<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd">
<article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article">
 <front>
  <journal-meta>
   <journal-id journal-id-type="publisher-id">
    jemaa
   </journal-id>
   <journal-title-group>
    <journal-title>
     Journal of Electromagnetic Analysis and Applications
    </journal-title>
   </journal-title-group>
   <issn pub-type="epub">
    1942-0730
   </issn>
   <issn publication-format="print">
    1942-0749
   </issn>
   <publisher>
    <publisher-name>
     Scientific Research Publishing
    </publisher-name>
   </publisher>
  </journal-meta>
  <article-meta>
   <article-id pub-id-type="doi">
    10.4236/jemaa.2024.166006
   </article-id>
   <article-id pub-id-type="publisher-id">
    jemaa-134878
   </article-id>
   <article-categories>
    <subj-group subj-group-type="heading">
     <subject>
      Articles
     </subject>
    </subj-group>
    <subj-group subj-group-type="Discipline-v2">
     <subject>
      Engineering, Physics 
     </subject>
     <subject>
       Mathematics
     </subject>
    </subj-group>
   </article-categories>
   <title-group>
    Depolarization Degree to Determine Dihedral Attribute of Radar Target
   </title-group>
   <contrib-group>
    <contrib contrib-type="author" xlink:type="simple">
     <name name-style="western">
      <surname>
       Faisal
      </surname>
      <given-names>
       Aldhubaib
      </given-names>
     </name>
    </contrib>
   </contrib-group> 
   <aff id="affnull">
    <addr-line>
     aElectronics Department, Faculty of Technological Studies, Public Authority for Applied Education, Shuwaikh, Kuwait
    </addr-line> 
   </aff> 
   <pub-date pub-type="epub">
    <day>
     30
    </day> 
    <month>
     06
    </month>
    <year>
     2024
    </year>
   </pub-date> 
   <volume>
    16
   </volume> 
   <issue>
    06
   </issue>
   <fpage>
    85
   </fpage>
   <lpage>
    101
   </lpage>
   <history>
    <date date-type="received">
     <day>
      15,
     </day>
     <month>
      November
     </month>
     <year>
      2023
     </year>
    </date>
    <date date-type="published">
     <day>
      26,
     </day>
     <month>
      November
     </month>
     <year>
      2023
     </year> 
    </date> 
    <date date-type="accepted">
     <day>
      26,
     </day>
     <month>
      July
     </month>
     <year>
      2024
     </year> 
    </date>
   </history>
   <permissions>
    <copyright-statement>
     © Copyright 2014 by authors and Scientific Research Publishing Inc. 
    </copyright-statement>
    <copyright-year>
     2014
    </copyright-year>
    <license>
     <license-p>
      This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/
     </license-p>
    </license>
   </permissions>
   <abstract>
    This paper investigates the ability of the depolarization degree, derived from the characteristic polarization states at the resonant frequency set, to identify corner or swept, i.e. dihedral, changes in same-class targets by a metallic wire example. A well-estimated depolarization degree requires a robust extraction of the fundamental target resonance set in two orthogonal sets of fully co-polarized and cross-polarized polarization channels, then finding the null polarization states using the Lagrangian method. Such depolarization degree per resonance mode has the potential to form a robust feature set because it is relatively less sensitive to onset ambiguity, invariant to rotation, and could create a compact, recognizable, and separable distribution in the proposed feature space. The study was limited to two targets with two swept changes of fifteen degrees within normal incidence; under a supervised learning approach, the results showed that the identification rate converging to upper-bound (100%) for a signal-to-noise ratio above 20 dB and lower-bound around (50%) below −10 dB.
   </abstract>
   <kwd-group> 
    <kwd>
     Polarimetry
    </kwd> 
    <kwd>
      Radar Target Recognition
    </kwd> 
    <kwd>
      Time-Domain Analysis
    </kwd> 
    <kwd>
      Remote Sensing
    </kwd>
   </kwd-group>
  </article-meta>
 </front>
 <body>
  <sec id="s1">
   <title>1. Introduction</title>
   <p>In automatic target recognition applications, a radar system operating at the target optic region may use radar signature models, such as range profile <xref ref-type="bibr" rid="scirp.134878-1">
     [1]
    </xref>-<xref ref-type="bibr" rid="scirp.134878-3">
     [3]
    </xref>, cross-range (imaging) <xref ref-type="bibr" rid="scirp.134878-4">
     [4]
    </xref>-<xref ref-type="bibr" rid="scirp.134878-6">
     [6]
    </xref>, and micro-Doppler shifts analysis <xref ref-type="bibr" rid="scirp.134878-7">
     [7]
    </xref> <xref ref-type="bibr" rid="scirp.134878-8">
     [8]
    </xref>. Nevertheless, this comes at higher complexity and computation costs. On the contrary, a radar system operating at the target fundamental resonance region may apply less complex techniques, such as the complex natural resonance (CNR) signature <xref ref-type="bibr" rid="scirp.134878-9">
     [9]
    </xref>-<xref ref-type="bibr" rid="scirp.134878-12">
     [12]
    </xref>, capable of recognizing the radar target class and even the target type when combined with the shape attributes found in the characteristic polarization states (CPSs) <xref ref-type="bibr" rid="scirp.134878-13">
     [13]
    </xref>-<xref ref-type="bibr" rid="scirp.134878-16">
     [16]
    </xref>.</p>
   <p>According to the singularity expansion model (SEM) of a transient response, a series of resonance modes with a set of natural frequencies, damping factor, and residue could resemble the late-time transient portion of a pulsed radar return covering the target fundamental resonance region. The resonant frequency, which is excitation-independent, instills information about the size of the elementary structures; the damping factor is excitation-independent and reflects the material composition. Subsequently, the resonant frequency and damping factor form the first layer in the recognition process to classify or categorize the targets into the same class when the targets have similar dimensions and composition, e.g. mid-sized jetfighters.</p>
   <p>In contrast, the residue is excitation-dependent and reflects the mode peak strength, thus used to construct the polarization scattering matrix required to derive the CPS set. Hence, recognizing the target type within the same class requires incorporating shape attributes from the CPS in the decision-making process of the recognition operation <xref ref-type="bibr" rid="scirp.134878-10">
     [10]
    </xref>. Interestingly, the CPS of a higher fundamental mode has the potential to provide better information about the dihedral or swept degree between joint parts of the target as the electrical interaction between joint target structures increases with a higher resonant frequency.</p>
   <p>The CPS set represents the polarization states of reception at which maximum, minimum, or null reception exists in the co-polarized and cross-polarized directions, such that there will be four co-polarized states for a reception: two co-polarized maximums and two co-polarized nulls. Henceforth, evaluated at the target resonant frequency, the co-polarized set of the CPS should be able to unfold the crude degrees of symmetry, depolarization, and tilt in the target substructures along the incidence plane, for targets of similar axes of symmetry, such a symmetry feature becomes redundant for recognition. Meanwhile, the tilt degree associated with a single mode is a variant feature that depends on target rotation in the incidence plane.</p>
   <p>On the contrary, the depolarization degree is invariant to the target rotation within the incidence plane and reflects the dihedral degree in corner structures. However, the accuracy or uncertainty in the estimated depolarization set depends on the accuracy of the extracted resonance signature, which usually degrades with ambiguities in the signature modal order and late time onset, plus noise and low resonant to specular return. Therefore, a constraint must apply to how well the estimated resonance signature resembles the original late-time response (quantified by the modal order and variance merit, as explained later) and how this affects the ability of feature samples to form recognizable and separable patterns in the feature space <xref ref-type="bibr" rid="scirp.134878-17">
     [17]
    </xref>-<xref ref-type="bibr" rid="scirp.134878-20">
     [20]
    </xref>.</p>
   <p>Previously, in <xref ref-type="bibr" rid="scirp.134878-12">
     [12]
    </xref>, the author used a feature space of depolarization and tilt degrees per resonance mode to identify swept changes in a generic aircraft target model within a ten degrees azimuthal sector and achieved a recognition performance of 85% - 100% from −10 to +15 dB. Instead, the present work will attempt to verify the capability of depolarization degree only to identify swept changes of fifteen degrees in a wire target model. The identification method uses a supervised learning approach under noise variations with a weight distance measure metric (depending on the substructure dimension as a fraction of the whole target) to select the most discriminative modes from the target’s radar response. The approach could achieve full recognition at a signal-to-noise ratio (SNR) beyond 20 dB for a normal incidence when the specular return and onset ambiguity are at the high end.</p>
   <p>The paper’s outline is as follows: Sections 2 and 3 outline the mathematical background of the CNR signature, the null polarization states, and the identification algorithm. Section 4 shows the results of the rate of correct (ROC) identification results, and finally, Section 5 reaches conclusions and points out the direction of further studies.</p>
  </sec><sec id="s2">
   <title>
    <xref ref-type="bibr" rid="scirp.134878-"></xref>2. Background</title>
   <sec id="s2_1">
    <title>
     <xref ref-type="bibr" rid="scirp.134878-"></xref>2.1. The SEM Signature</title>
    <p>Due to a wideband pulse incident covering the fundamental resonance region of the radar target under examination, the SEM theory approximates the transient oscillatory response of the original signal, which begins after some late-time onset, T<sub>L</sub>, as a sum of exponentially decaying sinusoids, expressed as y(t):</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         y 
       </mi> 
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        </mo> 
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          </mi> 
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       </mo> 
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        </mo> 
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          </mi> 
          <mi>
            m 
          </mi> 
         </msub> 
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           t 
         </mi> 
         <mo>
           + 
         </mo> 
         <mi>
           arg 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              c 
            </mi> 
            <mi>
              m 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (1)</p>
    <p>The parameter M defines the modal order of the signature (by default, set it equal to the number of cardinal target substructures); c<sub>m</sub> defines the complex residues; δ<sub>m</sub> defines the damping factor; ω<sub>m</sub> defines the angular resonant frequencies. Notably, the residue and damping factors are essential parameters used to estimate the energy of the resonance. As a rule of thumb, the late-time onset commences after the incident wave transits the farthest tip of the target along the incident plane. The farthest tip appears as the farthest pulse peak in the return response and before the commencement of the oscillatory return (see Equation (2) in <xref ref-type="bibr" rid="scirp.134878-12">
      [12]
     </xref>). Another way is to take the reciprocal of the first fundamental frequency (if well excited) and add the pulse width duration.</p>
    <p>The matrix pencil of function (MPOF) algorithm may be used to extract and estimate the three resonance parameters in two steps: first, the solution of an ill-conditioned matrix of y(t) formed by delays of y(t) and then find the roots of a polynomial by the singular value decomposition (SVD) <xref ref-type="bibr" rid="scirp.134878-21">
      [21]
     </xref>.</p>
    <p>The variance amplitude figure (VAF) metric quantifies the degree of uncertainty in the estimated resonance set by measuring the similarity of the approximated signal, y(t), to the original signal, x (t &gt; T<sub>L</sub>), after the selected onset, T<sub>L</sub> <xref ref-type="bibr" rid="scirp.134878-22">
      [22]
     </xref>.</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         VAF 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mn>
         100 
       </mn> 
       <mo>
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       </mo> 
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             var 
           </mi> 
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         </mfrac> 
        </mrow> 
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          ) 
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       </mrow> 
      </mrow> 
     </math> (2)</p>
    <p>The “var” defines the variance.</p>
    <p>Henceforth, the signature signal y(t) must fulfill two constraints to derive a reliable CPS set: have consistent M and sufficient VAF merit in all polarization channels.</p>
   </sec>
   <sec id="s2_2">
    <title>2.2. The Characteristic Polarization States (CPSs)</title>
    <p>For quad-polarization directions, the backscattered responses in orthogonal linear basis (h, v) of transmission and reception directions form a real-time dependent matrix S<sup>2</sup> <sup>×</sup> <sup>2</sup> as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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              </mo> 
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          ] 
        </mo> 
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      </mrow> 
     </math> (3)</p>
    <p>The subscripts hh and vv denote the co-polarized scattering directions or channels, while hv and vh denote the cross-polarized scattering channels (reciprocal for monostatic case). Since the resonance residue is the only polarization-dependent term, a reside polarization scattering matrix (RPSM), namely C<sup>2</sup> <sup>×</sup> <sup>2</sup>, can thus describe the target polarization scattering at a single resonance by dropping the time dependence term, i.e. 
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     </math>, as follows:</p>
    <p>
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     </math> (4)</p>
    <p>Therefore, constructing the RPSM requires that the associated residue of this resonance be extractable from the temporal response by the MPOF in all polarization channels.</p>
    <p>On reception, the signal is split into co- and cross-polarized channels, with the power at the antenna terminals established separately for each channel. The complex residues, c<sub>hh</sub>, and c<sub>vv</sub>, denote the co-polarized scattering coefficients, with c<sub>yx</sub> and c<sub>xy</sub> denoting the cross-polarized scattering coefficients, and are equal for the reciprocal (monostatic) case. The constraint of having consistent modal order in the matrix means that the co- and cross-polarized terms must have the same modal order, i.e. 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
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     </math> for every extraction trial.</p>
    <p>Next, the related power in the co-polarized channels is a function of the antenna polarization state, represented by Stokes vector g, as follows:</p>
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        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mstyle mathvariant="bold" mathsize="normal"> 
          <mi>
            R 
          </mi> 
         </mstyle> 
         <mo>
           ⋅ 
         </mo> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <mrow> 
            <mo>
              [ 
            </mo> 
            <mstyle mathvariant="bold" mathsize="normal"> 
             <mi>
               C 
             </mi> 
            </mstyle> 
            <mo>
              ] 
            </mo> 
           </mrow> 
           <mtext>
             U 
           </mtext> 
           <msup> 
            <mrow> 
             <mrow> 
              <mo>
                [ 
              </mo> 
              <mstyle mathvariant="bold" mathsize="normal"> 
               <mi>
                 C 
               </mi> 
              </mstyle> 
              <mo>
                ] 
              </mo> 
             </mrow> 
            </mrow> 
            <mo>
              * 
            </mo> 
           </msup> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           ⋅ 
         </mo> 
         <msup> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             R 
           </mi> 
          </mstyle> 
          <mrow> 
           <mo>
             − 
           </mo> 
           <mn>
             1 
           </mn> 
          </mrow> 
         </msup> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         ⋅ 
       </mo> 
       <msup> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           g 
         </mi> 
        </mstyle> 
        <mtext>
          T 
        </mtext> 
       </msup> 
      </mrow> 
     </math> (5)</p>
    <p>where 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          R 
        </mi> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mtable> 
          <mtr> 
           <mtd> 
            <mn>
              1 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              1 
            </mn> 
           </mtd> 
          </mtr> 
          <mtr> 
           <mtd> 
            <mn>
              1 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </mtd> 
          </mtr> 
          <mtr> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              1 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              1 
            </mn> 
           </mtd> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
          </mtr> 
          <mtr> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
           <mtd> 
            <mi>
              j 
            </mi> 
           </mtd> 
           <mtd> 
            <mrow> 
             <mo>
               − 
             </mo> 
             <mi>
               j 
             </mi> 
            </mrow> 
           </mtd> 
           <mtd> 
            <mn>
              0 
            </mn> 
           </mtd> 
          </mtr> 
         </mtable> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, the Stokes vector 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          g 
        </mi> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            0 
          </mn> 
         </msub> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            2 
          </mn> 
         </msub> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            3 
          </mn> 
         </msub> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> defines the antenna’s polarization state in terms of g<sub>0</sub> as total, g<sub>1</sub> as linear h-v, g<sub>2</sub> as linear at ±45˚, and g<sub>3</sub> as circular power portions, respectively. The product ([C] 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mo>
        ⊗ 
      </mo> 
     </math> [C]<sup>*</sup>) defines the Kronecker product of matrix C and its conjugate. Applying the Lagrangian multiplier method to the power function in (5) subject to the constraint function ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Φ 
       </mi> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            2 
          </mn> 
         </msub> 
         <mo>
           , 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mn>
            3 
          </mn> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msqrt> 
        <mrow> 
         <msubsup> 
          <mi>
            g 
          </mi> 
          <mn>
            1 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           + 
         </mo> 
         <msubsup> 
          <mi>
            g 
          </mi> 
          <mn>
            2 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
         <mo>
           + 
         </mo> 
         <msubsup> 
          <mi>
            g 
          </mi> 
          <mn>
            3 
          </mn> 
          <mn>
            2 
          </mn> 
         </msubsup> 
        </mrow> 
       </msqrt> 
       <mo>
         − 
       </mo> 
       <msub> 
        <mi>
          g 
        </mi> 
        <mn>
          0 
        </mn> 
       </msub> 
      </mrow> 
     </math>) to optimize the received power yield the following three simultaneous equations:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           P 
         </mi> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mi>
            n 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         − 
       </mo> 
       <mi>
         μ 
       </mi> 
       <mfrac> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <mi>
           Φ 
         </mi> 
        </mrow> 
        <mrow> 
         <mo>
           ∂ 
         </mo> 
         <msub> 
          <mi>
            g 
          </mi> 
          <mi>
            n 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         , 
       </mo> 
       <mtext>
           
       </mtext> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         1 
       </mn> 
       <mo>
         , 
       </mo> 
       <mn>
         2 
       </mn> 
       <mo>
         , 
       </mo> 
       <mn>
         3. 
       </mn> 
      </mrow> 
     </math> (6)</p>
    <p>
     <xref ref-type="bibr" rid="scirp.134878-"></xref>where, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        μ 
      </mi> 
     </math> is the Lagrangian multiplier, which optimizes the power quantity rate of change as a function of the constraint variables. Solving (6) produces two pairs of co-polarized CPS, the orthogonal co-pol max pair (cm<sub>1,</sub> <sub>2</sub>)and the co-pol null pair (cn<sub>1,</sub> <sub>2</sub>), which engulf the copol max of minor power, forming a polarization fork around a great circle, as depicted in <xref ref-type="fig" rid="fig1">
      Figure 1
     </xref>. The variableg<sub>3</sub> of the major co-pol max reflects the symmetry (0 for the symmetrical target, ±1 for the nonsymmetrical target). The co-pol null pair set is not orthogonal but defines a characteristic anglerelated to the depolarization degree, γ, as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         γ 
       </mi> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <mtext>
           dot 
         </mtext> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mstyle mathvariant="bold" mathsize="normal"> 
             <mi>
               g 
             </mi> 
            </mstyle> 
            <mrow> 
             <mtext>
               cn 
             </mtext> 
             <mn>
               1 
             </mn> 
            </mrow> 
           </msub> 
           <mo>
             , 
           </mo> 
           <msub> 
            <mstyle mathvariant="bold" mathsize="normal"> 
             <mi>
               g 
             </mi> 
            </mstyle> 
            <mrow> 
             <mtext>
               cn 
             </mtext> 
             <mn>
               2 
             </mn> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <mrow> 
          <mo>
            ‖ 
          </mo> 
          <mrow> 
           <msub> 
            <mstyle mathvariant="bold" mathsize="normal"> 
             <mi>
               g 
             </mi> 
            </mstyle> 
            <mrow> 
             <mtext>
               cn1 
             </mtext> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ‖ 
          </mo> 
         </mrow> 
         <mrow> 
          <mo>
            ‖ 
          </mo> 
          <mrow> 
           <msub> 
            <mstyle mathvariant="bold" mathsize="normal"> 
             <mi>
               g 
             </mi> 
            </mstyle> 
            <mrow> 
             <mtext>
               cn2 
             </mtext> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            ‖ 
          </mo> 
         </mrow> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (7)</p>
    <fig id="fig1" position="float">
     <label>Figure 1</label>
     <caption>
      <title>Figure 1. Characteristic polarization state pairs form a polarization signature (polarization fork).</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId41.jpeg?20240729024241" />
    </fig>
   </sec>
  </sec><sec id="s3">
   <title>3. The Method</title>
   <p>The following steps summarize and illustrate the procedures:</p>
   <p>1) Derive the transient response of the co- and cross-polarized directions {hh, yx; xy, vv} where x<sub>┴</sub>y (see <xref ref-type="fig" rid="fig5">
     Figure 5
    </xref>, for example).</p>
   <p>2) Measure the uncertainty in the resonance extraction (see <xref ref-type="fig" rid="fig6">
     Figure 6
    </xref>, for example).</p>
   <p>3) Use an ensemble average approach to the constraints on the modal order and the VAF merit (see <xref ref-type="fig" rid="fig7">
     Figure 7
    </xref>, for example).</p>
   <p>4) Extract the resonance residue using the MPOF method (see <xref ref-type="table" rid="table2">
     Table 2
    </xref>, for example).</p>
   <p>5) Find the co-pol null states of each resonance and then the depolarization degree per resonance (see <xref ref-type="table" rid="table3">
     Table 3
    </xref> and <xref ref-type="table" rid="table4">
     Table 4
    </xref>, for example).</p>
   <p>6) Determine the weighted feature set for all known targets (two in this case) (see <xref ref-type="fig" rid="fig8">
     Figure 8
    </xref>, for example).</p>
   <p>7) Use a supervised learning approach to calculate the rate of correct identification vs. SNR (see <xref ref-type="fig" rid="fig9">
     Figure 9
    </xref>, for example).</p>
   <sec id="s3_1">
    <title>
     <xref ref-type="bibr" rid="scirp.134878-"></xref>3.1. The Feature Set</title>
    <p>Assuming that the targets have identical substructures and dimensions, as in the case of same-class aircraft targets, the problem is to discriminate or identify these same-class targets by their dihedral shape feature per resonance mode. Therefore, it is desirable to quantify the shape variant degree ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <mi>
         λ 
       </mi> 
      </mrow> 
     </math>) of a substructure (X), e.g. wings, for i'th target, say q<sub>i</sub>, compared to a reference target, q<sub>ref</sub>, as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          X 
        </mi> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <msub> 
          <mi>
            q 
          </mi> 
          <mi>
            i 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mi>
            X 
          </mi> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            Ω 
          </mi> 
          <mi>
            λ 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
       <mfrac> 
        <mrow> 
         <mrow> 
          <mo>
            | 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              θ 
            </mi> 
            <mi>
              i 
            </mi> 
           </msub> 
           <mo>
             − 
           </mo> 
           <msub> 
            <mi>
              θ 
            </mi> 
            <mrow> 
             <mi>
               r 
             </mi> 
             <mi>
               e 
             </mi> 
             <mi>
               f 
             </mi> 
            </mrow> 
           </msub> 
          </mrow> 
          <mo>
            | 
          </mo> 
         </mrow> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            Ω 
          </mi> 
          <mi>
            θ 
          </mi> 
         </msub> 
        </mrow> 
       </mfrac> 
      </mrow> 
     </math> (8)</p>
    <p>where the angle 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mi>
        θ 
      </mi> 
     </math> denotes the substructure swept angle about the main body direction ranges from parallel, that is, zero, to perpendicular, i.e. max degree 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          Ω 
        </mi> 
        <mi>
          θ 
        </mi> 
       </msub> 
      </mrow> 
     </math> (=90˚); the term 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          X 
        </mi> 
       </msub> 
      </mrow> 
     </math> denotes the dimension of the substructure of interest; the term 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          Ω 
        </mi> 
        <mi>
          λ 
        </mi> 
       </msub> 
      </mrow> 
     </math> denotes the total sum of substructure dimensions of interest.</p>
    <p>Then, for the number of training targets (Q) with prior probabilities of P(q<sub>i</sub>), 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         i 
       </mi> 
       <mo>
         = 
       </mo> 
       <mtext>
         1 
       </mtext> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
       <mo>
         , 
       </mo> 
       <mi>
         Q 
       </mi> 
      </mrow> 
     </math>, express the average shape variant ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          X 
        </mi> 
       </msub> 
      </mrow> 
     </math>) of a substructure X as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          X 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <mi>
           Q 
         </mi> 
         <mo>
           − 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
       </mfrac> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
         <mi>
           Q 
         </mi> 
        </munderover> 
        <mrow> 
         <mi>
           P 
         </mi> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              q 
            </mi> 
            <mi>
              n 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           ⋅ 
         </mo> 
         <mi>
           Δ 
         </mi> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mi>
            X 
          </mi> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mrow> 
           <msub> 
            <mi>
              q 
            </mi> 
            <mi>
              n 
            </mi> 
           </msub> 
          </mrow> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mi>
           Δ 
         </mi> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math> (9)</p>
    <p>For multiple substructures 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          X 
        </mi> 
        <mtext>
          1 
        </mtext> 
       </msub> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          X 
        </mi> 
        <msup> 
         <mi>
           M 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </msub> 
      </mrow> 
     </math> that are excited by M resonances, then the weighting of the depolarization degree, γ, per mth resonance by the averages ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mrow> 
         <mi>
           X 
         </mi> 
         <mn>
           1 
         </mn> 
         <mo>
           , 
         </mo> 
         <mo>
           ⋯ 
         </mo> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            M 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>) forms the proposed feature set F in M-dimensional space as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mi>
          F 
        </mi> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mrow> 
        <mo>
          [ 
        </mo> 
        <mrow> 
         <mi>
           Δ 
         </mi> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mrow> 
           <msub> 
            <mi>
              X 
            </mi> 
            <mn>
              1 
            </mn> 
           </msub> 
          </mrow> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            γ 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mo>
           , 
         </mo> 
         <mo>
           ⋯ 
         </mo> 
         <mo>
           , 
         </mo> 
         <mi>
           Δ 
         </mi> 
         <msub> 
          <mi>
            λ 
          </mi> 
          <mrow> 
           <msub> 
            <mi>
              X 
            </mi> 
            <mi>
              M 
            </mi> 
           </msub> 
          </mrow> 
         </msub> 
         <mo>
           ⋅ 
         </mo> 
         <msub> 
          <mi>
            γ 
          </mi> 
          <mi>
            M 
          </mi> 
         </msub> 
        </mrow> 
        <mo>
          ] 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (10)</p>
    <p>
     <xref ref-type="bibr" rid="scirp.134878-"></xref>To make the feature set as compact as possible, and hence, fewer distance computations and more separable feature patterns of different targets, select the 1,…., M* resonances with ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         Δ 
       </mi> 
       <msub> 
        <mi>
          λ 
        </mi> 
        <mi>
          X 
        </mi> 
       </msub> 
      </mrow> 
     </math>) above a certain upper threshold or discard the ones below a certain lower threshold.</p>
   </sec>
   <sec id="s3_2">
    <title>3.2. The Learning Approach</title>
    <p>In the training stage, the algorithm begins by estimating the expected (mean) feature set, namely the training prototype, by generating, per resonance, a sample distribution of the feature set with noise perturbation per target. Then, in the testing stage, the algorithm assigns the test sample corrupted by noise from a target under test to the stored target database with the minimum distance aggregated across the M' resonances of interest. The following steps summarize the identification approach for trained targets (Q<sub>tr</sub>) and test targets (Q<sub>ts</sub>) as follows:</p>
    <p>
     <xref ref-type="bibr" rid="scirp.134878-"></xref>1) Training stage: For N realizations or trials, generate the noisy sample distribution of the set as 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           F 
         </mi> 
        </mstyle> 
        <mi>
          i 
        </mi> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           F 
         </mi> 
        </mstyle> 
        <mrow> 
         <mn>
           0 
         </mn> 
         <mo>
           , 
         </mo> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         ; 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
       <mo>
         ; 
       </mo> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mi>
           F 
         </mi> 
        </mstyle> 
        <mrow> 
         <mi>
           N 
         </mi> 
         <mo>
           − 
         </mo> 
         <mn>
           1 
         </mn> 
         <mo>
           , 
         </mo> 
         <mi>
           i 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>, then the training prototype ( 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mstyle mathvariant="bold" mathsize="normal"> 
       <mover accent="true"> 
        <mi>
          F 
        </mi> 
        <mo>
          ˜ 
        </mo> 
       </mover> 
      </mstyle> 
     </math>) is the expected value, i.e. the first moment, expressed as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mstyle mathvariant="bold" mathsize="normal"> 
        <mover accent="true"> 
         <mi>
           F 
         </mi> 
         <mo>
           ˜ 
         </mo> 
        </mover> 
       </mstyle> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <mi>
           N 
         </mi> 
         <mo>
           − 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
       </mfrac> 
       <mstyle displaystyle="true"> 
        <munderover> 
         <mo>
           ∑ 
         </mo> 
         <mrow> 
          <mi>
            n 
          </mi> 
          <mo>
            = 
          </mo> 
          <mn>
            0 
          </mn> 
         </mrow> 
         <mrow> 
          <mi>
            N 
          </mi> 
          <mo>
            − 
          </mo> 
          <mn>
            1 
          </mn> 
         </mrow> 
        </munderover> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             F 
           </mi> 
          </mstyle> 
          <mi>
            n 
          </mi> 
         </msub> 
        </mrow> 
       </mstyle> 
      </mrow> 
     </math> (11)</p>
    <p>2) Test stage: Taking one of the stored targets as the test target q<sub>j</sub>, where its feature set samples are considered the test sample set (F<sub>j</sub>), then across M' modes of interest, measure the aggregate distance (D) between the nth test sample (F<sub>n,</sub> <sub>j</sub>) from target q<sub>j</sub> and the training prototype 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mstyle mathvariant="bold" mathsize="normal"> 
         <mover accent="true"> 
          <mi>
            F 
          </mi> 
          <mo>
            ˜ 
          </mo> 
         </mover> 
        </mstyle> 
        <mi>
          i 
        </mi> 
       </msub> 
      </mrow> 
     </math> of the i'th target q<sub>i</sub> by a distance metric ||.|| as follows:</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mrow> 
         <mi>
           n 
         </mi> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            M 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           i 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           j 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mn>
          1 
        </mn> 
        <mrow> 
         <msup> 
          <mi>
            M 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
         <mo>
           − 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
       </mfrac> 
       <munderover> 
        <mstyle mathsize="140%" displaystyle="true"> 
         <mo>
           ∑ 
         </mo> 
        </mstyle> 
        <mrow> 
         <mi>
           m 
         </mi> 
         <mo>
           = 
         </mo> 
         <mn>
           1 
         </mn> 
        </mrow> 
        <msup> 
         <mi>
           M 
         </mi> 
         <mo>
           ′ 
         </mo> 
        </msup> 
       </munderover> 
       <mrow> 
        <mo>
          ‖ 
        </mo> 
        <mrow> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mover accent="true"> 
            <mi>
              F 
            </mi> 
            <mo>
              ˜ 
            </mo> 
           </mover> 
          </mstyle> 
          <mi>
            i 
          </mi> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            m 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
         <mo>
           − 
         </mo> 
         <msub> 
          <mstyle mathvariant="bold" mathsize="normal"> 
           <mi>
             F 
           </mi> 
          </mstyle> 
          <mrow> 
           <mi>
             n 
           </mi> 
           <mo>
             , 
           </mo> 
           <mi>
             j 
           </mi> 
          </mrow> 
         </msub> 
         <mrow> 
          <mo>
            ( 
          </mo> 
          <mi>
            m 
          </mi> 
          <mo>
            ) 
          </mo> 
         </mrow> 
        </mrow> 
        <mo>
          ‖ 
        </mo> 
       </mrow> 
      </mrow> 
     </math> (12)</p>
    <p>3) Repeating the previous step for 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         i 
       </mi> 
       <mo>
         = 
       </mo> 
       <mtext>
         1 
       </mtext> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mi>
           t 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> cataloged targets will generate (N.Q<sub>tr</sub>) distances, i.e. 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mrow> 
         <mi>
           n 
         </mi> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            M 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           i 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           j 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
      </mrow> 
     </math>, 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         n 
       </mi> 
       <mo>
         = 
       </mo> 
       <mn>
         0 
       </mn> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
       <mo>
         , 
       </mo> 
       <mi>
         N 
       </mi> 
       <mo>
         − 
       </mo> 
       <mtext>
         1 
       </mtext> 
      </mrow> 
     </math> and 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mi>
         i 
       </mi> 
       <mo>
         = 
       </mo> 
       <mtext>
         1 
       </mtext> 
       <mo>
         , 
       </mo> 
       <mo>
         ⋯ 
       </mo> 
       <mo>
         , 
       </mo> 
       <msub> 
        <mi>
          Q 
        </mi> 
        <mrow> 
         <mi>
           t 
         </mi> 
         <mi>
           r 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math>, for a single test target q<sub>j</sub>.</p>
    <p>4) Assign sample F<sub>n,</sub> <sub>j</sub> to i'th target q<sub>i</sub> if the minimum distance D<sub>n,</sub> <sub>M'</sub>(i, j)<sub>min</sub> &gt; D<sub>n,</sub> <sub>M'</sub>(≠i, j)<sub>min</sub> + distance threshold (h), or else declare unable to assign and discard this result if D<sub>n,</sub> <sub>M'</sub>(i, j)<sub>min</sub> ≤ D<sub>n,</sub> <sub>M'</sub>(≠i, j)<sub>min</sub> + h. The user selects the threshold, h, as a fraction of the maximum distance 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mrow> 
         <mi>
           max 
         </mi> 
        </mrow> 
       </msub> 
       <mo>
         = 
       </mo> 
       <msqrt> 
        <mrow> 
         <msub> 
          <mi>
            r 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mo>
           ⋯ 
         </mo> 
         <mo>
           + 
         </mo> 
         <msub> 
          <mi>
            r 
          </mi> 
          <msup> 
           <mi>
             M 
           </mi> 
           <mo>
             ′ 
           </mo> 
          </msup> 
         </msub> 
        </mrow> 
       </msqrt> 
      </mrow> 
     </math> where r = max(γ), i.e. r = 1.</p>
    <p>5) If the j'th and i'th targets of the minimum distance are the same, i.e. 
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mrow> 
         <mi>
           n 
         </mi> 
         <mo>
           , 
         </mo> 
         <msup> 
          <mi>
            M 
          </mi> 
          <mo>
            ′ 
          </mo> 
         </msup> 
        </mrow> 
       </msub> 
       <mrow> 
        <mo>
          ( 
        </mo> 
        <mrow> 
         <mi>
           i 
         </mi> 
         <mo>
           , 
         </mo> 
         <mi>
           j 
         </mi> 
         <mo>
           = 
         </mo> 
         <mi>
           i 
         </mi> 
        </mrow> 
        <mo>
          ) 
        </mo> 
       </mrow> 
       <mo>
         = 
       </mo> 
       <msub> 
        <mi>
          D 
        </mi> 
        <mrow> 
         <mi>
           min 
         </mi> 
        </mrow> 
       </msub> 
      </mrow> 
     </math> then declares able to assign to the correct target (correct decision), incrementing the number of correct target identification (A<sub>j</sub>) for the j'th target, else declare unable to assign to the correct target (incorrect decision).</p>
    <p>6) Repeat the previous step for each test target; then, the ROC is the ratio of the total number of correct target identifications (A) to the product (Q<sub>ts</sub>. Q<sub>tr</sub>. N), expressed as a percentage.</p>
    <p>
     <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> 
       <mtext>
         ROC 
       </mtext> 
       <mo>
         = 
       </mo> 
       <mfrac> 
        <mrow> 
         <msub> 
          <mi>
            A 
          </mi> 
          <mn>
            1 
          </mn> 
         </msub> 
         <mo>
           + 
         </mo> 
         <mo>
           ⋯ 
         </mo> 
         <mo>
           + 
         </mo> 
         <msub> 
          <mi>
            A 
          </mi> 
          <mrow> 
           <msub> 
            <mi>
              Q 
            </mi> 
            <mrow> 
             <mi>
               t 
             </mi> 
             <mi>
               r 
             </mi> 
            </mrow> 
           </msub> 
          </mrow> 
         </msub> 
        </mrow> 
        <mrow> 
         <msub> 
          <mi>
            Q 
          </mi> 
          <mrow> 
           <mi>
             t 
           </mi> 
           <mi>
             s 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           × 
         </mo> 
         <msub> 
          <mi>
            Q 
          </mi> 
          <mrow> 
           <mi>
             t 
           </mi> 
           <mi>
             r 
           </mi> 
          </mrow> 
         </msub> 
         <mo>
           × 
         </mo> 
         <mi>
           N 
         </mi> 
        </mrow> 
       </mfrac> 
       <mo>
         × 
       </mo> 
       <mn>
         100 
       </mn> 
      </mrow> 
     </math> (13)</p>
    <p>7) Repeat previous steps with different SNRs to establish the curve of the ROC vs. SNR levels. For Q<sub>ts</sub> targets with the same prior probability, the lower bound of the ROC curve, at least theoretically, will set approximately around 100/Q<sub>ts</sub>, e.g. 50% for Q = 2, %33 for Q = 3.</p>
    <p>Henceforth, the results will show how well the identification algorithm performs under modal order and VAF constraints, with shape variant weighting the feature set per resonance mode.</p>
   </sec>
  </sec><sec id="s4">
   <title>
    <xref ref-type="bibr" rid="scirp.134878-"></xref>4. Simulation and Results</title>
   <p>
    <xref ref-type="bibr" rid="scirp.134878-"></xref>The EM software FEKO <xref ref-type="bibr" rid="scirp.134878-23">
     [23]
    </xref> enables the modelling of a wire target. It calculates the frequency response by the method of moments, setting the maximum frequency preferably at twice the highest resonant frequency of interest. A wire target model is sufficient for our purpose, as the dihedral structures provide sufficient polarization information to implement the identification algorithm. <xref ref-type="fig" rid="fig2">
     Figure 2
    </xref> depicts the configuration of the target dimensions and shape. The angle θ<sub>w</sub> defines the wing’s swept angle, whereas θ<sub>t</sub> defines the tail’s swept angle with the longitudinal axis.</p>
   <fig id="fig2" position="float">
    <label>Figure 2</label>
    <caption>
     <title>Figure 2. The aircraft wire model configuration with normal incidence looks in the u<sub>1</sub> direction. The angles θ<sub>w</sub>, and θ<sub>t</sub> give the model different shapes but do not change the dimensions.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId91.jpeg?20240729024244" />
   </fig>
   <p>The simulation (with values depicted in <xref ref-type="table" rid="table1">
     Table 1
    </xref>) uses two different swept sets (θ<sub>w</sub>, θ<sub>t</sub>) = (30˚, 60˚) and (45˚, 45˚) to have two models with a swept difference of 15˚ to validate the feature set robustness. Having more than two test targets will only decrease the lower bound of the ROC curve, but the approach is still valid for two targets. Changing the angles θ<sub>w</sub> and θ<sub>t</sub> does not affect the geometrical dimensions (i.e. a similar set of resonant frequencies) but leads to different shapes and, subsequently, different polarization characteristics.</p>
   <table-wrap id="table1">
    <label>
     <xref ref-type="table" rid="table1">
      Table 1
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.134878-"></xref>Table 1. Feko simulation values.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="50.00%"><p style="text-align:center">Parameter</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="50.00%"><p style="text-align:center">Value</p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="50.00%"><p style="text-align:center">Start frequency</p></td> 
      <td class="custom-top-td acenter" width="50.00%"><p style="text-align:center">1.9 MHz</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Stop frequency</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">1 GHz</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Number of frequency points</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">512</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Excitation source voltage</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">1V</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Incidence direction</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Normal</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Wire radius</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">0.33 cm</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">Number of segments</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">83</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="50.00%"><p style="text-align:center">SEM modal order</p></td> 
      <td class="acenter" width="50.00%"><p style="text-align:center">4</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="50.00%"><p style="text-align:center">Late-time onset</p></td> 
      <td class="custom-bottom-td acenter" width="50.00%"><p style="text-align:center">25 ns</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>This configuration led to four dominant resonances, i.e. M = 4, corresponding to the mid, the nose-wings, the wings-mid, and the tails, respectively, as depicted in <xref ref-type="fig" rid="fig3">
     Figure 3
    </xref>. However, only the second to fourth-order resonances reflect the dihedral features of the target.</p>
   <fig id="fig3" position="float">
    <label>Figure 3</label>
    <caption>
     <title>Figure 3. The current distribution per mode shows the excited section of the aircraft model.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId92.jpeg?20240729024244" />
   </fig>
   <p>
    <xref ref-type="bibr" rid="scirp.134878-"></xref>In <xref ref-type="fig" rid="fig4">
     Figure 4
    </xref>, the current distributions of four selected segments belonging to (the nose, wing, mid, and tail) sections of the model demonstrate that the resonances, i.e. reflected by peaks in the response, correspond mainly to sections of the mid, the wings, the nose, and the tails, respectively. The jointed nose, mid, and skewed wing effect will be more profound on the total response, as seen in <xref ref-type="fig" rid="fig4">
     Figure 4
    </xref>. Each section has a different resonant frequency depending on its dimensions, but both models have the same resonant frequency set overall. Therefore, both models are assumed to be electrically similar. <xref ref-type="fig" rid="fig5">
     Figure 5
    </xref> shows the temporal response for both models after Fourier Transforming the frequency response. In general, the x-pol returns of both models display less specular reflections and better oscillatory returns (more robust modes). Henceforth, with different noise levels, anticipate that some resonance residue may be difficult to attain in all quadrature polarization channels.</p>
   <p>
    <xref ref-type="fig" rid="fig6">
     Figure 6
    </xref> presents two trials of MPOF extraction against SNR from 0 to +40 dB, leading to the frequency distribution of four resonances with noise. Both models’ resonance sets are generally closely identical, as expected, especially the first and second sets. This trial evaluation displays modes around 180, 290, 375 - 410, and 650 MHz. In addition, there are slight and uncorrelated shifts in the frequency of the extracted modes from channel to channel and from model to model. Shifts in the third and fourth sets are more noticeable, suggesting that allowing a guard or margin band when grouping residues from the quadrature polarization channels is good practice. The fourth-ordered resonance caused the most uncertainty in the signature modal as it was very susceptible to noise below 20dB, suggesting either reducing the modal order with lower SNR or using ensemble averaging to enhance the SNR.</p>
   <p>To satisfy a well-estimated resonance signature with noise perturbation, i.e. an approximated signal of consistent modal order and high VAF, take the ensemble average of the original signal before MPOF extraction. As shown in <xref ref-type="fig" rid="fig7">
     Figure 7
    </xref>, applying the ensemble average against noise can guarantee consistency in the modal order M and improve the VAF, e.g. by four folds at 0 dB from 20% to 80%.</p>
   <fig-group id="fig4" position="float">
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>(a) Model A--(b) Model B--Figure 4. The current-frequency responses in hh-pol of the selected segments belonging to the nose (#7), wing(#12), mid(#41), and tail stabilizer (#61), respectively.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId93.jpeg?20240729024244" />
    </fig>
    <fig id="fig4" position="float">
     <label>Figure 4</label>
     <caption>
      <title>(a) Model A--(b) Model B--Figure 4. The current-frequency responses in hh-pol of the selected segments belonging to the nose (#7), wing(#12), mid(#41), and tail stabilizer (#61), respectively.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId94.jpeg?20240729024244" />
    </fig>
   </fig-group>
   <fig-group id="fig5" position="float">
    <fig id="fig5" position="float">
     <label>Figure 5</label>
     <caption>
      <title>(a) Model A--(b) Model B--Figure 5. Calculated temporal responses of both models in HH and HV channels.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId95.jpeg?20240729024244" />
    </fig>
    <fig id="fig5" position="float">
     <label>Figure 5</label>
     <caption>
      <title>(a) Model A--(b) Model B--Figure 5. Calculated temporal responses of both models in HH and HV channels.</title>
     </caption>
     <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId96.jpeg?20240729024243" />
    </fig>
   </fig-group>
   <fig id="fig6" position="float">
    <label>Figure 6</label>
    <caption>
     <title>(a) Model A<p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/9801935-rId99.jpeg?20240729024243" /></p> <p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/9801935-rId100.jpeg?20240729024244" /></p>(b) Model BFigure 6. The fourth-order resonant frequency distributions in (hh and hv) channels against SNR for (a) Model A and (b) Model B. There are three distinctive resonances in the ranges 144 - 155, 270 - 300, and 450 - 500 MHz. Generally, higher modes are more susceptible to noise, e.g. the fourth mode below 20 dB.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="" />
   </fig>
   <fig id="fig6" position="float">
    <label>Figure 6</label>
    <caption>
     <title>(a) Model A<p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/9801935-rId99.jpeg?20240729024243" /></p> <p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/9801935-rId100.jpeg?20240729024244" /></p>(b) Model BFigure 6. The fourth-order resonant frequency distributions in (hh and hv) channels against SNR for (a) Model A and (b) Model B. There are three distinctive resonances in the ranges 144 - 155, 270 - 300, and 450 - 500 MHz. Generally, higher modes are more susceptible to noise, e.g. the fourth mode below 20 dB.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId97.jpeg?20240729024243" />
   </fig>
   <fig id="fig6" position="float">
    <label>Figure 6</label>
    <caption>
     <title>(a) Model A<p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/9801935-rId99.jpeg?20240729024243" /></p> <p class="imgGroupCss_v"><img class=" imgMarkCss lazy" data-original="https://html.scirp.org/file/9801935-rId100.jpeg?20240729024244" /></p>(b) Model BFigure 6. The fourth-order resonant frequency distributions in (hh and hv) channels against SNR for (a) Model A and (b) Model B. There are three distinctive resonances in the ranges 144 - 155, 270 - 300, and 450 - 500 MHz. Generally, higher modes are more susceptible to noise, e.g. the fourth mode below 20 dB.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId98.jpeg?20240729024243" />
   </fig>
   <fig id="fig7" position="float">
    <label>Figure 7</label>
    <caption>
     <title>Figure 7. Ensemble average per SNR for M = 4 and VAF &gt; 80%.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId101.jpeg?20240729024244" />
   </fig>
   <p>After applying the MPOF to the temporal backscattered signal of Model A, a set of four resonances exist with complex residues as shown in <xref ref-type="table" rid="table2">
     Table 2
    </xref>, inserting the complex residues into (4) for each mode and then applying (5) and solving the co-pol CPS set at each resonance mode, as listed in <xref ref-type="table" rid="table3">
     Table 3
    </xref> and <xref ref-type="table" rid="table4">
     Table 4
    </xref>, illustrating that the target models have a different CPS set at each resonance and, subsequently, different physical attributes. For the first model, at the first resonance, the geometry is forecasted to be highly long as the dot product g<sub>cn1</sub>∙g<sub>cn2</sub> = 1 and tilted about 45˚ (as 1/2tan<sup>−</sup><sup>1</sup>(g<sub>2</sub>/g<sub>1</sub>) = 45˚ for [g<sub>cn1</sub> + g<sub>cn2</sub>]); thus corresponding mainly to the midsection. The second to the fourth have similar CPS sets with the non-linear property as g<sub>cn1</sub>∙g<sub>cn2</sub> 
    <math display="inline" xmlns="http://www.w3.org/1998/Math/MathML"> <mo>
       ≠ 
     </mo> 
    </math> 1, forecasting a dihedral structure. These attributes of the CPS at the dominant resonances agree with what a priori known about the target composite is. In particular, the g<sub>3</sub> of the co-pol max set, cm<sub>1,</sub> <sub>2</sub>, for all resonances is zero, indicating that all target geometries are symmetrical.</p>
   <table-wrap id="table2">
    <label>
     <xref ref-type="table" rid="table2">
      Table 2
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.134878-"></xref>Table 2. The scattering coefficients of Model A.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="24.99%"><p style="text-align:center">Resonance order</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="25.01%"><p style="text-align:center">c<sub>hh</sub></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="24.99%"><p style="text-align:center">c<sub>yx</sub></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="25.01%"><p style="text-align:center">c<sub>vv</sub></p></td> 
     </tr> 
     <tr> 
      <td class="custom-top-td acenter" width="24.99%"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="25.01%"><p style="text-align:center">0.49 − 0.13j</p></td> 
      <td class="custom-top-td acenter" width="24.99%"><p style="text-align:center">0.37 − 0.38j</p></td> 
      <td class="custom-top-td acenter" width="25.01%"><p style="text-align:center">−0.49 + 0.13j</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="24.99%"><p style="text-align:center">2</p></td> 
      <td class="acenter" width="25.01%"><p style="text-align:center">0.92 + 0.73j</p></td> 
      <td class="acenter" width="24.99%"><p style="text-align:center">0.28 + 0.11j</p></td> 
      <td class="acenter" width="25.01%"><p style="text-align:center">−0.92 − 0.73j</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="24.99%"><p style="text-align:center">3</p></td> 
      <td class="acenter" width="25.01%"><p style="text-align:center">−1.44 + 3.64j</p></td> 
      <td class="acenter" width="24.99%"><p style="text-align:center">0.64 + 0.03j</p></td> 
      <td class="acenter" width="25.01%"><p style="text-align:center">1.44 − 3.64j</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="24.99%"><p style="text-align:center">4</p></td> 
      <td class="custom-bottom-td acenter" width="25.01%"><p style="text-align:center">−0.97 − 2.23j</p></td> 
      <td class="custom-bottom-td acenter" width="24.99%"><p style="text-align:center">-0.65 + 0.15j</p></td> 
      <td class="custom-bottom-td acenter" width="25.01%"><p style="text-align:center">−0.97 − 2.23j</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <table-wrap id="table3">
    <label>
     <xref ref-type="table" rid="table3">
      Table 3
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.134878-"></xref>Table 3. The CPS of Model A.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="16.66%"><p style="text-align:center">Mode order</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="16.67%"><p style="text-align:center">CPS</p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="16.67%"><p style="text-align:center">g<sub>1</sub></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="16.66%"><p style="text-align:center">g<sub>2</sub></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="16.67%"><p style="text-align:center">g<sub>3</sub></p></td> 
      <td class="custom-bottom-td custom-top-td acenter" width="16.67%"><p style="text-align:center">P<sub>c</sub></p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="16.66%"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.66%"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">1</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−1</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−1</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-bottom-td acenter" width="16.66%"><p style="text-align:center">−1</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="16.66%"><p style="text-align:center">2</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.66%"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">1</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−1</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.34</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−0.26</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.97</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-bottom-td acenter" width="16.66%"><p style="text-align:center">−0.26</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">−0.97</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="16.66%"><p style="text-align:center">3</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.66%"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">1.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−1</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.51</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−0.16</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.98</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-bottom-td acenter" width="16.66%"><p style="text-align:center">−0.16</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">−0.98</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="16.66%"><p style="text-align:center">4</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.66%"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-top-td acenter" width="16.67%"><p style="text-align:center">1</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−1.0</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.32</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="16.67%"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="acenter" width="16.66%"><p style="text-align:center">−0.27</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.96</p></td> 
      <td class="acenter" width="16.67%"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0</p></td> 
      <td class="custom-bottom-td acenter" width="16.66%"><p style="text-align:center">−0.27</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">−0.96</p></td> 
      <td class="custom-bottom-td acenter" width="16.67%"><p style="text-align:center">0.0</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <table-wrap id="table4">
    <label>
     <xref ref-type="table" rid="table4">
      Table 4
     </xref></label>
    <caption>
     <title>
      <xref ref-type="bibr" rid="scirp.134878-"></xref>Table 4. Compared to the first model, the CPS results of Model B.</title>
    </caption>
    <table class="MsoTableGrid custom-table" border="0" cellspacing="0" cellpadding="0"> 
     <tr> 
      <td class="custom-bottom-td custom-top-td acenter" width="15.78%" colspan="2"><p style="text-align:center">Mode order</p></td> 
      <td class="custom-bottom-td custom-top-td aleft" width="15.62%" colspan="2"><p style="text-align:left">CPS</p></td> 
      <td class="custom-bottom-td custom-top-td aleft" width="17.15%" colspan="2"><p style="text-align:left">g<sub>1</sub></p></td> 
      <td class="custom-bottom-td custom-top-td aleft" width="17.14%" colspan="2"><p style="text-align:left">g<sub>2</sub></p></td> 
      <td class="custom-bottom-td custom-top-td aleft" width="17.15%" colspan="2"><p style="text-align:left">g<sub>3</sub></p></td> 
      <td class="custom-bottom-td custom-top-td aleft" width="17.15%"><p style="text-align:left">P</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="15.78%" colspan="2"><p style="text-align:center">1</p></td> 
      <td class="custom-top-td acenter" width="15.62%" colspan="2"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.14%" colspan="2"><p style="text-align:center">1.0</p></td> 
      <td class="custom-top-td acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.15%"><p style="text-align:center">1.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.62%" colspan="2"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.14%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.15%"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.62%" colspan="2"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.14%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.15%"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="15.62%" colspan="2"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.14%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.15%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.15%"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="15.13%"><p style="text-align:center">2</p></td> 
      <td class="custom-top-td acenter" width="15.30%" colspan="2"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.38%" colspan="2"><p style="text-align:center">1.0</p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">1.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.30%" colspan="2"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.38%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.03</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.30%" colspan="2"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.38%" colspan="2"><p style="text-align:center">−0.72</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.7</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.00</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="15.30%" colspan="2"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.38%" colspan="2"><p style="text-align:center">−0.72</p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">−0.7</p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.00</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="15.13%"><p style="text-align:center">3</p></td> 
      <td class="custom-top-td acenter" width="15.30%" colspan="2"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.38%" colspan="2"><p style="text-align:center">1.0</p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">1.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.30%" colspan="2"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.38%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.71</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.30%" colspan="2"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.38%" colspan="2"><p style="text-align:center">−0.08</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">1.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="15.30%" colspan="2"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.38%" colspan="2"><p style="text-align:center">−0.08</p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td rowspan="4" class="custom-top-td acenter" width="15.13%"><p style="text-align:center">4</p></td> 
      <td class="custom-top-td acenter" width="15.30%" colspan="2"><p style="text-align:center">cm<sub>1</sub></p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.38%" colspan="2"><p style="text-align:center">1.0</p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-top-td acenter" width="17.40%" colspan="2"><p style="text-align:center">1.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.30%" colspan="2"><p style="text-align:center">cm<sub>2</sub></p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.38%" colspan="2"><p style="text-align:center">−1.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td class="acenter" width="15.30%" colspan="2"><p style="text-align:center">cn<sub>1</sub></p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="acenter" width="17.38%" colspan="2"><p style="text-align:center">−0.87</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.49</p></td> 
      <td class="acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
     </tr> 
     <tr> 
      <td class="custom-bottom-td acenter" width="15.30%" colspan="2"><p style="text-align:center">cn<sub>2</sub></p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
      <td class="custom-bottom-td acenter" width="17.38%" colspan="2"><p style="text-align:center">−0.87</p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">−0.49</p></td> 
      <td class="custom-bottom-td acenter" width="17.40%" colspan="2"><p style="text-align:center">0.0</p></td> 
     </tr> 
    </table>
   </table-wrap>
   <p>Next, to demonstrate the ability of the co-null state to discriminate between similar type models, the feature space per resonance mode consists of samples or realization of the dihedral degree generated at this mode with a predetermined SNR. <xref ref-type="table" rid="table3">
     Table 3
    </xref> derives and lists the CPS set at each resonance for Model A.</p>
   <p>Comparing the results of both tables for Models A and B, their co-null set at the second to fourth resonance demonstrates the significant difference, complying with the swept angle change made to the wings and tails.</p>
   <p>
    <xref ref-type="fig" rid="fig8">
     Figure 8
    </xref> depicts the distribution of the third and fourth modes at 20dB SNR, showing normal distributions that are separable with high VAF. These samples will form the test prototypes in the 20 dB testing stage later, whereas the expected prototype constitutes the 20 dB training prototype stored in the cataloged database.</p>
   <fig id="fig8" position="float">
    <label>Figure 8</label>
    <caption>
     <title>Figure 8. The feature space per third and fourth resonances for the perpendicular incidence direction.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId104.jpeg?20240729024244" />
   </fig>
   <p>In general, the depolarization degree appears most distinctive along the second to fourth resonances since these resonances excite the wing and tail sections of the target, respectively. This distinctiveness coincides with the degrees of the two targets differing along these sections.</p>
   <p>The evaluation of the ROC performance undergoes a training process under SNR levels similar to that of the test sample. <xref ref-type="fig" rid="fig9">
     Figure 9
    </xref> depicts the identification performances per resonance with only the modal order constraint M = 4 applied. Identification improves with more resonance in the feature set, e.g. the ROC of the combined third and fourth modes, compared to the individual ROC of the third or fourth modes.</p>
   <fig id="fig9" position="float">
    <label>Figure 9</label>
    <caption>
     <title>Figure 9. The identification performance per modes of interest.</title>
    </caption>
    <graphic mimetype="image" position="float" xlink:type="simple" xlink:href="https://html.scirp.org/file/9801935-rId105.jpeg?20240729024243" />
   </fig>
   <p>Generally, the third and fourth have the best performance, reaching the lower bound of 50% near −10 dB.</p>
  </sec><sec id="s5">
   <title>5. Conclusion</title>
   <p>The paper evaluated the ability of the depolarization degree to identify swept changes in a simple wire target that resembles an aircraft. Such a feature set is compact, reflects the target’s dimensions and configuration attributes, is invariant to orientation, forms a recognizable pattern in the proposed feature space, and is resilient to ambiguity in the late time onset and noise compared to the symmetry and tilt degrees. Adding the constraints on the modal order M and VAF improved the certainty in the resonance set and thus the performance of the ROC; in this case, it achieved an identification rate with a lower bound below −10 dB and an upper bound of 100% at 20 dB. In future work, the identification approach must consider estimating the expected feature set with aspect variation. Therefore, the diversity of the target’s look angle should be considered, and other decision-making algorithms, such as the nearest neighbor or statistical methods, should be exploited, especially nonparametric types and fuzzy logical approaches.</p>
  </sec>
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