<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    ojmsi
   </journal-id>
   <journal-title-group>
    <journal-title>
     Open Journal of Modelling and Simulation
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2327-4018
   </issn>
   <issn publication-format="print">
    2327-4026
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/ojmsi.2025.131001
   </article-id>
   <article-id pub-id-type="publisher-id">
    ojmsi-138161
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Model Design and Simulation of an 80 kW Capacitor Coupled Substation Derived from a 132 kV Transmission Line
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Sinqobile Wiseman
      </surname>
      <given-names>
       Nene
      </given-names>
     </name>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Bolanle Tolulope
      </surname>
      <given-names>
       Abe
      </given-names>
     </name>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Agha Francis
      </surname>
      <given-names>
       Nnachi
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aDepartment of Electrical Engineering, Tshwane University of Technology, eMalahleni, South Africa
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     16
    </day> 
    <month>
     12
    </month>
    <year>
     2024
    </year>
   </pub-date> 
   <volume>
    13
   </volume> 
   <issue>
    01
   </issue>
   <fpage>
    1
   </fpage>
   <lpage>
    19
   </lpage>
   <history>
    <date date-type="received">
     <day>
      31,
     </day>
     <month>
      Octobre
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      13,
     </day>
     <month>
      Octobre
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      13,
     </day>
     <month>
      December
     </month>
     <year>
      2024
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    The global rise in energy demand, particularly in remote and sparsely populated regions, necessitates innovative and cost-effective electrical distribution solutions. Traditional Rural Electrification (RE) methods, like Conventional Rural Electrification (CRE), have proven economically unfeasible in such areas due to high infrastructure costs and low electricity demand. Consequently, Unconventional Rural Electrification (URE) technologies, such as Capacitor Coupled Substations (CCS), are gaining attention as viable alternatives. This study presents the design and simulation of an 80 kW CCS system, which taps power directly from a 132 kV transmission line to supply low-voltage consumers. The critical components of the CCS, the capacitors are calculated, then a MATLAB/Simulink model with the attained results is executed. Mathematical representation and state-space representation for maintaining the desired tapped voltage area also developed. The research further explores the feasibility and operational performance of this CCS configuration, aiming to address the challenges of rural electrification by offering a sustainable and scalable solution. The results show that the desired value of the tapped voltage can be achieved at any level of High Voltage (HV) with the selection of capacitors that are correctly rated. With an adequately designed control strategy, the research also shows that tapped voltage can be attained under both steady-state and dynamic loads. By leveraging CCS technology, the study demonstrates the potential for delivering reliable electricity to underserved areas, highlighting the system’s practicality and effectiveness in overcoming the limitations of conventional distribution methods.
   </abstract>
   <kwd-group> 
    <kwd>
     Capacitor-Coupled Substation
    </kwd> 
    <kwd>
      Transmission Line-linked Capacitor-Coupled Substation
    </kwd> 
    <kwd>
      Capacitor-Coupled Substation Simulation
    </kwd> 
    <kwd>
      Microgrids
    </kwd> 
    <kwd>
      Rural Electrification
    </kwd> 
    <kwd>
      Power System Modeling
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>The rapid growth in global energy demand, coupled with the need for sustainable and economically viable power solutions, has prompted a re-evaluation of traditional electrical distribution methods, especially in remote and sparsely populated regions <xref ref-type="bibr" rid="scirp.138161-1">
     [1]
    </xref>. The demand for efficient and cost-effective electrical distribution has driven innovations in power system architectures <xref ref-type="bibr" rid="scirp.138161-2">
     [2]
    </xref>. Traditional approaches to Rural Electrification (RE) such as Conventional Rural Electrification (CRE) have been considered economically unviable in sparsely populated regions, particularly rural areas, as they are often associated with minimal electricity demand perception <xref ref-type="bibr" rid="scirp.138161-3">
     [3]
    </xref> <xref ref-type="bibr" rid="scirp.138161-4">
     [4]
    </xref>. As a result, Un-Conventional Rural Electrification (URE) technologies are being explored to provide a cost-effective system for supplying electrical power to rural areas <xref ref-type="bibr" rid="scirp.138161-5">
     [5]
    </xref> <xref ref-type="bibr" rid="scirp.138161-6">
     [6]
    </xref>. CCS represents a technology that is currently under continuous exploration for rural electrification purposes <xref ref-type="bibr" rid="scirp.138161-7">
     [7]
    </xref> <xref ref-type="bibr" rid="scirp.138161-8">
     [8]
    </xref>. CCS entails coupling capacitors used to tap electrical power from HV lines and convert it to distribution-level voltages. However, directly tapping power from an HV transmission line using CCS can induce transient behaviours within the electrical network, inevitably impacting the primary components of the CCS <xref ref-type="bibr" rid="scirp.138161-9">
     [9]
    </xref>-<xref ref-type="bibr" rid="scirp.138161-11">
     [11]
    </xref>.</p>
   <p>This article presents a comprehensive review of a model design and simulation of an 80 kW CCS tapped from a 132 kV transmission line. The main objective of this study is to assess the feasibility and performance of the proposed CCS configuration, designed with the aim of delivering electricity directly from the HV lines to the LV consumers. Microgrids, while recognized as a potential solution, have not yet developed a comprehensive business model that effectively balances affordability with satisfactory cost recovery <xref ref-type="bibr" rid="scirp.138161-12">
     [12]
    </xref>. By using CCS, electrification to remote or sparsely populated areas can be cost-effective as opposed to using conventional distribution network infrastructure <xref ref-type="bibr" rid="scirp.138161-4">
     [4]
    </xref>.</p>
   <sec id="s1_1">
    <title>1.1. Research Problem</title>
    <p>The increasing demand for efficient and cost-effective electrical distribution, particularly in remote and sparsely populated areas, necessitates innovative power system architectures. Conventional approaches to rural electrification, such as the use of standard distribution networks, have proven economically unviable due to the high infrastructure costs and low electricity demand in these regions. Consequently, unconventional solutions like Capacitor Coupled Substations (CCS) are being explored as potential alternatives.</p>
    <p>This study seeks to evaluate the feasibility and performance of an 80 kW CCS design, which taps power directly from a 132 kV transmission line, to supply electricity to low-voltage consumers. By investigating this configuration, the research aims to determine whether CCS can serve as a cost-effective solution for rural electrification, overcoming the limitations of traditional distribution methods and addressing the challenge of delivering affordable, reliable electricity to sparsely populated areas.</p>
   </sec>
   <sec id="s1_2">
    <title>1.2. Contribution</title>
    <p>The study contributes to the ongoing exploration of CCS by providing a detailed design and simulation of an 80 kW CCS system. It enhances understanding of CCS’s practical applications in rural electrification, offering insights into the system’s operational performance, stability, and potential as a scalable solution for delivering electricity to underserved areas.</p>
   </sec>
   <sec id="s1_3">
    <title>1.3. Novelty Contribution</title>
    <p>While CCSs have been explored theoretically, their application for direct tapping from HV lines to supply electricity to LV consumers, particularly in sparsely populated or rural areas, remains unexplored. The study provides a unique approach by proposing and simulating an 80 kW CCS system, specifically designed to deliver electricity from a 132 kV transmission line to LV consumers. This fills a gap in the existing research, where practical implementations of such systems are scarce.</p>
    <sec id="s1">
     <title>2. Background Theory</title>
     <p>One of the recent instances of practical implementation of a CCS has clearly demonstrated the system’s feasibility and effectiveness in supplying electrical power to dedicated loads <xref ref-type="bibr" rid="scirp.138161-13">
       [13]
      </xref>. Through rigorous testing and operation, practical studies have shown that CCS can reliably meet the energy needs of specific consumers or applications, thereby, highlighting its potential as a viable solution for electrification in various contexts such as in sparsely populated areas or low dedicated loads <xref ref-type="bibr" rid="scirp.138161-14">
       [14]
      </xref>. A CCS can be integrated into an electrical transmission network using either a nominal-π or nominal-T configuration. The nominal-T configuration is typically employed for shorter transmission lines, extending up to 80 km, while the nominal-π configuration is preferred for medium-length transmission lines exceeding 80 km <xref ref-type="bibr" rid="scirp.138161-15">
       [15]
      </xref>. In essence, current studies do not provide any limitations on the type of transmission line where a CCS can be adopted.</p>
     <p>
      <xref ref-type="fig" rid="fig1">
       Figure 1
      </xref> below illustrates the simplified depiction of a typical CCS. This approach is similar to that of a Capacitive Voltage Transformer (CVT), which is a transformer commonly used in power systems to reduce extra-high voltage signals to low voltage signals for tasks such as metering or operating protective relays <xref ref-type="bibr" rid="scirp.138161-16">
       [16]
      </xref> <xref ref-type="bibr" rid="scirp.138161-17">
       [17]
      </xref>.</p>
     <p>The simplified CCS, as shown in <xref ref-type="fig" rid="fig1">
       Figure 1
      </xref> above, employs a capacitor-divider configuration where capacitors (C<sub>1</sub> and C<sub>2</sub>) are linked across the incoming voltage (V<sub>in</sub>) to generate the desired tap-voltage (V<sub>T</sub>), which is measured from the tapping node located between the two capacitors. The voltage output (V<sub>out</sub>) is calculated by subtracting the voltage drop across the inductor (L) from V<sub>T</sub>. It is important to note that C<sub>1</sub> and C<sub>2</sub> refer to capacitor banks rather than individual capacitors where C<sub>1</sub> represents Capacitor Bank 1, while C<sub>2</sub> represents Capacitor Bank 2.</p>
     <fig id="fig1" position="float">
      <label>Figure 1</label>
      <caption>
       <title>Figure 1. Overly simplified CCS <xref ref-type="bibr" rid="scirp.138161-18">
         [18]
        </xref>.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId15.jpeg?20241216043837" />
     </fig>
     <p>The tap-voltage (V<sub>T</sub>) is calculated as follows:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           T 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            i 
          </mi> 
          <mi>
            n 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          × 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math> (1)</p>
     <p>The output voltage is calculated as follows:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            o 
          </mi> 
          <mi>
            u 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           T 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             L 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> (2)</p>
     <p>The output voltage can also be represented as follows:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            o 
          </mi> 
          <mi>
            u 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mo>
          × 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           L 
         </mi> 
        </msub> 
       </mrow> 
      </math> (3)</p>
     <p>The equations provided, as (1), (2), and (3), serve as the basis for determining the elements of a CCS. The objective is to ensure the stability of V<sub>out</sub> as the CCS delivers power to a downstream transformer within the distribution network.</p>
     <p>In <xref ref-type="fig" rid="fig2">
       Figure 2
      </xref> below, the equivalent CCS connected to a standard transmission line is depicted.</p>
     <fig id="fig2" position="float">
      <label>Figure 2</label>
      <caption>
       <title>Figure 2. CCS connected to a typical transmission line.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId22.jpeg?20241216043837" />
     </fig>
    </sec>
   </sec>
   <sec id="s3">
    <title>3. Methodology</title>
    <p>The methodology outlines the sequential steps undertaken in a research study <xref ref-type="bibr" rid="scirp.138161-19">
      [19]
     </xref>. In this study, the methodology undertaken involved the calculation of the required capacitors to achieve the desired tap voltage, the mathematical representation of the system and the development, modeling, and analysis of a CCS system using MATLAB/Simulink software. Subsequently, the results derived from the MATLAB/Simulink model were thoroughly analysed. <xref ref-type="fig" rid="fig3">
      Figure 3
     </xref> illustrates the designed block diagram model, while <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref> and <xref ref-type="fig" rid="fig5">
      Figure 5
     </xref> depict the line model utilized in the analysis. These figures provide visual representations of the models employed in the study, facilitating a comprehensive understanding of the research approach and findings of the research.</p>
    <p>
     <xref ref-type="fig" rid="fig3">
      Figure 3
     </xref> displays the model block diagram encompassing various components, including the supply block, the transmission line segment preceding the CCS tap node, the transmission line segment succeeding the CCS tap node, the downstream transmission line block, the CCS block itself, and the CCS load block. Additionally, <xref ref-type="fig" rid="fig4">
      Figure 4
     </xref> shows the physical model representation of a CCS.</p>
    <fig id="fig3" position="float">
     <label>Figure 3</label>
     <caption>
      <title>Figure 3. Model block diagram.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId23.jpeg?20241216043838" />
    </fig>
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>Figure 4. CCS model.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId24.jpeg?20241216043838" />
    </fig>
    <sec id="s3_1">
     <title>3.1. Parameters Used</title>
     <p>The aim of this study is to develop and simulate an 80 kW loaded Capacitor Coupled Substation (CCS) connected to a standard transmission network. The selected transmission network is operated at 132 kVrms. To define the parameters of the CCS, predetermined values were used, and background calculations were conducted and the results were used for the model. The selected parameters are detailed in <xref ref-type="table" rid="table1">
       Table 1
      </xref>.</p>
     <table-wrap id="table1">
      <label>
       <xref ref-type="table" rid="table1">
        Table 1
       </xref></label>
      <caption>
       <title>
        <xref ref-type="bibr" rid="scirp.138161-"></xref>Table 1. Model system known parameters.</title>
      </caption>
      <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
       <tr> 
        <td class="custom-bottom-td acenter" width="28.60%"><p style="text-align:center">Parameter</p></td> 
        <td class="custom-bottom-td acenter" width="28.60%"><p style="text-align:center">Value</p></td> 
        <td class="custom-bottom-td acenter" width="42.81%"><p style="text-align:center">Description</p></td> 
       </tr> 
       <tr> 
        <td class="custom-top-td acenter" width="28.60%"><p style="text-align:center">V<sub>s</sub></p></td> 
        <td class="custom-top-td acenter" width="28.60%"><p style="text-align:center">132 kV rms</p></td> 
        <td class="custom-top-td acenter" width="42.81%"><p style="text-align:center">Supply voltage representing upstream of the transmission line</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="28.60%"><p style="text-align:center">V<sub>T</sub></p></td> 
        <td class="acenter" width="28.60%"><p style="text-align:center">11 kV rms</p></td> 
        <td class="acenter" width="42.81%"><p style="text-align:center">The desired tap voltage for the CCS</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="28.60%"><p style="text-align:center">CCS load</p></td> 
        <td class="acenter" width="28.60%"><p style="text-align:center">400 V rms, 50 Hz, 80 kW, 0.8 PF</p></td> 
        <td class="acenter" width="42.81%"><p style="text-align:center">The CCS load voltage level</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="28.60%"><p style="text-align:center">Downstream load</p></td> 
        <td class="acenter" width="28.60%"><p style="text-align:center">132 kV rms, 50 Hz, 50 MW</p></td> 
        <td class="acenter" width="42.81%"><p style="text-align:center">Load downstream of the CCS tap note</p></td> 
       </tr> 
      </table>
     </table-wrap>
     <p>The parameters in <xref ref-type="table" rid="table1">
       Table 1
      </xref> are used to calculate the variables required in order to achieve the desired V<sub>TAP</sub>, and thus, the CCS load voltage of 400 V rms. The voltage selected is based on readily available and commonly used transmission lines and distribution transmission voltages in South Africa.</p>
     <p>Using (1), (2) and (3), with known supply voltage and the desired tap voltage, the respective capacitors C<sub>1</sub> and C<sub>2</sub> are calculated.</p>
    </sec>
    <sec id="s3_2">
     <title>
      <xref ref-type="bibr" rid="scirp.138161-"></xref>3.2. Modeling and Simulation</title>
     <p>The process of modeling the system involves the utilization of MATLAB/Simulink software, a powerful computational tool widely employed in engineering research. Furthermore, to ensure a comprehensive analysis, different voltage levels were used to determine the impact on the capacitors to keep tapped voltage within acceptable tolerances. This approach provided a deeper understanding of the system’s behaviour under varying conditions. The parameters used in the simulated model, crucial for accurately capturing the system behaviour, are outlined in <xref ref-type="table" rid="table1">
       Table 1
      </xref>.</p>
     <p>The model utilized for simulating the system is depicted in <xref ref-type="fig" rid="fig4">
       Figure 4
      </xref> in the preceding section. This model was streamlined by employing internal MATLAB/Simulink parameters within the subsystem. The primary parameter values were extracted mainly from six model scopes, as outlined in <xref ref-type="table" rid="table2">
       Table 2
      </xref>.</p>
     <p>The simulation was conducted with all circuit breakers in the system remaining closed for the entire duration of the 1.5-second simulation run. The findings from this simulation are elaborated upon in Section 4.</p>
     <table-wrap id="table2">
      <label>
       <xref ref-type="table" rid="table2">
        Table 2
       </xref></label>
      <caption>
       <title>
        <xref ref-type="bibr" rid="scirp.138161-"></xref>Table 2. Measured parameters by scope.</title>
      </caption>
      <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
       <tr> 
        <td class="custom-bottom-td acenter" width="30.81%"><p style="text-align:center">Scope number</p></td> 
        <td class="custom-bottom-td acenter" width="69.19%"><p style="text-align:center">Scop measured parameters</p></td> 
       </tr> 
       <tr> 
        <td class="custom-top-td acenter" width="30.81%"><p style="text-align:center">Scope 1</p></td> 
        <td class="custom-top-td acenter" width="69.19%"><p style="text-align:center">Supply parameters</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="30.81%"><p style="text-align:center">Scope 2</p></td> 
        <td class="acenter" width="69.19%"><p style="text-align:center">Transmission network downstream parameters</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="30.81%"><p style="text-align:center">Scope 3</p></td> 
        <td class="acenter" width="69.19%"><p style="text-align:center">CCS tap parameter</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="30.81%"><p style="text-align:center">Scope 4</p></td> 
        <td class="acenter" width="69.19%"><p style="text-align:center">Distribution transformer primary voltage</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="30.81%"><p style="text-align:center">Scope 5</p></td> 
        <td class="acenter" width="69.19%"><p style="text-align:center">Distribution transformer secondary voltage</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="30.81%"><p style="text-align:center">Scope 6</p></td> 
        <td class="acenter" width="69.19%"><p style="text-align:center">CCS load parameter</p></td> 
       </tr> 
      </table>
     </table-wrap>
    </sec>
   </sec>
   <sec id="s4">
    <title>4. Results and Discussion</title>
    <p>The results obtained from the calculations and simulated model are presented in detail. The results are analysed and discussed to provide comprehensive insights into the performance of the system. These findings are visually represented, and each offers a distinct perspective on various aspects of the simulation. Through the interpretation of these figures, we aim to assess the behaviour and characteristics of the simulated system under normal steady state conditions, contributing to a deeper understanding of its functionality.</p>
    <sec id="s4_1">
     <title>4.1. Calculated Results</title>
     <p>Using the known parameters as per <xref ref-type="table" rid="table1">
       Table 1
      </xref>, to calculate the values of the capacitor banks 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> with the given parameters, the following results were achieved.</p>
     <p>Using:</p>
     <p>From Equation (1), 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> are calculated as:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             V 
           </mi> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              p 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             V 
           </mi> 
           <mi>
             s 
           </mi> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math></p>
     <p>With the known supply voltage and the desired 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>, the ratio is:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            11 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            kV 
          </mtext> 
         </mrow> 
         <mrow> 
          <mn>
            132 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            kV 
          </mtext> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            11 
          </mn> 
         </mrow> 
         <mrow> 
          <mn>
            132 
          </mn> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mn>
            12 
          </mn> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math></p>
     <p>Therefore, the relationship between 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> is:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          11 
        </mn> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math></p>
     <p>The individual capacitor banks capacitance is calculated using the system frequency of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          f 
        </mi> 
        <mo>
          = 
        </mo> 
        <mn>
          50 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          Hz 
        </mtext> 
       </mrow> 
      </math> and the relationship between the reactance 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           X 
         </mi> 
         <mi>
           C 
         </mi> 
        </msub> 
       </mrow> 
      </math> and capacitance 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
         C 
       </mi> 
      </math> as:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           X 
         </mi> 
         <mi>
           C 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
          <mtext>
              
          </mtext> 
          <mi>
            f 
          </mi> 
          <mtext>
              
          </mtext> 
          <mi>
            C 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math></p>
     <p>Ignoring the load impedance gives the ratio of the capacitors as 1:11 (from 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          11 
        </mn> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math>). Therefore:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mi>
              o 
            </mi> 
            <mi>
              t 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              l 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <mn>
            12 
          </mn> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            11 
          </mn> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mi>
              o 
            </mi> 
            <mi>
              t 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              l 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <mn>
            12 
          </mn> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math></p>
     <p>The actual values of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math>, with the CCS power of 80 kW at 0.8PF is calculated from:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mtext>
          Apparent 
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
          Power 
        </mtext> 
        <mtext>
            
        </mtext> 
        <mi>
          S 
        </mi> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mi>
           P 
         </mi> 
         <mrow> 
          <mi>
            P 
          </mi> 
          <mi>
            F 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            80 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            kW 
          </mtext> 
         </mrow> 
         <mrow> 
          <mn>
            0.8 
          </mn> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mn>
          100 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kV 
        </mtext> 
        <mo>
          ⋅ 
        </mo> 
        <mtext>
          A 
        </mtext> 
       </mrow> 
      </math></p>
     <p>Assuming nominal total reactive power is balanced:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            l 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          ≈ 
        </mo> 
        <mfrac> 
         <mi>
           S 
         </mi> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
          <mtext>
              
          </mtext> 
          <mi>
            f 
          </mi> 
          <mtext>
              
          </mtext> 
          <msubsup> 
           <mi>
             V 
           </mi> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              p 
            </mi> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msubsup> 
         </mrow> 
        </mfrac> 
        <mo>
          ≈ 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            100 
          </mn> 
          <mo>
            × 
          </mo> 
          <msup> 
           <mrow> 
            <mn>
              10 
            </mn> 
           </mrow> 
           <mn>
             3 
           </mn> 
          </msup> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mo>
            × 
          </mo> 
          <mn>
            3.14146 
          </mn> 
          <mo>
            × 
          </mo> 
          <msup> 
           <mrow> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mn>
                11 
              </mn> 
              <mo>
                × 
              </mo> 
              <msup> 
               <mrow> 
                <mn>
                  10 
                </mn> 
               </mrow> 
               <mn>
                 3 
               </mn> 
              </msup> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
           </mrow> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
        <mo>
          ≈ 
        </mo> 
        <mn>
          2.63 
        </mn> 
        <mtext>
            
        </mtext> 
        <mi>
          μ 
        </mi> 
        <mtext>
          F 
        </mtext> 
       </mrow> 
      </math></p>
     <p>Therefore:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mo>
          ≈ 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            2.63 
          </mn> 
          <mtext>
              
          </mtext> 
          <mi>
            μ 
          </mi> 
          <mi>
            F 
          </mi> 
         </mrow> 
         <mrow> 
          <mn>
            12 
          </mn> 
         </mrow> 
        </mfrac> 
        <mo>
          ≈ 
        </mo> 
        <mn>
          0.22 
        </mn> 
        <mtext>
            
        </mtext> 
        <mi>
          μ 
        </mi> 
        <mtext>
          F 
        </mtext> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mo>
          ≈ 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            11 
          </mn> 
          <mo>
            × 
          </mo> 
          <mn>
            2.63 
          </mn> 
          <mtext>
              
          </mtext> 
          <mi>
            μ 
          </mi> 
          <mi>
            F 
          </mi> 
         </mrow> 
         <mrow> 
          <mn>
            12 
          </mn> 
         </mrow> 
        </mfrac> 
        <mo>
          ≈ 
        </mo> 
        <mn>
          2.41 
        </mn> 
        <mtext>
            
        </mtext> 
        <mi>
          μ 
        </mi> 
        <mtext>
          F 
        </mtext> 
       </mrow> 
      </math>.</p>
     <p>From the calculated value of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math>, the simulation values used are presented in <xref ref-type="table" rid="table3">
       Table 3
      </xref>.</p>
     <table-wrap id="table3">
      <label>
       <xref ref-type="table" rid="table3">
        Table 3
       </xref></label>
      <caption>
       <title>
        <xref ref-type="bibr" rid="scirp.138161-"></xref>Table 3. Simulation parameters based on calculated C<sub>1</sub> and C<sub>2</sub>.</title>
      </caption>
      <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
       <tr> 
        <td class="custom-bottom-td acenter" width="27.01%"><p style="text-align:center">Parameter</p></td> 
        <td class="custom-bottom-td acenter" width="39.66%"><p style="text-align:center">Value</p></td> 
        <td class="custom-bottom-td acenter" width="33.33%"><p style="text-align:center">Source</p></td> 
       </tr> 
       <tr> 
        <td class="custom-top-td acenter" width="27.01%"><p style="text-align:center">V<sub>s</sub></p></td> 
        <td class="custom-top-td acenter" width="39.66%"><p style="text-align:center">132 kV rms</p></td> 
        <td class="custom-top-td acenter" width="33.33%"><p style="text-align:center">Selected transmission line</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">V<sub>T</sub></p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">11 kV rms</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Selected tap voltage</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">CCS load</p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">400 V rms, 50 Hz, 80 kW, 0.8 PF</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Selected load value</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">Downstream load</p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">132 kV rms, 50 Hz, 50 MW</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Selected load value</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">CCS transformer</p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">11 kV/400 V</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Selected transformer</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">C<sub>1</sub></p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">0.22 µF</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Calculated capacitor 1</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">C<sub>2</sub></p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">2.41 µF</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Calculated capacitor 2</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">L</p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">1 mH</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Line inductance</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">Tx line section #1</p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">300 km</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Selected</p></td> 
       </tr> 
       <tr> 
        <td class="acenter" width="27.01%"><p style="text-align:center">Tx line section #2</p></td> 
        <td class="acenter" width="39.66%"><p style="text-align:center">300 km</p></td> 
        <td class="acenter" width="33.33%"><p style="text-align:center">Selected</p></td> 
       </tr> 
      </table>
     </table-wrap>
    </sec>
    <sec id="s4_2">
     <title>4.2. Single Line Representation</title>
     <p>The calculated values of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> are then used to simulate the system and observe its behaviour. The results obtained from the simulation are shown in <xref ref-type="fig" rid="figFigures 4-8">
       Figures 4-8
      </xref> and <xref ref-type="fig" rid="fig9">
       Figure 9
      </xref>.</p>
     <p>
      <xref ref-type="fig" rid="fig5">
       Figure 5
      </xref> presents the supply voltage parameters with 132 kV rms as the supply and the resulting current, active power and reactive power based on the given CCS and downstream load. The downstream load parameters are also presented in <xref ref-type="fig" rid="fig6">
       Figure 6
      </xref>.</p>
     <p>
      <xref ref-type="fig" rid="fig7">
       Figure 7
      </xref> presents the CCS tap node with the 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> being approximately 15.6 kV peak ≈ 11 kV rms, with <xref ref-type="fig" rid="fig8">
       Figure 8
      </xref> representing the resulting CCS transformer secondary voltage of approximately 565 V peak ≈ 400 V rms, while <xref ref-type="fig" rid="fig9">
       Figure 9
      </xref> represents the CCS load parameters with the selected 80 kW load.</p>
     <p>The study primarily focused on three key voltage levels: the supply voltage (V<sub>in</sub>), the tap voltage (V<sub>T</sub>), and the load voltage (V<sub>L</sub>). These voltage levels play a critical role in the operation and performance of the system under investigation.</p>
     <p>From the simulation results, the summarised results based on the main variable of focus, 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>, are expressed in <xref ref-type="fig" rid="fig10">
       Figure 10
      </xref>, <xref ref-type="fig" rid="fig11">
       Figure 11
      </xref> and <xref ref-type="fig" rid="fig12">
       Figure 12
      </xref>, where <xref ref-type="fig" rid="fig10">
       Figure 10
      </xref> and <xref ref-type="fig" rid="fig11">
       Figure 11
      </xref> present the supply, 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> and transformer secondary voltages, while <xref ref-type="fig" rid="fig12">
       Figure 12
      </xref> presents the numerical representation of the peak values for the supple and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>, respectively.</p>
     <fig id="fig5" position="float">
      <label>Figure 5</label>
      <caption>
       <title>Figure 5. Supply parameters.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId87.jpeg?20241216043844" />
     </fig>
     <fig id="fig6" position="float">
      <label>Figure 6</label>
      <caption>
       <title>Figure 6. Downstream parameters.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId88.jpeg?20241216043844" />
     </fig>
     <fig id="fig7" position="float">
      <label>Figure 7</label>
      <caption>
       <title>Figure 7. CCS V<sub>tap</sub> node.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId89.jpeg?20241216043844" />
     </fig>
     <fig id="fig8" position="float">
      <label>Figure 8</label>
      <caption>
       <title>Figure 8. Distribution secondary voltage.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId90.jpeg?20241216043845" />
     </fig>
     <fig id="fig9" position="float">
      <label>Figure 9</label>
      <caption>
       <title>Figure 9. CCS load parameters.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId91.jpeg?20241216043845" />
     </fig>
     <fig id="fig10" position="float">
      <label>Figure 10</label>
      <caption>
       <title>Figure 10. Supply, tapped and transformer secondary voltage.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId92.jpeg?20241216043844" />
     </fig>
     <fig id="fig11" position="float">
      <label>Figure 11</label>
      <caption>
       <title>Figure 11. Supply, tapped voltage and transformer secondary voltage.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId93.jpeg?20241216043844" />
     </fig>
     <fig id="fig12" position="float">
      <label>Figure 12</label>
      <caption>
       <title>Figure 12. MATLAB measured voltage.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId94.jpeg?20241216043844" />
     </fig>
     <p>The measured voltages, extrapolated from <xref ref-type="fig" rid="fig11">
       Figure 11
      </xref> and <xref ref-type="fig" rid="fig12">
       Figure 12
      </xref> are:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           s 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            i 
          </mi> 
          <mi>
            n 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          1.866 
        </mn> 
        <msup> 
         <mi>
           e 
         </mi> 
         <mrow> 
          <mo>
            + 
          </mo> 
          <mn>
            05 
          </mn> 
         </mrow> 
        </msup> 
        <mo>
          = 
        </mo> 
        <mn>
          1.866 
        </mn> 
        <mo>
          × 
        </mo> 
        <msup> 
         <mrow> 
          <mn>
            10 
          </mn> 
         </mrow> 
         <mn>
           5 
         </mn> 
        </msup> 
        <mo>
          = 
        </mo> 
        <mn>
          186.6 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kV 
        </mtext> 
       </mrow> 
      </math></p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           t 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            f 
          </mi> 
          <mo>
            , 
          </mo> 
          <mi>
            p 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            i 
          </mi> 
          <mi>
            m 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            r 
          </mi> 
          <mi>
            y 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          1.540 
        </mn> 
        <msup> 
         <mi>
           e 
         </mi> 
         <mrow> 
          <mo>
            + 
          </mo> 
          <mn>
            05 
          </mn> 
         </mrow> 
        </msup> 
        <mo>
          = 
        </mo> 
        <mn>
          1.540 
        </mn> 
        <mo>
          × 
        </mo> 
        <msup> 
         <mrow> 
          <mn>
            10 
          </mn> 
         </mrow> 
         <mn>
           4 
         </mn> 
        </msup> 
        <mo>
          = 
        </mo> 
        <mn>
          15.4 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kV 
        </mtext> 
       </mrow> 
      </math></p>
     <p>Since the MATLAB results waveform represents the peak value, the root mean square (RMS) is calculated as:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            s 
          </mi> 
          <mo>
            , 
          </mo> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
          <mi>
            s 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             V 
           </mi> 
           <mrow> 
            <mi>
              p 
            </mi> 
            <mi>
              e 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              k 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msqrt> 
           <mn>
             2 
           </mn> 
          </msqrt> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            186.6 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            kV 
          </mtext> 
         </mrow> 
         <mrow> 
          <msqrt> 
           <mn>
             2 
           </mn> 
          </msqrt> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mn>
          131.9 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kV 
        </mtext> 
       </mrow> 
      </math></p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mo>
            , 
          </mo> 
          <mi>
            r 
          </mi> 
          <mi>
            m 
          </mi> 
          <mi>
            s 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             V 
           </mi> 
           <mrow> 
            <mi>
              p 
            </mi> 
            <mi>
              e 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              k 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msqrt> 
           <mn>
             2 
           </mn> 
          </msqrt> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <mn>
            15.4 
          </mn> 
          <mtext>
              
          </mtext> 
          <mtext>
            kV 
          </mtext> 
         </mrow> 
         <mrow> 
          <msqrt> 
           <mn>
             2 
           </mn> 
          </msqrt> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mn>
          10.89 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kV 
        </mtext> 
       </mrow> 
      </math></p>
     <p>These results show that the selected C<sub>1</sub> and C<sub>2</sub> gives the desired 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>.</p>
     <p>In <xref ref-type="fig" rid="fig12">
       Figure 12
      </xref>, V<sub>line</sub> represents the incoming voltage from the voltage source supply, serving as the primary source of electrical energy. V<sub>t</sub>, or tap voltage, denotes the voltage level obtained after tapping from the transmission line, which is essential for regulating and delivering electrical power to the subsequent components of the CCS system. <xref ref-type="fig" rid="fig12">
       Figure 12
      </xref> is simplified as:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            L 
          </mi> 
          <mi>
            i 
          </mi> 
          <mi>
            n 
          </mi> 
          <mi>
            e 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          1.866 
        </mn> 
        <mo>
          × 
        </mo> 
        <mn>
          10 
        </mn> 
        <msup> 
         <mi>
           e 
         </mi> 
         <mn>
           5 
         </mn> 
        </msup> 
        <mo>
          = 
        </mo> 
        <mn>
          186 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kVpeak 
        </mtext> 
        <mo>
          = 
        </mo> 
        <mn>
          132 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kVrms 
        </mtext> 
       </mrow> 
      </math></p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mn>
          1.540 
        </mn> 
        <mo>
          × 
        </mo> 
        <mn>
          10 
        </mn> 
        <msup> 
         <mi>
           e 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
        <mo>
          = 
        </mo> 
        <mn>
          15.4 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kVpeak 
        </mtext> 
        <mo>
          = 
        </mo> 
        <mn>
          11 
        </mn> 
        <mtext>
            
        </mtext> 
        <mtext>
          kVrms 
        </mtext> 
       </mrow> 
      </math></p>
    </sec>
    <sec id="s4_3">
     <title>4.3. Results Repetition</title>
     <p>The calculated results can also be used as the basis for any CCS design. The 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> can be achieved by adjusting 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math> and 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> from any HV supply. A basic MATLAB Code that can be used is presented in <xref ref-type="table" rid="table4">
       Table 4
      </xref>.</p>
     <table-wrap id="table4">
      <label>
       <xref ref-type="table" rid="table4">
        Table 4
       </xref></label>
      <caption>
       <title>
        <xref ref-type="bibr" rid="scirp.138161-"></xref>Table 4. MATLAB code.</title>
      </caption>
     </table-wrap>
     <fig id="fig13" position="float">
      <label>Figure 13</label>
      <caption>
       <title>The results of the code in <xref ref-type="table" rid="table4">
         Table 4
        </xref> are presented in <xref ref-type="table" rid="table5">
         Table 5
        </xref>.The same code can be used when the supply voltage changes, as shown in the example result presented in <xref ref-type="table" rid="table6">
         Table 6
        </xref>, when the supply voltage is changed to 400 kV.Testing the code on the nominal HV levels used in South Africa <xref ref-type="bibr" rid="scirp.138161-20">
         [20]
        </xref>, the code can adjust 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    C
   
           </mi> 
   
           <mn>
            
    1
   
           </mn> 
  
          </msub> 
 
         </mrow>

        </math> and 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    C
   
           </mi> 
   
           <mn>
            
    2
   
           </mn> 
  
          </msub> 
 
         </mrow>

        </math> to achieve the desired tapped voltage as shown in <xref ref-type="table" rid="table7">
         Table 7
        </xref>.<xref ref-type="bibr" rid="scirp.138161-"></xref>Table 5. <xref ref-type="table" rid="table4">
         Table 4
        </xref> MATLAB code run results.
        <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
 
         <tr> 
  
          <td class="aleft" width="17.09%"><p style="text-align:left">Final C1: 0.218903 µF</p><p style="text-align:left">Final C2: 2.397979 µF</p><p style="text-align:left">Final tap voltage: 10841.13 V</p><p style="text-align:left">Iterations: 100</p></td> 
 
         </tr>

        </table><xref ref-type="bibr" rid="scirp.138161-"></xref>Table 6. <xref ref-type="table" rid="table4">
         Table 4
        </xref> MATLAB code run results when Vs is 400 kV rms.
        <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
 
         <tr> 
  
          <td class="aleft" width="17.09%"><p style="text-align:left">Final C1: 0.122561 µF</p><p style="text-align:left">Final C2: 4.282966 µF</p><p style="text-align:left">Final tap voltage: 10913.58 V</p><p style="text-align:left">Iterations: 100</p></td> 
 
         </tr>

        </table><xref ref-type="bibr" rid="scirp.138161-"></xref>Table 7. Achieved 

        <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    V
   
           </mi> 
   
           <mrow> 
    
            <mi>
             
     t
    
            </mi>
    
            <mi>
             
     a
    
            </mi>
    
            <mi>
             
     p
    
            </mi>
   
           </mrow> 
  
          </msub> 
 
         </mrow>

        </math> from different 

        <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    V
   
           </mi> 
   
           <mi>
            
    s
   
           </mi> 
  
          </msub> 
 
         </mrow>

        </math>.
        <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
 
         <tr> 
  
          <td class="custom-bottom-td acenter" width="17.09%"><p style="text-align:center">HV Level</p></td> 
  
          <td class="custom-bottom-td acenter" width="17.09%"><p style="text-align:center">88 kV</p></td> 
  
          <td class="custom-bottom-td acenter" width="17.09%"><p style="text-align:center">132 kV</p></td> 
  
          <td class="custom-bottom-td acenter" width="17.09%"><p style="text-align:center">275 kV</p></td> 
  
          <td class="custom-bottom-td acenter" width="17.09%"><p style="text-align:center">400 kV</p></td> 
  
          <td class="custom-bottom-td acenter" width="17.09%"><p style="text-align:center">765 kV</p></td> 
 
         </tr> 
 
         <tr> 
  
          <td class="custom-top-td acenter" width="17.09%"><p style="text-align:center">
    
            <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
              <msub> 
               <mi>
                 C 
               </mi> 
               <mn>
                 1 
               </mn> 
              </msub> 
             </mrow>
    
            </math></p></td> 
  
          <td class="custom-top-td acenter" width="17.09%"><p style="text-align:center">0.273 µF</p></td> 
  
          <td class="custom-top-td acenter" width="17.09%"><p style="text-align:center">0.219 µF</p></td> 
  
          <td class="custom-top-td acenter" width="17.09%"><p style="text-align:center">0.147 µF</p></td> 
  
          <td class="custom-top-td acenter" width="17.09%"><p style="text-align:center">0.123 µF</p></td> 
  
          <td class="custom-top-td acenter" width="17.09%"><p style="text-align:center">0.087 µF</p></td> 
 
         </tr> 
 
         <tr> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">
    
            <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
              <msub> 
               <mi>
                 C 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msub> 
             </mrow>
    
            </math></p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">1.924 µF</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">2.398 µF</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">3.577 µF</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">4.283 µF</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">6.017 µF</p></td> 
 
         </tr> 
 
         <tr> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">
    
            <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
              <msub> 
               <mi>
                 V 
               </mi> 
               <mrow> 
                <mi>
                  t 
                </mi> 
                <mi>
                  a 
                </mi> 
                <mi>
                  p 
                </mi> 
               </mrow> 
              </msub> 
             </mrow>
    
            </math></p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">11.1 kV</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">10.8 kV</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">11.0 kV</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">10.9 kV</p></td> 
  
          <td class="acenter" width="17.09%"><p style="text-align:center">11.2 kV</p></td> 
 
         </tr>

        </table><xref ref-type="bibr" rid="scirp.138161-"></xref><xref ref-type="table" rid="table7">
         Table 7
        </xref> presents the resulting 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    V
   
           </mi> 
   
           <mrow> 
    
            <mi>
             
     t
    
            </mi>
    
            <mi>
             
     a
    
            </mi>
    
            <mi>
             
     p
    
            </mi>
   
           </mrow> 
  
          </msub> 
 
         </mrow>

        </math> tapped from different values of 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    V
   
           </mi> 
   
           <mi>
            
    s
   
           </mi> 
  
          </msub> 
 
         </mrow>

        </math> with 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    C
   
           </mi> 
   
           <mn>
            
    1
   
           </mn> 
  
          </msub> 
 
         </mrow>

        </math> and 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    C
   
           </mi> 
   
           <mn>
            
    2
   
           </mn> 
  
          </msub> 
 
         </mrow>

        </math> that gives that resulting 

        <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
          <msub> 
   
           <mi>
            
    V
   
           </mi> 
   
           <mrow> 
    
            <mi>
             
     t
    
            </mi>
    
            <mi>
             
     a
    
            </mi>
    
            <mi>
             
     p
    
            </mi>
   
           </mrow> 
  
          </msub> 
 
         </mrow>

        </math>.</title>
      </caption>
      <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2860311-rId115.jpeg?20241216043845" />
     </fig>
     <p>The tapped voltage ( 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>) can be influenced by the load <xref ref-type="bibr" rid="scirp.138161-21">
       [21]
      </xref>. 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> on a steady-state circuit is derived by Equation (1). However, when the load connected changes, it affects the impedance seen by the capacitors, thus altering the 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>. The load introduces an additional impedance parallel with 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> and can be represented by 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           Z 
         </mi> 
         <mrow> 
          <mi>
            C 
          </mi> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>. If 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           Z 
         </mi> 
         <mi>
           L 
         </mi> 
        </msub> 
       </mrow> 
      </math> is the impedance of the load, then the effective impedance across 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math> and the load is given by:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           Z 
         </mi> 
         <mrow> 
          <mi>
            e 
          </mi> 
          <mi>
            f 
          </mi> 
          <mi>
            f 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mn>
               1 
             </mn> 
             <mrow> 
              <msub> 
               <mi>
                 Z 
               </mi> 
               <mrow> 
                <mi>
                  C 
                </mi> 
                <mn>
                  2 
                </mn> 
               </mrow> 
              </msub> 
             </mrow> 
            </mfrac> 
            <mo>
              + 
            </mo> 
            <mfrac> 
             <mn>
               1 
             </mn> 
             <mrow> 
              <msub> 
               <mi>
                 Z 
               </mi> 
               <mi>
                 L 
               </mi> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mo>
            − 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </msup> 
       </mrow> 
      </math></p>
     <p>where: 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           Z 
         </mi> 
         <mrow> 
          <mi>
            C 
          </mi> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mi>
            j 
          </mi> 
          <mi>
            ω 
          </mi> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <mi>
            j 
          </mi> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
          <mtext>
              
          </mtext> 
          <mi>
            f 
          </mi> 
          <mtext>
              
          </mtext> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math></p>
     <p>The 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> under varying load is thus derived from:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           S 
         </mi> 
        </msub> 
        <mo>
          × 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             Z 
           </mi> 
           <mrow> 
            <mi>
              e 
            </mi> 
            <mi>
              f 
            </mi> 
            <mi>
              f 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mrow> 
          <msub> 
           <mi>
             Z 
           </mi> 
           <mrow> 
            <mi>
              e 
            </mi> 
            <mi>
              f 
            </mi> 
            <mi>
              f 
            </mi> 
           </mrow> 
          </msub> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             Z 
           </mi> 
           <mrow> 
            <mi>
              C 
            </mi> 
            <mn>
              1 
            </mn> 
           </mrow> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mo>
          → 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mi>
           S 
         </mi> 
        </msub> 
        <mo>
          × 
        </mo> 
        <mfrac> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mrow> 
            <mi>
              j 
            </mi> 
            <mi>
              ω 
            </mi> 
            <msub> 
             <mi>
               C 
             </mi> 
             <mn>
               2 
             </mn> 
            </msub> 
           </mrow> 
          </mfrac> 
          <mo>
            × 
          </mo> 
          <msub> 
           <mi>
             Z 
           </mi> 
           <mi>
             L 
           </mi> 
          </msub> 
         </mrow> 
         <mrow> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mrow> 
            <mi>
              j 
            </mi> 
            <mi>
              ω 
            </mi> 
            <msub> 
             <mi>
               C 
             </mi> 
             <mn>
               2 
             </mn> 
            </msub> 
           </mrow> 
          </mfrac> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             Z 
           </mi> 
           <mi>
             L 
           </mi> 
          </msub> 
          <mo>
            + 
          </mo> 
          <mfrac> 
           <mn>
             1 
           </mn> 
           <mrow> 
            <mi>
              j 
            </mi> 
            <mi>
              ω 
            </mi> 
            <msub> 
             <mi>
               C 
             </mi> 
             <mn>
               1 
             </mn> 
            </msub> 
           </mrow> 
          </mfrac> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </math></p>
     <p>In order to maintain the desired value of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>:</p>
     <p>Using the data from <xref ref-type="table" rid="table4">
       Table 4
      </xref>, a state-space representation for maintaining the desired tapped voltage ( 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>) on a CCS under dynamic loads can be modelled as follows, using state variables:</p>
     <p>The state-space equations is therefore defined using Kirchhoff’s Current Law (KCL) at the 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
       </mrow> 
      </math>, with 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           s 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>, being the current from the source, as:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mfrac> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <msub> 
           <mi>
             V 
           </mi> 
           <mrow> 
            <mi>
              C 
            </mi> 
            <mn>
              1 
            </mn> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           s 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           L 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>Using Kirchhoff’s Voltage Law (KVL) across L, gives:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          L 
        </mi> 
        <mfrac> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <msub> 
           <mi>
             I 
           </mi> 
           <mi>
             L 
           </mi> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            C 
          </mi> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            C 
          </mi> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>While using KCL at 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </math>, where 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mrow> 
          <mi>
            l 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            d 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math> is the current drawn by the dynamic load connected to the system, gives:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mfrac> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <msub> 
           <mi>
             V 
           </mi> 
           <mrow> 
            <mi>
              C 
            </mi> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mtext>
            d 
          </mtext> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           L 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mrow> 
          <mi>
            l 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            d 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>The state-space equations are thus given as:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mover accent="true"> 
          <mi>
            x 
          </mi> 
          <mo>
            ˙ 
          </mo> 
         </mover> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             I 
           </mi> 
           <mi>
             s 
           </mi> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             x 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mover accent="true"> 
          <mi>
            x 
          </mi> 
          <mo>
            ˙ 
          </mo> 
         </mover> 
         <mn>
           2 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mi>
           L 
         </mi> 
        </mfrac> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             x 
           </mi> 
           <mn>
             1 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             x 
           </mi> 
           <mn>
             3 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mover accent="true"> 
          <mi>
            x 
          </mi> 
          <mo>
            ˙ 
          </mo> 
         </mover> 
         <mn>
           3 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mrow> 
          <msub> 
           <mi>
             C 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
         </mrow> 
        </mfrac> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             x 
           </mi> 
           <mn>
             2 
           </mn> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            − 
          </mo> 
          <msub> 
           <mi>
             I 
           </mi> 
           <mrow> 
            <mi>
              l 
            </mi> 
            <mi>
              o 
            </mi> 
            <mi>
              a 
            </mi> 
            <mi>
              d 
            </mi> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             t 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>The matrix representation is thus:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mover accent="true"> 
                <mi>
                  x 
                </mi> 
                <mo>
                  ˙ 
                </mo> 
               </mover> 
               <mn>
                 1 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mover accent="true"> 
                <mi>
                  x 
                </mi> 
                <mo>
                  ˙ 
                </mo> 
               </mover> 
               <mn>
                 2 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mover accent="true"> 
                <mi>
                  x 
                </mi> 
                <mo>
                  ˙ 
                </mo> 
               </mover> 
               <mn>
                 3 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mrow> 
              <mo>
                − 
              </mo> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   1 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mi>
                 L 
               </mi> 
              </mfrac> 
             </mrow> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mrow> 
              <mo>
                − 
              </mo> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mi>
                 L 
               </mi> 
              </mfrac> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mrow> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 x 
               </mi> 
               <mn>
                 1 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 x 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 x 
               </mi> 
               <mn>
                 3 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mrow> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   1 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           s 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <mo>
                − 
              </mo> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mrow> 
          <mi>
            l 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            d 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>The output equation, which relates the state variables to 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           x 
         </mi> 
         <mn>
           3 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>, is:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          y 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mn>
               1 
             </mn> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 x 
               </mi> 
               <mn>
                 1 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 x 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <msub> 
               <mi>
                 x 
               </mi> 
               <mn>
                 3 
               </mn> 
              </msub> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mi>
                 t 
               </mi> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>In order to maintain the desired 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>, control input 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          u 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math> is introduced as part of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           s 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>, making 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mi>
           s 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math> a function of 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          u 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>. The input vector B and control law can be modified accordingly to achieve the desired 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math>. The state-space model to use when designing control strategies to maintain the desired 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           V 
         </mi> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            p 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
      </math> under varying load conditions is given by:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mover accent="true"> 
          <mi>
            x 
          </mi> 
          <mo>
            ˙ 
          </mo> 
         </mover> 
         <mn>
           1 
         </mn> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           A 
         </mi> 
         <mi>
           x 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <msub> 
         <mi>
           B 
         </mi> 
         <mi>
           u 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          + 
        </mo> 
        <msub> 
         <mi>
           B 
         </mi> 
         <mrow> 
          <mi>
            l 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            d 
          </mi> 
         </mrow> 
        </msub> 
        <msub> 
         <mi>
           I 
         </mi> 
         <mrow> 
          <mi>
            l 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            d 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          y 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          = 
        </mo> 
        <msub> 
         <mi>
           C 
         </mi> 
         <mi>
           x 
         </mi> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mi>
           t 
         </mi> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math></p>
     <p>where:</p>
     <p>
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          A 
        </mi> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mrow> 
              <mo>
                − 
              </mo> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   1 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mi>
                 L 
               </mi> 
              </mfrac> 
             </mrow> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mrow> 
              <mo>
                − 
              </mo> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mi>
                 L 
               </mi> 
              </mfrac> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mrow> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>, 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          B 
        </mi> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mrow> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>, 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <msub> 
         <mi>
           B 
         </mi> 
         <mrow> 
          <mi>
            l 
          </mi> 
          <mi>
            o 
          </mi> 
          <mi>
            a 
          </mi> 
          <mi>
            d 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
           </mtr> 
           <mtr> 
            <mtd> 
             <mrow> 
              <mo>
                − 
              </mo> 
              <mfrac> 
               <mn>
                 1 
               </mn> 
               <mrow> 
                <msub> 
                 <mi>
                   C 
                 </mi> 
                 <mn>
                   2 
                 </mn> 
                </msub> 
               </mrow> 
              </mfrac> 
             </mrow> 
            </mtd> 
           </mtr> 
          </mtable> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </math>, 
      <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
        <mi>
          C 
        </mi> 
        <mo>
          = 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mtable> 
           <mtr> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
             <mn>
               0 
             </mn> 
            </mtd> 
            <mtd> 
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    </sec>
   </sec>
   <sec id="s5">
    <title>5. Conclusions</title>
    <p>This study explored the feasibility and performance of an 80 kW Capacitor Coupled Substation (CCS) system tapped from a 132 kV transmission line, with the goal of providing an alternative solution for rural electrification. By integrating the CCS directly into the high-voltage network and tapping power for low-voltage consumers, the model successfully demonstrated that stable tap voltages could be achieved under varying supply conditions. The research highlights the potential of CCS technology to serve as a scalable alternative to traditional distribution networks, especially in sparsely populated regions where conventional electrification methods are economically unviable.</p>
    <p>The simulation results revealed that the proposed CCS system could maintain the desired tap voltage even under different load conditions, provided appropriate adjustments were made to the capacitor banks. The MATLAB/Simulink model, validated through extensive calculations, confirmed that the CCS design could reliably deliver electricity to low-voltage consumers. This approach not only fills a critical gap in rural electrification research but also opens avenues for further development and practical implementation of CCS systems in remote areas.</p>
    <p>The study contributes valuable insights into the practical application of CCS technology for rural electrification, offering a promising solution to address the challenges of delivering reliable electricity to underserved communities. Future research could build upon these findings by exploring the long-term stability, economic viability, and potential integration of renewable energy sources within the CCS framework.</p>
   </sec>
   <sec id="s6">
    <title>Recommendations</title>
    <p>The following is the recommendation for future research:</p>
    <p>Further analysis of a CCS in a dynamic state is to be conducted in order to identify operability of a CCS in a real-world environment.</p>
   </sec>
  </sec>
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