<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article  PUBLIC "-//NLM//DTD Journal Publishing DTD v3.0 20080202//EN" "http://dtd.nlm.nih.gov/publishing/3.0/journalpublishing3.dtd"><article xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:xlink="http://www.w3.org/1999/xlink" dtd-version="3.0" xml:lang="en" article-type="research article"><front><journal-meta><journal-id journal-id-type="publisher-id">OJDM</journal-id><journal-title-group><journal-title>Open Journal of Discrete Mathematics</journal-title></journal-title-group><issn pub-type="epub">2161-7635</issn><publisher><publisher-name>Scientific Research Publishing</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.4236/ojdm.2021.113007</article-id><article-id pub-id-type="publisher-id">OJDM-110485</article-id><article-categories><subj-group subj-group-type="heading"><subject>Articles</subject></subj-group><subj-group subj-group-type="Discipline-v2"><subject>Physics&amp;Mathematics</subject></subj-group></article-categories><title-group><article-title>
 
 
  On the Number of Idempotent Partial Contraction Mappings of a Finite Chain
 
</article-title></title-group><contrib-group><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Oladapo</surname><given-names>Adekunle Ojo</given-names></name><xref ref-type="aff" rid="aff1"><sup>1</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Fatma</surname><given-names>Salim Ali Al-Kharousi</given-names></name><xref ref-type="aff" rid="aff2"><sup>2</sup></xref></contrib><contrib contrib-type="author" xlink:type="simple"><name name-style="western"><surname>Abdullahi</surname><given-names>Umar</given-names></name><xref ref-type="aff" rid="aff3"><sup>3</sup></xref><xref ref-type="corresp" rid="cor1"><sup>*</sup></xref></contrib></contrib-group><aff id="aff2"><addr-line>Department of Mathematics, Sultan Qaboos University, Al-Khod, Muscat, Oman</addr-line></aff><aff id="aff3"><addr-line>Department of Mathematics, Khalifa University of Science and Technology, Sas Al-Nakhl, Abu Dhabi, U. A. E.</addr-line></aff><aff id="aff1"><addr-line>Oyo State College of Agriculture and Technology, Igboora, Oyo State, Nigeria</addr-line></aff><pub-date pub-type="epub"><day>08</day><month>06</month><year>2021</year></pub-date><volume>11</volume><issue>03</issue><fpage>94</fpage><lpage>101</lpage><history><date date-type="received"><day>4,</day>	<month>March</month>	<year>2021</year></date><date date-type="rev-recd"><day>10,</day>	<month>July</month>	<year>2021</year>	</date><date date-type="accepted"><day>13,</day>	<month>July</month>	<year>2021</year></date></history><permissions><copyright-statement>&#169; Copyright  2014 by authors and Scientific Research Publishing Inc. </copyright-statement><copyright-year>2014</copyright-year><license><license-p>This work is licensed under the Creative Commons Attribution International License (CC BY). http://creativecommons.org/licenses/by/4.0/</license-p></license></permissions><abstract><p>
 
 
  Let <inline-formula><inline-graphic xlink:href="dit_1798cf4c-b9a5-4ada-b2d4-9fbf535a6d28.png" xlink:type="simple"/></inline-formula>be the partial symmetric semigroup on <inline-formula><inline-graphic xlink:href="dit_86c31e58-0588-44fc-8ff3-78c73dc14be6.png" xlink:type="simple"/></inline-formula>and let <inline-formula><inline-graphic xlink:href="dit_09f7ec2a-49d1-463d-952e-93fbe00740cd.png" xlink:type="simple"/></inline-formula>and <inline-formula><inline-graphic xlink:href="dit_4aca07c1-9a36-44b6-83af-46fdd6278ca4.png" xlink:type="simple"/></inline-formula>be its subsemigroups of order-preserving contractions and order-preserving, order-decreasing contractions mappings of <inline-formula><inline-graphic xlink:href="dit_72d2bbdf-2b96-4812-a993-f49640bb98c9.png" xlink:type="simple"/></inline-formula>, respectively. In this paper we investigate the cardinalities of <inline-formula><inline-graphic xlink:href="dit_95038cdc-5496-495f-bfb9-29c817ba2df4.png" xlink:type="simple"/></inline-formula>and <inline-formula><inline-graphic xlink:href="dit_f8d3d782-ff8c-43b3-84af-d21a3f4291d5.png" xlink:type="simple"/></inline-formula>, the set idempotents of <inline-formula><inline-graphic xlink:href="dit_ac8237f8-83ec-4767-9029-b546377bf106.png" xlink:type="simple"/></inline-formula>and <inline-formula><inline-graphic xlink:href="dit_8b1bf8bf-7472-453c-965d-7308da5b4f4c.png" xlink:type="simple"/></inline-formula>, respectively. We also investigate the cardinalities of certain equivalences on <inline-formula><inline-graphic xlink:href="dit_e5f7aec4-67c1-48ba-8d03-ea6ceb2e7627.png" xlink:type="simple"/></inline-formula>and <inline-formula><inline-graphic xlink:href="dit_42a31943-fe9d-4ea8-8999-3aadb705fb38.png" xlink:type="simple"/></inline-formula>.
 
</p></abstract><kwd-group><kwd>Height</kwd><kwd> Right (Left) Waist and Fix of a Transformation</kwd><kwd> Idempotents</kwd></kwd-group></article-meta></front><body><sec id="s1"><title>1. Introduction</title><p>Let X n = { 1 , 2 , ⋯ , n } . A (partial) transformation α : Dom α ⊆ X n → Im α ⊆ X n is said to be full or total if Dom α = X n ; otherwise it is called strictly partial. The set of partial transformations of X n , denoted by P n , more commonly known as the partial transformation semigroup is also known as the partial symmetric semigroup or monoid with composition of mappings as the semigroup operation. Similarly, the set of full (or total) transformations of X n , denoted by T n , more commonly known as the full transformation semigroup is also known as the (full) symmetric semigroup or monoid.</p><p>We shall write the image of x under α as ( x ) α (or simply x α ) instead of α ( x ) . This is called the right-hand notation and it has the advantage that composition of maps is read from left to right, that is, ( x ) α β = ( ( x ) α ) β . Further, a transformation α ∈ P n is said to be order-preserving (order-reversing) if ( ∀ x , y ∈ Dom α ) x ≤ y ⇒ x α ≤ y α ( x α ≥ y α ) and, a contraction mapping (or simply a contraction) if ( ∀ x , y ∈ Dom α ) | x − y | ≥ | x α − y α | . We shall denote by O C P n and O D C P n , the semigroups of order-preserving partial contractions and of order-preserving, order-decreasing partial contractions of X n , respectively.</p><p>Recently, Zhao and Yang [<xref ref-type="bibr" rid="scirp.110485-ref1">1</xref>] initiated the algebraic study of semigroups of order-preserving partial contractions of X n , where they referred to our contractions as compressions. A general systematic studied of various semigroups of contraction mappings of a finite chain was initiated in the papers [<xref ref-type="bibr" rid="scirp.110485-ref2">2</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref3">3</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref4">4</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref5">5</xref>]. While the papers [<xref ref-type="bibr" rid="scirp.110485-ref2">2</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref4">4</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref5">5</xref>] investigated algebraic properties of various semigroups of contraction mappings of a finite chain, Adeshola and Umar [<xref ref-type="bibr" rid="scirp.110485-ref3">3</xref>] investigated combinatorial properties of the semigroups of order-preserving full contraction mappings, O C T n and its subsemigroup of order-decreasing full contraction mappings, O D C T n . This paper investigates the combinatorial properties of the set of idempotents of O C P n and O D C P n and of certain natural equivalences on them.</p><p>An element e in a semigroup S, is said to be an idempotent if e 2 = e . Every finite semigroup contains an idempotent and in a group there is only one idempotent, namely the identity. Semigroups which contain a “sufficient” supply of idempotents (for example, regular, abundant, etc.) have been the object of study by many semigroup theorists largely due to the role idempotents play in determining the structure of such semigroups. Counting the number of idempotents in a semigroup has attracted the attention of several authors, see for example [<xref ref-type="bibr" rid="scirp.110485-ref3">3</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref6">6</xref>] - [<xref ref-type="bibr" rid="scirp.110485-ref17">17</xref>], which is by no means a complete list. For a detailed account on combinatorial enumeration problems in transformation semigroup theory we refer the reader to Umar [<xref ref-type="bibr" rid="scirp.110485-ref17">17</xref>]. It is fairly obvious that the number of full and partial transformation idempotents of X n denoted by | E ( T n ) | and | E ( P n ) | are, respectively,</p><p>| E ( T n ) | = ∑ p = 0 n ( n p ) p n − p [<xref ref-type="bibr" rid="scirp.110485-ref14">14</xref>] and | E ( P n ) | = ∑ p = 0 n ( n p ) ( p + 1 ) n − p [<xref ref-type="bibr" rid="scirp.110485-ref18">18</xref>].</p><p>However, at least two non-trivial cases are worth mentioning. In an elegant paper in 1971, Howie [<xref ref-type="bibr" rid="scirp.110485-ref10">10</xref>] showed that the number of full order-preserving idempotents denoted by | E ( O n ) | is</p><p>| E ( O n ) | = f 2 n ,</p><p>where f m denotes the mth Fibonacci number, defined recursively for m &gt; 2 by</p><p>f 1 = f 2 = 1 ,       f m = f m − 1 + f m − 2 .</p><p>More recently, Adeshola and Umar [<xref ref-type="bibr" rid="scirp.110485-ref3">3</xref>] showed that the number of full order-preserving contraction idempotents denoted by | E ( O C T n ) | is</p><p>| E ( O C T n ) | = n ( n + 1 ) / 2 = ( n + 1 2 ) .</p><p>We conclude this section with a breakdown of our investigation section by section. In Section 2 we obtain the cardinalities of various equivalence classes defined on E ( O C P n ) . In Section 3 we obtain the analogues of the results from Section 2 for E ( O D C P n ) . These cardinalities lead to formulae for the orders of E ( O C P n ) and E ( O D C P n ) as well as new triangles of numbers which are as at the time of submitting this paper not yet recorded in [<xref ref-type="bibr" rid="scirp.110485-ref19">19</xref>].</p><p>For standard concepts in semigroup and transformation semigroup theory, see for example [<xref ref-type="bibr" rid="scirp.110485-ref8">8</xref>] [<xref ref-type="bibr" rid="scirp.110485-ref9">9</xref>]. In particular, the set of idempotents of a semigroup S is denoted by E ( S ) .</p></sec><sec id="s2"><title>2. The Semigroup O C P n</title><p>Our approach is essentially that of [<xref ref-type="bibr" rid="scirp.110485-ref20">20</xref>]. For α ∈ P n define F ( α ) = { x ∈ [ n ] : x α = x } as the set of fixed points of α , and let</p><p>● e n = | E ( O C P n ) | ,</p><p>● β n = | { α ∈ E ( O C P n ) : F ( α ) = ∅ } | ,</p><p>● u n = | { α ∈ E ( O C P n ) : { 1 } ⊆ F ( α ) } | ,</p><p>● v n = | { α ∈ E ( O C P n ) : F ( α ) = { 1 } } | = | { α ∈ E ( O C P n ) : F ( α ) = { n } } | ,</p><p>● a n = | { α ∈ E ( O C P n ) : { 1 , n } ⊆ F ( α ) } | ,</p><p>● γ n = | { α ∈ E ( O C P n ) : F ( α ) = { 1 , n } | .</p><p>Then we have the following results:</p><p>Lemma 2.1. For n ≥ 1 , γ n = 1 , and γ 0 = 0 .</p><p>Lemma 2.2. For n ≥ 2 , a n = 2 n − 2 , a 1 = 1 and a 0 = 0 .</p><p>Proof. Let α ∈ E ( O C P n ) be such that { 1, n } ⊆ F ( α ) . It is clear that for all x ∈ X n \ { 1, n } either x ∈ Dom   α or x ∉ Dom α . In the former, we must have x α = x and there are n − 2 choices for x. Thus each x has two degrees of freedom. The result is clear when n = 1 . □</p><p>Lemma 2.3. For n ≥ 1 , v n = 2 n − 1 , and v 0 = 0 .</p><p>Proof. Let α ∈ E ( O C P n ) be such that { 1 } = F ( α ) = Im α . Then for all x ∈ Dom   α , we must have x α = 1 , and again, each with 2 degrees of freedom. □</p><p>Next, we state and prove an analogue of ( [<xref ref-type="bibr" rid="scirp.110485-ref20">20</xref>], Lemma 4) which will be useful in what follows.</p><p>Lemma 2.4. For n ≥ 2 , u n = v n + γ 2 u n − 1 + ⋯ + γ n u 1 .</p><p>Proof. u n − v n is the number of maps α ∈ O C P n with 1 α = 1 and i α = i for some i &gt; 1 : if r is the smallest integer greater than 1 such that r α = r ; then clearly the number of such maps α is ∑ r = 2 n     γ r u n − r + 1 , as required. □</p><p>This leads to the following lemma:</p><p>Lemma 2.5. For n ≥ 1 , u n = 2 n − 2 ( n + 1 ) , and u 0 = 0 .</p><p>Proof. Substituting γ n and v n with 1 and 2 n − 1 , respectively into Lemma 2.4 we get</p><p>u n = 2 n − 1 + u n − 1 + u n − 2 + ⋯ + u 1 (1)</p><p>Replacing n by n − 1 we get</p><p>u n − 1 = 2 n − 2 + u n − 2 + u n − 3 + ⋯ + u 1 (2)</p><p>Subtracting (2) from (1) we get</p><p>u n = 2 n − 2 + 2 u n − 1 ,</p><p>which implies (by iteration)</p><p>u n = 2 n − 2 ( n + 1 ) ,</p><p>as required. □</p><p>We also have</p><p>Lemma 2.6. For n ≥ 0 , β n = 1 .</p><p>Next, we state and prove an analogue of ( [<xref ref-type="bibr" rid="scirp.110485-ref20">20</xref>], Lemma 5) which will be useful in what follows.</p><p>Lemma 2.7. For n ≥ 2 , e n = β n + v 1 u n − 1 + v 2 u n − 2 + ⋯ + v n u 1 .</p><p>Proof. The nilpotents of O C P n are precisely those that do not have fixed points (see [<xref ref-type="bibr" rid="scirp.110485-ref21">21</xref>] ), hence e n − β n is the number of maps α ∈ O C P n with at least one fixed point. If u n , r is the number of such maps α with r as the smallest fixed point, then u n , r = v r u n − r + 1 . Hence e n − β n = ∑ r = 1 n     v r u n − r + 1 . The result now follows. □</p><p>Now we are ready to state and prove one of the two main results of this section.</p><p>Theorem 2.8. For n ≥ 0 , e n = 1 + 2 n − 3 n ( n + 3 ) .</p><p>Proof. Using Lemmas 2.5, 2.6 &amp; 2.7 we see that</p><p>e n = 1 + 2 0 &#215; 2 n − 2 ( n + 1 ) + 2 1 &#215; 2 n − 3 n + 2 2 &#215; 2 n − 4 ( n − 1 ) + ⋯     + 2 n − 2 &#215; 2 0 &#215; 3 + 2 n − 1 &#215; 2 − 1 &#215; 2 = 1 + 2 n − 2 [ ( n + 1 ) + n + ( n − 1 ) + ⋯ + 3 + 2 + 1 − 1 ] = 1 + 2 n − 2 [ ( n + 1 ) ( n + 2 ) / 2 − 1 ] = 1 + 2 n − 3 n ( n + 3 ) ,</p><p>as required. □</p><p>Now we let e ( x ) be the (ordinary) generating functions of the sequence e n above. The proof of the next result is routine using Theorem 2.8 above.</p><p>Theorem 2.9. e ( x ) = ∑ n ≥ 0     e n x n = 1 − 5 x + 10 x 2 − 6 x 3 ( 1 − x ) ( 1 − 2 x ) 3 = ( 1 − x ) ( 1 − 4 x + 6 x 2 ) ( 1 − x ) ( 1 − 2 x ) 3 .</p><p>As in Umar [<xref ref-type="bibr" rid="scirp.110485-ref17">17</xref>], for natural numbers n ≥ k ≥ p ≥ 0 we define</p><p>F p k ( n ; p , k ) = F ( n ; p , k ) = | { α ∈ S : h ( α ) = | Im α | = p , w + ( α ) = k } | , (3)</p><p>F p ( n ; p ) = F ( n ; p ) = | { α ∈ S : h ( α ) = | Im α | = p } | , F k ( n ; k ) = F ( n ; k ) = | { α ∈ S : w + ( α ) = k } | . (4)</p><p>Then we have</p><p>Proposition 2.10. Let S = E ( O C P n ) . Then F p k ( n ; 1, k ) = 2 n − 1 and</p><p>F ( n ; p , k ) = ∑ t = 1 k − p + 1 ( k − t + 1 p − 2 ) 2 n − ( k − t + 1 ) , ( n ≥ k ≥ p ≥ 2 ) .</p><p>Proof. Let α ∈ E ( O C P n ) be such that h ( α ) = | Im α | = p and w + ( α ) = k . First, notice that if p = 1 then { k } = F ( α ) = Im α , and so k α = k . Now for all x ∈ [ n ] \ { k } there are two degrees of freedom: x ∈ Dom α and x α = k ; or x ∉ Dom α . Hence F p k ( n ; 1, k ) = 2 n − 1 .</p><p>Next, let t = min ( Im α ) then t ∈ { 1,2, ⋯ , k − p + 1 } . Next, note that we can</p><p>choose the remaining p − 2 elements of F ( α ) in ( k − t + 1 p − 2 ) ways, since</p><p>t , k ∈ Im   α = F ( α ) ⊆ Dom   α . Similarly, the remaining elements of Dom   α can be chosen from { 1,2, ⋯ , t − 1 } ∪ { k + 1, k + 2, ⋯ , n } in 2 t − 1 ⋅ 2 n − k = 2 n − ( k − t + 1 ) ways, as each has two degrees of freedom. Now taking the sum over the range of t yields the required result. □</p><p>Immediately, we deduce the following</p><p>Corollary 2.11. Let S = E ( O C P n ) . Then F k ( n ; 0 ) = 1 and</p><p>F ( n ; k ) = ( k + 1 ) 2 n − 2 , ( n ≥ k ≥ 1 ) .</p><p>Corollary 2.12. Let S = E ( O C P n ) . Then F p ( n ; 0 ) = 1 , F p ( n ; 1 ) = n 2 n − 1 and</p><p>F ( n ; p ) = ∑ k = p n   ∑ t = 1 k − p + 1 ( k − t + 1 p − 2 ) 2 n − ( k − t + 1 ) ,   ( n ≥ p ≥ 2 ) .</p><p>Finally, notice that we may recover Theorem 2.8 from either of the two corollories above. For some selected values of F ( n ; k ) and F ( n ; p ) in E ( O C P n ) see <xref ref-type="table" rid="table1">Table 1</xref> and <xref ref-type="table" rid="table2">Table 2</xref> below:</p><table-wrap id="table1" ><label><xref ref-type="table" rid="table1">Table 1</xref></label><caption><title> Some selected values of F ( n ; k ) in E ( O C P n ) </title></caption><table><tbody><thead><tr><th align="center" valign="middle" >k n</th><th align="center" valign="middle" >0</th><th align="center" valign="middle" >1</th><th align="center" valign="middle" >2</th><th align="center" valign="middle" >3</th><th align="center" valign="middle" >4</th><th align="center" valign="middle" >5</th><th align="center" valign="middle" >6</th><th align="center" valign="middle" >∑ k = 0 n F ( n ; k ) = | E ( O C P n ) |</th></tr></thead><tr><td align="center" valign="middle" >0</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >1</td></tr><tr><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >2</td></tr><tr><td align="center" valign="middle" >2</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >2</td><td align="center" valign="middle" >3</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >6</td></tr><tr><td align="center" valign="middle" >3</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >4</td><td align="center" valign="middle" >6</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >19</td></tr><tr><td align="center" valign="middle" >4</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" >12</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >20</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >57</td></tr><tr><td align="center" valign="middle" >5</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >24</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >40</td><td align="center" valign="middle" >48</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >161</td></tr><tr><td align="center" valign="middle" >6</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >48</td><td align="center" valign="middle" >64</td><td align="center" valign="middle" >80</td><td align="center" valign="middle" >96</td><td align="center" valign="middle" >112</td><td align="center" valign="middle" >433</td></tr></tbody></table></table-wrap><table-wrap id="table2" ><label><xref ref-type="table" rid="table2">Table 2</xref></label><caption><title> Some selected values of F ( n ; p ) in E ( O C P n ) </title></caption><table><tbody><thead><tr><th align="center" valign="middle" >p n</th><th align="center" valign="middle" >0</th><th align="center" valign="middle" >1</th><th align="center" valign="middle" >2</th><th align="center" valign="middle" >3</th><th align="center" valign="middle" >4</th><th align="center" valign="middle" >5</th><th align="center" valign="middle" >6</th><th align="center" valign="middle" >∑ p = 0 n F ( n ; p ) = | E ( O C P n ) |</th></tr></thead><tr><td align="center" valign="middle" >0</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >1</td></tr><tr><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >2</td></tr><tr><td align="center" valign="middle" >2</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >4</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >6</td></tr><tr><td align="center" valign="middle" >3</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >12</td><td align="center" valign="middle" >5</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >19</td></tr><tr><td align="center" valign="middle" >4</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >17</td><td align="center" valign="middle" >6</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >57</td></tr><tr><td align="center" valign="middle" >5</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >80</td><td align="center" valign="middle" >49</td><td align="center" valign="middle" >23</td><td align="center" valign="middle" >7</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >161</td></tr><tr><td align="center" valign="middle" >6</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >192</td><td align="center" valign="middle" >129</td><td align="center" valign="middle" >72</td><td align="center" valign="middle" >30</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >433</td></tr></tbody></table></table-wrap></sec><sec id="s3"><title>3. The Semigroup O D C P n</title><p>Let</p><p>● d n = | E ( O D C P n ) | ,</p><p>● z n = | { α ∈ E ( O D C P n ) : F ( α ) = { n } } | .</p><p>Then observe that Lemmas 2.1, 2.2, 2.4, 2.5 &amp; 2.6 are all valid if we replace O C P n with O D C P n . Moreover, in contrast to Lemma 2.3 we have</p><p>Lemma 3.1. For n ≥ 1 , z n = 1 .</p><p>To prove the main result of this section, the following lemma (which can be proved by induction) will be needed:</p><p>Lemma 3.2. For n ≥ 1 , we have ∑ i = 1 n     i 2 n − i = 2 n + 1 − ( n + 2 ) .</p><p>An analogue of Lemma 2.7 will also be needed.</p><p>Lemma 3.3. For n ≥ 2 , d n = β n + z 1 u n − 1 + z 2 u n − 2 + ⋯ + z n u 1 .</p><p>Thus we can now state and prove one of the main results of this section.</p><p>Theorem 3.4. For n ≥ 0 , d n = 1 + n 2 n − 1 .</p><p>Proof. Using Lemmas 2.5, 2.6, 3.1 &amp; 3.3 we see that</p><p>d n = 1 + 2 n − 2 ( n + 1 ) + 2 n − 3 n + 2 n − 4 ( n − 1 ) + ⋯ + 2 0 [ n − ( n − 3 ) ] + 1</p><p>= 2 + n [ 2 n − 2 + 2 n − 3 + ⋯ + 2 0 ] + 2 n − 2         − [ 2 n − 4 − 2 &#215; 2 n − 5 − 3 &#215; 2 n − 6 − ⋯ − ( n − 3 ) &#215; 2 0 ]</p><p>= 2 + n ( 2 n − 1 − 1 ) + 2 n − 2 − [ 2 n − 2 − ( n − 1 ) ] (by Lemma 3.2)</p><p>= 1 + n 2 n − 1 ,</p><p>as required. □</p><p>Now we let d ( x ) be the (ordinary) generating functions of the corresponding sequence above. Then we have the following result whose proof is routine using Theorem 3.4.</p><p>Theorem 3.5. d ( x ) = ∑ n ≥ 0     d n x n = 1 − 3 x + 3 x 2 ( 1 − x ) ( 1 − 2 x ) 2 = ( 1 − x ) 3 + x 3 ( 1 − x ) ( 1 − 2 x ) 2 .</p><p>As in the previous section we obtain expressions for the following combinatorial functions.</p><p>Proposition 3.6. Let S = E ( O D C P n ) . Then</p><p>F ( n ; p , k ) = ( k − 1 p − 1 ) 2 n − k , ( n ≥ k ≥ p ≥ 0 ) .</p><p>Proof. Let α ∈ E ( O D C P n ) be such that h ( α ) = | Im α | = p and w + ( α ) = k .</p><p>First, note that we can choose the remaining p − 1 elements of F ( α ) in ( k − 1 p − 1 )</p><p>ways, since k ∈ Im α = F ( α ) ⊆ Dom α . Similarly, the remaining elements of Dom   α can be chosen from [ n ] \ { 1,2, ⋯ , k } in 2 n − k ways, as each has two degrees of freedom: x α = k or x ∉ Dom   α . □</p><p>Immediately, we deduce the following</p><p>Corollary 3.7. Let S = E ( O D C P n ) . Then F k ( n ; 0 ) = 1 and F ( n ; k ) = 2 n − 1 , ( n ≥ k ≥ 1 ) .</p><p>Corollary 3.8. Let S = E ( O D C P n ) . Then F p ( n ; 0 ) = 1 and</p><p>F ( n ; p ) = ∑ k = p n ( k − 1 p − 1 ) 2 n − k , ( n ≥ p ≥ 1 ) .</p><p>Finally, notice that we may recover Theorem 3.4 from either of the two corollories above. For some selected values of F ( n ; k ) and F ( n ; p ) in E ( O D C P n ) see <xref ref-type="table" rid="table3">Table 3</xref> and <xref ref-type="table" rid="table4">Table 4</xref> below:</p><table-wrap id="table3" ><label><xref ref-type="table" rid="table3">Table 3</xref></label><caption><title> Some selected values of F ( n ; k ) in E ( O D C P n ) </title></caption><table><tbody><thead><tr><th align="center" valign="middle" >k n</th><th align="center" valign="middle" >0</th><th align="center" valign="middle" >1</th><th align="center" valign="middle" >2</th><th align="center" valign="middle" >3</th><th align="center" valign="middle" >4</th><th align="center" valign="middle" >5</th><th align="center" valign="middle" >6</th><th align="center" valign="middle" >∑ k = 0 n F ( n ; k ) = | E ( O D C P n ) |</th></tr></thead><tr><td align="center" valign="middle" >0</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >1</td></tr><tr><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >2</td></tr><tr><td align="center" valign="middle" >2</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >2</td><td align="center" valign="middle" >2</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >5</td></tr><tr><td align="center" valign="middle" >3</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >4</td><td align="center" valign="middle" >4</td><td align="center" valign="middle" >4</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >13</td></tr><tr><td align="center" valign="middle" >4</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" >8</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >33</td></tr><tr><td align="center" valign="middle" >5</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >81</td></tr><tr><td align="center" valign="middle" >6</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >32</td><td align="center" valign="middle" >193</td></tr></tbody></table></table-wrap><table-wrap id="table4" ><label><xref ref-type="table" rid="table4">Table 4</xref></label><caption><title> Some selected values of F ( n ; p ) in E ( O D C P n ) </title></caption><table><tbody><thead><tr><th align="center" valign="middle" >p n</th><th align="center" valign="middle" >0</th><th align="center" valign="middle" >1</th><th align="center" valign="middle" >2</th><th align="center" valign="middle" >3</th><th align="center" valign="middle" >4</th><th align="center" valign="middle" >5</th><th align="center" valign="middle" >6</th><th align="center" valign="middle" >∑ p = 0 n F ( n ; p ) = | E ( O D C P n ) |</th></tr></thead><tr><td align="center" valign="middle" >0</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >1</td></tr><tr><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >2</td></tr><tr><td align="center" valign="middle" >2</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >3</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >5</td></tr><tr><td align="center" valign="middle" >3</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >7</td><td align="center" valign="middle" >4</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >13</td></tr><tr><td align="center" valign="middle" >4</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >15</td><td align="center" valign="middle" >11</td><td align="center" valign="middle" >5</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" ></td><td align="center" valign="middle" >33</td></tr><tr><td align="center" valign="middle" >5</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >31</td><td align="center" valign="middle" >26</td><td align="center" valign="middle" >16</td><td align="center" valign="middle" >6</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" ></td><td align="center" valign="middle" >81</td></tr><tr><td align="center" valign="middle" >6</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >63</td><td align="center" valign="middle" >57</td><td align="center" valign="middle" >42</td><td align="center" valign="middle" >22</td><td align="center" valign="middle" >7</td><td align="center" valign="middle" >1</td><td align="center" valign="middle" >193</td></tr></tbody></table></table-wrap><p>Remark 3.9. The sequence d n , is recorded (in [<xref ref-type="bibr" rid="scirp.110485-ref19">19</xref>] ) as A005183.</p></sec><sec id="s4"><title>Support</title><p>Financial support from TRC Grant No: RC/SCI/DOMS/13/01 is gratefully acknowledged.</p></sec><sec id="s5"><title>Conflicts of Interest</title><p>The authors declare no conflicts of interest regarding the publication of this paper.</p></sec><sec id="s6"><title>Cite this paper</title><p>Ojo, O.A., Al-Kharousi, F.S.A. and Umar, A. (2021) On the Number of Idempotent Partial Contraction Mappings of a Finite Chain. Open Journal of Discrete Mathematics, 11, 94-101. https://doi.org/10.4236/ojdm.2021.113007</p></sec></body><back><ref-list><title>References</title><ref id="scirp.110485-ref1"><label>1</label><mixed-citation publication-type="other" xlink:type="simple">Zhao, P. and Yang, M. (2012) Regularity and Green’s Relations on Semigroups of Transformations Preserving Order and Compression. 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