<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    wjcmp
   </journal-id>
   <journal-title-group>
    <journal-title>
     World Journal of Condensed Matter Physics
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2160-6919
   </issn>
   <issn publication-format="print">
    2160-6927
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/wjcmp.2024.144009
   </article-id>
   <article-id pub-id-type="publisher-id">
    wjcmp-137780
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    On the Role of Chemical Potential in Determining the Temperature Dependent Critical Magnetic Field and the Penetration Depth of Superconductors
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Gulshan Prakash
      </surname>
      <given-names>
       Malik
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref> 
     <xref ref-type="aff" rid="aff2"> 
      <sup>2</sup>
     </xref>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Vijaya Shankar
      </surname>
      <given-names>
       Varma
      </given-names>
     </name> 
     <xref ref-type="aff" rid="aff1"> 
      <sup>1</sup>
     </xref> 
     <xref ref-type="aff" rid="aff3"> 
      <sup>3</sup>
     </xref>
    </contrib>
   </contrib-group> 
   <aff id="aff1">
    <addr-line>
     aGurugram, India
    </addr-line> 
   </aff> 
   <aff id="aff2">
    <addr-line>
     aTheory Group, School of Environmental Sciences, Jawaharlal Nehru University, New Delhi, India
    </addr-line> 
   </aff> 
   <aff id="aff3">
    <addr-line>
     aDepartment of Physics and Astrophysics, University of Delhi, Delhi, India
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     04
    </day> 
    <month>
     11
    </month>
    <year>
     2024
    </year>
   </pub-date> 
   <volume>
    14
   </volume> 
   <issue>
    04
   </issue>
   <fpage>
    96
   </fpage>
   <lpage>
    106
   </lpage>
   <history>
    <date date-type="received">
     <day>
      7,
     </day>
     <month>
      October
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      25,
     </day>
     <month>
      October
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      25,
     </day>
     <month>
      November
     </month>
     <year>
      2024
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    Dealing with both elemental and high-T
    <sub>c</sub> superconductors (SCs) - Sn, Nb and Pb belonging to the former category, and MgB
    <sub>2</sub> and different samples of YBCO to the latter - we show that the difference in the values of their critical magnetic field H
    <sub>c</sub>
    <sub>1,</sub>
    <sub>c</sub>
    <sub>2</sub> and the penetration depth λ
    <sub>L</sub>(0) is, remarkably, attributable predominantly to the difference in the values of a single parameter, viz., the chemical potential (μ) close to their critical temperatures (T
    <sub>c</sub>s). Based directly on the dynamics of pairing in a magnetic field and the corresponding number equation, our approach relates H
    <sub>c</sub>
    <sub>1,</sub>
    <sub>c</sub>
    <sub>2</sub> of an SC with the following set of its properties: S
    <sub>1</sub> = {μ, T
    <sub>c</sub>, Debye temperature, effective mass of the electron, magnetic interaction parameter, Landau index}. Hence, it provides an alternative to the approach followed by Talantsev [Mod. Phys. Lett. B 
    <b>33</b>, 1950195 (2019)] who has shown by ingeniously combining the results of various well-established theories that H
    <sub>c</sub>
    <sub>2</sub> of an SC can be calculated via four different equations, each of which invokes two or more properties from its sample-specific set S
    <sub>2</sub> = {T
    <sub>c</sub>, gap, coherence length, λ
    <sub>L</sub>(0), jump in sp. ht.}, which is radically different from S
    <sub>1</sub>.
   </abstract>
   <kwd-group> 
    <kwd>
     Pairing and Number Equations Incorporating Temperature
    </kwd> 
    <kwd>
      Chemical Potential and Magnetic Field
    </kwd> 
    <kwd>
      Critical Magnetic Field
    </kwd> 
    <kwd>
      Penetration Depth
    </kwd> 
    <kwd>
      Sn
    </kwd> 
    <kwd>
      Nb
    </kwd> 
    <kwd>
      Pb
    </kwd> 
    <kwd>
      MgB
     <sub>2</sub>
    </kwd> 
    <kwd>
      YBCO
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>It is well known that the properties of a superconductor (SC) differ not only from one SC to another, but also from sample to sample of the same SC - depending on the sample geometry, size, nature of doping, manner of preparation, etc. Thus, for example, two samples of YBa<sub>2</sub>Cu<sub>3</sub>O<sub>7</sub> have been found to have the values of their critical temperature (T<sub>c</sub>) and the upper critical magnetic field 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         H 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mn>
          2 
        </mn> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> at temperature T = 0 when the applied field H is along the c-direction as given below <xref ref-type="bibr" rid="scirp.137780-1">
     <a href="#ref1">[1]</a>
    </xref>.</p>
   <p>
    <xref ref-type="bibr" rid="scirp.137780-"></xref>YBa<sub>2</sub>Cu<sub>3</sub>O<sub>6.5</sub>: T<sub>c</sub> = 62 K, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         H 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mn>
          2 
        </mn> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        87 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mtext>
          10 
        </mtext> 
       </mrow> 
       <mn>
         4 
       </mn> 
      </msup> 
      <mtext>
          
      </mtext> 
      <mtext>
        G 
      </mtext> 
     </mrow> 
    </math></p>
   <p>YBa<sub>2</sub>Cu<sub>3</sub>O<sub>7-</sub><sub>δ</sub> (with δ ≈ near-optimal value of doping): T<sub>c</sub> = 92.4 K,</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         H 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mn>
          2 
        </mn> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        34 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mtext>
          10 
        </mtext> 
       </mrow> 
       <mn>
         4 
       </mn> 
      </msup> 
      <mtext>
          
      </mtext> 
      <mtext>
        G 
      </mtext> 
     </mrow> 
    </math> (1)</p>
   <p>Pertaining to a different pair of samples (with unspecified values of δ) of the same SC and direction of the applied field, the values of T<sub>c</sub> and the London penetration depth 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         λ 
       </mi> 
       <mi>
         L 
       </mi> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mi>
          b 
        </mi> 
       </mrow> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> below provide another example <xref ref-type="bibr" rid="scirp.137780-1">
     [1]
    </xref>.</p>
   <p>Sample 1: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        66 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        K 
      </mtext> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         λ 
       </mi> 
       <mi>
         L 
       </mi> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mi>
          b 
        </mi> 
       </mrow> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        260 
      </mn> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math></p>
   <p>Sample 2: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         T 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        92 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        K 
      </mtext> 
     </mrow> 
    </math>, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         λ 
       </mi> 
       <mi>
         L 
       </mi> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mi>
          b 
        </mi> 
       </mrow> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        89 
      </mn> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (2)</p>
   <p>Employing the examples of both elemental SCs (Sn, Nb and Pb) and high-T<sub>c</sub> SCs (MgB<sub>2</sub> and two samples of YBCO), it is the purpose of this paper to show that the difference in the above-noted properties of these SCs can be understood predominantly on the basis of the difference in the values of a single parameter that characterizes them. This parameter, remarkably, is μ<sub>1</sub>, i.e., the value of the chemical potential μ at t<sub>1</sub> ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mo>
       ≡ 
     </mo> 
    </math>T<sub>1</sub>/T<sub>c</sub>) close to 1 (say, 0.9) and hence amenable to experimental verification. The ramifications/implications of this result will be discussed. Before we do so, however, we give below a brief account of some of the earlier approaches to calculating H<sub>c</sub><sub>2</sub> of an SC in order to highlight the difference between them and the approach followed in this paper.</p>
   <p>The most widely employed approach for the calculation of H<sub>c</sub><sub>2</sub> (B<sub>c</sub><sub>2</sub> in the SI system of units) is due to Werthamer, Helfand and Hohenberg (WHH) <xref ref-type="bibr" rid="scirp.137780-2">
     [2]
    </xref>, which is based on the electron spin and spin-orbit effects. The WHH equation is</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ln 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mi>
           T 
         </mi> 
         <mrow> 
          <msub> 
           <mi>
             T 
           </mi> 
           <mi>
             c 
           </mi> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              B 
            </mi> 
            <mo>
              = 
            </mo> 
            <mn>
              0 
            </mn> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        ψ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mn>
           2 
         </mn> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        − 
      </mo> 
      <mi>
        ψ 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mn>
           1 
         </mn> 
         <mn>
           2 
         </mn> 
        </mfrac> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mrow> 
          <mi>
            ℏ 
          </mi> 
          <mi>
            D 
          </mi> 
          <msub> 
           <mi>
             B 
           </mi> 
           <mrow> 
            <mi>
              c 
            </mi> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mi>
             T 
           </mi> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <msub> 
           <mi>
             ϕ 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mi>
            k 
          </mi> 
          <mi>
            T 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
     </mrow> 
    </math></p>
   <p>where ψ is the Euler’s digamma function, D the diffusion constant for the normal electrons/holes in the conduction band, 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ϕ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        2.07 
      </mn> 
      <mo>
        × 
      </mo> 
      <mn>
        1 
      </mn> 
      <msup> 
       <mn>
         0 
       </mn> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          15 
        </mn> 
       </mrow> 
      </msup> 
      <mtext>
          
      </mtext> 
      <mtext>
        Wb 
      </mtext> 
     </mrow> 
    </math> the flux quantum and k the Boltzmann constant. An older equation for B<sub>c2</sub> in the classical two-fluid Gorter-Casimir model <xref ref-type="bibr" rid="scirp.137780-3">
     [3]
    </xref> is</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         B 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mn>
          2 
        </mn> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           ϕ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          π 
        </mi> 
        <msubsup> 
         <mi>
           ξ 
         </mi> 
         <mn>
           0 
         </mn> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
     </mrow> 
    </math></p>
   <p>where ξ<sub>0</sub> is the coherence length at t = 0. A variant of the above equation is the Jones-Hulm-Chandrasekhar model <xref ref-type="bibr" rid="scirp.137780-4">
     [4]
    </xref></p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         B 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mn>
          2 
        </mn> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           ϕ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mi>
          π 
        </mi> 
        <msubsup> 
         <mi>
           ξ 
         </mi> 
         <mn>
           0 
         </mn> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          − 
        </mo> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          1 
        </mn> 
        <mo>
          + 
        </mo> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        . 
      </mo> 
     </mrow> 
    </math></p>
   <p>Finally, the following equation for B<sub>c</sub><sub>2</sub> given by Gor’kov <xref ref-type="bibr" rid="scirp.137780-5">
     [5]
    </xref> is also said to provide a good fit to the data over the entire range of temperature</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         B 
       </mi> 
       <mrow> 
        <mi>
          c 
        </mi> 
        <mn>
          2 
        </mn> 
       </mrow> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         B 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mfrac> 
       <mrow> 
        <msqrt> 
         <mn>
           2 
         </mn> 
        </msqrt> 
       </mrow> 
       <mrow> 
        <mn>
          1.77 
        </mn> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           λ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           ξ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          1.77 
        </mn> 
        <mo>
          − 
        </mo> 
        <mn>
          0.53 
        </mn> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          + 
        </mo> 
        <mn>
          0.07 
        </mn> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           4 
         </mn> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
     </mrow> 
    </math></p>
   <p>where 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         B 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> is the thermodynamic critical field.</p>
   <p>It is interesting to note that combining each of the models noted above with a mix of the other properties of the SC, e.g., its gap Δ and the jump in the specific heat, Talantsev <xref ref-type="bibr" rid="scirp.137780-6">
     [6]
    </xref> has recently derived four new equations for B<sub>c</sub><sub>2</sub> each of which leads to nearly as good a fit to the empirical data of compressed H<sub>3</sub>S as the other. It is notable that all of these approaches including that of Talantsev determine B<sub>c</sub><sub>2</sub> indirectly via the effects it has on one or more properties of the SC such as ξ<sub>0</sub> and λ<sub>0</sub>. In contrast with these, the approach followed in this paper determines H<sub>c</sub><sub>2</sub> directly via the dynamics of pairing, i.e., by employing an H<sub>c</sub><sub>2</sub>-dependent pairing equation (PE) together with the corresponding number equation (NE). Below, we will return to a further discussion of Talantsev’s work and draw attention to how our approach complements his approach.</p>
   <p>The PE and the NE on which the present study is based are given in the next section. Both of these equations are μ-, T- and H-dependent. These are supplemented by the equation for λ<sub>L</sub>(0). Procedural details of the application of these equations to both elemental and high-T<sub>c</sub> SCs are given in Section 3. The final section sums up our findings.</p>
  </sec><sec id="s2">
   <title>2. The Core Equations</title>
   <sec id="s2_1">
    <title>2.1. The μ-, T- and H-Dependent Pairing Equation (PE)</title>
    <p>The PE is obtained via a 4-d Bethe-Salpeter equation (BSE) the 4<sup>th</sup> dimension of which is employed to temperature-generalize it via the Matsubara prescription. Subjecting the resulting 3-d equation to the Landau quantization scheme further generalizes it to include an applied magnetic field leading to the quantization of the transverse components of momentum into Landau levels. Finally, the PE employed here is obtained from this 1-d equation by putting the binding energy/gap Δ = 0, whence it gives the value of the critical magnetic field H<sub>c</sub> at any T or, equivalently, T<sub>c</sub> corresponding to any H. Derived in <xref ref-type="bibr" rid="scirp.137780-7">
      [7]
     </xref> and subjected to a correction <xref ref-type="bibr" rid="scirp.137780-8">
      [8]
     </xref>, this equation is reproduced below from the latter reference where it was shown to provide the basis of a new microscopic approach for dealing with the T- and H-dependent critical current densities of SCs.</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1 
       </mn> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          m 
        </mi> 
       </msub> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <munderover> 
          <mo>
            ∫ 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              L 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               .. 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mrow> 
           <msub> 
            <mi>
              L 
            </mi> 
            <mn>
              2 
            </mn> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mn>
               .. 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </munderover> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mtext>
              d 
            </mtext> 
            <mi>
              ξ 
            </mi> 
           </mrow> 
           <mrow> 
            <msqrt> 
             <mrow> 
              <mn>
                1 
              </mn> 
              <mo>
                + 
              </mo> 
              <mrow> 
               <mi>
                 ξ 
               </mi> 
               <mo>
                 / 
               </mo> 
               <mi>
                 μ 
               </mi> 
              </mrow> 
             </mrow> 
            </msqrt> 
           </mrow> 
          </mfrac> 
          <mstyle displaystyle="true"> 
           <munderover> 
            <mo>
              ∑ 
            </mo> 
            <mrow> 
             <mi>
               n 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               0 
             </mn> 
            </mrow> 
            <mrow> 
             <msub> 
              <mi>
                N 
              </mi> 
              <mrow> 
               <mi>
                 L 
               </mi> 
               <mn>
                 1 
               </mn> 
              </mrow> 
             </msub> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mn>
                 .. 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </munderover> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <mi>
                tanh 
              </mi> 
              <mrow> 
               <mo>
                 [ 
               </mo> 
               <mrow> 
                <mfrac> 
                 <mi>
                   ξ 
                 </mi> 
                 <mrow> 
                  <mn>
                    2 
                  </mn> 
                  <mi>
                    k 
                  </mi> 
                  <mi>
                    T 
                  </mi> 
                 </mrow> 
                </mfrac> 
                <mo>
                  + 
                </mo> 
                <mfrac> 
                 <mrow> 
                  <mi>
                    ℏ 
                  </mi> 
                  <mi>
                    Ω 
                  </mi> 
                  <mrow> 
                   <mo>
                     ( 
                   </mo> 
                   <mrow> 
                    <msub> 
                     <mi>
                       H 
                     </mi> 
                     <mi>
                       c 
                     </mi> 
                    </msub> 
                   </mrow> 
                   <mo>
                     ) 
                   </mo> 
                  </mrow> 
                 </mrow> 
                 <mrow> 
                  <mn>
                    2 
                  </mn> 
                  <mi>
                    k 
                  </mi> 
                  <mi>
                    T 
                  </mi> 
                 </mrow> 
                </mfrac> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    n 
                  </mi> 
                  <mo>
                    + 
                  </mo> 
                  <mrow> 
                   <mn>
                     1 
                   </mn> 
                   <mo>
                     / 
                   </mo> 
                   <mn>
                     2 
                   </mn> 
                  </mrow> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
               </mrow> 
               <mo>
                 ] 
               </mo> 
              </mrow> 
             </mrow> 
             <mrow> 
              <mi>
                ξ 
              </mi> 
              <mo>
                + 
              </mo> 
              <mi>
                ℏ 
              </mi> 
              <mi>
                Ω 
              </mi> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <msub> 
                 <mi>
                   H 
                 </mi> 
                 <mi>
                   c 
                 </mi> 
                </msub> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
              <mrow> 
               <mo>
                 ( 
               </mo> 
               <mrow> 
                <mi>
                  n 
                </mi> 
                <mo>
                  + 
                </mo> 
                <mrow> 
                 <mn>
                   1 
                 </mn> 
                 <mo>
                   / 
                 </mo> 
                 <mn>
                   2 
                 </mn> 
                </mrow> 
               </mrow> 
               <mo>
                 ) 
               </mo> 
              </mrow> 
             </mrow> 
            </mfrac> 
           </mrow> 
          </mstyle> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         , 
       </mo> 
      </mrow> 
     </math> (3)</p>
    <p>where</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mi>
            m 
          </mi> 
         </msub> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mrow> 
           <mi>
             e 
           </mi> 
           <msub> 
            <mi>
              H 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
           <mi>
             V 
           </mi> 
          </mrow> 
          <mrow> 
           <mn>
             16 
           </mn> 
           <msup> 
            <mi>
              π 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </mfrac> 
         <msqrt> 
          <mrow> 
           <mfrac> 
            <mrow> 
             <mn>
               2 
             </mn> 
             <mi>
               η 
             </mi> 
             <msub> 
              <mi>
                m 
              </mi> 
              <mi>
                e 
              </mi> 
             </msub> 
            </mrow> 
            <mi>
              μ 
            </mi> 
           </mfrac> 
          </mrow> 
         </msqrt> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <mi>
           μ 
         </mi> 
         <mo>
           = 
         </mo> 
         <mi>
           ρ 
         </mi> 
         <mi>
           k 
         </mi> 
         <mi>
           θ 
         </mi> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <msub> 
          <mi>
            L 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mi>
             k 
           </mi> 
           <mi>
             θ 
           </mi> 
          </mrow> 
          <mn>
            3 
          </mn> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             ρ 
           </mi> 
           <mo>
             + 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <msub> 
          <mi>
            L 
          </mi> 
          <mn>
            2 
          </mn> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mrow> 
           <mi>
             k 
           </mi> 
           <mi>
             θ 
           </mi> 
          </mrow> 
          <mn>
            3 
          </mn> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             2 
           </mn> 
           <mi>
             ρ 
           </mi> 
           <mo>
             + 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            N 
          </mi> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mi>
           f 
         </mi> 
         <mi>
           l 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           r 
         </mi> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mfrac> 
            <mn>
              2 
            </mn> 
            <mn>
              3 
            </mn> 
           </mfrac> 
           <mfrac> 
            <mrow> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mi>
                 ρ 
               </mi> 
               <mo>
                 + 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mi>
               k 
             </mi> 
             <mi>
               θ 
             </mi> 
            </mrow> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               Ω 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <msub> 
                <mi>
                  H 
                </mi> 
                <mi>
                  c 
                </mi> 
               </msub> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </mfrac> 
           <mo>
             − 
           </mo> 
           <mfrac> 
            <mn>
              1 
            </mn> 
            <mn>
              2 
            </mn> 
           </mfrac> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <mi>
           Ω 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              H 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mrow> 
          <mrow> 
           <msub> 
            <mi>
              Ω 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <msub> 
            <mi>
              H 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            / 
          </mo> 
          <mi>
            η 
          </mi> 
         </mrow> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <msub> 
          <mi>
            Ω 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           = 
         </mo> 
         <mn>
           1.7588 
         </mn> 
         <msup> 
          <mtext>
            s 
          </mtext> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mtext>
            G 
          </mtext> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msup> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math></p>
    <p>The parameter λ<sub>m</sub> is the magnetic interaction parameter corresponding to temperature T, applied field H and the chemical potential μ which has been parametrized in terms of the Debye temperature of the SC as ρkθ, where k is the Boltzmann constant and ρ a free parameter; - V (V &gt; 0) is the usual BCS model interaction due to the ion-lattice and Coulomb repulsion between electrons and finally, m<sub>e</sub> is the mass of an electron and η its enhancement factor.</p>
   </sec>
   <sec id="s2_2">
    <title>2.2. The μ-, T- and H-Dependent Number Equation (NE)</title>
    <p>Also reproduced from <xref ref-type="bibr" rid="scirp.137780-8">
      [8]
     </xref>, the NE is:</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mi>
          s 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mn>
           ... 
         </mn> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          C 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
       <msup> 
        <mrow> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mi>
             h 
           </mi> 
           <msub> 
            <mi>
              H 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mn>
            3 
          </mn> 
          <mo>
            / 
          </mo> 
          <mn>
            2 
          </mn> 
         </mrow> 
        </mrow> 
       </msup> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <munderover> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mrow> 
           <msqrt> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mn>
                 .. 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </msqrt> 
          </mrow> 
         </munderover> 
         <mrow> 
          <mstyle displaystyle="true"> 
           <munderover> 
            <mo>
              ∑ 
            </mo> 
            <mrow> 
             <mi>
               n 
             </mi> 
             <mo>
               = 
             </mo> 
             <mn>
               0 
             </mn> 
            </mrow> 
            <mrow> 
             <msub> 
              <mi>
                N 
              </mi> 
              <mn>
                2 
              </mn> 
             </msub> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <mn>
                 .. 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </munderover> 
           <mrow> 
            <mi>
              F 
            </mi> 
            <mrow> 
             <mo>
               ( 
             </mo> 
             <mrow> 
              <mn>
                ... 
              </mn> 
             </mrow> 
             <mo>
               ) 
             </mo> 
            </mrow> 
            <mtext>
              d 
            </mtext> 
            <mi>
              z 
            </mi> 
            <mo>
              , 
            </mo> 
           </mrow> 
          </mstyle> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mtext> 
       </mtext> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           h 
         </mi> 
         <mo>
           ≠ 
         </mo> 
         <mn>
           0 
         </mn> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (4)</p>
    <p>where</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            C 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mo>
           = 
         </mo> 
         <mn>
           2.1213 
         </mn> 
         <mo>
           × 
         </mo> 
         <msup> 
          <mtext>
            10 
          </mtext> 
          <mn>
            9 
          </mn> 
         </msup> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <mi>
           t 
         </mi> 
         <mo>
           = 
         </mo> 
         <mrow> 
          <mi>
            T 
          </mi> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              T 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
         </mrow> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <mi>
           h 
         </mi> 
         <mo>
           = 
         </mo> 
         <mrow> 
          <mi>
            H 
          </mi> 
          <mo>
            / 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              H 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
         </mrow> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <mi>
           L 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mn>
            1 
          </mn> 
          <mn>
            3 
          </mn> 
         </mfrac> 
         <mfrac> 
          <mrow> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ρ 
             </mi> 
             <mi>
               q 
             </mi> 
             <mo>
               + 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mi>
             k 
           </mi> 
           <mi>
             θ 
           </mi> 
          </mrow> 
          <mrow> 
           <mi>
             ℏ 
           </mi> 
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           </mi> 
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              ) 
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         </mfrac> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
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            N 
          </mi> 
          <mn>
            2 
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             .. 
           </mn> 
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            ) 
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           f 
         </mi> 
         <mi>
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           r 
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            [ 
          </mo> 
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            </mn> 
            <mn>
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            </mn> 
           </mfrac> 
           <mfrac> 
            <mrow> 
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                ( 
              </mo> 
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               <mi>
                 ρ 
               </mi> 
               <mi>
                 q 
               </mi> 
               <mo>
                 + 
               </mo> 
               <mn>
                 1 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
             <mi>
               k 
             </mi> 
             <mi>
               θ 
             </mi> 
            </mrow> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               Ω 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
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                <mi>
                  h 
                </mi> 
                <mi>
                  c 
                </mi> 
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              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </mfrac> 
           <mo>
             − 
           </mo> 
           <mfrac> 
            <mn>
              1 
            </mn> 
            <mn>
              2 
            </mn> 
           </mfrac> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math></p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         F 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
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           ... 
         </mn> 
        </mrow> 
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          ) 
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       </mrow> 
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         = 
       </mo> 
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        </mo> 
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           1 
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            { 
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             </mo> 
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                1 
              </mn> 
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                / 
              </mo> 
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                2 
              </mn> 
             </mrow> 
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               + 
             </mo> 
             <msup> 
              <mi>
                z 
              </mi> 
              <mn>
                2 
              </mn> 
             </msup> 
             <mo>
               − 
             </mo> 
             <mfrac> 
              <mrow> 
               <mi>
                 q 
               </mi> 
               <mi>
                 ρ 
               </mi> 
               <mi>
                 k 
               </mi> 
               <mi>
                 θ 
               </mi> 
              </mrow> 
              <mrow> 
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                 ℏ 
               </mi> 
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                 Ω 
               </mi> 
               <mrow> 
                <mo>
                  ( 
                </mo> 
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                  h 
                </mi> 
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                  ) 
                </mo> 
               </mrow> 
              </mrow> 
             </mfrac> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
          <mo>
            } 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math></p>
    <p>The PE and NE are supplemented by the equation for the London penetration depth</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          L 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msqrt> 
        <mrow> 
         <mfrac> 
          <mrow> 
           <msub> 
            <mi>
              ε 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <mi>
             η 
           </mi> 
           <msub> 
            <mi>
              m 
            </mi> 
            <mi>
              e 
            </mi> 
           </msub> 
           <msup> 
            <mi>
              c 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
          <mrow> 
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            <mi>
              N 
            </mi> 
            <mi>
              s 
            </mi> 
           </msub> 
           <msup> 
            <mi>
              e 
            </mi> 
            <mn>
              2 
            </mn> 
           </msup> 
          </mrow> 
         </mfrac> 
        </mrow> 
       </msqrt> 
       <mo>
         , 
       </mo> 
      </mrow> 
     </math> (SI Units) (5)</p>
    <p>where ε<sub>0</sub> = 8.85 × 10<sup>−</sup><sup>12</sup> F∙m<sup>−</sup><sup>1</sup>, c is the velocity of light, e the electronic charge, and N<sub>s</sub> is as given by (4).</p>
   </sec>
  </sec><sec id="s3">
   <title>3. Procedural Details</title>
   <p>In the following</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
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           1 
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             1 
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         </mrow> 
         <mo>
           / 
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             T 
           </mi> 
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             c 
           </mi> 
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         </mrow> 
        </mrow> 
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          , 
        </mo> 
        <mtext> 
        </mtext> 
        <msub> 
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          </mi> 
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            1 
          </mn> 
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            c 
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            2 
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           ) 
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           </mrow> 
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             ) 
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        <msub> 
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           t 
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          = 
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           </mi> 
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           </mi> 
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        </mtext> 
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             </mi> 
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             ) 
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           </mi> 
           <mrow> 
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              c 
            </mi> 
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            </mn> 
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              , 
            </mo> 
            <mi>
              c 
            </mi> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
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             0 
           </mn> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mrow> 
        <mo>
          , 
        </mo> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math></p>
   <p>where t<sub>1</sub> = 0.9 and t<sub>0</sub> = 0.1 for reasons to be specified.</p>
   <sec id="s3_1">
    <title>3.1. Elemental SCs</title>
    <p>In order to show that the properties of an SC in an external field are determined predominantly by 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         μ 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            t 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, we proceed as follows.</p>
    <p>1) Solve (3) for any SC to obtain the value of λ<sub>m</sub><sub>1</sub> with the input of its empirically listed values of T<sub>c</sub>, H<sub>c</sub>, an assumed value of μ<sub>1</sub> = ρkθ (ρ a free parameter), t<sub>1</sub> = 0.9 and the relation</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          h 
        </mi> 
        <mi>
          c 
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          </mi> 
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            t 
          </mi> 
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            ) 
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        </mrow> 
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          / 
        </mo> 
        <mrow> 
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          <mi>
            H 
          </mi> 
          <mi>
            c 
          </mi> 
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        </mrow> 
       </mrow> 
       <mo>
         = 
       </mo> 
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         1 
       </mn> 
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         − 
       </mo> 
       <msup> 
        <mi>
          t 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         , 
       </mo> 
      </mrow> 
     </math> (6)</p>
    <p>which for the most part has been found to be sound empirically and leads to h<sub>c</sub><sub>1</sub> = 0.19. Employment of this relation has been necessitated because, in general, the value of h<sub>c</sub><sub>1</sub> at t<sub>1</sub> is not known. Note that the choice of t<sub>1</sub> = 0.9 does away with the need to specify the self-field, which would be needed for t = 1 because then h<sub>c</sub><sub>1</sub> = 0, whereas a non-zero value of the latter is required for the employment of (4).</p>
    <p>2) After λ<sub>m</sub><sub>1</sub> is determined as noted in 1), solve (3) to determine the value of μ<sub>0</sub> corresponding to the values of t<sub>0</sub> = 0.1 and h<sub>c</sub><sub>0</sub> = 0.99 via (6). The reason for choosing t = 0.1 and not 0 is that the listed value of any parameter at t = 0 is invariably one that is extrapolated from a low value of t because no experiment has ever been performed exactly at T = 0. This will be further discussed below. Since μ<sub>1</sub> was parametrized as ρkθ, if we define μ<sub>0</sub> = qμ<sub>1</sub>, then it means that we are now solving the equation for q by replacing ρ by qρ in the earlier equation that yielded the value of λ<sub>m</sub><sub>1</sub>. Of course, we also need the value of λ<sub>m</sub><sub>0</sub> in order to obtain the value of q, which is easily obtained from the expression for λ<sub>m</sub> given below (3) by noting that</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mrow> 
           <mi>
             m 
           </mi> 
           <mn>
             0 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mrow> 
           <mi>
             m 
           </mi> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
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       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
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          <mi>
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          </mi> 
          <mrow> 
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             0 
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          </mrow> 
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         <msub> 
          <mi>
            h 
          </mi> 
          <mrow> 
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             1 
           </mn> 
          </mrow> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <msqrt> 
          <mi>
            q 
          </mi> 
         </msqrt> 
        </mrow> 
       </mfrac> 
       <mo>
         , 
       </mo> 
      </mrow> 
     </math></p>
    <p>since 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          μ 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mi>
         q 
       </mi> 
       <msub> 
        <mi>
          μ 
        </mi> 
        <mn>
          1 
        </mn> 
       </msub> 
      </mrow> 
     </math>. For the sake of concreteness, we write below the equation from which q is calculated. In terms of the dimensionless variable 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         x 
       </mi> 
       <mo>
         = 
       </mo> 
       <mrow> 
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          ξ 
        </mi> 
        <mo>
          / 
        </mo> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <mi>
           k 
         </mi> 
         <mi>
           t 
         </mi> 
         <msub> 
          <mi>
            T 
          </mi> 
          <mi>
            c 
          </mi> 
         </msub> 
        </mrow> 
       </mrow> 
      </mrow> 
     </math>, this equation is</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mn>
         1 
       </mn> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
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        </mi> 
        <mrow> 
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           m 
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           1 
         </mn> 
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        <mrow> 
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          </mi> 
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           <mn>
             0 
           </mn> 
          </mrow> 
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          </mi> 
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        </mrow> 
       </mfrac> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <msqrt> 
          <mi>
            q 
          </mi> 
         </msqrt> 
        </mrow> 
       </mfrac> 
       <mstyle displaystyle="true"> 
        <mrow> 
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          <mo>
            ∫ 
          </mo> 
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              1 
            </mn> 
           </msub> 
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            </mo> 
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               .. 
             </mn> 
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            <mo>
              ) 
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           </mrow> 
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            </mi> 
            <mn>
              2 
            </mn> 
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            </mo> 
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               .. 
             </mn> 
            </mrow> 
            <mo>
              ) 
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           </mrow> 
          </mrow> 
         </munderover> 
         <mrow> 
          <mstyle displaystyle="true"> 
           <munderover> 
            <mo>
              ∑ 
            </mo> 
            <mrow> 
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             </mi> 
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               = 
             </mo> 
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             </mn> 
            </mrow> 
            <mrow> 
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              <mi>
                N 
              </mi> 
              <mrow> 
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               </mi> 
               <mn>
                 0 
               </mn> 
              </mrow> 
             </msub> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
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                 .. 
               </mn> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </munderover> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <mtext>
                d 
              </mtext> 
              <mi>
                x 
              </mi> 
             </mrow> 
             <mrow> 
              <msqrt> 
               <mrow> 
                <mn>
                  1 
                </mn> 
                <mo>
                  + 
                </mo> 
                <mfrac> 
                 <mrow> 
                  <mn>
                    2 
                  </mn> 
                  <msub> 
                   <mi>
                     t 
                   </mi> 
                   <mn>
                     0 
                   </mn> 
                  </msub> 
                  <msub> 
                   <mi>
                     T 
                   </mi> 
                   <mi>
                     c 
                   </mi> 
                  </msub> 
                 </mrow> 
                 <mrow> 
                  <mi>
                    q 
                  </mi> 
                  <mi>
                    ρ 
                  </mi> 
                  <mi>
                    θ 
                  </mi> 
                 </mrow> 
                </mfrac> 
               </mrow> 
              </msqrt> 
              <mi>
                x 
              </mi> 
             </mrow> 
            </mfrac> 
            <mfrac> 
             <mrow> 
              <mi>
                tanh 
              </mi> 
              <mrow> 
               <mo>
                 [ 
               </mo> 
               <mrow> 
                <mi>
                  x 
                </mi> 
                <mo>
                  + 
                </mo> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    n 
                  </mi> 
                  <mo>
                    + 
                  </mo> 
                  <mrow> 
                   <mn>
                     1 
                   </mn> 
                   <mo>
                     / 
                   </mo> 
                   <mn>
                     2 
                   </mn> 
                  </mrow> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <mfrac> 
                 <mrow> 
                  <mi>
                    ℏ 
                  </mi> 
                  <mi>
                    Ω 
                  </mi> 
                  <mrow> 
                   <mo>
                     ( 
                   </mo> 
                   <mrow> 
                    <msub> 
                     <mi>
                       h 
                     </mi> 
                     <mrow> 
                      <mi>
                        c 
                      </mi> 
                      <mn>
                        0 
                      </mn> 
                     </mrow> 
                    </msub> 
                   </mrow> 
                   <mo>
                     ) 
                   </mo> 
                  </mrow> 
                 </mrow> 
                 <mrow> 
                  <mn>
                    2 
                  </mn> 
                  <mi>
                    k 
                  </mi> 
                  <msub> 
                   <mi>
                     t 
                   </mi> 
                   <mn>
                     0 
                   </mn> 
                  </msub> 
                  <msub> 
                   <mi>
                     T 
                   </mi> 
                   <mi>
                     c 
                   </mi> 
                  </msub> 
                 </mrow> 
                </mfrac> 
               </mrow> 
               <mo>
                 ] 
               </mo> 
              </mrow> 
             </mrow> 
             <mrow> 
              <mrow> 
               <mo>
                 [ 
               </mo> 
               <mrow> 
                <mi>
                  x 
                </mi> 
                <mo>
                  + 
                </mo> 
                <mrow> 
                 <mo>
                   ( 
                 </mo> 
                 <mrow> 
                  <mi>
                    n 
                  </mi> 
                  <mo>
                    + 
                  </mo> 
                  <mrow> 
                   <mn>
                     1 
                   </mn> 
                   <mo>
                     / 
                   </mo> 
                   <mn>
                     2 
                   </mn> 
                  </mrow> 
                 </mrow> 
                 <mo>
                   ) 
                 </mo> 
                </mrow> 
                <mfrac> 
                 <mrow> 
                  <mi>
                    ℏ 
                  </mi> 
                  <mi>
                    Ω 
                  </mi> 
                  <mrow> 
                   <mo>
                     ( 
                   </mo> 
                   <mrow> 
                    <msub> 
                     <mi>
                       h 
                     </mi> 
                     <mrow> 
                      <mi>
                        c 
                      </mi> 
                      <mn>
                        0 
                      </mn> 
                     </mrow> 
                    </msub> 
                   </mrow> 
                   <mo>
                     ) 
                   </mo> 
                  </mrow> 
                 </mrow> 
                 <mrow> 
                  <mn>
                    2 
                  </mn> 
                  <mi>
                    k 
                  </mi> 
                  <msub> 
                   <mi>
                     t 
                   </mi> 
                   <mn>
                     0 
                   </mn> 
                  </msub> 
                  <msub> 
                   <mi>
                     T 
                   </mi> 
                   <mi>
                     c 
                   </mi> 
                  </msub> 
                 </mrow> 
                </mfrac> 
               </mrow> 
               <mo>
                 ] 
               </mo> 
              </mrow> 
             </mrow> 
            </mfrac> 
           </mrow> 
          </mstyle> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         , 
       </mo> 
      </mrow> 
     </math> (7)</p>
    <p>where</p>
    <p>
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            x 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mi>
             θ 
           </mi> 
          </mrow> 
          <mrow> 
           <mn>
             6 
           </mn> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <msub> 
            <mi>
              T 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             2 
           </mn> 
           <mi>
             ρ 
           </mi> 
           <mi>
             q 
           </mi> 
           <mo>
             + 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           , 
         </mo> 
         <mtext> 
         </mtext> 
         <msub> 
          <mi>
            x 
          </mi> 
          <mn>
            2 
          </mn> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mfrac> 
          <mi>
            θ 
          </mi> 
          <mrow> 
           <mn>
             6 
           </mn> 
           <msub> 
            <mi>
              t 
            </mi> 
            <mn>
              0 
            </mn> 
           </msub> 
           <msub> 
            <mi>
              T 
            </mi> 
            <mi>
              c 
            </mi> 
           </msub> 
          </mrow> 
         </mfrac> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             2 
           </mn> 
           <mi>
             ρ 
           </mi> 
           <mi>
             q 
           </mi> 
           <mo>
             + 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mtd> 
       </mtr> 
       <mtr> 
        <mtd> 
         <msub> 
          <mi>
            N 
          </mi> 
          <mrow> 
           <mi>
             L 
           </mi> 
           <mn>
             0 
           </mn> 
          </mrow> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mn>
             .. 
           </mn> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           = 
         </mo> 
         <mi>
           f 
         </mi> 
         <mi>
           l 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           o 
         </mi> 
         <mi>
           r 
         </mi> 
         <mrow> 
          <mo>
            [ 
          </mo> 
          <mrow> 
           <mfrac> 
            <mn>
              2 
            </mn> 
            <mn>
              3 
            </mn> 
           </mfrac> 
           <mfrac> 
            <mrow> 
             <mi>
               k 
             </mi> 
             <mi>
               θ 
             </mi> 
            </mrow> 
            <mrow> 
             <mi>
               ℏ 
             </mi> 
             <mi>
               Ω 
             </mi> 
             <mrow> 
              <mo>
                ( 
              </mo> 
              <mrow> 
               <msub> 
                <mi>
                  h 
                </mi> 
                <mrow> 
                 <mi>
                   c 
                 </mi> 
                 <mn>
                   0 
                 </mn> 
                </mrow> 
               </msub> 
              </mrow> 
              <mo>
                ) 
              </mo> 
             </mrow> 
            </mrow> 
           </mfrac> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <mi>
               ρ 
             </mi> 
             <mi>
               q 
             </mi> 
             <mo>
               + 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             − 
           </mo> 
           <mfrac> 
            <mn>
              1 
            </mn> 
            <mn>
              2 
            </mn> 
           </mfrac> 
          </mrow> 
          <mo>
            ] 
          </mo> 
         </mrow> 
         <mo>
           . 
         </mo> 
        </mtd> 
       </mtr> 
      </mtable> 
     </math></p>
    <p>3) For the remainder of our procedure, it is convenient to deal with a specific SC, say Nb, for which λ<sub>L</sub>(0) = 52 nm <xref ref-type="bibr" rid="scirp.137780-1">
      [1]
     </xref>. With the values of θ, η, T<sub>c</sub> and H<sub>c</sub> given in <xref ref-type="table" rid="table1">
      Table 1
     </xref>, the choice of the free parameter ρ = 10 leads via (3) to λ<sub>m</sub><sub>1</sub> = 1.212 × 10<sup>−</sup><sup>6</sup> and thence to q = 2.607, N<sub>s</sub> = 2.81 × 10<sup>28</sup> m<sup>−</sup><sup>3</sup> and λ<sub>L</sub>(0) = 109.8 nm via (4) and (5), respectively. Since the last of these values is more than twice its listed value, we now repeat the steps carried out for ρ = 10 by progressively increasing ρ. Thus, we find that ρ = 30.7 leads to λ<sub>L</sub>(0) = 51.96 nm. The values of the other parameters corresponding to these are given in <xref ref-type="table" rid="table1">
      Table 1
     </xref>, which includes the final results for not only Sn and Pb, but also MgB<sub>2</sub> and YBCO.</p>
    <table-wrap id="table1">
     <label>
      <xref ref-type="table" rid="table1">
       Table 1
      </xref></label>
     <caption>
      <title>
       <xref ref-type="bibr" rid="scirp.137780-"></xref>Table 1. The empirical values for elemental SCs in column 1 are taken from Poole <xref ref-type="bibr" rid="scirp.137780-1">
        [1]
       </xref> and the values of η from Kittel <xref ref-type="bibr" rid="scirp.137780-9">
        [9]
       </xref>, except for Nb for which it is taken from Ashcroft and Mermin <xref ref-type="bibr" rid="scirp.137780-10">
        [10]
       </xref>. The equations employed to obtain the values of various parameters are as follows: λ<sub>m1</sub> and N<sub>L1</sub> via (3); q, λ<sub>m</sub><sub>0</sub>(t<sub>0</sub>) and N<sub>L</sub><sub>0</sub> via (7) and N<sub>s</sub> and λ<sub>L</sub>(t<sub>0</sub>) via (4) and (5), respectively. For the values of the parameters pertaining to MgB<sub>2</sub> and YBCO in column 1, see (8) and (9), respectively. YBCO/Y and YBCO/Ba mean that the 1PEM is due to the Y- and Ba-ions, respectively.</title>
     </caption>
     <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">SC</p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
            ρ 
          </mi> 
         </math></p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              μ 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
           <mo>
             = 
           </mo> 
           <mi>
             ρ 
           </mi> 
           <mi>
             k 
           </mi> 
           <mi>
             θ 
           </mi> 
          </mrow> 
         </math></p><p style="text-align:center">(eV)</p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              λ 
            </mi> 
            <mrow> 
             <mi>
               m 
             </mi> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              N 
            </mi> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mi>
             q 
           </mi> 
           <mo>
             = 
           </mo> 
           <mfrac> 
            <mrow> 
             <msub> 
              <mi>
                μ 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
            </mrow> 
            <mrow> 
             <msub> 
              <mi>
                μ 
              </mi> 
              <mn>
                1 
              </mn> 
             </msub> 
            </mrow> 
           </mfrac> 
          </mrow> 
         </math></p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              λ 
            </mi> 
            <mrow> 
             <mi>
               m 
             </mi> 
             <mn>
               0 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td rowspan="5" class="acenter" width="9.68%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              N 
            </mi> 
            <mrow> 
             <mi>
               L 
             </mi> 
             <mn>
               0 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
         </math></p></td> 
       <td rowspan="5" class="acenter" width="10.67%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              N 
            </mi> 
            <mi>
              s 
            </mi> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                t 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
           <mo>
             × 
           </mo> 
           <msup> 
            <mrow> 
             <mn>
               10 
             </mn> 
            </mrow> 
            <mrow> 
             <mn>
               28 
             </mn> 
            </mrow> 
           </msup> 
          </mrow> 
         </math></p><p style="text-align:center">(m<sup>−</sup><sup>3</sup>)</p></td> 
       <td rowspan="5" class="acenter" width="8.70%"><p style="text-align:center"> 
         <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <msub> 
            <mi>
              λ 
            </mi> 
            <mi>
              L 
            </mi> 
           </msub> 
           <mrow> 
            <mo>
              ( 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                t 
              </mi> 
              <mn>
                0 
              </mn> 
             </msub> 
            </mrow> 
            <mo>
              ) 
            </mo> 
           </mrow> 
          </mrow> 
         </math></p><p style="text-align:center">(nm)</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">θ, T<sub>c</sub> (K)</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center"> 
         <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
           <mi>
             η 
           </mi> 
           <mo>
             = 
           </mo> 
           <mrow> 
            <mrow> 
             <msubsup> 
              <mi>
                m 
              </mi> 
              <mi>
                e 
              </mi> 
              <mo>
                ∗ 
              </mo> 
             </msubsup> 
            </mrow> 
            <mo>
              / 
            </mo> 
            <mrow> 
             <msub> 
              <mi>
                m 
              </mi> 
              <mi>
                e 
              </mi> 
             </msub> 
            </mrow> 
           </mrow> 
          </mrow> 
         </math></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">H<sub>c</sub><sub>1</sub>(G)</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="12.87%"><p style="text-align:center">λ<sub>L</sub>(0) (nm)</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">Sn</p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">195, 3.72</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">148</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.49</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.192 × 10<sup>−</sup><sup>6</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">3,134,994</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">1.975</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">8.125 × 10<sup>−</sup><sup>6</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">1,184,352</p></td> 
       <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">2.029</p></td> 
       <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">41.87</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">1.26</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">305</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="12.87%"><p style="text-align:center">42</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">Pb</p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">96, 7.2</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">249</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.06</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">9.075 × 10<sup>−</sup><sup>6</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">1,543,592</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.27</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">3.139 × 10<sup>−</sup><sup>5</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">670,971</p></td> 
       <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">3.675</p></td> 
       <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">38.9</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">1.97</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">800</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="12.87%"><p style="text-align:center">39</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">Nb</p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">276, 9.25</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">30.7</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">0.730</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">1.074 × 10<sup>−</sup><sup>6</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">1,735,552</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.356</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">3.645 × 10<sup>−</sup><sup>6</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">770,501</p></td> 
       <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">12.55</p></td> 
       <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">51.96</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">12</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">1580</p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="12.87%"><p style="text-align:center">52</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">MgB<sub>2</sub></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">1062, 39</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.32</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">0.212</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">2.331 × 10<sup>−</sup><sup>5</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">11,418</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">3.055</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">6.948 × 10<sup>−</sup><sup>5</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">5538</p></td> 
       <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">0.447</p></td> 
       <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">139.9</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">3.1</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">2.5 × 10<sup>4</sup></p></td> 
      </tr> 
      <tr> 
       <td class="custom-bottom-td acenter" width="12.87%"><p style="text-align:center">140</p></td> 
      </tr> 
      <tr> 
       <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">YBCO/Y</p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
       <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">410, 92</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">6.77</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">0.239</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">4.427 × 10<sup>−</sup><sup>3</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">222</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">5.506</p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">9.831 × 10<sup>−</sup><sup>3</sup></p></td> 
       <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">210</p></td> 
       <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">1.070</p></td> 
       <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">88.89</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">3.0</p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">112 × 10<sup>4</sup></p></td> 
      </tr> 
      <tr> 
       <td class="acenter" width="12.87%"><p style="text-align:center">89</p></td> 
      </tr> 
     </table>
    </table-wrap>
    <p>Continued</p>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">YBCO/Ba</p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">478 <xref ref-type="bibr" rid="scirp.137780-8">
         [8]
        </xref>, 92</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">6.2</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">0.255</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">3.630 × 10<sup>−</sup><sup>3</sup></p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">240</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">5.139</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">8.343 × 10<sup>−</sup><sup>3</sup></p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">210</p></td> 
      <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">1.072</p></td> 
      <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">88.88</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">3.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">112 × 10<sup>4</sup></p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="12.87%"><p style="text-align:center">89</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="12.87%"><p style="text-align:center">YBCO/Y</p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="9.68%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="10.67%"><p style="text-align:center"></p></td> 
      <td class="custom-top-td acenter" width="8.70%"><p style="text-align:center"></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">410, 66</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">1.264</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">0.045</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">4.245 × 10<sup>−</sup><sup>3</sup></p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">79</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">6.516</p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">8.666 × 10<sup>−</sup><sup>6</sup></p></td> 
      <td rowspan="4" class="acenter" width="9.68%"><p style="text-align:center">62</p></td> 
      <td rowspan="4" class="acenter" width="10.67%"><p style="text-align:center">0.125</p></td> 
      <td rowspan="4" class="acenter" width="8.70%"><p style="text-align:center">260.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">3.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">91 × 10<sup>4</sup></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="12.87%"><p style="text-align:center">260</p></td> 
     </tr> 
    </table>
   </sec>
   <sec id="s3_2">
    <title>3.2. MgB<sub>2</sub> and YBCO</title>
    <p>The procedural details for dealing with these SCs are similar to those for the elemental SCs, except that in the BSE-based approach which leads to a generalization of the BCS equations (GBCSEs) via the employment of a superpropagator, explanation of the values of its T<sub>c</sub> and multiple gaps requires invoking more than a 1-phonon exchange mechanism (1PEM) for the formation of Cooper pairs. This is in contrast to the situation for elemental SCs for which 1PEM suffices. Hence, the question is: Do we require, say, 2PEM to deal with the properties of a composite SC in a magnetic field? The answer to this question is: not necessarily, because for the SCs considered here, the magnetic interaction parameter, i.e., λ<sub>m</sub> in (3), due to the B-ions in MgB<sub>2</sub> (Mg plays a secondary role via the proximity effect), or due to the Y- or Ba-ions ions in YBCO, turns out to be considerably smaller (and well below the Bogoliubov upper limit of 0.5) than any of the non-magnetic interaction parameters that occur in the equations for their T<sub>c</sub> and the gaps <xref ref-type="bibr" rid="scirp.137780-11">
      [11]
     </xref>.</p>
    <p>For MgB<sub>2</sub>, we now need to resolve θ(MgB<sub>2</sub>) = 815 K which is the mean of its values given in <xref ref-type="bibr" rid="scirp.137780-12">
      [12]
     </xref> into θ<sub>B</sub> and θ<sub>Mg</sub>. The basic idea here is due to Born and Karmann <xref ref-type="bibr" rid="scirp.137780-13">
      [13]
     </xref> <xref ref-type="bibr" rid="scirp.137780-14">
      [14]
     </xref> who had pointed out a long time ago that elastic waves in an anisotropic solid travel with different velocities in different directions and are hence characterized by different Debye frequencies or temperatures. Employing the double-pendulum model for the resolution of θ(MgB<sub>2</sub>) into the θs of its constituents <xref ref-type="bibr" rid="scirp.137780-15">
      [15]
     </xref>, we obtain <xref ref-type="bibr" rid="scirp.137780-11">
      [11]
     </xref> θ<sub>B</sub> = 1062 K and θ<sub>Mg</sub> =322 K (which we will not need). The basis for the value of each of the other properties of MgB<sub>2</sub> noted in column 1 of <xref ref-type="table" rid="table1">
      Table 1
     </xref> is as follows</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          c 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         39 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         K 
       </mtext> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-12">
      [12]
     </xref>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         η 
       </mi> 
       <mo>
         = 
       </mo> 
       <mtext>
         3 
       </mtext> 
       <mtext>
         .1 
       </mtext> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-16">
      [16]
     </xref></p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          H 
        </mi> 
        <mrow> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         2.5 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mn>
          4 
        </mn> 
       </msup> 
       <mtext>
           
       </mtext> 
       <mtext>
         G 
       </mtext> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           H 
         </mi> 
         <mo>
           | 
         </mo> 
         <mo>
           | 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-12">
      [12]
     </xref>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          λ 
        </mi> 
        <mi>
          L 
        </mi> 
        <mrow> 
         <mi>
           a 
         </mi> 
         <mi>
           b 
         </mi> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         140 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-17">
      [17]
     </xref> (8)</p>
    <p>When the 1PEM is considered to be due to the Y ions in YBCO, the values of the above parameters are:</p>
    <p>θ<sub>Y</sub> = θ(YBCO) = 410 K <xref ref-type="bibr" rid="scirp.137780-1">
      [1]
     </xref> (because the sub-lattice that contains the Y ions has no other constituent)</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          T 
        </mi> 
        <mi>
          c 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         92 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         K 
       </mtext> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-1">
      [1]
     </xref>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         η 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         3.0 
       </mn> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-18">
      [18]
     </xref></p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          H 
        </mi> 
        <mrow> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mn>
         112 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mn>
          4 
        </mn> 
       </msup> 
       <mtext>
           
       </mtext> 
       <mtext>
         G 
       </mtext> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           H 
         </mi> 
         <mo>
           | 
         </mo> 
         <mo>
           | 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-19">
      [19]
     </xref>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          λ 
        </mi> 
        <mi>
          L 
        </mi> 
        <mrow> 
         <mi>
           a 
         </mi> 
         <mi>
           b 
         </mi> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         89 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math> <xref ref-type="bibr" rid="scirp.137780-1">
      [1]
     </xref> (9)</p>
    <p>It is seen from <xref ref-type="table" rid="table1">
      Table 1
     </xref> that when the 1PEM is considered to be due to the Y ions, λ<sub>L</sub>(t<sub>0</sub>) ≈ 89 nm is obtained when μ<sub>1</sub> = 0.240 eV and that nearly the same value for λ<sub>L</sub>(t<sub>0</sub>) results when the IPEM is considered to be due to the Ba ions with μ<sub>1</sub> = 0.255 eV.</p>
   </sec>
   <sec id="s3_3">
    <title>3.3. Dealing With Two Samples of YBCO that Have Significantly Different Values of T<sub>c</sub> and λ<sub>L</sub>(0)</title>
    <p>Of the samples the properties of which were noted in (2), we have already dealt in detail with Sample 2 that has T<sub>c</sub> = 92 K and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          λ 
        </mi> 
        <mi>
          L 
        </mi> 
        <mrow> 
         <mi>
           a 
         </mi> 
         <mi>
           b 
         </mi> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         89 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math>. We now deal with Sample 1 of the same SC which is characterized by T<sub>c</sub> = 66 K and 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          λ 
        </mi> 
        <mi>
          L 
        </mi> 
        <mrow> 
         <mi>
           a 
         </mi> 
         <mi>
           b 
         </mi> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mn>
         260 
       </mn> 
       <mtext>
           
       </mtext> 
       <mtext>
         nm 
       </mtext> 
      </mrow> 
     </math>. H<sub>c2</sub> of this sample may be estimated to be 91 × 10<sup>4</sup> G, since H<sub>c</sub><sub>2</sub> = 87 × 10<sup>4</sup> G for the sample for which T<sub>c</sub> = 62 K - vide (1). The last row in <xref ref-type="table" rid="table1">
      Table 1
     </xref> gives the values of all the parameters corresponding to 
     <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msubsup> 
        <mi>
          λ 
        </mi> 
        <mi>
          L 
        </mi> 
        <mrow> 
         <mi>
           a 
         </mi> 
         <mi>
           b 
         </mi> 
        </mrow> 
       </msubsup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mn>
          0 
        </mn> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> of Sample 1.</p>
   </sec>
  </sec><sec id="s4">
   <title>4. Summing Up</title>
   <p>It has been shown in this paper that one can choose for any SC, via the choice of ρ, any value of μ(t<sub>1</sub>) from among a multitude of them and find a value of μ(t<sub>0</sub>) corresponding to it which is consistent with the empirical value of H<sub>c</sub><sub>1</sub><sub>,c2</sub>(t<sub>0</sub>) of the SC for t<sub>0</sub> close to 0. However, demanding that the so-obtained value of H<sub>c</sub><sub>1,</sub><sub>c</sub><sub>2</sub>(t<sub>0</sub>) should also lead to the empirical value of λ<sub>L</sub>(t<sub>0</sub>) of the SC fixes μ<sub>1</sub> uniquely.</p>
   <p>It is seen from <xref ref-type="table" rid="table1">
     Table 1
    </xref> that the value of μ<sub>0</sub> = qμ<sub>1</sub> (which is ≈ Fermi energy, E<sub>F</sub>) for MgB<sub>2</sub>, or any sample of YBCO, is considerably smaller than its value for the elemental SCs. This is in accord with the general belief that high-T<sub>c</sub> superconductivity is governed by low values of E<sub>F</sub>; see, e.g., <xref ref-type="bibr" rid="scirp.137780-20">
     [20]
    </xref>.</p>
   <p>It is interesting to note that we have adopted in this paper a variant of a part of the template given by Dogan and Cohen <xref ref-type="bibr" rid="scirp.137780-21">
     [21]
    </xref> to deal with various properties of SCs where the route to the value of λ<sub>L</sub>(0) is provided by the following equations</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ξ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             ϕ 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
          <msub> 
           <mi>
             H 
           </mi> 
           <mrow> 
            <mi>
              c 
            </mi> 
            <mn>
              2 
            </mn> 
           </mrow> 
          </msub> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mn>
             0 
           </mn> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
        </mfrac> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math> (10)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mi>
         F 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          π 
        </mi> 
        <msub> 
         <mi>
           Δ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <msub> 
         <mi>
           ξ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         ℏ 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (11)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         N 
       </mi> 
       <mi>
         s 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <mn>
          3 
        </mn> 
        <msup> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msubsup> 
             <mi>
               m 
             </mi> 
             <mi>
               e 
             </mi> 
             <mn>
               2 
             </mn> 
            </msubsup> 
            <msubsup> 
             <mi>
               v 
             </mi> 
             <mi>
               F 
             </mi> 
             <mn>
               2 
             </mn> 
            </msubsup> 
           </mrow> 
           <mrow> 
            <msup> 
             <mi>
               ℏ 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mo>
           / 
         </mo> 
         <mn>
           2 
         </mn> 
        </mrow> 
       </mrow> 
      </msup> 
      <mo>
        , 
      </mo> 
     </mrow> 
    </math> (12)</p>
   <p>followed by (5) for the calculation of λ<sub>L</sub>(0); 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ϕ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> above denotes the magnetic flux quantum and Δ<sub>0</sub> and ξ<sub>0</sub> denote the gap and the coherence length, respectively. The application of the above equations to YBCO with H<sub>c</sub><sub>2</sub>(0) = 112 T, Δ<sub>0</sub> = 20 meV leads to</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ξ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1.71 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm, 
      </mtext> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mi>
         F 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        1.64 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mn>
         5 
       </mn> 
      </msup> 
      <mrow> 
       <mtext>
         m 
       </mtext> 
       <mo>
         / 
       </mo> 
       <mtext>
         s 
       </mtext> 
      </mrow> 
      <mtext>
        , 
      </mtext> 
      <msub> 
       <mi>
         N 
       </mi> 
       <mi>
         s 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        9.54 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mn>
          25 
        </mn> 
       </mrow> 
      </msup> 
      <mtext>
          
      </mtext> 
      <msup> 
       <mtext>
         m 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          3 
        </mn> 
       </mrow> 
      </msup> 
      <mo>
        , 
      </mo> 
      <mtext> 
      </mtext> 
      <msub> 
       <mi>
         λ 
       </mi> 
       <mi>
         L 
       </mi> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        544 
      </mn> 
      <mtext>
          
      </mtext> 
      <mtext>
        nm 
      </mtext> 
     </mrow> 
    </math> (13)</p>
   <p>In the approach followed here on the other hand, m<sub>e</sub> is replaced by ηm<sub>e</sub> and the values of ξ<sub>0</sub> and Δ<sub>0</sub> are not required. Solution of (3) with the input of μ<sub>1</sub> then leads to the values of λ<sub>m</sub><sub>0</sub> and N<sub>L</sub><sub>0</sub>; that of (7) to the values of q, λ<sub>m</sub><sub>0</sub> and N<sub>L</sub><sub>0</sub>; N<sub>s</sub>(t<sub>0</sub>) is obtained via (4) which is employed in lieu of (12) and, finally, λ<sub>L</sub>(t<sub>0</sub>) is calculated via (5). It is notable that our approach leads to v<sub>F</sub>(YBCO) = 3.9 × 10<sup>5</sup> m/s via μ<sub>0</sub> = qμ<sub>1</sub> and 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mi>
         F 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mrow> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <msub> 
           <mi>
             μ 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
         <mo>
           / 
         </mo> 
         <mrow> 
          <mi>
            η 
          </mi> 
          <msub> 
           <mi>
             m 
           </mi> 
           <mi>
             e 
           </mi> 
          </msub> 
         </mrow> 
        </mrow> 
       </mrow> 
      </msqrt> 
      <mtext>
          
      </mtext> 
      <mi>
        c 
      </mi> 
     </mrow> 
    </math>(μ<sub>0</sub> and m<sub>e</sub> in units of electron-Volt) which is very close to the upper limit of the range (2.5 × 10<sup>5</sup> – 3.8 × 10<sup>5</sup> m/s) of the universal Fermi velocity of hydrides <xref ref-type="bibr" rid="scirp.137780-22">
     [22]
    </xref>.</p>
   <p>Since the lowest value of t adopted in this paper is 0.1, it is tacitly assumed that the values of the parameters on which λ<sub>L</sub> depends change insignificantly on extrapolation from t = 0.1 to t = 0. This flattening of the H<sub>c</sub><sub>2</sub>(t) vs. t plot for such values of t is in accord with the results obtained by Talantsev <xref ref-type="bibr" rid="scirp.137780-6">
     [6]
    </xref> for compressed H<sub>3</sub>S by employing four different equations based on well-established theories. Each of these equations invoked two or more parameters from the sample-specific set of the SC comprising {T<sub>c</sub>, gap, coherence length, λ<sub>L</sub>(0) and jump in sp. ht.} However, departures from this type of behavior, i.e., a steep rise in the value of H<sub>c</sub><sub>2</sub>(t) as t → 0 which is reminiscent of the divergence of ξ as t → 1, seem to have been empirically observed recently. For this reason, we believe that it is a good practice while quoting the value of any parameter to specify the lowest temperature at which it has been empirically determined (rather than reporting its extrapolated value) as has been done by Minkov, et al. <xref ref-type="bibr" rid="scirp.137780-23">
     [23]
    </xref> who have quoted the value of T as 10 K while reporting for compressed H<sub>3</sub>S the values of ξ<sub>0</sub>, λ<sub>L</sub>, etc. For a further discussion of the possible departure of the value of H<sub>c</sub><sub>2</sub>(t) from its value from, say t = 0.1, to lower values of t, we draw attention to <xref ref-type="bibr" rid="scirp.137780-24">
     [24]
    </xref> where a study of the H<sub>c</sub><sub>2</sub>(t) of compressed H<sub>3</sub>S and the issue of whether or not it satisfies the criterion of the Meissner effect was carried out by following the same approach as in this paper.</p>
   <p>A significant result of this paper is that if we could find empirically for any SC the values of h<sub>c</sub><sub>1</sub>/h<sub>c</sub><sub>2</sub> at t<sub>1</sub> and the unique value of μ(t<sub>1</sub>) that leads via μ(t<sub>0</sub>) to the value of its λ<sub>L</sub>(t<sub>0</sub>) by employing the equations that have been given, then we shall have a new, dynamics-based approach to calculate H<sub>c</sub><sub>2</sub> as an alternative to the existing approaches. We believe that this result is empirically verifiable. It is interesting to draw attention to yet another approach for the calculation of H<sub>c</sub><sub>2</sub> which is based on the thermodynamics of an SC in a magnetic field <xref ref-type="bibr" rid="scirp.137780-25">
     [25]
    </xref> and hence differs from all the other approaches including the one presented in this paper. It is worth noting that these different approaches ought to be viewed as complementing each other - rather than as competing approaches - because they shed light on different features of the same phenomenon. Finally, in so far as the practical applications are concerned, the study reported here suggests that by controlling the value of μ – which is a problem that belongs to the realm of chemical engineering - we could fabricate SCs that have bespoke properties.</p>
  </sec>
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