<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jmp
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of Modern Physics
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2153-1196
   </issn>
   <issn publication-format="print">
    2153-120X
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jmp.2024.1513100
   </article-id>
   <article-id pub-id-type="publisher-id">
    jmp-138496
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    On the Constancy of the Speed of Light in All Directions: A Proposed Experiment to Measure the One-Way Speed of Light
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Konstantinos
      </surname>
      <given-names>
       Patrinos
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aPhysics Department, School of Applied Mathematical and Physical Sciences, National Technical University of Athens, Athens, Greece
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     17
    </day> 
    <month>
     12
    </month>
    <year>
     2024
    </year>
   </pub-date> 
   <volume>
    15
   </volume> 
   <issue>
    13
   </issue>
   <fpage>
    2422
   </fpage>
   <lpage>
    2445
   </lpage>
   <history>
    <date date-type="received">
     <day>
      30,
     </day>
     <month>
      October
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      23,
     </day>
     <month>
      October
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      23,
     </day>
     <month>
      December
     </month>
     <year>
      2024
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    The self-rotating motion of the earth makes it possible to test the constancy of the speed of light in all directions by measuring the one-way speed of light. The review of the implemented experiments to test the constancy of the speed of light, based on the theory of the absolute system of reference, yields some indications that the speed of light is affected by the self-rotational motion of the earth. The newest experiments based either on the methodology of standing waves or on the Compton edge effect cannot contribute in this field of research. A proposed experiment to measure the one-way speed of light, and the corresponding relativistic predictions, are discussed.
   </abstract>
   <kwd-group> 
    <kwd>
     Constancy of the Speed of Light
    </kwd> 
    <kwd>
      Ether-Drift Experiment
    </kwd> 
    <kwd>
      Michelson-Morley Experiment
    </kwd> 
    <kwd>
      One-Way Speed of Light
    </kwd> 
    <kwd>
      Anisotropies of the Speed of Light
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>The purpose of the present study is to test the constancy of the speed of light in all directions. It should be mentioned, although it is widely known, that the history of this effort goes back a long time, more than a century ago. The experiments of the period 1881-1930, described in <xref ref-type="bibr" rid="scirp.138496-1">
     [1]
    </xref>-<xref ref-type="bibr" rid="scirp.138496-15">
     [15]
    </xref>, were intended to confirm the view that light propagates at a constant speed in the ether and that the ether is the medium of propagation of electromagnetic radiation, based on the electromagnetic theory of light formulated by James Maxwell in 1861. The first attempt was made in 1881 by Albert Abraham Michelson, who devised a new method to achieve this goal, in which no appreciable displacement of the interference fringes was observed, so the experiment was repeated in 1887 by Albert Abraham Michelson and Edward Williams Morley, this time with greater precision.</p>
   <p>All attempts to measure the speed of the earth relative to the ether were based on measurements of the displacement of the interference fringes proportional to the ratio 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <msup> 
         <mi>
           v 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>. This is mainly due to Fresnel’s theory predicting a positive result of ether drift experiments only to second order in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mi>
         v 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>, because Fresnel’s dragging coefficient would cause a negative outcome of all optical experiments capable of measuring effects to first order in 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mi>
         v 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>.</p>
   <p>Experimental experience has shown that the speed of light emitted by a light source placed in a rotating frame and observed from the inertial frame of the laboratory is equal to the speed of light emitted by a light source stationary in the laboratory. This experimental result is consistent with the basic principle of special relativity that the speed of light is constant in any inertial frame of reference regardless of the speed of the light source. However, there is no corresponding experimental experience to confirm the principles of relativity, regarding the constancy of the speed of light in all directions, according to the estimates of an observer who is on a self-rotating frame with a small angular velocity. Such a test of the constancy of the speed of light could be made with respect to a reference frame of a geographic location on the surface of the earth, given the angular velocity of the earth’s self-rotation.</p>
   <p>There are two conflicting views in the scientific community on the constancy of the speed of light. One view is that derived from direct measurements, using interferometers in which light propagates bidirectionally in each arm, i.e. in each arm there are two beams, an incident and a reflected, with opposite directions. The experimental results obtained from the use of interferometers, regarding the calculation of the upper limit on ether drift velocity, range from 1.5 km/s to 20 km/s. Also a simple re-analysis of the old results (1887) from the Michelson-Morley interferometer experiment has been done by Reginald T. Cahill and Kirsty Kitto, motivated by developments in a new information-theoretic modelling of reality, known as Process Physics, as reported in <xref ref-type="bibr" rid="scirp.138496-16">
     [16]
    </xref>. This analysis takes into account the refractive index of the optical medium, in this case, air, and the Lorentz-Fitzgerald contraction, so the calculated velocity with respect to a preferred frame of reference is multiplied by a factor of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mn>
         1 
       </mn> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            − 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>. However, the analysis by Reginald T. Cahill and Kirsty Kitto does not take into account the Fresnel drag coefficient. In the paper by J. Shamir and R. Fox, ref. <xref ref-type="bibr" rid="scirp.138496-15">
     [15]
    </xref>, in which all these factors are taken into account and the optical material used has a refractive index of 1.49, the authors state the following</p>
   <p>“We make three assumptions here which are included in most of the rival theories to STR:</p>
   <p>1) There exists a preferred frame of reference (“ether”) with respect to which we can (in principle, at least) measure velocities and accelerations.</p>
   <p>2) The Lorentz contraction of length is a real physical process.</p>
   <p>3) The Fresnel drag coefficient is given exactly by</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        b 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           n 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        , 
      </mo> 
     </mrow> 
    </math></p>
   <p>where n is the refractive index of a transparent material.”</p>
   <p>The experimental result is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        v 
      </mi> 
      <mo>
        ≤ 
      </mo> 
      <mn>
        6.64 
      </mn> 
      <mtext>
          
      </mtext> 
      <mrow> 
       <mrow> 
        <mtext>
          km 
        </mtext> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mtext>
         s 
       </mtext> 
      </mrow> 
     </mrow> 
    </math>, and is commented by the authors as follows</p>
   <p>“The upper limit to the velocity of the earth through the ether (6.64 km/s) that was obtained in this experiment is much less than the orbital velocity of the earth around the sun (about 30 km/s). The experimental basis of special relativity is thus enhanced by this negative result.”</p>
   <p>The other view is based on the claim that the experimental errors resulting from the use of interferometers are large and also on the newer experimental methodologies of searching for anisotropies of the speed of light, namely, on the measurement of the frequency change during the change of orientation of a resonator, and on the experimental measurements derived from the Compton edge effect. The claim that the experimental errors resulting from the use of interferometers are large comes from the experimental experience of those involved with such experiments using Michelson’s methodology and on this subject we cite a small part of the paper by Albert Abraham Michelson and Edward Morley, described in <xref ref-type="bibr" rid="scirp.138496-2">
     [2]
    </xref>, where the authors state the following</p>
   <p>“In the first experiment, one of the principal difficulties encountered was that of revolving the apparatus without producing distortion; and another was its extreme sensitiveness to vibration. This was so great that it was impossible to see the interference fringes except at brief intervals when working in the city, even at two o’clock in the morning. Finally, as before remarked, the quantity to be observed, namely, a displacement of something less than a twentieth of the distance between the interference fringes may have been too small to be detected when masked by experimental errors.”</p>
   <p>The experimental result obtained following the methodology for measuring the frequency change of a resonator, with respect to the upper bound on ether drift velocity, during the period 1958-1964 is ~30 m/s. As of 2015, optical and microwave resonator experiments have improved this limit to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mtext>
          Δ 
        </mtext> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        ≃ 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          18 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>. Also, in 2018, as the authors V. G. Gurzadyan and A. T. Margaryan stated in <xref ref-type="bibr" rid="scirp.138496-17">
     [17]
    </xref> for the case of Compton edge effect,</p>
   <p>“to probe the light speed invariance with respect to the velocity of the apparatus, namely, with respect to the beam electron reference system and the reference system of the calorimeter, we use the data of GRAAL’s Laser Compton Backscattered (LCB) experiment.”</p>
   <p>and the result obtained from the data analysis is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mi>
          δ 
        </mi> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        7.1 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          12 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>.</p>
   <p>However, based on the theory of the absolute reference system, the present study demonstrates that these newer experimental methodologies cannot contribute to this field of research.</p>
   <p>In order to remove this contradiction between the experimental results derived from the use of interferometers on the one hand and the results derived from the newer experiments based on the methodology of standing wave and the measurements of GRAAL’s Laser Compton Backscattered (LCB) experiment on the other hand, the most effective way is to test the constancy of the speed of light by directly measuring the one-way speed of light. The one-way measurement of light speed experiment proposed in the present study aims to test not only the constancy of the speed of light for a light source and an observer located in a rotating frame of reference, but also the effect on the speed of light due to a supposed preferred system of reference.</p>
   <p>The Lorentz-Fitzgerald contraction, in its classical description, is mentioned in the literature mainly for rectilinear motions of bodies, with respect to inertial frames of reference. In a self-rotating frame of reference, difficulties arise in applying this classical view of the contraction of bodies due to their motion with respect to the ether.</p>
   <p>A relevant example is worth mentioning. Imagine a circular homogeneous metal disk, rotating around an axis of rotation perpendicular to its plane, passing through its center of mass. You will realize that you cannot apply this Lorentz-Fitzgerald contraction theory unless you accept that the radius of the disk also decreases and furthermore that it is no longer a homogeneous body since its density will depend on the radial distance.</p>
   <p>Let us denote by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> the density of the circular disk when it is stationary. The density of the rotating disk will be a function of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ρ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, that is, it will depend on the radial distance 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       r 
     </mi> 
    </math>. A stationary annular differential mass of the circular disk is expressed by the relation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        M 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <mi>
        π 
      </mi> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mi>
        r 
      </mi> 
      <mtext>
        d 
      </mtext> 
      <mi>
        r 
      </mi> 
     </mrow> 
    </math>. The radius of the annular differential mass, when the disk rotates with angular velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ω 
     </mi> 
    </math> decreases by a factor 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        γ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <msup> 
             <mi>
               ω 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <msup> 
             <mi>
               r 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           / 
         </mo> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>, so the annular differential mass takes the form 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        M 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <mi>
        π 
      </mi> 
      <mi>
        ρ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           r 
         </mi> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mi>
            γ 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             r 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mtext>
        d 
      </mtext> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           r 
         </mi> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mi>
            γ 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             r 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. Finally, for the density 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ρ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> we obtain an expression of the form 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ρ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <msub> 
         <mi>
           ρ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <msup> 
             <mi>
               ω 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <msup> 
             <mi>
               r 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.138496-"></xref>The cause of radius reduction of the circular disk cannot be attributed to the Lorentz-Fitzgerald contraction, since the vector velocity, due to the rotational motion, of each elementary mass 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        m 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mi>
        r 
      </mi> 
      <mtext>
        d 
      </mtext> 
      <mi>
        r 
      </mi> 
      <mtext>
        d 
      </mtext> 
      <mi>
        φ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        ρ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         r 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           r 
         </mi> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mi>
            γ 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             r 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mtext>
        d 
      </mtext> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mi>
           r 
         </mi> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mi>
            γ 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             r 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mtext>
        d 
      </mtext> 
      <mi>
        φ 
      </mi> 
     </mrow> 
    </math> of this disk is perpendicular to the radial straight line segment of length 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mi>
         r 
       </mi> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mi>
          γ 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           r 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>. In summary, the classical concept of Galilean kinematics, when studying phenomena that evolve in a compact rotating frame of reference, cannot include the Lorentz-Fitzgerald contraction.</p>
   <p>However, these results do not appear in the case of a rectilinear and uniformly accelerated body, in which at a given moment in time it can be considered that the body in question constitutes a momentarily physical inertial frame of reference, since at that moment in time all the elementary masses of this body are in the same kinetic state, with the same instantaneous vector velocity.</p>
   <p>According to the theory of the absolute system of reference, the main part of which is formulated in <xref ref-type="bibr" rid="scirp.138496-18">
     [18]
    </xref>-<xref ref-type="bibr" rid="scirp.138496-22">
     [22]
    </xref>, when the light source and the observer are in a momentarily inertial reference system, the measured phase velocity of the light beam propagating in a vacuum is the known from the literature. Also, according to this theory, in the case where the physical frame of reference in which the light source and the observer are located is rotating, the phase velocity of the light beam is obtained based on the rules of Galilean kinematics. Based on the theory of the absolute system of reference, we will examine the topics of the following sections.</p>
   <p>There is today a widespread concern in the scientific community regarding the constancy of the speed of light in all directions, so such a test is necessary. We would thus test the principle of the theory of relativity, on the constancy of the speed of light, which in this case is expressed by the formulation that the measurement of the speed of light is nearly independent of the self-rotational motion of the Earth.</p>
  </sec><sec id="s2">
   <title>
    <xref ref-type="bibr" rid="scirp.138496-"></xref>2. Review of the Searching for Anisotropies of the Speed of Light Behaving as the First and Third of the Legendre Polynomials</title>
   <p>The analysis of the shifts of the fringe position is made in <xref ref-type="bibr" rid="scirp.138496-23">
     [23]
    </xref> for anisotropies that behave as</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           ϕ 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msub> 
         <mi>
           c 
         </mi> 
         <mrow> 
          <msub> 
           <mo> 
           </mo> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mrow> 
       <mo>
         [ 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <msub> 
         <mi>
           b 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <msub> 
         <mi>
           P 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            cos 
          </mi> 
          <mi>
            ϕ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <msub> 
         <mi>
           b 
         </mi> 
         <mn>
           3 
         </mn> 
        </msub> 
        <msub> 
         <mi>
           P 
         </mi> 
         <mn>
           3 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            cos 
          </mi> 
          <mi>
            ϕ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ] 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
     </mrow> 
    </math></p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          cos 
        </mi> 
        <mi>
          ϕ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        cos 
      </mi> 
      <mi>
        ϕ 
      </mi> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         3 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          cos 
        </mi> 
        <mi>
          ϕ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          5 
        </mn> 
        <msup> 
         <mrow> 
          <mi>
            cos 
          </mi> 
         </mrow> 
         <mn>
           3 
         </mn> 
        </msup> 
        <mi>
          ϕ 
        </mi> 
        <mo>
          − 
        </mo> 
        <mn>
          3 
        </mn> 
        <mi>
          cos 
        </mi> 
        <mi>
          ϕ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        c 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         ϕ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> is the vacuum phase velocity of light in a direction that makes an angle 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ϕ 
     </mi> 
    </math> with a presumed single preferred direction in space.</p>
   <p>Dr. Arthur I. Miller pointed out to the authors a crucial Lorentz theorem, namely that no interferometer can detect an ether wind in first order in the earth’s velocity. [H. A. Lorentz, Theory of Electrons (Teubner, Leipzig, 1909)]. After that, in <xref ref-type="bibr" rid="scirp.138496-24">
     [24]
    </xref>, the authors retracted the claim that their experiment is able to detect an aether wind (if the ether effect can be described by a Fresnel drag coefficient).</p>
   <p>However, by correctly applying the laws of Galilean kinematics to this subject under consideration, based on the experimental result, we can determine the order of magnitude of the velocity with respect to the earth’s orbital reference system.</p>
   <fig id="fig1" position="float">
    <label>Figure 1</label>
    <caption>
     <title>Figure 1. A diagram of the interferometer used.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505477-rId60.jpeg?20241226034947" />
   </fig>
   <p>
    <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref> shows the operating principle of the interferometer used. Light entering the interferometer from the light source is split by the beam splitter into two beams which travel around the interferometer in opposite directions. These two beams recombine on the beam splitter, and a fringe pattern is formed by the lens. When the glass is present, both beams pass through the glass.</p>
   <p>The optical path of each of the two beams, which travel in opposite directions, is the isosceles triangle of <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, with interior angles 45˚, 90˚, 45˚. The length of the two equal arms is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        12 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        cm 
      </mtext> 
     </mrow> 
    </math>. The glass is 12 cm long and is made of crown glass with a refractive index of 1.5. The line segment passing through the glass has a length equal to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        2 
      </mn> 
      <mi>
        d 
      </mi> 
      <mo>
        + 
      </mo> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mn>
         2 
       </mn> 
      </msqrt> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        ≃ 
      </mo> 
      <mn>
        17 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        cm 
      </mtext> 
     </mrow> 
    </math>.</p>
   <p>According to Galilean kinematics, a path of vector length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math> of an optical beam in an earth laboratory moving with vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> with respect to the earth’s orbital reference system is defined by the equation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        + 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         c 
       </mi> 
      </mstyle> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math></p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       t 
     </mi> 
    </math> is the time required for the wavefront to travel the vector length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math>, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> is the vector phase velocity of light with respect to the earth’s orbital reference system. We denote by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> the components of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> which are perpendicular to the plane of the interferometer, and with 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> the parallels to it, so we get the equations</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
     </mrow> 
    </math>(1)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        + 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>(2)</p>
   <p>The time 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       t 
     </mi> 
    </math> is given by equation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           | 
         </mo> 
         <mrow> 
          <msub> 
           <mstyle mathvariant="bold" mathsize="normal"> 
            <mi>
              c 
            </mi> 
           </mstyle> 
           <mo>
             ∥ 
           </mo> 
          </msub> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mstyle mathvariant="bold" mathsize="normal"> 
            <mi>
              v 
            </mi> 
           </mstyle> 
           <mo>
             ∥ 
           </mo> 
          </msub> 
         </mrow> 
         <mo>
           | 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mi>
           ℓ 
         </mi> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             c 
           </mi> 
           <mo>
             ∥ 
           </mo> 
          </msub> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            + 
          </mo> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mrow> 
               <mrow> 
                <msub> 
                 <mi>
                   v 
                 </mi> 
                 <mo>
                   ∥ 
                 </mo> 
                </msub> 
               </mrow> 
               <mo>
                 / 
               </mo> 
               <mrow> 
                <msub> 
                 <mi>
                   c 
                 </mi> 
                 <mo>
                   ∥ 
                 </mo> 
                </msub> 
               </mrow> 
              </mrow> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <mn>
            2 
          </mn> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <msub> 
               <mi>
                 v 
               </mi> 
               <mo>
                 ∥ 
               </mo> 
              </msub> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mrow> 
              <msub> 
               <mi>
                 c 
               </mi> 
               <mo>
                 ∥ 
               </mo> 
              </msub> 
             </mrow> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mi>
            cos 
          </mi> 
          <mi>
            φ 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(3)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       φ 
     </mi> 
    </math> is the angle between the vectors 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         c 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math>. The dot product of the vector 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> with both sides of Equation (2) yields the equality</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mo>
        + 
      </mo> 
      <msubsup> 
       <mi>
         v 
       </mi> 
       <mo>
         ∥ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math></p>
   <p>so</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ℓ 
      </mi> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mi>
        cos 
      </mi> 
      <mi>
        θ 
      </mi> 
      <mo>
        + 
      </mo> 
      <msubsup> 
       <mi>
         v 
       </mi> 
       <mo>
         ∥ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msubsup> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         c 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mi>
        t 
      </mi> 
      <mi>
        cos 
      </mi> 
      <mi>
        φ 
      </mi> 
     </mrow> 
    </math></p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       θ 
     </mi> 
    </math> is the angle between the vectors 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math>, so substituting 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        cos 
      </mi> 
      <mi>
        φ 
      </mi> 
     </mrow> 
    </math> into the Equation (3) we get the following quadratic equation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mrow> 
          <msubsup> 
           <mi>
             v 
           </mi> 
           <mo>
             ∥ 
           </mo> 
           <mn>
             2 
           </mn> 
          </msubsup> 
         </mrow> 
         <mrow> 
          <msubsup> 
           <mi>
             c 
           </mi> 
           <mo>
             ∥ 
           </mo> 
           <mn>
             2 
           </mn> 
          </msubsup> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msup> 
       <mi>
         t 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <msub> 
         <mi>
           v 
         </mi> 
         <mo>
           ∥ 
         </mo> 
        </msub> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mrow> 
        <msubsup> 
         <mi>
           c 
         </mi> 
         <mo>
           ∥ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mi>
        t 
      </mi> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           ℓ 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msubsup> 
         <mi>
           c 
         </mi> 
         <mo>
           ∥ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>(4)</p>
   <p>and the solution is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           c 
         </mi> 
         <mo>
           ∥ 
         </mo> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mrow> 
            <msub> 
             <mi>
               v 
             </mi> 
             <mo>
               ∥ 
             </mo> 
            </msub> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msub> 
             <mi>
               c 
             </mi> 
             <mo>
               ∥ 
             </mo> 
            </msub> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <msubsup> 
               <mi>
                 v 
               </mi> 
               <mo>
                 ∥ 
               </mo> 
               <mn>
                 2 
               </mn> 
              </msubsup> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mrow> 
              <msubsup> 
               <mi>
                 c 
               </mi> 
               <mo>
                 ∥ 
               </mo> 
               <mn>
                 2 
               </mn> 
              </msubsup> 
             </mrow> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <msup> 
           <mrow> 
            <mi>
              sin 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mrow> 
          <msubsup> 
           <mi>
             v 
           </mi> 
           <mo>
             ∥ 
           </mo> 
           <mn>
             2 
           </mn> 
          </msubsup> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <msubsup> 
           <mi>
             c 
           </mi> 
           <mo>
             ∥ 
           </mo> 
           <mn>
             2 
           </mn> 
          </msubsup> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(5)</p>
   <p>Substituting 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         c 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> into Equation (5) we get the following generalized form</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msubsup> 
           <mi>
             v 
           </mi> 
           <mo>
             ⊥ 
           </mo> 
           <mn>
             2 
           </mn> 
          </msubsup> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mrow> 
            <msqrt> 
             <mrow> 
              <msup> 
               <mi>
                 v 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
              <mo>
                − 
              </mo> 
              <msubsup> 
               <mi>
                 v 
               </mi> 
               <mo>
                 ⊥ 
               </mo> 
               <mn>
                 2 
               </mn> 
              </msubsup> 
             </mrow> 
            </msqrt> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msqrt> 
             <mrow> 
              <msup> 
               <mi>
                 c 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
              <mo>
                − 
              </mo> 
              <msubsup> 
               <mi>
                 v 
               </mi> 
               <mo>
                 ⊥ 
               </mo> 
               <mn>
                 2 
               </mn> 
              </msubsup> 
             </mrow> 
            </msqrt> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <msup> 
                 <mi>
                   v 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msup> 
                <mo>
                  − 
                </mo> 
                <msubsup> 
                 <mi>
                   v 
                 </mi> 
                 <mo>
                   ⊥ 
                 </mo> 
                 <mn>
                   2 
                 </mn> 
                </msubsup> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <msup> 
                 <mi>
                   c 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msup> 
                <mo>
                  − 
                </mo> 
                <msubsup> 
                 <mi>
                   v 
                 </mi> 
                 <mo>
                   ⊥ 
                 </mo> 
                 <mn>
                   2 
                 </mn> 
                </msubsup> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <msup> 
           <mrow> 
            <mi>
              sin 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               v 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <mo>
              − 
            </mo> 
            <msubsup> 
             <mi>
               v 
             </mi> 
             <mo>
               ⊥ 
             </mo> 
             <mn>
               2 
             </mn> 
            </msubsup> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <mo>
              − 
            </mo> 
            <msubsup> 
             <mi>
               v 
             </mi> 
             <mo>
               ⊥ 
             </mo> 
             <mn>
               2 
             </mn> 
            </msubsup> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(6)</p>
   <p>If the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> is perpendicular to the plane of the interferometer, then the Equation (6) yields the following equality</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mi>
           ℓ 
         </mi> 
         <mo>
           / 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mrow> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <msup> 
             <mi>
               v 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(7)</p>
   <p>in which the time 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       t 
     </mi> 
    </math> is independent of the angle 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       θ 
     </mi> 
    </math>, so no displacement of the interference fringe pattern is observed during the rotation of the interferometer. The maximum displacement during interferometer rotation is observed when the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> is parallel to the interferometer plane, so the Equation (6) yields the following equation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mi>
             v 
           </mi> 
           <mo>
             / 
           </mo> 
           <mi>
             c 
           </mi> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <msup> 
               <mi>
                 v 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 c 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
             </mrow> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <msup> 
           <mrow> 
            <mi>
              sin 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mrow> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(8)</p>
   <p>In order to identify any effect of the earth’s self-rotating motion on the studied experiment, at least the order of magnitude of the velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math>, which obtained from the measured displacement of the interference fringe pattern, must be calculated. Because the vector velocity of the laboratory due to the self-rotating motion of the earth is parallel to the plane of the interferometer, we have to calculate the displacement of the interference fringe pattern using Equation (8).</p>
   <p>Since in this case 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mi>
         n 
       </mi> 
      </msub> 
      <msub> 
       <mrow></mrow> 
       <mrow> 
        <msub> 
         <mrow></mrow> 
         <mo>
           ∥ 
         </mo> 
        </msub> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          c 
        </mi> 
       </mstyle> 
       <mi>
         n 
       </mi> 
      </msub> 
     </mrow> 
    </math>, inside the glass Equation (2) takes the form</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         n 
       </mi> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         n 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            c 
          </mi> 
         </mstyle> 
         <mo>
           / 
         </mo> 
         <mi>
           n 
         </mi> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <mi>
          f 
        </mi> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           v 
         </mi> 
        </mstyle> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         n 
       </mi> 
      </msub> 
     </mrow> 
    </math>(9)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       f 
     </mi> 
    </math> is the Fresnel drag coefficient, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       n 
     </mi> 
    </math> is the refractive index of glass, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         n 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        ℓ 
      </mi> 
     </mrow> 
    </math>. Therefore, defining that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       θ 
     </mi> 
    </math> is the angle between the horizontal arm and the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math>, we obtain</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         n 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <mrow> 
         <mi>
           c 
         </mi> 
         <mo>
           / 
         </mo> 
         <mi>
           n 
         </mi> 
        </mrow> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              v 
            </mi> 
            <mi>
              cos 
            </mi> 
            <mi>
              θ 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              n 
            </mi> 
            <mi>
              c 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 v 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
              <msup> 
               <mrow> 
                <mi>
                  sin 
                </mi> 
               </mrow> 
               <mn>
                 2 
               </mn> 
              </msup> 
              <mi>
                θ 
              </mi> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 n 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
              <msup> 
               <mi>
                 c 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
          </mrow> 
         </mrow> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mrow> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               n 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(10)</p>
   <p>Also for the two small parts of the horizontal arm, of length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        d 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           / 
         </mo> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        × 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          17 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          cm 
        </mtext> 
        <mo>
          − 
        </mo> 
        <mn>
          12 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          cm 
        </mtext> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        2.5 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        cm 
      </mtext> 
     </mrow> 
    </math>,</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         d 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         d 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mi>
             v 
           </mi> 
           <mo>
             / 
           </mo> 
           <mi>
             c 
           </mi> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <msup> 
               <mi>
                 v 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 c 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
             </mrow> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <msup> 
           <mrow> 
            <mi>
              sin 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mrow> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(11)</p>
   <p>In each arm of the triangular interferometer, due to the opposite directions of the two beams, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <msub> 
       <mi>
         θ 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        cos 
      </mi> 
      <msub> 
       <mi>
         θ 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mo>
        , 
      </mo> 
      <mi>
        i 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        , 
      </mo> 
      <mn>
        2 
      </mn> 
      <mo>
        , 
      </mo> 
      <mn>
        3 
      </mn> 
     </mrow> 
    </math>, of one direction are opposite to those of the other direction. Based on the geometry of <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, the arrival time difference of the wavefronts of these two beams is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
      <mtr> 
       <mtd> 
        <mi>
          Δ 
        </mi> 
        <mi>
          t 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           θ 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           [ 
         </mo> 
         <mrow> 
          <mn>
            4 
          </mn> 
          <mi>
            d 
          </mi> 
          <mi>
            cos 
          </mi> 
          <mi>
            θ 
          </mi> 
          <mo>
            + 
          </mo> 
          <mn>
            2 
          </mn> 
          <mi>
            ℓ 
          </mi> 
          <mi>
            cos 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              θ 
            </mi> 
            <mo>
              + 
            </mo> 
            <mrow> 
             <mrow> 
              <mn>
                3 
              </mn> 
              <mi>
                π 
              </mi> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mn>
               4 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            + 
          </mo> 
          <mn>
            2 
          </mn> 
          <mi>
            ℓ 
          </mi> 
          <mi>
            cos 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              θ 
            </mi> 
            <mo>
              + 
            </mo> 
            <mrow> 
             <mrow> 
              <mn>
                5 
              </mn> 
              <mi>
                π 
              </mi> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mn>
               4 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ] 
         </mo> 
        </mrow> 
        <mfrac> 
         <mrow> 
          <mrow> 
           <mi>
             v 
           </mi> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <msup> 
             <mi>
               v 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mo>
          + 
        </mo> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mfrac> 
         <mrow> 
          <mrow> 
           <mi>
             v 
           </mi> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               n 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mfrac> 
         <mrow> 
          <mrow> 
           <mi>
             v 
           </mi> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <msup> 
             <mi>
               v 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
        </mfrac> 
        <mo>
          + 
        </mo> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mfrac> 
         <mrow> 
          <mrow> 
           <mi>
             v 
           </mi> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mrow> 
            <msup> 
             <mi>
               v 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <msup> 
               <mi>
                 n 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
              <msup> 
               <mi>
                 c 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msup> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          ≃ 
        </mo> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          f 
        </mi> 
        <mfrac> 
         <mrow> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             3 
           </mn> 
          </msup> 
         </mrow> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             4 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math>(12)</p>
   <p>Therefore, the maximum time difference which corresponds to the maximum displacement of the interference fringe pattern is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        Δ 
      </mtext> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mi>
          m 
        </mi> 
        <mi>
          a 
        </mi> 
        <mi>
          x 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        ℓ 
      </mi> 
      <mi>
        f 
      </mi> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           v 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(13)</p>
   <p>and the maximum displacement of the interference fringe pattern is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        δ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        4 
      </mn> 
      <mi>
        f 
      </mi> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         λ 
       </mi> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           v 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           3 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(14)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       λ 
     </mi> 
    </math> is the wavelength. Unfortunately, there are no data, the existence of which would allow a reanalysis, but we can use the values of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         b 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         b 
       </mi> 
       <mn>
         3 
       </mn> 
      </msub> 
     </mrow> 
    </math> (Equation (9), p. 3324, in <xref ref-type="bibr" rid="scirp.138496-23">
     [23]
    </xref>), considering very small the angles 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ϕ 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
     </mrow> 
    </math>, so the Legendre polynomials 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          cos 
        </mi> 
        <msub> 
         <mi>
           ϕ 
         </mi> 
         <mi>
           i 
         </mi> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         3 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          cos 
        </mi> 
        <msub> 
         <mi>
           ϕ 
         </mi> 
         <mi>
           i 
         </mi> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> are approximately equal to unity. Also the scale factor 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       F 
     </mi> 
    </math> can be considered to be of the order of magnitude of unity, so the experimental value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       δ 
     </mi> 
    </math> is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         δ 
       </mi> 
       <mrow> 
        <mi>
          e 
        </mi> 
        <mi>
          x 
        </mi> 
        <mi>
          p 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        ≃ 
      </mo> 
      <mn>
        3 
      </mn> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           b 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mo>
          + 
        </mo> 
        <msub> 
         <mi>
           b 
         </mi> 
         <mn>
           3 
         </mn> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mi>
        n 
      </mi> 
      <mi>
        ℓ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1.3 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          11 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>. Substituting this experimental value of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       δ 
     </mi> 
    </math> into Equation (14), for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        λ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        5 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          7 
        </mn> 
       </mrow> 
      </msup> 
      <mtext>
          
      </mtext> 
      <mtext>
        m 
      </mtext> 
     </mrow> 
    </math>, yields a value for the velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math> of approximately 0.87 km/s, which is of the order of magnitude of the earth’s equatorial speed of 0.4651 km/sec.</p>
  </sec><sec id="s3">
   <title>
    <xref ref-type="bibr" rid="scirp.138496-"></xref>3. A Review of Experiments Implemented Using New Technologies</title>
   <p>On January 9, 1954, a proposal by H. Littman Furth for a new ether drift experiment published. This proposal, described in <xref ref-type="bibr" rid="scirp.138496-25">
     [25]
    </xref>, had as its main objective an experiment for testing whether second-order effects predicted by classical (non-relativistic) optics as results of an “aether drift” could be detected with standing electromagnetic waves.</p>
   <p>The theoretical part of this proposal in brief is that in the absence of an ether drift one has 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ν 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mi>
          n 
        </mi> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            ℓ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ν 
     </mi> 
    </math> is the resonance frequency, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math> is the length of resonator tube, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       n 
     </mi> 
    </math> is the integral multiple of the periodic time 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       T 
     </mi> 
    </math> of the oscillator, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       c 
     </mi> 
    </math> is the phase velocity of electromagnetic wave. But if the tube points in the direction of translational movement (velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math>) of the earth with respect to the ether, the condition for resonance is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        n 
      </mi> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>, and the resonance frequency will be:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ν 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          n 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mi>
        ν 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mrow> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(15)</p>
   <p>and if the tube is at right angles to the direction of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math> the resonance frequency is:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ν 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         n 
       </mi> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
       </mrow> 
      </mfrac> 
      <msqrt> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          − 
        </mo> 
        <msup> 
         <mi>
           v 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </msqrt> 
      <mo>
        = 
      </mo> 
      <mi>
        ν 
      </mi> 
      <msqrt> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mrow> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math>(16)</p>
   <p>A few months later, on April 17, 1954, L. Essen describes with positive comments the previous article of H. Littman Furth in a new article in the same scientific journal, as seen in <xref ref-type="bibr" rid="scirp.138496-26">
     [26]
    </xref>. In the following year, on May 7, 1955, L. Essen carried out the first experiment following this new methodology. As he states in <xref ref-type="bibr" rid="scirp.138496-27">
     [27]
    </xref> “A cylindrical cavity resonator of length 16.866 cm. and diameter 8.075 cm. was used to control the frequency of an oscillator at approximately 9200 Mc./s. The resonator was mounted with its axis horizontal and was rotated continuously in a horizontal plane at a rate of about one turn per minute, the frequency of the oscillator being measured by comparison with a quartz standard at intervals of 45˚ during the rotation.”</p>
   <p>Following this experiment, a series of experiments were carried out using this methodology, some of which date from 2003 to 2015. Earth’s direction and velocity (ca. 368 km/s (229 mi/s)) relative to the CMB (cosmic microwave background) rest frame are ordinarily used as references in these searches for anisotropies. The experimental results during the period 2003-2004, as stated in <xref ref-type="bibr" rid="scirp.138496-28">
     [28]
    </xref>-<xref ref-type="bibr" rid="scirp.138496-31">
     [31]
    </xref> are 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mtext>
          Δ 
        </mtext> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        ≤ 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          15 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>, during the period 2005-2007, as stated in <xref ref-type="bibr" rid="scirp.138496-32">
     [32]
    </xref>-<xref ref-type="bibr" rid="scirp.138496-36">
     [36]
    </xref> are 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mtext>
          Δ 
        </mtext> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        ≤ 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          16 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>, in 2009, as stated in <xref ref-type="bibr" rid="scirp.138496-37">
     [37]
    </xref> <xref ref-type="bibr" rid="scirp.138496-38">
     [38]
    </xref> are 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mtext>
          Δ 
        </mtext> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        ≤ 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          17 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> and in 2015 as stated in <xref ref-type="bibr" rid="scirp.138496-39">
     [39]
    </xref> the experimental result is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mtext>
          Δ 
        </mtext> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        ≃ 
      </mo> 
      <mn>
        9.2 
      </mn> 
      <mo>
        ± 
      </mo> 
      <mn>
        10.7 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          19 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> (95% confidence interval). However, as we will demonstrate below, these experimental results are in agreement with the theory of the absolute reference system, according to which the measurement of the speed of light by an observer who is stationary in a rotating reference system is that obtained from Galilean kinematics.</p>
   <p>According to a related study in <xref ref-type="bibr" rid="scirp.138496-40">
     [40]
    </xref> (7.4. STANDING WAVES), the Cartesian components of the electric vector 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           i 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> of the incident wave, for incidence perpendicular to the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        x 
      </mi> 
      <mi>
        y 
      </mi> 
     </mrow> 
    </math> plane i.e. along the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       z 
     </mi> 
    </math> axis, are obtained by the equations</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         E 
       </mi> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           i 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <msub> 
         <mi>
           τ 
         </mi> 
         <mi>
           i 
         </mi> 
        </msub> 
       </mrow> 
      </msup> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msubsup> 
       <mi>
         E 
       </mi> 
       <mi>
         y 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           i 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <msub> 
         <mi>
           τ 
         </mi> 
         <mi>
           i 
         </mi> 
        </msub> 
       </mrow> 
      </msup> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msubsup> 
       <mi>
         E 
       </mi> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           i 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>(17)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> are the amplitudes of the components of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           i 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> parallel and perpendicular respectively to the plane of incidence,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         τ 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mi>
           z 
         </mi> 
         <mi>
           u 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(18)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ω 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <mi>
        π 
      </mi> 
      <mi>
        ν 
      </mi> 
     </mrow> 
    </math>, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       u 
     </mi> 
    </math> is the velocity of propagation. The Cartesian components of the electric vector 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           r 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> of the reflected wave are</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         E 
       </mi> 
       <mi>
         x 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           r 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <msub> 
         <mi>
           τ 
         </mi> 
         <mi>
           r 
         </mi> 
        </msub> 
       </mrow> 
      </msup> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msubsup> 
       <mi>
         E 
       </mi> 
       <mi>
         y 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           r 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <msub> 
         <mi>
           τ 
         </mi> 
         <mi>
           r 
         </mi> 
        </msub> 
       </mrow> 
      </msup> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msubsup> 
       <mi>
         E 
       </mi> 
       <mi>
         z 
       </mi> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           r 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>(19)</p>
   <p>where</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         τ 
       </mi> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           z 
         </mi> 
         <mi>
           u 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(20)</p>
   <p>We suppose that in this case the reflectivity may be taken as unity, so, by the Fresnel Formulae we obtain 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
     </mrow> 
    </math>, and if 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         y 
       </mi> 
      </msub> 
     </mrow> 
    </math> are the amplitude components of the electric vector, we may write 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ∥ 
       </mo> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mo>
         ⊥ 
       </mo> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         y 
       </mi> 
      </msub> 
     </mrow> 
    </math>. The 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math>-component of the electric vector of the total field is</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           E 
         </mi> 
         <mi>
           x 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msubsup> 
         <mi>
           E 
         </mi> 
         <mi>
           x 
         </mi> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             i 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msubsup> 
        <mo>
          + 
        </mo> 
        <msubsup> 
         <mi>
           E 
         </mi> 
         <mi>
           x 
         </mi> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             r 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msubsup> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <msub> 
         <mi>
           A 
         </mi> 
         <mi>
           x 
         </mi> 
        </msub> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               τ 
             </mi> 
             <mi>
               i 
             </mi> 
            </msub> 
            <mo>
              − 
            </mo> 
            <msub> 
             <mi>
               τ 
             </mi> 
             <mi>
               r 
             </mi> 
            </msub> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <msup> 
         <mtext>
           e 
         </mtext> 
         <mrow> 
          <mo>
            − 
          </mo> 
          <mi>
            ı 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <msub> 
                 <mi>
                   τ 
                 </mi> 
                 <mi>
                   i 
                 </mi> 
                </msub> 
                <mo>
                  + 
                </mo> 
                <msub> 
                 <mi>
                   τ 
                 </mi> 
                 <mi>
                   r 
                 </mi> 
                </msub> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
            <mo>
              − 
            </mo> 
            <mrow> 
             <mi>
               π 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msup> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math>(21)</p>
   <p>Similarly,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           E 
         </mi> 
         <mi>
           y 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msubsup> 
         <mi>
           E 
         </mi> 
         <mi>
           y 
         </mi> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             i 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msubsup> 
        <mo>
          + 
        </mo> 
        <msubsup> 
         <mi>
           E 
         </mi> 
         <mi>
           y 
         </mi> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             r 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msubsup> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <mn>
          2 
        </mn> 
        <msub> 
         <mi>
           A 
         </mi> 
         <mi>
           y 
         </mi> 
        </msub> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               τ 
             </mi> 
             <mi>
               i 
             </mi> 
            </msub> 
            <mo>
              − 
            </mo> 
            <msub> 
             <mi>
               τ 
             </mi> 
             <mi>
               r 
             </mi> 
            </msub> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <msup> 
         <mtext>
           e 
         </mtext> 
         <mrow> 
          <mo>
            − 
          </mo> 
          <mi>
            ı 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <msub> 
                 <mi>
                   τ 
                 </mi> 
                 <mi>
                   i 
                 </mi> 
                </msub> 
                <mo>
                  + 
                </mo> 
                <msub> 
                 <mi>
                   τ 
                 </mi> 
                 <mi>
                   r 
                 </mi> 
                </msub> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
            <mo>
              − 
            </mo> 
            <mrow> 
             <mi>
               π 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </msup> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math>(22)</p>
   <p>and</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (23)</p>
   <p>Let 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math> be the velocity of the laboratory relative to the earth’s orbital reference system 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math> in the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       z 
     </mi> 
    </math>-direction. In the reference system 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
      <mi>
        S 
      </mi> 
      <mo>
        ′ 
      </mo> 
     </msup> 
    </math> of the laboratory, we assume that one end-plate of the resonator tube is on the side of the microwave generator at position 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
        <mo>
          , 
        </mo> 
        <msup> 
         <mi>
           z 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
        <mi>
          ℓ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, while the other end-plate is at position 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
        <mo>
          , 
        </mo> 
        <msup> 
         <mi>
           z 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        x 
      </mi> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         z 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        z 
      </mi> 
      <mo>
        − 
      </mo> 
      <mi>
        v 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>. For refractive index equal to unity the phase velocity is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        u 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
     </mrow> 
    </math>. According to relevant study in <xref ref-type="bibr" rid="scirp.138496-41">
     [41]
    </xref> the Doppler effect is expressed by the relation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ω 
      </mi> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mi>
         ω 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <msup> 
        <mi>
          k 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mstyle> 
      <mo>
        ⋅ 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <msup> 
        <mi>
          v 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mstyle> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <msup> 
        <mi>
          v 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <msup> 
        <mi>
          k 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         k 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>, and equivalently 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         ω 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
      <mo>
        − 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         k 
       </mi> 
      </mstyle> 
      <mo>
        ⋅ 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>. The phase velocity transformation is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <msup> 
        <mi>
          u 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         u 
       </mi> 
      </mstyle> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           v 
         </mi> 
        </mstyle> 
        <mo>
          ⋅ 
        </mo> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mover accent="true"> 
          <mi>
            u 
          </mi> 
          <mo>
            ^ 
          </mo> 
         </mover> 
        </mstyle> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mover accent="true"> 
        <mi>
          u 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
      </mstyle> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mover accent="true"> 
       <mi>
         u 
       </mi> 
       <mo>
         ^ 
       </mo> 
      </mover> 
     </mstyle> 
    </math> is a unit vector in the direction of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        u 
      </mi> 
     </mstyle> 
    </math>. In 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
      <mi>
        S 
      </mi> 
      <mo>
        ′ 
      </mo> 
     </msup> 
    </math> for the incident wave we obtain 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          u 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mo>
        + 
      </mo> 
      <mi>
        v 
      </mi> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          ω 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         ω 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            c 
          </mi> 
          <mo>
            + 
          </mo> 
          <mi>
            v 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>, while for the reflected wave 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          u 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        c 
      </mi> 
      <mo>
        − 
      </mo> 
      <mi>
        v 
      </mi> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          ω 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         ω 
       </mi> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            c 
          </mi> 
          <mo>
            − 
          </mo> 
          <mi>
            v 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ω 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         ω 
       </mi> 
       <mi>
         r 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
     </mrow> 
    </math>, indicating that the observer of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
      <mi>
        S 
      </mi> 
      <mo>
        ′ 
      </mo> 
     </msup> 
    </math> receives frequencies like the derived from phase velocities of the incident and reflected electromagnetic wave in a resonator tube stationary with respect to the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math> reference system. This result is consistent with our initial assumption that the absolute value of the phase velocity is constant at 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math>, equal to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       c 
     </mi> 
    </math>, despite the microwave generator and end-plates being stationary with respect to the self-rotating system 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
      <mi>
        S 
      </mi> 
      <mo>
        ′ 
      </mo> 
     </msup> 
    </math>.</p>
   <p>According to Equations (18), (20), (21), the components of the electric vector are</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        2 
      </mn> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mi>
            t 
          </mi> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mi>
             π 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>(24)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         y 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        2 
      </mn> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         y 
       </mi> 
      </msub> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mi>
            t 
          </mi> 
          <mo>
            − 
          </mo> 
          <mrow> 
           <mi>
             π 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>(25)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>(26)</p>
   <p>and in a strictly analogous manner, using the equation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         H 
       </mi> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mi>
        n 
      </mi> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mover accent="true"> 
        <mi>
          s 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
      </mstyle> 
      <mo>
        × 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         E 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        H 
      </mi> 
     </mstyle> 
    </math> is the magnetic vector, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       n 
     </mi> 
    </math> is the refractive index of medium, and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mover accent="true"> 
       <mi>
         s 
       </mi> 
       <mo>
         ^ 
       </mo> 
      </mover> 
     </mstyle> 
    </math> denoting a unit vector in the direction of propagation, we obtain the following expressions for the components of the magnetic vector of the total field:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         y 
       </mi> 
      </msub> 
      <mi>
        cos 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <mi>
          ω 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>(27)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mi>
         y 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        2 
      </mn> 
      <msub> 
       <mi>
         A 
       </mi> 
       <mi>
         x 
       </mi> 
      </msub> 
      <mi>
        cos 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            ω 
          </mi> 
          <mi>
            z 
          </mi> 
         </mrow> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msup> 
       <mtext>
         e 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mi>
          ı 
        </mi> 
        <mi>
          ω 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </msup> 
     </mrow> 
    </math>(28)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         H 
       </mi> 
       <mi>
         z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>(29)</p>
   <p>so standing waves are created in the resonator tube with resonance frequency 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ν 
     </mi> 
    </math>.</p>
   <p>If the tube is at right angles to the direction of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math>, i.e. the tube is perpendicular to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       x 
     </mi> 
    </math>-direction, we assume that one end-plate of the resonator tube is on the side of the microwave generator at position 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
        <mo>
          , 
        </mo> 
        <msup> 
         <mi>
           z 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
        <mi>
          ℓ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, while the other end-plate is at position 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           x 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
        <mo>
          , 
        </mo> 
        <msup> 
         <mi>
           z 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> of reference system 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
      <mi>
        S 
      </mi> 
      <mo>
        ′ 
      </mo> 
     </msup> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        x 
      </mi> 
      <mo>
        − 
      </mo> 
      <mi>
        v 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         z 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        z 
      </mi> 
     </mrow> 
    </math>. In the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math> reference system the incidence must be perpendicular to the end-plate to generate standing waves, so at 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
      <mi>
        S 
      </mi> 
      <mo>
        ′ 
      </mo> 
     </msup> 
    </math> the phase velocity is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <msup> 
        <mi>
          u 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         u 
       </mi> 
      </mstyle> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           v 
         </mi> 
        </mstyle> 
        <mo>
          ⋅ 
        </mo> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mover accent="true"> 
          <mi>
            u 
          </mi> 
          <mo>
            ^ 
          </mo> 
         </mover> 
        </mstyle> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mover accent="true"> 
        <mi>
          u 
        </mi> 
        <mo>
          ^ 
        </mo> 
       </mover> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         u 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>. The Doppler effect in this case is expressed by the relation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         ω 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
      <mo>
        − 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         k 
       </mi> 
      </mstyle> 
      <mo>
        ⋅ 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
     </mrow> 
    </math>, i.e., there is not a Doppler effect. The components of the electric and magnetic vector are given by the Equations (24) to (29).</p>
   <p>We observe that following the experimental methodology of standing waves the theoretical results based on Galilean kinematics are the same as the relativistic ones. This methodology differs from that of Michelson. Also the results of the Kennedy-Thorndike experiment, stated in <xref ref-type="bibr" rid="scirp.138496-42">
     [42]
    </xref>, and of the experimental data analysis based on the methodology of testing the constancy of the speed of light from measurements derived from the Compton edge effect, stated in <xref ref-type="bibr" rid="scirp.138496-17">
     [17]
    </xref>, are in agreement with the theory of the absolute system of reference.</p>
  </sec><sec id="s4">
   <title>
    <xref ref-type="bibr" rid="scirp.138496-"></xref>4. Test of the Constancy of the Speed of Light in All Directions on the Surface of the Earth</title>
   <p>The vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> due to the self-rotating motion of the Earth has a direction towards the east, so the experimental setup should have the corresponding orientation, determined according to the cardinal points on the horizon. In this case, the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> is parallel to the plane of the interferometer. One such experiment, which actually has a somewhat satisfactory experimental resolution, is that of Illingworth which we will study.</p>
   <p>We will review the experimental work of Illingworth in 1927, described in <xref ref-type="bibr" rid="scirp.138496-9">
     [9]
    </xref>, focusing our observations on the points of interest. This experimental research is a repetition of the Michelson-Morley experiment according to a new methodology that Dr. R. J. Kennedy, National Research Fellow at the California Institute of Technology, had applied a year earlier.</p>
   <p>The total time between departure and return of the wavefront in each arm of the Michelson-Morley interferometer, based on Equation (8) is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          m 
        </mi> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        + 
      </mo> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <mi>
          π 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mi>
              ℓ 
            </mi> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mi>
             c 
           </mi> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             β 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <msup> 
           <mrow> 
            <mi>
              sin 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <msup> 
         <mi>
           β 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(30)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        β 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mi>
         v 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>.</p>
   <p>According to Equation (30), it follows that if the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> is parallel to the vector length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math>, then 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mi>
              ℓ 
            </mi> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mi>
             c 
           </mi> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             β 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>, while if the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> is perpendicular to the vector length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math> we get 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mrow> 
            <mn>
              2 
            </mn> 
            <mi>
              ℓ 
            </mi> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mi>
             c 
           </mi> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <mn>
            1 
          </mn> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             β 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>, as expected.</p>
   <p>In an experimental setup Michelson-Morley, which is located inside the Earth laboratory, the return time difference of the wave fronts of the two perpendicular light beams at the point of observation, according to Equation (30), will be equal to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          m 
        </mi> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        − 
      </mo> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mi>
          r 
        </mi> 
        <mi>
          m 
        </mi> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <mrow> 
         <mi>
           π 
         </mi> 
         <mo>
           / 
         </mo> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. If the experimental setup is rotated by 90˚ this time difference will have changed by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        Δ 
      </mtext> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>, so</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
      <mtr> 
       <mtd> 
        <mtext>
          Δ 
        </mtext> 
        <mi>
          t 
        </mi> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mi>
              a 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              m 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             θ 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mi>
              a 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              m 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              θ 
            </mi> 
            <mo>
              + 
            </mo> 
            <mrow> 
             <mi>
               π 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mi>
              a 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              m 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              θ 
            </mi> 
            <mo>
              + 
            </mo> 
            <mrow> 
             <mi>
               π 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mi>
              a 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              m 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              θ 
            </mi> 
            <mo>
              + 
            </mo> 
            <mi>
              π 
            </mi> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          = 
        </mo> 
        <mn>
          2 
        </mn> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mi>
              a 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              m 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             θ 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mi>
              a 
            </mi> 
            <mi>
              r 
            </mi> 
            <mi>
              m 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              θ 
            </mi> 
            <mo>
              + 
            </mo> 
            <mrow> 
             <mi>
               π 
             </mi> 
             <mo>
               / 
             </mo> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math>(31)</p>
   <p>therefore, the displacement of the interference fringe pattern is obtained from the relation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        δ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mi>
         λ 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           θ 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            θ 
          </mi> 
          <mo>
            + 
          </mo> 
          <mrow> 
           <mi>
             π 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(32)</p>
   <p>In his paper, Illingworth states “The purpose of the present investigation is to make a study of the sensitivity obtainable by Kennedy’s method and to make further investigations as to the presence of an ether drift using Kennedy’s apparatus”. Based on the initial finding that a small weight of 14 g caused a displacement equal to 1/500 of the fringe, starting with the field of view exactly balanced, it was noted each time how many such small weights were removed or added to bring it back into balance after from rotation 90˚. The measurement procedure and the way of calculating the average displacement, due to orientation, in terms of weight are mentioned in Tab. 2 in <xref ref-type="bibr" rid="scirp.138496-9">
     [9]
    </xref>.</p>
   <p>In <xref ref-type="table" rid="table1">
     Table 1
    </xref>, the measurements of the average displacements, due to orientation, in terms of weight, obtained by the process in which, as Illingworth states, “the observer stopped the apparatus and took a reading when he was looking north, west, south, east and north, the readings being taken every 30 seconds”. This choice was made under the assumption of a displacement of the interference fringe pattern, due to the eastward motion of the earth laboratory, so these orientations give the maximum possible displacements.</p>
   <table-wrap id="table1">
    <label>
     <xref ref-type="table" rid="table1">
      Table 1
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.138496-"></xref>Table 1. Readings that were taken at 5 A.M., 11 A.M., 5 P.M., and 11 P.M. July 9, with the procedure in which “the observer stopped the apparatus and took a reading when he was looking north, west, south, east and north”. Data are from Tab. 3 in <xref ref-type="bibr" rid="scirp.138496-9">
       [9]
      </xref>.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="22.81%"><p style="text-align:center">5 A.M.</p></td> 
      <td class="custom-bottom-td acenter" width="22.81%"><p style="text-align:center">11 A.M.</p></td> 
      <td class="custom-bottom-td acenter" width="22.81%"><p style="text-align:center">5 P.M.</p></td> 
      <td class="custom-bottom-td acenter" width="22.81%"><p style="text-align:center">11 P.M.</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="22.81%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="22.81%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="22.81%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="22.81%"><p style="text-align:center">N,S-E,W</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="22.81%"><p style="text-align:center">0.12</p></td> 
      <td class="custom-top-td acenter" width="22.81%"><p style="text-align:center">0.35</p></td> 
      <td class="custom-top-td acenter" width="22.81%"><p style="text-align:center">0.12</p></td> 
      <td class="custom-top-td acenter" width="22.81%"><p style="text-align:center">−0.05</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.57</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.21</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.28</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.09</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.00</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.03</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.72</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.63</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.10</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.15</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.08</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.22</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.32</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.11</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.09</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.00</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.01</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.24</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.15</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.20</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.07</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.15</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.03</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.18</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.03</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.03</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">0.00</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center">−0.05</p></td> 
      <td class="acenter" width="22.81%"><p style="text-align:center"></p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>According to this hypothesis, if in the initial placement, one of the two vertical arms of the interferometer is parallel to the east-west direction, based on (32), the displacement of the interference fringe pattern in a rotation of the interferometer by 90˚ is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        δ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mi>
         λ 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mn>
           0 
         </mn> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mi>
             π 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             2 
           </mn> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        ≃ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mrow> 
             <mi>
               v 
             </mi> 
             <mo>
               / 
             </mo> 
             <mi>
               c 
             </mi> 
            </mrow> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mi>
           λ 
         </mi> 
         <mo>
           / 
         </mo> 
         <mi>
           ℓ 
         </mi> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>so, as Illingworth states in <xref ref-type="bibr" rid="scirp.138496-9">
     [9]
    </xref>, in this case, the velocity, which by the way is referred to as “ether velocity”, for this experiment yields a velocity value</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        v 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        112 
      </mn> 
      <msqrt> 
       <mi>
         δ 
       </mi> 
      </msqrt> 
      <mtext>
          
      </mtext> 
      <mrow> 
       <mrow> 
        <mtext>
          km 
        </mtext> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mtext>
         s 
       </mtext> 
      </mrow> 
     </mrow> 
    </math>(33)</p>
   <p>The average value of the measurements listed in <xref ref-type="table" rid="table1">
     Table 1
    </xref> is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mover accent="true"> 
       <mi>
         w 
       </mi> 
       <mo>
         ¯ 
       </mo> 
      </mover> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <mn>
          32 
        </mn> 
       </mrow> 
      </mfrac> 
      <munderover> 
       <mstyle displaystyle="true" mathsize="140%"> 
        <mo>
          ∑ 
        </mo> 
       </mstyle> 
       <mrow> 
        <mi>
          i 
        </mi> 
        <mo>
          = 
        </mo> 
        <mn>
          1 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          32 
        </mn> 
       </mrow> 
      </munderover> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mi>
         w 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        0.0113 
      </mn> 
     </mrow> 
    </math></p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         w 
       </mi> 
       <mi>
         i 
       </mi> 
      </msub> 
     </mrow> 
    </math> is each measurement, so, since the experimental value of the displacement of the interference fringe pattern is 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        δ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mover accent="true"> 
        <mi>
          w 
        </mi> 
        <mo>
          ¯ 
        </mo> 
       </mover> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mn>
          500 
        </mn> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>, the absolute value of the velocity, according to relation (33), is</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        v 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        112 
      </mn> 
      <msqrt> 
       <mrow> 
        <mrow> 
         <mo>
           | 
         </mo> 
         <mrow> 
          <mrow> 
           <mover accent="true"> 
            <mi>
              w 
            </mi> 
            <mo>
              ¯ 
            </mo> 
           </mover> 
           <mo>
             / 
           </mo> 
           <mrow> 
            <mn>
              500 
            </mn> 
           </mrow> 
          </mrow> 
         </mrow> 
         <mo>
           | 
         </mo> 
        </mrow> 
       </mrow> 
      </msqrt> 
      <mo>
        = 
      </mo> 
      <mn>
        0.53 
      </mn> 
      <mtext>
          
      </mtext> 
      <mrow> 
       <mrow> 
        <mtext>
          km 
        </mtext> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mtext>
         s 
       </mtext> 
      </mrow> 
     </mrow> 
    </math>(34)</p>
   <p>If the procedure is followed in which, as described by Illingworth, “the directions were changed to north-east, north-west, south-west, south-east and north-east”, then the two perpendicular arms form angles 45˚ with the vector velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math>, so according to the relation (32), the displacement in a rotation of the interferometer by 90˚ is</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        δ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          c 
        </mi> 
       </mrow> 
       <mi>
         λ 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mi>
             π 
           </mi> 
           <mo>
             / 
           </mo> 
           <mn>
             4 
           </mn> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mrow> 
           <mrow> 
            <mn>
              3 
            </mn> 
            <mi>
              π 
            </mi> 
           </mrow> 
           <mo>
             / 
           </mo> 
           <mn>
             4 
           </mn> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math></p>
   <p>In this case the displacement is zero, so this procedure is not suitable for determining the requested speed. In <xref ref-type="table" rid="table2">
     Table 2
    </xref>, which records only the average displacement in terms of weights, there appears to be a tendency toward zero in the columns headed NW, SE-SW, NE.</p>
   <table-wrap id="table2">
    <label>
     <xref ref-type="table" rid="table2">
      Table 2
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.138496-"></xref>Table 2. Average displacement in terms of weights. Data taken from Tab. 3 in <xref ref-type="bibr" rid="scirp.138496-9">
       [9]
      </xref>.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="24.07%" colspan="2"><p style="text-align:center">5 A.M.</p></td> 
      <td class="custom-bottom-td acenter" width="25.30%" colspan="2"><p style="text-align:center">11 A.M.</p></td> 
      <td class="custom-bottom-td acenter" width="25.32%" colspan="2"><p style="text-align:center">5 P.M.</p></td> 
      <td class="custom-bottom-td acenter" width="25.32%" colspan="2"><p style="text-align:center">11 P.M.</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="11.71%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-top-td acenter" width="12.36%"><p style="text-align:center">NW,SE-</p><p style="text-align:center">SW,NE</p></td> 
      <td class="custom-top-td acenter" width="12.92%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-top-td acenter" width="12.38%"><p style="text-align:center">NW,SE-</p><p style="text-align:center">SW,NE</p></td> 
      <td class="custom-top-td acenter" width="12.94%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-top-td acenter" width="12.38%"><p style="text-align:center">NW,SE-</p><p style="text-align:center">SW,NE</p></td> 
      <td class="custom-top-td acenter" width="12.94%"><p style="text-align:center">N,S-E,W</p></td> 
      <td class="custom-top-td acenter" width="12.38%"><p style="text-align:center">NW,SE-</p><p style="text-align:center">SW,NE</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="11.71%"><p style="text-align:center">+0.18</p></td> 
      <td class="custom-top-td acenter" width="12.36%"><p style="text-align:center">−0.08</p></td> 
      <td class="custom-top-td acenter" width="12.92%"><p style="text-align:center">−0.004</p></td> 
      <td class="custom-top-td acenter" width="12.38%"><p style="text-align:center">−0.001</p></td> 
      <td class="custom-top-td acenter" width="12.94%"><p style="text-align:center">−0.041</p></td> 
      <td class="custom-top-td acenter" width="12.38%"><p style="text-align:center">−0.025</p></td> 
      <td class="custom-top-td acenter" width="12.94%"><p style="text-align:center">−0.17</p></td> 
      <td class="custom-top-td acenter" width="12.38%"><p style="text-align:center">+0.025</p></td> 
     </tr> 
    </table>
   </table-wrap>
  </sec><sec id="s5">
   <title>
    <xref ref-type="bibr" rid="scirp.138496-"></xref>5. Predictions of General Theory of Relativity on Light Speed Measuring in a Rotating Frame</title>
   <p>In a rotating system of reference the expression for 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <msup> 
       <mi>
         s 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math>, in cylindrical coordinates 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        , 
      </mo> 
      <mi>
        ϕ 
      </mi> 
      <mo>
        , 
      </mo> 
      <mi>
        z 
      </mi> 
     </mrow> 
    </math>, as stated in <xref ref-type="bibr" rid="scirp.138496-43">
     [43]
    </xref> (§89. Rotation, p. 254), is given by the relation:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        d 
      </mtext> 
      <msup> 
       <mi>
         s 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          − 
        </mo> 
        <msup> 
         <mi>
           Ω 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mtext>
        d 
      </mtext> 
      <msup> 
       <mi>
         t 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mn>
        2 
      </mn> 
      <mi>
        Ω 
      </mi> 
      <msup> 
       <mi>
         r 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mtext>
        d 
      </mtext> 
      <mi>
        ϕ 
      </mi> 
      <mtext>
        d 
      </mtext> 
      <mi>
        t 
      </mi> 
      <mo>
        − 
      </mo> 
      <mtext>
        d 
      </mtext> 
      <msup> 
       <mi>
         z 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        − 
      </mo> 
      <msup> 
       <mi>
         r 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mtext>
        d 
      </mtext> 
      <msup> 
       <mi>
         ϕ 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mtext>
        d 
      </mtext> 
      <msup> 
       <mi>
         r 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math>(35)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       Ω 
     </mi> 
    </math> is the angular velocity of rotation. Denoting by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         0 
       </mn> 
      </msup> 
      <mo>
        , 
      </mo> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         1 
       </mn> 
      </msup> 
      <mo>
        , 
      </mo> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        , 
      </mo> 
      <msup> 
       <mi>
         x 
       </mi> 
       <mn>
         3 
       </mn> 
      </msup> 
     </mrow> 
    </math>, respectively, the coordinates 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        c 
      </mi> 
      <mi>
        t 
      </mi> 
      <mo>
        , 
      </mo> 
      <mi>
        r 
      </mi> 
      <mo>
        , 
      </mo> 
      <mi>
        ϕ 
      </mi> 
      <mo>
        , 
      </mo> 
      <mi>
        z 
      </mi> 
     </mrow> 
    </math>, we have for the nonzero components of the metric tensor the expressions</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mrow> 
        <mn>
          00 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mrow> 
        <msup> 
         <mi>
           Ω 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mrow> 
        <mn>
          11 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mrow> 
        <mn>
          22 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <msup> 
       <mi>
         r 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mrow> 
        <mn>
          33 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mn>
        1 
      </mn> 
      <mo>
        , 
      </mo> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mi>
         g 
       </mi> 
       <mrow> 
        <mn>
          02 
        </mn> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mrow> 
        <mi>
          Ω 
        </mi> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
      <mo>
        . 
      </mo> 
     </mrow> 
    </math>(36)</p>
   <p>Also as stated in <xref ref-type="bibr" rid="scirp.138496-43">
     [43]
    </xref>, “As in every stationary field, clocks on the rotating body cannot be uniquely synchronized at all points. Proceeding with the synchronization along any closed curve, we find, upon returning to the starting point, a time differing from the initial value by an amount [see (88.5)]…”, so the time difference, due to lack of uniquely synchronization, along a path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math> is equal to</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <msubsup> 
         <mo>
           ∫ 
         </mo> 
         <mi>
           A 
         </mi> 
         <mi>
           B 
         </mi> 
        </msubsup> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msub> 
            <mi>
              g 
            </mi> 
            <mrow> 
             <mn>
               0 
             </mn> 
             <mi>
               α 
             </mi> 
            </mrow> 
           </msub> 
          </mrow> 
          <mrow> 
           <msub> 
            <mi>
              g 
            </mi> 
            <mrow> 
             <mn>
               00 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <msup> 
          <mi>
            x 
          </mi> 
          <mi>
            α 
          </mi> 
         </msup> 
        </mrow> 
       </mrow> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <msubsup> 
         <mo>
           ∫ 
         </mo> 
         <mi>
           A 
         </mi> 
         <mi>
           B 
         </mi> 
        </msubsup> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <mi>
             Ω 
           </mi> 
           <msup> 
            <mi>
              r 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
           <mtext>
             d 
           </mtext> 
           <mi>
             ϕ 
           </mi> 
          </mrow> 
          <mrow> 
           <mn>
             1 
           </mn> 
           <mo>
             − 
           </mo> 
           <mrow> 
            <mrow> 
             <msup> 
              <mi>
                Ω 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
             <msup> 
              <mi>
                r 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mrow> 
             <msup> 
              <mi>
                c 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
            </mrow> 
           </mrow> 
          </mrow> 
         </mfrac> 
        </mrow> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math></p>
   <p>or, assuming that 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        Ω 
      </mtext> 
      <mi>
        r 
      </mi> 
      <mo>
        / 
      </mo> 
      <mi>
        c 
      </mi> 
      <mo>
        ≪ 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math> (i.e. that the velocity of rotation is small compared with the velocity of light),</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          Ω 
        </mi> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <msubsup> 
         <mo>
           ∫ 
         </mo> 
         <mi>
           A 
         </mi> 
         <mi>
           B 
         </mi> 
        </msubsup> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mi>
              r 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <mi>
           ϕ 
         </mi> 
        </mrow> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math>(37)</p>
   <p>As the integral 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <msubsup> 
         <mo>
           ∫ 
         </mo> 
         <mi>
           A 
         </mi> 
         <mi>
           B 
         </mi> 
        </msubsup> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msup> 
            <mi>
              r 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </mfrac> 
         <mtext>
           d 
         </mtext> 
         <mi>
           ϕ 
         </mi> 
        </mrow> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math> is independent of 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       z 
     </mi> 
    </math>, it is defined as a plane surface, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math>, at any plane perpendicular to the axis of rotation, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       z 
     </mi> 
    </math>, according to the equation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        S 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mstyle displaystyle="true"> 
       <mrow> 
        <msubsup> 
         <mo>
           ∫ 
         </mo> 
         <msup> 
          <mi>
            A 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
         <msup> 
          <mi>
            B 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </msubsup> 
        <mrow> 
         <msup> 
          <mi>
            r 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mtext>
           d 
         </mtext> 
         <mi>
           ϕ 
         </mi> 
        </mrow> 
       </mrow> 
      </mstyle> 
     </mrow> 
    </math>, defining by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         A 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <msup> 
       <mi>
         B 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </mrow> 
    </math> the projection of the path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math> on this plane, so, we obtain the relation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mo>
        ± 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          Ω 
        </mi> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mi>
        S 
      </mi> 
     </mrow> 
    </math>(38)</p>
   <p>and the sign + or - holding according as we traverse the path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         A 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <msup> 
       <mi>
         B 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </mrow> 
    </math> in, or opposite to, the direction of rotation.</p>
   <p>Let us assume that a ray of light propagates along a straight-line path, which is the path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math>. As stated in <xref ref-type="bibr" rid="scirp.138496-43">
     [43]
    </xref>, the velocity of light, by definition, is always equal to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       c 
     </mi> 
    </math>, if the times are synchronized along the given path and if at each point we use the proper time. Since the difference between proper and world time is of the order 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <msup> 
         <mi>
           v 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math>, then in calculating the required time interval 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       t 
     </mi> 
    </math> to terms of order 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mi>
         v 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math> this difference can be neglected. Therefore, we have</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ± 
      </mo> 
      <mfrac> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          Ω 
        </mi> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mi>
        S 
      </mi> 
     </mrow> 
    </math>(39)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math> is the length of the path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math>. From this, it follows that the calculated speed of light, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mi>
         ℓ 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </mrow> 
    </math>, is equal to</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        c 
      </mi> 
      <mo>
        ± 
      </mo> 
      <mn>
        2 
      </mn> 
      <mi>
        Ω 
      </mi> 
      <mfrac> 
       <mi>
         S 
       </mi> 
       <mi>
         ℓ 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>(40)</p>
   <p>However, the phase velocity of the light ray is not given by the expression (40). Let us assume that at points 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       A 
     </mi> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       B 
     </mi> 
    </math> there are two observers who record the time of emission of an electromagnetic signal and the time of its reception respectively. In order to calculate the phase velocity of propagation of the electromagnetic signal based on the length and time measurements, the observer located at point 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       B 
     </mi> 
    </math> must take into account the time difference due to the inability to synchronize the clocks in a rotating system and correct the indication of his clock so that the term 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mo>
        ± 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            Ω 
          </mi> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mrow> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mi>
        S 
      </mi> 
     </mrow> 
    </math> in the relation (39) to be canceled. Then the phase velocity will be given by the relation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        c 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <msub> 
         <mi>
           t 
         </mi> 
         <mi>
           p 
         </mi> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(41)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the calculated propagation time of the signal from point A to point B, after the correction of the time of clock at point B.</p>
   <p>A direct way to calculate the phase velocity of the electromagnetic signal, stated in <xref ref-type="bibr" rid="scirp.138496-44">
     [44]
    </xref>, is that of transforming the expression of a plane electromagnetic wave from the inertial reference system to the rotating one. From this calculation, it follows that the phase velocity of the electromagnetic signal in the rotating reference frame is equal to that estimated in the inertial reference frame, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       c 
     </mi> 
    </math>.</p>
   <p>Let us consider the case where a light beam is emitted by a source that is stationary with respect to the surface of the earth at a geographical location and propagates parallel to the earth’s equatorial plane, along the aforementioned straight-line path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math> of length 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ℓ 
     </mi> 
    </math>. We denote by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       Ω 
     </mi> 
    </math> the angular velocity of the earth. Also we denote by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math> the vector velocity of the light source due to the rotational motion of the earth and by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       R 
     </mi> 
    </math> the distance of point 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       A 
     </mi> 
    </math> from the axis of rotation of the earth, as shown in <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref>.</p>
   <fig id="fig2" position="float">
    <label>Figure 2</label>
    <caption>
     <title>Figure 2. The light beam is directed from point 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        
  A
 
       </mi>

      </math> to point 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        
  B
 
       </mi>

      </math>. We denote by 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal">
  
        <mi>
         
   v
  
        </mi>
 
       </mstyle>

      </math> the vector velocity of the light source due to the rotational motion and by 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        
  R
 
       </mi>

      </math> the distance of point 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        
  A
 
       </mi>

      </math> from the axis of rotation of the earth. We also denote by 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        
  ℓ
 
       </mi>

      </math> the length of the path 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <mi>
         
   A
  
        </mi>
  
        <mi>
         
   B
  
        </mi>
 
       </mrow>

      </math> and by 

      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        
  θ
 
       </mi>

      </math> the angle between the vector velocity of the light source and the direction of the light beam.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505477-rId448.jpeg?20241226034948" />
   </fig>
   <p>In this case the velocity vector, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        v 
      </mi> 
     </mstyle> 
    </math>, and the straight line segments 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        O 
      </mi> 
      <mi>
        A 
      </mi> 
     </mrow> 
    </math> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math> lie in a plane which is parallel to the equatorial plane, that is, they are perpendicular to the axis of rotation of the earth. Therefore the aforementioned surface 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math> will be equal to the area of the triangle 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        O 
      </mi> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math> and will be given by the relation 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        S 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mi>
        R 
      </mi> 
      <mi>
        ℓ 
      </mi> 
      <mi>
        cos 
      </mi> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math>, where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       θ 
     </mi> 
    </math> is the angle between the vector velocity of the light source and the direction of the light beam. Therefore, the relation (39), substituting the 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtext>
       Ω 
     </mtext> 
    </math> by 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mi>
         v 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         R 
       </mi> 
      </mrow> 
     </mrow> 
    </math>, takes the form</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          v 
        </mi> 
        <mi>
          ℓ 
        </mi> 
        <mi>
          cos 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(42)</p>
   <p>If the light beam propagates eastward, then 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        cos 
      </mi> 
      <mi>
        θ 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>, so we obtain the equation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mi>
           v 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(43)</p>
   <p>whereas, if it propagates westward</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         π 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           v 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(44)</p>
   <p>However, as mentioned above, the times obtained from Equations (43), (44), are not those predicted by the phase velocity of the light beam. The phase velocity of the light beam is equal to that estimated in the inertial reference frame and the corresponding time is given by the relation</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>(45)</p>
   <p>Equation (8), which is derived based on Galilean kinematics, especially in the case where beam propagates eastward or westward, is the corresponding of Equation (42). When the propagation direction of the light beam is towards the east, according to the relation (8) the required time interval for the propagation of the light beam from point 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       A 
     </mi> 
    </math> to point 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       B 
     </mi> 
    </math>, is:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         e 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mo>
          − 
        </mo> 
        <mi>
          v 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        ≃ 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mi>
           v 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(46)</p>
   <p>and when it propagates west it is:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         w 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mo>
          + 
        </mo> 
        <mi>
          v 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        ≃ 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           v 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>(47)</p>
   <p>Despite the fact that the times obtained from the relations (43), (44), agree with those resulting from the relations (46), (47), respectively, the phase velocities of the light beam obtained from the relations (46), (47), i.e. based on Galilean kinematics, differ from the relativistic one which is constant and equal to that of the inertial reference frame.</p>
   <p>If the light beam propagates northward or southward, or, in the general case, if the path 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        A 
      </mi> 
      <mi>
        B 
      </mi> 
     </mrow> 
    </math> of the beam and the earth’s axis of rotation are in the same plane, then, since the angle 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       ϕ 
     </mi> 
    </math> remains constant, from the relation (37) it follows that the time difference 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mtext>
        Δ 
      </mtext> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> is zero, so 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mi>
         ℓ 
       </mi> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>. According to Galilean kinematics, that is, according to the relation (8) the required time interval, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>, for the propagation of the light beam to the north or south, is:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mi>
          n 
        </mi> 
        <mo>
          , 
        </mo> 
        <mi>
          s 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ℓ 
       </mi> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <msup> 
           <mi>
             c 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
          <mo>
            − 
          </mo> 
          <msup> 
           <mi>
             v 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>(48)</p>
   <p>thus, in this case, too, the Galilean phase velocity of the beam does not agree with the relativistic one.</p>
   <p>In the case in which the path of the light beam is a closed contour, the surface 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       S 
     </mi> 
    </math> is the projected area of the contour on a plane perpendicular to the axis of rotation. Therefore, the two-way speed of the light, measured by an earthly observer will be equal to 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       c 
     </mi> 
    </math>, that is, it will have the same value as the estimated in an inertial reference frame. This means that in a rotating reference frame, the estimated time from the departure to the return of a light ray to the same point is always 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          ℓ 
        </mi> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mi>
         c 
       </mi> 
      </mrow> 
     </mrow> 
    </math>, that is, independent of the speed 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       v 
     </mi> 
    </math>.</p>
  </sec><sec id="s6">
   <title>
    <xref ref-type="bibr" rid="scirp.138496-"></xref>6. Measuring the One-Way Speed of Light</title>
   <p>The purpose of the study in this section is to propose a method of measuring the speed of light in a single direction, without reflection. The proposed experiment is theoretically studied in the case of classical velocities addition, based on Galilean kinematics, namely in the case where the earth’s equatorial speed and the well-known from the literature light speed in vacuum being classically added, and it is found that the measuring of the difference between the light speed that based on Galilean kinematics and the relativistic one gives visible results.</p>
   <sec id="s6_1">
    <title>
     <xref ref-type="bibr" rid="scirp.138496-"></xref>6.1. Experimental Setup</title>
    <p>Let us consider the case of a laser source and a horizontal rotating circular frame on which are placed two plates in each of which there is a thin slit (<xref ref-type="fig" rid="fig3">
      Figure 3
     </xref>). The laser source is a uniform intensity distribution one, and through two contacts appropriately placed on the rotating frame and on the laser it sends a pulse of short duration of wavelength in the visible range, whose wavefront is very close to the thin slit of the plate closest to the laser when the two thin slits and the laser are aligned.</p>
    <fig id="fig3" position="float">
     <label>Figure 3</label>
     <caption>
      <title>Figure 3. A diagram of the experimental arrangement.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505477-rId511.jpeg?20241226034948" />
    </fig>
    <p>The laser and the sensor are stationary with respect to the laboratory, but it is possible to orient this laser in any direction, determined according to the cardinal points on the horizon. When the circular frame is stopped moving, having made the required placements of the laser source and the two plates, we consider that a small part of the laser beam can pass through the two equal width thin slits and so it can incident on the laser beam intensity measurement sensor. The number of rotations in a time period can be measured through the mechanism of emission of short-duration laser pulses.</p>
   </sec>
   <sec id="s6_2">
    <title>
     <xref ref-type="bibr" rid="scirp.138496-"></xref>6.2. Basic Theory</title>
    <p>We denote by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        d 
      </mi> 
     </math> the width of the two thin slits. We also denote by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        ℓ 
      </mi> 
     </math> the radial distance of the two thin slits. The vector velocity 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
     </math> due to the self-rotating motion of the Earth has a direction towards the east, so the experimental setup should have the corresponding orientation, determined according to the cardinal points on the horizon. In this case, the vector velocity 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
     </math> is parallel to the plane of the circular frame. According to Galilean kinematics the time required for the wavefront of the light beam to travel along a path equal to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        ℓ 
      </mi> 
     </math> is given by the relation (8).</p>
    <p>Let us consider the power of the outgoing beam, which comes from the emitted laser pulse at the exact moment of alignment of the thin slits and the laser. Let 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math> be the power of the outgoing beam when the circular frame is stationary and the laser and the thin slits are aligned. We denote by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        f 
      </mi> 
     </math> the rotation frequency of the circular frame. Also we denote by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
      </mrow> 
     </math> the distance of the inner slit from the axis of rotation, and by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
      </mrow> 
     </math> the velocities of the outer and inner slits respectively, so we obtain the equalities 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         ℓ 
       </mi> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         π 
       </mi> 
       <mtext>
           
       </mtext> 
       <mi>
         f 
       </mi> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
      </mrow> 
     </math>, and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <mi>
         π 
       </mi> 
       <mtext>
           
       </mtext> 
       <mi>
         f 
       </mi> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
      </mrow> 
     </math>. Because the width of the slits is small and the time in which the photons exit from the outer slit is also short, the movements of the two slits can be considered rectilinear.</p>
    <p>The wavefront of the emitted laser pulse reaches the outer slit in time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         τ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          θ 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>. In a time less than 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        τ 
      </mi> 
     </math> no photons exit the outer slit, so the power of the outgoing beam is zero along this slit, while at time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        τ 
      </mi> 
     </math>, due to the displacement of the outer slit by a length of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mi>
         τ 
       </mi> 
      </mrow> 
     </math>, a part of the outgoing beam of width 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         d 
       </mi> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mi>
         τ 
       </mi> 
      </mrow> 
     </math> with the corresponding power exits. Therefore, the power function of the outgoing beam with respect to time is discontinuous.</p>
    <p>If we assume that the circular frame rotates clockwise, then, after the specific time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        τ 
      </mi> 
     </math> the right edge of the inner slit allows the passage of more photons due to its movement to the right, while the left edge of the outer slit due to its movement also to the right limits the number of outgoing photons. The time interval of the increase in the width of the outgoing beam on its right side begins at time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        τ 
      </mi> 
     </math> and we consider that it is estimated at time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        t 
      </mi> 
     </math>. Suppose that during the time interval 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         Δ 
       </mtext> 
       <mi>
         t 
       </mi> 
       <mo>
         = 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         − 
       </mo> 
       <mi>
         τ 
       </mi> 
      </mrow> 
     </math>, due to the movement of the inner slit, the width of the outgoing beam on its right side increased by a length 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
      </mrow> 
     </math>. The length 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
      </mrow> 
     </math> will be equal to the length of displacement of the inner slit in time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         Δ 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math>, so 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
       <mtext>
         Δ 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math>. We denote by 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
      </mrow> 
     </math> the decrease in the width of the outgoing beam from the left side, so 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mtext>
         Δ 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math>. The total decrease in the width of the outgoing beam is equal to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          x 
        </mi> 
        <mi>
          i 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            u 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            u 
          </mi> 
          <mi>
            i 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mtext>
         Δ 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math>, so its total width at time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        t 
      </mi> 
     </math> is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         d 
       </mi> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mi>
         τ 
       </mi> 
       <mo>
         − 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            u 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            u 
          </mi> 
          <mi>
            i 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mtext>
         Δ 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math>. Therefore, the time of zeroing of the width of the outgoing beam is</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mrow> 
         <mi>
           m 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           x 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <msub> 
          <mi>
            u 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            u 
          </mi> 
          <mi>
            i 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           τ 
         </mi> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mi>
            i 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mi>
            i 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>The power of the outgoing beam, for 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         τ 
       </mi> 
       <mo>
         ≤ 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ≤ 
       </mo> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mrow> 
         <mi>
           m 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           x 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>, is 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         P 
       </mi> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             d 
           </mi> 
           <mo>
             − 
           </mo> 
           <msub> 
            <mi>
              u 
            </mi> 
            <mi>
              o 
            </mi> 
           </msub> 
           <mi>
             τ 
           </mi> 
           <mo>
             − 
           </mo> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                u 
              </mi> 
              <mi>
                o 
              </mi> 
             </msub> 
             <mo>
               − 
             </mo> 
             <msub> 
              <mi>
                u 
              </mi> 
              <mi>
                i 
              </mi> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mtext>
             Δ 
           </mtext> 
           <mi>
             t 
           </mi> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mi>
          d 
        </mi> 
       </mrow> 
      </mrow> 
     </math>. For 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         0 
       </mn> 
       <mo>
         ≤ 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         &lt; 
       </mo> 
       <mi>
         τ 
       </mi> 
      </mrow> 
     </math> there is no outgoing beam. The power function shown in <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref> is given by the following relation</p>
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>Figure 4. Curve of the power of the light beam reaching the outer thin slit versus time, which is taken once per revolution. The time 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
         
  τ
 
        </mi>

       </math> is equal to 

       <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
         <mi>
          
   t
  
         </mi>
  
         <mrow>
   
          <mo>
           
    (
   
          </mo> 
   
          <mi>
           
    θ
   
          </mi> 
   
          <mo>
           
    )
   
          </mo>
  
         </mrow>
 
        </mrow>

       </math>.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505477-rId576.jpeg?20241226034948" />
    </fig>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         P 
       </mi> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          { 
        </mo> 
        <mrow> 
         <mtable columnalign="left"> 
          <mtr columnalign="left"> 
           <mtd columnalign="left"> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd columnalign="left"> 
            <mrow> 
             <mtext>
               if 
             </mtext> 
             <mtext>
                 
             </mtext> 
             <mn>
               0 
             </mn> 
             <mo>
               ≤ 
             </mo> 
             <mi>
               t 
             </mi> 
             <mo>
               &lt; 
             </mo> 
             <mi>
               τ 
             </mi> 
             <mo>
               , 
             </mo> 
            </mrow> 
           </mtd> 
          </mtr> 
          <mtr columnalign="left"> 
           <mtd columnalign="left"> 
            <mrow> 
             <msub> 
              <mi>
                P 
              </mi> 
              <mi>
                o 
              </mi> 
             </msub> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mn>
                 1 
               </mn> 
               <mo>
                 − 
               </mo> 
               <mrow> 
                <mrow> 
                 <msub> 
                  <mi>
                    u 
                  </mi> 
                  <mi>
                    i 
                  </mi> 
                 </msub> 
                 <mi>
                   τ 
                 </mi> 
                </mrow> 
                <mo>
                  / 
                </mo> 
                <mi>
                  d 
                </mi> 
               </mrow> 
               <mo>
                 − 
               </mo> 
               <mrow> 
                <mrow> 
                 <mrow> 
                  <mo>
                    ( 
                  </mo> 
                  <mrow> 
                   <msub> 
                    <mi>
                      u 
                    </mi> 
                    <mi>
                      o 
                    </mi> 
                   </msub> 
                   <mo>
                     − 
                   </mo> 
                   <msub> 
                    <mi>
                      u 
                    </mi> 
                    <mi>
                      i 
                    </mi> 
                   </msub> 
                  </mrow> 
                  <mo>
                    ) 
                  </mo> 
                 </mrow> 
                 <mi>
                   t 
                 </mi> 
                </mrow> 
                <mo>
                  / 
                </mo> 
                <mi>
                  d 
                </mi> 
               </mrow> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </mtd> 
           <mtd columnalign="left"> 
            <mrow> 
             <mtext>
               if 
             </mtext> 
             <mtext>
                 
             </mtext> 
             <mi>
               τ 
             </mi> 
             <mo>
               ≤ 
             </mo> 
             <mi>
               t 
             </mi> 
             <mo>
               ≤ 
             </mo> 
             <msub> 
              <mi>
                t 
              </mi> 
              <mrow> 
               <mi>
                 m 
               </mi> 
               <mi>
                 a 
               </mi> 
               <mi>
                 x 
               </mi> 
              </mrow> 
             </msub> 
             <mo>
               . 
             </mo> 
            </mrow> 
           </mtd> 
          </mtr> 
         </mtable> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math></p>
    <p>The maximum power of the outgoing beam is obtained at time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        τ 
      </mi> 
     </math>, so</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mrow> 
         <mi>
           m 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           x 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           − 
         </mo> 
         <mfrac> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             π 
           </mi> 
           <mtext>
               
           </mtext> 
           <mi>
             f 
           </mi> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mi>
              o 
            </mi> 
           </msub> 
           <mi>
             t 
           </mi> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mi>
              θ 
            </mi> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mi>
            d 
          </mi> 
         </mfrac> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>(49)</p>
    <p>The required frequency of rotation of the circular frame in order to prevent the light beam from exiting the thin slit of the outer plate is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          d 
        </mi> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <mi>
           π 
         </mi> 
         <msub> 
          <mi>
            R 
          </mi> 
          <mi>
            o 
          </mi> 
         </msub> 
         <mi>
           t 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            θ 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math>(50)</p>
    <p>If the frequency 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
      </mrow> 
     </math> is measured experimentally then the time 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          θ 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> of the beam’s propagation from the slit of the inner plate to the slit of the outer one is obtained from the relation (50).</p>
    <p>In the present experimental procedure, no clocks are used to measure the time interval 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          θ 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, nor is any clock synchronization required. The physical quantities used are the distances and velocities in the space of the experimental arrangement, which can be estimated by an inertial observer who watches this experimental proceeder, since the differences in the proper time, the measured lengths and the measured velocities in the inertial and the rotating reference frames are of the order of 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mrow> 
        <mrow> 
         <msup> 
          <mi>
            v 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <msup> 
          <mi>
            c 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math>. Therefore, the value of the time interval 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mi>
          θ 
        </mi> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> predicted by the theory of relativity, for example in the case in which the laser beam propagates eastward or westward is not that obtained from the relations (43), (44), but from the equation 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         t 
       </mi> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mi>
          ℓ 
        </mi> 
        <mo>
          / 
        </mo> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </mrow> 
     </math>.</p>
   </sec>
   <sec id="s6_3">
    <title>
     <xref ref-type="bibr" rid="scirp.138496-"></xref>6.3. An Example</title>
    <p>Assume that 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         ℓ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         1 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         m 
       </mtext> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          R 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         1.2 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         m 
       </mtext> 
      </mrow> 
     </math>, 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         d 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         10 
       </mn> 
       <mtext>
           
       </mtext> 
       <mi>
         μ 
       </mi> 
       <mtext>
         m 
       </mtext> 
      </mrow> 
     </math>, and that the beam propagates east. As speed 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        v 
      </mi> 
     </math> we will consider the earth’s equatorial speed of 0.4651 km/sec. Transit time is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mi>
          e 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <mn>
           299792458 
         </mn> 
         <mo>
           − 
         </mo> 
         <mn>
           465 
         </mn> 
        </mrow> 
       </mfrac> 
       <mtext>
           
       </mtext> 
       <mtext>
         s 
       </mtext> 
       <mo>
         ≃ 
       </mo> 
       <mn>
         3.335646126 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           9 
         </mn> 
        </mrow> 
       </msup> 
       <mtext>
           
       </mtext> 
       <mtext>
         s 
       </mtext> 
      </mrow> 
     </math>(51)</p>
    <p>and when the beam propagates west the transit time is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          t 
        </mi> 
        <mi>
          w 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <mn>
           299792458 
         </mn> 
         <mo>
           + 
         </mo> 
         <mn>
           465 
         </mn> 
        </mrow> 
       </mfrac> 
       <mtext>
           
       </mtext> 
       <mtext>
         s 
       </mtext> 
       <mo>
         ≃ 
       </mo> 
       <mn>
         3.335635778 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           9 
         </mn> 
        </mrow> 
       </msup> 
       <mtext>
           
       </mtext> 
       <mtext>
         s 
       </mtext> 
      </mrow> 
     </math>(52)</p>
    <p>Also assume that 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         50 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         mW 
       </mtext> 
      </mrow> 
     </math>. In our example, the maximum power of the outgoing beam during the rotation of the circular frame is given by the relation</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mrow> 
         <mi>
           m 
         </mi> 
         <mi>
           a 
         </mi> 
         <mi>
           x 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          P 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           − 
         </mo> 
         <mfrac> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             π 
           </mi> 
           <mtext>
               
           </mtext> 
           <mi>
             f 
           </mi> 
           <msub> 
            <mi>
              R 
            </mi> 
            <mi>
              o 
            </mi> 
           </msub> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
          </mrow> 
          <mi>
            d 
          </mi> 
         </mfrac> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>(53)</p>
    <p>In this case, the curve of the outgoing beam maximum power versus frequency is plotted in <xref ref-type="fig" rid="fig5">
      Figure 5
     </xref>.</p>
    <p>The required frequency of rotation of the circular frame in order to prevent the light beam from exiting the thin slit of the outer plate, when the beam propagates east, is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <msub> 
        <mrow></mrow> 
        <mi>
          e 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           10 
         </mn> 
         <mo>
           × 
         </mo> 
         <msup> 
          <mrow> 
           <mn>
             10 
           </mn> 
          </mrow> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             6 
           </mn> 
          </mrow> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <mi>
           π 
         </mi> 
         <mo>
           × 
         </mo> 
         <mn>
           1.2 
         </mn> 
         <mo>
           × 
         </mo> 
         <mn>
           3.335646126 
         </mn> 
         <mo>
           × 
         </mo> 
         <msup> 
          <mrow> 
           <mn>
             10 
           </mn> 
          </mrow> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             9 
           </mn> 
          </mrow> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mtext>
           
       </mtext> 
       <msup> 
        <mtext>
          s 
        </mtext> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
       </msup> 
       <mo>
         ≃ 
       </mo> 
       <mn>
         23856.689 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         rpm 
       </mtext> 
      </mrow> 
     </math>(54)</p>
    <p>while, when the beam propagates west, is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <msub> 
        <mrow></mrow> 
        <mi>
          w 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           10 
         </mn> 
         <mo>
           × 
         </mo> 
         <msup> 
          <mrow> 
           <mn>
             10 
           </mn> 
          </mrow> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             6 
           </mn> 
          </mrow> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <mi>
           π 
         </mi> 
         <mo>
           × 
         </mo> 
         <mn>
           1.2 
         </mn> 
         <mo>
           × 
         </mo> 
         <mn>
           3.335635778 
         </mn> 
         <mo>
           × 
         </mo> 
         <msup> 
          <mrow> 
           <mn>
             10 
           </mn> 
          </mrow> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             9 
           </mn> 
          </mrow> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mtext>
           
       </mtext> 
       <msup> 
        <mtext>
          s 
        </mtext> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
       </msup> 
       <mo>
         ≃ 
       </mo> 
       <mn>
         23856.763 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         rpm 
       </mtext> 
      </mrow> 
     </math>(55)</p>
    <p>Therefore, in 1000 minutes of rotation with frequencies 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <msub> 
        <mrow></mrow> 
        <mi>
          e 
        </mi> 
       </msub> 
      </mrow> 
     </math> and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          f 
        </mi> 
        <mi>
          o 
        </mi> 
       </msub> 
       <msub> 
        <mrow></mrow> 
        <mi>
          w 
        </mi> 
       </msub> 
      </mrow> 
     </math>, a difference of 74 revolutions arises.</p>
    <fig id="fig5" position="float">
     <label>Figure 5</label>
     <caption>
      <title>Figure 5. The power versus frequency curve.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/7505477-rId621.jpeg?20241226034948" />
    </fig>
   </sec>
  </sec><sec id="s7">
   <title>7. Discussion</title>
   <p>As references in the test of the constancy of light speed, Earth’s direction and velocity (ca. 368 km/s (229 mi/s)) relative to the cosmic microwave background (CMB) rest frame are ordinarily used. As stated in <xref ref-type="bibr" rid="scirp.138496-22">
     [22]
    </xref>, “The spherical electromagnetic wave, which consists of free photons of gravitational field force carriers, comes from the continuous conversion of bound photons into free photons (and vice versa), and their frequency spectrum is the spectrum of the ‘mass frequency’ of bound photons from which they originate…”. The photons of the CMB are the force carriers of the gravitational attraction field, as correctly stated in <xref ref-type="bibr" rid="scirp.138496-45">
     [45]
    </xref>. Therefore, the CMB rest frame is the absolute reference system. However, based on the theory of the absolute reference system, the “absolute reference system” is not the one referred to in the literature as “preferred system of reference”, with respect to which any light ray propagates with a constant phase velocity 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       c 
     </mi> 
    </math>. According to the theory of the absolute reference system, the “preferred system of reference” for a laboratory anywhere in the universe is a corresponding inertial reference system which is characterized by specific “transport frequencies” of the structural elements of the matter of the laboratory, and these “transport frequencies” the light ray in question also has.</p>
   <p>The Earth’s orbital motion is considered inertial during measurements of the displacement of the interference fringe pattern. The tests of the Michelson-Morley experiment show that this movement of the Earth does not affect the speed of light in any direction. But the Earth’s self-rotating motion is a field of research, in terms of testing the constancy of the speed of light in all directions, for an observer in a self-rotating frame of reference. Due to the very low Earth’s equatorial speed compared to the speed of light the use of an interferometer to test the constancy of the speed of light in this reference system requires a corresponding experimental resolution. Illingworth’s measurements, analyzed based on the revision of the origin of the interference fringe pattern displacement phenomenon in the present study, seem to approach this goal.</p>
   <p>The value of the speed obtained from the relationship (34), if not interpreted as the speed of the Earth with respect to the ether, but as a speed due to the Earth’s self-rotation, approaches the value of Earth’s equatorial speed reported in the literature. Although the statistical errors are large, the result of the relationship (34) is an indication, prompting us to examine the correctness of this hypothesis by repeating the experiment with a more accurate experimental setup.</p>
  </sec>
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