<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jhepgc
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of High Energy Physics, Gravitation and Cosmology
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    2380-4327
   </issn>
   <issn publication-format="print">
    2380-4335
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jhepgc.2024.104088
   </article-id>
   <article-id pub-id-type="publisher-id">
    jhepgc-136495
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Gravitomagnetic Waves Predicted by the Theory of Informatons
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Antoine
      </surname>
      <given-names>
       Acke
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aRetired Professor Kaho Sint-Lieven, Now KU Leuven, Faculty of Engineering Technology, Ghent Campus, Ghent, Belgium
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     28
    </day> 
    <month>
     08
    </month>
    <year>
     2024
    </year>
   </pub-date> 
   <volume>
    10
   </volume> 
   <issue>
    04
   </issue>
   <fpage>
    1564
   </fpage>
   <lpage>
    1577
   </lpage>
   <history>
    <date date-type="received">
     <day>
      24,
     </day>
     <month>
      May
     </month>
     <year>
      2024
     </year>
    </date>
    <date date-type="published">
     <day>
      7,
     </day>
     <month>
      May
     </month>
     <year>
      2024
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      7,
     </day>
     <month>
      October
     </month>
     <year>
      2024
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    In this article we show that the description of the gravitational field as a cloud of g-information implies the phenomenon of “gravitomagnetic” or “gravitational waves”
    <sup>1</sup> and that accelerated mass particles and radioactive decay are sources of such waves. It is also shown that a gravitomagnetic wave propagating in a certain direction can be understood as the macroscopic manifestation of a spatial sequence of informatons whose characteristic angle is fluctuating along that—with the speed of light—speeding “train”. Finally, it is shown that gravitomagnetic waves transport energy in the form of packages carried by informatons. These entities are called “gravitons”.
   </abstract>
   <kwd-group> 
    <kwd>
     Gravity
    </kwd> 
    <kwd>
      Gravitational Field
    </kwd> 
    <kwd>
      Gravitomagnetic Waves
    </kwd> 
    <kwd>
      Informatons
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>In the framework of the theory of informatons <xref ref-type="bibr" rid="scirp.136495-1">
     [1]
    </xref>-<xref ref-type="bibr" rid="scirp.136495-5">
     [5]
    </xref>, a gravitational field is a dual entity, having a field- and an induction component ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math>) simultaneously created by its common sources: time-variable masses and mass flows. It is the manifestation at the macroscopic level of a cloud of informatons: mass and energy less granular entities that—relative to an inertial reference frame—are moving with the speed of light and that are carriers of information referring to the position (“g-information”) and the velocity (“β-information”) of their emitter.</p>
   <p>The Maxwell-Heaviside <xref ref-type="bibr" rid="scirp.136495-1">
     [1]
    </xref> equations, that describe how a gravitational field ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math>) is generated and how it evolves in space and in time, imply fluctuations in its intensity that are propagating at the speed of light as waves outward from the source of that field.</p>
   <p>More specifically, from the postulate of the emission of informatons <xref ref-type="bibr" rid="scirp.136495-2">
     [2]
    </xref>-<xref ref-type="bibr" rid="scirp.136495-5">
     [5]
    </xref>, it can be deduced that an accelerated mass particle is the source of a gravitational field of which the time dependent components of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> represent waves that are traveling with the speed of light. It follows that a harmonically oscillating mass particle is the source of an harmonically gravitational wave transporting energy in the form of “gravitons”: quanta of energy carried by informatons.</p>
   <p>A change of the rest mass of an object—what occurs during radioactive decay— is another source of a gravitational wave. Indeed, the change of the rest mass of an object immediately results in a change of the rate at which it emits informatons which gives rise to a disturbance of its gravitational field that propagates with the speed of light.</p>
   <p>Let’s also mention that gravitational waves were first proposed by Oliver Heaviside <xref ref-type="bibr" rid="scirp.136495-6">
     [6]
    </xref> in 1893 and then later by Henri Poincaré <xref ref-type="bibr" rid="scirp.136495-7">
     [7]
    </xref> in 1905 as the gravitational equivalent of electromagnetic waves. More recently, attention was also paid to the phenomenon in the work of Oleg Jefimenko <xref ref-type="bibr" rid="scirp.136495-8">
     [8]
    </xref>.</p>
  </sec><sec id="s2">
   <title>2. The Wave Equation</title>
   <p>In free space—where 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         ρ 
       </mi> 
       <mi>
         G 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          J 
        </mi> 
       </mstyle> 
       <mi>
         G 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math>—the Maxwell-Heaviside <xref ref-type="bibr" rid="scirp.136495-1">
     [1]
    </xref> equations are:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        d 
      </mi> 
      <mi>
        i 
      </mi> 
      <mi>
        v 
      </mi> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (1)</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        d 
      </mi> 
      <mi>
        i 
      </mi> 
      <mi>
        v 
      </mi> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mn>
        0 
      </mn> 
     </mrow> 
    </math> (2)</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mi>
        o 
      </mi> 
      <mi>
        t 
      </mi> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            B 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (3)</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mi>
        o 
      </mi> 
      <mi>
        t 
      </mi> 
      <mtext>
          
      </mtext> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mfrac> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (4)</p>
   <p>To attempt a solution of a group of simultaneous equations, it is usually a good plan to separate the various functions of space to arrive at equations that give the distributions of each.</p>
   <p>It follows from (3):</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mi>
        o 
      </mi> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          r 
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        </mi> 
        <mtext>
            
        </mtext> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mi>
        r 
      </mi> 
      <mi>
        o 
      </mi> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mo>
            ∂ 
          </mo> 
          <msub> 
           <mstyle mathvariant="bold" mathsize="normal"> 
            <mi>
              B 
            </mi> 
           </mstyle> 
           <mi>
             g 
           </mi> 
          </msub> 
         </mrow> 
         <mrow> 
          <mo>
            ∂ 
          </mo> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (3’)</p>
   <p>Because <xref ref-type="bibr" rid="scirp.136495-9">
     [9]
    </xref></p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mi>
        o 
      </mi> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          r 
        </mi> 
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        <mtext>
            
        </mtext> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           F 
         </mi> 
        </mstyle> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        g 
      </mi> 
      <mi>
        r 
      </mi> 
      <mi>
        a 
      </mi> 
      <mi>
        d 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          d 
        </mi> 
        <mi>
          i 
        </mi> 
        <mi>
          v 
        </mi> 
        <mtext>
            
        </mtext> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           F 
         </mi> 
        </mstyle> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        − 
      </mo> 
      <msup> 
       <mo>
         ∇ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         F 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>, where 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mo>
         ∇ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math> is the Laplacian,</p>
   <p>(3’) leads to:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        g 
      </mi> 
      <mi>
        r 
      </mi> 
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        a 
      </mi> 
      <mi>
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      </mi> 
      <mrow> 
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         ( 
       </mo> 
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        </mi> 
        <mtext>
            
        </mtext> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        − 
      </mo> 
      <msup> 
       <mo>
         ∇ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msup> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mi>
        r 
      </mi> 
      <mi>
        o 
      </mi> 
      <mi>
        t 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <mo>
            ∂ 
          </mo> 
          <msub> 
           <mstyle mathvariant="bold" mathsize="normal"> 
            <mi>
              B 
            </mi> 
           </mstyle> 
           <mi>
             g 
           </mi> 
          </msub> 
         </mrow> 
         <mrow> 
          <mo>
            ∂ 
          </mo> 
          <mi>
            t 
          </mi> 
         </mrow> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mo>
         ∂ 
       </mo> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <mi>
          t 
        </mi> 
       </mrow> 
      </mfrac> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          r 
        </mi> 
        <mi>
          o 
        </mi> 
        <mi>
          t 
        </mi> 
        <mtext>
            
        </mtext> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            B 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math></p>
   <p>And taking into account (1) and (4):</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mo>
         ∇ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msup> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mo>
           ∂ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (5)</p>
   <p>This is the general form of the wave equation. This form applies as well to the g-induction, as is readily shown by taking first the rotor of (4) and then substituting (2) and (3):</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mo>
         ∇ 
       </mo> 
       <mn>
         2 
       </mn> 
      </msup> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mo>
           ∂ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            B 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> (5’)</p>
   <p>Solutions of this equation describe how disturbances of the gravitational field propagate as waves with speed c.</p>
   <p>To illustrate this, we consider the special case of space variation in one dimension only. If we take the x-component of (5) and have space variations only in the z-direction, the equation becomes simply:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mo>
           ∂ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           E 
         </mi> 
         <mrow> 
          <mi>
            g 
          </mi> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msup> 
         <mi>
           z 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msup> 
         <mo>
           ∂ 
         </mo> 
         <mn>
           2 
         </mn> 
        </msup> 
        <msub> 
         <mi>
           E 
         </mi> 
         <mrow> 
          <mi>
            g 
          </mi> 
          <mi>
            x 
          </mi> 
         </mrow> 
        </msub> 
       </mrow> 
       <mrow> 
        <mo>
          ∂ 
        </mo> 
        <msup> 
         <mi>
           t 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>This equation has a general solution of the form</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mrow> 
        <mi>
          g 
        </mi> 
        <mi>
          x 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         f 
       </mi> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           z 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        + 
      </mo> 
      <msub> 
       <mi>
         f 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mi>
           z 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> (6)</p>
   <p>The first term of (6) represents the wave or function f<sub>1</sub> traveling with velocity c and unchanged form in the positive z-direction, the second term represents the wave or function f<sub>2</sub> traveling with velocity c and unchanging form in the negative z-direction.</p>
  </sec><sec id="s3">
   <title>3. The g-Index of an Informaton Emitted by an Accelerated Mass Particle</title>
   <p>In <xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>, we consider a mass particle with rest mass m<sub>0</sub> that, during a finite time interval, moves with constant acceleration 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         a 
       </mi> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         z 
       </mi> 
      </msub> 
     </mrow> 
    </math> relative to the IRF O. At the moment t = 0, m<sub>0</sub> starts from rest at the origin O, and at t = t it passes at the point P<sub>1</sub>. Its velocity is there defined by 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         v 
       </mi> 
      </mstyle> 
      <mo>
        = 
      </mo> 
      <mi>
        v 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        t 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         z 
       </mi> 
      </msub> 
     </mrow> 
    </math>, and its position by</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mi>
         t 
       </mi> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        v 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math></p>
   <p>We limit our considerations to the situation where the speed of the particle remains much smaller than the speed of light: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mi>
         v 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ≪ 
      </mo> 
      <mn>
        1 
      </mn> 
     </mrow> 
    </math>.</p>
   <fig id="fig1" position="float">
    <label>Figure 1</label>
    <caption>
     <title>Figure 1. The g-index of an informaton emitted by an accelerated particle.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181125-rId62.jpeg?20241010121057" />
   </fig>
   <p>The informatons that during the infinitesimal time interval (t, t + dt) pass near the fixed point P (whose position relative to the moving particle m<sub>0</sub> is defined by the time dependent position vector 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        r 
      </mi> 
     </mstyle> 
    </math>) have been emitted at the moment 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        t 
      </mi> 
      <mo>
        − 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>, when m<sub>0</sub> passed at P<sub>0</sub> with velocity 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          v 
        </mi> 
       </mstyle> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         z 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        v 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         z 
       </mi> 
      </msub> 
     </mrow> 
    </math>. The position of P relative to P<sub>0</sub> is defined by the time dependent position vector 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          r 
        </mi> 
       </mstyle> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         r 
       </mi> 
      </mstyle> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. Δt, the time interval during which m<sub>0</sub> moves from P<sub>0</sub> to P<sub>1</sub> is the time that the informatons need to move—with the speed of light—from P<sub>0</sub> to P</p>
   <p>from which we can conclude that 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>, and that</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        v 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        v 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             r 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        v 
      </mi> 
      <mo>
        − 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>Between the moments 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>, m<sub>0</sub> is moving from P<sub>0</sub> to P<sub>1</sub>. That movement can be considered as the resultant (the superposition) of a uniform movement with constant speed 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        v 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> and a uniformly accelerated movement with constant acceleration a.</p>
   <p>1) In the below figure, we consider the case of the particle m<sub>0</sub> moving with constant speed 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math> along the Z-axis. At the moment 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        t 
      </mi> 
      <mo>
        − 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math> m<sub>0</sub> passes at P<sub>0</sub> and at the moment t at 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
     </mrow> 
    </math>: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         v 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>. The informatons that, during the infinitesimal time interval (t, t + dt), pass near the point P—whose position relative to the uniformly moving particle m<sub>0</sub> at the moment t is defined by the position vector 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <msup> 
       <mi>
         r 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </mstyle> 
    </math>—have been emitted at the moment t<sub>0</sub> when m<sub>0</sub> passed at P<sub>0</sub>.</p>
   <fig id="fig2" position="float">
    <label>Figure 2</label>
    <caption>
     <title>Their velocity vector 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal">
  
        <mi>
         
   c
  
        </mi>
 
       </mstyle>

      </math> is on the line 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    P
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mi>
         
   P
  
        </mi>
 
       </mrow>

      </math>, their g-index 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mstyle mathvariant="bold" mathsize="normal">
    
          <mi>
           
     s
    
          </mi>
   
         </mstyle> 
   
         <mi>
          
    g
   
         </mi> 
  
        </msub> 
 
       </mrow>

      </math> points to 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <msup> 
    
          <mi>
           
     P
    
          </mi> 
    
          <mo>
           
     ′
    
          </mo> 
   
         </msup> 
   
         <mn>
          
    1
   
         </mn> 
  
        </msub> 
 
       </mrow>

      </math>:
      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    P
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <msub> 
   
         <msup> 
    
          <mi>
           
     P
    
          </mi> 
    
          <mo>
           
     ′
    
          </mo> 
   
         </msup> 
   
         <mn>
          
    1
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <msub> 
   
         <mi>
          
    v
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   ⋅
  
        </mo>
  
        <mi>
         
   Δ
  
        </mi>
  
        <mi>
         
   t
  
        </mi>
  
        <mo>
         
   =
  
        </mo>
  
        <msub> 
   
         <mi>
          
    v
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mfrac> 
   
         <mrow> 
    
          <msub> 
     
           <mi>
             r 
           </mi> 
     
           <mn>
             0 
           </mn> 
    
          </msub> 
   
         </mrow> 
   
         <mi>
          
    c
   
         </mi> 
  
        </mfrac> 
 
       </mrow>

      </math>2) In the below figure, we consider the case of the particle m<sub>0</sub> starting at rest at P<sub>0</sub> and moving with constant acceleration a along the Z-axis.At the moment 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    t
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <mi>
         
   t
  
        </mi>
  
        <mo>
         
   −
  
        </mo>
  
        <mi>
         
   Δ
  
        </mi>
  
        <mi>
         
   t
  
        </mi>
 
       </mrow>

      </math> it is at P<sub>0</sub> and at the moment t at 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <msup> 
    
          <mi>
           
     P
    
          </mi> 
    
          <mo>
           
     ″
    
          </mo> 
   
         </msup> 
   
         <mn>
          
    1
   
         </mn> 
  
        </msub> 
 
       </mrow>

      </math>:
      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mi>
          
    P
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
  
        <msub> 
   
         <msup> 
    
          <mi>
           
     P
    
          </mi> 
    
          <mo>
           
     ″
    
          </mo> 
   
         </msup> 
   
         <mn>
          
    1
   
         </mn> 
  
        </msub> 
  
        <mo>
         
   =
  
        </mo>
  
        <mfrac> 
   
         <mn>
          
    1
   
         </mn> 
   
         <mn>
          
    2
   
         </mn> 
  
        </mfrac> 
  
        <mo>
         
   ⋅
  
        </mo>
  
        <mi>
         
   a
  
        </mi>
  
        <mo>
         
   ⋅
  
        </mo>
  
        <msup> 
   
         <mrow> 
    
          <mrow>
     
           <mo>
             ( 
           </mo> 
     
           <mrow> 
            <mi>
              Δ 
            </mi> 
            <mi>
              t 
            </mi> 
           </mrow> 
     
           <mo>
             ) 
           </mo>
    
          </mrow>
   
         </mrow> 
   
         <mn>
          
    2
   
         </mn> 
  
        </msup> 
 
       </mrow>

      </math><p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/2181125-rId107.jpeg?20241010121057" /></p>The informatons that during the infinitesimal time interval (t, t + dt) pass near the point P (whose position relative to the uniformly accelerated particle m<sub>0</sub> is at t defined by the position vector 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal">
  
        <msup> 
   
         <mi>
          
    r
   
         </mi> 
   
         <mo>
          
    ″
   
         </mo> 
  
        </msup> 
 
       </mstyle>

      </math>) have been emitted at t<sub>0</sub> when m<sub>0</sub> was at P<sub>0</sub>. Their velocity vector 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal">
  
        <mi>
         
   c
  
        </mi>
 
       </mstyle>

      </math> points away from P<sub>0</sub>, their g-index 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <mstyle mathvariant="bold" mathsize="normal">
    
          <mi>
           
     s
    
          </mi>
   
         </mstyle> 
   
         <mi>
          
    g
   
         </mi> 
  
        </msub> 
 
       </mrow>

      </math> to 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <msup> 
    
          <mi>
           
     P
    
          </mi> 
    
          <mo>
           
     ″
    
          </mo> 
   
         </msup> 
   
         <mn>
          
    2
   
         </mn> 
  
        </msub> 
 
       </mrow>

      </math>. To determine the position of 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <msub> 
   
         <msup> 
    
          <mi>
           
     P
    
          </mi> 
    
          <mo>
           
     ″
    
          </mo> 
   
         </msup> 
   
         <mn>
          
    2
   
         </mn> 
  
        </msub> 
 
       </mrow>

      </math>, we consider, relative to the accelerated reference frame OX’Y’Z’ that is anchored to m<sub>0</sub>, the trajectory of the informatons that at t<sub>0</sub>are emitted in the direction of P (

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <mi>
         
   α
  
        </mi>
  
        <mo>
         
   =
  
        </mo>
  
        <mfrac> 
   
         <mi>
          
    π
   
         </mi> 
   
         <mn>
          
    2
   
         </mn> 
  
        </mfrac> 
  
        <mo>
         
   −
  
        </mo>
  
        <msub> 
   
         <mi>
          
    θ
   
         </mi> 
   
         <mn>
          
    0
   
         </mn> 
  
        </msub> 
 
       </mrow>

      </math>).<p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/2181125-rId120.jpeg?20241010121057" /></p>Relative to OX’Y’Z’ these informatons are accelerated with an amount 

      <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
  
        <mo>
         
   −
  
        </mo>
  
        <mstyle mathvariant="bold" mathsize="normal">
   
         <mi>
          
    a
   
         </mi>
  
        </mstyle>
 
       </mrow>

      </math>: they follow a parabolic trajectory described by the equation:</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181125-rId90.jpeg?20241010121057" />
   </fig>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msup> 
       <mi>
         z 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mi>
        t 
      </mi> 
      <mi>
        g 
      </mi> 
      <mi>
        α 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mi>
         y 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mi>
         a 
       </mi> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mrow> 
          <mi>
            cos 
          </mi> 
         </mrow> 
         <mn>
           2 
         </mn> 
        </msup> 
        <mi>
          α 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <msup> 
        <mi>
          y 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         2 
       </mn> 
      </msup> 
     </mrow> 
    </math></p>
   <p>At the moment 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         t 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>, when they pass at P, the tangent line to that trajectory cuts the Z’-axis at the point M, that is defined by:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          z 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mi>
         M 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>That means that the g-indices of the informatons that at the moment t pass at P, point to a point M on the Z-axis that has a lead of</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mi>
        M 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mrow> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            t 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mn>
         2 
       </mn> 
      </msup> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mn>
         2 
       </mn> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>on 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
     </mrow> 
    </math>, the actual position of the mass particle. And since 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mtext>
          
      </mtext> 
      <mtext>
          
      </mtext> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         2 
       </mn> 
      </msub> 
     </mrow> 
    </math>, we conclude that:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        a 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msubsup> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>In the inertial reference frame O (<xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>) 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> points to the point P<sub>2</sub> on the Z-axis determined by the superposition of the effect of the velocity (1) and the effect of the acceleration (2):</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         1 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <msup> 
        <mi>
          P 
        </mi> 
        <mo>
          ″ 
        </mo> 
       </msup> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           v 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mi>
         r 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mi>
         a 
       </mi> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <msubsup> 
       <mi>
         r 
       </mi> 
       <mn>
         0 
       </mn> 
       <mn>
         2 
       </mn> 
      </msubsup> 
     </mrow> 
    </math></p>
   <p>The carrier line of the g-index 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> of an informaton that—relative to the inertial frame O—at the moment t passes near P forms a “characteristic angle” 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math> with the carrier line of its velocity vector 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math>, that can be deduced by application of the sine-rule in triangle 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <msub> 
       <mi>
         P 
       </mi> 
       <mn>
         2 
       </mn> 
      </msub> 
      <mi>
        P 
      </mi> 
     </mrow> 
    </math> (<xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>):</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           P 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <msub> 
         <mi>
           P 
         </mi> 
         <mn>
           2 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <msub> 
           <mi>
             θ 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            + 
          </mo> 
          <mi>
            Δ 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <msub> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>From which it follows that</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          Δ 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           v 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           θ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          + 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mi>
         a 
       </mi> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mi>
         r 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <msub> 
         <mi>
           θ 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          + 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math></p>
   <p>From the fact that P<sub>0</sub>P<sub>1</sub>—the distance travelled by m<sub>0</sub> during the time interval Δt—can be neglected relative to P<sub>0</sub>P—the distance travelled by light during the same period—it follows that 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         θ 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        ≈ 
      </mo> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math> and that 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         r 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        ≈ 
      </mo> 
      <mi>
        r 
      </mi> 
     </mrow> 
    </math>. So:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          Δ 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           v 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mi>
        θ 
      </mi> 
      <mo>
        + 
      </mo> 
      <mfrac> 
       <mi>
         a 
       </mi> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        r 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math></p>
   <p>We can conclude that the g-index 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> of an informaton that at the moment t passes near P, has a longitudinal component, this is a component in the direction of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> (its velocity vector) and a transversal component, this is a component perpendicular to that direction. It is evident that:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
      <mtr> 
       <mtd> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            s 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           s 
         </mi> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          cos 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            e 
          </mi> 
         </mstyle> 
         <mi>
           c 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           s 
         </mi> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          sin 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            Δ 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            e 
          </mi> 
         </mstyle> 
         <mrow> 
          <mo>
            ⊥ 
          </mo> 
          <mi>
            c 
          </mi> 
         </mrow> 
        </msub> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          ≈ 
        </mo> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           s 
         </mi> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            e 
          </mi> 
         </mstyle> 
         <mi>
           c 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <msub> 
         <mi>
           s 
         </mi> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               v 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
           <mi>
             c 
           </mi> 
          </mfrac> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            sin 
          </mi> 
          <mi>
            θ 
          </mi> 
          <mo>
            + 
          </mo> 
          <mfrac> 
           <mi>
             a 
           </mi> 
           <mrow> 
            <msup> 
             <mi>
               c 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mfrac> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            r 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            sin 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            e 
          </mi> 
         </mstyle> 
         <mrow> 
          <mo>
            ⊥ 
          </mo> 
          <mi>
            c 
          </mi> 
         </mrow> 
        </msub> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math></p>
  </sec><sec id="s4">
   <title>4. The Gravitational Field of an Accelerated Mass Particle</title>
   <p>The informatons that, at the moment t, are passing near the fixed point P—defined by the time dependent position vector 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        r 
      </mi> 
     </mstyle> 
    </math>—are emitted when m<sub>0</sub> was at P<sub>0</sub> (<xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>). Their velocity 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> is on the same carrier line as 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          r 
        </mi> 
       </mstyle> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          P 
        </mi> 
       </mstyle> 
       <mn>
         0 
       </mn> 
      </msub> 
      <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         P 
       </mi> 
      </mstyle> 
     </mrow> 
    </math>. Their g-index is on the carrier line P<sub>2</sub>P. According to §3, the characteristic angle 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math>— this is the angle between the carrier lines of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math>—has two components:</p>
   <p>1) a component 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <msup> 
       <mi>
         θ 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </mrow> 
    </math> related to the velocity of m<sub>0</sub> at the moment ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>) when the considered informatons were emitted. In the framework of our assumptions, this component is determined by:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          Δ 
        </mi> 
        <msup> 
         <mi>
           θ 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          v 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mo>
            − 
          </mo> 
          <mfrac> 
           <mi>
             r 
           </mi> 
           <mi>
             c 
           </mi> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math></p>
   <p>2) a component 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        Δ 
      </mi> 
      <msup> 
       <mi>
         θ 
       </mi> 
       <mo>
         ″ 
       </mo> 
      </msup> 
     </mrow> 
    </math> related to the acceleration of m<sub>0</sub> at the moment when they were emitted. This component is, in the framework of our assumptions, determined by:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        sin 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          Δ 
        </mi> 
        <msup> 
         <mi>
           θ 
         </mi> 
         <mo>
           ″ 
         </mo> 
        </msup> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          a 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mo>
            − 
          </mo> 
          <mfrac> 
           <mi>
             r 
           </mi> 
           <mi>
             c 
           </mi> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          r 
        </mi> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mi>
        θ 
      </mi> 
     </mrow> 
    </math></p>
   <p>The macroscopic effect of the emission of g-information by the accelerated particle m<sub>0</sub> is a gravitational field ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math>). We introduce the reference system ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         c 
       </mi> 
      </msub> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mrow> 
        <mo>
          ⊥ 
        </mo> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </msub> 
      <mo>
        , 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         φ 
       </mi> 
      </msub> 
     </mrow> 
    </math>) (<xref ref-type="fig" rid="fig1">
     Figure 1
    </xref>).</p>
   <p>1) With N the density of the flow of informatons at P (the rate per unit area at which the informatons cross an elementary surface perpendicular to the direction of their movement), the g-field at that point is</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        N 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math></p>
   <p>According to the postulate of the emission of informatons, the magnitude of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> is the elementary g-information quantity:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         s 
       </mi> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <mi>
          K 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mi>
           η 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mn>
        6.18 
      </mn> 
      <mo>
        × 
      </mo> 
      <msup> 
       <mrow> 
        <mn>
          10 
        </mn> 
       </mrow> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          60 
        </mn> 
       </mrow> 
      </msup> 
      <mtext>
          
      </mtext> 
      <msup> 
       <mtext>
         m 
       </mtext> 
       <mn>
         3 
       </mn> 
      </msup> 
      <mo>
        ⋅ 
      </mo> 
      <msup> 
       <mtext>
         s 
       </mtext> 
       <mrow> 
        <mo>
          − 
        </mo> 
        <mn>
          1 
        </mn> 
       </mrow> 
      </msup> 
     </mrow> 
    </math></p>
   <p>and the density of the flow of informatons at P is:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        N 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mover accent="true"> 
        <mi>
          N 
        </mi> 
        <mo>
          ˙ 
        </mo> 
       </mover> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msubsup> 
         <mi>
           r 
         </mi> 
         <mn>
           0 
         </mn> 
         <mn>
           2 
         </mn> 
        </msubsup> 
       </mrow> 
      </mfrac> 
      <mo>
        ≈ 
      </mo> 
      <mfrac> 
       <mover accent="true"> 
        <mi>
          N 
        </mi> 
        <mo>
          ˙ 
        </mo> 
       </mover> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mi>
          K 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mi>
           m 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>Taking into account that 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mrow> 
        <msub> 
         <mi>
           η 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <msub> 
       <mi>
         ν 
       </mi> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>, we obtain:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mtable columnalign="left"> 
      <mtr> 
       <mtd> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             m 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <mn>
            4 
          </mn> 
          <mi>
            π 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <msub> 
           <mi>
             η 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <msup> 
           <mi>
             r 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            e 
          </mi> 
         </mstyle> 
         <mi>
           c 
         </mi> 
        </msub> 
        <mo>
          − 
        </mo> 
        <mrow> 
         <mo>
           [ 
         </mo> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               m 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
           <mrow> 
            <mn>
              4 
            </mn> 
            <mi>
              π 
            </mi> 
            <mo>
              ⋅ 
            </mo> 
            <msub> 
             <mi>
               η 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
            <mo>
              ⋅ 
            </mo> 
            <mi>
              c 
            </mi> 
            <mo>
              ⋅ 
            </mo> 
            <msup> 
             <mi>
               r 
             </mi> 
             <mn>
               2 
             </mn> 
            </msup> 
           </mrow> 
          </mfrac> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            v 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mo>
              − 
            </mo> 
            <mfrac> 
             <mi>
               r 
             </mi> 
             <mi>
               c 
             </mi> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            sin 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </mrow> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mtext>
            
        </mtext> 
        <mo>
          + 
        </mo> 
        <mrow> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mi>
               ν 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
            <mo>
              ⋅ 
            </mo> 
            <msub> 
             <mi>
               m 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
           <mrow> 
            <mn>
              4 
            </mn> 
            <mi>
              π 
            </mi> 
            <mo>
              ⋅ 
            </mo> 
            <mi>
              r 
            </mi> 
           </mrow> 
          </mfrac> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            a 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mo>
              − 
            </mo> 
            <mfrac> 
             <mi>
               r 
             </mi> 
             <mi>
               c 
             </mi> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            sin 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mo>
           ] 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            e 
          </mi> 
         </mstyle> 
         <mrow> 
          <mo>
            ⊥ 
          </mo> 
          <mi>
            c 
          </mi> 
         </mrow> 
        </msub> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math></p>
   <p>2) 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math>, the g-induction at P, is defined as the density of the cloud of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       β 
     </mi> 
    </math> -information at that point. That density is the product of n, the density of the cloud of informations at P (number per unit volume) with 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         β 
       </mi> 
      </msub> 
     </mrow> 
    </math>, their 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       β 
     </mi> 
    </math>-index:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        n 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         β 
       </mi> 
      </msub> 
     </mrow> 
    </math></p>
   <p>The 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
       β 
     </mi> 
    </math>-index of an informaton refers to the information it carries regarding the state of motion of its emitter; it is defined as:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         β 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           c 
         </mi> 
        </mstyle> 
        <mo>
          × 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            s 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>And n, the density of the cloud of informatons at P, is related to N, the density of the flow of informatons at that point by: 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        n 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         N 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>.</p>
   <p>So:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mi>
        n 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          s 
        </mi> 
       </mstyle> 
       <mi>
         β 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         N 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mfrac> 
       <mrow> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           c 
         </mi> 
        </mstyle> 
        <mo>
          × 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            s 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           c 
         </mi> 
        </mstyle> 
        <mo>
          × 
        </mo> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            N 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <msub> 
           <mstyle mathvariant="bold" mathsize="normal"> 
            <mi>
              s 
            </mi> 
           </mstyle> 
           <mi>
             g 
           </mi> 
          </msub> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           c 
         </mi> 
        </mstyle> 
        <mo>
          × 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>With the expression of that we have derived above under 1 we finally obtain:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mrow> 
       <mo>
         [ 
       </mo> 
       <mrow> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             ν 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <msub> 
           <mi>
             m 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <mn>
            4 
          </mn> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            π 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <msup> 
           <mi>
             r 
           </mi> 
           <mn>
             2 
           </mn> 
          </msup> 
         </mrow> 
        </mfrac> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          v 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mo>
            − 
          </mo> 
          <mfrac> 
           <mi>
             r 
           </mi> 
           <mi>
             c 
           </mi> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          sin 
        </mi> 
        <mi>
          θ 
        </mi> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             ν 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <msub> 
           <mi>
             m 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
         </mrow> 
         <mrow> 
          <mn>
            4 
          </mn> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            π 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            c 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            r 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          a 
        </mi> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mi>
            t 
          </mi> 
          <mo>
            − 
          </mo> 
          <mfrac> 
           <mi>
             r 
           </mi> 
           <mi>
             c 
           </mi> 
          </mfrac> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          sin 
        </mi> 
        <mi>
          θ 
        </mi> 
       </mrow> 
       <mo>
         ] 
       </mo> 
      </mrow> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         φ 
       </mi> 
      </msub> 
     </mrow> 
    </math></p>
   <p>The time dependent components of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> and of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> represent waves traveling with the speed c in the direction of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> <xref ref-type="bibr" rid="scirp.136495-5">
     [5]
    </xref> We say that an accelerated mass particle is the source of a “gravitational wave” 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mrow> 
       <mo>
         { 
       </mo> 
       <mrow> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            E 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
        <mo>
          , 
        </mo> 
        <msub> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            B 
          </mi> 
         </mstyle> 
         <mi>
           g 
         </mi> 
        </msub> 
       </mrow> 
       <mo>
         } 
       </mo> 
      </mrow> 
     </mrow> 
    </math>. Its components are both transverse to 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> and mutually perpendicular.</p>
   <p>From the mathematical expressions derived above it can be concluded that at a point P, sufficient far from the accelerated particle m<sub>0</sub>, the components of the</p>
   <p>wave under consideration are proportional to 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mo> 
      </mo> 
      <mfrac> 
       <mn>
         1 
       </mn> 
       <mi>
         r 
       </mi> 
      </mfrac> 
     </mrow> 
    </math> and they are determined by the</p>
   <p>acceleration of the source at the time the involved informatons were emitted:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          E 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           ν 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mi>
           m 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          r 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           r 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mi>
        θ 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mrow> 
        <mo>
          ⊥ 
        </mo> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math></p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          B 
        </mi> 
       </mstyle> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mo>
        − 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           ν 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <msub> 
         <mi>
           m 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          π 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          c 
        </mi> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          r 
        </mi> 
       </mrow> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        a 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           r 
         </mi> 
         <mi>
           c 
         </mi> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        sin 
      </mi> 
      <mi>
        θ 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         φ 
       </mi> 
      </msub> 
     </mrow> 
    </math></p>
  </sec><sec id="s5">
   <title>5. The Gravitational Field of a Harmonically Oscillating Mass Particle</title>
   <fig id="fig3" position="float">
    <label>Figure 3</label>
    <caption>
     <title>Figure 2. A harmonically oscillating particle.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181125-rId231.jpeg?20241010121057" />
   </fig>
   <p>In <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref>, we consider a mass particle with rest mass m<sub>0</sub> that harmonically oscillates around the origin of the inertial reference frame O with frequency</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        ν 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         ω 
       </mi> 
       <mrow> 
        <mn>
          2 
        </mn> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          π 
        </mi> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math>. Now t it passes at P<sub>1</sub>. We suppose that the speed of the particle described by:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        v 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        V 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        cos 
      </mi> 
      <mi>
        ω 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math></p>
   <p>is always much smaller than the speed of light.</p>
   <p>The elongation z(t) and the acceleration a(t) are then expressed as:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        z 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         V 
       </mi> 
       <mi>
         ω 
       </mi> 
      </mfrac> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        cos 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          ω 
        </mi> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        a 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mi>
         t 
       </mi> 
       <mo>
         ) 
       </mo> 
      </mrow> 
      <mo>
        = 
      </mo> 
      <mi>
        ω 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        V 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mi>
        cos 
      </mi> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          ω 
        </mi> 
        <mi>
          t 
        </mi> 
        <mo>
          + 
        </mo> 
        <mfrac> 
         <mi>
           π 
         </mi> 
         <mn>
           2 
         </mn> 
        </mfrac> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math></p>
   <p>We restrict our considerations about the gravitational field of m<sub>0</sub> to points P that are “far away” from the origin O: we assume that the amplitude of the oscillation is very small relative to the distances between the origin and the points P on which we focus.</p>
   <p>Thus, relative to O, 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         B 
       </mi> 
       <mrow> 
        <mi>
          g 
        </mi> 
        <mi>
          φ 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> and 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mrow> 
        <mi>
          g 
        </mi> 
        <mo>
          ⊥ 
        </mo> 
        <mi>
          c 
        </mi> 
       </mrow> 
      </msub> 
     </mrow> 
    </math> are, according the conclusions of the preceding paragraph, in the “far field” expressed as functions of the space and time coordinates as:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mtable> 
      <mtr> 
       <mtd> 
        <msub> 
         <mi>
           B 
         </mi> 
         <mrow> 
          <mi>
            g 
          </mi> 
          <mi>
            φ 
          </mi> 
         </mrow> 
        </msub> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             E 
           </mi> 
           <mrow> 
            <mi>
              g 
            </mi> 
            <mo>
              ⊥ 
            </mo> 
            <mi>
              c 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mi>
           c 
         </mi> 
        </mfrac> 
        <mo>
          = 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             ν 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            k 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <msub> 
           <mi>
             m 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            V 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            sin 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mrow> 
          <mn>
            4 
          </mn> 
          <mi>
            π 
          </mi> 
          <mi>
            r 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          ⋅ 
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        <mi>
          sin 
        </mi> 
        <mrow> 
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           ( 
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          <mi>
            ω 
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          <mi>
            t 
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          <mo>
            − 
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            k 
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          <mi>
            r 
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         </mrow> 
         <mo>
           ) 
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        </mrow> 
       </mtd> 
      </mtr> 
      <mtr> 
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        <mo>
          = 
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         <mrow> 
          <msub> 
           <mi>
             ν 
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             0 
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          </msub> 
          <mo>
            ⋅ 
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          <msub> 
           <mi>
             m 
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           <mn>
             0 
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            ⋅ 
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          <mi>
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            ⋅ 
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            V 
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            ⋅ 
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            sin 
          </mi> 
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            θ 
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         </mrow> 
         <mrow> 
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            4 
          </mn> 
          <mi>
            π 
          </mi> 
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          </mi> 
          <mi>
            r 
          </mi> 
         </mrow> 
        </mfrac> 
        <mo>
          ⋅ 
        </mo> 
        <mi>
          sin 
        </mi> 
        <mrow> 
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           ( 
         </mo> 
         <mrow> 
          <mi>
            ω 
          </mi> 
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            t 
          </mi> 
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            − 
          </mo> 
          <mi>
            k 
          </mi> 
          <mi>
            r 
          </mi> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mtd> 
      </mtr> 
      <mtr> 
       <mtd> 
        <mo>
          = 
        </mo> 
        <mo>
          − 
        </mo> 
        <mfrac> 
         <mrow> 
          <msub> 
           <mi>
             ν 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <msub> 
           <mi>
             m 
           </mi> 
           <mn>
             0 
           </mn> 
          </msub> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            a 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mi>
              t 
            </mi> 
            <mo>
              − 
            </mo> 
            <mfrac> 
             <mi>
               r 
             </mi> 
             <mi>
               c 
             </mi> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mi>
            sin 
          </mi> 
          <mi>
            θ 
          </mi> 
         </mrow> 
         <mrow> 
          <mn>
            4 
          </mn> 
          <mi>
            π 
          </mi> 
          <mi>
            c 
          </mi> 
          <mi>
            r 
          </mi> 
         </mrow> 
        </mfrac> 
       </mtd> 
      </mtr> 
     </mtable> 
    </math></p>
   <p>With 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        k 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         c 
       </mi> 
       <mi>
         ω 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>.</p>
   <p>So, an harmonically oscillating particle emits a transversal “gravitomagnetic” wave that propagates out of the mass with the speed of light and that in the “far field” is defined by the previous equations.</p>
   <p>The intensity of the “far gravitational field” is inversely proportional to r, and is determined by the component of the acceleration of m<sub>0</sub>, that is perpendicular to the direction of 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          e 
        </mi> 
       </mstyle> 
       <mi>
         c 
       </mi> 
      </msub> 
     </mrow> 
    </math>.</p>
  </sec><sec id="s6">
   <title>6. Gravitational Radiation</title>
   <sec id="s6_1">
    <title>6.1. Poynting Theorem</title>
    <p>In free space the components of a gravitational field are completely defined by the vectoral functions 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           E 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           x 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           y 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           z 
         </mi> 
         <mo>
           ; 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> and 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           B 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           x 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           y 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           z 
         </mi> 
         <mo>
           ; 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>. It can be shown <xref ref-type="bibr" rid="scirp.136495-4">
      [4]
     </xref> <xref ref-type="bibr" rid="scirp.136495-5">
      [5]
     </xref> that the spatial area G enclosed by the surface S—at the moment t—contains an amount of energy given by the expression:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         U 
       </mi> 
       <mo>
         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msub> 
          <mo>
            ∭ 
          </mo> 
          <mi>
            G 
          </mi> 
         </msub> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <msub> 
               <mi>
                 η 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
              <mo>
                ⋅ 
              </mo> 
              <msubsup> 
               <mi>
                 E 
               </mi> 
               <mi>
                 g 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msubsup> 
             </mrow> 
             <mn>
               2 
             </mn> 
            </mfrac> 
            <mo>
              + 
            </mo> 
            <mfrac> 
             <mrow> 
              <msubsup> 
               <mi>
                 B 
               </mi> 
               <mi>
                 g 
               </mi> 
               <mn>
                 2 
               </mn> 
              </msubsup> 
             </mrow> 
             <mrow> 
              <mn>
                2 
              </mn> 
              <msub> 
               <mi>
                 ν 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            V 
          </mi> 
         </mrow> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math></p>
    <p>The rate at which the energy escapes from G is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           U 
         </mi> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mo>
         − 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msub> 
          <mo>
            ∭ 
          </mo> 
          <mi>
            V 
          </mi> 
         </msub> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <msub> 
             <mi>
               η 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
            <mo>
              ⋅ 
            </mo> 
            <msub> 
             <mstyle mathvariant="bold" mathsize="normal"> 
              <mi>
                E 
              </mi> 
             </mstyle> 
             <mi>
               g 
             </mi> 
            </msub> 
            <mo>
              ⋅ 
            </mo> 
            <mfrac> 
             <mrow> 
              <mo>
                ∂ 
              </mo> 
              <msub> 
               <mstyle mathvariant="bold" mathsize="normal"> 
                <mi>
                  E 
                </mi> 
               </mstyle> 
               <mi>
                 g 
               </mi> 
              </msub> 
             </mrow> 
             <mrow> 
              <mo>
                ∂ 
              </mo> 
              <mi>
                t 
              </mi> 
             </mrow> 
            </mfrac> 
            <mo>
              + 
            </mo> 
            <mfrac> 
             <mn>
               1 
             </mn> 
             <mrow> 
              <msub> 
               <mi>
                 ν 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </mfrac> 
            <mo>
              ⋅ 
            </mo> 
            <msub> 
             <mstyle mathvariant="bold" mathsize="normal"> 
              <mi>
                B 
              </mi> 
             </mstyle> 
             <mi>
               g 
             </mi> 
            </msub> 
            <mo>
              ⋅ 
            </mo> 
            <mfrac> 
             <mrow> 
              <mo>
                ∂ 
              </mo> 
              <msub> 
               <mstyle mathvariant="bold" mathsize="normal"> 
                <mi>
                  B 
                </mi> 
               </mstyle> 
               <mi>
                 g 
               </mi> 
              </msub> 
             </mrow> 
             <mrow> 
              <mo>
                ∂ 
              </mo> 
              <mi>
                t 
              </mi> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            V 
          </mi> 
         </mrow> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math></p>
    <p>According to the third law of Maxwell-Heaviside:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         r 
       </mi> 
       <mi>
         o 
       </mi> 
       <mi>
         t 
       </mi> 
       <mtext>
           
       </mtext> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           E 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>and according to the fourth law:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         r 
       </mi> 
       <mi>
         o 
       </mi> 
       <mi>
         t 
       </mi> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          η 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             E 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>So:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           U 
         </mi> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msub> 
          <mo>
            ∭ 
          </mo> 
          <mi>
            G 
          </mi> 
         </msub> 
         <mrow> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <msub> 
               <mstyle mathvariant="bold" mathsize="normal"> 
                <mi>
                  B 
                </mi> 
               </mstyle> 
               <mi>
                 g 
               </mi> 
              </msub> 
             </mrow> 
             <mrow> 
              <msub> 
               <mi>
                 ν 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </mfrac> 
            <mo>
              ⋅ 
            </mo> 
            <mi>
              r 
            </mi> 
            <mi>
              o 
            </mi> 
            <mi>
              t 
            </mi> 
            <mtext>
                
            </mtext> 
            <msub> 
             <mstyle mathvariant="bold" mathsize="normal"> 
              <mi>
                E 
              </mi> 
             </mstyle> 
             <mi>
               g 
             </mi> 
            </msub> 
            <mo>
              − 
            </mo> 
            <msub> 
             <mstyle mathvariant="bold" mathsize="normal"> 
              <mi>
                E 
              </mi> 
             </mstyle> 
             <mi>
               g 
             </mi> 
            </msub> 
            <mo>
              ⋅ 
            </mo> 
            <mi>
              r 
            </mi> 
            <mi>
              o 
            </mi> 
            <mi>
              t 
            </mi> 
            <mfrac> 
             <mrow> 
              <msub> 
               <mstyle mathvariant="bold" mathsize="normal"> 
                <mi>
                  B 
                </mi> 
               </mstyle> 
               <mi>
                 g 
               </mi> 
              </msub> 
             </mrow> 
             <mrow> 
              <msub> 
               <mi>
                 ν 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            V 
          </mi> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msub> 
          <mo>
            ∭ 
          </mo> 
          <mi>
            G 
          </mi> 
         </msub> 
         <mrow> 
          <mi>
            d 
          </mi> 
          <mi>
            i 
          </mi> 
          <mi>
            v 
          </mi> 
          <mrow> 
           <mo>
             ( 
           </mo> 
           <mrow> 
            <mfrac> 
             <mrow> 
              <msub> 
               <mstyle mathvariant="bold" mathsize="normal"> 
                <mi>
                  E 
                </mi> 
               </mstyle> 
               <mi>
                 g 
               </mi> 
              </msub> 
              <mo>
                × 
              </mo> 
              <msub> 
               <mstyle mathvariant="bold" mathsize="normal"> 
                <mi>
                  B 
                </mi> 
               </mstyle> 
               <mi>
                 g 
               </mi> 
              </msub> 
             </mrow> 
             <mrow> 
              <msub> 
               <mi>
                 ν 
               </mi> 
               <mn>
                 0 
               </mn> 
              </msub> 
             </mrow> 
            </mfrac> 
           </mrow> 
           <mo>
             ) 
           </mo> 
          </mrow> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            V 
          </mi> 
         </mrow> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math></p>
    <p>By application of the theorem of Ostrogradsky <xref ref-type="bibr" rid="scirp.136495-9">
      [9]
     </xref>: we can rewrite this as:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mo>
         − 
       </mo> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           U 
         </mi> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           t 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msub> 
          <mo>
            ∯ 
          </mo> 
          <mi>
            S 
          </mi> 
         </msub> 
         <mrow> 
          <mfrac> 
           <mrow> 
            <msub> 
             <mstyle mathvariant="bold" mathsize="normal"> 
              <mi>
                E 
              </mi> 
             </mstyle> 
             <mi>
               g 
             </mi> 
            </msub> 
            <mo>
              × 
            </mo> 
            <msub> 
             <mstyle mathvariant="bold" mathsize="normal"> 
              <mi>
                B 
              </mi> 
             </mstyle> 
             <mi>
               g 
             </mi> 
            </msub> 
           </mrow> 
           <mrow> 
            <msub> 
             <mi>
               ν 
             </mi> 
             <mn>
               0 
             </mn> 
            </msub> 
           </mrow> 
          </mfrac> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             S 
           </mi> 
          </mstyle> 
         </mrow> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math></p>
    <p>from which we can conclude that the expression</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             E 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mo>
           × 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          S 
        </mi> 
       </mstyle> 
      </mrow> 
     </math></p>
    <p>defines the rate at which energy flows in the sense of the positive normal through the surface element dS at a point P in a gravitational field.</p>
    <p>So, the density of the energy flow at P is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             E 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mo>
           × 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>This vectoral quantity is called the “Poynting’s vector”. It is represented by 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
       <mi>
         P 
       </mi> 
      </mstyle> 
     </math>:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          P 
        </mi> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             E 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mo>
           × 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>The amount of energy transported through the surface element dS in the sense of the positive normal during the time interval dt is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         U 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             E 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mo>
           × 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          S 
        </mi> 
       </mstyle> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math></p>
   </sec>
   <sec id="s6_2">
    <title>6.2. The Energy Radiated by a Harmonically Oscillating Particle—Gravitons</title>
    <p>In §5 it is shown that a harmonically oscillating point mass m<sub>0</sub> radiates a gravitational wave that at a far point Q is defined by (<xref ref-type="fig" rid="fig2">
      Figure 2
     </xref>):</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           E 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          E 
        </mi> 
        <mrow> 
         <mi>
           g 
         </mi> 
         <mo>
           ⊥ 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           e 
         </mi> 
        </mstyle> 
        <mrow> 
         <mo>
           ⊥ 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           V 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           sin 
         </mi> 
         <mi>
           θ 
         </mi> 
        </mrow> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         sin 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           ω 
         </mi> 
         <mi>
           t 
         </mi> 
         <mo>
           − 
         </mo> 
         <mi>
           k 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           e 
         </mi> 
        </mstyle> 
        <mrow> 
         <mo>
           ⊥ 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math></p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           B 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          B 
        </mi> 
        <mrow> 
         <mi>
           g 
         </mi> 
         <mi>
           φ 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           e 
         </mi> 
        </mstyle> 
        <mi>
          φ 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           ω 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           V 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           sin 
         </mi> 
         <mi>
           θ 
         </mi> 
        </mrow> 
        <mrow> 
         <mn>
           4 
         </mn> 
         <mi>
           π 
         </mi> 
         <mi>
           c 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         sin 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           ω 
         </mi> 
         <mi>
           t 
         </mi> 
         <mo>
           − 
         </mo> 
         <mi>
           k 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           e 
         </mi> 
        </mstyle> 
        <mi>
          φ 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>And in §4 it is shown that the amount of energy transported by a gravitational wave ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           E 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           B 
         </mi> 
        </mstyle> 
        <mi>
          g 
        </mi> 
       </msub> 
      </mrow> 
     </math>) during a time interval dt through a surface element dS in the sense of the positive normal is</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         U 
       </mi> 
       <mo>
         = 
       </mo> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          P 
        </mi> 
       </mstyle> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          S 
        </mi> 
       </mstyle> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mi>
         t 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             E 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
         <mo>
           × 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             B 
           </mi> 
          </mstyle> 
          <mi>
            g 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          S 
        </mi> 
       </mstyle> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mi>
         t 
       </mi> 
      </mrow> 
     </math></p>
    <p>At a point P in the far gravitational field of a harmonically oscillating mass particle m<sub>0</sub>, the instantaneous value of Poynting’s vector at P is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          P 
        </mi> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            ω 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            V 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mi>
             sin 
           </mi> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mi>
           θ 
         </mi> 
        </mrow> 
        <mrow> 
         <mn>
           16 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            π 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           c 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            r 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mrow> 
         <mi>
           sin 
         </mi> 
        </mrow> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           ω 
         </mi> 
         <mi>
           t 
         </mi> 
         <mo>
           − 
         </mo> 
         <mi>
           k 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           e 
         </mi> 
        </mstyle> 
        <mi>
          c 
        </mi> 
       </msub> 
      </mrow> 
     </math></p>
    <p>The amount of energy that, during one period T, flows through the surface element dS that at P is perpendicular to the direction of the movement of the informatons, is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         U 
       </mi> 
       <mo>
         = 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msubsup> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mi>
            T 
          </mi> 
         </msubsup> 
         <mrow> 
          <mi>
            P 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            t 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            S 
          </mi> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            ω 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            V 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mi>
             sin 
           </mi> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mi>
           θ 
         </mi> 
        </mrow> 
        <mrow> 
         <mn>
           16 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            π 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           c 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            r 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mi>
          T 
        </mi> 
        <mn>
          2 
        </mn> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mi>
         S 
       </mi> 
      </mrow> 
     </math></p>
    <p>And, with 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         ω 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           π 
         </mi> 
        </mrow> 
        <mi>
          T 
        </mi> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         2 
       </mn> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         π 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math>:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         d 
       </mtext> 
       <mi>
         U 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            V 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mi>
             sin 
           </mi> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mi>
           θ 
         </mi> 
        </mrow> 
        <mrow> 
         <mn>
           8 
         </mn> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <mtext>
           d 
         </mtext> 
         <mi>
           S 
         </mi> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            r 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math></p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <mtext>
           d 
         </mtext> 
         <mi>
           S 
         </mi> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            r 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mtext>
         d 
       </mtext> 
       <mi>
         Ω 
       </mi> 
      </mrow> 
     </math> is the solid angle under which dS is “seen” from the origin. So, the oscillating mass particle radiates per unit of solid angle in the direction 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        θ 
      </mi> 
     </math>, per period, an amount of energy 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          Ω 
        </mi> 
       </msub> 
      </mrow> 
     </math>:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          u 
        </mi> 
        <mi>
          Ω 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            V 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mrow> 
           <mi>
             sin 
           </mi> 
          </mrow> 
          <mn>
            2 
          </mn> 
         </msup> 
         <mi>
           θ 
         </mi> 
        </mrow> 
        <mrow> 
         <mn>
           8 
         </mn> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math></p>
    <p>This quantity is greatest in the direction perpendicular to the movement of the particle ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         θ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         90 
       </mn> 
       <mo>
         ˚ 
       </mo> 
      </mrow> 
     </math>) and it is proportional to the frequency of the wave, thus proportional to the frequency at which the particle is oscillating.</p>
    <p>It follows that the amount of energy radiated per period by the oscillating particle is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          U 
        </mi> 
        <mi>
          T 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mn>
           2 
         </mn> 
         <mi>
           π 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            V 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           8 
         </mn> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <mstyle displaystyle="true"> 
        <mrow> 
         <msubsup> 
          <mo>
            ∫ 
          </mo> 
          <mn>
            0 
          </mn> 
          <mi>
            π 
          </mi> 
         </msubsup> 
         <mrow> 
          <msup> 
           <mrow> 
            <mi>
              sin 
            </mi> 
           </mrow> 
           <mn>
             3 
           </mn> 
          </msup> 
          <mi>
            θ 
          </mi> 
          <mo>
            ⋅ 
          </mo> 
          <mtext>
            d 
          </mtext> 
          <mi>
            θ 
          </mi> 
         </mrow> 
        </mrow> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mi>
           π 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mi>
            V 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
        <mrow> 
         <mn>
           3 
         </mn> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math> (7)</p>
    <p>
     <xref ref-type="bibr" rid="scirp.136495-"></xref>We posit that the energy radiated by an oscillating mass particle travels through space in the form of particle-like packets of energy, called “gravitons” and that the energy 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          U 
        </mi> 
        <mi>
          g 
        </mi> 
       </msub> 
      </mrow> 
     </math> transported by a graviton is proportional to the frequency of the oscillator, so:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          U 
        </mi> 
        <mi>
          g 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msup> 
        <mi>
          h 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math> (8)</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
       <mi>
         h 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </math> plays the role of Planck’s constant <xref ref-type="bibr" rid="scirp.136495-10">
      [10]
     </xref> in electromagnetism. Thus, a graviton can be understood as an informaton transporting a quantum of energy 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          h 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math>. From (7) and (8), it follows that the number of gravitons emitted per period by an oscillating particle with rest mass m<sub>0</sub> is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mrow> 
         <mi>
           g 
         </mi> 
         <mi>
           T 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            U 
          </mi> 
          <mi>
            T 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            h 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           ν 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mo> 
       </mo> 
       <mfrac> 
        <mi>
          π 
        </mi> 
        <mn>
          3 
        </mn> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            h 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <msubsup> 
        <mi>
          m 
        </mi> 
        <mn>
          0 
        </mn> 
        <mn>
          2 
        </mn> 
       </msubsup> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mi>
          V 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math></p>
    <p>If the particle would be carrier of an electric charge q, it would also be a source of photons: informatons transporting a quantum of energy 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         h 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math>. On the basis of the analogy between gravitational and electromagnetic fields <xref ref-type="bibr" rid="scirp.136495-2">
      [2]
     </xref> we can conclude that the number of photons emitted per period by a point charge q is:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mi>
           T 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mi>
          π 
        </mi> 
        <mn>
          3 
        </mn> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            μ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <mi>
           h 
         </mi> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           c 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mi>
          q 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mi>
          V 
        </mi> 
        <mn>
          2 
        </mn> 
       </msup> 
      </mrow> 
     </math></p>
    <p>It is reasonable to assume that it are the same informatons that at the moment of their emission will be charged with a graviton and a photon, what implies that:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mrow> 
         <mi>
           f 
         </mi> 
         <mi>
           T 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mo> 
       </mo> 
       <msub> 
        <mi>
          N 
        </mi> 
        <mrow> 
         <mi>
           g 
         </mi> 
         <mi>
           T 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math></p>
    <p>It follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          h 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ν 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            μ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            q 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         h 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            ϵ 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            η 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            q 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         h 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         7.43 
       </mn> 
       <mo>
         × 
       </mo> 
       <msup> 
        <mrow> 
         <mn>
           10 
         </mn> 
        </mrow> 
        <mrow> 
         <mo>
           − 
         </mo> 
         <mn>
           21 
         </mn> 
        </mrow> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <mfrac> 
        <mrow> 
         <msubsup> 
          <mi>
            m 
          </mi> 
          <mn>
            0 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
        </mrow> 
        <mrow> 
         <msup> 
          <mi>
            q 
          </mi> 
          <mn>
            2 
          </mn> 
         </msup> 
        </mrow> 
       </mfrac> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         h 
       </mi> 
      </mrow> 
     </math></p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
       <mi>
         h 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </math> is, in contrast to h, dependent on the ratio mass/charge of the emitter if it, as in the case of a proton and an electron, is electrically charged. If the emitter is neutral, as in the case of a neutron, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <msup> 
       <mi>
         h 
       </mi> 
       <mo>
         ′ 
       </mo> 
      </msup> 
     </math> depends on the ratio mass/charge of the electrically charged particle with the same rest mass as the emitter.</p>
    <p>( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msup> 
        <mi>
          h 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math>), the quantum of energy transported by a graviton, is in any case negligibly small compared to ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         h 
       </mi> 
       <mo>
         ⋅ 
       </mo> 
       <mi>
         ν 
       </mi> 
      </mrow> 
     </math>), the quantum of energy transported by a photon emitted by an oscillator with the same frequency. This makes it impossible to observe gravitons that are emitted by electrically charged bodies: in that case the presence of gravitons leads to an insignificant fluctuation of the energy quantum of the photons. We can still note that the quantum of energy transported by gravitons that are emitted by electrons is negligibly small compared to the quantum of energy transported by gravitons that are emitted by protons and neutrons.</p>
   </sec>
  </sec><sec id="s7">
   <title>7. Gravitational Wave Emitted by an Object with Variable Rest Mass</title>
   <p>Another phenomenon that is the source of a gravitational wave is the conversion of rest mass into energy (what per example happens in the case of radioactive processes). To illustrate this, let us—relative to an inertial reference frame—consider a particle with rest mass m<sub>0</sub> that—due to intern instability—during the period (0, Δt) emits EM radiation.</p>
   <p>This implies that that particle during that time interval is emitting electromagnetic energy U<sub>EM</sub> carried by photons (and gravitational energy U<sub>GEM</sub><sup>2</sup> carried by gravitons) that propagate with the speed of light. Between the moment t = 0 and the moment t = Δt, the rest mass of the particle is, because of this event, decreasing</p>
   <p>with an amount 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           U 
         </mi> 
         <mrow> 
          <mi>
            E 
          </mi> 
          <mi>
            M 
          </mi> 
         </mrow> 
        </msub> 
        <mrow> 
         <mo>
           ( 
         </mo> 
         <mrow> 
          <mo>
            + 
          </mo> 
          <msub> 
           <mi>
             U 
           </mi> 
           <mrow> 
            <mi>
              G 
            </mi> 
            <mi>
              E 
            </mi> 
            <mi>
              M 
            </mi> 
           </mrow> 
          </msub> 
         </mrow> 
         <mo>
           ) 
         </mo> 
        </mrow> 
       </mrow> 
       <mrow> 
        <msup> 
         <mi>
           c 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math> from the value m<sub>0</sub> to the value 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          m 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>. Because the</p>
   <p>gravitational field is determined by the rest mass, this implies that if t &lt; 0 the source of the gravitational field of the particle is m<sub>0</sub> and if t &gt; Δt it is 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          m 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>. It follows that at the moment t the gravitational field at a point P at a distance r &gt; c.t is proportional to m<sub>0</sub>, and at a point at a distance 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        r 
      </mi> 
      <mo>
        &lt; 
      </mo> 
      <mi>
        c 
      </mi> 
      <mo>
        ⋅ 
      </mo> 
      <mrow> 
       <mo>
         ( 
       </mo> 
       <mrow> 
        <mi>
          t 
        </mi> 
        <mo>
          − 
        </mo> 
        <mi>
          Δ 
        </mi> 
        <mi>
          t 
        </mi> 
       </mrow> 
       <mo>
         ) 
       </mo> 
      </mrow> 
     </mrow> 
    </math> to 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          m 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>.</p>
   <p>During the period (t, t + Δt) the gravitational field at a point at a distance r = c.t changes from the situation where it is determined by m<sub>0</sub> to the situation where it is determined by 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          m 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>. So, the conversion of rest mass of an object into radiation is the cause of a kink in the gravitational field of that object, a kink that with the speed of light—together with the emitted radiation—propagates out of the object.</p>
   <p>We can conclude that the conversion of (a part of) the rest mass of an object into radiation goes along with the emission by that object of a gravitational wave.</p>
   <p>The effect of the decrease—during the time interval (0, Δt)—of the rest mass of a point mass on the magnitude of its g-field E<sub>g</sub> at the point P at a distance r is shown in the plot of <xref ref-type="fig" rid="fig3">
     Figure 3
    </xref>.</p>
   <fig id="fig4" position="float">
    <label>Figure 4</label>
    <caption>
     <title>Figure 3. Gravitational wave emitted by an object with variable mass.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/2181125-rId338.jpeg?20241010121058" />
   </fig>
   <p>1) Until the moment 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         r 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>, the effect of the conversion of rest mass into radiation has not yet reached P. So, during the period ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mn>
        0 
      </mn> 
      <mo>
        , 
      </mo> 
      <mfrac> 
       <mi>
         r 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
     </mrow> 
    </math>) the quantity of</p>
   <p>mass-energy enclosed by an hypothetical sphere with radius r centered on the particle is still m<sub>0</sub> (the remaining part of the rest mass + all the radiation that during the mentioned period has arisen from the conversion of rest mass). From the first GEM equation it follows:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <mi>
           m 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <msub> 
         <mi>
           η 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>2) From the moment 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mi>
        t 
      </mi> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mi>
         r 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>, the radiation generated by the conversion of</p>
   <p>rest mass has left the space enclosed by the hypothetical sphere with radius r, that from that moment only contains the remaining rest mass 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <msup> 
        <mi>
          m 
        </mi> 
        <mo>
          ′ 
        </mo> 
       </msup> 
       <mn>
         0 
       </mn> 
      </msub> 
     </mrow> 
    </math>. From the first GEM equation it follows:</p>
   <p>
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         g 
       </mi> 
      </msub> 
      <mo>
        = 
      </mo> 
      <mfrac> 
       <mrow> 
        <msub> 
         <msup> 
          <mi>
            m 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
         <mn>
           0 
         </mn> 
        </msub> 
       </mrow> 
       <mrow> 
        <mn>
          4 
        </mn> 
        <mi>
          π 
        </mi> 
        <msub> 
         <mi>
           η 
         </mi> 
         <mn>
           0 
         </mn> 
        </msub> 
        <mo>
          ⋅ 
        </mo> 
        <msup> 
         <mi>
           r 
         </mi> 
         <mn>
           2 
         </mn> 
        </msup> 
       </mrow> 
      </mfrac> 
     </mrow> 
    </math></p>
   <p>3) During the time interval ( 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <mfrac> 
       <mi>
         r 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        , 
      </mo> 
      <mfrac> 
       <mi>
         r 
       </mi> 
       <mi>
         c 
       </mi> 
      </mfrac> 
      <mo>
        + 
      </mo> 
      <mi>
        Δ 
      </mi> 
      <mi>
        t 
      </mi> 
     </mrow> 
    </math>), the mass-energy enclosed by the</p>
   <p>hypothetical sphere with radius r is decreasing (not necessary linearly) because mass-energy flows out in the form of radiation. So, during that period 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
      <msub> 
       <mi>
         E 
       </mi> 
       <mi>
         g 
       </mi> 
      </msub> 
     </mrow> 
    </math> at P is decreasing.</p>
  </sec><sec id="s8">
   <title>8. Conclusion</title>
   <p>The existence of gravitational or gravitomagnetic waves is embedded in the GEM description of gravity. According to the theory of informatons a gravitational wave propagating outward from an oscillating mass particle at the speed of light is the macroscopic manifestation of the fact that the “train” of informatons emitted by that source is a spatial sequence of informatons whose characteristic angle is harmonically fluctuating along the “train” what implies that the component of their g-index perpendicular to their velocity 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
      <mi>
        c 
      </mi> 
     </mstyle> 
    </math> and their β-index fluctuate in space.</p>
  </sec><sec id="s9">
   <title>NOTES</title>
   <p><sup>1</sup>Both terms refer to the same phenomenon.</p>
   <p><sup>2</sup>Negligible in first approximation.</p>
  </sec>
 </body><back>
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