochetti, R. (2015) Low Earth Orbit (LEO) Mobile Satellite Communications Systems. In: Cochetti, R., Ed., Mobile Satellite Communications Handbook, Wiley, 119-155.
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref6">
    <label>6</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     De Selding, B.P. (2015) Virgin, Qualcomm Invest in OneWeb Satellite Internet Venture. SpaceNews. &gt;https://satellitemap.space/?constellation=oneweb 
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref7">
    <label>7</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Foust, J. (2018) Telesat to Announce Manufacturing Plans for LEO Constellation in Coming Months. SpaceNews. &gt;https://spacenews.com/telesat-to-announce-manufacturing-plans-for-leo-constellation-in-coming-months/ 
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref8">
    <label>8</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     (2020) Starlink Satellite Constellation. &gt;https://directory.eoportal.org/web/eoportal/satellite-missions/s/starlink 
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref9">
    <label>9</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Li, Y., Li, H., Liu, W., Liu, L., Zhao, W., Chen, Y., et al. (2023) A Networking Perspective on Starlink’s Self-Driving LEO Mega-Constellation. Proceedings of the 29th Annual International Conference on Mobile Computing and Networking, Madrid, 2-6 October 2023, 1-16. &gt;https://doi.org/10.1145/3570361.3592519
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref10">
    <label>10</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Botta, A. and Pescape, A. (2013) New Generation Satellite Broadband Internet Services: Should ADSL and 3G Worry? 2013 Proceedings IEEE INFOCOM, Turin, 14-19 April 2013, 3279-3284. &gt;https://doi.org/10.1109/infcom.2013.6567151
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref11">
    <label>11</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     del Portillo, I., Cameron, B.G. and Crawley, E.F. (2019) A Technical Comparison of Three Low Earth Orbit Satellite Constellation Systems to Provide Global Broadband. Acta Astronautica, 159, 123-135. &gt;https://doi.org/10.1016/j.actaastro.2019.03.040
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref12">
    <label>12</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Carvalho, R.A.D. (2019) Optimizing the Communication Capacity of a Ground Station Network. Journal of Aerospace Technology and Management, 11, e2319. &gt;https://doi.org/10.5028/jatm.v11.1026
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref13">
    <label>13</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cakaj, S. and Malarić, K. (2007) Rigorous Analysis on Performance of LEO Satellite Ground Station in Urban Environment. International Journal of Satellite Communications and Networking, 25, 619-643. &gt;https://doi.org/10.1002/sat.895
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref14">
    <label>14</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cakaj, S., Kamo, B., Enesi, I., and Shurdhi, O. (2011) Antenna Noise Temperature for Low Earth Orbiting Satellite Ground Stations at L and S Band. The Third International Conference on Advances in Satellite and Space Communications, Budapest, 17-22 April 2011, 1-6.
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref15">
    <label>15</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cakaj, S., Kamo, B., Lala, A. and Rakipi, A. (2014) Elevation Impact on Signal to Spectral Noise Density Ratio for Low Earth Orbiting Satellite Ground Station at S-Band. 2014 Science and Information Conference, London, 27-29 August 2014, 641-645. &gt;https://doi.org/10.1109/sai.2014.6918254
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref16">
    <label>16</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cakaj, S., Kamo, B., Koliçi, V. and Shurdi, O. (2011) The Range and Horizon Plane Simulation for Ground Stations of Low Earth Orbiting (LEO) Satellites. International Journal of Communications, Network and System Sciences, 4, 585-589. &gt;https://doi.org/10.4236/ijcns.2011.49070
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref17">
    <label>17</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Cakaj, S. (2021) The Parameters Comparison of the “Starlink” LEO Satellites Constellation for Different Orbital Shells. Frontiers in Communications and Networks, 2, Article 643095. &gt;https://doi.org/10.3389/frcmn.2021.643095
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref18">
    <label>18</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Paessler, D. (2022) Analyzing Starlink Speed and Availability over 10 Months with PRTG. Paessler the Monitoring Experts. &gt;https://blog.paessler.com/analyzing-starlink-speed-and-availability-over-10-months-with-prtg 
    </mixed-citation>
   </ref>
   <ref id="scirp.138890-ref19">
    <label>19</label>
    <mixed-citation publication-type="other" xlink:type="simple">
     Chougrani, H., et al. (2024) Connecting Space Missions Through NGSO Constellations: Feasibility Study. Frontiers in Communications and Networks, 2, Article 643095.
    </mixed-citation>
   </ref>
  </ref-list>
 </back>
</article>