<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    wjet
   </journal-id>
   <journal-title-group>
    <journal-title>
     World Journal of Engineering and Technology
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2331-4222
   </issn>
   <issn publication-format="print">
    2331-4249
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/wjet.2024.124059
   </article-id>
   <article-id pub-id-type="publisher-id">
    wjet-137141
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Chemistry 
     </subject>
     <subject>
       Materials Science, Engineering
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Numerical Simulation of the Flow of a Molten Blast Furnace Slag in an Open Channel
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Miguel A.
      </surname>
      <given-names>
       Barron
      </given-names>
     </name>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Joan
      </surname>
      <given-names>
       Reyes
      </given-names>
     </name>
    </contrib>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Aristeo
      </surname>
      <given-names>
       Garrido
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aDepartamento de Materiales, Universidad Autonoma Metropolitana Azcapotzalco, Mexico City, Mexico
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     04
    </day> 
    <month>
     09
    </month>
    <year>
     2024
    </year>
   </pub-date> 
   <volume>
    12
   </volume> 
   <issue>
    04
   </issue>
   <fpage>
    963
   </fpage>
   <lpage>
    975
   </lpage>
   <history>
    <date date-type="received">
     <day>
      30,
     </day>
     <month>
      September
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      29,
     </day>
     <month>
      September
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      29,
     </day>
     <month>
      October
     </month>
     <year>
      2024
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    Despite its industrial importance, the flow of molten blast furnace slag in open channels has not been sufficiently studied. In this work, the unsteady non-uniform flow of a molten blast furnace slag in a rectangular open channel is numerically studied by solving the Saint-Venant equations by means of an explicit backwards finite difference scheme. An Arrhenius-type dependence of the viscosity of the slag on temperature is assumed. To calculate that viscosity, four temperatures are considered, namely 1450˚C, 1500˚C, 1550˚C and 1600˚C. To study the dynamic response of the system, a half-sinusoidal pulse with duration of 5 s is imposed at the channel entrance. According to the numerical simulations, for all the temperatures considered, the slag flow in the channel for an angle of 5 degrees is supercritical in nature. However, for an angle of 1 degree, the flow is transcritical, that is, it presents a transition from subcritical to supercritical. 
   </abstract>
   <kwd-group> 
    <kwd>
     Blast Furnace Slag
    </kwd> 
    <kwd>
      Molten Slag
    </kwd> 
    <kwd>
      Open Channel Flow
    </kwd> 
    <kwd>
      Saint-Venant Equations
    </kwd> 
    <kwd>
      Supercritical Flow
    </kwd> 
    <kwd>
      Transcritical Flow 
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>The blast furnace is a countercurrent reactor which uses coke as the main fuel and reductant, sinter and pellets as the iron-bearing components, and slag-forming fluxes such as limestone and dolomite. Hot air is injected into the furnace through tuyeres located at the lower part of the furnace, coke is burned and the hot gases mainly containing N<sub>2</sub>, CO and CO<sub>2</sub> rise in countercurrent with the solid charge to the top of the furnace. The solid charge is heated and the iron oxides are chemically reduced to metallic iron <xref ref-type="bibr" rid="scirp.137141-1">
     [1]
    </xref>. Molten slag is formed by physical and chemical interaction between added fluxes and iron ore gangue. Molten pig iron and molten slag are collected in the furnace crucible. Due to its lower density, molten slag floats on top of molten iron. In 2022, 1301 million tons of pig iron was produced in the world through the blast furnace, which accounts 91.2% of the primary iron obtained <xref ref-type="bibr" rid="scirp.137141-2">
     [2]
    </xref>. Approximately 300 kg of slag are formed for each ton of pig iron <xref ref-type="bibr" rid="scirp.137141-3">
     [3]
    </xref>. This means that approximately 390 million tons of blast furnace slag are produced worldwide per year. Due to the large quantities of blast furnace slag produced each year and its high environmental impact, from the point of view of sustainability and saving natural resources, in recent years, blast furnace slag has begun to be used more and more in pavement applications, concrete aggregate, construction fill, and so on <xref ref-type="bibr" rid="scirp.137141-4">
     [4]
    </xref>.</p>
   <p>Molten slag is tapped from the blast furnace and conveyed through an open channel to a pouring pot. From the pot, the molten slag is transported to a cooling station where it is solidified and subjected to a dry granulation process <xref ref-type="bibr" rid="scirp.137141-5">
     [5]
    </xref>. There are little published works on the transport of molten metals in open channels, however, most of them study the flow of molten metals subjected to magnetic fields <xref ref-type="bibr" rid="scirp.137141-6">
     [6]
    </xref>-<xref ref-type="bibr" rid="scirp.137141-11">
     [11]
    </xref>. Recently, two of the current authors have published some articles in which the flow of molten metals in open channels is studied from the point of view of the metallurgical industry <xref ref-type="bibr" rid="scirp.137141-12">
     [12]
    </xref>-<xref ref-type="bibr" rid="scirp.137141-14">
     [14]
    </xref>. Open channels for transporting molten metals and slag in the metallurgical industry differ from channels for transporting irrigation water and wastewater by their angle of inclination and length. Due to the tendency of molten materials to reoxidize and freeze with atmospheric air, their angle of inclination is greater and their length is shorter compared to water transport channels. In addition, the construction material of a metallurgical channel is made of refractory material that withstands high temperatures.</p>
   <p>Despite the industrial importance of metallurgical slag, practically no studies have been reported on the flow of molten slag in open channels. Regarding the flow of a molten slag in open channels, two of the most important physical properties of a slag are viscosity and density. Among other things, molten slag differs from molten metal by the high viscosity and low density of the first one. The viscosity of a slag depends mainly on temperature and chemical composition <xref ref-type="bibr" rid="scirp.137141-15">
     [15]
    </xref>. It is expensive and difficult to measure the viscosity of molten slag in the laboratory. So, there are many empirical and mathematical models to predict the viscosity of molten blast furnace slag. For example, in <xref ref-type="bibr" rid="scirp.137141-16">
     [16]
    </xref>, a model based on discrete data points is reported. The model prediction is compared with viscosity data of slag of compositions typical to blast furnace operations, and the results show that the viscosity can be predicted with average error of less than 10%. Other models are based on partial least-squares regression <xref ref-type="bibr" rid="scirp.137141-17">
     [17]
    </xref>, on chemical composition <xref ref-type="bibr" rid="scirp.137141-18">
     [18]
    </xref>, on the Vogel-Fulcher-Tammann equation <xref ref-type="bibr" rid="scirp.137141-19">
     [19]
    </xref>, on experimental measurements by a rotating crucible viscometer <xref ref-type="bibr" rid="scirp.137141-20">
     [20]
    </xref>, and on optical basicity <xref ref-type="bibr" rid="scirp.137141-21">
     [21]
    </xref>.</p>
   <p>In this work, the unsteady non-uniform flow of a molten blast furnace slag in a rectangular open channel is studied by solving the Saint-Venant equations. The transient Saint-Venant equations are numerically solved by means of an explicit backwards finite difference scheme in one-dimensional space <xref ref-type="bibr" rid="scirp.137141-11">
     [11]
    </xref> <xref ref-type="bibr" rid="scirp.137141-22">
     [22]
    </xref> <xref ref-type="bibr" rid="scirp.137141-23">
     [23]
    </xref>. As in <xref ref-type="bibr" rid="scirp.137141-14">
     [14]
    </xref>, the half-sinusoidal pulse is imposed on the channel inlet as a boundary condition in the volumetric flow rate in order to observe the dynamic and stable response of the system. An Arrhenius-type dependence of viscosity with temperature is used to take into account the effect of temperature on flow dynamics. The values of the activation energy and the pre-exponential factor are taken from the literature for a synthetic slag similar to that of a blast furnace <xref ref-type="bibr" rid="scirp.137141-24">
     [24]
    </xref>. The friction slope and the frictional resistance coefficient are calculated using the expressions reported in <xref ref-type="bibr" rid="scirp.137141-25">
     [25]
    </xref>. Froude numbers are monitored to determine the type of flow present, whether subcritical, critical, or supercritical, and the possible transition between such flows. Research on the type of flow in open channels is important from the point of view of the adequate management of molten slag, but also on the adequate maintenance of the channel given that depending on the type of flow, gravity waves emerge and can lead to pulsations and flow instability, and erosion issues may arise.</p>
  </sec><sec id="s2">
   <title>2. Mathematical Model</title>
   <p>In an open channel, in which the depth of the transported liquid is small compared to the length, and the density of the liquid is constant, the height and the volumetric flow rate can be represented mathematically by the Saint-Venant equations. These equations are a one-dimensional form of the shallow water model <xref ref-type="bibr" rid="scirp.137141-26">
     [26]
    </xref>, and consist of a continuity equation and a momentum equation <xref ref-type="bibr" rid="scirp.137141-22">
     [22]
    </xref>:</p>
   <p>Continuity equation:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        b 
      </mi> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          h 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          Q 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          x 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (1)</p>
   <p>Momentum equation:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          Q 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mi>
         b 
       </mi> 
      </mfrac> 
      <mfrac> 
       <mo>
         ∂ 
       </mo> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          x 
        </mi> 
       </mrow> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msup> 
           <mi>
             Q 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
         <mi>
           h 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        + 
      </mo> 
      <mi>
        g 
      </mi> 
      <mi>
        b 
      </mi> 
      <mi>
        h 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mo>
            ∂ 
          </mo> 
          <mi>
            h 
          </mi> 
         </mrow> 
         <mrow> 
          <mo>
            ∂ 
          </mo> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          + 
        </mo> 
        <msub> 
         <mi>
           S 
         </mi> 
         <mi>
           f 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           S 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (2)</p>
   <p>In Equations (1) and (2) h(t, x) and Q(t, x) are the height of the liquid and the volumetric flow rate, respectively. Besides, t and x are the coordinates in time and space, respectively. Also, b is the width of the channel, g is the gravitational acceleration, S<sub>f</sub> is the friction slope, 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        tan 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         θ 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> is the channel slope, and θ is the channel inclination angle.</p>
   <p>Algebraic manipulation of Equation (2) yields the following expression for the momentum equation <xref ref-type="bibr" rid="scirp.137141-22">
     [22]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          Q 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mi>
        α 
      </mi> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          Q 
        </mi> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          x 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mi>
        β 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (3)</p>
   <p>where</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        α 
      </mi> 
      <mo>
        = 
      </mo> 
      <mn>
        2 
      </mn> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mi>
           Q 
         </mi> 
         <mrow> 
          <mi>
            b 
          </mi> 
          <mi>
            h 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          g 
        </mi> 
        <mi>
          h 
        </mi> 
        <mo>
          − 
        </mo> 
        <msup> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mi>
               Q 
             </mi> 
             <mrow> 
              <mi>
                b 
              </mi> 
              <mi>
                h 
              </mi> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mi>
             Q 
           </mi> 
           <mrow> 
            <mi>
              b 
            </mi> 
            <mi>
              h 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mn>
             5 
           </mn> 
           <mn>
             3 
           </mn> 
          </mfrac> 
          <mo>
            − 
          </mo> 
          <mfrac> 
           <mn>
             4 
           </mn> 
           <mn>
             3 
           </mn> 
          </mfrac> 
          <msub> 
           <mi>
             R 
           </mi> 
           <mi>
             h 
           </mi> 
          </msub> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (4)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        β 
      </mi> 
      <mo>
        = 
      </mo> 
      <mi>
        g 
      </mi> 
      <mi>
        b 
      </mi> 
      <mi>
        h 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           S 
         </mi> 
         <mi>
           f 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           S 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (5)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         R 
       </mi> 
       <mi>
         h 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          b 
        </mi> 
        <mi>
          h 
        </mi> 
       </mrow> 
       <mrow> 
        <mi>
          b 
        </mi> 
        <mo>
          + 
        </mo> 
        <mn>
          2 
        </mn> 
        <mi>
          h 
        </mi> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (6)</p>
   <p>The friction slope can be estimated from the Darcy-Weisbach formula <xref ref-type="bibr" rid="scirp.137141-25">
     [25]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mi>
         f 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         f 
       </mi> 
       <mi>
         D 
       </mi> 
      </msub> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mi>
           u 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
       <mrow> 
        <mn>
          8 
        </mn> 
        <mi>
          g 
        </mi> 
        <mi>
          h 
        </mi> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (7)</p>
   <p>where 
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         f 
       </mi> 
       <mi>
         D 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mrow> 
       <mrow> 
        <mn>
          24 
        </mn> 
       </mrow> 
       <mo>
         / 
       </mo> 
       <mrow> 
        <mi>
          R 
        </mi> 
        <mi>
          e 
        </mi> 
       </mrow> 
      </mrow> 
     </mrow> 
    </math> is the frictional resistance coefficient, u is the liquid velocity, and Re is the Reynolds number, which is determined is this way:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        R 
      </mi> 
      <mi>
        e 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           D 
         </mi> 
         <mi>
           h 
         </mi> 
        </msub> 
        <mi>
          u 
        </mi> 
        <mi>
          ρ 
        </mi> 
       </mrow> 
       <mi>
         μ 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> (8)</p>
   <p>where D<sub>h</sub> = 4R<sub>h</sub> is the hydraulic diameter, and ρ and μ are the density and the viscosity, respectively.</p>
   <p>Solving u from Equation (8) and substituting it into Equation (7) yields</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         S 
       </mi> 
       <mi>
         f 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           f 
         </mi> 
         <mi>
           D 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          8 
        </mn> 
        <mi>
          g 
        </mi> 
        <mi>
          h 
        </mi> 
       </mrow> 
      </mfrac> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <mi>
              R 
            </mi> 
            <mi>
              e 
            </mi> 
            <mi>
              μ 
            </mi> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               D 
             </mi> 
             <mi>
               h 
             </mi> 
            </msub> 
            <mi>
              ρ 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math> (9)</p>
   <p>The viscosity of a slag depends strongly on temperature. Assuming Arrhenius-type dependence, the viscosity can be calculated in this way <xref ref-type="bibr" rid="scirp.137141-24">
     [24]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        μ 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         μ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mi>
        exp 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            E 
          </mi> 
          <mi>
            a 
          </mi> 
         </mrow> 
         <mrow> 
          <mi>
            R 
          </mi> 
          <mi>
            T 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (10)</p>
   <p>where μ<sub>0</sub> is the pre-exponential factor (kg/m∙s), Ea is the activation energy (J/mol), R = 8.314 (J/mol∙K) is the gas constant, and T is the absolute temperature (˚K).</p>
   <p>NUMERICAL SOLUTION</p>
   <p>Saint-Venant equations were numerically solved by means of an explicit backwards finite difference scheme <xref ref-type="bibr" rid="scirp.137141-13">
     [13]
    </xref> <xref ref-type="bibr" rid="scirp.137141-23">
     [23]
    </xref>. The discretized continuity equation becomes:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         h 
       </mi> 
       <mi>
         i 
       </mi> 
       <mrow> 
        <mi>
          n 
        </mi> 
        <mo>
          + 
        </mo> 
        <mn>
          1 
        </mn> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         h 
       </mi> 
       <mi>
         i 
       </mi> 
       <mi>
         n 
       </mi> 
      </msubsup> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
         <mrow> 
          <mi>
            b 
          </mi> 
          <mi>
            Δ 
          </mi> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msubsup> 
         <mi>
           Q 
         </mi> 
         <mi>
           i 
         </mi> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            + 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </msubsup> 
        <mo>
          − 
        </mo> 
        <msubsup> 
         <mi>
           Q 
         </mi> 
         <mrow> 
          <mi>
            i 
          </mi> 
          <mo>
            − 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            + 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </msubsup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (11)</p>
   <p>And the discretized momentum equation is given by:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msubsup> 
       <mi>
         Q 
       </mi> 
       <mi>
         i 
       </mi> 
       <mrow> 
        <mi>
          n 
        </mi> 
        <mo>
          + 
        </mo> 
        <mn>
          1 
        </mn> 
       </mrow> 
      </msubsup> 
      <mo>
        = 
      </mo> 
      <msubsup> 
       <mi>
         Q 
       </mi> 
       <mi>
         i 
       </mi> 
       <mi>
         n 
       </mi> 
      </msubsup> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <msubsup> 
       <mi>
         α 
       </mi> 
       <mi>
         i 
       </mi> 
       <mi>
         n 
       </mi> 
      </msubsup> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msubsup> 
         <mi>
           Q 
         </mi> 
         <mi>
           i 
         </mi> 
         <mi>
           n 
         </mi> 
        </msubsup> 
        <mo>
          − 
        </mo> 
        <msubsup> 
         <mi>
           Q 
         </mi> 
         <mrow> 
          <mi>
            i 
          </mi> 
          <mo>
            − 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           n 
         </mi> 
        </msubsup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        − 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
      <msubsup> 
       <mi>
         β 
       </mi> 
       <mi>
         i 
       </mi> 
       <mi>
         n 
       </mi> 
      </msubsup> 
     </mrow> 
    </math> (12)</p>
   <p>To solve the Saint-Venant equations, an initial condition and a boundary condition for h and Q are required.</p>
   <p>Initial conditions for h and Q:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        h 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
        <mi>
          x 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         h 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> (13)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Q 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mn>
          0 
        </mn> 
        <mo>
          , 
        </mo> 
        <mi>
          x 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         Q 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> (14)</p>
   <p>Boundary condition for h:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        h 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          , 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         h 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> (15)</p>
   <p>Boundary condition for Q:</p>
   <p>A half-sinusoidal inflow pulse is imposed at the upstream of the channel on Q in order to analyze the dynamic response of slag in the channel <xref ref-type="bibr" rid="scirp.137141-13">
     [13]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Q 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          , 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         Q 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mi>
        A 
      </mi> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mn>
            2 
          </mn> 
          <mi>
            π 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
         <mi>
           T 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        , 
      </mo> 
      <mi>
        t 
      </mi> 
      <mo>
        ≤ 
      </mo> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
     </mrow> 
    </math> (16)</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Q 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          , 
        </mo> 
        <mn>
          0 
        </mn> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         Q 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        , 
      </mo> 
      <mi>
        t 
      </mi> 
      <mo>
        &gt; 
      </mo> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mi>
         p 
       </mi> 
      </msub> 
     </mrow> 
    </math> (17)</p>
   <p>where T = pulse period, t<sub>p</sub> = pulse duration time, and A = 0.75Q<sub>0</sub> is the pulse amplitude.</p>
   <p>The discretized Saint-Venant equations were programmed in Fortran 95 language and solved for a simulation time of 60 s using Re = 4 × 10<sup>3</sup>. Open channels used to transport metals and molten slag are shorter and steeper than channels used to transport irrigation and drainage water. A channel length of 10 m was assumed. In the numerical simulations, 500 nodes were employed, which produced a Δx value of 0.02 m. To have numerical stability, a time step Δt of 1 × 10<sup>−4</sup> s was established <xref ref-type="bibr" rid="scirp.137141-13">
     [13]
    </xref>.</p>
  </sec><sec id="s3">
   <title>3. Results and Comments</title>
   <p>As was stated above, the viscosity of a slag depends fundamentally on temperature and chemical composition. The viscosity decreases as the temperature increases. The main components of a blast furnace slag are CaO, MgO, SiO<sub>2</sub> and Al<sub>2</sub>O<sub>3</sub>. The viscosity decreases with the increase of MgO and increases with the increase of Al<sub>2</sub>O<sub>3</sub> <xref ref-type="bibr" rid="scirp.137141-24">
     [24]
    </xref>. The chemical composition of the considered blast furnace slag and its viscosity parameters, are shown in <xref ref-type="table" rid="table1">
     Table 1
    </xref> and <xref ref-type="table" rid="table2">
     Table 2
    </xref>, respectively. Viscosity parameters were calculated from the temperature-viscosity data reported in <xref ref-type="bibr" rid="scirp.137141-24">
     [24]
    </xref>.</p>
   <table-wrap id="table1">
    <label>
     <xref ref-type="table" rid="table1">
      Table 1
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.137141-"></xref>Table 1. Chemical composition of the blast furnace slag <xref ref-type="bibr" rid="scirp.137141-24">
       [24]
      </xref>.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="32.43%"><p style="text-align:center">Component</p></td> 
      <td class="custom-bottom-td acenter" width="19.16%"><p style="text-align:center">CaO</p></td> 
      <td class="custom-bottom-td acenter" width="19.16%"><p style="text-align:center">SiO<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="21.89%"><p style="text-align:center">Al<sub>2</sub>O<sub>3</sub></p></td> 
      <td class="custom-bottom-td acenter" width="19.16%"><p style="text-align:center">MgO</p></td> 
      <td class="custom-bottom-td acenter" width="19.16%"><p style="text-align:center">MoO<sub>3</sub></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="32.43%"><p style="text-align:center">Weight percent</p></td> 
      <td class="acenter" width="19.16%"><p style="text-align:center">41.6</p></td> 
      <td class="acenter" width="19.16%"><p style="text-align:center">38.0</p></td> 
      <td class="acenter" width="21.89%"><p style="text-align:center">17.2</p></td> 
      <td class="acenter" width="19.16%"><p style="text-align:center">3.0</p></td> 
      <td class="acenter" width="19.16%"><p style="text-align:center">0.2</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <table-wrap id="table2">
    <label>
     <xref ref-type="table" rid="table2">
      Table 2
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.137141-"></xref>Table 2. Viscosity parameters of the blast furnace slag, calculated from <xref ref-type="bibr" rid="scirp.137141-24">
       [24]
      </xref>.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="25.67%"><p style="text-align:center">Parameter</p></td> 
      <td class="custom-bottom-td acenter" width="27.31%"><p style="text-align:center">Value</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="25.67%"><p style="text-align:center">μ<sub>0</sub>, kg/(m∙s)</p></td> 
      <td class="custom-top-td acenter" width="27.31%"><p style="text-align:center">9.469 × 10<sup>−5</sup></p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="25.67%"><p style="text-align:center">Ea, J/mol</p></td> 
      <td class="acenter" width="27.31%"><p style="text-align:center">1.940 × 10<sup>5</sup></p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>Four temperature values were considered, namely, 1450˚C, 1500˚C, 1550˚C, and 1600˚C, corresponding to 1723.15, 1773.15, 1823.15, and 1873.15˚K, respectively. The viscosity values as a function of temperature, calculated with Equation (10), are shown in <xref ref-type="table" rid="table3">
     Table 3
    </xref>.</p>
   <table-wrap id="table3">
    <label>
     <xref ref-type="table" rid="table3">
      Table 3
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.137141-"></xref>Table 3. Calculated viscosities of the blast furnace slag.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="47.83%"><p style="text-align:center">Temperature, ˚K</p></td> 
      <td class="custom-bottom-td acenter" width="52.17%"><p style="text-align:center">Viscosity, kg/(m∙s)</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="47.83%"><p style="text-align:center">1723.15</p></td> 
      <td class="custom-top-td acenter" width="52.17%"><p style="text-align:center">0.7200</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="47.83%"><p style="text-align:center">1773.15</p></td> 
      <td class="acenter" width="52.17%"><p style="text-align:center">0.4915</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="47.83%"><p style="text-align:center">1823.15</p></td> 
      <td class="acenter" width="52.17%"><p style="text-align:center">0.3426</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="47.83%"><p style="text-align:center">1873.15</p></td> 
      <td class="acenter" width="52.17%"><p style="text-align:center">0.2434</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>Values of the rectangular open channel parameters considered in the numerical simulation are shown in <xref ref-type="table" rid="table4">
     Table 4
    </xref> <xref ref-type="bibr" rid="scirp.137141-13">
     [13]
    </xref> <xref ref-type="bibr" rid="scirp.137141-27">
     [27]
    </xref>.</p>
   <table-wrap id="table4">
    <label>
     <xref ref-type="table" rid="table4">
      Table 4
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.137141-"></xref>Table 4. Open channel parameters <xref ref-type="bibr" rid="scirp.137141-13">
       [13]
      </xref> <xref ref-type="bibr" rid="scirp.137141-27">
       [27]
      </xref>.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="49.26%"><p style="text-align:center">Parameter</p></td> 
      <td class="custom-bottom-td acenter" width="43.79%"><p style="text-align:center">Value</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="49.26%"><p style="text-align:center">Initial height (h<sub>0</sub>)</p></td> 
      <td class="custom-top-td acenter" width="43.79%"><p style="text-align:center">0.15 m</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="49.26%"><p style="text-align:center">Volumetric flow rate (Q<sub>0</sub>)</p></td> 
      <td class="acenter" width="43.79%"><p style="text-align:center">0.038 m<sup>3</sup>/s</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="49.26%"><p style="text-align:center">Channel width (b)</p></td> 
      <td class="acenter" width="43.79%"><p style="text-align:center">0.20 m</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="49.26%"><p style="text-align:center">Initial velocity (u<sub>0</sub>)</p></td> 
      <td class="acenter" width="43.79%"><p style="text-align:center">1.2667 m/s</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="49.26%"><p style="text-align:center">Channel length</p></td> 
      <td class="acenter" width="43.79%"><p style="text-align:center">10.0 m</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="49.26%"><p style="text-align:center">Inclination angle (θ)</p></td> 
      <td class="acenter" width="43.79%"><p style="text-align:center">5 degrees</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="49.26%"><p style="text-align:center">Initial velocity (u<sub>0</sub>)</p></td> 
      <td class="acenter" width="43.79%"><p style="text-align:center">1.27 m/s</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>The dimensionless Froude number Fr is essential for classifying flows in open channels. It is defined as follows <xref ref-type="bibr" rid="scirp.137141-28">
     [28]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        F 
      </mi> 
      <mi>
        r 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         u 
       </mi> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <mi>
            g 
          </mi> 
          <mi>
            h 
          </mi> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (18)</p>
   <p>As will be seen later, numerical simulations show that the slag height and velocity of the slag evolve in time from a transient state until they reach a steady state at the channel discharge after a time of 60 s. These steady state values of height and velocity, together with the Froude number, are shown in <xref ref-type="table" rid="table5">
     Table 5
    </xref>. The Froude numbers in this table were calculated using the steady-state values of height and velocity through the expression:</p>
   <table-wrap id="table5">
    <label>
     <xref ref-type="table" rid="table5">
      Table 5
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.137141-"></xref>Table 5. Values of height, slag velocity and Froude number in steady state as a function of temperature.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td acenter" width="32.49%"><p style="text-align:center">T (˚K)</p></td> 
      <td class="custom-bottom-td acenter" width="34.13%"><p style="text-align:center">h<sub>st</sub> (m)</p></td> 
      <td class="custom-bottom-td acenter" width="34.13%"><p style="text-align:center">u<sub>st</sub> (m/s)</p></td> 
      <td class="custom-bottom-td acenter" width="34.13%"><p style="text-align:center">Fr</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="32.49%"><p style="text-align:center">1723.15</p></td> 
      <td class="custom-top-td acenter" width="34.13%"><p style="text-align:center">0.05246</p></td> 
      <td class="custom-top-td acenter" width="34.13%"><p style="text-align:center">3.62174</p></td> 
      <td class="custom-top-td acenter" width="34.13%"><p style="text-align:center">5.04854</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="32.49%"><p style="text-align:center">1773.15</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">0.03800</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">5.00502</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">8.19795</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="32.49%"><p style="text-align:center">1823.15</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">0.02854</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">6.66519</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">12.59620</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="32.49%"><p style="text-align:center">1873.15</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">0.02196</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">8.66381</p></td> 
      <td class="acenter" width="34.13%"><p style="text-align:center">18.66719</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        F 
      </mi> 
      <mi>
        r 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           u 
         </mi> 
         <mrow> 
          <mi>
            s 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <msqrt> 
         <mrow> 
          <mi>
            g 
          </mi> 
          <msub> 
           <mi>
             h 
           </mi> 
           <mrow> 
            <mi>
              s 
            </mi> 
            <mi>
              t 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
        </msqrt> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (19)</p>
   <p>If Fr &lt; 1, h<sub>st</sub> &gt; h<sub>c</sub> and u<sub>st</sub> &lt; u<sub>c</sub>, then the flow regime is called subcritical. In this case, the role of gravitational forces is pronounced and the flow has relatively large depths and small velocities. If Fr &gt; 1, h<sub>st</sub> &lt; h<sub>c</sub> and u<sub>st</sub> &gt; u<sub>c</sub>, then the flow regime is called supercritical, the inertial forces are dominant and the flow is characterized by relatively small depths and large velocities <xref ref-type="bibr" rid="scirp.137141-29">
     [29]
    </xref>. If Fr = 1, the flow regime is denoted as critical. In this case, gravity waves can lead to pulsations in channels, and stability and erosion issues may arise. To avoid the possibility of flow pulsations, it is important to avoid channel designs with 0.9 &lt; Fr &lt; 1.1 <xref ref-type="bibr" rid="scirp.137141-28">
     [28]
    </xref>.</p>
   <p>The critical depth h<sub>c</sub> is the flow depth at a section of the channel where the flow is critical. The expression for the critical depth is <xref ref-type="bibr" rid="scirp.137141-30">
     [30]
    </xref>:</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         h 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msup> 
             <mi>
               Q 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
           <mrow> 
            <msup> 
             <mi>
               b 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
            <mi>
              g 
            </mi> 
           </mrow> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <mrow> 
         <mn>
           1 
         </mn> 
         <mo>
           / 
         </mo> 
         <mn>
           3 
         </mn> 
        </mrow> 
       </mrow> 
      </msup> 
     </mrow> 
    </math> (20)</p>
   <p>The velocity associated with the critical depth is called critical velocity, and is determined by making Fr = 1 in Equation (18):</p>
   <p>
    <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         u 
       </mi> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msqrt> 
       <mrow> 
        <mi>
          g 
        </mi> 
        <msub> 
         <mi>
           h 
         </mi> 
         <mi>
           c 
         </mi> 
        </msub> 
       </mrow> 
      </msqrt> 
     </mrow> 
    </math> (21)</p>
   <p>Using the data in <xref ref-type="table" rid="table4">
     Table 4
    </xref>, the following values for critical height and critical velocity are obtained: h<sub>c</sub> = 0.1544 m, u<sub>c</sub> = 1.23072 m/s.</p>
   <p>The results of the numerical simulations are described and commented below. <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref> shows the evolution in time of the slag height at the channel discharge for different values of temperature. The height of the slag starts from a value h<sub>o</sub> = 0.15 m, which is maintained for about 2 seconds. Then, it decreases until a time of approximately 3 seconds, time in which the height presents a peak due to the effect of the half-sinusoidal pulse of the volumetric flow. From the peak onwards, the height decreases apparently exponentially until reaching a steady-state value h<sub>st</sub>. This stable value of the height decreases with increasing temperature, as can be seen in <xref ref-type="table" rid="table5">
     Table 5
    </xref> and <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref>. In all cases, the stable value of the height is below the critical height, namely h<sub>st</sub> &lt; h<sub>c</sub>. <xref ref-type="fig" rid="fig3">
     Figure 3
    </xref> shows that the Froude number Fr increases as the temperature of the slag increases or the viscosity of the slag decreases. For all temperatures considered, the value of Fr is greater than unity. This, together with the fact that h<sub>st</sub> &lt; h<sub>c</sub>, means that the slag flow in the channel is a supercritical flow, regardless of the slag temperature.</p>
   <fig id="fig1" position="float">
    <label>Figure 1</label>
    <caption>
     <title>Figure 1. Evolution over time of the slag height at the channel discharge for different slag temperatures. The dashed line represents the critical height.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId62.jpeg?20241101030942" />
   </fig>
   <fig id="fig2" position="float">
    <label>Figure 2</label>
    <caption>
     <title>Figure 2. Steady-state slag height at channel discharge as a function of slag temperature.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId63.jpeg?20241101030942" />
   </fig>
   <fig id="fig3" position="float">
    <label>Figure 3</label>
    <caption>
     <title>Figure 3. Froude number as a function of slag temperature.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId64.jpeg?20241101030942" />
   </fig>
   <p>The time changes of slag velocity in the open channel discharge for different slag temperatures are shown in <xref ref-type="fig" rid="fig4">
     Figure 4
    </xref>. The velocity of the slag increases progressively until it reaches a stable value that depends strongly on temperature. However, it is possible to observe two small peaks in the slag velocity, around a time of 3 and 7 s. <xref ref-type="fig" rid="fig5">
     Figure 5
    </xref> explicitly shows the dependence of the steady state velocity on temperature. As can be seen in <xref ref-type="table" rid="table5">
     Table 5
    </xref>, <xref ref-type="fig" rid="fig4">
     Figure 4
    </xref> and <xref ref-type="fig" rid="fig5">
     Figure 5
    </xref>, all steady-state velocity values increase with an increase in temperature, and all of them are greater than the critical velocity, i.e., u<sub>st</sub> &gt; u<sub>c</sub>. These results corroborate the supercritical nature of the slag flow in the open channel considered. <xref ref-type="fig" rid="fig6">
     Figure 6
    </xref> shows the evolution in time of the volumetric flow rate. Two peaks are seen before 10 s, and from here, the values stabilize at Q<sub>0</sub>. It means that for any temperature value, regardless of the different steady-state values of height and velocity, the steady-state volumetric flow remains constant. The presence of the two peaks can be explained, presumably, by the action of the gravitational forces that cause the first peak, and the inertial forces of the applied semi-sinusoidal pulse that cause the second peak. This is corroborated in <xref ref-type="fig" rid="fig7">
     Figure 7
    </xref>, which shows the behavior of the volumetric flow rate at 1723.15 K with and without pulse.</p>
   <fig id="fig4" position="float">
    <label>Figure 4</label>
    <caption>
     <title>Figure 4. Evolution over time of the slag velocity at the channel discharge for different slag temperatures. The dashed line represents the critical velocity.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId65.jpeg?20241101030942" />
   </fig>
   <fig id="fig5" position="float">
    <label>Figure 5</label>
    <caption>
     <title>Figure 5. Steady-state slag velocity at channel discharge as a function of slag temperature.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId66.jpeg?20241101030942" />
   </fig>
   <fig id="fig6" position="float">
    <label>Figure 6</label>
    <caption>
     <title>Figure 6. Evolution over time of the volumetric flow rate at the channel discharge as a function of the slag temperature.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId67.jpeg?20241101030942" />
   </fig>
   <fig id="fig7" position="float">
    <label>Figure 7</label>
    <caption>
     <title>Figure 7. Volumetric flow rate in the channel discharge with and without the half-sinusoidal pulse.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId68.jpeg?20241101030942" />
   </fig>
   <p>In order to know the influence of the channel inclination angle θ on the type of flow, an additional numerical simulation was carried out using an angle of 1 degree and a temperature of 1723.15 K. The results for the slag height are shown in <xref ref-type="fig" rid="fig8">
     Figure 8
    </xref> for two angles of 1 and 5 degrees. As seen in this Figure, the height of the slag has an interesting behavior when θ = 1. For this angle, when 5 s have elapsed, the slag height reaches a peak that exceeds the critical height, and thereafter decreases to a value below the critical height. This means that for a short time of about 3 s, the flow is subcritical, and then it becomes supercritical. In other words, the flow is temporary transcritical in nature <xref ref-type="bibr" rid="scirp.137141-31">
     [31]
    </xref>, that is, the flow presents a temporary transition from subcritical to supercritical for an inclination angle of 1 degree.</p>
   <fig id="fig8" position="float">
    <label>Figure 8</label>
    <caption>
     <title>Figure 8. Evolution over time of the slag height at the channel discharge for two different channel inclination angles at T = 1723.15˚K.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/1561597-rId69.jpeg?20241101030942" />
   </fig>
  </sec><sec id="s4">
   <title>4. Conclusions</title>
   <p>The flow of molten blast furnace slag in an open channel was numerically analyzed. For this, the transient Saint-Venant equations were solved using an explicit finite difference scheme. Four slag temperatures were considered. A length of ten meters, a width of 0.2 m, and an inclination angle of five degrees were also set. In order to know the influence of the channel inclination angle on the type of flow, an additional numerical simulation was carried out using an angle of 1 degree. A volumetric flow rate at the inlet was set at 0.038 m<sup>3</sup>/s. A half-sinusoidal pulse in the volumetric flow of slag with a duration of five s and amplitude of 75% of the initial flow was established at the entrance of the channel in order to observe the response of the system. From the results of the numerical simulations, the following conclusions can be drawn:</p>
   <p>1) For the channel considered, the slag flow is supercritical in nature, regardless of the value of the slag temperature.</p>
   <p>2) The slag flow, in terms of height and velocity, reaches a steady state whose values are dependent on temperature.</p>
   <p>3) Steady-state height decreases with temperature, while steady state velocity increases with temperature. In both cases, the volumetric flow remains constant.</p>
   <p>4) The Froude number increases with temperature. This means that if the temperature of the slag increases, the supercritical nature of the flow becomes more intense.</p>
   <p>5) An inclination angle of one degree of the channel produces a transient flow of transcritical nature, that is, it presents a temporary transition from subcritical flow to supercritical flow. An angle of five degrees does not present such a transition.</p>
   <p>Of course, all numerical results and conclusions shown in this work should be verified with plant data or published works. However, to the authors’ knowledge, that information is not available.</p>
  </sec>
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